A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
L UCIA B ERETTA A LBERTO T OGNOLI
Some basic facts in algebraic geometry on a non algebraically closed field
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 3, n
o2 (1976), p. 341-359
<http://www.numdam.org/item?id=ASNSP_1976_4_3_2_341_0>
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Algebraic Geometry
on a non
Algebraically Closed Field. (*)
LUCIA BERETTA - ALBERTO
TOGNOLI (**)
Introduction.
Some
aspects
ofalgebraic geometry
on R are studied in[1].
One of themost useful tools to
study algebraic (and analytic) geometry
on B is theconcept
ofcomplexification.
In this work we introduce ageneralization
of the
complexification
which is calledcompletion
and is well defined for any field K. One of thediseagreable
facts inalgebraic geometry
on .I~ isthat theorem B is false.
In
[5]
Lucia Beretta proves thefollowing
theorem: the functor .1~ of theglobal
sections is exact in thecategory
of0~
A-coherent(***)
modules if(V, 0~)
is an affine
variety
on .1~.Clearly
this theoremgives
thegood
condition thatreplaces
the the-orem B and makes it
possible
to workusing
sheaftheory.
In this work we prove that the functor .1~ is exact on the
category
of0v
A-coherent modules where
(V, Ov)
is an affinevariety
on .K and g is any field.1. -
Regular
functions on an affine reducedvariety.
Let .K be a
field,
subfield of the fieldK;
in thefollowing
Kn is consideredembedded in
Kn.
The
algebraic
closure of K shall be notedby K.
DEFINITION 1. Let V be an affine
variety
ofKn,
we shall call closure(or completion)
of V in.K
theintersection 9
of all closed sets ofl~n
that contain V.(*) Lavoro
eseguito
nell’ambito del G.N.S.A.G.A. del C.N.R.(**)
Università della Calabria.(***) An 0, module is called A-coherent if there exists an exact sequence
on 0,, 0.
Pervenuto alla Redazione il 27 Gennaio 1975.
REMARK 1. The
completion f of
Vdepends
on theembedding
andif
K =R, .k
= is the usualcomplexification of
v.PROOF. If n =1 the result is clear.
Suppose
the lemma isproved
for n -1 and let:For any
(x1,
...,zn_i)
Eand xn
E .K we have:P(x1,
...,xn)
= 0then, by
induction ..., = 0 and the lemma isproved.
Let .K be a subfield of
k
and let be a basis of-~
as .g module.We shall suppose
1k = OCi,
E I(we
use themultiindex)
we have:where
DEFINITION 2.
Let,
asbefore,
P ...,Xn]
and be a basisof
k
on .g then thePj(x)
of(1)
are called thecomponents
of P in the basisPi1(X)
is called the.g-component
of P.In
particular
we have and .LEMMA 2. Let
K
be afield
and K asubfield,
V c .gn anaffine variety and V’
thecompletion
init..
Let
Iv,
II p
be the idealsof
the elementsof
...,X n], -k I-x., - - ., X n]
which are zero on
V, ~’.
We have:
I v
isgenerated
asfl
moduleby Iv
Kn = V.PROOF. Let
P1, ... , ~n]
begenerators
ofAny Pi
de-fines an element
P;
of and contains vhence
Pi E Iv.
So we have
proved: (ideal generated by Pi).
Let
now REI v
and .R= .2
be adecomposition
of .R associated toi
a basis
By
remark 2 anyl~i
is an element ofI p
hence :I v
=(ideal generated by Pa).
REMARK 3. Lemma 2 is
equivalent
to thefollowing
relation :and shows that
.~n
induces on X" its owntopology.
~a
LEMMA 3. Let
K
be afield
and K asubfield. Let
V = anaffine
{=1 s
variety of
Kn andVi
the irreduciblecomponents.
=U
the com-_
2=1
pletion of
V inK
are the irreduciblecomponents
wehave : q
= sand Vi is
thecompletion of Vi.
_ a
PROOF. If
Vi
is thecompletion
ofVi clearly U Vi
is thecompletion
i=l
of V. We must prove
that Vi
is irreducibleon ft.
and ..., q.If
Ya =
is reducible we may suppose(Vi
isirreducible)
and this isimpossible
because of theminimality
of9,.
We have
proved
that theV
a are irreducible onft..
