with Matter
Alfons Weber
CCLRC & University of Oxford Graduate Lecture 2004
Table of Contents
Bethe-Bloch Formula
Energy loss of heavy particles by Ionisation
Multiple Scattering
Change of particle direction in Matter
Cerenkov Radiation
Light emitted by particles travelling in dielectric materials
Transition radiation
Light emitted on traversing matter boundary
Bethe-Bloch Formula
Describes how heavy particles (m>>me) loose energy when travelling through
material
Exact theoretical treatment difficult
Atomic excitations
Screening
Bulk effects
Simplified derivation ala MPhys course
Phenomenological description
Bethe-Bloch (1)
Consider particle of charge ze, passing a stationary charge Ze
Assume
Target is non-relativistic
Target does not move
Calculate
Energy transferred to target (separate)
ze
Ze r b
θ x
y
Bethe-Bloch (2)
2
0
1
x 2 p dtF Zze
c b
Force on projectile
Change of momentum of target/projectile
Energy transferred
2 2
3
2 2
0 0
cos cos
4 4
x
Zze Zze
F r b
2 2 2 4
2 2 2
0
1
2 2 (2 ) ( )
p Z z e
E M M c b
Bethe-Bloch (3)
Consider α-particle scattering off Atom
Mass of nucleus: M=A*mp
Mass of electron: M=me
But energy transfer is
Energy transfer to single electron is
2 2 2 4 2
2 2 2
0
1
2 2 (2 ) ( )
p Z z e Z
E M M c b M
2 4
2 2 2 2
0
2 1
( ) (4 )
e
e
E b E z e
m c b
Bethe-Bloch (4)
Energy transfer is determined by impact parameter b
Integration over all impact parameters
b db
ze
2 (number of electrons / unit area )
=2 A
dn b
db
b Z N x A
Bethe-Bloch (5)
Calculate average energy loss
There must be limit for Emin and Emax
All the physics and material dependence is in the calculation of this quantities
max
max min min
max min
2 2
2
2 2
2
2
2 0
d d ( ) 2 ln
d
ln
with 2
4
b e b
e b
b
e E
E
A
e
n m c Zz
E b E b C x b
b A
m c Zz
C x E
A C N e
m c
Bethe-Bloch (6)
Simple approximations for
From relativistic kinematics
Inelastic collision
Results in the following expression
min 0 average ionisation energy E I
2 2 2 2 2
2
0
2 m ce ln 2 m ce
E Zz
x C A I
2 2 2
2 2 2
max 2
2 2
1 2
e
e
e e
E m c m c
m m
M M
Bethe-Bloch (7)
This was just a simplified derivation
Incomplete
Just to get an idea how it is done
The (approximated) true answer is
with
ε screening correction of inner electrons
δ density correction, because of polarisation in medium
2 2 2 2 2
max 2
2 2
0
2
1 ( )
2 ln
2 2 2
e e
m c m c E
E Zz
x C A I
Energy Loss Function
Average Ionisation Energy
Density Correction
Density Correction does depend on material
with
x = log10(p/M)
C, δ0, x0 material dependant constants
Different Materials (1)
Different Materials (2)
Particle Range/Stopping Power
Application in Particle ID
Energy loss as measured in tracking chamber
Who is Who!
Straggling (1)
So far we have only discussed the mean energy loss
Actual energy loss will scatter around the mean value
Difficult to calculate
parameterization exist in GEANT and some standalone software libraries
From of distribution is important as energy loss distribution is often used for calibrating the detector
Straggling (2)
Simple parameterisation
Landau function
Better to use Vavilov distribution
2 2
1 1
( ) exp ( )
2 2
with
e
f e
E E
m c Zz
C x
A
Straggling (3)
δ-Rays
Energy loss distribution is not Gaussian around mean.
