R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
L UIGI O RSINA
Solvability of linear and semilinear eigenvalue problems with L
1data
Rendiconti del Seminario Matematico della Università di Padova, tome 90 (1993), p. 207-238
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and Semilinear Eigenvalue Problems with L1 Data.
LUIGI
ORSINA (*)
ABSTRACT - We
study
the equationwhere A is a linear
elliptic
operator indivergence
form, ~ is a real numberand f is
a functionbelonging
to We find existence results similar to those obtained in the casef E L 2 (~l ).
Furthermore, westudy
the Landes- mann-Lazer,Dolph
and Ambrosetti-Prodiproblems
for the operator A, al-ways with
L 1 (S2 )
data.1. Introduction.
In this paper we
give
an existence result inL 1 (~ )
for theproblem
where S~ is a bounded open set in N ~
2, f E
and A is alinear, selfadjoint elliptic operator
indivergence
form withcompact resolvent, acting
between and its dual spaceH -1 (,~ ).
(*) Indirizzo dell’A.:
Dipartimento
di Matematica, Universitàdegli
Studi«La
Sapienza»,
P.le A. Moro 5, 00185, Roma,Italy.
Our result will be
comparable
with the results obtainedif f belongs
to
L 2 (~ );
we willactually
find that(1.1)
has a solution if À is not aneigenvalue
of A inL 2 (S~ ) and,
if À is aneigenvalue,
has afamily
of sol-utions that can be written as u = û + p, with u fixed
and a belonging
tothe
corresponding eigenspace. Differently
from theL 2 (S~ )
case, the sol- ution needs not beunique
withoutregularity hypotheses
on the coeffi- cients ofA; however,
it isunique
in a sense that will bespecified
afterwards.
We state now the basic
assumptions
on(1.1).
Let S~ be a bounded open set in
R N
N ; 2.Let Q -
R, i, j
=1, ..., N
be measurable functions suchthat,
ifwe define the matrix
a(z) = (a2~ (x))i, ~ -1...N~
we have:We define the
following
differentialoperator
indivergence
form:Thanks to the
assumptions
on et, A is a linearelliptic operator
act-ing
between and its dualH -1 (S~ ). Moreover,
A isautoadjoint
and has
compact resolvent; then,
it is well known that there exists a se-quence {ki}
of real numbers such that for every i E N it ispossible
tofind at least a
function p belonging
towith ç = 0,
thatsatisfies
Beside
that,
theeigenvalues ~
form anincreasing
sequence of realpositive
numbers thatdiverges
toMoreover,
forevery ki
there isonly
a finite number oflinearly
inde-pendent functions,
that we can consider orthonormal inL2(Q),
that sat-isfy (1.5). So,
for every i we can define theeigenspace Ei
as the linearspace of the
eigenfunctions corresponding
to the sameeigenvalue ki.
Furthermore,
sinceeigenfunctions corresponding
to differenteigen-
values are
orthogonal
inL 2 (S~ ),
we have a sequence of orthonormaleigenfunctions,
that form a Hilbert base ofL 2 (~ ).
We will renameeigenvalues, eigenfunctions
andeigenspaces
so that we havefor every n E N.
It is well known that every 1Jn
belongs
toL °° (~ );
moreover, the di- mensionof El
is one and the firsteigenfunction yi
can be chosenpositi-
ve almost
everywhere.
DEFINITION 1.1. We say that a solution u of a
problem
with datumf belonging
toL1(Q)
is a solution obtainedby approximation,
if u is the limit of a sequence un of solutions of the sameproblem
withL 2 (S~ )
datafn
thatapproximate f
in L(see [1]).
We are
going
to prove thefollowing
resultthat,
asannounced,
willbe similar to the one obtained in the
L 2 (S~ ) theory.
THEOREM 1.1.
Suppose
the(1.2), (1.3)
and(1.4)
hold.Let
f
be afunction in L1(Q).
Let q be a real number with 1 ~ q
N/N -
1. Let ~ be a real num-ber ;
wedistinguish
between two cases.every i. Then
(1.1)
has aunique
soLution u obtainedby approximation,
with u inB) À = À i for
some i.Then, if
( 1.1 )
has afamily of
solutions inW6’
that can be written as u == u + q;, with u
uniquely
obtainedby approximation
and q EEi;
moreover
This paper will be divided into six sections. The second section will contain some technical tools that are needed in order to prove Theorem
1.1,
that will beproved
in section three.In the fourth
section,
we willstudy
the nonlinearproblem
withresonance
where
g(s)
is a bounded function of s that has limit both at + 00 and - oo ; we will see that thisequation
has at least one solutionif f E
satisfies the same condition that is sufficient to have existence of sol- utions in the case
f E L 2 (SZ ).
