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A geometrical analysis of limit layers and interfaces of lattices
Michel Duneau
To cite this version:
Michel Duneau. A geometrical analysis of limit layers and interfaces of lattices. Journal de Physique
I, EDP Sciences, 1992, 2 (6), pp.871-886. �10.1051/jp1:1992185�. �jpa-00246608�
Classification
Physics
Abstracts61.50J 61.50K 61.70N 64.70K
A geometrical analysis of limit layers and interfaces of lattices
Michel Duneau
(*)
Centre de
Physique Thdorique,
EcolePolytechnique,
91128 Palaiseau Cedex, France(Received
3J October I99I, revised 3 December I99I,accepted
13 DecemberI99I)
R4sum4. Les couches limites d'un rdseau au
voisinage
d'unplan quelconque
peuvent dtre d£crites par la mdthode de coupe. Les sitescorrespondants
sontproches
d'un r6seau moyen bi- dimensionnel contenu dans leplan
limite. La modulation assoc16e a la structure d'un cisaillement fractionnairesimple.
Dans les cas oh deux r£seaux de mdme densit6 sont lids par un double cisaillement nous montrons que pour certaines orientations d'interface les deux couches limites ont le mdme rdseau moyen, favorisant airtsi une coh6renceoptimale.
Abstract. Limit
layers
of a lattice in theneighborhood
of anyplane
can be describedby
the cutmethod. The
corresponding
nodes are close to a 2-dirnensional average lattice contained in the limitplane.
The associated modulation has the structure of asimple
fractional shear. ln cases where two lattices ofequal density
are relatedby
a double shear we show that forparticular
orientations of the interface both limit
layers
share the same average lattice, thusfavoring
anoptimal
coherence.I. Introduction.
The cut method was
extensively
used in connection withquasicrystals
in order toprovide
models of
quasiperiodic
structures withnon-crystallographic symmetries (see
for instanceII).
In such constructions a
higher
dimensional space is introduced(for
instance R6 in the case of icosahedralstructures)
and the cut method allows one to select nodes of anon-physical
lattice(for
instance26)
and toproject
these nodes in the 3-dimensionalphysical
space.Thus,
quasiperiodic
structures such as the 3-dimensional Penrosetilings
arefinally
obtained.In this paper we show that the cut method can be used with benefit in the
ordinary
3-dimensional space for the
description
of limitlayers,
interfaces anddisplacive
transformationsbetween lattices. The occurrence and the
importance
ofquasiperiodic ordering
ingrain
boundaries was
already
noticed in[2-4].
The limit
layers
of a half lattice cutby
aplane
are obvious instances of the cut method. The toolsdeveloped
in thequasicrystal
field can beapplied
in this more intuitive situation. As anexample
these limitlayers
tum out to be close to 2-dimensional lattices even when the cutplane
is irrational. This result is based on the construction of average lattices ofquasiperiodic
structures. We shall see that the bounded transformation from a
(possibly quasiperiodic) layer
(*) CNRS-UPRA 0014.
of a lattice into its 2-dimensional average lattice is a fractional version of a shear transformation.
The fractional shears are introduced and discussed. We show that
they provide
thesimplest
bounded transformations between lattices and therefore
give
the bestgeometrical
candidates fordisplacive
transformations. As mentioned abovethey
are involved in the construction ofaverage
lattices,
butthey
also prove to be useful in theanalysis
of moregeneral displacive
transformations.
Shear transformations can be used to
analyse
therelationships
between two lattices ofequal density.
Four successive shears areusually required
to map a latticeL~
onto a latticeL~
in 3 dimensions. However forparticular pairs
oflattices,
or forparticular
relative orientations this number can be lowered to two(or
evenone).
Suchexceptional
cases arebelieved to have a
physical meaning.
For instance it was shown in[5]
that icosahedral twins of cubic lattices, as observed in[6]
in the Almnfesi system, arepair
wise relatedby only
twoshears. On the other hand the relative orientations between
grains giving
rise to usualcoincidence lattices can be shown to
correspond
to one or two shears with rationalparameters
[7].
In section 2 we recall the definition and
properties
of linear shear transformations and we introduce fractional shear transformations. Then we show in section 3 that mostsimple
bounded transformations between lattices are
given by
such fractional shears. In section 4 we consider limitlayers
of lattices boundedby
aplane
oftypically
irrational orientation. We show that such limitlayers
are close to an 2-dimensional average latticelying
in thisplane.
