J
OURNAL DE
T
HÉORIE DES
N
OMBRES DE
B
ORDEAUX
R
EINHARD
S
CHERTZ
Construction of Ray class fields by elliptic units
Journal de Théorie des Nombres de Bordeaux, tome
9, n
o2 (1997),
p. 383-394
<http://www.numdam.org/item?id=JTNB_1997__9_2_383_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
Construction
ofRay
ClassFields
by Elliptic
Units
par REINHARD SCHERTZ*
RÉSUMÉ. En
multiplication complexe,
il est démontré que lesunités
elliptiques
sont contenues dans certains corps de classesde rayon sur un corps
quadratique imaginaire
K,
et Ramachan-dra[3]
a démontré que ces corps peuvent êtreengendrés
sur Kpar des unités
elliptiques.
Pourtant lesgénérateurs
construits par Ramachandraimpliquent
desproduits
assezcompliqués
degrandes
puissances
de valeurssingulières
de la fonction deFe-lix Klein définie
plus
bas,
ainsi que desproduits
de valeurs du discriminant A. Nous démontrons dans cet article que dans laplupart
des cas ungénérateur
est donné par unepuissance
d’unevaleur
singulière
de la fonction de Felix Klein ou bien par lequo-tient de deux de ces valeurs. Ces dernières sont trés utiles pour des raisons
numériques,
car les coefficients de leurspolynômes
minimaux sont relativement
petits,
cequi
est mis en évidence pardes
exemples
en fin d’article.ABSTRACT. From
complex multiplication
we know thatelliptic
units are contained in certain ray class fields over a
quadratic
imaginary
number fieldK,
and Ramachandra[3]
has shown that these ray class fields can even begenerated
by
elliptic
units. How-ever the generators constructedby
Ramachandra involve verycomplicated products
ofhigh
powers ofsingular
values of the Kleinform defined below and
singular
values of the discriminant A. It is the aim of this paper toshow,
that in many cases a generatorover K can be constructed as a power of one
singular
value of theKlein form or as a
quotient
of two such values. The latter arevery suitable for numerical puposes because it turns out that the coefficients of their minimal
polynomials
are rathersmall,
as it can be seen in the numericalexamples
at the end of this article.*
The results of this paper were obtained during an invited stay at the University of Bordeaux.
They were favoured by the warm hospitality of the Institute for Mathematics.
1. Introduction and Results
We let L be a lattice in C and wl, w2 a Z-basis of L with
W2
> 0. The normalized Klein form is then definedby
Here a denotes the a-function of the Dedekind eta-function. z* is
defined
by
with the real coordinates zl, Z2 of z = zlwl + and the
quasi-periods
of the
elliptic
Weierstrass(-function
of Lbelonging
to Wl, W2-In what follows let Il be a
quadratic imaginary
number field ofdiscrimi-nant
d,
D thering
ofintegers
in Ii andf
anintegral
Ideal of D . We denoteby
the ray class fieldmodulo f
overK,
and we assume thatf
is alsothe conductor of
K(f)IK.
We fix a basis off
with > 0. Then for vE ~
we havewhere
f =
min(N
nf)
is the smallestinteger
inf.
It follows from the transformation formula of theeta-function,
that the 12-th powers of the values in(3)
or theirquotients
areindependent
of the choice of basis inf.
So we can write more
elegantly
Using
this notation we collect some known facts in Theorem 1 and 2.THEOREM 1.
1)
cp(v
If)12J
Efor
every v E,i7 ~
f.
2)
The actionof
a Frobenius mapQ(c)
of
Ii(f)/K
belonging
to anintegral
ideal c
prime
tof
isgiven
by
THEOREM 2.
1)
If
gcd(f, f)
=1,
thenfor
vE D B f
the valuec~
(v
If)12J
isthe
f-th
powerof
an elementof
K(f).
2)
Let A be in ,~7 andb,
cprimitive
idealsof
normb,
c, such that 6c iswhere
f*
E N‘ is the nonsplit
part
of f
andf**
E l~Y thesplit
part
of
f .
