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ANNALES DE

L’INSTITUT FOURIER

LesAnnales de l’institut Fouriersont membres du

Daciberg Lima Gonçalves, John Guaschi & Oscar Ocampo Embeddings of finite groups inBnk(Pn)fork= 2,3 Tome 70, no5 (2020), p. 2005-2025.

<http://aif.centre-mersenne.org/item/AIF_2020__70_5_2005_0>

© Association des Annales de l’institut Fourier, 2020, Certains droits réservés.

Cet article est mis à disposition selon les termes de la licence Creative Commons attribution – pas de modification 3.0 France.

http://creativecommons.org/licenses/by-nd/3.0/fr/

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EMBEDDINGS OF FINITE GROUPS IN B

n

k

(P

n

) FOR k = 2, 3

by Daciberg LIMA GONÇALVES, John GUASCHI & Oscar OCAMPO

Abstract. —Letn> 3 andk∈ {2,3}. We study the embedding of a given finite groupGin the quotientBnk(Pn), whereBnis thenthArtin braid group, l(Pn)}l∈N is the lower central series of thenth pure braid group Pn, and |G|

denotes the order ofG. If such an embedding exists, it is known that gcd(|G|, k!) = 1. In this paper, we show that if Gis a finite group for which gcd(|G|, k!) = 1, thenGembeds intoB|G|k(P|G|). Ifk= 2, the result was proved independently by Beck and Marin. IfG=ZproθZd, where the actionθis injective,pis an odd prime,p>5 ifk= 3, andddividesp1 and satisfies gcd(d, k!) = 1, we show that Gembeds intoBprk(Ppr). Ifk= 2, this is a special case of another result of Beck and Marin. We also construct explicit embeddings inB92(P9) of the two non-Abelian groups of order 27.

Résumé. —Soientn>3 etk∈ {2,3}. Nous étudions le plongement d’un groupe fini donnéGdans le quotientBnk(Pn), oùBnest lenegroupe de tresses d’Artin, l(Pn)}l∈Nest la série centrale descendante dunegroupe de tresses puresPn, et

|G|désigne l’ordre deG. Si un tel plongement existe, on sait que pgcd(|G|, k!) = 1.

Si Gest un groupe fini pour lequel pgcd(|G|, k!) = 1, nous montrons dans cet article queGse plonge dansB|G|k(P|G|). Sik= 2, ce résultat a été démontré indépendamment par Beck et Marin. SiG=ZproθZd, où l’actionθest injective, p est un nombre premier impair, p > 5 si k = 3, et d divise p1 et vérifie pgcd(d, k!) = 1, nous montrons queG se plonge dansBprk(Ppr). Si k = 2, c’est un cas particulier d’un autre résultat de Beck et Marin. Nous construisons également des plongements explicites des deux groupes non-abéliens d’ordre 27 dansB92(P9).

1. Introduction

If n∈N, let Bn denote the (Artin) braid group on nstrings. It is well known that Bn admits a presentation with generators σ1, . . . , σn−1 that

Keywords:Braid groups, quotients, embedding of finite groups.

2020Mathematics Subject Classification:20F36, 20F18, 20F14, 20B35, 16S34.

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are subject to the relationsσiσj =σjσi for all 16i < j6n−1 for which

|i−j|>2, andσiσi+1σi=σi+1σiσi+1for all 16i6n−2. Letσ: BnSn

denote the surjective homomorphism onto the symmetric groupSndefined byσ(σi) = (i, i+ 1) for all 16i6n−1. Thepure braid group Pn onn strings is defined to be the kernel ofσ, from which we obtain the following short exact sequence:

(1.1) 1→PnBn

σ Sn→1.

IfG is a group, recall that its lower central series {Γk(G)}k∈N is defined by Γ1(G) =G, and Γk(G) = [Γk−1(G), G] for all k>2 (if H and K are subgroups of G, [H, K] is defined to be the subgroup of G generated by the commutators of the form [h, k] =hkh−1k−1, wherehH andkK).

Note that Γ2(G) is the commutator subgroup of G, and that Γk(G) is a normal subgroup ofGfor all k∈N. In our setting, sincePn is normal in Bn, it follows that Γk(Pn) is also normal in Bn, and the extension (1.1) induces the following short exact sequence:

(1.2) 1→Pnk(Pn)→Bnk(Pn)→σ Sn →1,

obtained by taking the quotient ofPn andBn by Γk(Pn). It follows from results of Falk and Randell [3] and Kohno [7] that the kernel of (1.2) is tor- sion free (see Proposition 2.1 for more information). The quotient groups of the formBnk(Pn) have been the focus of several recent papers. First, the quotientBn2(Pn) belongs to a family of groups known asenhanced symmetric groups[8, page 201] that were analysed in [11]. Secondly, in their study of pseudo-symmetric braided categories, Panaite and Staic showed that this quotient is isomorphic to the quotient ofBnby the normal closure of the set