The transformation
mapping
the nodes of the limitlayer
onto the nodes of the average lattice isproved
to be a fractional shear. In section 5 we consider the mostgeneral
relative orientations between lattices ofequal density.
We show that the transition matrices are theproduct
of at most 4 shear matrices and wegive
asimple algorithm
to compute them. In 2 dimensions the mostgeneral
transition matrix is theproduct
of 3 shears. We consider theexample
of two square lattices with a arm relative orientation. In section 6 we focus on theexceptional
cases of the double shears and we show thatthey
can be identifiedby
asimple
criterion. In section 7 the same double shear cases are
proved
toyield
most « coherent »interfaces,
the orientations of which arespecified by special
latticeplanes
of an intermediate lattice.2. Shear transformations and fractional shear transformations.
A shear transformation is a linear
mapping
whichreads, using
Dirac's bracket notation :+ Sl ~l St ~2 Sl ~3
~
"
~ +
'S) (~
" 52 ~l + 52 ~2 52 ~3
(2.1)
53 ~l 53 ~2 + 53
3~
S(x)
= x +
(« [x)
swhere s is a vector and « is a covector.
Therefore S transforms a
point
xby
a translation of constant direction s with anamplitude (« ix) ills ii.
The transformation has an invariantplane
definedby (« ix)
= 0 which is
equivalent
toS(x)
= x.We shall
only
consider volumepreserving
shear transformations which are characterizedby
the further condition
(« s)
= 0 which is
equivalent
to det(S)
=
I. In this case the invariant
plane
contains the shear direction s and the inverse of S isgiven by
S~ '=
I
[s) (« [.
Let
L~
=
AZ ~ and
L~
=
BZ~
denote two lattices ofequal density.
The 3 x 3 real structure matrix A isregular
and its columnsgive
aparticular
basis ofL~, la)
=
jai,
a~,a~)
witha,
=Ae;,
where(e~,e~,e~)
is the standard basis of the 3-dimensional space. Thus Aspecifies
the metric and orientation parameters ofL~. Similarly 16)
=
(bi, b~, b~)
withb,
=
Be;
where B is a structure matrix of the latticeL~.
Structure matrices map the abstract lattice
23,
in the space of « indices », onto the real lattices in thephysical
space.However, any lattice has
infinitely
many different basis andconsequently infinitely
manystructure matrices.
Actually,
for any modular matrix U, I.e. withintegral
entries anddeterminant ±
I,
we also haveL~
= AUZ 3 in such a way that A'= AU is an
equally
validstructure matrix of
L~ corresponding
to the basis(a')
=
(a(, a(, a()
withal
=
A'e,
=
£
U~, a~. Therefore agiven
latticeonly specifies
a class of structure matricesJ
defined up to
right multiplication by
a modular matrix.We shall say that
L~
andL~
are relatedby
asimple
shear transformation S= I +
is) («
if :
I) L~
andL~
have structure matrices A and B such that B=
AS,
which isequivalent
toA B
= S
2)
the vector s is an irreducible vector of the lattice 23 and(« is)
= 0.This condition means that the
corresponding
basesla)
and16) satisfy
thefollowing
relation :
b,
=ASe;
=
A
(e,
+ «,s)
= a, + «, w
(2.2)
where w
=
As is a lattice vector of
L~.
Notice that since s in invariantby S,
w=
As
=
Bs also
belongs
toL~
so thatL~
andL~
have a common I-dimensional sublattice.With more
appropriate
choices of bases(such
that a~ =b~
=As)
this relation can take asimpler
form where the shear matrix Ssimply
reads :II
o o
S= o I o
«1 «~ l
in such a way that :
b~=a~+«~a~
b~
= a~ + «~ a~(2.3)
b~
= a~.The above shear transformation S is defined and acts in the space of indices. In
physical
space, the
corresponding
linear transformation which mapsL~
ontoL~
isgiven by
S~
= ASA Oneeasily
checks that :S~L~=S~AZ3=ASZ3=BZ3=L~
S~
has thefollowing expression
:s~ ~li i i i>j Ii1 (2.4)
with w
= As and
w =
(A
~)~ «.Thus w
gives
the shear direction andw defines the invariant
plane
in thephysical
space.One
easily
checks that(w [w)
=
0 which is
equivalent
to det(S~)
=
I. The inverse of
JOURNAL DE PHYSIQUE -T 2, N's, JUNE 1992 34
S~
is the shear transformationSi~
=I-[w)(w[.
