C OMPOSITIO M ATHEMATICA
H. B. K EYNES
D. N EWTON
Ergodic measures for non-abelian compact group extensions
Compositio Mathematica, tome 32, n
o1 (1976), p. 53-70
<http://www.numdam.org/item?id=CM_1976__32_1_53_0>
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53
ERGODIC MEASURES FOR NON-ABELIAN COMPACT GROUP EXTENSIONS
H. B.
Keynes*
and D. Newton Noordhoff International PublishingPrinted in the Netherlands
0. Introduction
In this paper, we shall be concerned with
extending
the results of[6]
to
arbitrary
groupextensions,
andutilizing
ourprevious
results to liftdynamical properties
of measures. Theanalytic
structure of anergodic
measure
sitting
over a fixedergodic
measure was examined in detail in[6]
for compact abelian groups.However,
in most distalextensions,
the groups thatnaturally
arise are ingeneral
non-abelian. Inparticular, given
a distalextension,
one can ’build’ itusing
almostperiodic extensions,
and each almostperiodic
extension comesby ’interpolating’
betweena group extension over the base transformation group
(see [5,
pp.255-6]
for a
precise statement).
In the case where the spaces in theoriginal
extension are
metric,
one can show that the group extensions involved also have metric spaces.Although
this fact issurely known,
we have been unable to locate it inprint,
and thus will include aproof
in anAppendix.
With this in
mind,
the extension ofanalytic
results togeneral
compact group extensions isnatural,
and we carry this out in Section 2. Infact,
we shall carry out our
analysis
for the case where X and Y are compactT2,
and G is metric. Themajor
result obtained is that everyergodic
measure above a fixed one is derived
by
first anisomorphism
and thenan
ergodic
’Haar lift’. Ourisomorphisms
are Borel in the case that Xis metric or T is
countable,
andisomorphisms
of thecompletion
in thegeneral
case. To dothis,
one needs to construct T invariant functions which aresimultaneously eigenfunctions
for irreduciblerepresentations
of the compact group. Problems arise in
obtaining
astrictly
invariantsection in the
general
case; thisyields
the weaker type ofisomorphism
in the
general
case.* Research supporfed in part by NSF GP32306X.
In Section
3,
we consider thefollowing problem : given
a free abeliangroup extension n :
(G : X, T) (Y, T)
and an invariant measure v onY with some
dynamical properties,
how can one’perturb’
the action onX to still maintain a G-extension and yet have the Haar lift of v
enjoy
the same
dynamical property.
Thesimplest type
ofperturbation
comesfrom a continuous
homomorphism
x : T ~G, namely pX(x, t)
=x(t)(xt).
We show that for most
(in
the sense ofcategory)
x, the Haar lift willenjoy
the same property with respect to the action p,. Theproperties
examined are
ergodicity
andweak-mixing,
andanalogous
results forminimality
andtopological weak-mixing
are indicated in certain cases.We note that
Parry
and Jones[4]
first considered thesequestions
forthe most
general
type ofperturbation
under theintegers
and thereals,
and also showed that theseproperties
lift for almost allperturbations.
However,
our actionsbelong
to a set which is first category in theirtopology (the coboundaries),
and hence the results are distinct from oneanother.
We will
generally
follow the notation andterminology
of[6].
Theadditional structures
required
will bepresented
in the next section.1. Preliminaries
We
begin by establishing
some notation. Let(X, T)
denote a topo-logical
transformation group with X a compactT2
space and T alocally
compactseparable
group.We shall
briefly
review thenotation
established in[6]. Thus,
we will beconsidering
a freeG-extension, (G; X, T)
of another transformation group( Y, T)
where Y and G are compactT2,
and n :(G ; X, T) - ( Y, G)
will be the canonical map. If H is a
subgroup
ofG,
we will consider thesplitting
03C0 = n2 0 nl, where 03C01:(H; X, T) ~ (X/H, T) yields
a freeH-extension and 03C02:
(X/H, T) ~ (Y, T)
is the naturalhomomorphism.
Again, M(X, T)
will be the collection of T-invariantregular
Borelprobability
measures onX,
andE(X, T)
theergodic
measures inM(X, T).
Also,
03C0*:M(X, T) ~ M(Y, T)
will be the canonical mapgiven by n * v(B)
=v(03C0-1B).