The fifth section will be devoted to the
study
of theproblem
where
g(s)
is a differentiable function such that thequantities (g(t) -
-
g(s))/(t - s) (for every t
and s inR)
and limg(s)ls
arestrictly
be-s-+=oo
tween two consecutive
eigenvalues
of A. As in the we will obtain the existence of a solution under no additionalhypotheses on f E L1(Q).
Aim of the sixth section will be the
study
of the «Ambrosetti-Prodi»equation
with 9
a twicecontinuously differentiable, strictly
convex functionwith bounded derivative
«crossing»
the firsteigenvalue
of A. We willsee
again
that there is no difference between the result that holds whenf is
anL’(0)
function and ourresult,
withf belonging
toL 1 (S~ ).
2. Some
preliminary
results.This section contains some technical results that will be used to prove Theorem 1.1. The f°lrst one is based on ideas contained
in [2];
forthe sake of
completeness,
we will rewrite theproof.
LEMMA 2.1. Let N > 2. Let m be a real
number,
with1 m
2N/(N
+2).
Let q
= m * =Nm/(N - m). Let 1 gn 1 be a
sequenceof functions of
L 2 (~ ),
bounded in suppose a sequenceof
solutions
of
theproblems
is bounded in
W6’
and there exists a constant c, thatdepends only
on q, a, m andQ,
such thatPROOF. Let r be a real number such that 0 r 1 and define
Since vn belongs
to it can be chosen as test function in(2.1).
We thus
obtain,
thanks to(1.2):
Let now q 2 be a real number that we will choose later. Then we
have,
thanks to Sobolevimbedding,
Hölderinequality
and(2.3):
Now we choose r such that
rq/(2 - q)
=q *,
and(1 - r) m’
=q *;
this
implies
that r =(N( 2 - q))/(N - q)
andthat q
= m *. It is easy tosee that if 1 m
2N/(N
+2)
then the conditions 0 r 1and q
2are fulfilled.
Thanks to this choice of r and q, we have
that can be rewritten as
From
(2.5)
it follows that Wn is bounded inby
a constant.Again by (2.5)
it follows that the norm ofVWn
in isbounded,
up toa
constant, by
the norm of gn in and so we have(2.2).
REMARK 2.1. We note
explicitly
that the conditionm 2N/(N + 2 ) implies
that m*2; i.e.,
we cannot have wn bounded inHJ(Q).
Thecondition N > 2 is due to the fact
that,
for N =2,
we have2N/(N
++ 2) = 1.
Now we
give
the same result of Lemma2.1,
but with m =1;
in thiscase,
however,
we do not have boundedness of the wn in ac-tually,
we obtain that thegradients
of wn are bounded in a spacegreater
than This factis justified by Example
2.1 below.Moreover,
for purposes that will beexplained afterwards,
we do notgive
estimates on the solutions of(2.1),
but on some solutions Wn of(1.1);
we will also need an additionalhypothesis
on wn.LEMMA 2.2. Let q be a reacl number with
1 ~ q N/(N - 1 ).
Letgn 1 be a
sequenceof functions
inL 2 (~2 )
that is bounded inL1(Q);
sup- pose a sequenceof
solutionsof ( 1.1 )
with data gn;z. e.,
Suppose
is bounded inL 1 (~ ).
is bounded inW6’ q(Q)
.Moreover, if ~
=0,
there exists a constant c, thatdepends only
on q,« and
Q,
such thatPROOF. The
proof
isessentially
the same of Lemma 2.1. We choose areal number r with
r > 1,
and define vn =(1- ( 1
+1 wnl )1-r) sgn (wn).
Choosing vn,
as test function in(1.1)
wehave,
since1
1for the boundedness of both Wn
and gn
inL1(Q).
Thanks to thisinequali-
ty, (2.4)
becomesNow we choose r such that
rq/(2 - q)
=q * ;
thisimplies
that r =- (N( 2 - q ))/(N - q ),
and so the condition r > 1 is fulfilled if andonly
ifq
N/(N - 1).
