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(1)

A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE

F LORENT B ERTHELIN F RANÇOIS B OUCHUT

Solution with finite energy to a BGK system relaxing to isentropic gas dynamics

Annales de la faculté des sciences de Toulouse 6

e

série, tome 9, n

o

4 (2000), p. 605-630

<http://www.numdam.org/item?id=AFST_2000_6_9_4_605_0>

© Université Paul Sabatier, 2000, tous droits réservés.

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(2)

- 605 -

Solution with finite energy to

a

BGK system relaxing to isentropic gas dynamics(*)

FLORENT

BERTHELIN(1)

AND

FRANÇOIS BOUCHUT(2)

e-mail:Francois.Bouchut@ens.fr

Annales de la Faculté des Sciences de Toulouse Vol. IX, 4, 2000

pp. 605-630

RESUME. - On considere une equation BGK cinetique vectorielle don- nant la dynamique des gaz isentropique dans la limite de relaxation.

Nous montrons l’existence d’une solution faible satisfaisant une inégalité d’entropie cinétique, pour toute donnée initiale d’énergie finie.

ABSTRACT. - We consider a vector kinetic BGK equation leading to isentropic gas dynamics in the relaxation limit. We prove the existence of

a weak solution satisfying a kinetic entropy inequality for any initial data with finite energy.

TABLE OF CONTENTS

1. Introduction and main results 606

2. Properties of the kinetic entropy 609

3. Stability 614

4. Existence of a solution 617

5. Entropy equation 622

5.1. Approximation of H 622

5.2. Sketch of the proof 624

5.3. Linear terms 625

5.4. Nonlinear terms 626

5.5. Proof of Theorem 1.3 628

( * ) Reçu le 4 juillet 2000, accepté le 4 decembre 2000

~ Université d’Orléans et CNRS, UMR 6628, Departement de Mathématiques,

B.P. 6759, 45067 Orléans cedex 2, France.

e-mail: florent.berthelin@labomath.univ-orleans.fr

(2) Departement de Mathematiques et Applications,

École

Normale Superieure et CNRS,

UMR 8553, 45, rue d’Ulm, 75230 Paris cedex 05, France.

(3)

1. Introduction and main results

Relaxation models such as

proposed

in

[6]

have

proved

their

efhciency

in

building

numerical methods for conservation laws that are very easy to code and have nice

properties.

General

strategies

have been

proposed

in

[9], [13], [1], [3]

to build BGK

approaches

for

systems

of conservation laws.

However, analysis

of such models has

mainly

be achieved until now

only

when the

relaxed

equation

is scalar

(see [14]).

Here we consider a BGK model for the

one-dimensional

system

of

isentropic

gas

dynamics

with

0, u(t, x)

E R and K >

0,

1 ~y 3. The kinetic model has been introduced in

[3]

and can be written

where

f =

and

The kinetic

equilibrium x

in

(1.8)

has been introduced in

[7]

as a

generating

function for

entropies,

and has also been used in the

stability analysis

of

[10].

This function is also involved in

[12]

for the so called kinetic

formulation,

which is different from the BGK

equation

considered here. Previous results

(4)

for scalar

equations

can be found in

[4], 11~ , ~ [17] (see

also

[5]).

The first

existence result for a BGK

equation

was

given

in

[15] (see

also

[16]).

The main result of this paper is the existence of a

global

solution to the

systein (1.2)

with initial data

satisfying

energy bounds. We recall that the energy for

(1.1)

is

given by

and is a mathematical

entropy

for

(1.1).

The

corresponding

kinetic

entropy

for

(1.2)

is

given,

for

f = ( f o, f 1 )

E

D, by

We have the

following

theorems.

THEOREM 1.1. Assume that

f °

E

L1(Rx

x

Ri) satisfies

and

Then there exists a solution

f

to

(1.~)-(1.11) satisfying

(5)

THEOREM 1.2. -

If (1.17)

is not

satisfied,

we have the same result

except (1.,~4).

To obtain this

result,

we have to work with the

Tychonoff-Schauder

theorem instead of the usual Schauder theorem. The

only significant change

is for

compactness

and will be

explain

in the

corresponding

section.

THEOREM 1.3. - The solution

f

obtained in Theorems 1.1 or 1.2 sat-

isfies

with

as well as each

term from

the

decomposition ~.~7~. Besides,

z,

~),~) ~

x

R) for

any T >

0,

R >

0,

(6)

and the

integrand

in the

right-hand

sides

of (1 . 29)

and

(1. 30)

is

nonpositive.