It follows from the definition ofS~
thatS~ (a~ )
=b,
for I=
1, 2,
3 which means thatS~
maps the basis(a )
ofL~
onto the basis(b)
ofL~.
Moregenerally,
if x=£n;a;
is a lattice node ofL~ (n; integer)
thenS~(x)= £n;b;
is the lattice node ofL~
with the same indices. Notice that sincew is invariant
by S~,w
has the same coordinates with respect tola)
and(b).
Now,
ifL~
andL~
are relatedby
asimple
shear transformationS,
we caneasily
build a bounded transformation3,
called hereafter a fractionalshear,
which satisfies thefollowing properties
:Ii
3 is a one-to-onemapping
ofR3
such that3~
=
A3A maps
L~
ontoL~.
2)
3 is « bounded » in the sense that thedisplacement 3(x)
-x remains bounded whenx runs over R3.
3 is
given by
thefollowing equivalent
definitions(see Fig, 1)
:3(x
= x + Frac
j (« [xi j
s(2.5) 3(x)
=
S(x)
-RndI("lxl)I
Swhere
Rnd(t)
is the(integer valued)
round function(I)
in such a way thatFrac
(t)
= t Rnd
(t)
lies in the interval( 1/2, 1/2].
By
definition of3~
we have :3~(x)=x+Frac j(«[A~~x)]As=x+Frac j(w[x)]w 3~ (x)
=
S~ (x)
Rndj (w [xi
w~~'~~
Clearly,
3 is bounded since the norm of thedisplacement 3(x)
x= Frac
j(« [x)
s isbounded
by
is11 /2.
Similarly, 3~ (x)
x =Frac
j(w xi
w is boundedby
iw11 /2.Fig.
I. The square lattice L~ is transformed into L~by
a shear S of direction w= (2, 1). Both lattices
lay
in the bundle of dashed lines Aparallel
to w. The linear shear involvesdiverging
translations betweenx in L~ and S(x) in L~ whereas the fractional shear 3 translates x onto the nearest L~ node on the same line.
(1) The round function maps a real number t onto the nearest
integer
(with Rnd (n + 1/2) n for allinteger
n).3 is a one-to-one
mapping
for it has an inverse transformationgiven by
3~
~(x )
= x Frac[ (« xi
s.Similarly, 3~
is also one-to-one with an inversegiven by Ii ~(x)
= x Frac
(w xi
w. Theproperty
that3~
mapsL~
ontoL~
then follows from the remark that3~
differs fromS~ by multiples
of w which alsobelong
toL~ (see (2.6)).
Using coordinates,
themapping 3~
isexplicitly given by
:x =
£x;
a,-
3~ (x)
=£
x, b~ Rnd[£
«;x;j
w(2.7)
where
(x~,
x~,x~)
denote the coordinates of x with respect to the basis(a).
The coordinates~y~, y~,
y~)
of y=
3~ (x)
with respect to the basis(b)
are thereforegiven by
:y~ = x~ Rnd
£
«; x~ w;(2.8)
where
(w~,
w~,w~)
denotes the coordinates of w with respect to both bases(a)
and16 )
As a
conclusion,
the fractional shear3~
has thefollowing specific property
: it translates anode of
L~
onto the nearest node ofL~ lying
on the same lattice lineparallel
tow ; this follows from the
amplitude
Frac(w ix)
of the translationbeing
boundedby 1/2
and from wbeing
irreducible.3.
Simple
bounded transformations between lattices.In this section we show that the
simplest
bounded transformations between lattices areprovided by
fractional shear transformations as defined in the above section. The terms«
simple
» and « bounded »require
a clear definition which isgiven
below. It tums out that such transformations arepossible only
betweenparticular pairs
oflattices, namely
those for which the transition matrix isequivalent
to a shear matrix. Morecomplex relationships
between lattices will be considered in section 5.
By
asimple
bounded transformation we mean aglobal
one-to-onemapping 4
of the 3- dimensional space such that4 (x)
= x + w
(x)
u where q~ is a bounded real function and where u is a fixed vector. Thus4
transforms anypoint
xby
a translation of constant directionu and bounded
amplitude
q~(x )
i u ii.This definition is devised to
correspond
more or less tosimple displacive
transformations with the difference that in our context no energy consideration is involved.As will become clear in the
following
the fact that such a transformation maps agiven
lattice
L~
onto some latticeL~
is not obvious. Thisactually corresponds
tostrong
restrictionson
L~
andL~.
THEOREM.