σiσ−1i+1σiσ−1i+1σiσi−1+1i= 1,2, . . . , n−2 [10]. Thirdly, in [4], we showed that Bn2(Pn) is a crystallographic group, and that up to iso- morphism, its finite Abelian subgroups are the Abelian subgroups ofSn of odd order. In particular, the torsion ofBn2(Pn) is the odd torsion ofSn. We also gave an explicit embedding inB72(P7) of the Frobenius group Z7o Z3 of order 21, which is the smallest finite non-Abelian group of odd order. As far as we know, this is the first example of a finite non-Abelian group that embeds in a quotient of the formBn2(Pn). Almost all of the results of [4] were subsequently extended to the generalised braid groups associated to an arbitrary complex reflection group by Marin [9]. Ifp >3 is a prime number for which p≡3 mod 4, he showed that the Frobenius groupZpo Z(p−1)/2embeds inBp2(Pp). Observe that this group cannot be embedded inBn2(Pn) for any n < p, since Zp cannot be embedded inSn in this case. In another direction, the authors studied some aspects

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of the quotientBnk(Pn) for alln, k>3, and proved that it is an almost- crystallographic group [5]. For the casek= 3, it was shown that the torsion ofBn3(Pn) is the torsion ofSnthat is relatively prime with 6. For future reference, we summarise some of these results in the following theorem.

Theorem 1.1 ([4, Corollary 4], [5, Theorems 2 and 3]). — Letn>3.

(a) The torsion of the quotientBn2(Pn)is equal to the odd torsion ofSn.

(b) The groupBn3(Pn)has no elements of order2or3, and ifm∈N is relatively prime with 6 then Bn3(Pn) possesses elements of ordermif and only ifSn does.

Almost nothing is known about the torsion and the finite subgroups of Bnk(Pn) in the case wherek >3.

Suppose that n>3 andk>2. The results of [4, 5, 9] lead to a number of interesting problems involving the quotientsBnk(Pn). Given a finite groupG, a natural question in our setting is whether it can be embedded in some Bnk(Pn). In order to formulate some of these problems, we introduce the following notation. Let|G| denote the order ofG, letm(G) denote the least positive integerr for which G embeds in the symmetric group Sr, and if k > 2, let `k(G) denote the least positive integer s, if such an integer exists, for whichG embeds in the group Bsk(Ps). The integer `k(G) is not always defined. For example, if G is of even order, Theorem 1.1(a) implies thatGdoes not embed in any group of the form Bnk(Pn). However, if`k(G) is defined, thenm(G)6`k(G) using (1.2) and the fact thatPnk(Pn) is torsion free.

The main aim of this paper is to study the embedding of finite groups in the two quotientsBnk(Pn), wherek∈ {2,3}. In Section 2, we start by recalling some results from [4, 5] about the action ofSn on certain bases of the free Abelian groupsPn2(Pn) and Γ2(Pn)/Γ3(Pn), which we use to obtain information about the cycle structure of elements ofSn that fix elements of these bases. In Proposition 2.3, using cohomological arguments, we show that a short exact sequence splits if its quotient is a finite groupG and its kernel is a freeZ[G]-module. This provides a fundamental tool for embeddingGin our quotients. In Section 3, we prove the following result.

Theorem 1.2. — LetGbe a finite group, and letk∈ {2,3}. Then the groupGembeds inB|G|k(P|G|)if and only if gcd(|G|, k!) = 1.

The statement of Theorem 1.2 has been proved independently by Beck and Marin in the casek= 2 [1] using different methods within the setting of real reflection groups. This result may be viewed as a Cayley-type result

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for Bnk(Pn) since the proof makes use of the embedding of G in the symmetric group S|G|, as well as Proposition 3.1 that provides sufficient conditions on the fixed points in the image of an embedding ofGinSmfor Gto embed inBnk(Pn). If gcd(|G|, k!) = 1, it follows from this theorem that`k(G)6|G|by Theorem 1.2, from which we obtain:

(1.3) m(G)6`k(G)6|G|.

The analysis of the inequalities of (1.3) is itself an interesting problem.

Using Theorem 1.1, ifGis a cyclic group of prime order at least 5 andk is equal to either 2 or 3 then m(G) = `k(G) = |G|. In [1, Corollary 13], Beck and Marin show that m(G) = `2(G) for any finite group of odd order in a broader setting. This result may also be obtained by applying [1, Corollary 7] to [4, Corollary 4 and its proof]. We do not currently know whether there exist groups for whichm(G)< `3(G).

In Section 4, we study the embedding of certain finite groups in the quotientBnk(Pn), where k ∈ {2,3}. In the casek = 2, our results are special cases of [1, Corollary 13], but the methods that we use are rather different from those of [1], and they are also valid for the casek = 3. In Section 4.1, we consider certain semi-direct products of the formZnoθZm

for which the actionθis injective, and we analyse their possible embedding inBnk(Pn). Our main result in this direction is the following.

Theorem 1.3. — Letm, n>3, letG=ZnoθZm, whereθ: Zm→Znis the associated action, and let16t < nbe such thatθ(1m)is multiplication bytinZn. Assume thatgcd(tl−1, n) = 1for all16l6m−1. Ifmnis odd (resp.gcd(mn,6) = 1) thenGembeds inBn2(Pn)(resp. inBn3(Pn)).