If then there
exists "1
such that(Vi
isirreducible)
9~Z
in this case but this is
impossible.
The lemma isproved.
DEFINITION 3.
Let f c Kn
be an affinevariety,
we shall saythat
is
defined
on thesubfield
Kif
the ideal ...,Xn]
isgenerated by
LEMMA 4. Let V c Kn be acn
affine variety and f
thecompletion in K.
The
variety
is the intersectiono f a finite
numberof hypersurfaces defined
on K.PROOF. Let
PI
=... =Ps
= 0 be asystem
ofgenerators
ofIp
anda basis of
.IK
on .K.In this
hypothesis
thecomponents P~
of thePi generate I,
and we have :The lemma is
proved.
DEFINITION 4. Let Y c gn be an affine
variety,
U c V an open set andf :
K a function.f
is calledregular
in zo E TI iff there exists an open setU’3Xo
such that = ... ,Xn], 0,
if x E lT’.f
iscalled
regular
if it isregular
at anypoint.
PROPOSITION 1. Let V c Kn be an
affine variety .Kn
the com-pletion of
V in.~,
K.Any regular f unction f :
V --* K is the restrictionof
aregular function
f : ( ~ - ~S’ ) - k,
where8
is anaffine subvariety of ~’ defined
onK,
such that :8 n V = ø.
Two extensions
f
andf ’ of f
coincide where both aredefined
and the extensionf
is
defined
on K(i. d. locally f
is the restrictionof
aregular
elementof l1 (.tl 1,
...,X")).
PROOF. For any xo E V there exists a
neighbourhood
in V andP,
...,
X n]
such thatf i Uxo
=Q (x) ~ o,
x E -. LetP, Q...
be the elements of ..., defined
by P, Q
....We can construct a
covering
of Vusing
open setsÛx(
== 2013
=01 of V’
such that on anyUxs
an extension!5ilQi
off
is defined.Now we prove the
proposition
in the case: V is irreducible.We have
PiQk - 0, di, k
then 0 and the ra-tional functions define a
regular
functionf : ( - ) - .K,
where_ fJ. o
==n{==0}.
In thegeneral
case letV= U Vi2
be the de-i=l i=i
composition
of into irreduciblecomponents (see
lemma3).
We remark that if U is open
in f’
and then_ ~ -
E7 isclosed,
hence ifoO
containsVi,
contains also IfÛX(
andCl.,;
intersect
~~
thenthey
intersectV,
hence and areextensions of
1,,,
and hence coincide. So we haveproved
the firstpart
ofthe
proposition.
The
unicity
off
isproved
in the firstpart
of theproposition.
REMARK 4.
Proposition
1 is true(same proof), if
V is an open setof
anaffine variety
aneighbourhood of
V in thecompletion.
LEMMA
5. Let k
be afield algebraic
on thesubfield
K and suppose K.Let
P1, Pl(x) _ ... = Ps(x) = 0~ .
Thereexists
... 2 X,,]
such that andP(x)
=00.
PROOF. Let where any element of
.gi
isseparable
on Kand any element of is
purely inseparable
on.gi :
-. Letwe have
Let
Pl2
=rj a(Pl
+roP2)
where G is the Galois group of the exten-ocey
sion
K(a)).
We have thatPl2
isG-invariant,
hencePl2
EK[Xl,
...,Xn]
andclearly :
and
Starting
fromPl2
+wP3
in a similar way we defineP123
E ...,and so on.
Clearly
P =PI2...S
s satisfies the conditions of the lemma. Ifgi
=K,
then there exists WE.~i
and (JJ satisfies anequation
=0,
where p = characteristic of K. Let now
P12
=(PL
+clearly P12
sat- isfies(1)
and(2). Starting
fromP12
andP3
we may constructP123
and soon .... The lemma is now
proved.
PROPOSITION 2. Let K be a
field,
V c .g~ anaffine variety
andf :
V --> Ka
regular function.
There exists
.R, P E .K [X 1,
...,Xn]
such that:PROOF. If .K is
algebraically
closed the result is well known([2]). Let .K
be the
algebraic
closure of .g andV
thecompletion
of V.By proposition
1there exists a
regular
functionf : (Tl -~S) ~.K
that extendsf,
S closed setsuch
that 8
n Kn = 0.We may suppose that the
equations QI = 0, Q2
=0, ... , Q8
= 0of 8
arein ...,
Xn] (see proposition 1).