If N > 2 wehave,
with this choice of r and q, thatq/q *
> 1 -q/2
and so we obtain the boundedness in hence in N =2,
sinceq/q *
= 1 -q/2,
we have boundedness of Wn in if we add thehypothesis
c31;
thisinequality
is fulfilled ifthe norms of gn and Wn in
L 1 (D)
are small.But,
sinceproblem (1.1)
islinear,
we canalways
reduce ourselves to this case,by eventually
di-viding
both Wnand gn by
aconstant,
so that we obtain our result also in the case N = 2.If À = 0 we obtain
(2.6) observing
that c3 is a constantmultiplied by
the norm of gn inL~(~û)
andreasoning
as in theproof
of Lem-ma 2.1.
EXAMPLE 2.1. Let 0 =
B1~2( o) _ ~x
ER N: Ixl [ 1/2}.
Let 0 be a real
number;
define,It is
easily
seen that if 0 >1,
thenf belongs
to but does notbelong
to for any p > 1.Now we consider the
following problem
Since
f depends only
on the modulus of x, we seek radial solutions u;that
is,
we suppose that2c(x)
=v( 1 xl)
=v( p); passing
topolar
coordi-nates,
we have that v solves theequation
If we define
w( p )
= thenIntegrating
thisequation,
we haveand so
If we choose 0 > 1 such that
N/(N - 1)
6 -1,
that is to say if 1 0 2 - then Vu does notbelong to
but is forevery q
N/(N - 1). So,
we have found that Lemma 2.2 issharp: f in L’(0) implies
that ubelongs
toWô ~ q (~ )
for every qN/(N - 1)
butnot for q =
N/(N - 1).
Now we recall that
if f E L2(~),
then(1.1)
has aunique
solution if h is not aneigenvalue
of A. On thecontrary, if À = Ài
forsome i,
then(1.1)
can be solved if andonly if f E Eil,
where is the linear space of the funetions inL 2(o)
that areorthogonal
inL 2 (~ )
to every function inEi;
in this case there exists aunique u
EEil
such that any solution of(1.1)
can be written as ù+ P, with q
inEi.
From now on, when we say that u is a solution of
(1.1)
with data inL 2(i2)@
we will mean either a solution of(1.1)
when À is not aneigen- value,
or îî(as
definedbefore) when k = k
i for some i.The
following
result will be used in theproof
of Theorem1.1,
wherewe will deal with
approximated equations.
LEMMA 2.3. Let
q be
a realnumber,
with 1 ~ qN/(N - 1 ).
Leta sequence
of functions
inL 2 (S~ )
suchthat for
every n e N there exists a solution vnof
Suppose that fn
tendsstrongly
to 0 inL1(Q)
as n tends to + 00 and that vn is bounded inL 1 (~ ).
Then vn tends to 0weakly
inWJ’
PROOF. Let k E N be the
(unique)
number such thatWe note that with this choice of 1~ we have that
Now we
define, for j
eN, p(i)*
as the Sobolevimbedding exponent
forWlo"(Q)
i.e.we also define
p ~°~*
= p.We choose now a real
number p
such thatand
This
inequality, by
the choice ofk,
is fulfilled if andonly
ifwe can find such a p since N
2(k
+1) implies
that2N/(N
+2k) N/(N - 1). Moreover,
if k >1,
sincep~~-1~* N/(N - k),
we haveIf we define
v(1)
= vn , we have that solves theequation
Since is bounded in
L’(0),
we canapply
Lemma 2.2(with
Wn =and gn = fn );
it follows that is bounded in for every q such that 1 ; qN/(N - 1).
Inparticular,
it is bounded in(where
p is the number that has been chosenbefore)
and so inMoreover,
itweakly
converges in(up
to asubsequence
that wewill call
again
to a functionIf k > 1
(i.e.,
if N >2),
weconsider,
forany j
=2,
...,k,
a sequence of solutions of theequation
Since is bounded in
LP(Q)
and p2N/(N
+2),
we canapply
Lemma 2.1
(where
we choose w =V(2) g
=Àv(1)
and m =p);
we ob-tain that is bounded in
W6’ P (Q)
and so inNow we go on with this
method;
we canrepeatedly apply
Lem-ma 2.1 since is bounded in
LP’j-"’(0)
andp‘~-2’* ~ p(k-2)*
2N/(N
+2) by
thehypotheses
on p.p(k - 1)*
At the last
step,
we obtain that is bounded in and so, thanks to Sobolevimbedding,
in But from thehypotheses
on p we have
p ‘k~‘ ~
2 and so is bounded inL 2 (~ ).