In our case,n * E(X, T)
=E(Y, T). Finally, if y
EE(Y, T),
the Haar lift
of J1
isgiven by
where is Haar measure on
G,
and03C0-103BC
is the induced measure on03C0-1B(Y).
The main purpose of this paper is to take a fixed
ergodic
measure03BC ~ E(Y, T)
and describeanalytically
the structure of thosev E E(X, T)
with 03C0*v = Il. To this end we have to deal with
representations
of thegroup G. As a
general
reference we refer to[3].
Let
9l( G)
denote the set ofequivalence
classes of continuous finite- dimensional irreducibleunitary representation
of G. With no loss ofgenerality
we will assumerepresentations
act on a suitableCn, C being
the
complex field,
and where necessary we willidentify
aunitary
operatoron C" with its matrix relative to the standard basis. The dimension of
a
representation
a will be denotedby na
and theequivalence
class of awill be denoted
by [a] E 9l( G).
We denoteby
03A3n-1 thesphere
~ lin being
theinnerproduct
norm in Cn.Let a be an irreducible
representation
of G with dimension n. A Borelfunction
f :
X - 03A3n-1 is called ana- function
ifWe first want to show the existence of a-functions. We shall first need Borel sections.
LEMMA
(1.1) :
Let G be a Lie group. Then 03C0 admits local sections, i.e.,given
y EY,
there exists aneighborhood
Uof
y and a continuous maps : U - X with nos =
idu.
PROOF: [10,
page219].
LEMMA
(1.2) :
Let G be aLiegroup.
Then there exists a Borelisomorphism
ç : X - YxG.
PROOF:
By
Lemma1.1,
we can write Y =u 1 Ui, where Ui
is acompact
neighborhood,
andpi:Ui ~ X
is a local section. Iteasily
follows that gi:
Ui
x G ~03C0-1(Ui), (x, g)
-gpi(x)
is ahomeomorphism,
with inverse
where
gpi(z)
E G satisfiesgpi(z). pi03C0(z)
= z.Defining
çby qJ(x) = çj ’(x),
where i is minimal with respect to x ~
03C0-1(Ui), yields
the desired iso-morphism (ç
isactually
continuous except onUni=1 Bd. (Ui),
a nowheredense
set).
We now set gp = pr2 0 ~ : X - G.
Then gp
is Borel and satisfiesx =
gp(x) · p03C0(x),
where p : Y -X, p(y)
=pi(y),
where i isminimal,
is theinduced Borel
section, completing
theproof.
Let
f
be an a-function. Thenf (gx)
=f (x) for g
E ker a, and sof
defines on à-function on the induced extension
where 03B1 is the induced
representation
onG/ker
a.Conversely,
a-functionsyield
a functions. NowG/ker
a ~ im a is a closedsubgroup
of a Liegroup and hence is a Lie group. So a-functions can be
analyzed using
Lie group extensions.
LEMMA
(1.3) :
Let a be an irreduciblerepresentation of
G with dimensionn. Then there are n a-
functions fl ,
...,f"
such thatfor
each x E X the valuesfl(x), ..., fn(x) form
an orthonormal basisof
cn.Every a-function f
canthen be written in the
form
where the
functions ai(x)
are G-invariant Borelfunctions.
PROOF:
Using
the above comments, we assume WLOG that G is aLie group. Let v 1 , ..., Vn be an orthonormal basis on Cn and let p : Y - X be a Borel section. Define
It is
easily
verified that thesesatisfy
the first conditions of the lemma.Finally, if f’
is ana-function,
defineai(x) = ( f (x), fi(x)),
where(-, -)
is the inner
product.
Thenclearly
ai is Borel andSince
clearly f(x) = 03A3ni=1ai(x)fi(x),
the lemma isproved.
One final result on a-functions
LEMMA
(1.4) :
Let m beprobability
measure on X and letf :
X ~ 03A3n-1be a
Borel function
such thatMx)
=a(g) f (x)
a.e. m ,for
each g. Then there is a Borelfunction f ’ :
X ~In- 1such
thatf
= ,f ’
a.e. mand f ’
is an
a-function.
PROOF: Define h : G x X C"
by h(g, x)
=f(gx) - 03B1(g)f(x).