Let us

finally

mention that we can

study

kinetic invariant domains and establish the relaxation limit to

( 1.1 ),

this is done in

~2~ .

.

2.

Properties

of the kinetic

entropy

We recall the value of the mornents of

M,

and

for every p > 0 and u E R. We have the

following

identities which link the energy and the kinetic

entropy. They

can be obtained

easily.

PROPOSITION 2 .1. - The energy r~

of (1.12)

and the kinetic

entropy

H

of (1.13) satisfy

- - w i

for

every p >

0,

u E R and

03BE

E R such that

Mo ( p,

u,

03BE)

> 0.

The function H has the

following properties.

PROPOSITION 2.2. -

i)

H is convex with

respect

to

f

in

D,

ii)

H is continuous with

respect

to

f

in

rA

=

{(f0, f l )

E D ;

|f1| A fo)

for any A > o.

(7)

Proof. - i) In ]0,

it is easy to

compute

the hessian and to check its

nonnegativity. Then,

on a

straight

line from the

origin,

is

linear,

thus H is convex in D.

ii)

The

only difficulty

is at 0. Let be a sequence in

TAB~0~

which

converges to 0. Then

thus H is continuous at 0 in

TA .

D

LEMMA 2.3

(COERCIVENESS).2014

There exist > 0 such that

for

any E

R,

we have

with

Proof.

- Let

f E D,

0. From

identity (1.13),

we deduce that

pi pl

We

have | fl Ipl

-

(|f1| f0 (f0) ,

and

using Young’s inequality,

fo

Taking

0 6- 1 such that c

and setting

~o =

(~/c~ - ~~ / (2

+

2/A)

and ~1 =

~/pl,

we

get

The

key

result of this section is the

following.

(8)

PROPOSITION 2.4

(KEY

CONVEXITY

INEQUALITY).

- For any

fED,

p > 0 and u,

~

E we have

Proof.

- Let us

consider $ :

D - R defined

by

which is

possible

because

M(/),

u,

ç)

E D. We have to prove

that ~ >

0.

- At

infinity,

by

Lemma

2.3, 03C8(f) ~0f0p0

+ +

af o

+

bfl

+ e with a,

b,

e E

R,

and since p0,p1 >

1, 03C8(f)

- oo when

fo + | f1|

tends to

infinity. Moreover, 03C8(f) a fo

+

bf1

+ e, and we deduce

that $

is lower bounded in D.

- At the

frontier {f0

=

0, f 1 ~ 0) , If / f o

- oo and

~~ ( f )

also.

- At

0,

If

Mo ( p,

u,

~ )

>

0,

then

by Proposition 2 . 2 ( i )

and

( 2 . 5 ) , (2.8)

holds true for

any

f E D,

thus lim

~ ( f ) >

0. On the

contrary,

if

Alo(p,

u,

ç)

=

0,

then

f-o

Since

H( f, ~) > 0,

this

yields

lim

0,

in any case.

f-o

- Inside D

It

only

remains to

study possible

minima

of $

in

int(D). But $

is smooth

there,

and if

fo

>

0,

and

If there is a minimum

of 1/J

in

int(D),

at this

point,

its

partial

derivatives must

vanish,

thus ’"

(9)

and

We deduce that

Mo(p,

u,

~ )

> 0 and

f

=

M(p,

u,

~).

The value

of $

at this

point

is 0.

Putting

all the

steps together,

we conclude

that ~ >

0 in D.

D

An

important

consequence of this result is the

entropy

minimization

principle.

PROPOSITION 2.5. - Consider

f

E such that

f E D

a.e. and

Then

Then

M ~ f ~ (~)

=

the

terms of the

right-hand

side are

integrable

with

respect

to

ç,

and

~ f ~ (~) d~

-

f (~) d~.

Thus the result is ob- tained

by integration in £.

0

We can also deduce that the

entropy dissipation

in

(1.29)

has a

sign.

PROPOSITION 2.6. - For any

f

E

D, p > 0, u, ~

E

R;

Proof.

- Since H is convex in

D,

continuous in the cones of

Proposition

2.2 and smooth in

int(D),

we have if

f ~

0

(10)

Letting f -

0 on the axis

f 1

==

0,

we obtain

using (1.27)

that

(2.10)

is

indeed true for any

f E D

with the convention

The case

f

= 0 can also be seen

directly by

the definition of H.

