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Submitted on 1 Jan 1984

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Birefringence and Frederiks effect in a cubic liquid crystal

P. Saidachmetov

To cite this version:

P. Saidachmetov. Birefringence and Frederiks effect in a cubic liquid crystal. Journal de Physique, 1984, 45 (4), pp.761-764. �10.1051/jphys:01984004504076100�. �jpa-00209808�

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Birefringence and Frederiks effect in

a

cubic liquid crystal

P.

Saidachmetov (* )

Landau Institute for Theoretical Physics, U.S.S.R.

(Reçu le 24 octobre 1983, accepté le 12 décembre 1983 )

Résumé. 2014 Les expériences montrent que les cristaux liquides nématiques existants sont uniaxes avec une symétrie

de groupe continu. L’existence de cristaux liquides présentant une symétrie de groupe discret, par exemple la symétrie du groupe du cube, n’est pas interdite. Les candidats les plus probables pour cette classe de composés

sont les smectiques D qui ne présentent pas d’anisotropie optique. La question se pose de savoir comment distin- guer expérimentalement un cristal liquide cubique d’un liquide isotrope. Dans ce travail, on propose d’utiliser à cette fin l’effet Kerr anisotrope.

Abstract. 2014 Experiments show that the existing nematic liquid crystals are uniaxial with the continuous group symmetry. The existence of liquid crystals possessing a discrete group symmetry 2014 for instance, the cubic group symmetry 2014 is not forbidden. The most probable candidates for this class of compounds are so-called smectics D

which do not show optic anisotropy. The question arises of how to distinguish experimentally a cubic liquid crystal from an isotropic liquid In this work the anisotropic Kerr effect is proposed for this purpose.

Classification Physics Abstracts

61. 30G

Nelson and Toner [1]

proposed

that there exist smectic

liquid

crystals with the cubic group symmetry.

The most

probable

candidates for this class of com-

pounds

are so-called smectics D, which do not show

optic anisotropy

[2, 3]. The

question

of how to distin-

guish experimentally

a cubic

liquid crystal

from an

isotropic liquid

arises. In this work the

anisotropic

Kerr effect is

proposed

for this purpose.

According

to Nelson and Toner [1]

(see

also Pata-

shinskii and Mitus

[4]),

the order parameter in a cubic

liquid

crystal is defined

by

a fourth order ten-

sor

À.a.pya

where n’ are the unit vectors directed along the fourth-

order axes of a cube.

Let us consider a cubic

liquid crystal placed

in the

external electric field E. The energy of interaction of such a

crystal

with the external field can be written

(*) Permanent address : Physico-Technical Institute

of the Tadjik Academy of Sciences, Index 734063, Dushambe,

USSR.

using

rotational invariance considerations :

One can

easily

find the

anisotropic

part of the dielec- tric tensor from

equation (2) :

Generally

the eigenvalues of the tensor

B:p

are

where the

principal

axes are directed along the vec-

tors ni. When the field E is directed along a diagonal

of the cube or along one of the fourth-order axis,

the

anisotropy

is uniaxial. This situation is difficult to

distinguish

from the Kerr effect in an

isotropic liquid

In order to

distinguish

a cubic

liquid

crystal

from an

isotropic liquid

it is necessary to measure

the Kerr effect while

varying

the direction of the elec- tric field E. However, the variation of the direction of the electric field cannot

always

be followed

by

the

change

of the Kerr effect. Indeed, so far we consider

Article published online by EDP Sciences and available at http://dx.doi.org/10.1051/jphys:01984004504076100

(3)

762

the triad n‘ to be oriented

rigidly,

while the field E rotates

freely

with respect to it. Provided the effect of boundaries and other orienting factors is

negligible,

the field E will orient the cubic

liquid crystal

itself.

The

resulting

orientation

depends

on the sign of g.

If 9 > 0, the

crystal

is oriented in such a way as to make the direction of E coincide with a diagonal of

the cube. If g 0, E is directed along one of the fourth- order axes. So the cubic

liquid crystal

is oriented

by

the electric field in such a way as to make it

impossible

to

distinguish

from an

isotropic liquid.

Hence the

experiments

should be done in

layers sufficiently

thin

to orient the

liquid crystal

with the walls.

Though we do not know

anything

about the orien-

tational action of walls, the effect of wales is

probably

to orient a

crystal

in such a way as to direct the nor-

mal to a wall

along

a

diagonal

or along the

edge

of the

cube.

In the

vicinity

of a wall the direction of a

diagonal

or an

edge

of the cube is fixed ; however, a free rota- tion remains

possible

in the

plane perpendicular

to

the indicated direction. The electric field E, whose direction does not coincide with that of the normal to the surface, fixes this azimuthal angle. If the

diagonal

of the cube is

perpendicular

to the surface and g > 0, the

projection

of an

edge

and the

projection

of the

electric field

point

in

opposite

directions, while at

g 0 their directions coincide (see

Figs.

1 and 2).

If one of the cube

edges

is normal to the surface and g > 0, the

projection

of the electric field coincides with the

diagonal

of the cube face,

lying

on the sur-

face. If g 0, one of the cube

edges

is directed along

the

projection

of the electric field (see Figs. 3, 4).

We shall

designate

these different

geometric

situa-

tions

by

A + and B+. The letters A, B indicate whether the diagonal or the edge of the cube coincides with the normal to the surface, while indices ± refer to the

sign of the constant g.

