A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
J ÖRG B RÜDERN A LBERTO P ERELLI
Exponential sums and additive problems involving square-free numbers
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 28, n
o4 (1999), p. 591-613
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Exponential Sums and Additive Problems Involving Square-free Numbers
JÖRG BRÜDERN -
ALBERTO PERELLIAbstract. Let r v (N) denote the number of
representations
of theinteger
N as a sumof v
square-free
numbers. We obtain unconditional and conditional bounds for the error term in theasymptotic
formula for rv (N), when v > 3. The conditional bounds areessentially
bestpossible
for v > 4. The unconditional bounds are, for v > 3,essentially
bestpossible
with respect to the presentknowledge
onthe distribution of the zeros of the Riemann zeta function. Proofs are based on
the circle method. The main
ingredients
are a newpointwise
estimate for theexponential
sum S(a) oversquare-free
numbers and a recent bound (see [3]) for theL2-norm
of S(a) restricted to the minor arcs.Mathematics
Subject
Classification (1991) : 11P55.(1999), pp.
1. - Introduction
Let
r,-(N)
denote the number ofrepresentations
of the natural number N asthe sum of v
square-free
numbers. In a series of papersEvelyn
and Linfoot[5]
established
asymptotic
formulae forrv(N).
When v >2, they
obtainedwhere
6v(N)
is thesingular
series definedby
and where
Pervenuto alla Redazione 1’ 11
gennaio
1999.Note that
8 (v)
isstrictly increasing
with8 (v) -* 4
as v -~ 00. When v >3,
these results were obtained
by
theHardy-Littlewood
circlemethod,
and havebeen refined
by Mirsky [12]
toWhen v =
2, Evelyn
and Linfoot used anelementary argument
which was muchsimplified by
Estermann[4].
Morerecently
Heath-Brown[9]
consideredthe related
problem
ofcounting square-free twins;
his method carries over to theproblem
under consideration andyields
thevalidity
of(1)
with9 (2) = --4-
In this paper we
analyse
the error term in(1)
moreprecisely,
and link it with the zeros of Dirichlet L-functions. The first theoremimproves
on the resultsof
Evelyn
and Linfoot and ofMirsky
forall v >
3.THEOREM 1.
Let v >
3. ThenA further
improvement
of theexponent
in the error term belowv - 2
wouldimply
a zero-freestrip
of the Riemann zeta function to the left ofRe(s)
= 1.This is a consequence of the
following
theorem.THEOREM 2. Let 0 denote the supremum
of
the realparts of
the zerosof
theRiemann
zeta function. Then, for
any v > 2 and any 6 >0,
We
have # a 2 ,
withequality
should the Riemannhypothesis
hold. Onemay
conjecture
that the true order ofmagnitude
of the error term in( 1 )
isv 7
roughly
of sizeN"- 4 .
If one isprepared
to assume thegeneralised
Riemannhypothesis (G R H )
for all DirichletL-functions,
it ispossible
to confirmthis,
at least
when v a
4.THEOREM 3.
Suppose
that G R H holds.Then, 4,
Moreover,
Thus,
when v =3,
we miss theoptimal exponent
of N in the error term Ourproofs
of Theorems 1 and 3 utilize the circlemethod,
and thereforefollow the
path
ofEvelyn
and Linfoot in the first fewsteps.
A new tool for ourpurposes has become available
only
veryrecently. Granville, Vaughan, Wooley
and the authors
[3]
haveinvestigated
the mean square of theexponential
sumrestricted to minor arcs. For a
precise
statement of the result which is relevant to ushere,
let 1 :siN
and denoteby
the union of all intervalswith 1 q :S
Q
and(a , q )
=1,
and letm ( Q )
-1 +
6~’~] B~(6). Then,
Theorem 1.3 of[3]
asserts thatNote that this is
stronger
than"square
root cancellation" forAs was
explained
in[3],
one can deduce from(4),
via the circlemethod,
that(1)
holds with
9 (2)
=5 .