Finally, by adding (2.10)

to

(2.8),

we

get (2.9).

D

Let us end this

part by

estimates deduced from the boundedness of the kinetic

entropy.

PROPOSITION 2.7. - Consider

f

E

L1(Rx

x

Ri)

such that

f E D

a.e.,

and

Then

Proof.

We recall that po, pl are defined

by (2.7). First, using (1.13),

we have

Then,

since

fl

vanishes where

f o

=

0,

(11)

Thus,

from the

Cauchy-Schwarz inequality

we obtain

(2.12). Next,

with

(1.13) again,

and

(2.13)

follows.

Then,

we write

and obtain

(2.14). Finally, (2.15)

follows

obviously

from Lemma 2.3. 0 3.

Stability

In this

section,

we extend the

analysis

of

[15]

and prove the

stability

of an

approximate

solution. We shall denote

by ~)

-

~)

in

L1

x

R)

the convergence in x

R)

for any w C C and we shall use several similar conventions.

Let us first recall the classical characteristics formula for

(1.2).

LEMMA 3.1.2014 Let h C

L1 (~0, T[, Ll (1~

x and

f °

E

L1 (R

x

R)

. Then

there exists a

unique

solution

to the

problem

Furthermore,

(12)

We now prove a

stability

result for this

problem.

PROPOSITION 3 . 2. - Consider g, gn E x such that g, gn E D a.e.,

Set

and

If

pn - p and 03C1nun - pu in then there exists a sub-

n-o n-cxJ

sequence such that

F(gn)

n-o-

F(g)

in x

R)),

where

F(g)

is the solution to

(3. 1 )-(3.2)

with h =

A,I[g]

=

A4(p, u, £)

and

e x

R)

is

fixed. Moreover, if

pn - p in then

F(gn) -F(g)

in

C( [0, T] (R

x

R) ) .

Proof.

- At

first,

let us check that

F(g)

is well defined.

Using Proposi-

tion

2.5,

we have

Besides,

Estimate

(2.12) applied

to

Nf[g] gives

then that

Therefore,

we deduce that

M[g]

E

T ~,

x

II~)),

and we have the

same result for gn with uniform bounds.

(13)

We turn now to the

stability.

We can find a

subsequence

such that pn ~ p and pnun - pu a.e.

t, x.

Set E =

~(t, x)

E

~0, T~

x

R; p(t, x)

-

0~.

In

E~,

pn - p

and un

- u a.e.

t,

x, thus a.e.

(t, x)

E

E~, ~

E R. But

since

we deduce with

(2.17)

and

Cauchy-Schwarz inequality

that - 0 in

x

R) n {x

E

B~ ~ ) . Therefore,

after extraction of a

subsequence,

we

finally

obtain

Besides,

the estimates of

Proposition

2.7

applied

to

M~gn~ (t, ., .) give

that is

weakly compact

in

L 1 (~ 0,

x

R). Therefore,

we are

able to

apply

the Vitali

theorem,

which

gives

that

Now

and

Since the latter norm is

bounded,

we deduce

easily

that

F(gn) - F(g)

in

C(~0, T~,

x

II~)).

(14)

Finally,

if we assume moreover that in then

and since

M ~gn~ o > 0,

we deduce that

uniformly

in n. With

(2.17)

and

Cauchy-Schwarz inequality,

we

get

also

uniformly

in n, and we conclude that

~

-

M ~g~

in x

R) ,

and therefore

F(gn) -~ F(g)

in

C([O,T],Ll(

x

?)).

. D

4. Existence of a solution

This section is devoted to the

proof

of Theorem 1.1. Let

f °

satisfy

the

assumptions

of Theorem

1.1, namely

and set

We take

CH

and

CA

as

(15)

Define C to be the set of

all g

E x

R)) satisfying (Cl ) - (C4)

for a.e. t E

[0, T],

where

Let us also introduce

with

The initial data

f ° being fixed,

for any g E

C,

we denote

by F(g)

the

solution to

(3.1)-(3.2)

with h =

Proo f.

Let g E C. As in the

proof

of

Proposition 3.2, M ~g~

E

T ~,

L1 (R

x and we

get easily

that

M~g~

E C.

