• Aucun résultat trouvé

COMPACT IMBEDDINGS IN ELECTROMAGNETISM WITH INTERFACES BETWEEN CLASSICAL MATERIALS AND META-MATERIALS

N/A
N/A
Protected

Academic year: 2022

Partager "COMPACT IMBEDDINGS IN ELECTROMAGNETISM WITH INTERFACES BETWEEN CLASSICAL MATERIALS AND META-MATERIALS"

Copied!
21
0
0

Texte intégral

(1)

INTERFACES BETWEEN CLASSICAL MATERIALS AND META-MATERIALS

LUCAS CHESNEL AND PATRICK CIARLET JR.

Abstract. In a meta-material, the electric permittivity and/or the magnetic permeability can be negative in given frequency ranges. We investigate the solution of the time-harmonic Maxwell equations in a composite material, made up of classical materials, and meta-materials with negative electric permittivity, in a two-dimensional bounded domainΩ. We study the imbedding of the space of electric fields intoL2(Ω)2. In particular, we extend the famous result of Weber, proving that it is compact. This result is obtained by studying the regularity of the fields. We first isolate their most singular part, using a decompositionà laBirman-Solomyak. With the help of the Mellin transform, we prove that this singular part belongs to Hs(Ω)2, for somes > 0. Finally, we show that the compact imbedding result holds as soon as no ratio of permittivities between two adjacent materials is equal to−1.

Key words. Maxwell’s equations, interface problem, meta-material, compact imbedding, regu- larity of fields, Mellin transform.

AMS subject classifications.

1. Introduction. We consider the solution of the time-harmonic Maxwell equa- tions in a composite material. A composite material is modelled by non constant electric permittivity ε and magnetic permeability µ. The variations of εand µ can be smooth, or piecewise smooth. Recently, some new composites appeared, includ- ing classical materials and meta-materials. A meta-material exhibits special prop- erties. In given frequency ranges, it can behave like a material with negative elec- tric permittivity or/and negative magnetic permeability. Examples of meta-materials [25, 26, 27, 12] include superconductors, left-handed materials, etc. Due to the sign change between a classical material and a meta-material, the usual mathematical ap- proaches fail to resolve the corresponding electromagnetic models. In other words, these composites raise challenging questions, both from the mathematical and numer- ical points of view.

In this paper, we focus on an essential tool to study time-harmonic Maxwell equa- tions in a bounded (connected) domain Ω of Rd (d is the space dimension), that is the compact imbedding of the space of electric fields inL2(Ω)d. This result is indeed a key ingredient to solve the two instances of time-harmonic equations, namely the source problem (sustained vibrations) and the eigenvalue problem (free vibrations).

If the domain of interest is surrounded by a perfect conductor, the following functional space for electric fields,XN(Ω, ε), appears. It is made up of vector fieldsv that belong toL2(Ω)d, and such thatcurlv∈L2(Ω)d, div(εv)∈L2(Ω)andv×n= 0 on∂Ω, where nis the unit outward normal vector to ∂Ω.

Our main objective is to find an extension of the Weber compact imbedding theorem in the case of a composite material including classical and negative meta- materials. In the landmark paper [28], Weber proved that XN(Ω, ε) is compactly

Laboratoire POEMS, UMR 7231 CNRS/ENSTA/INRIA, ENSTA ParisTech, 32, boulevard Vic- tor, 75739 Paris Cedex 15, France;email: [email protected]

Laboratoire POEMS, UMR 7231 CNRS/ENSTA/INRIA, ENSTA ParisTech, 32, boulevard Vic- tor, 75739 Paris Cedex 15, France;email: [email protected]

1

(2)

imbedded intoL2(Ω)d whenεis a real function, bounded above and below by strictly positive constants, ford= 2,3.

In [9], the second author and co-workers prove this result for d = 3, in the following setting. The domainΩis partitioned into two subdomainsΩ1andΩ2, with a smooth interface (between the subdomains), and withεexhibiting a sign-changeat the crossing of the interface. This new result is proved under the assumption that the contrastκε (which is just κε|Ω1|Ω2 whenε is constant in each subdomains) is such that κε ∈/

κiε; κsε

, with −1 ∈ κiεsε

. The proof is direct, in the sense that the classical result stating that the imbeddings ofHs(Ω)into L2(Ω) are compact for s >0, is not used. Our method of proof, on the other hand, is to study thea priori regularity of elements of XN(Ω, ε). In this respect, it follows what has been done in proposition 3.7 of [1], or section 3 of [14], or in part 3.8 of [23], but it relies on different mathematical tools. More precisely, we shall prove that the space of electric field XN(Ω, ε) is (continuously) imbedded into spaces like Hs(Ω)d, with some ad hoc s >0 with the help of the Mellin transform, so that one can obtain the desired compactness result by using the classical result mentioned above. Along the way, we shall use several results of [16].

This compactness result is one of the two key ingredient result to prove that the source problem is well-posed, within the Fredholm, or isomorphism+compact, frame- work. The T-coercivity method (see [10]), or the three-field variational formulation (see [9]), then help obtaining the second key ingredient, coerciveness, so well-posedness follows. These two techniques provide some guidelines as to how the problem can be discretized.

In this paper, we shall study the two-dimensional case (d= 2). To simplify the proofs, we assume that the domain Ω has a connected boundary ∂Ω, and that εis piecewise constant. If that were not the case, the regularity results of elements of XN(Ω, ε) should remain valid, under reasonable assumptions, such as a piecewise smooth ε, with |ε| bounded above and below by strictly positive constants, or such as a multiply-connected boundary, which adds a finite dimensional vector subspace of curl-free and divergence-free elements ofXN(Ω, ε), whose elements can be studied separately.