This is weaker than theelementary
result ofEvelyn
andLinfoot for v =
2,
but for v > 3 one mayhope
toimprove
their workby starting
from theorthogonality
relationusing (4)
combined with areasonably strong pointwise
estimate forS(a).
Suchis
provided
in the next theorem.THEOREM 4. Let
S(a)
andtn(Q)
be as above.Then, for
1Q N 3/7
onehas
A similar result occurs inter alia in
Baker,
Brüdem and Harman[2],
butis
subject
to the morestringent condition Q N 1/3 .
We shall
begin
withproving
Theorem 4 in Section 2. Theargument
is basedon classical
Weyl
sumtechniques,
with an extra idea contained in Lemma 1 below. Anapplication
of the circle methodyields
Theorem1,
with(4)
andTheorem 4 as the
key ingredients.
This will be described in Section 3.The next two sections are
subject
toG R H,
and are devoted to theproof
ofTheorem 3. The
improved
error terms come from enhanced information about the distribution ofsquare-free
numbers in arithmeticprogressions
if G R H istrue. At the heart of
(4),
a version of theBarban-Davenport-Halberstam
theoremfor
square-free
numbers due to Warlimont[14]
is at work.Subject
to G R Hone may
expect
astronger
version of thelatter,
but asexperts
in this field willreadily recognize,
there are familiar but unconventionalproblems
with routineapproaches
toinvestigate
the distribution ofsquare-free
numbers in arithmeticprogressions.
We are ableonly
to establish theexpected
bound for a certainvariance
(see
Section 4below)
if thesquare-free numbers
are counted withsuitable
weights.
Theweight e-"IN
fits well with additiveproblems.
Thus weare forced to formulate the circle method
machinery
in terms of the abelian transformof the
previously
definedexponential
sum5’(of).
We can then write in termsof
absolutely convergent
Mellin transforms of Dirichlet L-functions(see (22)- (24)),
and usearguments inspired by
the work ofHardy
and Littlewood[7]
and Linnik
[ 11 ] (see
alsoLanguasco
and Perelli[10])
to establish a conditionalimprovement
of(4).
In Section5,
we use this to derive Theorem 4.Finally,
inSection
6,
we prove Theorem 2by
asimple
modification of a classical result ofMontgomery
andVaughan [13] ] concerning
the error term in theasymptotic
formula for
representations by
sums ofprimes.
With little extra effort our results can be extended to sums of k-free num-
bers ;
in the interest ofbrevity
we have refrained fromdoing
so.Some mention should be made of the work of Friedlander and Goldston
[6]
who considered the
analogous problem
withprimes
instead ofsquare-free
num-v i v 2
bers, subject
to G R H.Here,
the S2-result has an inplace
ofN’’- 4 ,
andcuriously, they
also obtained amatching
upper boundfor v >
4summands,
but for v = 3 their result falls somewhat short of theexpected
one.Our notational conventions are standard or else
explained
at theappropriate
stage
of theargument.
Statementsinvolving
an E are true for any 8 > 0. Note that this allows us to conclude from X «Z8,
Y « Z’ that one has X Y «Z’,
forexample.
2. -
Exponential
sums oversquare-free
numbersWe prepare for the
proof
of Theorem 4 with asimple
lemma.LEMMA 1. Let a E
R,
and let a EZ,q
Eq-l.
For D >
Then
PROOF. We may assume that since the bound is trivial in the
opposite
case. Let K =
[ 2Z ] .
The functionis
non-negative,
ofperiod
1 and satisfies~: ~
z. Hencewhere
By
Lemma 1 of Harman[8],
and the Lemma follows
immediately.
To establish Theorem
4,
we rewrite(3)
in the formWe evaluate the inner
geometric
sum, and thensplit
the outer summation intoranges D 2D. This routine
procedure yields
some D =D(a)
with1
D
such thatsay. The trivial bound
T(a, D) ND-1
issatisfactory
when D >Q,
so wemay assume that
D Q.