Let
L~=AZ~
andL~ =BZ~
denotetwo lattices and assume
4
is asimple
boundedtransformation,
as definedabove,
which mapsL~
ontoL~.
ThenL~
andL~
have the samedensity,
u is a lattice direction of both lattices and after a convenientscaling
(q~- rq~ and
u - r~
u)
which does notchange 4,
u is an irreducible vector ofL~
andL~.
PROOF.
One
easily
checks that ifL~
andL~
had not the samedensity,
a bounded one to onemapping
from
L~
toL~
would beimpossible.
Now for any x and y in
L~
we have :w(x)- w(y)- w(x-y)
=
iq~(x) q~(y) q~(x-y)i
u.First,
we can assume thisidentity
does not reducealways
to 0=
0 otherwise the
amplitude
q~ would be a linear
(and bounded)
function in this case q~ would vanish andconsequently L~
=Lb.
If the above
equation
is not trivialthen,
since the left hand sidebelongs
toL~,
u is a lattice direction of
L~.
Since
4
is assumed to be one-to-one fromL~
toL~,
for any x and y inL~
one can findz in
L~
such that 4(x) 4 (y)
=
4 (z).
Thisimplies
:0=w(x)-w(y)-w(z)
=x-y-z+iq~(x)-q~(y)-q~(z)iu
which in tum
implies
that u is also a lattice direction ofL~.
Consequently
both lattices have a common bundle of lattices lines Aparallel
to u. Themapping
4 thus transforms theL~
nodes on such a line into theL~
nodeslying
on the same line. Since thedisplacements
are assumed to remainbounded,
the I -dimensional latticesL~
n A andL~
n A must have the samedensity,
I,e, the same lattice parameter. From thisremark we conclude that
q~ and u can be rescaled
by
some real numberr#0
(q~ -rq~ and u
-r~~u)
in such a way that u is agenerator
of both latticesL~
n A andL~
n A. Thus u is an irreducible vector ofL~
andL~.
At this
point
we can raise a newquestion
:assuming L~
andL~
are relatedby
somesimple
bounded
transformation,
is there aparticular
transformation of this type which minimizes alldisplacements?
The answer ispositive
and the solution isgiven by
a fractional shear transformation.Actually,
on any line A the I-dimensional latticesL~
n A andL~
n A aresimply
translated from each other(they
have the same basis vectoru).
So there isonly
oneway to minimize the
displacements
: map any node ofL~
n A onto the nearest node ofL~
n A. But this solution isprecisely
what is obtainedby
the fractional shears as shown at the end of theprevious
section.Finally,
if two lattices are relatedby
asimple
boundedtransformation, they
are also relatedby
a fractional shear which minimizes thedisplacements.
This fractional shear is therefore asimple
and natural candidate for apossible displacive
transformation between these lattices.4. Limit
layers
and their average lattices.In this section we show that limit
layers
of a lattice in thevicinity
of aplane
are close to a 2- dimensional lattice.Furthermore, simple displacements transforming
the limitlayers
into their average lattices aregiven by
fractional shears as described in section 2.Let
L~
=AZ ~ denote a 3-dimensional lattice with structure matrix A. Assume this lattice is cut
by
aplane
lI ofequation (v ix)
= c and assume forsimplicity
that c= 0. lI may be
considered as an ideal free surface of the lattice or as an interface
plane
with respect to another structure. In either case different
phenomena
will contribute tochange
the structure in theneighborhood
of lI so that a definite limitlayer, supposed
to contain alldeformations,
ishard to
specify.
We shall
only
consider the case where lI iscompletely
irrational withrespect
toL~. Rational,
orpartially
rational orientations of lIgive
rise to asimpler
situation because the cutplane
contains at least a I-dimensional sublattice.For this reason, and for
geometrical
reasonsexplained below,
we shall consider different butparticular
limitlayers satisfying
the condition that their widthcorrespond
to some latticevector. In other
words,
we consider limitlayers
boundedby
twoplanes
lI-w/2 andlI+ w/2 where w is an irreducible vector of
L~ (which
does notbelong
to10.
