MAPPINGS OF FINITE DISTORTION:
ZORIC’S THEOREM,
AND EQUICONTINUITY RESULTS
MIHAI CRISTEA
We generalize some known results from the theory of quasiregular mappings, as Zoric’s theorem and some equicontinuity results. These generalizations hold for a special class of mappings with finite distortion satisfying condition (A), which extends the known class of quasiregular mappings, for which some recent modular and capacity inequalities established in [9] are valid.
AMS 2000 Subject Classification: 30C65.
Key words: Zoric’s theorem, Montel’s theorem, mapping of finite distortion.
1. INTRODUCTION
A mapping f : D → Rn, where D ⊂ Rn is a domain, is said to have finite distortion if the following conditions are satisfied:
1) f ∈Wloc1,1(D,Rn);
2) the Jacobian determinant Jf(x) is locally integrable;
3) there exists a finite a.e. measurable functionK:D→[0,∞] such that
|f(x)|n≤K(x)·Jf(x) a.e.
Notice that whenK ∈L∞(D) we obtain the known class of quasiregular mappings, and we refer the reader to [15], [14] for monographs devoted to this subject. Quasiregular mappings are either constant or open, discrete, satisfy condition (N) and a H¨older condition.
If the dilatation mapK ∈ Lploc(D), p > n−1, and f ∈ Wloc1,n(D,Rn), then it is shown in [11] that a map with finite distortion is open, discrete.
Recently, there were considered in [11], [9], [10], [13] mappings f :D→ Rn of finite distortion for which there exists some smooth, strictly increas- ing A : [0,∞) → [0,∞) with A(0) = 0, lim
t→∞A(t) = ∞ and satisfying the conditions:
(A0) exp(A(K))∈L1loc(D);
(A1)∞
1 A(t)
t dt=∞;
REV. ROUMAINE MATH. PURES APPL.,52(2007),5, 539–554
(A2) there exists t0>0 such thatA(t)·tincreases to infinity fort≥t0. As in [9], we say that a mapping of finite distortion satisfies condition (A) iff satisfies condition (A0), (A1), (A2). In [7] is shown that such nonconstant mappings are either constant or open, discrete. Our proofs are based on the following basic ingredients, valid for mappingsf :D→Rnof finite distortion and satisfying condition (A):
(i) M(f(Γ))≤MKn−1(Γ) for every path family Γ from D;
(ii) capf(E) ≤ capKn−1(E), where E = (G, C) is a capacitor with G⊂⊂D;
(iii) capKn−1(B(x, R), B(x, r)) → 0 as r → 0 and R > 0 is kept fixed.
They were established in [9], Corollary 4.2, Corollary 5.2 and Theorem 5.3.
Here, K is the dilatation map of f. We also give in Lemma 1 a condition able to ensure that capKn−1(B(x, R), B(x, r)) → 0 as r > 0 is kept fixed and R→ ∞. This last condition is necessary in the proof of Zoric’s theorem (Theorems 2 and 1).
We generalize Zoric’s theorem for mappings with finite distortion which satisfy condition (A) as follows.
Theorem 2 (Zoric’s theorem). Let n ≥3. Let f :Rn → Rn be a local homeomorphism and a mapping of finite distortion satisfying condition (A) for which there exists r > 0 such that
B(0,r)
exp(A(K(x)))· |x1|2ndx < ∞. Then f is a global homeomorphism.
We give a Picard type theorem in Theorem 4, in connection with a similar result from [9].
Theorem 4 (Picard’s theorem). Let F ⊂ Rn be closed, f : Rn\F → Rn a nonconstant map of finite distortion, satifying condition (A),such that MKn−1(F) = 0and there existsr >0such that
B(0,r)
exp(A(K(x)))·|x1|2ndx <
∞. Then capf(Rn\F) = 0.
We also give in Theorem 1 a version of Zoric’s theorem with some “sin- gular” sets K and B, extending some results from [1] and [2]. Our variants of Zoric’s theorem may be put in connection with some recent result from [6] and [11]. However, our results ensure that the map f : Rn → Rn is a homeomorphism, hence we give a complete generalization of Zoric’s theorem.
Indeed, in [6] is proved that if f :Rn → Rn is a local homeomprhism and a mapping of finite distortion ofK(x) dilatation satisfying condition (A), and MKn−1(∞) = 0, then there existsE⊂Rn with capE = 0 such thatf :Rn→ Rn\E is a homeomorphism. Our condition
B(0,r)
exp(A(K(x)))·|x1|2ndx <∞
implies that MKn−1(∞) = 0, hence our Theorem 2 generalizes the so called Global Homeomorphism Theorem from [6]. Also, in [11] is proved that if f :B(0, r)→Rnis a local homeomorphism of finite distortion ofK(x) dilata- tion satisfying conditon (A) with exp(A ◦K)∈L1(B(0, r)), then there exists δ(n, K, r) such thatf is injective onB(0, δ). The result from [11] is not enough for an arbitrary local homeomorphismf :Rn→Rnof finite distortion ofK(x) dilatation and satisfying condition (A) to be a global homeomorphism, as in the classical case when K(x) ≤ K on Rn, i.e., we cannot prove Zoric’s the- orem for mappings of finite distortion using [11]. An example from [8] shows that the fundamental condition
B(0,r)
exp(A(K(x)))· |x1|2ndx < ∞ used in Theorems 2 and 4 is necessary in order to ensure thatf :Rn→Rnis a global homeomorphism.