We begin by the notations in section 2. We shall consider the case of a polygonal domain Ω, partitioned into polygonal subdomains. In the next section, we prove a continuous splitting result for elements of XN(Ω, ε), which allows us to isolate the most singular part, expressed as a gradient of a scalar field. Then, in section 4, we study the regularity of this singular part, which leads to the compact imbedding result (§5). We generalize this result in section 6 by assuming that the domain and subdomains are curvilinear polygons. We conclude by providing a counter-example for a symmetric cavity composed of two materials whose permittivities are opposite.

2. Notations. LetΩbe a bounded, open, connected polygonal set ofR2, with connected boundary ∂Ω. The unit outward normal vector to ∂Ω is denoted by n, whereasτ is a unit tangent vector to∂Ω.

We assume thatΩis partitioned intoN open, polygonal subsetsΩj:

Ω =

N

[

j=1

j withΩi∩Ωj =∅ifi6=j.

(3)

We callP the partition. The interface between subdomainsΣ :=∪i6=j(∂Ωi∩∂Ωj)is made up of straight edges. Without loss of generality, we consider convex polygonsΩj, as they can be further subdivided into convex polygons if necessary. Then, to avoid unnecessary technical difficulties, we assume that the N polygons of the partition P can be labelled so thatΩjandΩj+1share at least one common edge, forj= 1.. N−1.

For j = 1.. N, (∂Ωkj)k=1.. nj denote the set of edges of Ωj, and(nkj)k=1.. nj are the corresponding unit outward normal vectors.

Let A denote the set of edges on the boundary ∂Ω (a side of ∂Ω can be divided into two or more edges, due to the partition), or on the interfaceΣ: define Aext :=

{A∈ A |A⊂∂Ω} the set of exterior edges, and Aint := A\Aext the set of inte- rior edges. Similarly, let S denote the set of vertices (new vertices can appear on

∂Ω, due to the partition), andSext :={S ∈ S |S∈∂Ω} the set of exterior vertices, Sint:=S\Sextthe set of interior vertices.

In what follows, the characteristic quantitiesεandµdefining the material, func- tions, etc. arecomplex valued. Let us consider more precisely ε ∈L(Ω), constant over each subdomain Ωj, with εj := ε|j 6= 0. As a particular case, ε can be real valued and exhibit a sign-shift between two neighboring subdomains. For a < b, we define the closed strip of the complex planeB(a;b) :={λ∈C|a≤ <(λ)≤b}.

Using differentiation in the sense of distributions, one classically defines the oper- ators curl and div acting overL2(Ω) :=L2(Ω)×L2(Ω), and the operatorcurl acting overL2(Ω). Forv= (vx, vy)∈L2(Ω),

curlv= ∂vy

∂x −∂vx

∂y ∈ D0(Ω), divv=∂vx

∂x +∂vy

∂y ∈ D0(Ω).

Forv∈L2(Ω),

curlv= ∂v

∂y,−∂v

∂x

!

∈ D0(Ω)× D0(Ω).

Let us introduce the functional spaces H(curl; Ω) :=

u∈L2(Ω)|curlu∈L2(Ω) , H(div;ξ; Ω) :=

u∈L2(Ω)|div(ξu)∈L2(Ω) , whereξbelongs toL(Ω). Next, let

XN(Ω, ε) :={u∈H(curl; Ω)∩H(div;ε; Ω)|u·τ = 0on∂Ω}. Endowed with the normkukX

N(Ω):=

kuk2L2(Ω)+kcurluk2L2(Ω)+kdiv(εu)k2L2(Ω)

12 , XN(Ω, ε) is a Hilbert space. Following Grisvard [18, 19], for any edge ∂Ωkj, we let He12(∂Ωkj) denote the set of elements of H12(∂Ωkj) whose continuation by 0 to ∂Ωj belongs toH12(∂Ωj).

For u∈L2(Ω) (respectively u ∈ L2(Ω)), we use the notation uj :=u|j (resp.

uj :=u|j). To study the regularity of scalar fields, we consider P Hs(Ω,P) :=

u∈L2(Ω)|uj∈Hs(Ωj), j= 1.. N fors >0.

(4)

On P Hs(Ω,P), we introduce the broken norm kukP Hs(Ω) :=

PN

j=1kujk2Hs(Ωj)

12 . We recall that, fors <1/2,kukP Hs(Ω)' kukHs(Ω). The vector valued counterpart is

PHs(Ω,P) :=P Hs(Ω,P)×P Hs(Ω,P).

So, we can introduce the subspace of piecewise smooth elements ofXN(Ω, ε), which writes

HN(Ω, ε) :=XN(Ω, ε)∩PH1(Ω,P).

Finally, we define families of weighted functional (Sobolev) spaces. For a 2-index α= (α1, α2)∈N2, we let

|α|:=α12 and ∂xα:= ∂|α|

α1x ∂α2y. GivenO any open subset ofR2,m∈Nandγ∈R, we introduce

Vγm(O) :=n

v∈L2loc(O)|r|α|−m+γxαv∈L2(O),∀α∈N2,|α| ≤mo whereris the distance to some given point ofO, with norm

kvkVm γ (O):=

 X

|α|≤m

r|α|−m+γxαv

2 L2(O)

1 2

.

To conclude,Vmγ(O)is the closure ofD(O)in Vγm(O).

3. A continuous splitting of fields of XN(Ω, ε). Let us prove a continuous splitting of fields that belong to XN(Ω, ε). This kind of result can be traced back to the works of Birman-Solomyak [5, 4, 6, 7]. We give here a proof that follows the lines of those of theorems 3.4 and 3.5 of [14]. By assumption, the partitionP ofΩis labelled so thatΩj and Ωj+1 share at least one common edge, forj = 1.. N−1: we call(Aj)j=1.. N−1 these edges.

