Localizations of tensor products
MANFREDDUGAS(*) - KELLYACEVES(*) - BRADLEYWAGNER(*)
ABSTRACT- A homomorphisml:A!BbetweenR-modules is called a localization if for allW2HomR(A;B) there is a uniquec2HomR(B;B) such thatWcl. We investigate localizations of tensor products of torsion-free abelian groups. For example, we show that the natural multiplication mapm:RR!Ris a local- ization if and only ifRis an E-ring.
KEYWORDS. Torsion-free abelian groups, tensor products, localizations.
MATHEMATICSSUBJECTCLASSIFICATION(1991). Primary 20K30, 15A15; Secondary 46M05.
1. Introduction
LetRdenote some ring. Many notions in the theory ofR-modules can be stated in terms of some universal property. Here are some examples:
(1) TheR-moduleFisfreewith basisBifBis a subset ofFsuch that for any R-moduleXand any functionf :B!Xthere exists a unique homo- morphismW:F!Xsuch thatWj33Bf.
(2) TheR-moduleGissmall, if for each familyfXi:i2IgofR-modules theabeliangroupHomRÿ
G;L
i2IXi
isnaturallyisomorphictoL
i2IHomR(G;Xi).
(3) TheR-moduleGisstrongly slender[9] if for each familyfXi:i2Ig ofR-modules the abelian groupHomRÿ Q
i2IXi;G
is naturally isomorphic to L
i2IHomR(Xi;G).
(*) Indirizzo degli A.: Department of Mathematics, Baylor University, Waco, Texas 76798, USA.
E-mail: [email protected] [email protected] [email protected]
(4) Let l2HomR(A;B) be a homomorphism. We call l a split homomorphism if for any R-module X and any W2HomR(A;X) there exists some c2HomR(B;X) such that Wcl. If one considers the case of XA and WidA, then it is easy to see that l is indeed a splitting homomorphism, i.e.lis injective andl(A) is a direct summand of B.
(5) TheR-moduleG isinjectiveif for any R-module X and any sub- module K of X and any W2HomR(K;G) there exists some c2 HomR(X;G) such that Wcj33K. Note that ``projective'' is the dual of
``injective''.
(6) Tensor products: To simplify notation, let us assume RZ. Let A;BandTbe abelian groups andt:AB!Ta bilinear map. The pair (T;t) is atensor productofAandB, if for any abelian groupX and any bilinear map s:AB!X, there exists a unique c2Hom(T;X) such thatsct. It is well known, of course, that tensor products exist and are unique up to isomorphism.
It would be easy to continue this list. All these definitions can be modified by restricting theX's. Let us do this. We get
(1s) In (1), replace ``X'' by ``F''. A moduleFsatisfying (1s) is calledself- freewith basisB, c.f. [5].
(2s) In (2), replace all the ``Xi'' by ``G''. Such a moduleGis calledself- small. This notion has been studied by many authors, c.f. [3] and the literature referenced there.
(3s) In (3), replace all the ``Xi'' by ``G''. Such a module is calledstrongly self-slender, c.f. [9].
(4s) In (4) replace ``X'' by ``B'' and add the condition that the mapcis unique. Such a homomorphism l:A!B is called a localization of A.
There is a large amount of literature on localizations. See for instance [6]
and [7] and the papers referenced there.
(5s) In (5), replace ``X'' by ``G''. Then G is called quasi-injective. If RZandKis restricted top-pure subgroups ofG, thenGis calledquasi- p-pure-injective, or qppi for short. Again, there is a lot of literature on this topic dating back to the 1970's, c.f. [1] or [13].
In this paper we focus on a specification (6s) of (6):
DEFINITION1. Let R be a ring, AAR a right R-module, BRB a left R-module and T some Abelian group. Following[12, page 207], we call a map t:AB!T a middle linear map if t is bilinear and t(ar;b)t(a;rb)for all a2A;b2B and r2R. Let MidlinR(A;B;T)de- note the set of all middle linear maps from AB into T. We call the pair (T;t) a qutensor productof A;B over R if for all s2MidlinR(A;B;T), there exists auniquehomomorphismc2HomZ(T;T)such thatsct.
The map:AB!ARB is a middle linear map with(a;b)ab for all a2A;b2B.
It follows from the definitions that qutensor products are a combination of the notions in (4s) and (6):
The pair (T;t) is a qutensor product of the modulesA;Bif and only if there exists a localization l:ARB!T such that tl , where :AB!ARBis the natural map with(a;b)abfor alla2A andb2B.
In this paper we concern ourselves with localizations of tensor products of torsion-free abelian groupsA;B.