Oncew is
chosen,
we can scale the normal vector v of lI in order that(
vw)
= I. The limit
layer
thus contains all nodes x such that 1/2 <
(
vix)
w 1/2 and each node x has adecomposition
:x =
(
v x)
w + y(4. 1)
where y = x
(v ix)
w lies in lI for the aboveequation implies ( vi y)
= 0.Since w is a lattice vector of
L~,
themapping
definedby
x - y = x(v [x)
w maps all nodes of the limitlayer
on a 2-dimensional lattice contained in lI. This lattice issimply
theintersection of lI with the bundle of lattice lines
parallel
to w(or
theimage
ofL~ by
theoblique projector parallel
to w onto10. Moreover,
since the width of thelayer
isspecified by
the irreducible vector w, each lattice lineparallel
to w contains aunique
node inside thelayer
andconsequently
themapping
is one-to-one(see Fig. 2). Finally,
the 2-dimensional lattice thus obtained can be considered as an average lattice of the limit
layer
and thedisplacements
are boundedby
iw11 /2 andparallel
to w.The
mapping
x - y defined above is not a shear transformation since( vi w)
is different from 0.However,
for x inside the limitlayer,
thismapping
proves to beequivalent
to afractional shear transformation of the form x
- y = x + Frac
(w [x)
w which is defined asfollows :
Since w
belongs
toL~
there exists areciprocal
vector p inLfl (different
fromv),
such that(p [w)
=
I. Now we define
w = p v and we observe that :
I) (w[w)
=0.2) (w[x)
=
(p[x) -(v[x)
so that for any lattice node x ofL~
we have Frac[(w ix)]
=
Frac
[- (v[x) ].
Therefore for any lattice node x inside the limit
layer
we have Frac(w [x) ]
=
(v [x)
and
consequently
themapping
reads :y=x-
(v[x)
w=x+Frac[(w[x)]w. (4.2)
This
equation
shows that themapping
of the limitlayer
onto its average lattice isgiven by
afractional shear as defined in section 2. The shear direction is
given by
the lattice vector w and the invariantplane
isspecified by
w with the condition(w [w)
=
0 satisfied.
The definition of w
= p v is not
unique
because there areinfinitely
manyreciprocal
vectors such that
(p[w)
=
I. The
corresponding
linear shearsS~
=I +[w)(w[
aredifferent but the associated fractional shears
3~
areequal
because Frac[(w ix)
] isindependent
of p for x inL~.
Notice also that all shearsS~
transform the latticeL~
into aunique
lattice Aspanned by
w andby
the 2-dimensional average lattice of the limitlayer
so that lI is a latticeplane
of A.fl+w/2
fl-w/2
w
Fig. 2. A layer is specified by the two planes 1I w/2 and 1I + w/2 where w is an irreducible lattice
vector and His an
arbitrary
direction. The nodes (black dots) lying inside the layer have an averagelattice (white dots) in 1I on which
they
mapby
translation boundedby
ii w [[/2.
Conversely,
assume A is a lattice such that A=
SL~
for some shear S= I +
w) (w
wherew is an irreducible vector of both lattices. If lI is a lattice
plane
of A such thatw and the 2-dimensional lattice A n lI span
A,
then A n lI is the average lattice of thelayer
of
L~
boundedby
lI w/2 and lI + w/2.5. Shear factorization of a transition matrix and bounded transformations between lattices.
If
L~
is agiven
lattice andL~
is a different lattice ofequal density,
the transition matrix T=
A B cannot in
general
reduce to asimple
shear matrix even with the free choice of the bases of the lattices.Actually,
a shear matrix with rational directiononly depends
on 2independent
realparameters
whereas the set of lattices ofgiven density
is an 8-dimensional manifold. For this reason we guess that ageneral
transition matrix will beequivalent
to theproduct
of 4 different shears. Arigorous proof
isgiven
below in 3 dimensions(see [8]
for ageneral proof
in n dimensions where n + I shears prove to benecessary).
The cases where
only
one or two shears can transformL~
intoL~
are thereforeexceptional
and
correspond
toparticular pairs
of lattices as will be seen in more details in section 6. IfL~
is definedonly
up to a rotation we see that theseexceptional
cases couldpossibly point
outparticular
orientationalrelationships.
IfL~
isequal
toL~,
up to arotation,
the same conclusion holds and it can be shown that the relative orientations associated with the existence of coincidence latticescorrespond
to suchexceptional
cases[7].
In[5]
it was shown that the relative orientationsgiving
rise to icosahedral twins of cubic lattices as observed in[6], namely
2 ar/5 rotations aroundpseudo
5-foldaxis,
alsocorrespond
to transitions matriceswhich are
equivalent
to a double shear.Let T denote a real 3 x 3 matrix with determinant I. For instance T
=
A B is a transition
matrix between two lattices
L~=
AZ ~ andL~ =BZ~
ofequal density.
Then T can bedecomposed
as aproduct
of 4simple
shear transformationsSo, St,
S~ andS~.