Using Lemma 4.2(a), we remark that the hypotheses of Theorem 1.3 imply that the actionθ: Zm→Aut (Zn) is injective. As an application of this theorem, we obtain the following corollary.

Corollary 1.4. — Letpbe an odd prime, letp−1 = 2jd, where dis odd, letd1 be a divisor ofd, and letGbe a group of the formZproθZd1, whereθ: Zd1→Aut (Zpr)is injective.

(a) Ifp>3thenGembeds inBpr2(Ppr).

(b) Ifp>5andd1satisfiesgcd(d1,3) = 1thenGembeds inBpr3(Ppr).

Since the group Zpr cannot be embedded in Sm for any m < pr, the groups of Corollary 1.4 satisfym(G) = `k(G) = pr, where k ∈ {2,3}, so the results of this corollary are sharp in this sense, and are coherent with those of [1, Corollary 13] in the casek= 2. Further, the groups that appear in [9, Corollary 3.11] correspond to the case wherer= 1,p≡3 mod 4, and

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d1 = (p−1)/2 is odd. Hence Corollary 1.4 generalises Marin’s result to the case where p is any odd prime and d1 is the greatest odd divisor of p−1, and more generally, in the casek= 2, the family of groups obtained in Theorem 1.3 extends even further that of the Frobenius groups of [9, Corollary 3.11].

At the end of the paper, in Section 4.2, we give explicit embeddings of the two non-Abelian groups of order 27 in B92(P9). Neither of these groups satisfies the hypotheses of Theorem 1.3. The fact that they embed inB92(P9) follows from the more general result of [1, Corollary 13], but our approach is different to that of [1]. Within our framework, it is natural to study these two groups, first because with the exception of the Frobenius group of order 21 analysed in [4], they are the smallest non-Abelian groups of odd order, and secondly because they are of order 27, so are related to the discussion in Section 4.1 on groups whose order is a prime power. The direct embedding of these groups inB92(P9) is computationally difficult due to the fact that the kernelP92(P9) of (1.2) is of rank 36, but we get round this problem by first considering an embedding in a quotient where the corresponding kernel is free Abelian of rank 9, and then by applying Proposition 2.3. We believe that this technique will prove to be useful for other groups.

If n>3, it follows from [1, Corollary 13] that the isomorphism classes of the finite subgroups of Bn2(Pn) are in bijection with those of the subgroups ofSn of odd order. The study of the finite non-cyclic subgroups ofBn3(Pn) constitutes work in progress.

Acknowledgements

The work on this paper took place during several visits to the Departa- mento de Matemática, Universidade Federal de Bahia, the Departamento de Matemática do IME – Universidade de São Paulo and to the Labora- toire de Mathématiques Nicolas Oresme UMR CNRS 6139, Université de Caen Normandie. The first and the third authors were partially supported by the FAPESP Projeto Temático “Topologia Algébrica, Geométrica e Diferencial” 2016/24707-4 (Brazil), and the first two authors were par- tially supported by the CNRS/FAPESP PRC project no 275209 (France) and no2016/50354-1 (Brazil). The third author was initially supported by a project grant no151161/2013-5 from CNPq. We would also like to thank Vincent Beck and Ivan Marin for sharing their results with us.

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2. Preliminaries

In this section, we recall several results concerning the torsion of the groupsBnk(Pn), wherek∈ {2,3}, as well as some group-cohomological facts from [2] that will be used in this paper. We first state the following result from [5] that we will require.

Proposition 2.1 ([5, Lemma 11]).

(a) Letn, k>2. Then the groupPnk(Pn)is torsion free.

(b) Letn>3, letk>l>1, and letGbe a finite group. IfBnk(Pn) possesses a (normal) subgroup isomorphic to G then Bnl(Pn) possesses a (normal) subgroup isomorphic toG. In particular, ifp is prime, and ifBnl(Pn)has nop-torsion thenBnk(Pn)has no p-torsion.

Note that the first part of Proposition 2.1 follows from papers by Falk and Randell [3, Theorem 4.2] and Kohno [7, Theorem 4.5] who proved inde- pendently that for alln>2 andk>1, the group Γk(Pn)/Γk+1(Pn) is free Abelian of finite rank, the rank being related to the Poincaré polynomial of certain hyperplane complements.