Then forevery g,
m{x : h(g, x) ~ 01 =
0.Setting
K ={(g, x) : h(g, x) ~ 0},
it followsthat 03BB x
m(K)
=0,
and so03BB{g: h(g, x) =1= 01
= 0 for x E L, a Borel set withm(L)
= 1.Hence,
if we definethen
f(gx)
=03B1(g)f(x) (g
EG,
x EX)
andclearly f(x)
=f(x)
if x E L.Now A =
{x|f(x)
=01
is Borel and G-saturated and soLo
= X-Ais also G-saturated.
Thus, f
=f
onLo
n L,m(Lo
nL)
= 1 andf:L0~03A3n-1
is a measurablemapping.
In the setX - Lo,
which haszero m-measure, we
replace f by
any Borel a-functionfo
into En - 1restricted to
X - Lo. Defining f ’ = 1
onLo
andf’ - fo
onX - Lo completes
theproof
of the lemma.2.
Ergodic
measures for group extensionsIn this section we
generalize
the results of[6]
to the case of notnecessarily
abelian compact group extensions. Webegin by giving
necessary and sufficient conditions for
ergodicity
of the Haar lift of anergodic
measure. The sameassumptions
as Section 1 will be in force.THEOREM
(2.1):
LetJ1 E E(1: T).
Then the Haarlift of
Il,fi, belongs
toE(X, T) if
andonly if
there are noa-functions, (X =1= 1, satisfying
PROOF:
Assume fi
EE(X, T)
and letfa
be an a-functionsatisfying
Then there is a constant a E 03A3n03B1-1 and a Borel set
F, fi(F)
= 1 such thatNow for any x, define
Gx
={g: gx ~ F}.
Sincethen
for
03C0-103BC-almost
all x. Pick one suchx E F,
and9 E G X.
Thena =
£(x)
=fa(gx)
=a(g)a.
SinceGx
isdense,
we have that03B1(g)a
= afor
all 9
E G. Since a isirreducible,
it follows that oc = 1.Now assume
that fa 0 t = fa
a.e.fi implies
that a = 1.Let W be the
subspace
ofL2(X, fi) consisting
of T-invariant functions.We
identify L2(Y, Il)
with thesubspace
ofL2(X, fi) consisting
of G-invariant functions. Theergodicity of Il implies
that W nL2(Y, Jl)
=G,
thesubspace
of constant functions.
Since fi
isG-invariant,
the action of G on X inducesa
unitary representation {Ug}
of G onL2(X, ,û).
Since W consists ofT-invariant functions and G commutes with
T,
it follows that W is aninvariant
subspace for {Ug}.
It follows fromgeneral representation theory (see
e.g.,[9,
Theorem7.8])
that Wdecomposes
into finite dimen- sionalsubspaces
onwhich {Ug}
is irreducible. Pick any such finite- dimensionalsubspace
and letfl,..., f,,
be an orthonormal basis of it and03B1(g)
the matris ofUg
relative to this basis. Define a vector-valued functionf
to C"by f
= col( fl,
...,fn)
wheneverpossible
and 0 other-wise. Then
f 03BF g
=a(g) f
inL2.
The set{x: f (x)
=01
is both G-in- variant andT-invariant,
soby
theergodicity of p
has measure 0.Normalizing f
inL2,
weobtain f
to03A3n-1 with f 03BF g
=a(g) f
inL2.
By 1.4,
we can assumef : X ~ 03A3n-1.
Sincef
isT invariant,
we havea = 1. It follows that
{Ug}
is theidentity representation
on W. SoW = .Y n
I3( Y) = C(j and
isergodic, completing
theproof.
Note that 2.1 does not
require
that G be metric.Our next theorem considers the other extreme case when there are the
’maximum’ number of T invariant a-functions.
By isomorphism,
we shallmean
isomorphisms
ofdynamical
systems. Thisrequires
the existence ofstrictly
T-invariant measurable sections in X overY, i.e.,
a Borel set B with03C0(B) Borel, M(nB)
=1,
xt E B whenever x EB, t E
T and n : B ~n(B)
measurable. If either X is metric or T is
countable,
then 03C0 isBorel,
and we use theterm’isomorphism
mod 0’. In thegénéral
case, we will need to consider n :(X, T, v0) ~ ( Y, T, ,uo),
where vo, po are thecompletions
of v, y
respectively.
We then use theexpression ’Lebesgue isomorphism
mod 0’.
