R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
C ARLO C ASOLO
S ILVIO D OLFI
Conjugacy class lengths of metanilpotent groups
Rendiconti del Seminario Matematico della Università di Padova, tome 96 (1996), p. 121-130
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Conjugacy Class Lengths of Metanilpotent Groups.
CARLO CASOLO - SILVIO
DOLFI (*)
ABSTRACT - We
study prime
divisors of thelengths
ofconjugacy
classes of a finite group G, withemphasis
on themetanilpotent
case. Inparticular,
we compare the number ofprime
divisors ofG/Z( G ) ~ with
the maximum number of dis- tinctprime
divisors of thelength
of asingle conjugacy
class of G.If G is a finite group, we write
.7r(G)
for the set of allprimes dividing
the order of G. If g e
G,
we denoteby
~G(g)
the set of allprime
divisorsof , the
length
of theconjugacy
class of g; then weput
Thus
~o * ( G )
is the set of allprimes dividing
thelengths
ofconjugacy
classes of G. It is an
elementary
fact thate*(G) = oT(GIZ(G)).
Similarly,
in charactertheory,
one defines the set of allprimes dividing
thedegrees
of the irreducible characters of the groupG,
and the maximum numbera~( G )
of distinctprimes dividing
the
degree
of asingle
irreducible character of G. It isconjectured that,
for soluble groups,~(G)~ ~2~(G).
This has been verifiedby
0.
Manz [ 13]
foro~( G ) = 1,
andby
D.Gluck [11]
fora(G) = 2.
To(*) Indirizzo dell’A.: Universita di Firenze,
Dipartimento
di Matematica «U..Dini», Viale
Morgagni 67/A,
50134 Firenze,Italy.
First author
partially supported by
«fondi MURST -Progetto
40% Teoria deiGruppi
aAlgebra
non commutativa»; second authorsupported by
a research grant from Istituto Nazionale di Alta Matematica «F. Severi».date,
the bestgeneral
result to be known is:~ ~o( G ) ~ ~ 3 ~( G ) + 2
(Manz
andWolf [14],
see also[15]).
On the
conjugacy
classside,
B.Huppert
has askedwhether,
for solu- ble groupsThis
inequality
has been verifiedby Chillag
andHerzog [5]
forQ * ( G ) = 1, by
P.Ferguson [7]
for Q *(G)
=2,
andby
Casolo[4]
for~ * ( G )
=3; also,
it showed in[3]
that it holds for everyperfect
group.Several results about the connection between
{} * ( G)
anda~ * ( G )
have beenpublished by
P.Ferguson.
Inparticular
she proves in[10]
that
~o * ( G ) ~ I ~ 4 0~ * ( G ) + 6
for every finite soluble groupG,
andthat
o * ( G ) ~ I 12 0~ * ( G )
forsupersoluble
groups in whichG/G ’
iscyclic [8].
In this paper we collect some observations on
Huppert’s
and relatedquestions.
Inparticular
we provethat,
even for metabelian groups, theanswer to it is
negative;
we showthat,
formetanilpotent
groups,(G) I
3 Q *(G)
and construct inExample
2 a of super- soluble metabelian groups such that Lim~o * (Gn) ~ /(~* (Gn))
= 3.All groups considered are finite. ~°°
Throughout
the paper, we will use without reference thefollowing elementary
and well known facts(see,
for instance[5,6]).
Let G be a
finite
group.1) If x
and y arecommuting
elementsof coprime
orderof G,
then
3)
Let pThen p o-
Q *( G ) if and only if G
has ac centraLSy-
low
p-subgroup.
If G is a finite group, we denote
by F(G)
theFitting subgroup
ofG, by Z(G)
the centre of G andby A(G)
thesubgroup
of Ggenerated by
allthe normal abelian
Sylow subgroups
of G.By
the Ito-MichlerTheorem,
a
prime p
EJt(G)
does not divide thedegree
of any irreducible character of G if andonly if
G has a normal abelianSylow p-subgroup.
Thus123
(which clearly
coincides withn(G/Z(F(G»).
Ourfirst
proposition
is aconjugacy
classanalogue
of[11;
Lemma1.1].
PROPOSITION 1. Let G be a
finite metanilpotent
group. Then there exists x EF(G)
such that a G(x)
=o(G).
PROOF. Let G be a
metanilpotent
group, let F =F(G),
and argueby
induction on
We first observe that we may assume that
G/F
is abelian. Infact,
ifGi /F
is the centre ofG/F,
thenF(Gl)
= Fand,
becauseG/F
isnilpo- tent, :rt(G/F) = n(G1 /F).
We show
that,
for each p en(F),
ifFp
is theSylow p-subgroup
of
F,
there exists xp eFp
such that a G(X) = G : CG (Fp) ~ ). By taking
x
= TI
xp , we will havep E 7l(F)
and therefore the conclusion will
follow,
becauseCG (F)
=Z(F).
