HAL Id: jpa-00209808
https://hal.archives-ouvertes.fr/jpa-00209808
Submitted on 1 Jan 1984
HAL is a multi-disciplinary open access archive for the deposit and dissemination of sci- entific research documents, whether they are pub- lished or not. The documents may come from teaching and research institutions in France or abroad, or from public or private research centers.
L’archive ouverte pluridisciplinaire HAL, est destinée au dépôt et à la diffusion de documents scientifiques de niveau recherche, publiés ou non, émanant des établissements d’enseignement et de recherche français ou étrangers, des laboratoires publics ou privés.
Birefringence and Frederiks effect in a cubic liquid crystal
P. Saidachmetov
To cite this version:
P. Saidachmetov. Birefringence and Frederiks effect in a cubic liquid crystal. Journal de Physique, 1984, 45 (4), pp.761-764. �10.1051/jphys:01984004504076100�. �jpa-00209808�
Birefringence and Frederiks effect in a cubic liquid crystal
P.
Saidachmetov (* )
Landau Institute for Theoretical Physics, U.S.S.R.
(Reçu le 24 octobre 1983, accepté le 12 décembre 1983 )
Résumé. 2014 Les expériences montrent que les cristaux liquides nématiques existants sont uniaxes avec une symétrie
de groupe continu. L’existence de cristaux liquides présentant une symétrie de groupe discret, par exemple la symétrie du groupe du cube, n’est pas interdite. Les candidats les plus probables pour cette classe de composés
sont les smectiques D qui ne présentent pas d’anisotropie optique. La question se pose de savoir comment distin- guer expérimentalement un cristal liquide cubique d’un liquide isotrope. Dans ce travail, on propose d’utiliser à cette fin l’effet Kerr anisotrope.
Abstract. 2014 Experiments show that the existing nematic liquid crystals are uniaxial with the continuous group symmetry. The existence of liquid crystals possessing a discrete group symmetry 2014 for instance, the cubic group symmetry 2014 is not forbidden. The most probable candidates for this class of compounds are so-called smectics D
which do not show optic anisotropy. The question arises of how to distinguish experimentally a cubic liquid crystal from an isotropic liquid In this work the anisotropic Kerr effect is proposed for this purpose.
Classification Physics Abstracts
61. 30G
Nelson and Toner [1]
proposed
that there exist smecticliquid
crystals with the cubic group symmetry.The most
probable
candidates for this class of com-pounds
are so-called smectics D, which do not showoptic anisotropy
[2, 3]. Thequestion
of how to distin-guish experimentally
a cubicliquid crystal
from anisotropic liquid
arises. In this work theanisotropic
Kerr effect is
proposed
for this purpose.According
to Nelson and Toner [1](see
also Pata-shinskii and Mitus
[4]),
the order parameter in a cubicliquid
crystal is definedby
a fourth order ten-sor
À.a.pya
where n’ are the unit vectors directed along the fourth-
order axes of a cube.
Let us consider a cubic
liquid crystal placed
in theexternal electric field E. The energy of interaction of such a
crystal
with the external field can be written(*) Permanent address : Physico-Technical Institute
of the Tadjik Academy of Sciences, Index 734063, Dushambe,
USSR.
using
rotational invariance considerations :One can
easily
find theanisotropic
part of the dielec- tric tensor fromequation (2) :
Generally
the eigenvalues of the tensorB:p
arewhere the
principal
axes are directed along the vec-tors ni. When the field E is directed along a diagonal
of the cube or along one of the fourth-order axis,
the
anisotropy
is uniaxial. This situation is difficult todistinguish
from the Kerr effect in anisotropic liquid
In order todistinguish
a cubicliquid
crystalfrom an
isotropic liquid
it is necessary to measurethe Kerr effect while
varying
the direction of the elec- tric field E. However, the variation of the direction of the electric field cannotalways
be followedby
thechange
of the Kerr effect. Indeed, so far we considerArticle published online by EDP Sciences and available at http://dx.doi.org/10.1051/jphys:01984004504076100
762
the triad n‘ to be oriented
rigidly,
while the field E rotatesfreely
with respect to it. Provided the effect of boundaries and other orienting factors isnegligible,
the field E will orient the cubic
liquid crystal
itself.The
resulting
orientationdepends
on the sign of g.If 9 > 0, the
crystal
is oriented in such a way as to make the direction of E coincide with a diagonal ofthe cube. If g 0, E is directed along one of the fourth- order axes. So the cubic
liquid crystal
is orientedby
the electric field in such a way as to make it
impossible
to
distinguish
from anisotropic liquid.
Hence theexperiments
should be done inlayers sufficiently
thinto orient the
liquid crystal
with the walls.Though we do not know
anything
about the orien-tational action of walls, the effect of wales is
probably
to orient a
crystal
in such a way as to direct the nor-mal to a wall
along
adiagonal
or along theedge
of thecube.
In the
vicinity
of a wall the direction of adiagonal
or an
edge
of the cube is fixed ; however, a free rota- tion remainspossible
in theplane perpendicular
tothe indicated direction. The electric field E, whose direction does not coincide with that of the normal to the surface, fixes this azimuthal angle. If the
diagonal
of the cube is
perpendicular
to the surface and g > 0, theprojection
of anedge
and theprojection
of theelectric field
point
inopposite
directions, while atg 0 their directions coincide (see
Figs.