We generalize in Theorem 5 a known equicontinuity result for quasireg- ular mappings as follows.
Theorem 5. Let D ⊂Rn be a domain, M ⊂Rn with capM > 0, W a family of mappings f :D→Rn\M of finite distortion satisfying condition (A) and having the same dilatation map K. Then W is equicontinuous if we consider the Euclidean distance on Dand the chordal distance on Rn.
We see that even in the case where all the mappings from the familyW areK-quasiregular, we improve the classical result established for quasiregular mappings in [15], Corollary 2.7, page 66. Indeed, the exceptional setM which is avoided by all the mapsf ∈W can be to be at most countable and chosen such that capM >0, hence of zero capacity.
We immediately obtain a Montel type theorem for mappings of finite distortion satisfying condition (A), extending in this way Theorem 8.14.1, [4], established in the particular caseA(t) =λt.
Theorem 6 (Montel’s theorem). Let D⊂ Rn be a domain. Let W be a bounded family of mappings f :D→ Rn of finite distortion with the same dilatation map K and satisfying condition (A). Then W is a normal family.
2. PRELIMINARIES
We call open a path q : [0,1) → Rn. A point x ∈ Rn will be called a limit point of q if there exists tp 1 such that q(tp) → x. If Γ is a path family in Rn, we define F(Γ) = {ρ : Rn → [0,∞] is a Borel map
|
γρds≥1 for every locally rectifiable γ ∈Γ}.Let nowD⊂Rn be open and ω :D → [0,∞] measurable and finite a.e. If ω : Rn → [0,∞] is defined by
ω(x) =ω(x) if x∈D, ω(x) = 0 if x /∈D, then we define the ω-modulus of Γ byMω(Γ) = inf
ρ∈F(Γ)
Rn
ρn(x)·ω(x)dx. For ω ≡1 we obtain the usual modulus M(Γ). If Γ1, Γ2are path families inRn, we say that Γ1>Γ2if every path from Γ1 has a subpath in Γ2. As in the classical case, we can prove that if Γ1>Γ2, thenMω(Γ1)≤Mω(Γ2). Also, we can prove thatMω
∞
i=1 Γi
≤ ∞
i=1Mω(Γi), and if ω1 ≤ ω2, then Mω1(Γ) ≤Mω2(Γ). For D ⊂ Rn open, E, F ⊂ D, we denote by ∆(E, F, D) the family of all paths, open or not, which join E with F inD.
We say that E = (D, C) is a condenser if C is compact, D is open, C ⊂ D ⊂ Rn. Let ω :D → [0,∞] be measurable and finite a.e. We define theω-capacity of E by capωE = inf
Rn|∇u|n(x)·ω(x)dx, where u∈C0∞(D) and u ≥ 1 on C. If ω = 1 we obtain the usual capacity cap E of E. We see that ifu is a test function for capωE, then ρ =|∇u| ∈ F(ΓE). This implies that Mω(ΓE) ≤ capω(E). Here, ΓE = {γ : [a, b] → D is a path | γ(a) ∈ C and γ has a limit point in ∂D} and from Proposition 10.2 in [15, page 54], we have capE = M(ΓE). If C ⊂Rn is compact, we say that cap C = 0 if cap(A, C) = 0 for every C⊂A⊂Rn open. By [15, Lemma 2.2, page 64], the definition is independent on the open set A such that C ⊂A. If C ⊂ Rn is arbitrary, we say that capC = 0 if capK= 0 for every compact K ⊂C.
Let now D ⊂ Rn be open, ω : D → [0,∞] measurable and finite a.e., A⊂D a set. We say that A is of zeroω-modulus, and we write Mω(A) = 0, if the ω-modulus of all paths having some limit point in A is zero. If ω ≥1, we see thatM(Γ)≤Mω(Γ). Hence, ifMω(A) = 0 then capA= 0.
If A ⊂D is countable and lim
r→0Mω(∆(B(x, r),B(x, R), D)) = 0 for ev- ery x ∈ A and every 0 < R with B(x, R) ⊂ D, we can prove as in the classical case that Mω(A) = 0. Using Theorem 5.3 in [9], we see that this holds, for instance, if ω = Kn−1, where K : D → [0,∞] is measurable and finite a.e. and for every x ∈ A there exists ρx > 0 such that B(x, ρx) ⊂ D
and
B(x,ρx)
exp(A(K(y)))dy <∞, whereAsatisfies conditions (A1) and (A2).