Further we assume
N(6) -
1mod 12 and N(a6) - 1
the notation
W2]
:= we canfind
an elerrcent{3
EK,
>0,
such that
With this choice
of
basis wedefine
putting
V*(zlL)
:= The traceof
f,~ being prime
tof**
thereis a solution a E Z
of
the congruence a.trace( f,Q) -
r’ 26,-1
modf **.
We2,..a
set
Then
- - - 11 ,. , ,
Further we have the Galois actions
In the
following
letbe the
decomposition of f
into powers ofprime
ideals. We defineBy
W we denote thesubgroup
of roots ofunity
inK,
and we setUsing
this notation we can now state the main results of this article in theTHEOREM 3. Let
f
be the conductorof
We assume that eitherf
is the power
of
aprime
ideal orsatisfies
the conditionej
,~2
for j=1,...,s-1
and ea,~2w,
lgcd(6, w).
We let 6 be an
integral
idealof
I(prime
tof ,
whose ideal class in the rayclass group
,~f
modf
has an orderdifferent from
1 and 3. Then the numbersare
generators
for
the extensionOf
course, the same is truefor
all roots
of
these numbersthat, according
to Theorem 2 are inIf the
hypothesis
of Theorem 3 about thepj’s
is not satisfied we canprove a somewhat weaker result. An
arbitrary integral ideal f
canalways
be
decomposed
in the formwhere f 2
equals
D or satisfies thehypothesis
of Theorem 3.f 1
is theproduct
of low powers of certain
prime
ideals above2,3,5
in the case d -4 andalso above 7 in the case d = -3. Given such a
decomposition
we setI
and we state the
hypothesis
(10)
For anygiven complex
numbersçp,
P EPt,
there exists a character Xof Ai
such thatX(p) =I
~p
for EPf.
THEOREM 4. Let H denote the Hilbert class
field
of
h’ and let b =(A)
be a
principal
ideal in Dprime to f,
whose ideal class inA-fhas
an orderdifferent from 1
and 3. Then under thehypothesis
(10)
about f
the numbers
.I%.-are
generators
for
the extensionI( (f) / H .
However numerical
examples computed
so farsuggest
theCONJECTURE. The assertions of Theorem 3 and 4 hold for an
arbitrary
conductor f
and for every ideal bprime to f ,
whose ideal class in9-f
is of order different from I.We will
explain later, why
our method ofproof
does not carry over to afull
proof
of theconjecture.
In view of Theorem 4 one would like to have also a
generator
for H thatTHEOREM 5. Let A be the discriminant
from
thetheory of elliptic functions
and let a and b be nonprincipal
integral
idealsof
K. We assumefurther
a = bif
a2
andb2
areprincipal.
ThenThe condition "a = b if
a2
andb2
areprincipal"
ismissing
in[5].
It isin fact necessary, because otherwise the element in Theorem 5 is a relative norm to a proper subfield.
It has been worked out in
[6]
that in many cases thegenerators
in Theo-rem 5 are even24th
powers of elements in H. This is forexample
true if aand b are non
principal prime
ideals of norm =1 mod 12 or if thediscrim-inant is
prime
to 6. In fact one can showusing
[6]
thatapart
from trivialexceptions
the ideals a and b canalways
be chosen so that thegenerator
inTheorem 5 is a
24th
power of an element in H.2. Proofs
Theorem 1 and 2 contain known facts that can
easily
be derived fromStark’s
reciprocity
law[7]
and the method described in[6],
as it isexplained
in
[4], [6]
and[7].
To prove the assertions of Theorems 3 and
4,
we letbe the Artin map between the ray class group
9-f
and the Galois group ofFor a
character X
ofRf
we consider the sumJ
Let
f x
denote the conductorof x,
and for everyintegral
ideal tsatisfying
fxltlf
we denoteby
the same letter thecorresponding
characterof At.