It is well known that a set of generators for Pn is given by the set {Ai,j}16i<j6n [6]. If j > i then we take Aj,i = Ai,j. By abuse of nota- tion, fork>2 and 16i < j6n, we also denote the image ofAi,j under the canonical projectionPnPnk(Pn) byAi,j. The groupsPn2(Pn) and Γ2(Pn)/Γ3(Pn) are free Abelian groups of finite rankn(n−1)/2 and n(n−1)(n−2)/6 respectively [3, Theorem 4.2]. By [4, Section 3, p. 399]

(resp. [5, equation (17)]), a basis forPn2(Pn) (resp. Γ2(Pn)/Γ3(Pn)) is given by:

(2.1) B={Ai,j|16i < j6n}(resp. byB0={αi,j,k|16i < j < k6n}), whereαi,j,k= [Ai,j, Aj,k]. The action by conjugacy ofBn2(Pn) (resp. of Bn3(Pn)) on Pn2(Pn) (resp. onPn3(Pn)) is defined in [4, Propo- sition 12] (resp. in [5, equation (8)]), and induces an action of Sn on Pn2(Pn) (resp. on Γ2(Pn)/Γ3(Pn)) that we now describe. If τSn, Ai,j ∈ Band αi,j,k ∈ B0 then by [4, Proposition 12] and [5, equation (8)], we have:

(2.2)

(τ·Ai,j=Aτ−1(i),τ−1(j)and

τ·αi,j,k=τ·[Ai,j, Aj,k] = [Aτ−1(i)−1(j), Aτ−1(j)−1(k)].

The following lemma implies thatSn acts on BandBb0 respectively, where b

B0=B0∪ B0−1. In each case, the nature of the action gives rise by linearity

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to an action ofSn on the whole group. We also obtain some information about the stabilisers of the elements ofB andBb0. This will play a crucial role in the proof of Proposition 3.1.

Lemma 2.2. — Letn>2, and letτSn.

(a) Let Ai,j be an element of the basis B of Pn2(Pn), where 1 6 i < j 6n. Then the elementτ·Ai,j given by the action ofSn on Pn2(Pn) belongs toB. Further, if τ·Ai,j =Ai,j then the cycle decomposition ofτ either contains a transposition, or at least two fixed elements.

(b) Letαi,j,k be an element of the basis B0 of Γ2(Pn)/Γ3(Pn), where 1 6 i < j < k 6 n. Then the element τ ·αi,j,k given by the action ofSnonΓ2(Pn)/Γ3(Pn)belongs toBb0. Further, ifτ·αi,j,kαi,j,k, α−1i,j,k then the cycle decomposition ofτ contains either a transposition, or a3-cycle, or at least three fixed elements.

Proof.

(a). — The first part follows from (2.2). If 16i < j6n and τSn

are such that τ·Ai,j =Ai,j then τ({i, j}) = {τ(i), τ(j)} ={i, j}, which implies the second part of the statement.

(b). — The first part is a consequence of [5, equation (16)]. Now suppose thatτ·αi,j,k

αi,j,k, α−1i,j,k , where 16i < j < k6nandτSn. By [5, equation (18)], we have τ({i, j, k}) = {τ(i), τ(j), τ(k)} = {i, j, k}, from

which we deduce the second part.

Lemma 2.2 implies that if G = Sn then B and Bb0 are G-sets, and the action ofGon each of these sets extends to a Z-linear action ofGon the freeZ-modulesZBandZB0 respectively, with respect to the embedding of

b

B0 in ZB0 given byαi,j,k 7−→ αi,j,k and α−1i,j,k 7−→(−1). αi,j,k, the under- lying free Abelian groups being naturally identified with Pn2(Pn) and Γ2(Pn)/Γ3(Pn) respectively. It follows thatPn2(Pn) and Γ2(Pn)/Γ3(Pn) each admit aG-module structure inherited from the action ofSn onBand Bb0 respectively.

Given a groupG, letZ[G] denote its group ring. The underlying Abelian group, also denoted by Z[G], may be regarded as a Z[G]-module (or as a G-module) via the multiplication in the ring Z[G] (see [2, Chapter I, Sections 2 and 3] for more details), namely:

(2.3) g·

Xm i=1

nigi= Xm i=1

ni(ggi)

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for all m∈ N, g, g1, . . . , gmG and n1, . . . , nm ∈ Z. The cohomology of the groupGwith coefficients inZ[G] regarded as aG-module is well under- stood. In the case thatGis finite, we have the following result concerning its embedding in certain extensions whose kernel is a free Z[G]-module.

First recall that ifM is an Abelian group that fits into an extension of the following form:

(2.4) 1→MEG→1,

thenM is also aZ[G]-module, the action being given by (2.4).

Proposition 2.3. — LetGbe a finite group. Given an extension of the form (2.4), suppose that M is a free Z[G]-module. Then the short exact sequence (2.4) splits. In particular, G embeds in E as a subgroup, and the restriction of the projectionEGto the embedded copy of Gis an isomorphism.

Proof. — First suppose thatM ∼=Z[G]. By [2, equation 6.5, p. 73], the groupH(G,Z[G]) is trivial for all ∗>1. In particular, H2(G,Z[G]) = 0, which implies that any extension of the form (2.4) withM =Z[G] is split [2, Chapter IV, Theorem 3.12], where the action of the quotient on the kernel turnsZ[G] into a Z[G]-module that is isomorphic to the one-dimensional freeZ[G]-module. Now suppose that M is an arbitrary free Z[G]-module whose Z[G]-module structure is defined by (2.4). So M ∼= ⊕JZ[G] as a Z[G]-module for some setJ, and:

H2(G, M)∼=H2

G,M

J

Z[G]

∼=M

J

H2(G,Z[G]) = 0

by the first part of the proof. The short exact sequence (2.4) splits as in

the caseM ∼=Z[G].