Lemma 1 also gives a condition which ensures thatMKn−1(∞) = 0.
IfD⊂Rnis open andb∈∂D, we defineC(f, b) ={w∈Rn|there exists bp∈D,bp→bsuch thatf(bp)→w}. IfB⊂∂D, we letC(f, B) =
b∈BC(f, b).
If E, F are Hausdorff spaces, f : E → F is a map, p : [0,1] → F is a path, x∈E is such thatf(x) =p(0),we say thatq: [0, a)→E is a maximal lifting ofpfromxwhen q(0) =x, 0< a≤1, f◦q =p|[0, a) andq is maximal with this property. Ifqis defined on [0,1], we say thatq is a lifting ofp. IfE, F are
domains in Rn and f is continuous, open, discrete, then there always exists a maximal lifting. We denote by µn the Lebesgue measure in Rn and by q the chordal metric inRn given byq(a, b) =|a−b| ·(1 +|a|2)−12 ·(1 +|b|2)−12 ifa, b ∈ Rn, q(a,∞) = (1 +|a|2)−12 if a∈ Rn, and by |a−b| the Euclidean distance betweenaand b inRn. We denote by Bq(x, r), respectivelyB(x, r), the ball of center x and radius r if we consider on Rn the chordal metric, respectively the Euclidean metric. In the same way, for a setA⊂Rnwe denote byq(A), respectivelyd(A), the diameter ofA. We denote by Wloc1,p(D,Rn) the Sobolev space of all functionsf :D→Rnwhich are locally inLp(D), together with their first order weak partial derivatives.
IfW is a family of mappingsf :D→Rn, we say that W is bounded if for every compact K ⊂ D there exists M(K) >0 such that |f(x)| ≤ M(K) for everyx∈K and everyf ∈W. IfX, Y are metric spaces andW is a family of mappings f : X → Y, we say that W is equicontinuous at x if for every ε >0 there exists δε > 0 such that d(f(x), f(y)) ≤ ε when d(y, x) ≤ δε for everyf ∈W. We say thatW is equicontinuous if it is equicontinuous at every point x ∈X. We say that W is a normal family if every sequence in W has a subsequence which converges uniformly on the compact subsets of X to a mapf :X →Y.
Lemma 1. Let n ≥ 2. Let D ⊂ Rn be an unbounded domain, K : D → [0,∞] measurable and finite a.e., A : [0,∞) → [0,∞) smooth, strictly increasing, with A(0) = 0, lim
t→∞A(t) =∞,satisfying condition (A1) and (A2) for which there exists r > 0 such that
D∩B(0,r)
exp(A(K(x)))· |x1|2ndx <∞. ThenMKn−1(∆(B(0, r)∩D,B(0, s)∩D, D)→0as s→ ∞and r >1is kept fixed.
Proof. Let g : Rn → Rn be defined by g(x) = x
|x|2 if x ∈ Rn and let Γrs = ∆(B(0, r)∩D,B(0, s)∩D, D), Λrs = ∆(g(D)∩B(0,1s), g(D)∩ B(0,1r), g(D)) for 1 < r < s. We show that MKn−1(Γrs) = MKn−1◦g(Λrs).
Letρ ∈F(Γrs) and ρ:Rn →[0,∞] be defined by ρ(x) =ρ(g(x))· |g(x)| if x ∈ D, ρ(x) = 0 if x /∈ D. Then ρ ∈ Γ(Λrs) and MKn−1◦g(Λrs) ≤
Rn
ρn(x)· Kn−1(g(x))dx=
D
ρn(g(x))|g(x)|n·Kn−1(g(x))dx=
D
ρn(g(x))·Kn−1(g(x))·
Jg(x)dx =
g(D)
ρn(y)·Kn−1(y)dy ≤
Rn
ρn(y)·Kn−1(y)dy. This implies that MKn−1◦g(g(Γrs)) =MKn−1◦g(Λrs)≤MKn−1(Γrs). By the same argument, we haveMKn−1(Γrs) =MKn−1◦g◦g(g(Λrs))≤MKn−1◦g(Λrs) and
(1) MKn−1(Γrs) =MKn−1◦g(Λrs).
Next,
g(D)∩B(0,1r)
exp(A(K(g(x))))dx=
g(D)∩B(0,1r)
exp(A(K(g(x))))·Jg−1(g(x))·Jg(x)dx=
=
D∩B(0,r)
exp(A(K(y)))·Jg−1(y)dy=
D∩B(0,r)
exp(A(K(y)))· 1
|y|2ndy <∞. Let now Γrs = ∆(B(0,1s),B(0,1r), B(0,1r)\B(0,1s)) for 1 < r < s and Q : Rn → [0,∞] be defined by Q(x) = K(g(x)) if x ∈ g(D), Q(x) = 1 if x /∈g(D). Since
B(0,1r)
exp(A(Q(x)))dx <∞, by Theorem 5.3, page 24, in [9], capQn−1(B(0,1r), B(0,1s)) → 0 as s → ∞ and r > 0 is kept fixed. We have MKn−1◦g(Λrs) ≤MQn−1(Λrs) ≤MQn−1(Γrs) ≤capQn−1(B(0,1r), B(0,1s)) and this implies that
(2) MKn−1◦g(Λrs)→0 ass→ ∞ and r >0 is kept fixed.