Thus,
letK = Fp
for some pr=Suppose
that K’ ~ 1. ThenF(G/K’)
=F/K’
so,if p
divides,’
thene(G) = g(G/K’)
andwe are done
by
the inductivehypothesis.
Otherwise K is aSylow p-subgroup
of F and G = KH where H is a Hallp’-subgroup
of G.Let
C = CH (K);
asH/C
isabelian, by [4;
Lemma2.4]
we haveK
= ~ x
EK; KC).
Since K is notabelian,
there exists x E eKBZ(K)
such thatCG (x) ~
KC. SinceCG (K) = Z(K) CH (K),
for such anelement x we
Suppose
now that K is abelian. ThenCG (K) ~ F
and soG/CG (K)
isan abelian group, the direct
product
of itsp’-component
T and its p-component
P. Observe that is a normalsubgroup
of G and that it is a propersubgroup
of K if P # 1. Asabove,
we canapply [4;
Lemma2.4]
toget
an element x E K whose orbit under T isregular,
with the ad-ditional
property
that x f1. if P # 1. For such an x, we obtainQG
(x) _ Jr( G : CG (K) ~ ).
Thiscompletes
theproof.
For each
prime divisor p
of the order of the groupG,
letGp
be aSy-
low
p-subgroup
of G and letn(p) =
. It is shown in[3]
thatObserving that, by
the Burnside’s criterion forp-nilpotency, n(p)
= 1 ifand
only
if it follows that theinequality I
2 a*
(G)
holds for any finite group G. Moreprecisely,
thefollowing
istrue:
PROPOSITION 2. Let G be a
finite
group and let p be the smallestprime
divisorof
. ThenFor soluble groups, we can say
slightly
more.PROPOSITION 3. Let G be a
finite soluble
group and let p be the smallestprime
divisorof I G: G’Z(G) 1.
. ThenThat this
inequality
is bestpossible
it is shownby Example
1 be-low. For the
proof
of it we need thefollowing elementary
observa-tion.
LEMMA 1. Let G be
a finite
soluble group, P aSylow p-subgroup of G,
acnd suppose that G =G’ CG (P).
Then G isp-nilpotent
cxnd P isabelian
(in particular n( p)
=1).
PROOF.
By
induction on Let N be a normalp’-subgroup
of G.Write G =
G/N
andadopt
the bar convention.Then, clearly,
G == G’
CG (P).
If N #1, by
the inductivehypothesis,
we have thatG
is p-nilpotent
and P isabelian;
as P = P weget
the conclusion. OtherwiseOp, (G)
=1,
whenceOp (G)
=F(G)
and soThus
G = G’ Z(Op(G)).
As G issoluble,
thisyields G=Z(Op(G». 8
PROOF OF PROPOSITION 3.
By
formula(1),
it isenough
to show thatn(q) >
p for every qE,7r(G’). Thus,
let qE.7r(G),
letGq
be aSylow q-sub-
group of
G,
and let N =NG ( Gq )
and C =CG ( Gq ). Now,
the number v ==
NG ’ Z( G ) : CG ’ Z( G ) I
=C(NnG’Z(G)) I
is a divisor ofn( q )
=C I. By
our choiceof p,
we have either%(q) a v a p
or v = 1.Also, clearly CG ’ Z(G) = CG ’ and, by
the Frattinitargument, NG ’ Z(G)
= G.However,
if v =1,
we have G = CG ’ and hencen( q )
= 1by
Lemma1;
therefore in this case. *
We define the class
covering
numbercln ( G )
of a finite group G asthe smallest
integer k
for which there exist 1~ elements gl , g2 , ... , gk of125
G such that
Similarly,
the charactercovering
numberccn(G)
is the smallestinteger
k for which there exist 1~ irreducible characters x 2 , ... , x k of G such thatn(x 1 ( 1 ))
U ... UU
n(Xk (1)
=~o(G).
Alvis andBarry [1, 2]
provethat,
for any finitesimple
group
G, dn (G) £
2 andccn ( G ) ~
3. We will observe inExample
1 thatthe class
covering
number of a metabelian group can bearbitrarily high.
It isinteresting
to notethat,
in thisrespect,
theparallelism
be-tween
conjugacy
classes and characters fails. Theproof
of the results in Section 1 of Manz andWolf [14]
can beeasily
modified togive
the fol-lowing
statement:Let G be a soluble group, then there exist irreducible characters x 1, x2, x3
of G
such thatn(x 1 (1» U n(X2 (1»
Un(X3 (1» ¿ ~o(G)~~2, 31.