3. Cayley-type results for subgroups of Bnk(Pn), k= 2,3 Letk∈ {2,3}. In this section, we prove Theorem 1.2 that may be viewed as an analogue of Cayley’s theorem forBnk(Pn). The following proposi- tion will be crucial in the proofs of Theorems 1.2 and 1.3.

Proposition 3.1. — Letk∈ {2,3}, letGbe a finite group whose order is relatively prime withk!, letm>3, and letϕ: GSmbe an embedding.

Assume that for allgG\ {e}, ϕ(g)fixes at most k−1 elements. Then the groupGembeds inBmk(Pm).

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Proof. — Assume first thatk= 2, so|G| is odd. LetGe be the (isomor- phic) image ofGbyϕinSm. Taking the inverse image byσof Gein (1.2) withn=m andk= 2 gives rise to the following short exact sequence:

(3.1) 1→Pm2(Pm)→σ−1(G)e −−−−−−→σ|σ1(G)e Ge→1.

From Section 2,G, and henceG, acts on the free Abelian groupe Pm2(Pm) of rankm(m−1)/2, and the restriction of this action to the basisBis given by (2.2). Let 16i < j6m, and letgGbe such thatϕ(g)·Ai,j=Ai,j. Since|G|is odd, the cycle decomposition ofϕ(g) contains no transposition, and by Lemma 2.2(a) and the hypothesis on the fixed points ofϕ(g), we see thatg=e. So for all 16i < j6m, the orbit ofAi,j contains exactly |G|

elements. In particular,|G|dividesm(m−1)/2, andBmay be decomposed as the disjoint union of the form `m(m−1)/2|G|

k=1 Ok, where each Ok is an orbit of length|G|. Fork= 1, . . . , m(m−1)/2|G|, letek ∈ Ok, and letHk

denote the subgroup ofPm2(Pm) generated byOk. ThenPm2(Pm)∼= Lm(m−1)/2|G|

k=1 Hk, and for allx∈ Ok, there exists a unique elementgG such that ϕ(g)·ek = x. Thus the map that to x associates g defines a bijection betweenOk and G. Since Ok is a basis of Hk, if hHk, there exists a unique family of integers{qg}gG such thath=Q

gG(ϕ(g)·ek)qg, and the map Φ: Hk→Z[G] defined by Φ(h) =P

gGqggmay be seen to be an isomorphism. Further, via Φ, the action ofGonHk corresponds to the usual action ofGonZ[G]. More precisely, ifγG, then:

Φ(ϕ(γ)·h) = Φ ϕ(γ)· Y

gG

(ϕ(g)·ek)qg

!

= Φ Y

gG

(ϕ(γg)·ek)qg

!

=X

gG

qgγg=γ·Φ(h),

the action ofγ on Φ(h) being given by (2.3). HencePm2(Pm) is isomor- phic toLm(m−1)/2|G|

1 Z[G] as Z[G]-modules, and by Proposition 2.3, we conclude that the extension (3.1) splits. ThusGis isomorphic to a subgroup Gbof σ−1(G), which in turn is a subgroup ofe Bm2(Pm), and this proves the result in the casek= 2. Now suppose thatk= 3. Since gcd(|G|,6) = 1,

|G|is odd, and as above,Gis isomorphic to the subgroupGbofBm2(Pm).

Consider the following extension:

1→Γ2(Pm)/Γ3(Pm)→Bm3(Pm)→ρ Bm2(Pm)→1,

whereρ: Bm3(Pm)→Bm2(Pm) denotes the canonical projection. Tak- ing the inverse image of Gb by ρ gives rise to the following short exact

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sequence:

(3.2) 1→Γ2(Pm)/Γ3(Pm)→ρ−1(G)b −−−−−→ρ|ρ1(bG) Gb→1.

Let ϕ0: Gb→Sm denote the embedding of Gb in Sm given by compos- ing ϕ by an isomorphism between Gb and G. Then Gb acts on the kernel Γ2(Pm)/Γ3(Pm) of (3.2) via (2.2). Since gcd( eG,6) = 1, for allbgGb\ {e}, the cycle decomposition of ϕ0(bg) contains neither a transposition nor a 3-cycle, and by hypothesis, ϕ0(bg) contains at most 2 fixed elements. It follows from Lemma 2.2(b) that if ϕ0(bg)·αi,j,k

αi,j,k, α−1i,j,k , where 16i < j < k6nandbgG, thenb bg=e. In particular, the orbits ofαi,j,k

andα−1i,j,k are disjoint, every orbit contains exactly|G|elements, and thus

|G| dividesm(m−1)(m−2)/6. So there exists a basis of Γ2(Pm)/Γ3(Pm) that is the disjoint union ofm(m−1)(m−2)/6|G| orbits of elements of

b

B0, and that for all 1 6 i < j < k 6 n, contains exactly one element of

αi,j,k, α−1i,j,k . As in the case k= 2, we conclude that the short exact sequence (3.2) splits, and thatGembeds inBm3(Pm).