Using (1) and (2), the proof is complete.
Lemma 2. Let D ⊂ Rn be open. Let f : D → Rn be a map of finite distortion satisfying condition (A) and K : D → [0,∞] the dilatation map of f. Then K ∈ Lploc(D) for every p > 0 and f ∈ Wloc1,p(D,Rn) for every 1≤p < n.
Proof. Using property (A2) we see that the function exp(A(t)) grows faster then anytp to infinity and therefore K ∈Lploc(D) for every 0< p <∞. We use now H¨older’s inequality and the integrability of the Jacobian to see that
B|f(x)|pdx <∞for every ballB withB ⊂Dand every 1≤p < n.
3. PROOFS OF THE MAIN RESULTS We start with
Theorem 1. Let n ≥3. Let B ⊂ Rn be closed, K ⊂ Rn\B closed in Rn\B with intK = ∅, f :Rn\(K ∪B) → Rn a map of finite distortion of K(x)dilatation satisfying condition (A)and a local homeomorphism such that MKn−1(B) = 0, intC(f, K) =∅, C(f, K) closed and Rn\C(f, K) connected.
Let E =K∪B∪f−1(C(f, K)).Suppose that exp(A(K))∈L1loc(Rn\K) and that there exists δ0 >0such that
B(0,δ0)∩(Rn\(K∪B))
exp(A(K(x)))·|x1|2n <∞.
Then
1)We can extend f to a local homeomorphism around each point x∈B with possibly f(x) = ∞ for some point x ∈ B. Also, extending if necessary the map f to a homeomorphism near ∞, we can lift every path: p[0,1] → Rn\C(f, K) from every point x∈Rn with f(x) =p(0).
2) If C(f, K) is compact, then intE = ∅ and f is injective on Rn\E.
If f can be continuously extended to K, then either f|Rn\K : Rn\K → Rn\C(f, K)orf|Rn\K :Rn\K→ Rn\C(f, K)is a homeomorphism. Finally, if f can be continuously extended to an open map on K, then f :Rn → Rn is a homeomorphism.
Proof. By Theorem 1.1 [13], we can take B =∅. Let Γ = {γ : [0,1) → Rn\K path|∞ ∈Im γ}. By Lemma 1,MKn−1(Γ) = 0.Using (i), we see that M(f(Γ))≤MKn−1(Γ) = 0, henceM(f(Γ)) = 0 and by Theorem 1 in [2], 1) is proved.
Suppose now that C(f, K) is compact and let r > 0 be such that C(f, K) ⊂ B(0, r), let 0 < r < s and let x ∈ Rn\K be such that f(x) ∈ B(0, s). LetQbe the component off−1(B(0, r)) which containsxand letU be the component off−1(B(0, s)) which contains x. Then U ⊂Q and since B(0, r) is simply connected and f|Q : Q → B(0, r) is a local homeomor- phism which lifts the paths,f|Q :Q→ B(0, r) is a homeomorphism, hence f|U : U → B(0, s) also is a homeomorphism. Since f|∂U : ∂U → S(0, s) is a homeomorphism, Jordan’s theorem implies thatRn\∂U has exactly two components, one of them being U. Since U is homeomorphic to B(0, s), U is unbounded. If U0 is any other component of f−1(B(0, s)), by the same argument, f|U0 :U0 → B(0, s) is a homeomorphism, ∂U0 bounds a Jordan domain, and U0 is the unbounded component ofRn\∂U0. Let α >0 be such that ∂U ∪∂U0 ⊂ B(0, α). Then B(0, α) ⊂ U ∩U0, hence U = U0 and we obtain thatf−1(B(0, s)) has a single component U on which f is injective, K⊂U and U =f−1B(0, s).
Since f is a local homeomorphism on Rn\K and int C(f, K) = ∅, we have int E = ∅. Let x1, x2 ∈ Rn\E be such that f(x1) = f(x2) = y. Let
z ∈ B(0, s) and p : [0,1] → Rn\C(f, K) a path such that p(0) = y and
p(1) =z. We can liftp from x1 and x2 and find some paths qi : [0,1]→ Rn such that qi(0) = xi, f ◦ qi = p, i = 1,2. Since qi(1) ∈ f−1(B(0, s)) = U, f(qi(1)) =p(1), i= 1,2 and we proved thatf is injective onU, we obtain thatq1(1) =q2(1).We now use the property of the uniqueness of path lifting for local homeomorphisms to conclude thatx1 =x2. We therefore proved that f is injective onRn\E.
