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MAT137Y1 – LEC0501

Calculus!

Indeterminate forms and L’Hôpital’s Rule

November 28 th , 2018

Jean-Baptiste Campesato MAT137Y1 – LEC0501 – Calculus! – Nov 28, 2018 1

For next week

For Monday (Dec 3), watch the videos:

• Applied optimization: 6.1, 6.2

For Wednesday (Dec 5), watch the videos:

• Concavity: 6.11, 6.12

• Asymptotes: TBA

For Thursday (Dec 6), watch the videos:

• Curve sketching: TBA

Jean-Baptiste Campesato MAT137Y1 – LEC0501 – Calculus! – Nov 28, 2018 2

Computations Compute:

1 lim

𝑥→2

𝑥 2 + 2𝑥 − 6 𝑥 2 + 3𝑥 − 10

2 lim

𝑥→0

𝑒 2𝑥 2 − cos 𝑥 𝑥 sin 𝑥

3 lim

𝑥→∞

𝑥 2 𝑒 𝑥

4 lim

𝑥→∞

𝑒 𝑥 + 𝑒 −𝑥 𝑒 𝑥 − 𝑒 −𝑥

5 lim

𝑥→∞ (sin 𝑥) (𝑒 1/𝑥 − 1)

6 lim

𝑥→∞ 𝑥 sin 2 𝑥

7 lim

𝑥→∞ 𝑥 cos 2 𝑥

8 lim

𝑥→1 [( ln 𝑥) tan 𝜋𝑥 2 ]

Jean-Baptiste Campesato MAT137Y1 – LEC0501 – Calculus! – Nov 28, 2018 3

Limits from graphs Compute:

1 lim

𝑥→0

𝐻(𝑥)

𝐻(2 + 3𝑥) − 1 2 lim

𝑥→2

𝐹 −1 (𝑥) 𝑥 − 2

𝑥 𝑦

1 1

𝑂

𝑦 = 𝐻(𝑥)

𝑥 𝑦

1 1

𝑂

𝑦 = 𝐹 (𝑥)

Jean-Baptiste Campesato MAT137Y1 – LEC0501 – Calculus! – Nov 28, 2018 4

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Backwards L’Hôpital

Construct a polynomial 𝑃 such that lim 𝑥→1

𝑃 (𝑥)

𝑒 𝑥 − 𝑒 ⋅ 𝑥 = 1 𝑒

Jean-Baptiste Campesato MAT137Y1 – LEC0501 – Calculus! – Nov 28, 2018 5

Proving something is an indeterminate form

1 a Prove that ∀𝑐 ∈ ℝ, there exist functions 𝑓 and 𝑔 s.t.

lim 𝑥→0 𝑓 (𝑥) = 0, lim

𝑥→0 𝑔(𝑥) = 0, lim

𝑥→0

𝑓 (𝑥) 𝑔(𝑥) = 𝑐 b Find 𝑓 and 𝑔 such that

lim 𝑥→0 𝑓 (𝑥) = 0, lim

𝑥→0 𝑔(𝑥) = 0, lim

𝑥→0

𝑓 (𝑥) 𝑔(𝑥) = +∞

c Same as above with −∞.

2 Same for ∞

∞ , 0 ⋅ ∞, and ∞ − ∞.

Jean-Baptiste Campesato MAT137Y1 – LEC0501 – Calculus! – Nov 28, 2018 6

Infinity minus infinity

Compute:

1 lim

𝑥→0 [ csc 𝑥

𝑥 − cot 𝑥 𝑥 ]

2 lim

𝑥→∞ [ ln(𝑥 + 2) − ln (3𝑥 + 4)]

3 lim

𝑥→1 [ 2

𝑥 2 − 1 − 1 𝑥 − 1 ]

4 lim

𝑥→−∞ [ √𝑥 2 + 3𝑥 − √𝑥 2 − 3𝑥]

Jean-Baptiste Campesato MAT137Y1 – LEC0501 – Calculus! – Nov 28, 2018 7

Exponential indeterminate forms

Compute:

1 lim

𝑥→0 [1 + 2 sin(3𝑥)] 4 cot(5𝑥)

2 lim

𝑥→∞ ( 𝑥 + 2 𝑥 − 2 )

3𝑥

3 lim

𝑥→0

+

𝑥 𝑥

4 lim

𝑥→0 ( sin 𝑥 𝑥 )

1 𝑥 2

Jean-Baptiste Campesato MAT137Y1 – LEC0501 – Calculus! – Nov 28, 2018 8

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