Proposition 3.1. Let u ∈ XN(Ω, ε). There exist u1 ∈ HN(Ω, ε) and u2 ∈ XN(Ω, ε)with(curlu2,1)L2(Ωj)= 0 forj = 1.. N, such that

u=u1+u2. In addition, one has the stability estimate

ku1kPH1(Ω)+ku2kX

N(Ω)≤CkukX

N(Ω) (3.1)

where the constant C is independent ofu.

Proof. For anyw∈XN(Ω, ε), we definemj(w) := (curlw,1)L2(Ωj), forj= 1.. N.

To prove our claim, let us build explicitly a family (fj)j=1.. N−1 of elements of HN(Ω, ε), such that

u2=u−

N−1

X

i=1

cifi withci =

i

X

k=1

mk(u), i= 1.. N−1 (3.2)

(5)

automatically fulfills the conditionsmj(u2) = 0,j = 1.. N.

For j = 1.. N −1, let nj be the unit normal vector to Aj, going from Ωj to Ωj+1, andτj such that (τj,nj)is a direct, orthonormal basis. Let Mj be a given interior point of Aj, and let rj be the distance toMj. Next, define fj :=Cjζj(rjj, with a positive-valued function ζj ∈ D(R+), equal to 1 in a neighborhood of 0, with support such that suppfj ∩ S = ∅ and (suppfj ∩ A) ⊂ Aj. The constant Cj

is chosen so that (curlfj,1)L2(Ωj) = R

Ajfj ·τj = 1. Note that, by construction, fj|j·τ−fj|j+1·τ= 0andεfj|j·nj−εfj|j+1·nj = 0. Sincefj is smooth on Ωj andΩj+1 (and supported inΩj∪Ωj+1), we infer thatfj∈HN(Ω, ε).

Now, let u2 =u−PN−1

i=1 cifi ∈ XN(Ω, ε)be defined as in (3.2), and let us check thatmj(u2) = 0,j= 1.. N. First, for1≤j≤N,1≤i≤N−1, we remark that

mj(fi) =

1 ifj=i

−1 ifj=i+ 1 0 else. So, we have

m1(u2) =m1(u)−

N−1

X

i=1

cim1(fi) =m1(u)−c1= 0, and, forj= 2.. N−1,

mj(u2) =mj(u)−

N−1

X

i=1

cimj(fi) =mj(u)−cj+cj−1= 0.

On the other hand,

mN(u2) = mN(u) +cN−1 =

N

X

i=1

mi(u) = 0because u·τ= 0 on∂Ω.

Finally, let u1 := PN−1

i=1 cifi ∈ HN(Ω, ε). For i = 1.. N −1, there holds |ci| ≤ Pi

k=1|mk(u)| ≤Pi k=1

p|Ωk| kcurlukL2(Ωk) ≤Pi k=1

p|Ωk| kukX

N(Ω). As a conse- quence,ku1kPH1(Ω)≤C1kukX

N(Ω). This leads to (3.1), as ku2kX

N(Ω)≤ ku1kX

N(Ω)+kukX

N(Ω)≤C2ku1kPH1(Ω)+kukX

N(Ω). Theorem 3.2. Let u∈XN(Ω, ε). There exist u0 ∈HN(Ω, ε) andϕ∈H01(Ω) with div(ε∇ϕ)∈L2(Ω), such that

u=u0+∇ϕ.

Furthermore, one has the stability estimate

ku0kPH1(Ω)+k∇ϕkL2(Ω)+kdiv(ε∇ϕ)kL2(Ω)≤C kukX

N(Ω)

where the constant C is independent ofu.

Proof. Letu∈XN(Ω, ε). Thanks to proposition 3.1, there existu1∈HN(Ω, ε) andu2∈XN(Ω, ε)such thatu=u1+u2, with(curlu2,1)L2(Ωj)= 0, forj= 1.. N.

In addition, we have the estimate

ku1kPH1(Ω)+ku2kX

N(Ω)≤C1 kukX

N(Ω).

(6)

Let us begin by a study of u2. Thanks to the assumption (curlu2,1)L2(Ωj) = 0, for every j = 1.. N, there exist one, and only one up to a constant, φj in H1(Ωj) that solves

−∆φj =curlcurlφj = curlu2 inΩj

∂φj

∂nj = 0 on∂Ωj. (3.3)

All polygons Ωj are convex, so φj ∈ H2(Ωj) (cf. theorem 2.4.3 of [19]). Next, we define v ∈ L2(Ω) by v|j = curlφj, for j = 1.. N: it belongs to PH1(Ω,P), and kvkPH1(Ω)≤C2 kcurlu2kL2(Ω). In addition, forj = 1.. N,k= 1.. nj, there holds

v·τkj = ∂φj

∂nkj = 0 (3.4)

where τkj is such that (τkj,nkj) is a direct, orthonormal basis. Consequently, curlv belongs toL2(Ω), andw:=u2−v ∈H(curl; Ω)is curl-free. According to theorem 2.9 of [17, chapter 1] and thanks to the connectedness of ∂Ω, there exists one, and only oneϕ1∈H01(Ω) such that

w=∇ϕ1. So far,uhas been split as

u=u1+v+∇ϕ1

where u1 ∈ HN(Ω, ε), v ∈ PH1(Ω) and ϕ1 ∈ H01(Ω). However, except when ε is constant over Ω, div(εv) does not belong to L2(Ω). Using either theorem 1.5.2.8 of [18] or theorem 1 of [3], one can lift the normal trace of vj on∂Ωj, resulting in r∈P H2(Ω,P)∩H01(Ω)such that rj ∈H2(Ωj)∩H01(Ωj)that fulfills

∂rj

∂nkj|∂Ωk

j = vj·nkj

|∂Ωk

j, k= 1.. nj, j= 1.. N and krkP H2(Ω)≤C3 kvkPH1(Ω).