Remark 3.2. — An efficient way to use Proposition 3.1 is as follows.

Let ϕ: GSn be an embedding, and for an order-preserving inclusion ι: {1,2, . . . , m} ,−→ {1,2, . . . , n}, where m < n, consider the embedding SmSn. Suppose that the homomorphism ϕ factors through Sm, and letϕ0: GSm be the factorisation. It may happen that the hypotheses of Proposition 3.1 hold for ϕ0 but not for ϕ. In this case, we may apply this proposition toϕ0 to conclude the existence of an embedding of Gin Bmk(Pm), which in turn implies thatGembeds inBnk(Pn).

We are now able to prove Theorem 1.2.

Proof of Theorem 1.2. — Let G be a finite group, and let k ∈ {2,3}. If G embeds in the group B|G|k(P|G|) then Theorem 1.1 implies that gcd(|G|, k!) = 1. Conversely, suppose that gcd(|G|, k!) = 1. Consider the classical embedding ofGinS|G|that is used in the proof of Cayley’s theo- rem (note that we identifySGwithS|G|). More precisely, letψ: G×GG denote the action ofGon itself given by left multiplication. For allgG, the mapψg: GGdefined by ψg(h) =ψ(g, h) =ghis a permutation of G, and the map Ψ: GS|G| defined by Ψ(g) =ψg is an injective homo- morphism, so Ge = {ψg|gG} is a subgroup of S|G| that is isomorphic toG. The action ψ is free: ifhG then h=ψg(h) if and only if g =e.

In particular, ifg 6=e thenψg is fixed-point free, and so the permutation Ψ(g) is fixed-point free for allgG\ {e}. Takingm=|G|, the hypotheses of Proposition 3.1 are satisfied for the embedding Ψ: GS|G|, and we conclude thatGembeds inB|G|k(P|G|).

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4. Embeddings of some semi-direct products in Bnk(Pn), k∈ {2,3}

Let m, n ∈ N, and let k ∈ {2,3}. In this section, we study the prob- lem of embedding groups of the formZnoθZmin Bnk(Pn), where the representationθ: Zm→Aut (Zn) is taken to be injective. With additional conditions onθ, in Section 4.1, we prove Theorem 1.3. In Section 4.2, we study the two non-Abelian groups of order 27. The first such group is of the formZnoθZm, where θ is injective, but the additional conditions of Theorem 1.3 are not satisfied. The second such group is not of the form ZnoθZm. We prove that both of these groups embed in B92(P9). In the case of the first group, this shows that the hypotheses of Theorem 1.3 are sufficient to embedZnoθZm in Bnk(Pn), but not necessary. With respect to (1.3), these groups also satisfym(G) = `k(G) < |G|, which is coherent with [1, Corollary 13] in the casek= 2.

4.1. Proof of Theorem 1.3

Letm, n∈N. In this section,Gwill be a group of the formZnoθZm. We study the question of whetherGembeds inBnk(Pn), where k∈ {2,3}.

By Theorem 1.1, when G = ZnoθZm for such an embedding to exist, gcd(|G|, k!) = 1, and so we shall assume from now on that this is the case. In order to apply Proposition 3.1, we will make use of a specific embedding ofGinSn studied by Marin in the case wheren is prime and m= (n−1)/2 [9], as well as the restriction to Gof the action of Sn on Pn2(Pn) and Γ2(Pn)/Γ3(Pn) described by equation (2.2). If q ∈ N, we will denote the image of an integerrunder the canonical projectionZ→Zq

byrq, or simply byrif no confusion is possible.

Following [9, proof of Corollary 3.11], we start by describing a homomor- phism from K to SA, for groups of the form K =AoθH, where A and H are finite, A is Abelian, and SA denotes the symmetric group on the set A. Let (u, v)K, where the elements of K are written with respect to the semi-direct product AoθH, and let ϕ(u,v): AA be the affine transformation defined by:

(4.1) ϕ(u,v)(z) =θ(v)(z) +ufor allzA.

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Lemma 4.1.

(a) For all (u, v) ∈ K, the map ϕ(u,v): AA defined in (4.1) is a bijection.

(b) Let ϕ: KSA be the map defined by ϕ(u, v) = ϕ(u,v) for all (u, v) ∈ K. Then ϕ is a homomorphism. Further, if the action θ: H →Aut (A)is injective then ϕis too.

Proof.

(a). — If (u, v)∈K, the statement follows from the fact thatθ(v) is an automorphism ofA.