Now we consider the sequence E of solutions of the
equations
choosing
as test function in thisequation,
weeasily obtain, by
theHôlder and Poincaré
inequalities
andby
the boundedness ofvnk)
inL 2 (~ ),
thatand so
vnk + 1)
is bounded inthus,
itweakly
converges in up to asubsequence
that we will callagain
to a functionV(k+ 1).
Now we substract the
equations
satisfiedby as j
ranges from 1 to k + 1. We obtainand, going
on until the k-thstep,
Now we can
apply
Lemma 2.2 to the first of theseequations:
from(2.6)
it follows thatvn2’ -
tends to 0strongly
in and so insince fn
tends to 0 inthen,
from the secondequation
andfrom Lemma 2.1 it follows that
và3) - Và2)
tends to 0strongly
inWô ~ p ‘l’* (S~ )
and so inL p ‘l’* (S~ ). Going
on, we obtain thatvnk + 1) - v)’
tends to 0
strongly
in This means that every sequencevn’’
has the same limit in that is
obviously v ~ l’.
Sov ‘k + 1>
=v c 1 >;
this
implies
that itself is inPassing
to the limit in(2.8),
we obtainNow we have two
possibilities;
if k is not aneigenvalue
thensince
(2.10)
has aunique
solution inIf ~ _ ~
i forsome i,
then now we recall that we havechosen all the
vn1 ~
inE/-,
and since theorthogonality
relation passes to the limitby Lebesgue theorem, by
thestrong
convergence of tov ~ 1 ~
in andby
the factthat q j i belongs
to L °°(~ ),
we have that alsobelongs
to these two factsimply again
that = 0.So,
up to asubsequence, vnl ~ = vn --~ 0 weakly
in nowwe recall
that vn
is bounded intVj’
for every q such that 1 ~ qN/(N - 1)
and so itweakly
converges, up to asubsequence,
to afunction v that is
obviously
0. Since anyconverging subsequence
of v,, has the samelimit,
that is zero, we can conclude that the whole sequene Vn tends to zero inWJ’ q(D),
for every q such that 1 qN/(N -
- 1 ).
REMARK 2.2. We note
explicitly
that(2.10)
has been foundusing only
the factthat vn
was bounded inL1(Q)
and the convergenceof fn
to0 in
L1(Q).
This means that we can conclude thatequation (2.10)
holds notonly
inW6’
but also in every time we obtain itpassing
tothe limit in
equations
thatsatisfy
thehypotheses
of Lemma 2.3.REMARK 2.3. If A is an
elliptic operator
withregular
coefficients(for example,
A= - d)
the fact thatv ~ 1 ~
= 0 followsimmediately
from apassage to the limit in the
equation
satisfiedby
Vn, i.e. in(2.8).
Actual-ly,
we obtain that satisfies theequation
By
means of«bootstrap» arguments,
we have thatbelongs
toNow we can make the same remarks as in the
proof
of Lemma2.3 to obtain = 0.
If A is more
general,
as in thepresent
case, this method cannot be used if the solution is not apriori
in see[3]
for acounterexample
about the lack of
uniqueness
when the solution is notregular.
Now we need the last
result, concerning
thepossibility
ofapproxi- mating
an function withL 2 (~ )
functions thatsatisfy
someconditions.
LEMMA 2.4. Let p be a real numbers.
Let f be a ficnction in L 1 (Q).
Suppose that, for some i,
Then there exists a sequence
of functions of
suchthat:
PROOF.
Let fn
be a sequence of functions inL2(S2)
that tendsto f in L1(S~).
We defmee
Let
now fn = fn - 1 (tni -
ip),p i
i* FromLebesgue
theorem and from.
gu
the
hypothesis
we have as n - oo, for everyj.
If wechoose fn
as ourapproximating
sequence, we have that(2.11)
holds true(by
theorthonormality
of thepi
inL2(0»;
moreoverand the latter
expression
tends to 0 as n tends toinfmity. 8
3. Proof of Theorem 1.1.
We are
going
togive
theproof
of Theorem 1.1. We will use the tools introduced in the last section to show the boundedness of someapproxi- mating
solutions of(1.1).
The idea is to
approximate f
withL 2 (S~ ) functions,
solve theprob-
lems with these functions as
data,
and then show that these solutions converge to a solution of(1.1).