By
the lemma 5 we know that there exists P E.K[Xl, ... , Xn]
such that~P
=0) DS
andP(x) =F 0
if x E .Kn.The
function /
is defined in the affine(see [2]),
closed subsetV j --- {P
=0}
of
Kn - {jp = 0) ,
y hence it is the restriction of aregular
functionf ’
definedon
Kn - (P = 0) (see [2]).
It is known(see [2])
thatf’
is of the form Let now be theK-component
of R’ withrespect
to a basisof
.K
onK, clearly
and theproposition
isproved.
COROLLARY 1. Let K be a non
algebraically
closedfield
thenfor
any n E N there exists ahomogeneous polynomial
P E ...,X n]
such thatP(X)
= 0i f
andonly i f
X =(0,
...,0).
PROOF. We
apply
the construction of the lemma 5 to thepolynomials X
...,X".
is
homogeneous,
say ofdegree
q, let and so on.A similar construction is
possible
if .K ispurely inseparable
on K.In the
following proposition
we use the euclideantopology
of Rn.PROPOSITION 3. Let Vc Rn be an
affine, quasi-regular,
coherent(*)
com-pact affine variety.
UDV an open setof
Rn andf :
R a C°°f unction
suchthat
f I v
is the restrictionof
aregular function.
For any
compact
setH c tT, E > 0, q E N there
existsuch that :
PROOF.
By proposition
2 there exist such thatQ’l~) ~ ~f
Yz e Rn.By
theorem 1 of[3]
there exist...y~]y
such thatif
P/Q
=(P"Q’+ P’)/Q’ i), ii)
andiii)
are satisfied.2. -
Properties
of coherence.Let .g be a field and
0xn
the sheaf of the germs of theregular
functionson gn.
A
(non reduced) affine variety
on K is aringed
space(V, °Kn¡Jv)
where
Jv
is a coherent ideal subsheaf ofOg~
and: V =support Op.
(V, 0v)
is called reduced iff3 =
sheaf of all germs zero on V.(*)
V is quasiregular
in x if the ideal of analytic functions zero isgenerated
by 1,, V isquasi
regular if it is so at anypoint.
V is coherent iff the associatedanalytic
space is coherent.Following [2]
we callalgebraic prevariety
on K aringed
space(X, Ox) locally isomorphic
to an affinevariety
defined on K.Finally
analgebraic prevariety (X, Ox)
is called avariety
iff thediag-
onal
11x
of is closed inLet
(X, Ox)
be analgebraic prevariety
on K and 3 a coherent ideal sub-sheaf of
Og,
theringed
space(V =support OXIJ, OXIJ)
is called an al-gebraic subprevariety
of X.As usual we can define the
locally
closedsubprevariety
of(X, Ox)
andit is easy to
verify
that anylocally
closedsubprevariety
of(X, Ox)
has anatural structure of
algebraic prevariety
on K.It is easy to
verify
that anysubprevariety
of analgebraic variety
on Kis an
algebraic variety
on K.In
particular
we shall callprojective variety
any closedsubvariety
ofP n(K)
=projective
space on .K of dimension n.Let ~K be an
algebraically
closedfield,
and an affinevariety.
An
0.
module Y is coherentif,
andonly if,
there exists an exact sequence:For any g we
give
thefollowing
definition : an0 ~
module Y is called A-coherentif,
andonly if,
there exists a resolution oftype (1).
We have the
following
THEOREM 1. Let an
affine
reducedvariety
on thethen
0xn , 0v , Jv
are A-coherent modules and0,,
is an A-coherent0v
module..PROOF.
Using
thearguments
of[2]
we prove all the coherence condi- tions(the arguments
do notdepend
on the fact that K isalgebraically closed).
We have the exact sequence
hence to prove that
0,
is A-coherent we mustverify
that there is a sur-jection 0~-~~-~C
and this isproved
in[2].