(b). — Part (a) implies that the map ϕis well defined. We now prove thatϕis a homomorphism. If (u1, v1),(u2, v2)∈K, then for allzA, we have:

(u2,v2)ϕ(u1,v1))(z) =ϕ(u2,v2)(θ(v1)(z) +u1)

=θ(v2)(θ(v1)(z) +u1) +u2

=θ(v2)(θ(v1)(z)) +θ(v2)(u1) +u2

=θ(v2v1)(z) +θ(v2)(u1) +u2

=ϕ(u2+θ(v2)(u1),v2v1)(z)

=ϕ(u2,v2)(u1,v1)(z),

so ϕ(u2,v2)ϕ(u1,v1) =ϕ(u2,v2)(u1,v1), and ϕ is a homomorphism. Finally, suppose thatθis injective, and let (u, v)∈Ker (ϕ). Thenz=ϕ(u, v)(z) = ϕ(u,v)(z) = θ(v)(z) +ufor all zA. Taking z to be the trivial element eA of A yields u = eA. Hence θ(v) = IdA, and it follows that v is the trivial elementH by the injectivity ofθ, which completes the proof of the

lemma.

As above, let G be a semi-direct product of the formZnoθZm, where θ: Zm→Aut (Zn) is the associated action. Note that we can apply the construction of equation (4.1) toG, and so the conclusions of Lemma 4.1 hold forG. The element 1mgenerates the additive groupZm, soθ(1m) is an automorphism ofZn whose order dividesm, and since any automorphism ofZn is multiplication by an integer that is relatively prime withn, there exists 1 6 t < n such that gcd(t, n) = 1, θ(1m) is multiplication by t, andtm ≡1 modn. If θ is injective, the order of the automorphism θ(1m) is equal tom, and so tl 6≡1 modn for all 1 6l < m, but this does not imply that tl−1 is relatively prime with n. However, the condition that gcd(tl−1, n) = 1 for all 16l < mis the hypothesis that we require in order to prove Theorem 1.3, and as we shall now see, implies thatθ is injective.

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Lemma 4.2. — Letn, m∈N, letGbe a semi-direct product of the form ZnoθZm, and let16t < nbe such thatθ(1m)is multiplication inZn by t. Suppose thatgcd(tl−1, n) = 1for all16l6m−1.

(a) The actionθ: Zm→Aut (Zn)is injective, and the homomorphism ϕ: GSZn defined in Lemma 4.1 is injective.

(b) For all(u, v)∈G\{(0n,0m)}, the permutationϕ(u, v)fixes at most one element, and ifv6= 0mthenϕ(u, v)fixes precisely one element.

Proof.

(a). — To prove the first part, we argue by contraposition. Suppose that θ is not injective. Then there exists 1 6l < m such that θ(lm) = IdZn. Nowθ(1m) is multiplication byt, soθ(lm) is multiplication bytl, and thus tl≡1 modn, which implies that gcd(tl−1, n)6= 1. The second part of the statement follows from Lemma 4.1(b).

(b). — Let (u, v)∈G\{(0n,0m)}. Ifv= 0mthenu6= 0n, soϕ(u,0m)(z) = z+u6=z for allz∈Zn, henceϕ(u,0m)is fixed-point free. So suppose that v6= 0m. Sinceθ(v) is multiplication by tv, the corresponding affine trans- formationϕ(u,v): Zn→Zn is given by ϕ(u,v)(z) =tvz+ufor allz ∈Zn. By hypothesis, gcd(tv−1, n) = 1, sotv−1 is invertible inZn, and ifz∈Zn, we have:

ϕ(u,v)(z) =z⇐⇒tvz+u=z⇐⇒(tv−1)z=−u⇐⇒z=−u(tv−1)−1 inZn. Henceϕ(u,v)possesses a unique fixed point.

The above framework enables us to prove Theorem 1.3 using Proposi- tion 3.1.

Proof of Theorem 1.3. — Letϕ: GSZnbe the embedding ofGinSZn of Lemma 4.1(b). By Lemma 4.2(b), for allgG\ {e},ϕ(g) fixes at most one point. So the embeddingϕsatisfies the hypotheses of Proposition 3.1, from which we conclude thatGembeds inBn2(Pn) (resp. inBn3(Pn))

ifmnis odd (resp. if gcd(mn,6) = 1).

As an application of Theorem 1.3, we consider groups of the formZnoθH, whereH is finite,n=pris a power of an odd primep, wherer∈N, and the homomorphismθ: H →Aut (Zpr) is injective. Recall from [12, p. 146, lines 16–17] that:

(4.2) Aut (Zpr)∼=Z(p−1)pr−1 ∼=Zp−1⊕Zpr−1,

where the isomorphisms of (4.2) are described in [12, p. 145–146]. We shall now prove Corollary 1.4 by studying injective actions of the form

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θ: H →Z(p−1)pr−1, where H is a cyclic group whose order is an odd di- visor ofp−1. Note that for our purposes, it suffices to takeH to be the (unique) subgroup ofZp−16Aut (Zpr) of orderd1, andθ to be inclusion.

