A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
L. A. A ˘IZENBERG C. R EA
The moment-condition for the free boundary problem for CR functions
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 20, n
o2 (1993), p. 313-322
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The
Moment-Condition for
theFree
Boundary Problem for CR Functions
L.A.
A~ZENBERG -
C. REA1. - Statements
We are interested in
studying
afree boundary problem
forholomorphic
functions: a continuous function
f
isgiven
on an openpiece
r of theboundary
of an open set in ~n and we want to find a
holomorphic
function in the open set which is continuous up to r and takes the valuef
there. We shall say then thatf
extendsholomorphically
to theoriginal
open set.If n > 2 then
f
mustsatisfy
a well known necessarycondition, i.e., f
must be a CR function on r.
This
problem
has been studied in[1], [7], [10], [12], [14], [15], [16], [17]
(for
a survey see[2]
Section27).
In those papers rathercomplicated
conditionsare
given
withexception
of[7]. Recently, using
asimple
theorem in one variable(Theorem
Abelow),
in thespirit
of[7], simpler
results have been obtained.Later,
verygeneral
resultsappeared ([16], [9])
butthey
are hard to use.A
generalization
of the one-variable-theorem A is in[5].
We shall consider it later in Theorem B.We are indebted to Lee Stout who
pointed
out an error in a former version of Theorem 2. We also thank PeterPlug
for useful conversations.Let Q be an open set in
Cz
xCnw,
r c aSZ ahypersurface
of classC1,
transversal to the z-direction. Write
Lw - Cz
xfwl.
Assume
that,
for all w E cn that is connected andNext
fix,
for any w withLw n CJ.f:0,
a conformalmapping
Spw : D -Lw,
During the preparation of the manuscript the first Author was a visiting professor at the University of Roma - Tor Vergata, supported by M.P.I. Research founds.The second Author is supported by M.P.I. Research founds.
Pervenuto alla Redazione il 5 Dicembre 1991 e in forma definitiva il 22 Giugno 1992.
injective,
withnon-vanishing derivative,
with theseproperties:
is a closed subset of
The inverse of pw defines a
function 0 :
D. Let nowf
be acontinuous,
CR function on r such
that,
for any w,f
o pw is aLl
function on the curve nr)
c D. SetTHEOREM 1.
f
extendsholomorphically
to 0, continuous up to rif
andonly if
This will be obtained as a consequence of two other results: Theorem A and Theorem 2 below.
THEOREM A.
(Aizenberg [3]).
Let 1 be aCl, simple
curve in the unit disc D, closed as a subsetof
D. LetD+,
D- be the componentsof
assume0 E D-. Let
f be a
continuousfunction
on ~y,f
EL1(1).
SetThen
f
extends as aholomorphic function
onD+,
continuous up to Iif
andonly if
A
simple proof
of thisTheorem,
renewed for thenecessity side,
can befound in Section 3.
THEOREM 2. Let 0 c and r c 8Q
satisty (1)
and letf :
Cbe a
function
which isholomorphic
with respect to the z-variable and, when restricted to(Q
ur)
rlLw,
is continuous up to r nLw.
Assume thatfir
is CRand continuous. Then
f
isholomorphic
in SZ with respect to all variables and continuous on K2 U r.Notice that the
CR-hypothesis
is essential in the last theorem: if thishypothesis fails,
thenf might
be evennon-locally
bounded as we show in the nextEXAMPLE. 92
((z, w)) )z) I 1/2,lwl I 1},
r m((z, w)
E11
2/3}, f (z, w)
=w(z - 1)1/lwl
forw f0, f (z, 0)
= 0. There isf
ECO(r)
because315
there I z - 1 ~ I 2/3
1, but near Q11 ]
>1 }
nfw
=ol f
is unbounded(local
boundedness off
would at least ensure itscontinuity by
a well knownLindelbf
procedure).
PROOF OF THEOREM 1. Set 1m =
W(Lw n r)
C D sothat,
forak(w)
definedin
(3),
we have - -Thus we can
apply
Theorem A tof
o on "Iw and thisgives
that(4)
is
equivalent
to the fact thatf
o extendsholomorphically
to1b(Q
nLw),
continuous up to "Iw, for any w.If we go back to with we obtain that
(4)
isequivalent
to thefact that
f
isholomorphic
with respect to the z-variableand,
when restricted to it is continuous up tor n Lw .
Thus thenecessity
of condition(4)
followsimmediately.
For thesufficiency
we haveonly
toapply
Theorem 2.0 REMARK 1. No
assumption
is made on thedependence
of thepw’s
onw and their choice is
suggested by
the various situations where the theoremapplies.
See"applications"
below.REMARK 2. The
L1
1assumption
in Theorem 1 and Theorem A can beforgotten
whenthey
are used asextendability
theorems: one shrinks Q U r alittle bit...