Three different
arguments
are available to estimateT (a, D)
moreprecisely.
We write X =
By
Dirichlet’stheorem,
there arecoprime integers
a, qwith 1
X
and we note thatFirst suppose that Then
by (7),
and we can writewhere
This shows that that
We
again
make use of to inferwhich is more than
required.
We may now suppose that
8 D2
>Q. Now, by
Lemma 3.2 of Baker[I],
If
N Q-1
we conclude thatD) «
which isagain accept-
able.It remains to discuss the case where
In the notation introduced in Lemma
1, by
that Lemma and(7),
By (8),
this reduces toT (a, D)
«N 112+E +N’+ED -3/2 .
This will beacceptable
if
D3/2 > Q.
We may therefore suppose that DQ2tJ.
Butthen, by (8), D2 Q4/3
which isimpossible
forQ N3/~,
and theproof
ofTheorem 4 is
complete.
3. - The addition of
square-free
numbersThis section is devoted to the
proof
of Theorem 1. Webegin
with thecase v = 3. The
argument departs
from theintegral (5).
Let m =m(N/)
and9R =
Then, by
Theorem 4 and(4),
and
(5) yields
We prepare for the treatment of the
major
arcs 9Rby introducing
a suitableapproximation
toS(a).
LetG (q )
be themultiplicative
function defined onprime
powers
by
Furthermore,
letFor and write
This defines
S*(a)
on~( 2 N 1~2),
and for a in this set, we writeWe recall a
special
case of Lemma 3.2 of[3]
which asserts that for 1Q
one has
It is now
straightforward
toreplace Sea) by S*(a)
in(9).
Note that(13) gives
We
multiply by e(-aN)
andintegrate
over 9Jl to infer thatwhere
Bounds for
E2
andE3
arereadily
deduced from(14)
and Theorem 4. We writeS)1(Q) = ~(26)~(6). Then,
for 1 sQ N 1~3,
we deduce from Theorem 4 that-
and
(14)
nowyields
From
(10),
we haveG (q ) « q8-1,
and from(11)
we see that +It follows at once that for 1
Q N 1 ~3
one hasand
(14)
shows thatOn
summing (15)
and(17)
overQ
=2-> N 1 ~3 with j
E N we deduce thatFor the estimation of
EI
we invoke Lemma 4.2 of[3]
which shows thatThus, by (16),
we haveHence, by summing
overQ
=2-~ N 1 ~3
asbefore,
we find thatE
1 «N3~2+£ .
We may now conclude that indeed
(9)
holds withSea) replaced by S* (a ),
andconsequently,
where
We now observe that
by elementary counting,
and that for any.
We use the latter with X
= q -1 N-2~3
and then obtainwhere
As we have observed
earlier,
wehave IG(q)1 I q £-1. Moreover,
one has the familiar estimate(q, N),
and thereforeBy
a similarargument,
onereadily
confirms thatCollecting together, (18) finally gives
Since
G(q)
andcq (N)
aremultiplicative
functionsof q,
we may rewrite the infinite sum as an Eulerproduct,
and one then finds thatTheorem 1 now
follows,
at least when v = 3. Forlarger
values of v one mayproceed
asabove, estimating
the extragenerating
functionstrivially.
Detailsmay be omitted.
4. - A conditional mean square estimate
In this section we
provide improved
versions of(4)
and(14) subject
toG R H. It will be necessary to work with
rapidly convergent
Mellintransforms,
and therefore we express our results in terms of the abelian transformS(a)
defined in
(6).
Before we can formulate our firstlemma,
which is still un-conditional,
we need to introduce some notation. For any Dirichlet character modulo r, let =X (b)e(b/r)
denote its Gauss sum, and letL(s, X)
be the Dirichlet L-function. Whenever
rlq,
writeBy comparing
Eulerproducts,
onereadily
confirms that forRe(s)
> 1 one hasLEMMA 2. For any
coprime
natural numbers a, q and anyf3
one haswhere.