To prove that
3,
is A-coherent we mustverify
that there is asurjec-
tion
0 £n
-* Ker 0.Let
~~
=(0,
...1,
...0),
i=1,
..., p be thegenerators
of and letbe the
images
inLet now
suppose K
beinfinite,
otherwise Kn is discrete and the theorem is trivial.Let be a local relation. The
i=l 1n .
function y
is zero on an open nonempty set,
hence isp B=i
identically
zerogives
aglobal
relation thatgenerates
the local one. So we have
proved
that there exists an exact sequence and3,
is A-coherent.The fact that
0-~
is an A-coherent0v
module isproved by
thefollowing.
LEMMA 2. In the
hypothesis of
theorem1,
asheaf
Yof 0~
modules isA-coherent as
0,
moduleif,
andonly if,
it is A-coherent as module.PROOF.
Using
thearguments
of[2]
we prove the conditions of coherence.Let us suppose we have the exact sequence
then we can construct the commutative
diagram.
where n’ and n" are defined
using
the canonicalprojection
and or is defined in thefollowing
way :( 0,
...,1,
...,0 ), i =1,
..., p be thegenerators
of
r(O~)
andWe remark that the maps
n" :T(0£n) -T(0$)
aresurjective (see proposition
2 of§ 1).
Let then a is defined
by
The exact sequence proves the A -coherence of
as
0xn
module.Let now be defined the exact sequence
We deduce the commutative
diagram:
where J is defined
using
the abovearguments and j
can be defined because is an0,
module and hence if we have = 0. From the dia- gram we deduce the exact sequenceOv
X-’~ ,~ -~
0 that ends theproof.
REMARK 1. There exist
locally
free sheaves on R that are not A-coherent.Let is irreducible
(see [1])
and=
0} = (0, 0, 0)
u(1, 0, 0).
Let .F’ -~ R3 be the line bundle defined
by
thecocycle 1/rp given
in thecovering
R3 -(0, o, 0), U2
= R3 -(1, 0, 0).
Let T be the sheaf of the germs of
algebraic
sections of F.It’s easy to see that any section on
~i
that can be extended to aglobal
section can be divided
by cp
and hence it is zero on(0, 0, 0).
From this factit follows that Y does’nt
satisfy
theoremA,
and hence it is not A-coherent.We remark that there exist coherent subsheaves of
ORn
that do notsatisfy
theorem A.
Let Y be the sheaf above constructed and y the section that coincides
with 99
on R3 -(0, 0, 0)
and 1 on the second chart.Let Y’ be the subsheaf of Y
generated by
y, we haveclearly ORa .
Y’ contains the subsheaf 99. and hence Y" does’nt
satisfy
theorem A.
PROPOSITION 1. Let K be a
field, (V, Ov)
anaffine subvariety of
Kn andIn this
hypothesis (Vp
={x
E V:0},
is anaffine variety. If
K is notalgebraically
closed any open setof
V is anaffine variety.
PROOF. It is not difficult to
verify (see [2]),
that(Y,
isisomorphic
to the affine
subvariety
of definedby
=0,
1- P 0where g, = ... = gq = 0 are
generators
ofIf ..K is not
algebraically
closed the lemma 5 of§
1 proves that any closed set of V isjust
the locus of zero of some ...,Xn]
intersected with V and theproposition
isproved.
PROPOSITION 2. Let K be a non
algebraically
closedfield
then theprojective
space
Pn(K)
isisomorphic
to anaffine variety.
PROOF. Let ...,
Xn]
be anhomogeneous polynomial
ofdegree q
such that
R(X)
= 0 « X =(0,..., 0) (see corollary
1 of§ 1).
Letthe Veronese map of
degree
q and w = va xR:the map obtained
adding
.R to the set of all monomial functions ofdegree
q.Clearly w(Pn(K))
~1{R
=0) = #
hencew(Pn(K»)
is an affinevariety
of
isomorphic
toPn(K).
3. - The
completion
of aprevariety.
In this
paragraph
we shall define thecompletion
of an affinevariety
(non necessarly reduced),
and of analgebraic prevariety.
DEFINITION 1. Let g be a
field,
subfield of the fieldk,
andan A-coherent module. A
sheaf f -+ U,
defined on aneighbourhood
Uof in
li n
is called acompletions
of T(in 8 )
if there exist two exact sequencessuch that a is an extension of a. A
completion # -
IJ is called a strongcompletion
iff for any x E .gn we have:In the
following,
we shall consider Ycanonically
embedded in andit is easy to
verify that,
from the fact thatOlKn
is a subsheaf of it fol- lows that Y is a subsheaf of’PlKn.