T
=
so s~ s~ si (5.1)
' So2 So3 o o
So
= o I o S~ = o I o°
° '
31
532 with
0 0 S12 S13
S~
= s~j s23 S~ = 0 0(5.2)
o o 0 0
This statement holds for almost all matrices T.
Actually
itrequires
thefollowing
conditions :
T~i
# 0 and T~~T~i T~i
T~~ # 0. If these conditions were not met, oneeasily
checks that a
permutation
matrix P can be found such thatthey
are satisfied forT'
=
TP
(taking advantage
of the fact that det(T~
#0).
The
proof
of the factorization(5,I)
isgiven by
thefollowing algorithm.
. Find a shear matrix
So,
of the formgiven
in(5.2),
such that(So)~~
T= U satisfies
Uii
= I and
Uii
U~~Ui~ U~i
=I. This is
easily
achieved since :1) lfll
"l~ll
S021~21 S031~31~
l
~) ~fll ~22 ~12 ~21
"l~ll
1~22 1~121~21 503(1~221~31 1~21 1~32) ~ l.The second
equation gives
so~ and the rust one afterwardsgives
so~,provided
the condition mentioned above is satisfied :l~ll1~22
+ 1~121~21~~~
1~221~31 1~21 1~32 1-
Tii
+so~T~i
SW "
~m 21
. Find a shear matrix
Si
such thatU(Si )~
=
V satisfies
Vi
j =
V~~
= I andVi~
=Vi~
= 0.
These
equations
read :1) V22
"~22
S12~21
"
~) l~12
"~12
S12" °
3) ~'13
~~13
S13" °
They
are satisfiedby Uking
si~=
Ui~
and si~=
Ui~.
Now V reads :0
1
~'"
~'21 ~'23
'31
~'32 ~'33
. Find a shear matrix S~ such that
V(S~)~
=
W satisfies
W~i
= W~~ = 0 and W~~ = I.These conditions read :
1)
f~'21"
~'21
S21 ~ °~)
f~'23"
~'23
523 " °3)
f~'33 ""33
523~'32 "They
are satisfiedby taking
s~i=
V~i
and s~~ =V~~.
Now W reads :Ii
o ow= o i o.
W31
W32
. The last
step yields
a shear matrix S~ such thatW(S~)~~
=
I,
I,e. S~ =W,
so thatS31 ~ f~'31 ~tld 532 ~
~'32.
Finally
we have obtained(So)~ T(Si)~ (S~)~ (S~)~
=
I which reads :
T
=
SOS~S~SI.
The above factorization of the transition matrix T=A
~~B
shows thatany two lattices
L~
andL~
with the samedensity
areusually
relatedby
theproduct
of four sheartransformations :
Lb
~ $A,O~A,3 ~A,2~A, I
~a
with
S~,
I = AS; A
By replacing
each linear shear transformationS~,, by
thecorresponding
fractional shear
3~,
; = AZ ;A ~, as defined in section2,
we see that a bounded transform- ation fromL~
toL~
isgiven by
thecomposition
of four fractional shears :3~,
o3~,
~
3~,
~
3~,
1.
As an
example
we shall consider here the 2-dimensional case of two square lattices with a arm relative orientation.First the factorization theorem in 2 dimensions reads as follows :
If T is a 2x2 matrix with determinant
I,
there exist 3 shear transformationsSo, Si
and S~ such thatT=
SOS~SI (5.3)
where
I
oy
ioj
Isjj
~°
o 1~~
s2
~~ o
~~'~~
The
product
of these shear matrices readsSo S~ Si
=
~
~ ~°~~ ~° ~ ~~ ~ ~° ~~~(5.5)
s~ I + s~ si
The three
parameters
s~ si and s~ areeasily
derived from the entries of T(notice
however that ifT~i
=
0,
T must bereplaced
with TP where P is a convenientpermutation matrix).
If
L~
andL~
denote the two square lattices relatedby
a armrotation,
the transition matrix T issimply
the arm rotation and the above factorization reads :/jl -lj [I I-/j[
0j[1 1-/j ~~6)
~ ~~
l 0 II
fi
0According
to the definitions of section2,
thecorresponding
fractional shears aregiven by
30(x)
= x + Frac
[(I /) x~]
ei
~2(Y
" Y + Frac ~yl~
II
e2
(5.7)
Ii (z
= z + Frac
[(I /) z~]
ei
% / j~ I /~m ~ ~
j
' ~ *-w ~ *+ ~ ~a
/+m
~ ~~ d ~~m
f / ~ j
w~ , ~ ~ ~
GO
W~G*~
. OW C~ ~B
+~ ~ +~ ~ +~
~ ~ ~ /
~*Q~
~R'~
~ ~
*9e~
~
wvj~ , j--~, ~
~, ~/, ~i /,
Fig.