REMARK 3. No
assumption
is necessary on theboundary
behaviour of"I in Theorem A
and, correspondingly,
nr)
c D in Theorem 1. For different values of w this last can have very differentshapes;
ari arcjoining
two
points,
a closed curve, a curve which isergodic
to theboundary
a0....For instance of Theorem A
(or n r)
in Theorem1,
for allw)
isa closed curve, then those theorems
yield
thesolvability
of an exteriorproblem.
REMARK 4. Instead of
taking
F C aS2, one can taker c Q, disconnecting
Q in two parts SZ- and Theorem 1
might
beapplicable
twice: to S2+ U r andto K2- U r so that it
yields
a necessary and sufficient condition for the solution of an interiorproblem.
We shall see such a situation in theapplications
below.See Remark 6 in Section 2.
REMARK 5. The
proof
of Theorem 2 can become very easy ifstronger hypothesis
areimposed.
For instance iff
E n Ur)
then theproof
goes as follows: for
any j
=1, ... , n, fw~
isz-holomorphic
and vanishes on r and henceeverywhere
in Q.Also if r contains no
complex hypersurface,
then theapplication
ofTrepreau’s
well known theoremyields quickly
to the statement.Nevertheless,
if
really nothing
is assumed on the behaviour off
out of r(such
as localboundedness or
Lloc)
and on thecomplex
structure of r, then Theorem 2becomes a rather delicate matter.
Further
possible Developments.
We obtained Theorem 1applying
Theorem2 to Theorem A. One could start with the n- dimensional
analogue
of TheoremA which we state now.
THEOREM B.
(Aizenberg, Kytmanov [5]).
Let Q be a Reinhardt domain in]
theimage of
anby (zl, ... , zn)
->(Izl Iz,, 1),
b aC2(n - 2)- form
in the spaceof
themoduli,
with supporton lanl, y (y) = 0 (1 l 1, ... , |sn|
theMinkowski functional of
Q. Let r be asmooth, relatively
closedhypersurface
in K2 which divides SZ in two domains Q-, S2+ and let 0 be in f2-. Then
for
the
holomorphic
extensionof
a CRfunction f
EcO(r)
nL1(r)
it is necessary andsu, ffccient
thatwhere
1
and
[~-]
standsfor ( ~ ~1 ~ , ... , ~
usual notationfor
the multi-index isemployed
and
da(Q)
=maxii Izal.
Other
developments
of Theorem A are in[4].
2. -
Applications
of Theorem 1The very
general
set up of Theorem 1 has been conceived in view of itssimple
formulation for someimportant
classes of domains or manifolds.We list some of them.
(A)
S2 is contained in acomplete
]-circular domain A.0 C is such that A
(
1 and(z, w) E 0 imply
Those domains can be
given
the formB C ~n is an open subset
and p
is apositive,
lower semi-continuous function onB. The map pw of Theorem 1 is defined
by ~
H~p(w),
hence0 (z, w)
=Let Q be defined
by 0
> 0,where Q
EC1(ð)
is a realfunction,
rby
theequation ø
= 0. Ourrequirements (1)
and(2)
on theposition
of r withrespect
to Q andto the maps pw become
Ø(O, w)
0,0_, ~ 0
on r and for now E B, O(z, w)
ispositive
for all zE c, Izl p(w).
For any
f
EC°(r)
nCR(r),
set317
and
Li == I I z 1
is the maximal circular set such thatf
extends toLi n Q.
Hence the necessary and sufficient condition
(4)
forf
to be the trace of afunction
holomorphic
in Q, continuous up to r, becomesand this is very easy to handle in concrete cases.
(B)
Q is contained in acomplete
circular domain(Cartan domain)
A.Here A is a domain in
Cz
with the property thatimply Az
E A.If B C
Pn- I (C)
is the open set of thosecomplex
lines which have non-empty intersection with0B~0~
and 7r : is the usualprojection,
can begiven
theequation
where p
isagain
any lowersemicontinuous, positive
function on B. The restis very similar to the case
(A):
let Qbe 0
> 0,0 ~ Q,
and r -{4J
=01
withn
on r. For
any w E B
letLw
be thecomplex
linethrough
thej=1
origin corresponding
to w(Lw =
U{0})
and a(w) ELw,
withla(w)l =
1,be
arbitrarily
chosen.(If
0 E A, we have B = and a continuousa(w)
does notexist,
but thisdisplays
norole).
The function
may be non-continuous.
Nevertheless,
if we setagain
the condition
turns out
again
to be necessary and sufficient forf
to be extendable to Q as we want.(C)
Q is a partof
a disc bundle A.Although
Theorem 1 is stated for open sets, its method works for manifoldsas well. Let be 0 -
{ z
EL, I z I 1 },
where L is aholomorphic
line bundleover a
complex
manifold Band I
a lower semicontinuous hermitian metricon the fibers
Lw
of L, (w EB). Now 0 :
0 -~ D is thecomplex
gauge function of A. Further details are similar to thepreceding
cases.(D)
Q is contained in a domain A withsimply
connected sections.In this case Q c A c
Cz
xC~
and foreach w, Ow -
A n{C~z
x{w } },
there is a Riemann map Aw - D which defines a
function y:
A -> D. If r is unbounded then theL1
1assumption
onf
becomes anasymptotic
condition. Note that if Q ispseudoconvex
then thesimply-connectedness hypothesis
is useless.REMARK 6.
