C OMPOSITIO M ATHEMATICA
D. R. L EWIS
The dimensions of complemented hilbertian subspaces of uniformly convex Banach lattices
Compositio Mathematica, tome 50, n
o1 (1983), p. 83-92
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83
THE DIMENSIONS OF COMPLEMENTED HILBERTIAN SUBSPACES OF UNIFORMLY CONVEX BANACH LATTICES
D.R. Lewis *
Compositio Mathematica 50 (1983) 83-92
© 1983 Martinus Nijhoff Publishers, The Hague. Printed in the Netherlands
For X a
given
Banach spaceDvoretzky’s
Theorem[ 1 ] implies
that every finite dimensional E c X contains a Hilbertiansubspace
F. In this paperwe are interested in
spaces X
for which the F’s canalways
be chosen tobe
uniformly complemented
inX,
andespecially
inobtaining
estimatesfor dim F in terms of dim E. It is
clearly
necessary to suppose that X doesn’t contain~n1’s uniformly.
For Banach lattices X Johnson and Tzafriri[8]
have shown that the last condition is also sufficient. Thenovelty
of the resultspresented
here is the estimates for dim F in terms of dimE,
which arequite sharp.
The maintechnique
used in theproofs
isthe version of
Dvoretzky’s
Theorem provenby Figiel,
Lindenstrauss and Milman in[2];
forproperly
chosenellipsoids
theLevy
means involvedthere can be estimated
using
theproperties
ofp-summing operators
defined on the space X.This paper was submitted in another
place
in1978,
and so has beendelayed
inappearing.
Since that time the resultspresented
here havebeen
considerably strengthened: Figiel
andTomczak-Jaegermann [21] ]
extend these results to
uniformly
convex and k-convex spaces;Benyamini
and Gordon
[20]
consider random factorizations of maps moregeneral
than the
identity on ~n2:
Pisier’s theorem[22]
a space notcontaining £? ’s
must be k-convex shows all the results mentioned carry over to B-convex spaces.
The notation and
terminology
used here is for the most part standard.We
only
recall the definitions used in the statements of theorems.A Banach lattice L is q-concave if there is a constant A > 0 with
for all xl, x2, ... , xn E L.
Similarly
L is p-convex if there is a constant* Research partially supported by NSF Research Grant MCS 77-04174. Received April 14, 1980.
B > 0 with
for all x l, x2, ... ,
xn E L.
In each case we writeKq(L)
andKp(L)
for thebest constants A and B
appearing
in theinequalities.
The basic facts about q-concave and p-convex lattices may be found in[9], [13]
and[12].
For
2 s
oo and E agiven
space we take the s-cotype constantof E, 03B1S(E),
to be the smallest a > 0 such thatfor any x1,
x2 , ... , xn ~ E. Here rl ,
r2"’" rn,... are the Rademacher functions on[0, 1].
It is obvious that03B1s(~Ns)
=1, 2 s
00.The Banach-Mazur distance between
isomorphic spaces E
and F isLet X be a fixed space
and 03BB
1. For E c X a finite dimensionalsubspace
we definec03BB(E)
to be the maximum of the dimensions of those F ~ E for which(i) d ( F, ~dimF2) 2,
and(ii)
there is aprojection
of X onto F of norm at most À.In the
terminology
ofPelczynski
and Rosenthal[16]
X is calledlocally
03C0-Euclidean if there is a
constant 03BB
1 and a functionf
on the natural numbers such thatc03BB(E) n
wheneverdim E f(n).
Finally
for 1 p 00,p’
is theconjugate of p (1/p
+1/p’ = 1).
THEOREM 1: Let X be a space which is a
subspace 01 quotient 01 a
p-convexand q-concave Banach lattice
L, 1 p 2 q ~. There is a 03BB
1 sothat, for
E c X any n dimensionalsubspace
and s E[2, q],
Before
giving
theproof
wepoint
out some instances of the theorem.(a)
Thehypothesis
of the theoremimplies
that X iscotype q [ 13],
andso for some constant a > 0 and a =
min(2/p’, 2/q ),
whenever X ~ E is finite dimensional. In
particular X
islocally
qr-Euclidean. This result is also stated in
[8], though
no estimate forcx(E)
isgiven.
85
(b)
The lattice L =Lp (03BC)
isboth p-convex
and p-concave, 1 p 00, andconsequently (*)
holds with a =min(2/p’, 2/p ).
For2 p
00 thisis
well-known,
and follows from the results of[2]
and[14]. Taking E = ~np
and
using
the results of[2]
shows that this lower bound forc03BB(E)
is bestpossible
for L anL -space.
(c)
In case2 s q
andd(E, ~ns) n1/s-1/p’
and hence
( * )
is true with a =2/p’.