3. The one-to-onemapping
between the two square lattices at arm isgiven by
thecomposition
of3 successive fractional shears.
The
composition
of these threemappings
therefore mapsL~
ontoL~ (see Fig. 3)
and writes :30 3~ 30(x)
= x + Frac
[(I /) x~]
ei + Frac
[(xi
+ Frac[(
I/) x~])/ ~fi]
e~
+ Frac
[(
I/)(x~
+ Frac
[(xi
+ Frac[(
I/) x~] )/ II )]
ei
(5.8)
This formula shows that the
displacements
arealways
boundedby
iet +e~/2[[
=l12.
This transformation can also be
computed explicitly using
coordinates associated to the successivelattices,
like in section 2. As aresult,
x= xi at +x~a~ in
L~
ismapped
ontoy = yj
bi
+ y~b~
inL~
with :yj = xi Rnd
[(I /)x~]
Rnd
i(
i/) (x~
Rnd(/(x~
Rnd( (i /) x~))/2))1 (5.9)
y~ = x~ Rnd
[/ (xi
Rnd( (I /) x~) )/2]
Such a bounded one-to-one
mapping
is not obvious. At firstglance
a natural candidate forsuch a map would consist in
mapping
apoint
x ofL~
onto theorigin
y of the square ofL~
which contains x.However,
squares ofL~
may contain0,
or 2points
ofL~
so that the one- to-oneproperty
could not be satisfied.6. The double shear case.
The cases where the transition matrix
T=A~~B
between two latticesL~ =AZ~
andL~
=BZ~
is theproduct
ofonly
two shear transformations seem to be ofphysical
interest.This
algebraic property
of the transition matrices has a more intuitivemeaning
as we shall see below.Moreover,
ageometrical
characterization is welcome since the transition matricesbetween two lattices are defined up to
right
and leftmultiplication by
modular matrices(owing
tochanges
ofbases).
Let us first consider the case where T
= A B = S is a
single
shear transformation for anappropriate
choice of the structure matrices A and B. Then, asexplained
in section2,
both lattices have a common lattice vector w=
As
=
Bs and
they lay
on a common bundle of lattice lines.In Fourier space, the dual lattices
Lfl
andLf
have structure matrices A*=
(A~~)~
and B*=
(B~~)~.
If the basesla)
and16)
are such that a~ = b~ = w, like in(2.3),
thecorresponding
dual basesla *)
=
jai, at, at
and16 *)
=
16(,
b~*,b?)
are relatedby
thefollowing equations
:at
=
b? (6.1)
~~"~~+~l~l+~2~~.
All lattice
planes corresponding
toreciprocal
vectors njal
+ n~at belong
to both lattices.These
planes
are those which are builtby
means of anypair
of lattice linesparallel
tow. The dual lattices
lay
on a stack ofplanes parallel
to theplane spanned by
at
andat
and their intersectiongenerically
reduces to the 2-dimensional latticespanned by
the same basis.
The double shear case is characterized
by L~
andL~ having
structure matricesA and B such that T
= A B is the
product
of two shear matrices :~
~2 ~l (~
+'52) (~2' )(~
+'Sl) (~l )
(~ ~)
Tx= x +
(«i ix)
si +(«~[x)
s~ +(«~[sj) («~ ix)
s~where si and s~ are two different irreducible
integral
vectorsdefining
the directions of the shears in the space of indices. The invariantplanes
are definedby
«~ and «~ andsatisfy
(«~[s~)
=
(«~[s~)
=
0.
Since A B
=
S~ St,
we may define the structure matrix r= AS
~ = BS
p
of a new lattice A=
rZ~.
A isa
simple
shear deformation of bothL~
andL~
and can be considered as anintermediate lattice between them: if
S~=AS2A~'
andS~=BSi~B~'
we haver
=
S~A
=S~
B so that A=
S~ L~
=S~ L~.
These shears areexplicitly given by
:s~
= I +jw~j jw~j
~ ~
s~
= i +
iw~i iw~i
with w~ = As
z, w~ =
(A
~)~ «~, w~=
Bsi
and w~ =(B~
~)~ «~.Now, using
the above relations we see that :rsi
= AS
~ si =
As1
+(«~[si) As~
=
BSj
si=
Bsi
= w~
(6.4) rs~
= AS~s~ =
As~
= BSj
s~ =Bs~ (« ii s~) Bsi
= w~.