Note that this is possible as soon as vj·nkj

|∂Ωk

j ∈He12(∂Ωkj): as a matter of fact, there holdsvj·nkj = ∂φj

∂τkj ∈He12(∂Ωkj), because ∂φj

∂nkj0 = 0for allk0 = 1.. nj. Define nextu3:=v− ∇r. This field is such that

i) u3∈L2(Ω) ii) u3|j ∈H1(Ωj)

iii) curlu3=curlv=curlu2∈L2(Ω) iv) u3·τ|∂Ω=v·τ|∂Ω− ∇r·τ|∂Ω =

cf. (3.4)

−∇r·τ|∂Ω =

r∈H01(Ω)

0.

Now, as εju3|j·nkj

|∂Ωk

j = 0,k= 1.. nj, j= 1.. N, one obtains div(εu3)∈L2(Ω).

Combining those arguments allows us to conclude thatu3∈HN(Ω, ε) =XN(Ω, ε)∩ PH1(Ω,P).

Letϕ:=ϕ1+r∈H01(Ω) andu0:=u1+u3. By construction u=u0+∇ϕ

(7)

with div(ε∇ϕ) =div(εu)−div(εu0)∈L2(Ω). Also

ku0kPH1(Ω) ≤ ku1kPH1(Ω)+kvkPH1(Ω)+k∇rkPH1(Ω)

≤ ku1kPH1(Ω)+ (1 +C3)kvkPH1(Ω)

≤ ku1kPH1(Ω)+C2(1 +C3)kcurlu2kL2(Ω)

≤ C1(1 +C2(1 +C3))kukX

N(Ω)

k∇ϕkL2(Ω) ≤ ku−u0kL2(Ω)

≤ kukX

N(Ω)+ku0kL2(Ω)

≤ (1 +C4)kukX

N(Ω)

and kdiv(ε∇ϕ)kL2(Ω) ≤ kdiv(εu)kL2(Ω)+kdiv(εu0)kL2(Ω)

≤ kdiv(εu)kL2(Ω)+C5 ku0kPH1(Ω)

≤ (1 +C4C5)kukX

N(Ω)

whereC4:=C1(1 +C2(1 +C3))et C5:= max

jj|.

4. A study of the regularity. Recall that Ω is a bounded, open, connected polygonal set ofR2, with connected boundary∂Ω. In this section, we show that, under some assumptions that will be described later on, the scalar potential ϕ ∈ H01(Ω) that appears in the splitting of theorem 3.2 is actually “more regular thanH1”. More precisely, we prove that there existsσ0>1, which depends only onΩ, on the partition and onε, such that one hasϕ∈ ∩s < σ0Hs(Ω).

Let us consider the unbounded operatorF inL2(Ω):

D(F) :=

u∈H01(Ω)|div(ε∇u)∈L2(Ω)

F u := div(ε∇u) . (4.1)

Now, we study the regularity of an elementu∈D(F). From time to time, we shall use the notationf :=F u=div(ε∇u)∈L2(Ω).

Let us begin by some well-known results. Classically (chapter 2, volume 1 of [22];

theorem 2.1.3 of [19], or [2]), the following interior regularity holds.

Theorem 4.1. Let Obe an open subset ofΩsuch thatO ∩ S=O ∩ A=∅. Then ubelongs toH2(O), with estimate

kukH2(O)≤C

kdiv(ε∇u)kL2(Ω)+k∇ukL2(Ω)

where the constant C is independent ofu.

Furthermore, theorem 2.1.4 of [19] provides the following regularity result around exterior edges.

Theorem 4.2. Let O be an open subset ofΩ such thatO ∩ S =O ∩ Aint =∅.

Thenubelongs toH2(O), with estimate kukH2(O)≤C

kdiv(ε∇u)kL2(Ω)+k∇ukL2(Ω)

where the constant C is independent ofu.

4.1. Regularity at interior edges: preliminaries. Let M be an interior point ofA∈ Aint. Assume thatΩ1 andΩ2 are the two subdomains of P such that Ω1∩Ω2=A. Considerdsmall enough so thatB(M, d)∩S=∅and(B(M, d)∩A)⊂A

(8)

where B(M, d) denotes the open ball of centreM and radiusd. Evidently, the fact that the value ofεjumps atApreventsa prioriuto belong toH2(B(M, d)). However, using a technique based on partial Fourier transform alongside one direction, we shall prove thatuj ∈H2(B(M, d)∩Ωj), j = 1,2. The proof of this result can be found in [16] (theorem 2.1). We will give a slightly different version using the T-coercivity approach (see [10, 8] for more details concerning this technique).

Let us begin by some geometric notations. Let(r, θ)denote the polar coordinates with respect to M. The angular coordinateθ is chosen arbitrarily. Letχ ∈ D(R+) be such that0≤χ≤1, equal to 1 on[0;d], with support contained in[0;dM]. Here dM > dis small enough so thatB(M, dM)∩S =∅and(B(M, dM)∩A)⊂A. Define the radial cutoff functionχM : (r, θ)7→χ(r)and the infinite stripsI:=R×I,Ij:=R×Ij, j= 1,2, with respectivelyI:= ]−dM;dM[,I1:= ]−dM; 0[andI2:= ]0;dM[. Without loss of generality, we suppose thatA⊂R× {0}, (B(M, dM)∩Ωj)⊂ Ij,j= 1,2.