Suppose now that f can be continuously extended to K and let a∈Rn be a point such that f is open at a. Let us show that {a} = f−1(f(a)).
Indeed, if there existsb=a,b∈Rn such that f(a) =f(b), let U1∈ V(a) and V ∈ V(f(a)) be such that f(U1) =V. Sincef is continuous at b, we can find U2∈ V(b) withU1∩U2=∅such thatf(U2)⊂V, and since intE =∅, we can findα ∈U2\E. Then we can findβ ∈U1\E withf(α) =f(β). So, we reached a contradiction, since we proved that f is injective onRn\E. It results now immediately that eitherf|Rn\K:Rn\K →Rn\f(K) orf|Rn\K :Rn\K → Rn\C(f, K) is a homeomorphism. If we additionally suppose that f also is an open map onK, we find thatf|Rn:Rn→Rn is a homeomorphism.
Proof of Theorem 2. We takeK =∅ in Theorem 1.
The following version of Zoric’s theorem seems to be new even for quasire- gular mappings.
Theorem 3. Let n ≥ 3. Let K ⊂ Rn be compact, f : Rn → Rn con- tinuous on Rn and of finite distortion of K(x) dilatation satisfying condition (A) on Rn\K for which there exists r >0 such that f is a local homeomor- phism on B(0, r)and
B(0,r)
exp(A(K(x)))·|x1|2ndx <∞. If fis unbounded, then there exists δ >0 such that f is injective on B(0, δ) while if f is open discrete on K,then f :Rn→Rn is a homeomorphism.
Proof. Suppose first that f is unbounded and let ρ > 0 be such that f(K)⊂B(0, ρ). Letp: [0,1]→B(0, ρ) be defined byp(t) = (1−t)f(x) +ty fort∈[0,1] and some x∈Rn\K and y ∈CB(0, ρ). As in Theorem 1 in [2], we try to liftpfrom x. Let 0< a≤1 and letq : [0, a)→Rn\K be a maximal lifting ofp from x withf ◦q=p|[0, a). As in our Theorem 1 and Theorem 1 in [2] we can find spheresS(p(a), r) and sets Qr which bound some Jordan domains Dr such that f|Qr : Qr → S(p(a), r) is a homeomorphism for a.e.
r >0, and we can suppose that B(0, ρ)∩B(p(a), r) =∅ for a.e. 0< r≤r0. As in Theorem 1 in [2], we have two cases.
In the first case, suppose that Dr ⊂ Ds for 0 < s < r ≤ r0. Let Wr = s<r(Ds\Dr) and Br = B(p(a), r)∪B(0, ρ) for 0 < r ≤r0. Then Br is connected for 0 < r ≤ r0 and let us fix 0 < s < r ≤ r0. We show that f((Ds\Dr)\K)⊂Br. Indeed, otherwise we can find a point α ∈(Ds\Dr)\K such that f(α) ∈ CBr. Let y ∈ Br and let Γ : [0,1] → Br be a path such that Γ(0) = f(α), Γ(1) = y. If we cannot lift Γ from α, we can find 0< c ≤1 and a maximal lifting γ : [0, c) → Rn\K of Γ from α. Let tp c be such that γ(tp) → z. Then z ∈ Ds, hence z = ∞ and z ∈ Qs∪Qr∪K, hence f(z) ∈ f(Qs ∪Qr ∪K) ⊂ Br. On the other hand, we have f(z) = f
plim→∞γ(tp)
= lim
p→∞f(γ(tp)) = lim
p→∞Γ(tp) = Γ(c) ∈ Br and we so reach a contradiction.
We see that we can lift Γ from α, hence we can find a path γ : [0,1]→ (Ds\Dr)\K with γ(0) = α and Γ = f ◦γ, hence y = Γ(1) = f(γ(1)) ∈ f((Ds\Dr)\K). Since y was arbitrary chosen in Br, we proved that Br ⊂ f((Ds\Dr)\K) ⊂f(Ds), so we reached a contradiction so f(Ds) is compact andBr is unbounded.
We therefore proved that f(Ds\Dr) ⊂ Br for 0 < s < r ≤ r0. Let A = lim
r→∞Wr. Then Wr is connected and f(Wr) ⊂ Br for 0 < r ≤ r0, hence C(f, A) = ∩
r>0f(Wr) is connected and C(f, A) ⊂ Br for 0 < r ≤ r0. Since p(a) ∈ C(f, A), we have C(f, A) ⊂ B(p(a), r) for 0 < r ≤ r0, hence C(f, A) ={p(a)}. This implies thatA∩K=∅and since f is a light map on Rn\K, we have cardA = 1. ThenA={∞} and f maps a neighbourhood of
∞near p(a) and this contradicts the fact that f is unbounded. We therefore proved that the caseDr⊂Ds for 0< s < r≤r0 cannot hold.