In rare cases a lot of energy is transferred to a single electron
If one excludes δ-rays, the average energy loss changes
Equivalent of changing Emax
δ-Ray
Restricted dE/dx
Some detector only measure energy loss up to a certain upper limit Ecut
Truncated mean measurement
δ-rays leaving the detector
2 2 2 2 2
2 2
0
2
max
2
2 1 ln
2
1 ( )
2 2
cut
e e cut
E E
cut
m c m c E
E Zz
x C A I
E E
Electrons
Electrons are different light
Bremsstrahlung
Pair production
Multiple Scattering
Particles don’t only loose energy …
… they also change direction
MS Theory
Average scattering angle is roughly Gaussian for small deflection angles
With
Angular distributions are given by
0
0 0
0
13.6 MeV
1 0.038ln radiation length
x x
cp z X X
X
2
2 2
0 0
2 2 0 0
1 exp
2 2
1 exp 2 2
space
plane plane
dN d dN d
Correlations
Multiple scattering and dE/dx are normally treated to be independent from each
Not true
large scatter large energy transfer
small scatter small energy transfer
Detailed calculation is difficult but possible
Wade Allison & John Cobb are the experts
Correlations (W. Allison)
Example: Calculated cross section for 500MeV/c in Argon gas.
Note that this is a Log-log-log plot - the cross section varies over 20 and more decades!
log kL
2
18
17
7
log kT
whole atoms at
low Q2 (dipole region)
electrons at high
Q2
electrons backwards in
CM nuclear small angle
scattering (suppressed by screening)
nuclear backward scattering in CM (suppressed by nuclear
form factor)
Log pL or energy transfer
(16 decades)
Log pT transfer (10 decades) Log
cross section
(30 decades)
Signals from Particles in Matter
Signals in particle detectors are mainly due to ionisation
Gas chambers
Silicon detectors
Scintillators
Direct light emission by particles travelling faster than the speed of light in a medium
Cherenkov radiation
Similar, but not identical
Transition radiation
Cherenkov Radiation (1)
Moving charge in matter
at rest slow fast
Wave front comes out at certain angle
That’s the trivial result!
Cherenkov Radiation (2)
cos c 1
n
Cherenkov Radiation (3)
How many Cherenkov photons are detected? 2
2 2
2
2 2 2
0 2 2
( )sin ( )d
( ) 1 1 d
1 1
with ( ) Efficiency to detect photons of energy radiator length
electron radius
c e e
e e
e
N L z E E E
r m c
L z E E
r m c n
LN n
E E
L r
Different Cherenkov Detectors
Threshold Detectors
Yes/No on whether the speed is β>1/n
Differential Detectors
βmax > β > βmin
Ring-Imaging Detectors
Measure β
Threshold Counter
Particle travel through radiator
Cherenkov radiation
Differential Detectors
Will reflect light onto PMT for certain angles only β Selecton
Ring Imaging Detectors (1)
Ring Imaging Detectors (2)
Ring Imaging Detectors (3)
More clever geometries are possible
Two radiators One photon detector
Transition Radiation
Transition radiation is produced when a relativistic particle traverses an
inhomogeneous medium
Boundary between different materials with different n.
Strange effect
What is generating the radiation?
Accelerated charges
Initially observer sees nothing
Later he seems to see two charges moving apart
electrical dipole
Accelerated charge is creating radiation
Transition Radiation (2)
Transition Radiation (3)
Consider relativistic particle traversing a boundary from material (1) to material (2)
Total energy radiated
Can be used to measure γ
2 2 2
2
2 2 2 2 2 2 2
d 1 1
d d / 1/ 1/
plasma frequency
p p
N z
Transition Radiation Detector
Table of Contents
Bethe-Bloch Formula
Energy loss of heavy particles by Ionisation
Multiple Scattering
Change of particle direction in Matter
Cerenkov Radiation
Light emitted by particles travelling in dielectric materials
Transition radiation
Light emitted on traversing matter boundary
Bibliography
PDG 2004 (chapter 27 & 28) and references therein
Especially Rossi
Lecture notes of Chris Booth, Sheffield
http://www.shef.ac.uk/physics/teaching/phy311
R. Bock, Particle Detector Brief Book
http://rkb.home.cern.ch/rkb/PH14pp/node1.html
Or just it!
Plea
I need feedback!
Questions
What was good?
What was bad?
What was missing?
More detailed derivations?
More detectors?
More…
Less…
A.Weber@rl.ac.uk