Proof of Corollary 1.4. — Letp >2 be prime, letp−1 = 2jd, wheredis odd, and letd1be a divisor ofd. So identifying Aut (Zpr) withZp−1⊕Zpr−1

via (4.2), and taking the subgroupH in the above discussion to be Zd1, there exists an injective homomorphism θ: Zd1 →Zp−1⊕Zpr−1, where θ(1d1) is an automorphism of Zpr given by multiplication by an integer tthat is relatively prime withp, and the orderd1 of this automorphism is also relatively prime withp. In particular, the order oft in the groupZpr

is equal tod1. We claim that gcd(tl−1, p) = 1 for all 0< l < d1. Suppose on the contrary that tl−1 is divisible by p for some 0 < l < d1. Then tl = 1 +kp, wherek ∈N, and [12, p. 146, line 12] implies that the order oftlin Zpr is a power ofp, which contradicts the fact thattis of orderd1 and gcd(d1, p) = 1. This proves the claim. Part (a) (resp. part (b)) follows using the fact that the order ofZpr oθZd1 is odd (resp. relatively prime

with 6) and by applying Theorem 1.3.

Remark 4.3. — As we mentioned in the introduction, the results of Corol- lary 1.4 are sharp in the sense that ifk∈ {2,3}, the groupsZproθZdsatisfy

`k(G) =m(G) =pr ifd >1, wherek∈ {2,3}. This result no longer holds if we remove the hypothesis that the order of the group being acted upon is a prime power. For example, if in the semi-direct productG=Zno Zd, we taken= 15 andd= 1 then G∼=Z3×Z5, and`2(G) =m(G) = 8<15 using [4, Theorem 3(b)] or [1, Corollary 13].

4.2. Further examples

In this final section, we give examples of two semi-direct products of the form Z9oθZ3 and (Z3⊕Z3)oθZ3 respectively that do not satisfy the hypotheses of Theorem 1.3, but that embed in B92(P9). We start with some general comments. If p is an odd prime, consider the group G=ZproθZpr−1(p−1), where with respect to the notation of [12, p. 146, line 8], the homomorphismθ: Zpr−1(p−1)→Aut (Zpr) sends 1pr−1(p−1)to the element of Aut (Zpr) given by multiplication in Zpr by t0, where t0 = (1 +p)g1, and where the order of g1 (resp. 1 +p) is equal top−1 (resp.

pr−1) in the multiplicative groupZpr. Ifd1is an odd divisor ofpr−1(p−1), letq=pr−1(p−1)/d1, and consider the subgroupZproθ0Zd1 ofG, where Zd1 is the subgroup ofZpr−1(p−1) of orderd1, andθ0: Zd1 →Aut (Zpr) is

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the restriction ofθtoZd1. Thenθ0(1d) =θ(qpr−1(p−1)) is multiplication by t =t0q in Zpr, and by injectivity, t is of order d1 in Zpr. If furtherd1 is divisible bypthen td1/p is of order pin Zpr, and by [12, p. 146, line 12], td1/p ≡ (1 +p)λpr−2 mod pr, where λ ∈ N and gcd(λ, p) = 1. It follows thattd1/p−1 is divisible byp, and since 0< d1/p < d1, the hypotheses of Theorem 1.3 are not satisfied for the groupZproθ0Zd1. As Example 4.4(a) below shows, ifp = 3 and r = 2, such a group may nevertheless embed in Bpr2(Ppr). In Example 4.4(b), we show that the other non-Abelian group of order 27, which is of the form (Zp ⊕Zp)o Zp, also embeds in B92(P9). It does not satisfy the hypotheses of Theorem 1.3 either.

Examples 4.4. — Suppose thatGis a group of order 27 that embeds in S9. Ifk= 2 andn= 9 in (1.2), taking the preimage ofGbyσleads to the following short exact sequence:

(4.3) 1→P92(P9)→σ−1(G)−−−−−−→σ|σ1(G) G→1,

where the rank of the free Abelian groupP92(P9) is equal to 36. As we shall now see, ifGis one of the two non-Abelian groups of order 27, the action ofS9on the basisBofP92(P9) given by (2.2) restricts to an action of Gon B for which there are two orbits, that ofA1,2, which contains 9 elements, and is given by:

(4.4) O={A1,2, A8,9, A5,6, A2,3, A7,8, A4,5, A1,3, A7,9, A4,6},

and that ofA5,9, which contains the remaining 27 elements ofB. LetH be the subgroup ofP92(P9) generated by the orbit ofA5,9. ThenH ∼=Z27, andH is not normal inB92(P9), but it is normal in the subgroupσ−1(G) ofB92(P9) since the basisB \ OofH is invariant under the action ofG.

We thus have an extension:

(4.5) 1→Hσ−1(G)→π He →1,

where He = σ−1(G)/H, and π: σ−1(G)→He is the canonical projection.

Equation (4.3) induces the following short exact sequence:

(4.6) 1→(P92(P9))/H→He →eσ G→1,

where eσ: He →G is the surjective homomorphism induced by σ, and we also have an extension:

(4.7) 1→HP92(P9)→ρ (P92(P9))/H→1,

obtained from the canonical projection ρ: P92(P9)→(P92(P9))/H. From the construction ofH, and using the fact thatP92(P9) (resp.H) is the free Abelian group of rank 36 (resp. 27) for which B (resp.B \ O)

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