In the second case, we have Ds ⊂ Dr for 0 < s < r ≤ r0 and let B = r>∩
0Dr. As before, we see that f(Dr\Ds) ⊂ Br for 0 < s < r ≤ r0, that C(f, B) = r>∩
0f(Dr) is connected and C(f, B) ⊂Br for 0 < r≤r0 and p(a)∈C(f, B). This implies that C(f, B) ⊂B(p(a), r) for 0< r ≤r0, hence C(f, B) = {p(a)}, B ∩K = ∅. Since f is a light map on Rn\K, we have cardB = 1. We use then the arguments from the proof of Theorem 1 in [2] to see that we can liftp from x.
We therefore proved that we can lift any pathp: [0,1]→B(0, p),p(t) = (1−t)f(x) +tyfort∈(0,1], wherex∈Rn\K andy∈B(0, ρ). We take now V =B(0, ρ), x∈(Rn\K)∩f−1(V) and letQ be the component of f−1(V) containing x. Then the map g = f|Q : Q → V is a local homeomorphism which lifts the paths and V is simply connected. This implies that g is a homeomorphism. We see thatQis the exterior of a Jordan domainDand the first half of theorem is proved.
Suppose now thatf is open and discrete on K. Let x ∈Rn\K, ρ > 0 such thatf(K) ⊂B(f(x), ρ) and let U ∈ V(x) and 0 < r < ρ be fixed such that B(f(x), r) ⊂ f(U). If y ∈ S(f(x), ρ), let αy ∈ U such that f(αy) ∈ S(f(x), r)∩[f(x), y] and let Γy : [0,1]→B(f(x), ρ),Γy(t) = (1−t)f(αy) +ty for t ∈ [0,1]. Let Cρ = {y ∈ S(f(x), ρ) | Γy cannot be lifted from αy} and Γ ={pathsγy : [0, cy) →Rn |y ∈ Cρ and γy is a maximal lifting of Γy from αy}. Then∞ ∈Imγfor everyγ∈Γ and by Lemma 1 we haveMKn−1(∞) = 0, henceM(Γ) = 0. Sincef is a map of finite distortion satisfying condition (A) onRn\K, we use (ii) to see thatM(f(Γ)) = 0. This implies thatmn−1(Cρ) = 0, hence we can lift a.e. path Γy from αy. Since ρ > 0 can be taken great enough, it results thatf is unbounded.
As in the first part of the proof, we can findρ >0 and a Jordan domain Dsuch that f|D:D→B(0, ρ) is a homeomorphism. Then f|∂D:∂D→ S(0, ρ) is a homeomorphism andf is open, discrete onD. Using the theorem of univalence on the border [3], we see that f is injective on D and f(D) = B(0, ρ). It results thatf :Rn→Rn is a homeomorpism.
Remark 1. Let f : Rn → Rn, f(x) = x if x ∈ B(0,1), f(x) = |xx|2 if x ∈ B(0,1). Then f is conformal on Rn\S(0,1), it is not an open map on S(0,1) and it is not injective. This shows that the openess of the mapf from Theorem 3 on the “singular” set K is necessary in order to ensure that f :Rn→Rnis a homeomorphism. We also see that if n≥3, f :Rn→Rnis a nonconstant map of finite distortion ofK(x) dilatation satisfying condition (A) and the condition
B(0,r)
exp(A(K(x)))|x1|2ndx <∞, then the branch set Bf = {x ∈ Rn | f is not a local homeomorphism at x} is either empty or unbounded.
Proof of Theorem 4. Since MKn−1(F) = 0, we have cap F = 0, hence that Rn\F is a domain. Since f is nonconstant on Rn\F, the functionf is open, discrete onRn\F. Suppose that capf(Rn\F)>0 and letK⊂Rn\F be compact, connected, with cardK > 1. Then E = (f(Rn\F), f(K)) is a capacitor and q(f(K)) >0, and by Lemma 2.6, page 65, in [5], there exists δ >0 such thatδ < capE. Let Γ = ∆(f(K),f(Rn\F),Rn) and let Γ be the family of all maximal liftings of some paths from Γ starting from some points ofK. Then Γ< f(Γ) and ifγ ∈Γ, thenγ has at least a limit point inF∪{∞}. Since
B(0,r)
exp(A(K(x)))·|x1|2ndx <∞, by Lemma 1 we haveMKn−1(∞) = 0, henceMKn−1(F ∪ {∞}) = 0. This implies that MKn−1(Γ) = 0. We use now (i) and obtain that δ <cap(E) =M(Γ)≤M(f(Γ))≤MKn−1(Γ) = 0, so we reach a contradiction. We therefore proved that capf(Rn\F) = 0.