Now, we localize the study of the regularity with the help of χM. Let f˜be the extension of f = F u = div(ε∇u) by 0 to I. Consider u := χMu; u belongs to H01(B(M, dM)), so its extensionw:= ˜uby0 toI belongs toH1(I). Consider next

p:=ε(˜u∆χM + 2∇˜u· ∇χM) + ˜f χM, (4.2) which belongs to L2(I), with compact support. According to its definition, w is a solution to the transmission problem in the infinite stripI

(Pstrip)

Findw∈H1(I) such that

εj∆wj =pj inIj, j= 1,2 wj= 0 on∂Ij∩∂I, j= 1,2 w1−w2= 0 on∂I1 ∩ ∂I2

ε1yw1−ε2yw2= 0 on∂I1 ∩ ∂I2.

4.2. Regularity at interior edges: Fourier transform. Applying the Fourier transform with respect to xto the equations of (Pstrip) for λ ∈ Ri, one finds that y7→w(λ, y) :=ˆ R+∞

−∞ e−λxw(x, y)dxis a solution to

( ˆPstrip)

εj2y2 ˆ

wj(λ, y) = ˆpj(λ, y) inIj, j= 1,2 ˆ

w1(λ,−dM) = ˆw2(λ, dM) = 0 ˆ

w1(λ,0) = ˆw2(λ,0)

ε1y1(λ,0) =ε2y2(λ,0).

Let us introduce the symbol related to( ˆPstrip)

Lstrip(λ) : D(Lstrip) −→ L2(I) v 7−→ (ε λ2+dyε dy)v whereD(Lstrip) :=

v∈H01(I)|vj∈H2(Ij), j= 1,2, ε1v01(0) =ε2v02(0) .

Lemma 4.3. Assume that ε12 6= 0. Then Lstrip(λ) is an isomorphism from D(Lstrip)toL2(I)for allλ∈Ri.

Proof. Denote respectively(·,·),(·,·)1,(·,·)2the scalar products of L2(I),L2(I1) and L2(I2). Define τ :=iλ∈R. If ψ is a measurable function onI, we will denote ψj:=ψ|Ij,j= 1,2. Let us introduce the sesquilinear form associated withLstrip(λ).

Forv,ψ∈H01(I), it is defined by a(v, ψ) :=

2

X

j=1

εj(v0j, ψ0j)j2εj(vj, ψj)j .

(9)

Let us distinguish two cases according to the value of the ratioε21.

•Ifε21∈C\R, then the formais coercive onH01(I).

Thus, for every g ∈ H−1(I), there exists a unique v ∈ H01(I) such that (ε λ2 + dyε dy)v=g inI. If moreovergbelongs toL2(I)thend2yv1∈L2(I1)sov1∈H2(I1).

Similarly, v2 ∈ H2(I2). Since Lsym(λ) is continuous from D(Lstrip) to L2(I), one can use the open mapping theorem to conclude thatLstrip is an isomorphism for all λ∈Ri.

•Ifε21∈R, the formais no more coercive onH01(I). Note that, asε126= 0,we know thatε216=−1.

To address this difficulty, we use the T-coercivity method, cf. [10, 8]. Introduce the operators R1, R2 such that (R1v1)(y) = v1(−y), (R2v2)(y) = v2(−y) and the isomorphisms (T1◦T1=T2◦T2=Id) ofH01(I)respectively defined by

T1v:=

v1 onI1

−v2+ 2R1v1 onI2

and T2v:=

v1−2R2v2 onI1

−v2 onI2

. For allv∈H01(I), one can write, using Young’s inequality, for allη >0,

−11 a(v, T1v)| = |(v10, v10)12(v1, v1)1+|ε21|((v02, v20)22(v2, v2)2) +2(ε21)((v02,(R1v1)0)22(v2,(R1v1))2)|

≥ (1−η−121|)((v01, v10)12(v01, v10)1) +|ε21|(1−η)((v20, v02)22(v20, v02)2).

Thus, if|ε21|<1, taking η such that|ε21|< η <1, one infers the existence of a constantC independent ofτ such that

|a(v, T1v)| ≥C((v0, v0) +τ2(v, v)),∀v∈H01(I). (4.3) Since T1 is an isomorphism of H01(I), this proves that for everyg ∈ H−1(I), there exists a uniquev∈H01(I)such that(ε λ2+dyε dy)v=g.

One proceeds similarly in the case|ε21|>1, working withT2. Finally, we conclude as in the caseε21∈C\R.

Remark 4.4. Notice that theT-coercivity method can not be used to deal with the caseε21 = 0, for whichε21=−1. Now, let us study the norm ofLsym(λ)−1, which is an operator fromL2(I)to D(Lsym).

Lemma 4.5. Assume thatε126= 0. Then there exists a constantCindependent of λ∈Ri such that

P2

j=1kvjkH2(Ij)+|λ|2kvkL2(I)≤CkLstrip(λ)vkL2(I), for allv∈D(Lstrip).

Proof. We prove this result in the caseε21∈R\{−1}, the caseε21∈C\R being easier to tackle. Consider v ∈ D(Lsym) and denote g = Lsym(λ)v. Suppose

21| <1. According to (4.3), one can writeC|λ|2(v, v)≤a(v, T1v) = −(g, T1v), withC >0 independent of λ. Noticing that T1 is a continuous operator from L2(I) toL2(I), one obtains the estimation

|λ|2kvkL2(I)≤CkgkL2(I) (4.4) whereC does not depend onλ. On the other hand, sinceεj2+d2y)vj=gj,j= 1,2, one has

d2yvj

L2(Ij)≤CkgkL2(I), j= 1,2. (4.5)

(10)

From (4.3), one can also writeC(v0, v0)≤a(v, T1v), hence

kdyvkL2(I)≤CkgkL2(I). (4.6) Using (4.4), (4.5) and (4.6), we can finally assert the existence ofC >0 independent ofλ∈Risuch that

2

X

j=1

kvjkH2(Ij)+|λ|2kvkL2(I)≤C kgkL2(I), (4.7)

for allv∈D(Lsym).