As a firststep
we will choose the ap-proximating functions;
wedistinguish
between two cases.A) Suppose
that À is not aneigenvalue. Let fn
be any sequence of functions inL 2 (S~ )
thatapproximates f in L 1 (~ ).
Then there exists a se-quenee lunl
of solutions of(1.1) with fn
as data.B) If À = Ài
forsome i,
weapproximate f in L 1 (0)
with the se-quenee fn given by
Lemma 2.4 with p =0,
sothat fn
EEi1
for every n.Then, again by
theL 2 (S~ ) theory,
there exists a of sol-utions of
(1.1) with fn
as data. We recall that we consider this sequence contained inNow we are
going
to prove that un is bounded inW6’ ~(~2).
We argueby contradiction, supposing
as a firststep
that Un is not bounded in LIf we define we have that vn solves the equa- tion
Since vn
andfn satisfy
thehypotheses
of Lemma2.3,
wehave
that vn
tends to 0weakly
inand, by
Rellichtheorem, strongly
in since = 1 we have a contradiction.So,
Un is bounded inL1(Q). Now,
weapply
Lemma 2.2(with
wn == un
and gn
=fn )
to obtain that Un is bounded in Then we extractfrom un
asubsequence
that convergesweakly
in to a function uthat
obviously
solves theequation.
Moreover,
for somei,
since we have chosen Un inEj’
forevery n E
N,
we obtain that also u is inEi1-
and so it satisfies(1.6);
fur-thermore,
it is easy to see that u solvesagain
theequation
forevery y in
Ei.
Now we
approximate f in L1(Q)
with twoof functions in
L2(Q); then,
thecorresponding sequences {u1n}
of solutions have the same limit in
0 (it
suffices tochoose vn
== un - un and gn
in Lemma 2.3 to obtainthis).
So we have shown the lastpart
of Theorem 1.1: the solution u isuniquely
obtainedby approximation (if À = Ài
for somei,
then itsprojection
ontoEi1-
isuniquely
obtainedby approximation).
REMARK 3.1. As it has been said in Remark
2.3,
if A is an opera- tor withregular coefficients,
we can conclude that the solution isunique
for everyf E
L1 (0),
since we can substract theequations
satis-fied
by
two solutions and find that their difference solves ahomoge-
neous
equation; again by
means ofbootstrap arguments,
this solution is in and so it is zero(if À
is aneigenvalue,
then itsprojection
ontoEil
iszero).
Anyway
this fact is notenough
to conclude aboutuniqueness:
we canonly speak
ofuniqueness
ofapproximated solutions;
forinstance,
thecounterexample
of Serrin(see [3])
is about anequation with f =
0 that hasboth a zero solution and a non zero one; our method obtains
only
the for-mer, that
is,
in a sense,«natural»,
while the other is«pathological».
REMARK 3.2. Without any
change
it is alsopossible
to prove thefollowing result,
in which(as
in[2]
for theequation A(u) = f )
we obtainmore
regularity
on u if we increase theregularity on f.
THEOREM 3.1.
Suppose
that(1.2), (1.3)
and(1.4)
hold.Let m be a real number with 1 m
2N/(N
+2).
Let
f
be afunction in Lm(Q).
Let q
= m* =m).
Let h be a realnumber;
wedistinguish
between two cases.
A) J, ~ Xi for
every i. Then(1.1)
has aunique
solutions u obtainedby approximation,
with u inB) ~
=~i for
some i.Then, if
(1.1)
has afamily of
solutions inW6’
that can be written as u == U
+ ~,
with uuniquely
obtainedby approximation and p
EEi ;
moreover
4. The «resonant» case.
In this
section,
we willstudy
the so-called «Landesmann-Lazer»equation:
with
g(s)
acontinuous,
bounded function. We aregoing
to show thatproblem (4.1)
has at least one solution under the samehypotheses on f
in that are needed in order to have existence in the case
f E L2(Q).
Actually,
we will prove thefollowing
THEOREM 4.1. Let g: R ~ R be a continuous
function;
suppose that there existthat g ± E R and that
Let
f
be anL 1 (S2 ) function
such thatThen there exists at least one solution u
of (4.1);
rnoreover, u be-Longs
toWô ~ q (~ ), for
every real number q such that1 ~ q N/(N -1 ).
PROOF. We
proceed by approximation,
as usual. We consider a se-quence fn
of functionsbelonging
toL2(Q)
andconverging to f in
such that
each fn
satisfies(4.3).