(Inner problems).
This is a continuation of Remark 4 in Sec- tion 1. Let A mp(w ) }
be as in(A)
or(B)
of Section 1, r m{ ~
=0 }
with
§z f0
on r. Foreach w E B, pick arbitrary
numbersa2(w),
withlaj(w)1 p(w), (j = 1, 2),
and 0,~[a2(w), w]
> 0. Setand
define,
as inThen the
following condition,
similar to(10)
is necessary and sufficient for
f
to be extendedholomorphically
to the wholeset A.
3. -
Complexified
doublelayer potential
orPlemelj integral
andproof
ofTheorem A
Let I
be aC
1 arc of curve in thecomplex plane C
suchthat -i
has twoendpoints
and letf
be acomplex
function on ~y. For z we consider theintegral
319
This is a
holomorphic
function The usual context forstudying
F iswhen
f is
Holder continuousin 1,
continuous only.In this case, F is continuous up to / and the
jump
of F across 1 isexactly equal
tof.
If
f
is not Holder butonly
continuous on y(or
continuous on 1,L
1 on~y)
then thecontinuity
of F up tao 1 nolonger
holds and the relationmust be taken in weaker sense,
i.e.,
ondipoles.
Ifz+,
z- are twopoints
on thenormal to ~ at some
point z
E 7, then we have(z+
and z- are taken at the left andright
siderespectively
of thepoint moving positively
on1).
In
particular
if F is continuous up to 1 from oneside,
then it is continuous from the other side too. For all that we refer to[ 11 ]
or to theoriginal proof
ofPlemelj [13].
More about this kind ofintegrals
can be found in[ 11 ],
see also[13].
We are now in a
position
forproving
Theorem A.PROOF OF THEOREM A. Let
F3=
be definedby
theintegral (13)
accord-ing
to z E D+ or z E D-. Since 0 E D- we can write in theintegral (13),
00
=
E-1
and obtain that the left hand side of(6)
is the in-o
verse of the radius of convergence of F- at the
origin.
Thus condition(6)
isequivalent
tosaying
that F- extendsholomorphically
to the whole disc and inparticular
is continuous on 1. Hence, if(6) holds,
then F+ is continuous up to 1, and F+ - F- isholomorphic
inD+,
continuous up to 1 andequal
tof
there.Conversely,
iff
extends in this way, then thepath
ofintegration
in theintegral defining
F- can be deformedonly
in a compact subset of D,going
inside in D+ so that the new set D- includes any
given point
of D and so F-is
holomorphic
in D and(6)
holds. 04. - Proof of Theorem 2
By Hartogs’
separateholomorphicity
theorem there is no restriction if we assume to be inC2
=Cz
x Also we can use a classical theorem ofHartogs ([10],
Lemma2.2.11)
which says that c A cCz
and B cCw
are opensets and A is
connected,
then anyz-holomorphic
function in A x B, which isw-holomorphic
in E x B, is also(z, w)-holomorphic
in A x B.Therefore, using
thehypothesis (1),
weonly
need to prove the statementnear a
point p E r
and choose two small discs D c cCw
so thatp E D x A and r cuts D x A in two open components
(D
x0)+
= Q n(D
xA)
and
(D
x0)-
sothat,
for each w c A, the discD,, =-
D x is divided intwo parts
D’ by
aC
1 curve IW = r nDw.
For any fixed z± E
(D
x0)~,
we consider thePlemelj integral
By
dominated convergence the functions F~ are continuous andholomorphic
with
respect
to zt in(D
xrespectively.
We shall now prove thatthey
arealso
holomorphic
withrespect
to w in(D
x0)~ respectively.
For we fix
(z~, wT-)
E(D
x0)~
and shall prove thew-holomorphicity
nearthis
point.
Take asmooth, compactly supported
function whose support is so small that xsupp 1/J
c(D
x0)~.
If weconsider 0
as a function inD x A, constant with respect to z,
then 1/Jlr
iscompactly supported.
There is
because
f (~, w)(~ -
I is a CR function on r and theholomorphicity
of F~follows.
Observe
incidentally that,
till now, weonly
dealt with the restriction off
to r, thus weproved
the well known Andreotti-Hill theorem[6]
about therepresentation
of CR functions as a difference of twoholomorphic
functions.The
z-holomorphic
functionf
will be considered now.There is c Q,
thus, by moving
theintegration defining
F-, .we have
where
91 D,,,
= nF- is now
z-holomorphic
in D x A,thus, again by
the classical theorem ofHartogs,
we conclude that F- extends to a function in D x A which isholomorphic
with respect to both variables and inparticular
is continuous onr, hence F+ is also continuous up to r as well as
f
= F+ - F-. D321
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Physics Institute
Russian Academy of Sciences Siberian branch
660036 Krasnoyarsk
Russia
Dipartimento di Matematica Universita Roma Tor Vergata
00133 Roma