PROOF. This is a
straightforward exercise,
so we shall be brief. In(6),
wesort terms
according
to the value of(q, n)
and take theresulting
formulaas the
starting point.
Nowwrite q
=rd, n
= md and note thatJL(md) =
0whenever
(m, d)
> 1. This shows thatThe condition
(m, r)
=(m, d)
= 1 isequivalent
with(m, q)
= 1. We sort thesum over m
according
to residue classes m --_b(mod r)
with 1 b r and(b, r )
=1,
and thenpick
up the congruence conditionby
characters modulo r.This leads to
But
by
iand the Mellin transform of e-’ is
r(s). Hence,
and the lemma follows
immediately.
DWe now wish to shift the line of
integration
in Lemma 2 to the left. Fromnow on, we assume that G R H is true. Let Xo denote the
principal
character( mod r ) .
Thenand
L(s, Xo)
has no zeros inRe(s)
>4. Since ~ (s)
isholomorphic
on Cexcept
for asimple pole
of residue 1 at s =1,
it follows thatfor X
= Xo theintegrand
in Lemma 2 isholomorphic
inRe(s) > 4 except
for asimple pole
at s =
1,
with residuewhere
When
X =1=
Xo, thenL (s, X)
isentire,
andL (2s, X2) again
has no zeros inRe(s)
>1. Thus,
in this case, theintegrand
in Lemma 2 isholomorphic
forRe(s) > 4.
*Fix a real number a
with 4
or2. By Stirling’s
formula and standardupper bounds for the
L-functions,
it isreadily confirmed that
the line of inte-gration
in Lemma 2 may be moved toRe (s )
= a. Since-c (Xo)
= =JL(r) by
a well-known evaluation ofRamanujan’s
sum, thisyields
where
with
The first term on the
right
of(22)
can be muchsimplified. Indeed, recalling (21 )
and
(10),
onereadily
verifies thatfor q
aprime
power, one hasbut
then, by multiplicativity,
thisidentity
holds for all q.Recalling
the definitionof
z(d, P),
we may rewrite(22)
asand it should become
apparent that 8(q, a, fJ)
is the properanalogue
of thefunction
A(a)
in Section 3 and[3].
Thefollowing
lemmagives
a mean square bound whichimproves
on(14).
PROOF.
a, -,8) ~
a,fJ) it
suffices to estimate theintegral
over
[0, 8].
We cover this intervalby [0, 2N-1] ]
andO (log N)
intervals of thetype [q, 2q]
with2A~’~ ~ ~
8. It follows that for somesuch q
we must havewhere
and
Ko
is definedlikewise,
but with theintegration
extended over[0, 2N-1].
We now
apply Cauchy’s inequality
to(23).
Anelementary
estimate for the divisor function then shows thatwhere in accordance with earlier
conventions,
wewrote q
= rd. We sumover a,
expand
the square, use theorthogonality
of characters and recall that for all X mod r. Thisyields
We estimate
Ko
first. In the interest ofbrevity,
writewith 4
a2
and t ER,
standard bounds for L-seriesprovide
theinequalities
subject
to GRH. We alsohave
= d -~and Dq (s, x)1 «q8 by elementary
estimates. Combined with
Stirling’s
formula forr (s),
theseinequalities imply
that
Moreover,
for zo now deduce thatwe have From
(24)
weWe may take cr
= 4
+ E. From(28)
it follows thatj i 2
Integrating
over[0,2N -1] ] yields Ko «N8-2q’2
which isacceptable.
More care is
required
to estimateK (r¡). Although
notstrictly
necessaryhere,
webegin by smoothing
the mean square; this process faciliates referenceto
Languasco
and Perelli[10]
below. The obviousinequality
is our
starting point.
Now open theright
hand side and recall(24), (29)
andthe definition of zo to infer that
where
An upper bound for
w)
isrequired.