Next, according

to Lemma

3.1,

F(g) E

x

IL~)),

and in order to prove that

F(g)

E

C,

we need

to prove

(Cl) - (C5).

Condition

(C5)

is satisfied since E C.

Then,

for

z = 0; 1,

we have

Obviously, F(g)o

> 0.

Furthermore,

if

F(g)o(t,

x,

03BE)

= 0 then

( f °)°(x -

t03BE, 03BE)

- 0 and

fo e-s/~M[g]0(t

- s, x -

s03BE, 03BE)

ds =

0,

thus - s, x -

s03BE, 03BE)

= 0 a.e. s

t[.

But

f °

E D and E

D,

thus

( f ° ) 1 (x - t03BE, 03BE)

= 0

and

(t -

s, x -

s~, ~)

= 0 a.e. s

t~,

and therefore

F(g)1 (t,

x,

~)

= 0.

(16)

Hence

F ~g~

e D Vt E

~0, T ~

, a. e.

x, ~,

and

(C1)

is satisfied.

Next,

if t >

0,

we can write

and

using

Jensen’s

inequality

with the convex function

H,

we

get

and thus

and

(C2)

is satisfied.

Similarly, integrating (4.8)

with i = 0 with

respect

to

(x, ~) gives (C3).

It

only

remains now to prove

(C4).

We have

by (2.13)

Then,

since E

C,

relation

(C4) gives

(17)

hence

Therefore,

with

(4.5),

This ends the

proof

of the lemma. D

Since

C

c

C,

we are now able to define F :

C -~ C

and we shall use the Schauder theorem to prove Theorem 1.1.

LEMMA 4.2. - The sets C and

C

are convex and not

empty;

C is

compact for

the weak

topology of

x

R),

and C is closed in

C([o,T],

x

Proo f.

Since H is convex, it is obvious that C and

C

are convex.

Then,

the constant

f ° belongs

to

C,

and

by

Lemma

4.1, C.

Thus C and

C

are not

empty. Next,

from

Proposition 2.7, (C4), (2.17)

and Dunford-Pettis’

(18)

theorem,

C is

relatively weakly compact

in

T[ R

x

R) .

Let us prove

now that C is closed in weak

L1 (]0, T[ R R).

Since C is convex, it is

enough

to prove that C is closed in

strong

x

R).

Thus let

(gn)n

be a

sequence in C which converges

to g

in x

R) .

After extraction of

a

subsequence, gn (t, . )

-

g(t, .)

in x and a.e. for a.e. t

E J o, T[. First, (gn)O

0 thus

go >

0.

Then,

since

by (2.17) ~(gn)1)

we

get

for a fixed time t and any Borel set V

by

Fatou’s lemma and

Cauchy-

Schwarz

inequality

Taking V

=

~x, ~ ;

-

0~,

we obtain that vanishes a.e.

in

V,

thus

g(t, x, ~)

E D a.e.

Then,

we

apply

Fatou’s lemma

again,

and

get

Similar

applications

of Fatou’s lemma

finally give that g

E

T ~,

L1 (R

x

lI~)),

and g E C. The closedness of

C

in

C( ~0, T~, L1 (R

x is

treated in a similar way, and

(C5)

follows from the

compactness

of C. D LEMMA 4.3.- F is continuous in

C for

the

topology C((0,T),

x

Proof-

Let gn, g E

C with gn - g in C([O,T],Ll(JR

x

R)). Then,

with

the notations of

Proposition 3.2,

pn - p and pn un - pu in

C ( ~0, T ~

Thus

Proposition

3.2

gives

the existence of a

subsequence

such that

F (gn ) -~ F (g )

in x

II~) ) ,

which is

enough

to prove the con-

tinuity

of F. D

LEMMA 4.4. - is

relatively compact

in

C(~O, T~,

x

(19)

Proof. -

Let

f n

=

F(gn), gn

E

C

be a sequence in

F (C)

Since

C

C

C,

by

Lemma 4.2 there

exist g

E C and a

subsequence

such that gn - g in

weak

L1 (~0, T[

x

R) .

Then with the notations of

Proposition 3.2,

pn - p, pnun - pu in weak But

by (C5), 8tgn

+ + -

with

hn

E C.

By

the

compactness averaging

lemma of

[8]

and

by (2.13)-(2.14),

we deduce that

f~ gn (t,

x,

~) d~

is

compact

in

We conclude that pn - p and in

Proposition

3.2

gives

thus the existence of a

subsequence

such that

f n

=

F(gn)

-

F(g)

in

C([o, T~,

x

II~)).