Remark 2. The condition
B(0,r)
exp(A(K(x)))·|x1|2ndx <∞, which en- sures thatMKn−1(∞) = 0, used in our generalizations of Zoric’s and Picard’s theorems, holds for instance if K(x) ≤ Kp for x ∈ B(0, p), p ≥ p0 and
lim sup
p→∞
Kp
lnp =α < n(i.e. it holds for a locally quasiregular mapping having some logarithmic growth of the constant of quasiregularity near∞). Indeed, takeA(t) =t. If p1≥p0 is such that Kp < α·lnp forp≥p1, then
B(0,p1)
exp(A(K(x)))· 1
|x|2ndx=
p≥p1
B(0,p+1)\B(0,p)
exp(A(K(x)))· 1
|x|2ndx≤
p≥p1
B(0,p+1)\B(0,p)
exp(Kp+1)· 1
|x|2ndx≤C0·
p≥p1
(p+ 1)α((p+ 1)n−pn)
p2n ≤
≤C1·
p≥p1
1
pn−α+1 <∞. HereC0 andC1 are suitable constants.
We can generalize in this way Theorems 8 and 9 from [2], obtaining a generalization of Zoric’s theorem for locally quasiregular mappings having a logarithmic growth of the constant of quasiregularity near∞.
Similarly, the condition
B(b,ρ)
exp(A(K(x)))dx <∞, which ensures that MKn−1(b) = 0 holds for instance if K(x) ≤ Kp on B(b,1p) for p ≥ p0 and lim sup
p→∞
Kp
lnp =α < n. This condition holds for locally quasiregular mappings having some logarithmic growth of the constant of quasiregularity near the critical pointb ∈ ∂D and it can be used in Theorems 1 and 4. Also, we see that the setB from Theorem 1 can be taken to be countable.
Proof of Theorem 5. Letx∈Dbe fixed and letε >0 withB(x, ε)⊂D.
We fix ε > 0 and suppose that there exist ρ > 0, rp → 0 and fp ∈ W such that q(fp(B(x, rp))) ≥ ρ for every p ∈ N. Then the fp are open, discrete mappings for every p ∈ N and fp(U)∩M = ∅ for every open, nonempty U ⊂ D and every p ∈ N. Then fp(B(x, rp))∩M = ∅ for every p ∈ N and we can findδ >0 such that δ ≤cap (M , fp(B(x, rp))) for every p ∈N (see Lemma 2.6, page 65, in [15]). By (ii) we have δ ≤ cap(M , fp(B(x, rp))) ≤ cap(fp(B(x, ε)), fp(B(x, rp))) ≤capKn−1(B(x, ε), B(x, rp))→ 0 ifrp → 0 and ε >0 is kept fixed, so we reach a contradiction. We therefore proved that for everyε >0 there exists δε >0 such that f(B(x, δε))⊂Bq(f(x), ε) for every f ∈W, i.e., W is equicontinuous at x.
Proof of Theorem 6. Let x ∈ D, δ > 0 be such that B(x, δ) ⊂ D and M > 0 such that |f(y)| ≤ M for every y ∈ B(x, δ) and every f ∈ W. Let W0 =
f|B(x, δ)|f ∈W
. By Theorem 5, W0 is equicontinuous at x, hence W is equicontinuous at x. Take on D the Euclidean metric and on Rn the chordal metric. By Theorem 20.4, page 68 in [16], if (fp)p∈N is a sequence of mappings fromW, we can find a subsequence (fpk)k∈Nand a mapf :D→Rn such that fpk → f uniformly on the compact subsets of D. Ifx ∈D is fixed and Mx >0 is such that |fpk(x)| ≤ Mx for every k ∈ N, then |f(x)| ≤ Mx, hencef takes finite values and it results thatW is a normal family.
Theorem 7. Let D⊂Rnbe a domain,W a family of mappings f :D→ Rn of finite distortion, with the same distortion map K satisfying condition (A), and let x ∈ D be such that there exists r, δ > 0 such that B(x, δ) ⊂D and f(B(x, δ))⊂B(f(x), r) for every f ∈W. Then W is equicontinuous at x,if we take on Dand on Rn the Euclidean distance.
Proof. Letf ∈W.Iff is constant onB(x, δ), thenf(B(x, ρ)) ={f(x)} ⊂ B(f(x), ε) for every 0 < ρ < δ, 0 < ε < r. Suppose that f is open, discrete on B(x, δ) and let 0 < ε < r, 0 < ρ < δ, and E = (B(x, δ), B(x, ρ)). Then f(E) = (f(B(x, δ), f(B(x, ρ)) is a capacitor and letνnbe the function defined in [15], page 60. Keepδ >0 fixed and letρ→0 such that capKn−1(E)≤νn(εr) for 0< ρ < δε. Then νn
|f(y)−f(x)|
r
≤ capf(E) ≤capKn−1(E) ≤ νn(rε) for every y ∈ B(x, ρ). Since νn is strictly increasing, we have |f(y)−f(x)| ≤ ε for everyy∈B(x, δε) and everyf ∈W, i.e., W is equicontinuous at x.