The texture of a cubic

liquid crystal

can be charac-

terized

by

one angle 0, which can be choosen to be the angle between the normal and the

diagonal

of the

cube in the cases A t and to be the

angle

between the normal and the

edge

of the cube in the cases B+.

The coordinates of the triad in the case A* are

written

explicitly

below :

where

00

=

arctg /.

We wile not write out the other

cases, as the generalization is obvious.

The

angle

between the

diagonal

of the cube and the field E can be fixed

arbitrarily

until the Frederiks transition.

Fig. 1. - The arrangement of the cube and the electric field vector for g > 0. L is the unit vector directed along the diagonal of the cube. nl, n2, n3 are the unit vectors directed along the edges of the cube. The normal to the surface coincides with the z-axis.

Fig. 2. - The arrangement of the main directions for g 0. The normal to the surface coincides with the diagonal

L of the cube.

Fig. 3. - The arrangement of the cube and the electric field vector for g > 0. The normal to the surface coincides with the edge of the cube.

Fig. 4. - The arrangement of the cube and the electric field vector for g 0.

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We now consider this transition. First of all, the gene- ral form of the elastic distortion energy in a cubic

liquid crystal

must be found

Restricting

ourselves

to the effects which are

quadratic

over the tensor

À.a.fJ1t1

as well as over the derivatives of this tensor, the cubic symmetry defines

unambiguously

the form of the elastic energy :

This

equation

differs from the usual

expression

for

a nematic

liquid crystal only

in the summation over i.

The values

Ki

can be

naturally

called the Frank cons- tants. The triad distribution

corresponds

to a mini-

mum of the energy H =

H,

+

He

at

given boundary

conditions.

The total energy in an electric field for the case A + has the form

where OE

is the

angle

between the normal to the sur-

face and the direction of the electric field,

Assuming

0 to be small

everywhere

we obtain appro-

ximately

from

(7)

where

The Frederiks transition takes

place

at a = 0, b > 0

only. Using equation (10)

we find these conditions to be satisfied at

OE

= -

00 or OE

= n/2 -

00.

The

critical value

Ec

can be found

by solving

the linear

Euler-Lagrange

equation for the functional

(9)

and

requiring

0 to be zero at z = 0 and z = d :

The constant b has the value b = 4 at

6E

= -

00

and b = 8 at

0E

=

nj2 - 00.

If E

Ee

and

OE

has the values indicated above,

the solution 0 = 0 is valid If

BE

deviates from the

distinguished

directions -

00

and

n/2 - 00,

the

angle

0 is nonzero at any value of E. The solution of the linear

equation

is

where

and d is the thickness of the cubic

liquid

crystal

layer.

The

equation (12)

is valid

provided

0 1 and b > 0.

In

particular,

at small

E/Ec

we have 0 -

(E/Ec)4;

at 9 close to

00

we have

0 - 0o - 9E I Ecjl E - E, 1.

Omitting

the calculations, we write down the values

E,

for another geometrical situation A-, B+ :

The

case A- :

The case B + :

OE

= 0

or BE

=

n/2,

b is

equal

to 8 or 4

respectively.

The case B - :

So at E

Er generally,

and at E

Ec

in the vici-

nity

of some

distinguished

directions, the deviation from the orientation fixed

by

the walls is

everywhere

small. This

yields

the

possibility

of observing the Kerr

effect at a

given value BE

and 0=0. The interaction- induced

anisotropy

of the dielectric tensor is uniaxial.

However, in contrast to the case of an

isotropic liquid,

the

anisotropy

axis coincides with the electric field direction. We would like to note also that the diffe-

rence of the refraction coefficients ne - no

depends

on the electric field direction.

The situation differs

slightly

if the usual Kerr effect

ðBa.fJ ’" Ea. EfJ

appears to contribute

significantly.

In

this case one of the

principal

axes of the dielectric

tensor is

perpendicular

to the

plane containing

the

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764

diagonal

of the cube, its

edge

and the electric field vector. The eigenvalue associated with this axis of the dielectric tensor B1 is a linear function of

cos

2(Oo

+

0,).

Let us draw attention to a

peculiarity

of the Fre-

deriks effect when the

angle 0E

=

arctg-.¡2.

It is possible to define the constants A, g, K’ (K’ =

3

K,

+

K2

+ 2

K3)

which measure the critical field and the angular

dependence

of the dielectric aniso- tropy.

Here some estimates for

Ee

are

presented

Assuming

the Franck constants to be 10-6

dyne

as in a nematic

liquid

crystal and A - l, g N

Eat-2 ~

4 x 10-’o CGSE

(Eat

is a characteristic atomic elec- tric

field)

we obtain

Ec ~

104

V/cm

for

layer

thickness

d - 10-’ cm.

Acknowledgments.

In conclusion, I express my gratitude to V. L. Pokrov-

sky

for the statement of the

problem

and to E. I. Kats

for useful discussions.

References

[1] NELSON, D. R., TONER, J., Phys. Rev. B 24 (1981) 363.

[2] DE GENNES, P. G., The Physics of Liquid Crystals (Clarendon Press, Oxford) 1974.

[3] PELZL, G., SACKMANN, H., Sympos. Chem. Soc. Faraday Div., N° 5 (1971).

[4] MITUS, A. S., PATASHINSKII, A. Z., Soviet Physics JETP

80 (1981) 1554.

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