1 and 2).If one of the cube
edges
is normal to the surface and g > 0, theprojection
of the electric field coincides with thediagonal
of the cube face,lying
on the sur-face. If g 0, one of the cube
edges
is directed alongthe
projection
of the electric field (see Figs. 3, 4).We shall
designate
these differentgeometric
situa-tions
by
A + and B+. The letters A, B indicate whether the diagonal or the edge of the cube coincides with the normal to the surface, while indices ± refer to thesign of the constant g.
The texture of a cubic
liquid crystal
can be charac-terized
by
one angle 0, which can be choosen to be the angle between the normal and thediagonal
of thecube in the cases A t and to be the
angle
between the normal and theedge
of the cube in the cases B+.The coordinates of the triad in the case A* are
written
explicitly
below :where
00
=arctg /.
We wile not write out the othercases, as the generalization is obvious.
The
angle
between thediagonal
of the cube and the field E can be fixedarbitrarily
until the Frederiks transition.Fig. 1. - The arrangement of the cube and the electric field vector for g > 0. L is the unit vector directed along the diagonal of the cube. nl, n2, n3 are the unit vectors directed along the edges of the cube. The normal to the surface coincides with the z-axis.
Fig. 2. - The arrangement of the main directions for g 0. The normal to the surface coincides with the diagonal
L of the cube.
Fig. 3. - The arrangement of the cube and the electric field vector for g > 0. The normal to the surface coincides with the edge of the cube.
Fig. 4. - The arrangement of the cube and the electric field vector for g 0.
We now consider this transition. First of all, the gene- ral form of the elastic distortion energy in a cubic
liquid crystal
must be foundRestricting
ourselvesto the effects which are
quadratic
over the tensorÀ.a.fJ1t1
as well as over the derivatives of this tensor, the cubic symmetry definesunambiguously
the form of the elastic energy :This
equation
differs from the usualexpression
fora nematic
liquid crystal only
in the summation over i.The values
Ki
can benaturally
called the Frank cons- tants. The triad distributioncorresponds
to a mini-mum of the energy H =
H,
+He
atgiven boundary
conditions.
The total energy in an electric field for the case A + has the form
where OE
is theangle
between the normal to the sur-face and the direction of the electric field,
Assuming
0 to be smalleverywhere
we obtain appro-ximately
from(7)
where
The Frederiks transition takes
place
at a = 0, b > 0only. Using equation (10)
we find these conditions to be satisfied atOE
= -00 or OE
= n/2 -00.
Thecritical value
Ec
can be foundby solving
the linearEuler-Lagrange
equation for the functional(9)
andrequiring
0 to be zero at z = 0 and z = d :The constant b has the value b = 4 at
6E
= -00
and b = 8 at
0E
=nj2 - 00.
If E
Ee
andOE
has the values indicated above,the solution 0 = 0 is valid If
BE
deviates from thedistinguished
directions -00
andn/2 - 00,
theangle
0 is nonzero at any value of E. The solution of the linearequation
iswhere
and d is the thickness of the cubic
liquid
crystallayer.
The
equation (12)
is validprovided
0 1 and b > 0.In
particular,
at smallE/Ec
we have 0 -(E/Ec)4;
at 9 close to
00
we have0 - 0o - 9E I Ecjl E - E, 1.
Omitting
the calculations, we write down the valuesE,
for another geometrical situation A-, B+ :The
case A- :The case B + :
OE
= 0or BE
=n/2,
b isequal
to 8 or 4respectively.
The case B - :
So at E
Er generally,
and at EEc
in the vici-nity
of somedistinguished
directions, the deviation from the orientation fixedby
the walls iseverywhere
small. This
yields
thepossibility
of observing the Kerreffect at a
given value BE
and 0=0. The interaction- inducedanisotropy
of the dielectric tensor is uniaxial.However, in contrast to the case of an
isotropic liquid,
the
anisotropy
axis coincides with the electric field direction. We would like to note also that the diffe-rence of the refraction coefficients ne - no
depends
on the electric field direction.
The situation differs
slightly
if the usual Kerr effectðBa.fJ ’" Ea. EfJ
appears to contributesignificantly.
Inthis case one of the
principal
axes of the dielectrictensor is
perpendicular
to theplane containing
the764
diagonal
of the cube, itsedge
and the electric field vector. The eigenvalue associated with this axis of the dielectric tensor B1 is a linear function ofcos
2(Oo
+0,).
Let us draw attention to a
peculiarity
of the Fre-deriks effect when the
angle 0E
=arctg-.¡2.
It is possible to define the constants A, g, K’ (K’ =
3
K,
+K2
+ 2K3)
which measure the critical field and the angulardependence
of the dielectric aniso- tropy.Here some estimates for
Ee
arepresented
Assuming
the Franck constants to be 10-6dyne
as in a nematic
liquid
crystal and A - l, g NEat-2 ~
4 x 10-’o CGSE
(Eat
is a characteristic atomic elec- tricfield)
we obtainEc ~
104V/cm
forlayer
thicknessd - 10-’ cm.
Acknowledgments.
In conclusion, I express my gratitude to V. L. Pokrov-
sky
for the statement of theproblem
and to E. I. Katsfor useful discussions.
References
[1] NELSON, D. R., TONER, J., Phys. Rev. B 24 (1981) 363.
[2] DE GENNES, P. G., The Physics of Liquid Crystals (Clarendon Press, Oxford) 1974.
[3] PELZL, G., SACKMANN, H., Sympos. Chem. Soc. Faraday Div., N° 5 (1971).
[4] MITUS, A. S., PATASHINSKII, A. Z., Soviet Physics JETP
80 (1981) 1554.