For E a2-isomorph
of.es , 2 s min( p’, q),
thisgives
a lower bound forcx(E) depending only
on theconvexity
of L. For Hilbertainsubspaces
ofLp(03BC)-spaces
1 p 2 thislower estimate cannot be
improved; by [2] ~np,
1p 2,
contains aHilbert
subspace
of dimension cl n, but nocomplemented
Hilbert sub- spaces of dimensiongxeater
thanc2n2/p’.
For L a p-convex lattice(1
p2)
with some non-trivialconcavity,
every n dimensional Hilbertsubspace
isc3n1/p-1/2-complemented [ 11 ].
Below X, L, p and q
have the samemeaning
as in the statement ofTheorem 1. The
proof
ispreceeded by
three shortlemmas,
the firstmentioned
by
Pisier in[18].
The lattice structure enters into the
proof only through
Lemma 1.LEMMA 1:
If
u: X ~ G isq’-integral
then u’ isp’-summing
andPROOF: It is
enough
to show that for u: L - Gq’-summing,
By Proposition
3.1 of[11] u’
maps the closed unit ball of G’ into an order bounded set andSince L’ is
p’-concave
withK’p(L’) = KP(L) [9],
the sameproposition gives
LEMMA 2:
If 2
s oc, H is an n dimensional Hilbert space and u: H - G any map, there is asubspace
A c H with dim Anl2
andPROOF: If the conclusion fails
inductively
choose m vectors x1, x2 , ... , x m e H tosatisfy
and
It is
clearly possible
to choosem = [n/2 + 1] n/2
such vectors. Butsince the
xi 1 s
are orthonormala contradiction.
For G a finite dimensional space
and ~ ~2
a Hilbertian norm onG, G2
denotes
G under ~ ~2.
LEMMA 3: Let E c X be any n dimensional
subspace.
There is a Hilbertiannorm Il 112
on E and an operator v :X ~ E2
suchthat, if
u :E2 ~ X is
theformai inclusion,
then vu =1 E
and03C0q(u)
=i’q(v) = n1/2.
PROOF:
By
Theorem 1.1 of[10]
there is anisomorphism
w:~n2 ~ E
sothat
03C0q(w) = 1
andi’q(w-1) = n. Define Illb
on Eby ~x~2 =
n-1/2~w-1(x)~. Clearly 03C0q(u) = i’q(u-1) = n1/2.
For v take any map v :X ~
E2
withviE
=U-I
andi’q(v)
=i’q(u-1) (such
an extension existsby
the
defining
factorization ofq’-integral maps).
PROOF OF THEOREM 1: Given E c X of dimension n,
choose ~ ~2,
u and vas in Lemma 3. We claim there is a constant a > 0
(depending only
on q andL)
and asubspace B ~ E
withdim B n/4
suchthat,
if UI = u1 B2
and VI
is
v followedby
theorthogonal projection
ofE2
ontoB2,
thenand
87
Trivially, 03C0(2,q)(u) 03C0q(u).
For2 s q
theproof
of a result ofMaurey ([15], Proposition 74,
p.90) implies
where
c(q)
is Khintchin’s constant.By
Lemma 2 there is an A c E with dim A >n/2
andBy
Lemma 1and
thus, again by
Lemma2,
there is a B c E withdim B > (dim A)/2 n/4
andProperties (1), (2)
and(3)
followimmediately
from thecorresponding properties
of u and v(and
Lemma1).
The remainder of the
proof
now followsusing
the results and tech-niques
of[2].
LetS c B2 be the
unitsphere Il 112 =
1 and dm be thenormalized,
rotational invariant measure on S. Recall that theLevy
meanof a continuous real valued function
f
on S is the numberMf
such thatLet M be the
Levy
mean ofx ~ ~u1(x)~ = ~x~
on S andM#
be theLevy
mean of
x ~ ~03BD’1(x)~
on S(of
courseB’2 = B2 naturally). Equality (1) implies
that for x ES,
and
consequently
We now claim that there is a constant b >
0, depending only
on p, q andL,
such thatTo prove the first let
a(q)
be the constantsatisfying
a(q)
is theq-summing
norm of theidentity on B2
andn/4
dimB,
soa(q) C5n’ /2
for some constant c5depending only
on q(cf. [4]). By
Pietsch’s
integral representation
theorem[17]
there is aprobability
mea-sure jn on S with
Thus
the last
by (2).
Theinequality M# b
followssimilarly
from(3).
By
Theorem 2.6 of[2] (and
the remarksfollowing)
there is an absoluteconstant c > 0 and an F ~ E with
~ ~2-equivalent
toM ~ ~2
onF, (8)
the norm
x ~~03BD’1(x)~2-equivalent
toM# ~ ~2
onF,
and(9)
dim F cn min{~u1~-1M,~03BD1~-1M#}2. (10)
By (6)
and(7)
M andM#
are at leastb-1
so,using (4)
and(5),
dim
F c6 min{03B1s(E)-2n2/s, n2/p’}.