We writewith 4
a2
as before. Note thatSince arctan y
= 2 - arctan Y
holds for y >0,
we now havewhere
If we now write
then
The
integral
J has been studiedby Languasco
and Perelli[10],
butonly
foror
= 2
and(in
theirset-up) t
>0, t’
> 0.However,
aninspection
of theirargument ([10],
pp.312-314)
shows that the estimates remain valid in our moregeneral
situation. Theinequality (14)
of[10]
stillholds, provided
thatG
1 nowdenotes a
primitive
of aprimitive
offl (,8).
If one then follows thepattern
of the estimation ofG
i in[10],
onereadily
confirms that the boundcorresponding
to
(20)
of[10]
now readsOne then finds that for some suitable c >
0,
one hasFrom
this, (32), (31)
and(30),
we may conclude thatwhere
A
straightforward
estimation shows that U «Nil (for example,
transform theintegral
via u = t+ t’, v
= t -t’). By (33), (27)
and(28)
itfollows .that
With cr
= 4 -~ ~
asbefore,
the Lemma now follows from(26).
05. - The addition of
square-free
numbers: conditional resultsWe return to the main theme of the
present
paper, and establish the con-ditional
asymptotic
formulae in Theorem 3.By orthogonality
and(6),
we haveWe shall
apply
the circle method to(34). Although
there is still a dissectioninto minor and
major
arcs, there is a certain flavour of amajor
arc treatmentthroughout
the interval[0, 1].
The intervals
{a : Iqa - al :S N-1~2}
with 1 aq
and(a, q)
= 1 arepairwise disjoint.
On the otherhand,
for any real number a, Dirichlet’s theoremyields coprime
numbersb,
r with 1 r-IN
N -1 ~2 . Therefore,
there are numbersK (q , a ) , K’ (q , a )
wherewith
such that the intervals
together
with the define adisjoint.
cover of we now
write, recalling (25),
Note that we may
regard S* (a ) and Sea)
as functions ofperiod
1.. defined for all real numbers.Recall the definition of
9R(Q), S)1(Q)
andm( Q)
from Section 3. It isinteresting
to compare the conclusions of the next Lemma with(14).
LEMMA 4. Let 1
4~. Then, subject to G R H,
and
PROOF. For the first
estimate,
use Lemma 3 with 3 =Q/(qN)
and sumQ.
For the secondestimate, proceed
likewise with 6 = andsum
over q
0LEMMA 5. Let
m(Q) be defined
as in Theorem 4.Then, for Q N3/7,
PROOF. This follows from Theorem 4
by partial
summation.For future
reference,
we record here a usefulcorollary. By (35)
and(10),
we have when a
Hence,
forwe have
From
(36)
and Lemma5,
we deduce that for one hasWe now embark on the main
argument.
Let v > 3 be a fixed natural number.By (36),
we haveBy (34),
we conclude thatwhere
Write m =
m(N3~~).
From Lemma 4 and(37)
we haveWhen 1 s
Q s N3/7,
we also deduce from Lemma 4 and(37)
thatand since 9R =
9R(N3/7)
is coveredby O (log N)
setsS)1(Q)
withN3/7,
the bounds
(39)
and(40) yield
We prepare for the estimation of
E4
with thefollowing
upper bound.LEMMA 6.
Let k >
2 and 12 N 1 /2.
ThenIf we take this for
granted,
then we may take k = 2v -2,
andapply Cauchy-Schwarz’s inequality
and Lemma 4 to deduce thatLikewise,
for one finds thatThe
interval[ N -1 ~2 , 1 -~ N-I/2]
may be covered andO (log N )
sets
S)1(Q)
with 1Q 4 ~. Hence, for v > 3,
we may conclude thatObserve that
by (41)
and(42),
we have suitable estimates for the errors in(38).
PROOF oF LEMMA 6.
By (35),
theintegral
inquestion
does not exceedThe first
integral
here is whereas the second is follows thatBy (10),
we haveG (q )
= 0unless q
is cube-free. For any cube-free q, we maywrite q =
withsquare-free,
and(10) yields IG(q)1
«q8(qlq2)-2.