Consequently
the threepairs
of vectors(rsj, rs~)
inA, (As1, As2)
inL~
and(Bsj, Bs2)
inL~
span the same latticeplane
W which thereforebelongs
to the three lattices. W is invariantwith
respect
to both shears S~ andS~
since the directions of the shears w~ and w~ are in W. ThereforeL~, L~
and Alay
on a common stack of latticeplanes parallel
to W.Finally,
the double shearSp
'S~ which mapsL~
ontoL~
transforms thepoints by
translationsparallel
to W.In Fourier space, the existence of a common sequence of lattice
planes implies
that thereciprocal
lattices ofL~
andL~
have a I-dimensional intersectionspanned by
areciprocal
vector w
orthogonal
to W. The Miller indices ofw are
proportional
to sj x s~(and equal
if this vector isirreducible). Actually,
the dual latticesLfl
andLt
haverespective
structure matrices A*=
(A
~)~ and B*=
(B~
~)~ whichsatisfy B*~~A*
=
T~=
(I
+i«i) isii)(I +1«2)iS21),
therefore si x s~ is invariant
by
T~ and A* si x s~=
B* si x s~
belongs
to bothreciprocal
lattices.
7. Interfaces and smooth transitions in the double shear case.
An ideal
planar
interface between two latticesL~
andL~
is definedby
5parameters
: two of themspecify
the orientation of the interfaceplane
and the othersgive
the relative translationbetween the lattices. The double shear case has
interesting
consequences withregards
to thedescription
ofpossible
interfacesplanes
betweenL~
andL~.
Moreprecisely
we show now that in this situationpa~icular
interface orientations arepointed
out forsimple geometric
reasons.Assume His a lattice
plane
of the intermediate lattice A defined in the above section which satisfies thefollowing
conditions : w~ and A n lI spanA,
andsimilarly
w~ and A n lI span A(see below).
We consider thelayer
ofL~
boundedby
lIwJ2
and lI +wJ2
and thelayer
of
L~
boundedby
lI-w/2
and lI+x/2.
NOW these two
layers
have the same averagelattice, namely
the 2-dimensional latticeA n lI. This
actually
follows from the construction of average lattices oflayers explained
at the end of section 4.More
precisely,
the fractional shear3~
which maps theL~
nodeslying
between lI-wJ2
and lI+wJ2
on theplane
lI isgiven by
:3~(x)
= x + Frac
[(w~[x)
w~(7,1)
3~
maps the nodes of limitlayer
ofL~
onto the 2-dimensional average lattice A n lI.Similarly,
the fractional shear associated toS~
isgiven by
:3~(x)
= x + Frac
[(w~[x)
w~(7.2)
3~
maps the nodes of limitlayer
ofL~
onto the same 2-dimensional lattice A n lI(see Fig. 4).
The condition
bearing
on theplanes lI,
mentioned at thebeginning
of thissection, requires
that the 2-dimensional lattice An lI spans A with both irreducible vectors w~ or
w~. Therefore if
v is the
reciprocal
vector of A* associated to lI we must have~~' ~a)
~ ~ ~'~~
~~' ~b)
" ~ ~.
~ o o
~ o
~ o °
~ o
~ o
~ o
~ o
~ o
~ o o
~ o °
~ o °
a
~ o o
~ o
~ o °
~ o ~ a a
~ o o
o o °
~ o °
a D a
~ o o
o o °
~ o °
a a a a
~ o
~ o °
~ o D a a a D D
~ o
~ o
o o D D a D a a a a
o o
o o °
a a a a a a a a a
o o
'I
a D a D D D a a a aa D D a D D a D a a a a
a D D D a D D a D D D D a
Fig.
4. The limitlayers
of L~ and L~ arcparallel
to a latticeplane
of the intermediate lattice A.They
have the same average lattice on whichthey
mapby simple displacements
of constant directionand bounded
amplitude.
Finally
the double shear case is characterizedby
thefollowing prope~ies
:I) L~
andL~
have a common latticeplane
Wspanned by respective
bases(As
i,
As~)
and(Bsi, Bs~)
such thatBsj
=
As i +
r~AS~
andAs~
=
Bs~
+ riAsi
with si and s~ inZ~,
andri, r~ real numbers