Finally,
let w:B2 ~ F2
be theorthogonal projection. Since ~03BD’1(x)|
2b~x~2
for xE F,
theprojection
wv jhas
norm at most 2b as anoperator
from X intoF2 . But ~y~2b~y~2
fory ~ F, so ~wu1~4b2
as anoperator from X into F. This concludes the
proof.
DA review of the
proof
of Theorem 1 showsthat,
once the Hilbert normIl I 112
and theoperators
u, v have beenchosen,
thekey inequalities
are theupper estimates for M and
M# given
in terms of03C0q(u) and 03C0p’(v’).
Suchestimates are available in several other instances.
Given 1 p 00 a
space X contains ~np’s uniformly
if there is asequence
(En)n
1 of finite dimensionalsubspaces
of X withsupnd(En,
~np)
00. If in addition there areprojections
un : X ~En
withsUPnllunl1
00, then X contains
uniformly complemented ~np’s.
89
THEOREM 2: Let L be a Banach lattice not
containing ~n~’s uniformly,
andlet X c L. Then either
(a)
X containsuniformly complemented ~n1 s,
or
(b)
X islocally 03C0-Euclidean.
In the second case there are
positive
constants À and a such thatfor all finite dimensional E c X.
THEOREM 3: There is an absolute constant c > 0 with the
following property.
If
E is an n dimensional space with a monotonesymmetric basis,
there is anm dimensional F c E and a
projection
w: E - F withand
Again
the firstpart
of Theorem 2 is stated withoutproof
in[8].
Theconclusion of Theorem 3 is of interest
only
in cased(E, ~n2)-2n
issubstantially larger
than(log n)2; by
John’s Theorem[7] d( E, ~2n) nl/2
for every n dimensional space, and every m dimensional F c E is at least
M1/2-complemented (of [3]).
PROOF OF THEOREM 2: Assume that X’ doesn’t contain
~n~’s uniformly.
The
arguments
of Pisier in[ 18]
show that there is a constant c > 0 and indices pand q,
1p 2 q
oo, so that03C0p’(v’) ci’q(v)
for everyq’-integral
map on X. Once this is established as a substitute for Lemma1,
theproof
canproceed exactly
as before.PROOF OF THEOREM 3: Let
(ei)in
be a monotonesymmetric
basis forE,
set
and write u :
E2 ~ E,
v: E ~E2
for the formal identities.Every
map g ofthe form
g( el )
=03B5i e03C0(i), with |03B5i|
= 1 for each i and qr apermutation ouf (1, 2, ... , n},
is anisometry
of both E andE2 ;
further theonly
mapsE2 ~ E
which commute with all such g are scalar
multiples
of u.By
anaveraging argument (cf. [5],
Lemma5.2) 03B1(u)03B1*(v)=n
for every Banach idealnorm a. Thus we may assume,
normalizing Il 112
if necessary, thatLet a and b be the best constants
satisfying
Another
averaging argument
showsM and
M#
are defined as in theproof
of Theorem 1.By
thatproof,
forany q
2,
where
03C0q(~2n)
denotes theq-summing
norm of theidentity
on~n2. Using
the
expression given
in[4]
for03C0q(~n2)
andStirling’s
formula there is anabsolute constant a > 0 such that
03C0q(~n2)-1 a(q/n)1/2
for all q > 2.Any
map w into an n dimensional space satisfies03C0q(w)n1/qi~(w)
(cf. [11], Corollary 1.7). Consequently, combining inequalities yields
and
similarly
the last
inequality by [6],
Lemma3.3,
since E has a monotone uncondi-91
tional basis. Now
taking q
=log
n,for some absolute constant c1.
Trivially, M a-1 and M# b-1. Using
the method of
Figuel-Lindenstrauss-Milman
as in theproof
of Theorem1
produces
an m dimensionalF c E,
which is2-isomorphic
to~m2,
c2log
n
complemented
in E and withThere are a number of natural
questions
aboutcomplemented
Hilbertsubspaces.
Let X be a space with some Rademachertype.
Is there aconstant 03BB 1, depending on X,
withfor all n dimensional E c X? For X a p-convex and q-concave lattice it is known
[ 11 ] that d ( E, ~n2) n1/p-q/q
for E c Xhaving
dimension n. Forsuch lattices Theorem 1
gives
anapparently stronger result, although
inthis case it is
likely
that the correct distance estimate isThe lattice structure enters into the
proofs
of our resultsonly through
the
inequality
for
operators
on X. For X the Schattenp-trace
class ofoperators on ~2,
Pisier
[ 18]
has shown that(#)
fails for every non-trivialpair
1 r2 s
00. We know of no non-trivial lower estimates for
cx(E)
ifE c Cp,
1 p
2, although sharp
upper estimates ford(E, ~n2)
are available[ 19].
Finally,
we know of nospace X
on which(#)
is true which is not asubspace
of aquotient
of a Banach latticehaving
some Rademachertype.
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(Oblatum 14-IV-1980)
Texas A&M University Department of Mathematics
College Station, TX 77843-3368 U.S.A.