. D

Proof of

Theorem l.1. . - We

apply

Schauder’s theorem in

C( ~0, T~, R))

to the

operator

F : C -

C. Using

all the results of this

section, C

is convex, closed and non

empty,

F is continuous

C

-

C

and is rel-

atively compact.

Thus we conclude the existence of a fixed

point f

E

C verifying F ( f ) = f.

This

gives

a solution in

[0, T]

for any T >

0,

and

by ex-

traction of a

diagonal subsequence,

we obtain a solution in

[0, oo[.

Relation

(1.21)

comes

clearly

from

(1.2)

because

~ f (t, x, ~)

E x

by Proposition 2.7,

and

(1.22)

is obtained

by integration

of

(4.8).

. D

Proof of

Theorem 1.2. - If the

assumption (1.17)

is not

satisfied,

we

have to use the

Tychonoff-Schauder

fixed

point

theorem in the

locally

con-

vex

topological

vector space x

1~~)).

Let us mention the

changes

that need to be

performed

to the results of Section 4.

First,

we have

to remove condition

(C4)

in the definitions of C and

C. Then,

in Lemma

4.2,

C is

compact

for the weak

topology

of x

R) ,

and

C

is

closed in x

R).

In Lemma

4.3,

F is continuous in

C

for the

topology

x

II~)),

and in Lemma

4.4, F(C)

is

relatively

compact

in x

R))

. D

5.

Entropy equation

In this section we prove that the

entropy H( f (t,

x,

~), ~)

satisfies a renor-

malized

equation,

as stated in Theorem 1.3. The

difhculty

is that H is not

smooth at the

origin,

and we have to build a monotone

approximation

of it

that is convex, smooth and that has slow

growth

at

infinity.

5.1. .

Approximation

of H

The most

singular

term in H in

(1.13)

is

obviously

(20)

We

begin by translating

the

singularity f o

= 0 to

f o

=

-~, by defining

for

~>0

which is convex and smooth in

D,

hence

In order to obtain a linear

growth

at

infinity,

we set

One can check that with this choice of c~ ,

We have

obviously ~s ( f )

.

LEMMA 5.1.2014

i)

The value

of

~s is

ii)

the

function

cp~ is convex in

D. nonnegative,

=

0.

iii)

we have

cps ( f ) ~ for f E D,

iv) if

0 b’ b then

( f ) for fED,

and

T

as

~~o.

v)

the

function

cps is

C1

in D and

cp~

is bounded in D.

Preuve.

i)

If

f

E

Dd , obviously cps ( f )

_ If

fED B Ds,

hence

(21)

If

0,

the supremum is reached at x = cs because cs

f 1 / ( f o

+

~),

and

if

0,

it is reached at -c~, and this

gives

the result.

ii)

The

convexity

is obvious from the

definition,

the

nonnegativity

also

since 0 E

D5 ,

and

cps (o)

is

computed by (5.6).

iii) If f e D5

then

~~ ( f =

and if

f

E

D B Ds,

then

~Ps(.f) _ -ca(.fo + s) + 2c~I.fl~ 2c~~.fl~.

.

Finally,

if

f E D

is

fixed,

for small

enough

b we have

f

E

D8, cps ( f )

-

.

v)

Formula

(5.6) gives obviously

two smooth functions. We have to check the

continuity

of the functions and their derivatives at the frontier where

( f 1 = ~(~-p~).

The

continuity

of 4’8 is

straightforward.

For the

derivatives,

we have

and we see that the two formula match

when |f1|

- +

03B4).

We

finally

notice that

~ cps ~ c~

+

2cj.

. D

5.2. Sketch of the

proof

In order to prove the

equation

on

H( f (t, x, ~), ~),

we

decompose

H as

and we are

going

to consider each term

successively.

A crucial

argument

is the

following

lemma.

LEMMA 5.2. - Assume that g E

C(~0, T~,

x

I~~)) verifies

(22)

Then

Proof-

Define

g(t, x, ~)

=

g(t,x

+

t~, ~).