Such a sequence can be found thanks to Lemma 2.4(where
we choose p= j dx).
As it is well known
(see [4]), condition (4.3)
for anL 2 (S~ ) function fn
is a sufficient condition for the existence of a solution un of the
problem:
Now we will show that the sequence Un is bounded in for every real number q with
1 ~ q N/(N - 1).
Suppose
that Un is not bounded inL1(Q). Then, reasoning
as in theproof
of Theorem1.1,
we consider the funetionsthat
satisfy
theequations
Since
(fn -
tends to 0 inL1(Q)
andlIVnIIL’(0)
= 1 wehave, by
Remark2.2, that vn
converges in0
to a function v thatbelongs
to and solves theequations
Since we do not know that v
belongs
toEi ,
we cannot conclude di-rectly
that v =0;
we canonly
say that there exists t e R such thatSuppose
that t >0;
then(since p1
> 0 and since Vn converges to v al- mosteverywhere)
we have thatand so, from the definition of g + ,
Now we
multiply equation (4.4) by ç1,
and obtainPassing
to thelimit,
thanks to(4.5)
and to the boundedness of g, wehave
that contradicts
(4.3).
With the same calculations we arrive at a contra- diction also in the case t 0. So we have t =0,
and thisimplies
thatv = 0. But since Vn has norm 1 in and converges
strongly
to v inthe same space, we have
again
a contradiction.So the sequence un is bounded in
L 1 (~ ).
No we canapply
Lemma2.2
(where
wechoose gn = fn - g(u,,»
to obtain that Un is bounded in~(~2),
and so, up to asubsequence
that we will callagain
un, it con-verges
(weakly
inWô ~ q (S~ ), strongly
in anda.e.)
to a function u.Since g
is continuous andbounded, and un
tends to u almost every-where,
we have that tends tog(u)
in for every p, and so usolves the
problem.
5.
Dolph
theorem.In this section we will
study
a semi-linearequation
whose nonlinear term is related to theeigenvalues
of A. We will show that thisequation
possesses at least one solution.
We now state the result:
THEOREM 5.1. Let g: R be a
di, fferentiable function.
Suppose
thatg(O)
= 0 and that there and e > 0 such that:moreover, suppose that there exist
Let
f
be afunction
inL 1 (S2).
Then there exists a
unique
solution obtainedby approximation for
the
equation
Moreover,
ubelongs
toW6’ q(0) for
every q such that 1 ~ qN/(N - 1).
PROOF.
Let fn
be a sequence of functions inL 2 (S~ )
thatapproximate f in Then,
theproblem
has a
unique
solution un in for every n E N(see [5]).
We will prove that un is bounded in
q (~ ),
for every real number q, 1 ~ q1 ).
As a firststep,
we suppose that un is not bound- ed inIf we
define Vn
=then vn
solves theequation
It is
easily
seen that from thehypotheses
on g it follows thatNow we define
so that the former
equation
can be written asSince
hn
is bounded inand vn
is bounded inL1(Q),
weobtain,
as in Lemma
2.2,
that vn is bounded inW6’ q(Q)
and so we can extract from it asubsequence
that converges(weakly
inW6’ q (~ ), strongly
inLq(D)
anda.e.)
to a function v.From the boundedness of
hn
inLoo (Q)
it follows that we can extracta
subsequence
that converges, Loo(Q)-weak-*,
to a function h. More-over,
since A k
+ e~ k + 1 - ~,
thenPassing
to thelimit,
we have that v solves theequation
Since h is a bounded
function,
we can reason as in Lemma 2.3 and obtain that v is notonly
inq (~ ),
but also in(see
Lemma 6.3 below for aproof
of thisclaim).
If a is a bounded measurable
function,
we can define theweighted eigenvalue problem
as follows: we search real numbers~(a)
and mea-surable functions
~(a) ~
0 such thatThen,
it is seenthat,
as in the case a =1,
it ispossible
to fmd a se-quence of
eigenvalues,
withcorresponding eigenfunctions
andeigenspaces;
moreover, thefollowing properties
hold(see [6]).
Now we consider
equation (5.6).
If v is notidentically
zero,then,
since it is in it can be seen as an
eigenfunction
of aweighted problem
withweight h
andeigenvalue
1.So,
there exists i such that= 1.
