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On Convergence of Non-Monotone Series. A Letter.

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HAL Id: hal-00708999

https://hal.archives-ouvertes.fr/hal-00708999

Preprint submitted on 16 Jun 2012

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On Convergence of Non-Monotone Series. A Letter.

Jyothiniranjan Pillay

To cite this version:

Jyothiniranjan Pillay. On Convergence of Non-Monotone Series. A Letter.. 2007. �hal-00708999�

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On Convergence of Non-Monotone Series.

A Letter.

J.I. Pillay

———————————————————————————————————

Abstract

We hope to bring to a close the analyses of the convergence of real valued series of the form Σf(n)|n∈N for differentiable functions, via the introduction of a theorem as a necessary condition for convergence of such series regardless of the nature off.

———————————————————————————————————

Introduction

The difficulties surrounding the analysis of fourier series for the purpose of es- tablishing everywhere convergent functions has been expressed in a recent paper by SV. Konyagin[1]. Many techniques used in the establishment of convergence are specific to monotone convergent series, as such convergence is difficult to establish in Fourier series. We introduce a new technique for use in such cases.

1. Convergence Theorem 1.1.

The series

1

f(n)|n∈N is convergent if and only if the integral

h→∞Lim

h

1

xf(x)dx converges.

Proof

A necessary condition for a series of the form

1

f(n) to be convergent is that

h→∞Limf(h) = 0.1Using the property stated, we have that

c

f(x)dx=f(c). From this, we may re write

1

f(n) as

c=1

c

f(x)dx. From the summation, it is easy to see that over every interval of one starting at one, the integrals arenA(n) where n is the nth interval of length one beginning at one and A(n) =

n+1

n

f(x)dx.

1For an oscillating nonconvergent series, we may subtractkfrom the integrals that follow in our proof, wherekis the limit of the function in concern.

1

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We note now that{n∩x} =N, thus ∑

∀n

nA(n) is approximately

1

xf(x)dx.

The difference between the two is smaller than

1

f(x)dx, since the sum of the difference between the upper and lower bound integrals∑

∀n n+1

n

f(x)dxand

∀n n+2

n+1

f(x)dx, is :

1

f(x)dx. Finally since

1

f(x)dx=f(1), this integral is always convergent and as such will not influence the behaviour of

1

xf(x)dx.

Figure 1:

2

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References.

[1] SV. Konyagin. Almost everywhere convergence and divergence of Fourier series. Proceedings of the international congress of mathematics,Madrid,Spain.

(2006).

3

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