THEOREM
(2.2):
For each irreduciblerepresentation
class[a] of
dimen-sion na, let there be na
pointwise orthogonal
T-invarianta-functions.
Letv E
E(X, T)
with 03C0*v = Il.Then if
either X is metric or T iscountable,
is an
isomorphism
mod 0.Otherwise,
is a
Lebesgue isomorphism
mod 0.PROOF : We will construct a
strictly
T invariant measurable section overY Let
fll,
i =1,...,
na bethe na
a-functions of the theorem. Since v isergodic
and 03C0*v = ,u there are constant vectorsai03B1,
i =1,...,
na such thatfi03B1(x) = ai03B1
a.e. v. PutSince there are
only
countable many[03B1],
X’ is a Borel set andv(X’)
= 1.Now let x E X’ and gx E
X’,
for some g E G. ThenThus, a(g)
is theidentity
map since thevectors a’
form a basis of cncx.This is also true for each a and so g = e. Therefore X’ intersects each orbit in at most one
point.
The remainder of the
proof
for the case that X is metric follows the final part of theproof
of Theorem 3.1.3 of[6],
so we sketch the details.We put
X0 = {x~X:xt~X’
for03BE-almost all t ~ T}, 03BE being
a leftinvariant Haar measure on T. Then X ° is a
strictly
T invariant Borel set which intersects each G-orbit in at most onepoint,
03C0X0 is a Borelset and n : X° -
nX° gives
therequired isomorphism.
For the
remaining
cases, we write X° =U~i= 1Ki ~ N,
wherev(N)
=0,
Ki
compact,Ki
cKi+1 and 7r 1 Ki continuous, by
Lusin’s Theorem. ThennlKi
is ahomeomorphism,
andsetting
K =U~i=1Ki, nlK
is a Borelisomorphism.
If T iscountable,
setKo
=nteTKt;
thenKo
is the desired Borel section over Y Ingeneral,
we can assume(see [6,
Remark3.2])
that 03C0X0 is
Borel,
and hence03C0(N)
is Borel withpn(N)
= 0. This willthen
yield
that X ° is the desiredLebesgue
section over Y Theproof
iscompleted.
Finally,
we combine Theorem 2.1 and 2.2 togive
THEOREM
(2.3):
Letv E E(X, T)
with 7r*v = Il. Then there is a closedsubgroup
H =H(v) of
G such thatif
wesplit
the extensionby H;
and put vi =
niv
then rc2 is a measure(either
Borel orLebesgue)
iso-morphism
mod 0 andv1
= v.PROOF: For each irreducible
representation
class[oc]
of G let therebe
precisely la pointwise orthogonal
T-invariant a-functionsfi03B1,
i =1,..., la (note
thatpossibly la
=0).
Since v isergodic
there are constant vectorsai03B1,
i =1,..., la
such thatWe define a
subgroup
Hby
and define
Then
v(X’)
= 1 andgiven
xe X’,
gx E X’ if andonly if g
E H. Nowconsider the
split
extension over HSince X’ is an H-saturated Borel set it follows that
03C01(X’)
is a Borel setin
X/H
withv1(03C01(X’))
= 1. We now notethat 03C01(X’)
is a Borel section for 03C02:X/H ~
Y To do this it suffices to show that if 03C0x1 = nX2 and 03C01x1, 03C01x2~ 03C01(X’)
then nixi = 03C01x2. Thisfollows, however, directly
from the definitions of X’ and H. The
technique
of Theorem 2.2 nowallows us to assert that 03C02:
(X/H, T, v1)
~( Y, T, p)
is a measure isomor-phism
mod 0.We thus have a
strictly
T invariant measure section mod0 ;
p : Y’ ~X/H
with n2 o p =
idY,, p 03BF 03C0t = 03C0t 03BF
p andv( Y’)
= 1. We use p tocomplete
the
proof by showing
that1
isergodic,
and thusvl -
v.Let
[a’]
ER(H)
withdimension na
and let[ac]
ER(G)
extend[a’].
Let
f03B1’:
X ~ 03A3n03B1’-1 be a T invariant a’-function. First we will constructan a-function.
We use
fa,
to construct an a-function as follows: if03C3: X/H ~ X
is any Borel
section,
then 03C3 03BF p : Y’ - X is a section over Y’. If x E03C0-1Y’,
then x =
g(x)ap(nx).