Since Àk h(x ) hk+1
for almost every x EQ,
from(5.7)
and(5.8)
we have:so that
Since ~ k and Àk+1
1 are two consecutiveeigenvalues of A,
we have acontradiction,
and so v = 0. But this isagain impossible, because vn
hasnorm
equal
to 1 inL 1 (S~ )
and convergesstrongly
to v in the samespace.
So,
Un is bounded in since(5.1) implies
that there exists aconstant el such that
we
have, applying
Lemma 2.2with gn
=g(un),
that Un is bounded inq(Q);
so, we can extractfrom un
asubsequence (that
we will callagain
that converges(weakly
instrongly
in anda.e.)
to a function u.Thanks to the
continuity
of g, to(5.9)
and to thestrong
convergence of Un to u in it follows thatg(un )
converges tog(u)
in the sameso, we can pass to the limit in the
approximate equation,
obtain-ing
that u solves(5.3).
Let
now u’ and U2
be two sequences of solutions of(5.3) correspond- ing
to two sequencesfunctions, f n and f,2,,
thatapproximate f
in
L1(Q).
If wedetine Vn
as the difference betweenun
andU2@ then v.
solves the
equation
where hn
has been defined asAgain, hn
is bounded inL °° (S~ ),
and so it converges inup to a
subsequence,
to a function h.Passing
to the limit we obtain that Vn tends to a function v thatbelongs
toHJ(Q) (see
Lemma 6.3below)
and that solves theequation
Since the
hypotheses
on gimply h(x) Àk+1
almost every-where,
we -can reason as before and obtain that v =0; hence,
we have aunique
solution obtainedby approximation.
6. The Ambrosetti-Prodi theorem.
In this section we are
going
tostudy
the «Ambrosetti-Prodi» equa- tion withdata;
i.e.where g
is a twicecontinuosly differentiable, strictly
convexfunction,
with the
property
thatg(s)/s
«crosses» the firsteigenvalue
of A as svaries on
R, f is
an function suchthat J
and t is a realn
number
(see [7]). Again,
our result will be similar to the one obtained whenf belongs
toL 2(Q).
We are
going
to prove thefollowing
theorem.THEOREM 6.1. Let
g:R -
R be astrictly
convexfunction belong- ing
toC2(R);
suppose thatg(O)
= 0 and that there exist two real num-bers À
and n
withsuch that
Let
f
be anL 1 (S2 ) function
such thatThen there exists a
unique
real number t =t(f)
such that thefol- lowing
holdsA) if
t > t then(6.1)
has no solutions obtainedby approxima- tion,
B) if
t = t then(6.1)
hasexactly
one solution obtainedby
approximation,
C) if t
t then(6.1)
hasexactly
two solutions obtainedby approximation,.
Moreover,
any solutionof (6.1) belongs
toW6’ q (Q), for
every real numbers q such that 1 ~ qN/N -
1.REMARK 6.1. The main difference with the Ambrosetti-Prodi the-
orem lies in the
fact, when fe L 2 (~2 ),
thenequation (6.1)
has no solution when t > t andexactly
one and two solutions when t = t or t trespectively.
Since we
proceed by approximation,
we canonly
say that our sol- utions areuniquely
obtainedby approximation,
andnothing
more.Before
giving
theproof
of Theorem6.1,
we need some technicalresults.
LEMMA 6.1. Let u be an
function,
anddefined, for y E S2,
Then, if
ubelongs
toLP(Q)
and vbelongs
toLP’ (Q),
we havePROOF. The result follows from easy
computations. M
REMARK 6.2. We note
explicitly that,
if ubelongs
toL 2 (S~ ),
thenP(u)
isnothing
but theprojection
of u ontoE1.l.
Now we recall the necessary
steps
in order to achieve theproof
ofthe Ambrosetti-Prodi theorem when
f belongs
toL 2 (S2 ) (see [8]
and [9]).
A solution u of
(6.1)
can be written in the formwith
u(s, f )
eEl’
and s= J
Uq:J11 dx.
Then it is seen thatu(s, f )
solves theequation
~awhile t and s
satisfy
theidentity
Since A - P is coercive on
E11., equation (6.7)
has aunique
solutionfor every s E
R,
sothat,
for tfixed,
the number of solutions of(6.1)
isequal
to the number of roots of theequation r(s)
= t. Thehypotheses
on g
imply
thatr(s)
is a concave function thatdiverges
to - 00 both at+ 00 and - 00 and has a
unique maximum;
if we dermet
to be the maxi-mum of
r(s)
onR,
then we find0,
1 or 2 solutions if t >t,
t = t or t trespectively.