Thus
ccn ( G ) ~
5 for any soluble group G.EXAMPLE 1. Let A be an
elementary
abelian p-group of rank % a1,
and OR be the set of all maximalsubgroups
of A. ThusI
=( ~ro n - 1 )/( p - 1)
=: k. M E be a set of k distinctprimes
such that 1 for all For each letCM
be acyclic
group of order qM and let A act onCM
with kernel M.Set N = Dir
CM
with the action of A inducedby
the action onM E M
each
CM .
Then each nonidentity
element of A centralizesexactly ( ~ro n ~ ~ - 1 )/( p - 1) primary components
ofN,
as any such element is contained in that number of maximalsubgroups
of A. Let G =Gn
be the semidirect
product
andlet g
be an element of it.Then we can write with
x E N,
a e A and[ x, a ] = 1. Now,
U
aG(a); clearly and, by
what we have ob-served, ( pn - 1)/( p - 1) - (~n -1 - 1)/(~ro - 1) _ ~ron -1.
Thus
a*(G)=pn-l+1.
NowN=G’,
whence~,~(G’)~ =(~n-1)/(~ro-1)
and the factor tends to
~ro/( p - 1 )
as n goes toinfinity.
In
particular, by taking p
=2,
weget
afamily
of metabelian groupsGn
such that Lim = 2.
n-, n
These same classes of
examples
show that the classcovering
num-ber of a metabelian group cannot be bounded
by
anypositive integer.
Having
fixed aprime
number p, letGn
be the group constructed above.We claim that
cln(Gn)
= n.Let gl ,
g2 , ... ,... U
QG (at ), where,
for each i =1, 2,
... ,t,
ai is thep-component of gi .
By replacing gi
with aconjugate
if necessary, we may suppose without loss ofgenerality
that allai’s belong
to A.Now,
thesubgroup
of A gen- erated ... ,at ~
iselementary
abelian of rank at mostt,
and istherefore contained in at least v =
(pn - t - 1 )/( p - 1)
maximal sub-groups, of A. Hence
(aI’
...,a,),
and so(gl ,
...,gt),
centralizes at least vprimary components
ofGn .
It follows that= to *
(Gn) implies
t ~ n .THEOREM 1. Let G be
metanilpotent
groups, and let p be the srnallestprime
divisorof G : G ’ Z( G ) ~ .
ThenPROOF. We first observe that for any finite group
G, e * (G) =
=
n(G/F)
U,r(G’),
where F is theFitting subgroup
of G. Infact,
let p ~ øjr(G/F)
U and let P be aSylow p-subgroup
of G. Then P ~ F andso P is normal in G.
Also,
P n G ’ =1,
whence[G, P] ~
P n G ’ =1;
thus
P ~ Z(G)
The converse is clear.Let now G be a
metanilpotent
group; then>
I by Proposition 3,
ando~ * ( G ) ~ ~ I by Proposition
1.Thus
That the
inequality
in Theorem 1 is bestpossible
it is shownby Example 2;
inparticular, by letting p
=2,
we construct an infinite fam-ily
ofsupersoluble
metabelian groupsGn
such thatEXAMPLE 2. Let p be a fixed
prime
number. For anypair (n, k)
ofpositive integers
setWe fix a
positive integer n,
and writeB
=(vn, n -
Forsimplicity,
we take n ;3,
in whichcase @
is aninteger.
...,a,j=
=
1, ..., /3)
ofa~3
distinctprimes
such that p divides 1 forall i, j.
Foreach i =
1,
... , a, letRi
be acyclic
group of order pip.Let A be an abelian group which is the direct
product
of ncyclic
127
groups of order
p n .
Then A hasexactly
a maximalsubgroups M1, ... , Ma .
For each i =1,
... , a there is afixed-point-free
action ofA/Mi
onRi .
These actions determine an action of A on the directprod-
uct R =
R1
x ... xRa ,
with kernelO(A)
= Ap. In the semidirectprod-
uct
RA,
we have(in
a way similar to that inExample 1),
for any a E A:’
Write now y = vn, n’ and let q, ql, ... , q. be distinct
primes (and
all dis- tinctfrom p
and the chosen in such a way(use
Dirichlet’sTheorem)
thatgi92-"?y
divideq - 1.
Let C be acyclic
group of order q, q2 ... 9y and N =N1
x ... xNy
anelementary
abelian group of orderq Y .
It is not hard to check that y = vn, n isexactly
the number of sub-groups K
of A such thatA/K
iscyclic
of order we list asA1,
...,AY
all such
subgroups.
We define an action of A x C on R x N in the
following
way. We let C centralize R and induce a non trivialautomorphism
oforder qk
oneach k =
1,
... , y, and let A act on R as describedabove,
and on Nby stabilizing
eachNk
andinducing
onNk
a group ofautomorphisms
ofwith kernel
Ak . Now,
if y is an element of orderp n
in A thenA/ y)
is the directproduct
of n - 1cyclic
groups of order~n . Thus y
iscontained in
exactly
vn. n -1subgroups
of A whosecorresponding
factorgroup is
cyclic
oforder p n.