Working withT2, the case|ε21|>1 can be handled similarly.

SinceLstrip(λ) ˆw(λ,·) =p(λ,·), thanks to lemma 4.5, one obtains

2

X

j=1

kwˆj(λ,·)kH2(Ij)+|λ|2kw(λ,ˆ ·)kL2(I)≤Ckˆp(λ,·)kL2(I), ∀λ∈Ri.

Above,C >0is independent ofλ.

With the help of the Parseval identity (see the lemma 5.2.4 of [21]), one deduces that wj∈H2(Ij),j= 1,2. Besides, there holds the estimate

kw1kH2(I1)+kw2kH2(I2)≤CkpkL2(I).

Using the expression (4.2) ofpand noticing thatχM = 1overB(M, d), one concludes

2

X

j=1

kujkH2(B(M,d)∩Ωj)≤C

kdiv(ε∇u)kL2(Ω)+k∇ukL2(Ω)

.

Let us summarize this result with the

Theorem 4.6. LetObe an open subset ofΩsuch thatO ∩ S=∅ and(O ∩ A)⊂ A= Ωi∩Ωj. Under the assumptionεij6= 0,ui belongs toH2(O ∩Ωi),uj belongs toH2(O ∩ Ωj), with estimate

kuikH2(O ∩i)+kujkH2(O ∩j)≤C

kdiv(ε∇u)kL2(Ω)+k∇ukL2(Ω)

where the constant C is independent ofu.

4.3. Regularity at boundary vertices: preliminaries. To carry out the study in the neighborhood of boundary vertices, we shall follow the method of proof given in [16], which relies itself on the founding paper of Kondrat’ev [20].

As in the study of the regularity at interior edges, let us begin by some geometric notations. ForS∈ Sext, let(r, θ)denote the polar coordinates with respect toS. The angular coordinateθis chosen in such a way that, ford >0small enough, there holds

B(S, d)∩Ω ={(rcosθ, rsinθ)|(r, θ)∈[0;d]×[0;θmax]}. One has alwaysθmax≤2π.

Next, letdS >0be small enough, so thatB(S, dS)∩ S={S}. Letχ∈ D(R+)be such that 0≤χ≤1, equal to1 on

0;d2S

, with support contained in [0;dS]. Then, the radial cutoff function χS : (r, θ)7→χ(r)is such that suppχS ∩ S ={S}, where suppχS is the support ofχS.

(11)

Define Ω := Ω˜ ∩B(S, dS). We number again the JS subdomains that have S as one of their boundary vertices, from 1 to JS. Further, if we denote by Ω˜j :=

j∩B(S, dS), j = 1.. JS, the new numbering is such that Ω˜j and Ω˜j+1 share one edge, forj= 1..(JS−1), whose angleθgrows withj. Then, forj = 1.. JS,δσjdenotes the interior opening ofΩ˜j (with δσj ≤πbecause Ω˜j is convex), and we setσ0:= 0, and σj :=σj−1+δσj, j = 1.. JS. By definition, there holds P

j=1.. JSδσj = θmax. Finally, we define the intervalsGj:= ]σj−1j[,j= 1.. JS, andG:= ]0;σJS[, and the unbounded angular sectors

Γ :=

(x, y)∈R2|r >0, θ∈G , Γj :=

(x, y)∈R2|r >0, θ∈Gj , j= 1.. JS.

Forv∈L2( ˜Ω)(resp. v∈L2(Γ)), we writevj:=v|˜j (resp. vj :=v|Γj),j= 1.. JS. We introduceΛε, S, the set of singular exponents related to the vertex S, which we define as the set of complex numbersλ∈Csuch that there is a non-zeroJS-tuple (φλ, j)Jj=1S ∈QJS

j=1H2(Gj)which fulfills the conditions below:

2θ2

φλ, j= 0 in Gj, j= 1.. JS

φλ,1(0) =φλ, JSJS) = 0

φλ, jj) =φλ, j+1j) j = 1..(JS−1) εjθφλ, jj) =εj+1θφλ, j+1j) j = 1..(JS−1).

Next, we localize the study of the regularity, usingχS. Letf˜be the extension of f by 0 to Γ. Next consideru:=χSu: ubelongs to H01( ˜Ω), so its extension w:= ˜u by0toΓ belongs toH1(Γ). Consider next

p:=ε(˜u∆χS+ 2∇˜u· ∇χS) + ˜f χS, (4.8) which belongs to L2(Γ), with compact support. According to its definition, w is a solution to the transmission problem

(Psector)

Findw∈H1(Γ) such that

εj∆wj =pj inΓj, j= 1.. JS

w1= 0 on∂Γ1∩∂Γ

wJS = 0 on∂ΓJS ∩∂Γ

wj−wj+1= 0 on∂Γj ∩∂Γj+1, j= 1..(JS−1) εjθwj−εj+1θwj+1 = 0 on∂Γj ∩∂Γj+1, j= 1..(JS−1).

4.4. Regularity at boundary vertices: Mellin transform. For the defini- tion of the Mellin transform, let us recall a classical lemma (see §2, chapter 2 of [24], or Annex AA of [15]).

Lemma 4.7. Let γ∈Rands∈N.

If v∈Vγs(Γ), then one can define its Mellin transform ˆ

v(λ,·) :=Mv(λ,·) = Z +∞

0

r−λv(r,·)dr r

for λ ∈ C such that <(λ) = s−γ −1. Moreover, one has η 7→ v(ξˆ +iη,·) ∈ L2(R, Hs(G)), whereξ:=s−γ−1.

(12)

In the problem of interest,wbelongs to H1(Γ), with a compact support. So, it also belongs toVγ1(Γ), for allγ >0. As a consequence, one can define its Mellin transform

ˆ

w(λ,·)on the complex lines{λ∈C| <(λ) =−γ}, for allγ >0. It follows thatw(λ,ˆ ·) is well-defined over the complex half-plane{λ∈C| <(λ)<0}.