REMARK 1.
If l~
isalgebraic
onK,
thenOkn
is astrong completion of If If.
is notalgebraic
onK,
ingeneral
PROOF. Let be a basis of
K
onK,
and ail= 1K.
We need thefollowing
LEMMA 1.
If .K
igalgebraic
onK,
and... , X n]
suchthat there exist
Pi, Qi E g[Xl, ..., .Xn]
such thatUsing
lemma1,
we shall prove remark 1.For any
x E gn,
letwhere
AB
=ring
of fractions withrespect
to B.We have a natural
isomorphism .~[Xl, ... , X,,] -- .K[Xl,
...,.X~.]
and we define an
We wish to prove
that j
isbijective.
we have:
But the last term is zero iff the coefficients of the are zeros and in this case
i,9 1ct i
hence j
isinjective.
Lemma 1 proves
that j
issurjective.
Let now K =
Q
= field of rationalnumbers, g = Q (~) ;
we wish to provexQQ ~ Q (~)
In fact but any element of is a
well defined function on a hence
PROOF OF LEMMA 1. We remark that
8
isinteger
onK,
henceOin x
isinteger
on°Kn,x.
’ We have a naturalinjection j :
so we_
’
K
’
can deduce that A def
(D .K
isinteger
on°Kn,x.
Letflz
be the maxi-’
K _
’
mal ideal of ’
clearly It
K is maximal in A and A is a localring
K
(in general
.A has finite numbersI1,
...,h
of maximal ideals over but anyIi
containsflz
hence A islocal).
It is now clear that the maximalK _
ideal of ’ is
isomorphic
toQ Ê, hence j
is anisomorphism.
K
REMARK 2. Let K be a
field, subfield of
thefield E.
For any A-coherentsheaf
Y -* .Kn there exists acompletion
Uand, i f .K
isalgebraic
onK,
then there exists a strong
completion.
In any case we have :,~ x
~ 9Vx E .Kn and
hence, i f Ê.
isalgebraic
onK;
OxnPROOF. There exists a resolution:
Let YI, ..., rjl, be the
generators (0, ..., 1, ... , 0)
....To fix oc is
equivalent
to the definition of such that where oc*: is inducedby
a.There exists
(see proposition
1of § 1)
an open set U of8n
such that U :) Kn and the au are the restrictions ofregular
functionsâij
defined on U(moreover
the1i;;
are defined on .g and U =8n - S
where ~S is closed and defined onK).
The matrix
(âii)
defines0y 3+ 0g
and the sheafcoker ~ _ ~’
is acompletion
of T.If
K
isalgebraic
onK, then, by
remark1,
we have for anyFrom
(1)
it and the firstpart
of the remark isproved.
K
In the
general
case we have and the sequence:may be written:
and the remark is
proved.
REMARK 3. Let K be a
field, subfield of .K, (V, 0v)
anaffine variety
onK,
and ,~ -~ V an A-coherent
0.
module. Let~’ ~
U be acompletion of
~’ andy E then there
exists y
U’ open in~’, V,
suchthat y
ex-tends y.
Let a : be a
homomorphism of
coherentOv modules,
andi’, g
twocompletions,
then there exists an extension & :T^lu Olu of
a where U is aneighbourhood of
V inf.
PROOF.
Using
the trivial extension of Y toKn,
it isenough
to provethe remark when V= gn.
We have an exact sequence
that can be extended to:
(see
remark2).
Let then there exists a
family ~T~’~}a-1...,s
of open sets(of U)
and sections such that : U is an affine open set of
Kn
containing
Kn and ’The
cocycle
is defined on thecovering {Ui}
and it has values inKer f¡,
hence(by
theoremB)
is trivial. From this it follows thatthere exists such extends y and
the first
part
of the remark isproved.
To prove the second
part
we construct the commutativediagram:
To define
y’
andy"
we make thefollowing
remark: all sheaves and verticalmorphism
can be extended toSpec (see
lemma 2 of§ 4) ;
hence the functor of the
global
section is exact on the vertical sequences(we
use the firstpart
of lemma3, § 4).
Letði = (0,
...,1,
...,0)
be the canonical
generators
andAs we have
just
remarked there existsOi
EF(O’n)
such that =y’
is definedby y’(~i) = 8i.