Now we can assume that03B1/H
has the form[03B1’0
’0].
If 0 is an
(na - n03B1’)
x 1 zero vector, we defineSince the set X - 03C0-1Y’ is T and G-invariant and has v-measure
0,
this set is irrelevant and wedefine fa
to be any a-function on it.Now we show
that fa
is T invariant. First note that6(z)t
=h(z, t)u(zt)
for some
h(z, t)
EH,
whenever z EX/H.We
then have thatwhich
gives
thatg(xt)
=g(x)h(pnx, t).
Hence
Therefore fa
is a T invariant a-function and so we may writeNow the coefficients
ai(x)
are both G andT invariant,
and thereforeconstant a.e. v. This means that for almost all x
fa(x) belongs
to thesubspace generated by a103B1, ..., al03B103B1.
Butby
the definition ofH, a IH
is theidentity
on thissubspace.
Therefore a’ is theidentity representation
on H.This shows that
1
isergodic
andcompletes
theproof.
It appears from the
proof
of Theorem 2.3 that thesubgroup
Hdepends
not
only
on v but also on the choice of a-functions. The next result shows that this is not the case.COROLLARY
(2.4) : H(v) = {h :
hv =vl,
that isH(v)
is the stabilizerof
the
ergodic
measure v.PROOF : Since v is a Haar lift
through H(v)
it follows thatLet X’ be the set defined in the
proof
of Theorem 2.3.If g ~ H (v)
thengX’
n X’ -0.
But thenv(gX’)
= 0 andgv(gX’)
=v(g’gX’) = v(X’)
= 1so
gv ~
v andhence g 0 Hv.
ThereforeHv
cH(v)
and theproof
iscomplete.
3.
Lifting dynamical properties
In this
section,
we will consider a free G extension n :(G; X, T) ~ (Y, T),
where X and Y are
metric,
G is abelian and T islocally
compactseparable
abelian. We fix m E
M(Y, T).
Consider Hom(T, G),
the group of continuoushomomorphisms
x : T ~G, provided
with the compact opentopology.
Then Hom
(T, G)
is alocally
compact abelian group.Given X
E Hom(T, G),
we define a new action of T on X as follows: if p is the old action of T
on
X,
we setPx(x, t)
=X(t)p(x, t)
=X(t)xt.
We shall writextx
forX(t)xt.
It is easy to check that
(G ; X, T, p.)
is still a bitransformation group and that(G ; X,
T,p,)
remains a free G-extensionof (Y, T).
Hence for every x, the Haar lift m EM(X, T, p.). Thus,
it ismeaningful
to askif, given
thatm is
ergodic (weak-mixing),
the natural extension m isergodic (weak- mixing)
with respect to p,. The intent of this section is to show that the first statement holds for a residual set in Hom( T, G),
and the secondstatement has a trivial answer in Hom
( T, G).
To prove our
results,
we recall thefollowing
notation: we letT(G)
and
T(T)
denote the character groups of G and Trespectively, and,
if y E
r(G),h
denotes a Borel function of type y,i.e., fy(gx)
=y(g)f (x).
Now consider the
following équations :
The basic result used in our
analysis
is thefollowing
THEOREM :
A. Assume that
m ~ E(Y,T). Suppose
thatwhenever fy
satisfies(1),
then y = 1. Then m is
ergodic.
B. Assume that m is
weak-mixing. Suppose
thatwhenever fy
satisfies(2)
for some b Er(T),
then y = 1. Then m isweak-mixing.
Statement A. is
precisely
the statement of[6,
Theorem3.1.2].
Withregard
toB.,
this statement appears in[4]
for T = Z or T = R.Although
no
proof
isgiven,
this result even in our situation followsdirectly
from[7,
Theorem3].
Forcompleteness,
we sketch aproof.
If the condition issatisfied,
then m isergodic by
part A.Suppose f 0 t
=03B4(t)f[03C0-1m]
(t E
T),with f
bounded and measurable.Since f is
invariant,|f|
is aconstant
by ergodicity
and so we assumef :
X K. Now if h : X - K also satisfies hou =ô(t)h[7i - lm](t E T),
thenh/ f
is invariant and soh =
cf,
c constant.Fix g
E G. Then( f o y) - t
=b(t)(f 0 g)[03C0-1m] (t
ET)
and so
f 03BF g
=03B3(g)f[03C0-1m].