Next, we shall useh:=r2p, wherepis defined in (4.8). Sincep∈L2(Γ)and moreover pis compactly supported,hbelongs toV−2+γ0 (Γ), for allγ≥0. In this case, its Mellin transformθ7→ˆh(λ, θ)is well-defined over the complex half-plane{λ∈C| <(λ)<1}.

Multiplying byr2the volume PDEs in(Psector), and then carrying out the Mellin transform forλ∈Csuch that<(λ)<0, one finds thatθ7→w(λ, θ)ˆ is a solution to

( ˆPsector)

εjθ22 ˆ

wj(λ, θ) = ˆhj(λ, θ) inGj, j= 1.. JS

ˆ

w1(λ,0) = ˆwJS(λ, σJS) = 0 ˆ

wj(λ, σj) = ˆwj+1(λ, σj) j= 1..(JS−1) εjθj(λ, σj) =εj+1θj+1(λ, σj) j= 1..(JS−1).

Next, consider the Mellin symbol related to( ˆPsector)

L(λ) : D(L) −→

JS

Y

j=1

L2(Gj) v 7−→ εj d2θ2

vj

JS j=1

whereD(L) :=

v∈H01(G)|vj ∈H2(Gj), εjvj0j) =εj+1vj+10j), j= 1..(JS−1) . Lemma 4.8. Let λ ∈ B(−1; 1). Then, L(λ) is a bijective map from D(L) to QJS

j=1L2(Gj)if, and only if, there holdsλ /∈Λε, S.

Proof. •Ifλ∈Λε, S, thenL(λ)is not one-to-one, so it is not bijective.

• If λ /∈ Λε, S, then L(λ) is one-to-one. Let us prove that L(λ) is also onto in this case. Let q= (qj)Jj=1S ∈QJS

j=1L2(Gj), and let us build a preimagev ∈D(L)ofq by L(λ).

Consider first the problems, set inGj

(Pja) Findvja∈H01(Gj) such that:

εj d2θ2

vaj =qj in L2(Gj),

j = 1.. JS. For a given indexj, the problem(Pja)is well-posed within the Fredholm framework. But, the operatorTj :=−d2θofL2(Gj), with domainH01(Gj)∩H2(Gj), is self-adjoint with compact resolvent. Its spectrum is equal to

k2π2/(σj−σj−1)2, k∈N . The first (smallest) eigenvalue ofTj2/(σj−σj−1)2, is therefore larger than or equal to1 becauseσj−σj−1≤π. Then, forλ∈ B(−1; 1),λ2 does not belong to the spec- trum of Tj. For the solution of problem (Pja) (for j = 1.. JS), uniqueness follows.

Within the Fredholm framework, this shows that, for allλ∈ B(−1; 1), problem(Pja) has one, and only one, soution vja,j = 1.. JS. Moreover, results on the regularity of solutions to elliptic PDEs indicate thatvja∈H2(Gj)⊂ C1(Gj), j= 1.. JS.

(13)

Next, let us consider the problem

(Pb)

Find(vjb)Jj=1S

JS

Y

j=1

H1(Gj) such that:

εj d2θ2

vjb= 0 inGj, j= 1.. JS

v1b(0) =vJb

SJS) = 0

vjbj) =vj+1bj) j= 1..(JS−1) εjvbj0j)−εj+1vbj+10j) =−αj j= 1..(JS−1)

where the right-hand sideαj is equal toεjvaj0j)−εj+1vj+1a 0j), j= 1..(JS−1).

If(vjb)Jj=1S solves(Pb), then the volume PDEs imply thatvjb(θ) =Ajei λθ+Bje−i λθ (resp. vjb(θ) =Ajθ+Bj) forλ6= 0(resp. λ= 0). Writing the transmission conditions (there are2 (JS−1)of them), together with the two Dirichlet boundary conditions at 0and atσJS, one builds an algebraic set of2JS linear equations, with2JS unknowns.

SinceL(λ)is one-to-one, it follows that(Pb)has one, and only one, solution.

Finally, define v by v|Gj = vja+vjb, j = 1.. JS. It belongs to D(L), and moreover L(λ)v=q. This proves that the operatorL(λ)is onto.

Next, we state a result on the norm ofL(λ)−1.

Lemma 4.9. Assume that εjj+1 6= 0, j = 1..(JS −1). Consider two real numbersα,β withα < β. Then there existη0>0 andC >0 independent of λsuch that,

JS

X

j=1

kd2θvjkL2(Gj)+|λ| kdθvkL2(G)+|λ|2kvkL2(G)≤CkL(λ)vkL2(G), for allv∈D(L)and all λ∈Csuch that|=(λ)|> η0 andα <<(λ)< β.

Proof. This nice result is proved in [16] (lemma 3.6). For the sake of clarity, we reformulate the (slightly modified) proof. Below,C >0 designate constant numbers independent of the functions and of λ. Define the two rectangles R1 := {(s, θ) ∈ R2|1/2< s <2 andθ∈G} andR2 :={(s, θ)∈R2|1/4< s < 4andθ ∈G}. One hasR1⊂R2. Considerζa smooth cutoff function which only depends onssuch that ζ= 1onR1 and suppζ⊂R2. Forv∈D(L), definew: (s, θ)7→ζ(s)eλsv(θ). Using the proof of the theorem 4.6 (cf. §4.2), one can first write

JS

X

j=1

kwjkH2(R1∩Γj)≤C(

JS

X

j=1

j∆wjkL2(R2∩Γj)+k∇wkL2(R2)). (4.9) On the one hand, in the cartesian coordinate system (s, θ), one has ∇w(s, θ) = ((dsζ(s)+λζ(s))eλsv(θ), ζ(s)eλsdθv(θ))and∆(ζ(s)eλsv(θ))(s, θ) =ζ(s)(d2θ2)eλsv(θ)+

2λdsζ(s)eλsv(θ) +d2sζ(s)eλsv(θ). Therefore, one obtains for|λ| 6= 0

JS

X

j=1

j∆wjkL2(R2∩Γj)+k∇wkL2(R2)

≤ C(kL(λ)vkL2(G)+kdθvkL2(G)+|λ| kvkL2(G)).