Each of suchsubgroups
is one of theAi’s,
i.e.the centralizer in A of one of the
components Nk
of N.Hence,
we havethat the number of
components Nk
contained inCN(y)
isprecisely
i
also, clearly, CN( y)
is the directproduct
of suchcomponents.
’
Let G =
Gn
be the semidirectproduct (R
xN) ~ (A
xC).
Then
le*(G)1 = In(R)lln(C)1 [
+ + y + 2.We
compute 7*(G). Let g
eG; by replacing g
with aconjugate
ifnecessary, we can
write g
= xa, where x e(R
xN) C,
a E A and[x, a]
= 1. If =z(R) then, by
formula(2),
Now, by
construction ofG, x
centralizesR,
so c.7l( C) U {p, g}.
Infact,
if h E N is theq-component
of x,U ~ p, q ~,
where9
QG (h)
fl.7r(C). Also,
h ECN (a),
so, iflal I
=pn
then h is con- tained in theproduct
of at most vn, n -1 1 of theNk’s.
It followsthat,
In any case, we have
Hence,
in fact it is easy to see that
Finally,
we have:as
Appendix.
We add some remarks on the
general
soluble case,refering
to a re-cent paper
[14]
of Manz and Wolf.Firstly,
we observe that the argu- ments in their Section1, involving
irreduciblecharacters,
can beeasily rephrased
in terms ofconjugacy
classes. Inparticular,
modifications in Lemma 1.3of [14]
lead to thefollowing parallel
statement.LEMMA 2.
Suppose
that M =CG (M)
is a normalelementary
abeLian
subgroups of
a soluble group G and acompletely
reducibleG-module
(possibly of
mixedcharacteristic).
Assume that Gsplits
over M with
complement
H. Then there exist xE M,
y E H such thatFrom this it
follows,
as in[14;
Theorem1.4] that, given
a solublegroup
G,
then 2 a*(G)
+ 2(see
Theorem 3 below for an129
easy
improvement).
This fact can be used togive
an alternativeproof
ofa
(slightly improved)
result of P.Ferguson.
THEOREM 2. Let G be a soluble group.
Then I e
*(G) ~ I
4a *(G)
++ 2. More
precisely,
let p be the smallestprime
divisorof G : G’ Z(G) ,.
Then
PROOF.
Simply apply
to the above observationProposition 3,
as inthe
proof
of Theorem 1.Indeed,
the constant term + 2 in Manz and Wolfsinequality
is at-tached to the occurrence of the
primes ~ 2, 3}
among the divisors ofobserving
that if theprime
2 or 3 occurs as divisor ofI
then it is controlled
by Proposition 3,
we can remove the additive con-stant 2 in Theorem 2
if p ~
5. Inparticular,
if G is a soluble group such that allprime
divisors ofI
aregreater
orequal
to5,
thenle*(G)1 I 3.25a * (G) (another slight improvement
of a result of P.Ferguson’s).
Also,
thearguments
of Manz and Wolf can beexploited
toget
a re-sult for
arbitrary
soluble groups,comparable
toProposition 1, namely
THEOREM 3. Let G be a soluble group, F the
Fitting subgroup of
G.Then there exist x, y E G such that U
aG(Y);2 ~(G)B{2, 3}.
PROOF. Let y be the set of all
primes p
such that G has a normal non-abelianSylow p-subgroup. By
Ito’s TheoremQ(G)
=y U
Let N =
~(G),
G =G/N
andadopt
the bar convention. Thus F =CZ7 (F) and, by
a Theorem ofGaschiiltz, _F
is acompletely redu_cible_G-module
and it is
complemented
in G. If H is acomplement
of F inG,
we canchoose H to be a
y’-subgroup
of G.By
Lemma2,
there exist x E F and y e H such thatQG (x)
U3}. Clearly then,
UU
aG ( y) ~ ~(G/F)B~ 2, 3}. Let,8 be
the set ofallpey
such thaty central-
izes the normal
Sylow p-subgroup
ofG;
that is~8
=YBUG (y).
For eachq
E,8,
we may take a non-centralelement gq
ofOq (G)
andset g
=q fl e
gq .q E B Then
6G(g) D B. Also, g
and y are twocommuting
elements of G of co-prime
order so: aG aG(g)
U aG(y) D B
U QG( y)
= y U aG( y).
Finally,
U(y
U~c(G/F))B~ 2, 31 = e(G)Bf 2, 3}.
COROLLARY Let G be a soluble group. Then
le(G)1 ( ~ 2~ * (G) + 2.
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