For k > 2,
we infer thatSimilary,
onereadily
confirms thatThe conclusion of Lemma 6 is immediate. 0
1
It remains to evaluate the main term in
(38). By
Lemma 6with Q
=(41)
and(42)
we havewhere
By (35),
we may writeThe
identity
may be verified
by
the calculus of residues. With z =27r ip,
weget
the power series
for e~
shows that the functionhas a
pole
oforder v,
with 1 at z =1,
and isholomorphic
for all other z. We now
integrate
this function clockwise over therectangle
with corners
-3:::.i T, (1 ~ i ) T . Then,
as r 2013~ oo, theintegrals
over the horizontalpaths
as well as over theportion
ofRe(z)
= T tend to0, by straightforward
estimates. The
integral
over the vertical line from -iT toiT, however,
tendsto the
integral
on theright
hand side of(48),
and(47)
follows from the residuetheorem.
For
X > N-1
we haveTherefore, by (43), (46)
and(47),
Now observe that
by (10)
andmultiplicativity,
the sum on the left
being absolutely convergent
for v > 2by (44).
Anotherapplication
of(44) yields
and Theorem 3 follows from
(45).
Note that we miss theoptimal
result forv = 3
only
in the estimation ofE5.
If it werepossible
in Theorem 4 to extend the range forQ
toQ s
then onewould,
in Theorem3,
obtain the sameprecision
for v = 3 as isprovided
for v > 4.6. - Proof of Theorem 2 .
Our
proof
of Theorem 2closely
follows a related result ofMontgomery
and
Vaughan [13],
and we are therefore rathersketchy.
We consider the power seriesfor z
= owith 2
o 1when g -
1. We writethroughout
This
problem
isstrongly
linked with the distribution of the error termsince, by partial summation,
one hasIt is useful now to record here the
elementary
boundvalid
whenever ~
> -1(see
Lemma 2 of[13]). Elementary
numbertheory
shows that
E(x) x1/2,
andEvelyn
and Linfoot[5] ]
obtainedE(x)
=if the Riemann
hypothesis holds;
if the Riemannhypothesis
isfalse,
one has1 ,
E(x)
= From(52)
and(53)
we may conclude as follows.LEMMA 7. In the notation introduced
above,
we have 1Moreover,
as ~O ---* 1from
theleft,
we haveRiemann
hypothesis
is true, one hasBy
theprevious lemma,
we have for any naturalnumber v >
2 thatwhich
by
anotherappeal
to the lemmayields
Our
preparations
are nowcomplete. By (53)
we see that Theorem 2 will followprovided
we are able to establish thatand this we shall now deduce from
(54).
Webegin by observing
that whenever(a, q)
=1,
one haswhence
for q >
2 we infer thatWhen q
=1, however,
the sum on the left hand side of(56) equals [x]. By (49)
it follows that
and
for v >
2 the sum in the error termcertainly
converges,by (10).
Thisyields
for v >
2.Now,
sinceis
readily
confirmedby elementary considerations,
we deduce from(57) by partial
summation thatand
(53) yields
The
required (55)
is now immediate from(54)
and(58).
Theproof
of Theorem 2 is nowcomplete.
If the Riemannhypothesis
is true, then the aboveargument
shows that #= i, 8
= 0 in Theorem 2 arepermissible.
REFERENCES
[1] R. C. BAKER,
"Diophantine Inequalities",
Oxford, Clarendon Press, 1986.[2] R. C. BAKER - J. BRÜDERN - G. HARMAN, Simultaneous
diophantine
approximation withsquare-free
numbers, Acta Arith. 63 (1993), 52-60.[3] J. BRÜDERN - A. GRANVILLE - A. PERELLI - R. C. VAUGHAN - T. D. WOOLEY, On the
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Stuttgart
D-70550
Stuttgart, Germany
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