It is direct toverify
that03B3~0393(G)
and sof
is a function of type y. Hence y m 1 and hencef
can beregarded
asbounded measurable on Y
Thus, f
is a constant,completing
theproof.
We need one last definition before
proving
the main result. If U is open in Hom( T, G),
then we can assume that U is basic: U =(x : x(C)
cW},
where C is compact in T, and W is a
neighborhood
of e in G. We say that Hom(T, G)
covers e ifgiven
U asabove, U {~(T):
XEU} ~
V, where Vis a
neighborhood
of e in G.THEOREM
(3.1):
Letm ~ E(Y, T). Suppose
that G is connected andHom
(T, G)
covers e. Thenfor
almost all x, m isergodic
with respect to(X, T, Px).
PROOF :
Suppose
m is notergodic
with respect to(X, T, p,).
Then thereexists
03B3 ~
1 andan fy satisfying (1).
Since G ismetric, T(G)
is countable.For
03B3 ~ 1,
setAy
={~
E Hom(T, G) : x
admits a solution to(1) using yl.
Now for fixed y, we
define :
Hom(T, G)
~ Hom(T, K) by (~)
= y 0 x.Now if x E
Ay
andIr 0 tx
=f03B3[03C0-1m],
thenHence,
(~-1)
is aT eigenvalue
for theoriginal
action of Tand,
since X ismetric,
astraightforward L2-argument
shows that there areonly countably
many sucheigenvalues.
It follows that(A-103B3)
and thus(A03B3)
is countable.
Setting (A03B3) = {(~i):
i ~1},
thenand to prove the
result,
we needonly
showthat -1(~i)
does not containan open set.
Suppose -1(~i) ~ U1,
withU
open. It follows that if U =U1~-1i,
then
|U
= 1. Since Hom(T, G)
covers e, thenU {~(T):~ ~ U} ~ V,
where Tl is open about e. Now
choose 9
E KThen g
=X(t)
for somex E U,
and soy(g)
=y(x(t))
=(~)(t)
= 1.Thus, ylV
~ 1 and soy(G)
isfinite. Since G is
connected,
this is acontradiction,
and the theorem isproved.
With
regard
toweak-mixing,
it isimpossible
toperturb
a non-weak-mixing
flow into aweak-mixing
flow within the class ofperturbations
induced
by
Hom(T, G).
The next result shows thatgiven
x E Hom(T, G), (X, T,
03C1~;m)
isweak-mixing precisely
when(X, T, p; m)
isalready
weak-mixing.
THEOREM
(3.2):
Let(Y, T, m)
beweak-mixing.
Then thefollowing
areequivalent :
(1) (X, 7§ p ; Ài) is weak-mixing.
(2)
For some x E Hom(T, G), (X, T,
03C1~;m)
isweak-mixing.
(3)
For every X E Hom(T, G), (X,
T, px;m)
isweak-mixing.
PROOF : We need
only
show that(1)
=>(3).
Choose x e Hom(T, G),
andsuppose
that fy
satisfiesf03B3(xt~) = 03B4(t)f03B3(x)[03C0-1m]
for some b Er(T).
Then since
we have that
Since
(X, T,
p;m)
is weakmixing,
thisimplies
that y = 1. The conclusion then follows from Theorem B.C OROLLARY 3.3:
A. Let
(Y, T)
beuniquely ergodic,
andm ~ E(Y, T).
Thenfor
almostall x,
(X,
T,03C1~) is uniquely ergodic,
and m Eg(X, T).
B. Let T = Z or
R,
and(Y, T, m)
beergodic
with mhaving
maximalentropy. Then
for
almost all x,(X, T,
px;m)
has maximal entropy.PROOF:
A. This follows
immediately
from Theorem 3.1 and[6, Corollary 2.2.6].
B.
Again,
this followsimmediately by
Theorem 3.2 and[6, Proposition
5.4.4].