Forf
= f x
and X 0 1
we know from CurtMeyer
[2]
that the above sum appearsas a factor in the value of the L-function of K
belonging
to X
at s = 1.Hence
where
w
and wf,,
denote the number of roots ofunity
in Ilcongruent
to1
mod f
resp. modfx -
Of course, on theright
hand side in(14) X
mustbe understood as a character of We
give
a sketch of theproof
of(14),
Itf"
which is
easily
deduced from thefollowing
relation between Klein-forms[1]:
For any twocomplex
lattices L C L’ and for any torsionpoint t
L,
M
where m =
N)
and N aninteger
such that NL’ C L.By
theexponent
12 the factors in(15)
becomeindependent
of the choice of basis in L andL’,
and,
due to theexponent
m, the valuesof p
are the samewhen t is
changed
modulo L’. We set t=1,
L’= f ,
L =jp
with anintegral
ideal f
and aprime
ideal p
of K. Then(15)
can be rewritten in the formwhere m =
l2fN(p)
andef
denotes the unit class inAj.
Now,
taking
conjugates
andlogarithms
of(16),
we find the relationwhich
implies
(14).
We observe thatAf(x)
may vanish iff
~
f X.
This is in fact the obstacle for theproof
of the aboveconjecture.
HoweverAf(x)
isnon zero for
enough
f’s
andx’s
to prove thefollowing
lemma,
whichyields
theproof
of the Theorems 3 and 4.The
proof
of Theorem 4 is obtained in the same way. We observe thatthe
subgroup
it in(19)
corresponding
to the intermediate field Lgenerated
by
E over H consists ofprincipal
ideals,
thusmaking
theapplication
ofLemma 1
possible.
LEMMA 1. Let a and b be ideals in
K,
prime
tof
and not contained in the unit class Then under thehypothesis of
Theorem 3about f
and d there exists a character Xof
~f
satisfying
The same assertion holds under the
hypothesis of
Theorem.~,
if
a and 6 areprincipal.
We
postpone
theproof
of lemma 1 andbegin
by showing
how theasser-tions of Theorems 3 and 4 follow from it: Proof of Theorem 3: Assume that
generates
over K an intermediate field L of We consider thediagram
of the fields inplay
andcorresponding subgroups
of9-f:
We assume now that
K(f).
ThenU #
~1},
andby
lemma 1 thereexists a
character X
of~f
with theproperty
This leads to a contradiction
for, appealing
to = cfor f)
EU,
we canrewrite
Af(x)
in the formwhere the inside sum of the
right
hand side must be zero because 1.Hence L = This
proves the first assertion of Theorem 3. The second
assertion is obtained in the same way.
Setting
where il denotes the
subgroup
ofAj
corresponding
to L. Theassumption
K(f)
implies
~1},
and weget
a contradictionif,
according
to thelemma,
wechoose X
so thatThis
completes
theproof
of Theorem 3. Proof of lemma 1:It suffices to prove the Lemma when the orders of a and b are
prime
numbers.
It is an
elementary
fact about a finite abelian groupG,
that for two elementsin G different from the unit element there exists a character whose value at
the two elements is different from 1. So for a and b
satisfying
thehypothesis
of lemma 1 we can find a
character X
of~f
so thatWe will now
change X
so that in addition to(27)
we haveAf(X) 54
0.If f
is the power of aprime
ideal p, this is not necessary, because thenx #
1implies plfx.
Otherwise we must look at theprime
idealsdividing
the conductor of x. So we consider thecharacter X
of(D/f)*
definedby x
via the
homomorphism
with kernel
(W
+f)
/f,
ef
denoting
the unit class in~f.
According
to thedecomposition
we can
write ~
as aproduct
of characters Xi of and we have the
implication
~ - ~ 2
Thus if all
the xj
are nontrivial,
we can conclude from(14)
that 0.Otherwise we
change X
so that in addition to(27)
allthe Xj
are non trivial.We assume that X, = 1.
By
definition of el and e, there exist charactershypothesis
"p~.
;1 gcd(6, z.c~)"
we can choose so thatviewing
as a character of(~/ f )*
we haveThis
implies
that we can find K E N such thatis trivial on
( W
+f)
/ f .
Thus o
can be viewed as a character of theimage
in
(28).
Using
the same letter weextend 9
to a character of~f
and setThen because of el
X’2
the conductorof X
must be divisibleby
pi , whereas the powers ofp2, I ..., p, - 1
dividing f X
are the same as thosedividing f x.