(4.10)

Sinceds(eλsv(θ)) =λeλsv(θ); dθ(eλsv(θ)) =eλsdθv(θ); d2s(eλsv(θ)) =λ2eλsv(θ);

d2θ(eλsv(θ)) =eλsd2θv(θ); d2s,θ(eλsv(θ)) =λeλsdθv(θ), one has on the other hand

JS

X

j=1

kwjkH2(R1∩Γj)≥C(

JS

X

j=1

kd2θvjkL2(Gj)+|λ| kdθvkL2(G)+|λ|2kvkL2(G)). (4.11)

(14)

Plugging (4.10) and (4.11) in (4.9), one finds PJS

j=1kd2θvjkL2(Gj)+|λ| kdθvkL2(G)+

|λ|2kvkL2(G)≤C(kL(λ)vkL2(G)+kdθvkL2(G)+|λ| kvkL2(G)).That is equivalent to

JS

X

j=1

kd2θvjkL2(Gj)+ (|λ| −C)kdθvkL2(G)+|λ|(|λ| −C)kvkL2(G)≤CkL(λ)vkL2(G).

Takingη0= 2C, one obtains the result of the lemma.

With the help of the analytic Fredholm theorem, one deduces the

Corollary 4.10. Assume thatεjj+16= 0,j= 1..(JS−1). Then there exist two real numbers αS, βS with 0 < αS < 1, 0 < βS < 1 such that (B(−αSS)∩ Λε, S)⊂Ri. In addition, the cardinality of B(−αSS)∩Λε, S is finite.

Using the Parseval identity (see the lemma 6.1.4 of [21]), one can now state an isomorphism result between weighted spaces (theorem 3.7 of [16]).

Theorem 4.11. Assume thatεjj+1 6= 0,j= 1..(JS−1). Letγ∈Rbe such that {λ∈C| <(λ) = 1−γ} ∩Λε, S = ∅. Then, for all P ∈ Vγ0(Γ), there exists one, and only one, solution W ∈V1γ−1(Γ) to the transmission problem

(Psectorγ )

Find W ∈Vγ−11 (Γ)such that:

εj∆Wj=Pj inΓj, j= 1.. JS

W1= 0 on∂Γ1∩∂Γ

WJS = 0 on∂ΓJS ∩∂Γ

Wj−Wj+1= 0 on∂Γj ∩∂Γj+1, j= 1..(JS−1) εjθWj−εj+1θWj+1= 0 on∂Γj ∩∂Γj+1, j= 1..(JS−1).

This solution can be expressed as W : (r, θ)7→W(r, θ) =M−1

L(λ)−1

(r, θ) = 1 2iπ↑

Z

<(λ)=1−γ

rλL(λ)−1Hˆ(λ, θ)dλ withH :=r2P.

Moreover,Wj ∈Vγ2j),j= 1.. JS, with the continuity estimate

kWkV1 γ−1(Γ)+

JS

X

j=1

kWjkV2

γj)≤C kPkV0 γ(Γ).

We already noticed that the right-hand side pthat appears in(Psector) belongs to L2(Γ)with compact support, sop∈Vγ0(Γ)for allγ≥0.

Definition 4.12. Assume that εjj+16= 0, j = 1..(JS −1). Let γ≥0 such that {λ∈C| <(λ) = 1−γ} ∩Λε, S=∅. We denote by w1−γ the solution to (Psectorγ ) with right-hand side equal top.

According to previous results, we know thatw1−γ can be expressed as w1−γ : (r, θ)7→w1−γ(r, θ) =M−1

L(λ)−1ˆh

(r, θ) = 1 2iπ↑

Z

<(λ)=1−γ

rλL(λ)−1ˆh(λ, θ)dλ .

Moreover,w1−γ belongs toV1γ−1(Γ), andw1−γj ∈Vγ2j),j= 1.. JS.

It turns out that, ifεjj+16= 0,j= 1..(JS−1), thenwβS (whereβSappears in corollary 4.10) is well-defined, and moreover it is more regular thanH1. As a matter

Références

Documents relatifs

Several physical problems cannot be investigated by classical potentials, such as quantities and mechanisms closely related to the electronic structure, since the potentials we

0 and 4 respectively; large and These twelve equivalent (neutral) surfaces small squares represent positively can be represented schematically by a charged sites at heights 1

Systematic experiments on near X9 and 213 CSL boundaries in Si, after high temperature compression testing with selected interface orientations, have been combined

In this paper, we study the method of weighted regularization for composite materials and prove the density of the space of piecewise regular vector fields in the space of the

Keywords - Harmonic Maxwell Equations; Electromagnetic Pulses, Electromagnetism; Homogenization; Asymptotic Analysis; Asymptotic Expansion; Two-scale Convergence; Effective

An effective stress tensor that controls the strength of unsaturated granular media is hence proposed and verified based on discrete element modelling (DEM) numerical simulations

Then, it is shown that the frame of the time-harmonic Maxwell’s equations cannot describe the behavior of electromagnetic waves in the situations of the perfect flat lens and

The loss expression in rectangular regions can be both used for the computation of the macroscopic classical loss component (i.e. currents flowing at the scale of the