We now show that the
assumption
that Hom( T, G)
covers e isalways
satisfied if T is
locally
compactseparable
abelian.THEOREM
(3.4): If
T islocally
compactseparable abelian,
thenHom
(T, G)
covers e.PROOF : First suppose T = Z. Then Hom
(Z, G) ~ G,
andclearly
Hom
(Z, G)
covers e. Next, suppose T = R. Since G isconnected,
then G is asubgroup
of some m-dimensional torus Km, where 1 ~ m ~ oo . If G =Km, m
oo, then Hom(R, Km) ~
IRm. This means that the U thatwe want to consider is transformed to a
neighborhood
of 0 E Rm. Nowit is well known that the one-parameter
subgroups
cover Km.Moreover,
any
one-parameter subgroup
has arepresentation
aswhere
(rl,
...,rm)
vary over a fixedneighborhood
of 0 E Rm. Soand Hom
(R, Km)
covers e. A similar argument holds for K"0.Finally,
if G c KOO is a
solenoid,
then a direct argumentinvolving
the representa- tion of G as an inverse limit of tori shows that in the metric case, theone-parameter subgroups
coverG,
and the same argument holds.Finally,
suppose T isarbitrary.
Then T ~ Rn x Zm xC,
with C compact[2].
Since T is assumed non-compact, either n ~ 1 or m ?1. If n ~ 1,
we have a
homomorphism
p : T ~R,
whichgives
If U is open about
1 T,
then-1(U)
is open about1R,
andby
theabove,
a
neighborhood
of e. But~(R)
=x(pT)
=p(x)(T),
whichgives
the result.A similar argument holds if m ~
1,
and thiscompletes
theproof.
As
noted,
we now have the results for the classical cases T = Z and T = R. For T =Z,
Theorem 3.1 wasalready
known[7,
Theorem4].
We now note some
straightforward
extensions of these ideas. Recall that a free G-extension n :(G ; X, T) ~ (Y, T)
issimple
if for every y Er(G),
there exists a continuous
function fy
of type y. We now consider theequation
We then have :
T HEOREM :
C.
Suppose (Y, T)
is minimal andwhenever fy
satisfies(3),
y = 1.Then
(X, T)
is minimal.D.
Suppose (Y, T)
is minimal andtopologically weak-mixing
andwhenever
fy
satisfies(4),
y = 1. Then(X, T)
is minimal andtopologically weak-mixing.
If(X, T)
is assumedminimal,
thenweak-mixing
isequiv-
alent to this condition.
PROOF:
C. This is a direct consequence of
[6,
Theorem6.3].
D. This
proof proceeds
as in TheoremB, replacing
measurableby
continuous functions.
We use this to prove the
analogue
of Theorem 3.1 forminimality.
THEOREM
(3.5): Suppose (Y, T) is
minimal and 7r:(G; X, T) ~ (Y, T)
isa
simple
G-extension with G connected. Thenfor
almost all x,(X,
T,Px)
is minimal.
PROOF : This
proof
follows the lines of Theorem3.1,
and hence will be omitted.Note that one obvious way of
getting
asimple
extension is to setX = G x Y and define
g(gl, y) == (ggl, y). Applying
Theorem 3.5 in thissetting
says that for almost allp,«g, y), t)
=(x(t)g, yt) gives
a minimalaction on X.
Finally,
for T= Z,
Theorem 3.5 wasalready
known[7,
Theorem2].
We should also note that if
(X, T)
isminimal,
D holds even if G is not abelian(but
T is stillabelian). Thus,
in the case that G issimple, (X, T)
is
topologically weak-mixing
whenever(Y, T)
is.Also,
a direct copy of Theorem 3.2 shows thatagain
in thetopological
case, it isimpossible
to
perturb
anon-weak-mixing
flow into aweak-mixing
flow within the class ofperturbations
inducedby
Hom( T, G).
We
finally
note that if we arewilling
togive
up thecontinuity
ofthe new
actions,
we can obtain the same results in thelarger
group Hom(1d, G)
of allhomomorphisms
from T to G(not necessarily
con-tinuous).
Here we consider T as a discrete group and hence Hom(Td, G)
is compact in the compact-open
topology (being equal
topointwise
convergence
topology). Carrying through
the sameproof
as Theorem3.1,
we recall that
if -1(~i)
~U, and
U =U1~-1i,
thenyi U
~ 1. In thiscase, a finite number of left translates of U covers Hom
(Td, G),
and so(Hom (Td, G))
is a finitesubgroup.
Now suppose that :If
kl, ..., kn
are the orders of the elements of(Hom (Td, G))
andk =
03C0i=1ki,
then(~)k = 1(~~Hom(Td,G)).