In a similar way we define
y".
The
morphism y’, y"
can be extended(see
remark2)
and hence also y has an extension to thecompletions
and the remark isproved.
DEFINITION 2. Let K be a
field,
subfield ofK,
and an affinevariety
definedby
the ideal subsheafJv
of°Kn.
A(strong) completion
of( Y, 0 p )
ink,
is any affinevariety
such that the sheaf0r
is a(strong) completion
of0.-
REMARK 4. Let be an
affine variety
and supposePl , ... , Pq
EE K[XI,
...,Xn]
generateJv
in anypoint of
V.(By
the remark contained in theorem 1of §
23v
isgenerated by
a finite number ofpolynomials).
let Pi
be the elementsof k[Xi, ... , Xn] defined by Pi,
thesheaf of
idealsgenerated by P,,
...,Pa . If K
isalgebraic
onK,
we have :23 - Annali della Scuola Norm. Sup. di Pisa
hence the
completion defined in §
1 coincides with thecompletion o f de f inition
2.Moreover
if
V c .Kn then there exists acompletion f
closed inl~n.
PROOF.
By
definitions and remark 1 we have the exact sequences :Clearly
then from(2)
we deduce the exact sequence:and
(3)
proves that°Kn¡3y)
is astrong completion
ofREMARK 5. Let
(V, Ov)
be anaffine variety
on K andan exact sequence
of
A-coherentOv
modules.I f Ov)
is acompletion of
V in thefield I~
there exists an open set U’of ~’
such that : V and thehomomorphisms oc, P
extend to an exact sequence :where
~’, i, ~"
arecompletions of Y’, Y,
~’"de f ined
on U’ and&, ~8
extend a,fl.
PROOF. The existence of
(2)
isproved
in remark 3. For any x E Vwe have :
The sheaves and
Kerp
are coherent hence(3)
is true in aneigh-
bourhood of x and the remark is
proved.
DEFINITION 3. Let K be a
field,
subfield of.K
and(X, Ox)
aprevariety
defined on K.
We shall say that the
prevariety (X, Oi)
defined onJE’
is acompletion
of
(X, Og)
iff X and for any E X there exist two affineneighbour-
hoods
Ux
in X and inX
such that is acompletion
of( l~x,
We have the
following:
THEOREM 1. Let K be a
subfield of
thefield .K
and(X, 0.)
aprevariety de f ined
on K.Then there exists a
completion (.~, Oi) of (X, Ox)
andif (X,
is avariety,
Oi)
can be chosen to be avariety.
Let 99: (V, °v)
~(X, Ox)
be amorphism of K-prevariety
and{.X, Og )
twocompletions ;
then there exists anextension ’ of
(pdefined
on aneighbourhood of
V(hence
thecompletion
isunique
nearV).
We need the
following:
LEMMA 2. Let K be a
subfield of .K, (V, Ov)
be aprevariety
on K anda
completion of
V.Let
(X, 0.)
be aprevariety
onK, (X, Oi)
acompletion
on.8 and 99: (V, Ov)
-(X, Ox)
be amorphism,
then there exists an extensioncp: (f’,
~(X, Oi)
of
qgdefined
on aneighbourhood 1" of
V and two such extensions coincideon a
neighbourhood of
V inf.
PROOF. For any x E V there
exists,
inV,
an open set x such that:is contained in an affine open set
W
of ~’ and-W~,
has acompletion lil,
that is an affine open set of
1.
We may suppose moreover that
V,,
is contained in an open set ofP’
such that is a
completion
ofV.,
and for E we haveUsing proposition
1 of§
1 we may construct an open(in ~’) covering
F,,
1 ... ,9,
f Jof F
and some extensionsaei : 99 1 fa: -8
ofLet x E
V, using
theargument
ofproposition
1of §
1 we deduce thatthere exists an open set
of *P
such that allthe tPilB:
coincide(where
defined). (If f3,,
= is thedecomposition
ofD.,
into irreducible com-ponents
werequire that P,
m V =Bi has Pi
ascompletion).
So
gluing together
the’i
we define the extension of lp, theunicity
of theextension is
proved by
the sameargument.
We remark that the lemma 2
implies
that if 99 is anisomorphism
wemay extend 99 to an
isomorphism 0’: ( ~’, --> (±’, Ox’) (it
isenough
toextend 99 and and to
verify
that id ~id).