Remark 3. Theorem 7 shows the interesting thing that if W is a family of mappingsf :D→Rnof finite distortion with the same distortion mapping K and satisfying condition (A), and x is a point from D, then it is sufficient to exist a single r > 0 and a single δ >0 such that f(B(x, δ)) ⊂B(f(x), r) for every f ∈ W to obtain the equicontinuity of the family W at the point x. Taking a mappingf :D→Rnof finite distortion and satisfying condition (A), fλ=f+λ, W = (fλ)λ∈Rn, we see immediately thatW is equicontinuous.
Since
g∈Wg(x) =Rn for everyx ∈D, we cannot apply Theorem 5 to deduce the equicontinuity of the familyW, but we can use instead Theorem 7.
Theorem 8. Let D⊂Rnbe a domain, W a family of homeomorphisms f :D→ f(D) of finite distortion with the same distortion map K satisfying condition (A) for which there exists r >0 such that for every f ∈ W there exist af, bf ∈/ Im f with q(af, bf)≥r. Then W is equicontinuous if we take the Euclidean distance on D and the chordal distance on Rn.
Proof. We follow the proof of Theorem 19.2, page 65 in [16]. Let λn be the function defined in [16], 12.4, page 38 and letx0 ∈D and 0< ε < r. Let Q0 = B(x0, α), Q1 = B(x0, β) be such that 0 < α < β and B(x0, β) ⊂ D, and let A = R(Q0,Q1). Then f(A) = R(f(Q0),f(Q1)) and q(f(Q1)) ≥ q(af, bf) ≥ r, q(f(Q0)) ≥ q(f(x), f(x0)) for every x ∈ Q0. Let x ∈ Q0 be fixed and t = min{q(f(x0), f(x)), r}. We keep β > 0 fixed and choose α small enough such that MKn−1(ΓA) ≤ λn(ε). Then λn(t) ≤ M(f(ΓA)) ≤ MKn−1(ΓA)≤λn(ε) and sinceλnis increasing, we havet≤ε. Sinceε < r, we gett=q(f(x), f(x0)). We therefore proved thatq(f(x), f(x0))≤εfor every x∈Q0 and every f ∈W.
Theorem 9. Let D⊂Rnbe a domain, W a family of homeomorphisms f :D →f(D) of finite distortion with the same dilatation map K satisfying condition (A) and such that one of the following condition is satisfied:
(i)there exist x1, x2∈Dand r >0 such that each f ∈W omits a point af with q(af, f(xi))≥r for i= 1,2;
(ii)there exist xi ∈D and r >0such that q(f(xi), f(xj))≥r for i=j, i, j= 1,2,3 and every f ∈W.
Then W is equicontinuous.
Proof. Suppose that condition (i) is satisfied and let Dk =D\ {xk} for k= 1,2. By Theorem 8, the familiesWk={f|Dk|f ∈W}are equicontinuous on Dk for k = 1,2, hence W is equicontinuous. Suppose now that condition (ii) is satisfied and letDij =D\ {xi, xj} andWij ={f|Dij|f ∈W}fori, j = 1,2,3. By Theorem 8, the families Wij are equicontinuous on Dij for i, j = 1,2,3, henceW is equicontinuous.
Corollary 1. Let D ⊂ Rn be a domain, W a family of homeomor- phisms f : D → f(D) of finite distortion with the same dilatation mapK, satisfying condition (A) such that f(ai) = bi, i = 1,2,3 for every f ∈ W, where a1, a2, a3 are three different points in Dand b1, b2, b3 are three different points in Rn. Then W is equicontinuous.
Theorem 10. Let D, Dj be domains in Rn, fj : D → Dj homeomor- phisms of finite distortion with the same dilatationmapKsatisfying condition (A) and such that fj →f. If card(Imf) ≥3, then f :D→ D is a home- omorphism onto a domain D from Rn while if fj → f uniformly on the compact subsets from D,then f is either constant or a homeomorphism onto a domain from Rn.
Proof. We follow the proof of Theorem 21.1 in [16] page 9. Letb1, b2, b3 be three different points in Imf,ak∈D such that f(ak) =bk fork= 1,2,3, and let r > 0 be such thatq(f(ai), f(aj))≥ r for i= j, i, j = 1,2,3. Then there exists j0 ∈N such thatq(fj(ai), fj(ak))≥ r2 fori=k,i, k = 1,2,3 and j≥j0. It follows from Theorem 9, condition 2), that the familyW = (fj)j≥j0 is equicontinuous. By Theorem 20.3 in [16], page 68, we havefj →f uniformly on the compact subsets of D, hence f is continuous on D. By Brouwer’s theorem, it is enough to prove thatf is injective onD.
Suppose that there existsz1, z2 ∈D,z1 =z2such thatf(z1) =f(z2) and let r > 0 be such that z2 ∈/ B(z1, r). Then fj(S(z1, r)) separates the points fj(z1) and fj(z2), hence we can findxj ∈S(z1, r) such that
(1) q(fj(xj), fj(z1))≤q(fj(z1), fj(z2)) for every j∈N.