Now we
begin
tostudy equation (6.7) when f belongs
toL1(Q).
The’first result is similar to Lemma 2.2.
LEMMA 6.2. Let q be a real
number,
with 1 ~ qN/(N - 1).
Let s be a real number. be a sequence
of L 2 (~ ) functions
that is bounded in and such = 0
for
everyn E ~T. 0
be a sequence
of
measurablefunctions
that is bounded in L 00(Q).
Suppose
that there exists ac E11. of
solutionsof
theproblem:
Suppose
that wn is bounded inL 1 (~ ).
Then there exists a constant c, that does notdepend
on n, such thatPROOF. Let r be a real
number,
with r > 1.Let vn
=(( 1
+1 Wn 1 )l - r - 1 ) sgn (wn)
and chooseP(vn)
as test func-tion in
(6.9). Since p1
and Wn areorthogonal
in for every n, weobtain, by (6.6),
Since
vn ~ ~ 1,
we haveby
thehypotheses
on wn ,fn
andhn.
The end of theproof
is achievedexactly
as in Lemma 2.2. aThe
following
result is theanlogous
of Lemma 2.3.Again,
if thedata tend to zero in the limit solution is zero if we add some
hy- potheses
on the sequencehn.
LEMMA 6.3. Let q be a real
number,
with 1 ~ qN/(N - 1).
be a sequence that tends to zero in
L1(Q)
and such dx = 0
for
every n E N.be D a
sequenceof
measurablefunctions
that is bounded in LOO(Q);
so we can extract asubsequence
that converges, Loo(Q)-weak-*,
to a
function
h. We suppose thatSuppose
that there exists a sequence cE 11. of
solutionsof
theproblem
Suppose
that vn is bounded inL 1 (~ ).
Then vn tendsweakly
inW6’
to zero.PROOF. The
proof
isessentially
the same of Lemma2.3;
we fix kand p
and construct the sequences = vn , @vn2~, ... , vnk+ 1>
that solvethe
equations
The
regularity
estimates on the are still valid thanks to the boundedness ofhn,
to Lemma 6.2 and to the fact that P is continuous between and for anyp ;
1(this
is an easy consequence ofthe definition of
P).
As in theproof
of Lemma2.3,
we have thatvnk + 1)
isbounded in and so it
weakly
converges, up to asubsequence
thatwe will call
again vnk + 1>,
to a functionV(k+1)
thatbelongs
toSubstracting
theequations
satisfiedby
the we haveso that all the sequences have the same limit in
Wô ~ ~ (~ ),
thanks to thefact
that fn
tends to zero inL 1 (~ )
andby
the boundednes ofhn;
this lim-it is
obviously So Vn = vn1 ~ weakly
converges to inW6’ P(Q),
and v =
v ~k + l
solves theequation
(we
can pass to the limit since convergesstrongly
toV(k+1)
in)).
Since all
the vn
are inEi ,
then also vbelongs
toChoosing v
astest
function,
we haveSince
on
E11.,
weobtain
0 and so v = 0. This means that the se-quence v~z
weakly converges
to 0 inW6’ P(Q).
Then we can end theproof
as in Lemma 2.3. a
In the
following Lemma,
we state theproperties
of the solutions ofequation (6.7)
when the datumf is
inL 1 (~ ).
LEMMA 6.4. Let q be a real number such that 1 ~ q
N/(N - 1).
Let s be a real number. Let
f
be afunction
inL1(Q)
such that= o.
0
Then there exists u =
u(s, f), unique
solution obtainedby approxi-
mation
of
theequation
in the sense that
for
every testfunction ç
in suchthat f dx
= 0.Moreover,
ubelongs
toWô ° 9(S~).
0Furthermore,
we have thatu(s, f) - u(t, f) belongs
toHJ(Q) for
every s and t in R and there exists a constant c such that
PROOF.
Let fn
be a sequence functions thatapproximate f
in and such
that
= 0 for every n e N(such
a sequence isgiven by
Lemma 2.4 with p =0).
Consider the sequence Un =fn )
of solutions of
equation (6.7).
We aregoing
to show that Un is boundedin
As
usual,
webegin
theproof arguing by
contradiction and suppos-ing
that Un is not bounded inL1(Q). Then,
we define Vn =so that Vn solves the
equation
Now we define