PROOF OF THEOREM 1. Let ‘li,
_ ~ ~h~2=1,...,a
be an open affinecovering
of X and
ZTz
c Kn, some realisation ofWe shall denote
by ZI$
thecompletions
of17~
in .Kn; andby Z7~
~Ui
sthe natural
isomorphisms.
Let
U2)
and = ·U~2
~U2’
Using
the lemma 2 we may extend e12 to amorphism
defined on anopen set
(Jla
ofCill
and we may supposeê12: Ûla
is an iso-morphism.
Using ê12
we mayglue together Ui
withU2
and construct acompletion
of
UI
UU2. After q
constructions we have thecompletion
of X. We wish to prove that if X is avariety
then8
can be constructed to be avariety.
It is
enough
to prove that if X =XI
U~2
is thedecomposition
of Xinto open
sets,
andXi
are twovarieties, completions
ofXi,
then we mayglue together
two open sets i ofX
Z and obtain avariety comple-
tion of X.
Let and the
identity
map. Letan extension of
(where x ~’ y ~
y =
êI2(X)),
be thequotient
and n: be the naturalprojection.
The
diagonal .312
ofXï2 X ~ 12
is theimage (under n X n)
of4 22 U d~11 U 112
Ud 2i
where
L1 ii = diagonal
of andgraph
ofêik.
It is easy to see thatX 12
is avariety
iff the3 ik
are closed subsets of Theni’12
isa
variety
iffJ ik, i ~ k,
are closed inX =
Xi
U~2
is avariety
then1112
and1121
are closed inXl
XX2
and~2
XXl.
Let
L1;k
be a closedcompletion
of in For anyXEXI2, 1112
isthe
graph
of the map hence in aneighbourhood 0
of x inXl, Ji2
isthe
graph
of a map~12
that extends ~12. Then there exists an openneigh-
bourhood
~’i2
of.Zi2
ini#i
such that~i2
is thegraph
of a map~i2 : X12 -~ ~2’
Using
the sameargument
forLl21
we find two open sets8]
such that
11ik
defines an extension of on8§
andclearly Llik
is closedin..Xi X .Xk .
The theorem is now
proved.
4. - The exactness of the functor r.
We wish to prove the
following
THEOREM 1. Let an
variety
on thefield
K.T hen the
o f
theglobal
sections is exact on thecactegory of
the A-coherent
Oy
modules.We
begin
with a definition.DEFINITION 1. Let
(V, 0v)
be a(reduced)
affinevariety
defined on thefield
K,
we shall call associated scheme the afline schemewhere
Osv
is the usual structural sheaf associated toSpecry
andry
=LEMMA 1. Let
(V, 0~)
be acnaffine variety
and asso-ciated
scheme,
then there exists a naturalinjection j :
such thatof the closed
points
ofPROOF. Let V be realized in
Kn,
I then to anypoint x
=(OCI,
...,9 ’Xn)
E Vwe associate the maximal
ideal j(x) generated by
the classes~X ~ - a2~
19
..., n.Now we wish to prove that any y E defines an element Yun;(V) of
We may suppose for a fixed and
by
de-finition we have that any element of is of the form
P/f’P,
If then
f w z « f(j-i(z)) # 0
andclearly
is aregular
func-tion on
Let now x E
U,
thenlocally y
is theimage
of a rational func- tion hence it is the restriction of a section of defined on an open set ofSpec-Vv containing j(x).
So we haveproved °SYI;(y) = j*(Ov).
We wish now to of the closed
points
ofSpec (7~.)}
y(the
other inclusion isclear).
Let a be a maximal ideal of
ry
andV
cKn
be thecompletion
of V intothe
algebraic
closureK
of K.Let oc be the ideal of
rv generated by
a and S the locus of zeros ofa,
let us suppose ~S = 0.
Any
...,Xn]
such thatP Is =
0is, by
themaximality
of a, in a.By
lemma 5 of§ 1
there existsP c K[XL
...,Xn]
such thatP(x) =1=
0if hence and this is
impossible.
So we mustsuppose
hence, again by maximality:
and the lemma isproved.
REMARK. In the
following
we shalloften identify
Vand j(V), Ov
acnd ....