By
a suitable choiceof p
in(34)
we must nowachieve,
that(27)
ist satisfiedalso for
~.
This meansNow
recalling q #
3 wedistinguish
the casesp = q = 2, p = q >_ 5,
andp #
q. If p = q = 2 we have7P2(a) =
7P2(b)
= 1 and(35)
holds becauseof
xw(a),x-’(6) ~
1. If p =q 2::
5 and pAel
we can conclude in the same way. Otherwise at most twoprime
residues J.L
mod p are forbiddenby
(35)
hence at least two are left tosatisfy
(35).
In the casep j4
q at mostone
prime
residue >
mod p is forbiddenby
(35)
ifp #
2 and at most oneprime
residue p
mod q, ifq #
2. So we canfind p
by
solving
simultaneouscongruences.
Proceeding
in this wayfor j
=2, ...,
s - 1 we end up with a characterX,
whose conductor is divisible
by
pi
... If now p,lfx’
we setWe observe that
~2~‘
is non trivial because of e,/2w.
Hence the conductorof X
xequals
the conductorof X
times a power of ps . Furthermore p can be-
-chosen so that
(27)
is satisfiedby
X.
So x
has the desiredproperties,
andLemma 1 is
proved
under thehypothesis
of Theorem 3.We now
let f satisfy
thehypothesis
of Theorem 4.Applying
the aboveconstruction,
we find acharacter X
with theproperty
(27),
whose conductoris divisible
by
all the that are not in the setP~
defined in(9). ~
canWe set
Then
QR
is a subset ofPf
and thusby
(10)
forthere exists a
character x’
ofAi
such thatSo
by setting
we have constructed a character
satisfying
and,
appealing
to(14),
we haveFurthermore
remembering
that a and b areprincipal
ideals,
we see thatx’(a)
=X’(6)
= 1.So x
satisfies(27),
because X
does. Thiscompletes
theproof
of Lemma 1 under theassumptions
of Theorem 4.Examples:
In the
following
examples
we considerelliptic
units of the formComputing
theirconjugates by
Theorem 1 we determine their minimalpolynomial
withrespect
to K.Example
1: We set d= -19, f
=(2 19)
and a -’7+ 2-is .
* Then(A)
hasorder 3
in Jlj.
So this is a caseexcepted
in Theorem 3.But,
confirming
ourconjecture,
thecomputation
shows that the number E is agenerator
ofExample
2: Weset d
=-7, f
= ~2 =(-1+~ ),
which is oneof the cases
excepted
in Theorem 3 and 4. We choose A = 13.Then,
confirming
theconjecture,
E is agenerator
ofI((f)/ I(
with the minimalpolynomial
, -, ,-,, -
,
_____
Example
3: We set d =-88, f
=(4)
and A = 1 +2 -22.
Then,
according
to Theorem 3 the number E is a
generator
of with the minimalpolynomial
REFERENCES
[1]
D.Kubert,
S.Lang,
Modular Units, Grundlehren Math.Wiss.,
Vol. 244,Springer-Verlag,
New-York/Berlin, (1981).
[2]
C.Meyer,
DieBerechnung
der Klassenzahl abelscherKörper
überquadratischen
Zahlkörpern,
Akademie-Verlag,
Berlin(1957).
[3]
K.Ramachandra,
SomeApplications
of Kronecker’s limitformula,
Ann. Math. 80(1964),
104-148.[4]
R.Schertz,
Galoismodulstruktur undelliptische
Funktionen, Journalof
Num-berTheory,
Vol.39, No. 3,
(1991.
[5]
R.Schertz,
Problèmes de construction enmultiplication complexe,
Séminairede Théorie des Nombres de Bordeaux 4
(1992),
239-262.[6]
R.Schertz,
Zurexpliziten
Berechnung
von Ganzheitsbasen inStrahl-klassenkörpern
über einemimaginär-quadratischen Zahlkörper,
Journalof
NumberTheory,
Vol.34,
No. 1(1990), 41-53.
[7]
H.Stark,
L-functions at s = 1,IV,
Advances in Math. 35(1980),
197-235.Reinhard SCHERTZ
Institut fur Mathematik der Universitit