Then

g

E

C(~0, T~,

x

R)), and g

verifies

g(o) - g(0)

E x

R),

=

h(t,

x +

t~, ~)

E

L1 (]0, T R

x

R) . Therefore,

and we deduce

(5.12)

and

(5.10). Then, (5.11)

comes from the

higher

mo-

ment lemma of

[15],

and

(5.13)

follows

by integration

of

(5.9). Finally,

inte-

grating (5.12)

with

respect

to

(x, ~),

we

get

for any t E

[0, T~

which is the

integral

form of

(5.14).

D

5.3. Linear terms

We are now able to treat the first two terms in

(5.8).

From now on,

f

denotes the solution obtained in Theorems 1.1 or 1.2. We recall that the estimates of

Proposition

2.7

apply

to

f (t, . )

and to

M ~ f ~ (t, . )

for any t > 0. Thus we can

apply

Lemma 5.2 to

03BE2 fo (t, x, 03BE)

and

03BEf1 (t,

x,

03BE),

and we

conclude that

and all the conclusions of Lemma 5.2 are valid.

(23)

5.4. Nonlinear terms

Let us first consider the last term in

(5.8), corresponding to (f)

=

We use the

approximation c~s ( f )

defined in Section 5.1. Since cps

is

Cl

and

globally Lipschitz continuous,

a vector

adaptation

of the classical

renormalization

property

allows to

multiply (1.2) by ~p~ ( f ),

which

yields

Since

cpa ( f )

E x

I~) ) ,

we can

apply

Lemma 5.2 to

cp~ ( f )

We

wish now to let ð - 0 in

(5.17).

We notice that ~ in

(5.1)

is smooth outside

the

origin,

and we define

~’ (o)

= 0

by

convention. Thus

LEMMA 5.3.- The terms

ay(f)

lie in x

1~8).

. The

right-hand

side

of (5.17)

is bounded in

x

R) uniformly

in

b.

and tends to in

x

R)

as b - 0.

Then,

=

-~(.~)

E x

-

1f0>02f21/f0

-

2V( f)

E x

R)). Next,

since

0 ~( f ), ~p~ ( f )

is bounded in x

independently

of ~.

Therefore, by (5.17)

and

by applying

the

identity (5.15)

to cp~

( f ),

we

obtain that

Then,

since yJ5 is convex in

D,

According

to

(5.20),

this function is bounded in

L1 (~0,

T x

R) indepen- dently

of S.

Observing

that with

(5.7), c~~ ( f )

- ~’

( f )

as b -

0, by applying

Fatou’s

lemma,

we deduce that

(24)

and therefore

From the

inequality

we deduce

and thus

We conclude that

Finally,

we observe with

(5.7)

that

and we conclude with

Lebesgue’s

theorem the convergence of each term of the

right-hand

side of

(5.17)

in

L1 (]0, T [ R

x

R)

as 03B4 - 0. D

Now,

we are able to conclude. For

any t > 0, .))

-

(f(t, .))

in

x

R)

as 03B4 - 0

by Lebesgue’s

theorem. But we can write

(5.12)

for

W6 (f) ,

By

Lemma

5.3,

we can pass to the limit in the

right-hand

side in

C ( ~0, T ~

,

Ll (JR

x

R)). Therefore,

(25)

For the last term

1/J(fo)

=

fo+l~~/(1-f-1/~) in (5.8),

we can use the approx- imation

Then the

argument

is similar as above

(even simpler, L 1

is

obtained

directly

since

f1/03BB0

E

L03BB(1+1/03BB), M0 [f]

E

L1+1/03BB),

and we do not

repeat

the

proof.

5.5. Proof of Theorem 1.3

According

to the

previous subsections,

we can

apply

Lemma 5.2 to each

term of the

decomposition (5.8). Noticing

that the convention on the value of

H’(o, ~) corresponds

to

~’(o) - 0,

we obtain

(1.25)-(1.28). Moreover,

~H( f (t, x, ~), ~)

E x

R)

and

But

by Proposition 2.6,

and since

J’ ( f - M ~ f ~ ) d~ = 0,

thus P E

L 1 (~ 0,

x

R) . Finally,

since

from

(5.31)

and

(5.32)

we obtain

(1.29)

and

(1.30).

D

(26)

Remark 5.1. - It is

possible

to prove

directly

that

Indeed

by (2.4)

and

Proposition 2.5,

thus

and

pU2, p’Y

E

L 1 {I~) ) . Then,

the

inequality

proves that

2Cfi . A

similar estimate holds for and the other terms in

(5.36)

are easy to estimate with

(5.38).

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