DEFINITION 2. Let be an affine
variety
defined on .g anda coherent sheaf of
0. module;
a coherent sheaf#-Spec
of
Osp
module is called an extension of ~’ iff there exist two exact sequences:where a is an extension of a.
LEMMA 2.
Any
A-coherentsheaf
,~ --~ Vdefined
on theaffine variety
V hasan
PROOF. We have an exact sequence
and a is
given by
where ti =(0, ..., 1, ..., 0)
Ek
Yk =
(0, ... , 1,
...,0 )
and Let a ix be the extension of aax toSpec(ry)
andOsp
themorphism
definedby (aik)i,k.
·Clearly
coker a is a coherent sheaf and is an extension of Y.LEMMA 3. Let
( TT, Op)
be anaffine variety de f ined
on thefield
K and~’ -~ V an A-coherent
sheaf of D ~
module. Let$ ~ Spec (1’Y)
be an extensionof
Y and y E then there E such thatj*(y)
=If Y, 9
are two coherent sheaves on V andY, g
twoextensions,
any mor-phism
ae: Y can be extended to amorphism a: j --~ ~.
PROOF. Is the same as the
proof
of the remark 3of §
3.COROLLARY 1. Let
( TT, OY)
be anaffine variety defined
on thefield
Kand ~’ -~ V an A-coherent
sheaf. Any
two extensions i= 1, 2,
of Y are
canonically isomorphic.
PROOF. The
identity
section of Hom($1’
can be extended toa global
sectionii; ii: $1 -+
is anisomorphism
for any xE j (V) hence, by
the
argument
used in lemma3, j7
is anisomorphism.
LEMMA 4. Let
( V, 0 p )
be anaffine variety defined
on thefield
K and0 --~ ~’’ -~ ~’ -~ ~" --~ 0 an exact sequence
of
A-coherentOv
modules. The sequenceof
extendedmorphisms :
is still exact.
PROOF. The relation
Ker Pa;
is true for any xE j ( Y)
hence forany
xESpecry (see
theargument
of lemma3).
REMARK. It is
possible
to associate to anyalgebraic prevariety (V, Ov)
on the
field
K aprescheme
in thefollowing
way :if
K 18 thealgebraic
closureof .K,
to(V, Ov)
we may associate onecompletion (V, 0j), (see § 3),
and to(V, Op;)
we may associate in aunique
way aprescheme (see
D.Munford,
« Anintroduction to
algebraic geometry »).
PROOF OF THEOREM 1. First we remark that it is
enough
to prove that if the sequence, ,
is
exact,
then the sequenceIn
general
we know that if(1)
isexact,
then:is exact.
It is
enough
to prove that ifis
exact,
thenis exact.
Let 9 -i* Y’--* 0
be an extension of ot; the coherent sheavesY-,
5i"" aredefined on hence we have:
is
surjective (by
theoremB) .
Let now y
E r(:F"); by
lemma 3 there exists an extensionji E T(§")
of y,by (4)
thereexists if
such thata*(~)
=y
hence y = and the theorem isproved.
REMARK. Theorem 1 can be
proved
alsousing
thecompletion of
V insteadof
the extension(see [5]
for theproof
in the realcase).
As a consequence of theorem 1 we have :
THEOBEM 2. Let K be a
field
and(V, Ov)
anaffine variety
on K. In thishypothesis
the categoryof
A-coherentOv
modules isisomorphic
to thecategory of finitely generated 1’’(OY)
modules.PROOF. The same as in
[2]
and[5].
BIBLIOGRAPHY
[1] M. GALBIATI - A. TOGNOLI, Alcune
proprietà
delle varietàalgebriche
reali,Annali della S.N.S. di Pisa (1973), pp. 359-404.
[2] J. P. SERRE, Faisceaux
algébriques
coherents, Ann. of maths., 61 (1955).[3] A. TOGNOLI, Su una congettura di Nash, Annali della S.N.S. di Pisa, (1973),
pp. 167-185.
[4] Seminari Cartan 1960-1961.
[5] L. BERETTA, Sull’esattezza del funtore 0393 in geometria algebrica reale, Boll. U.M.I.
(1974), pp. 66-74.
[6] H. CARTAN, Variétés analytiques réelles et variétés
analytiques
complexes, Bull.Soc. Math. France, 85 (1957), pp. 77-99.