Ifg E G
and g =X(t),
then03B3k(g)
=(~)k(t)
=1,
and thus y is of finite order. Since G isconnected,
this isimpossible.
We use this inshowing:
THEOREM
(3.6):
I. Let
m ~ E(Y,T),
and G be connected. Thenfor
almost all x E Hom(Td, G), m is ergodic
with respect to(X,
T,Px).
II. Let.
(Y, T, )
beuniquely ergodic,
and G be connected. Thenfor
almost all X E Hom
(Td, G), (X, T, px)
isuniquely ergodic.
PROOF : We need
only
show that ifTd
is the discrete groupunderlying
a
locally
compactseparable
abeliantopological
group, then(*)
holds.Following
theproof
of Theorem3.4,
we needonly
show this for T = Zor T = R. The first case is
obvious,
so we now show thatif 9
EG, ~(1)
= g for some ~ ~Hom(Rd, G). By [2,
Theorem25.20],
we have thatH =
{~(1)|~
E Hom(R, G)j
is a densesubgroup
of G. If g EG,
choosesequences
(gn)
E H and(xn)
E Hom(R, G)
with gn ~ g andXn(l)
= gn-By
compactness, we have that somesubsequence (~nj)
converges in Hom(Rd, G),
xnj ~ x. Thusgnj
=xnj(1) ~ ~(1)
and~(1)
= g,completing
the
proof.
We end this section
by making
one observationconcerning
weak-mixing
in the case T =Z, i.e.,
we havehomeomorphisms 9:
X ~X, 03C8:
Y - Y In this case, Hom(Z, G) ~
G.If m ~ 1,
thenand
thus,
if m isergodic
with respect to.pm,
then m isergodic
withrespect
to 9..pm
for a.e. g,by
Theorem3.6, 1.
Since a countable intersection of residual sets isresidual,
it follows that if m istotally ergodic
with respectto
gi,
then for a.e.g, m
istotally ergodic
with respect to ~. Since weak-mixing implies
totalergodicity,
we have shown:COROLLARY
(3.7):
Under the aboveassumptions,
suppose(1’:.p, m)
isweak-mixing.
Thenfor
a.e. g,(X,
g - ~;m)
istotally ergodic.
In
general,
we can define totalergodicity
for ageneral
flow( Y,
T,m) by requiring
that( Y, S, m)
beergodic
for everysyndetic
normalsubgroup
S of T. One can then show that
weak-mixing implies
totalergodicity.
Hence,
3.7 will hold for any countable group T.Appendix
In this
appendix,
we show that oneapplication
of thegeneral theory developed
in Section 2 is to the situation where(X, T)
and( Y, T)
aremetric minimal transformation groups with 9:
(X, T) ( Y, T)
a distalextension and
(Y, T) uniquely ergodic.
To seethis,
thegeneralized Furstenberg
StructureTheory (see [5]
for aprecise statement)
says thatwe build X from Y
by
steps of the formwhere
(X03B1+1, T)
is an isometric extensionof (X03B1, T)
in this case(in general, just
an almostperiodic
extension -see [1]
for thesedefinitions)
inter-polating
between the group extension(Ga, Ya, T)
of(Xa, T).
Ingeneral, Ga and Y03B1
are compact Hausdorff. We show that in the metric case we can chooseGa and Y03B1
to be compactmetric,
and thusapply
ourtheory.
We
again emphasize
that some of these results aresurely
known todynamicists,
but we have been unable to find them inprint.
We shall assume
familiarity with
notation and resultsof [1], especially Chapter
12.Let si
c r!4,
A =g(A),
the group ofA,
and setP = ~R03B1|03B1
EA),
the
algebra generated by {B03B1|03B1
EAI.
If B =g(B),
thenis a normal
subgroup
of A. If inaddition, 4
is a distal extension ofA,
then(A/S, [P|, T)
is a bitransformation group with[1, Prop. 12.12
and12.13]. Suppose
in thissituation, (H, |F|, T)
is anotherbitransformation group with A c-- 57 and
(|F|/H, T) ~ (ldj, T).
ThenH ~
A/F
where F =g(F), and
ff A ~ F.Thus,
Aot c ffexc-- 57(ot
EA),
and so P ~ F.