After some preliminaries in Section 2, we study localizations of ar- bitrary direct sums of modules in Section 3. In Section 4, we look at surjective localizations and find conditions for p-reduced torsion-free abelian groups having ap-reduced tensor product. In Section 5, we use the absolute E-rings constructed in [10] and [11] to obtain absolute localizations of torsion-free abelian groups that are p-reduced for in- finitely many primes p. In Section 6, we present some examples of some surprising properties of tensor products of reduced torsion-free abelian groups. For example, there exists a strongly indecomposable reduced abelian group G such that GG is reduced and completely decomposable. In Section 7, we consider torsion-free abelian groups of finite rank whosep-rank is less than their rank. We find an example of such a groupGof rank 4 and p-rank 2 such thatGGis not reduced, but G has no pure subgroups of rank at least 2 but of p-rank 1. (It is well known that GGis notp-reduced if Ghas rank at least 2 andp- rank 1.) We also find a quasi-isomorphism invariant for such groups. In the last section, we take a glimpse at zero product determinated al- gebras, c.f. [4]. Let 12Rbe a ring. Then there exists an epimorphism m:RZR!Rwith m(ab)abfor alla;b2R. We show thatmis a localization if and only if R is an E-ring.
2. Definitions and First Results Recall the following, well established
DEFINITION 2. Let M;L;X be modules over some ring and l2 Hom(M;L). Then l?X provided that for any a2Hom(M;X) there is auniqueb2Hom(L;X)such thatabl. Ifl?L, thenlis called a localization of M. Abusing notations, sometimes L is called a local- ization of M.
Next we show that qutensors are exactly the localizations of the or- dinary tensor product of the modules.
PROPOSITION1. Let ARandRB be modules andt2MidlinR(A;B;D).
Then t factors through , i.e. there exists l:ARB!D such that tl . Moreover, (D;t) is a qutensor product of A;B if and only if l:ARB!D is a localization of ARB.
PROOF. By the universal property of the tensor product, there is a uniquel2Hom(ARB;D) such thattl . Assume thatlis a local- ization and lets:AB!Dbe a bilinear map. By the universal property of the tensor product, there exists a unique mapd2Hom(ARB;D) such thatsd . Then there is a uniqueb2End(D) such thatdbland we have thatsbl bt. On the other hand, assume thatsgt.
We infer that gtgl bl and thus glbl. We con- clude thatgband we have that (D;t) is a qutensor ofA;B.
For the other direction, leta2Hom(ARB;D) and putsa , a middle linear map from AB into D. Thus there exists a unique b2End(D) such thatsbt and thusa bl , which implies that abl. If b02End(D) is some other map with ab0l, then sa b0l bl and we infer btb0t and thus bb0. This shows thatlis a localization. p
3. Localizations of Direct Sums of Modules We begin with:
PROPOSITION 2. Let l:AL
i2IAi!D be a localization, i.e. l?D.
Then there exists a setfgi:i2Ig of orthogonal idempotents in End(D) such that:
(a) For Digi(D) we have that D0L
i2IDiD and dilj33Ai2 Hom(Ai;Di).
(b) dj?Difor all i;j2I:
(c) ker (l)L
i2I(Ai\ker (l)).
(d) If the index set I is finite, then DD0.
PROOF. Define li:A!D by lij33Ailj33Ai and li(Aj) f0g for all i6j2I. Then there exist uniquegi2End(D) such that
ligilfor alli2I.
Let aP
j2Iaj2A where aj2Aj. Then (gili)(a)(gili)(ai) (gil)(ai)li(ai)li(a) and we have:
ligilifor alli2I.
Now we have (g2i)lgi(gil)gililigil and we infer thatgiis an idempotent element ofEnd(D).
Let i6j2I and a2A as above. Then (gigjl)(a)(gilj)(a) gi(lj(aj))gi(l(aj))li(aj)0. This shows that (gigj)l00l and it follows thatgigj0 for alli6j2I. We infer thatfgi:i2Igis a set of orthogonal idempotents and thus D0L
i2IDi is a submodule of D whereDigi(D).
Let ai2Ai. Then l(ai)li(ai)gi(li(ai))gi(D)Di. This shows thatdi2Hom(Ai;Di).
Note thatDDiker (gi) andgj(D)ker (gi) for alli6j2I.
To show thatdilj33Ai:Ai!Diis orthogonal toDj, leth2Hom(Ai;Dj) for somej2I. Thenhnaturally extends to a maph0fromAtoDby setting the maph0equal to 0 on the other summands ofA. Then there exists a unique mapu:D!Dsuch thath0ul. Letaaia(i) 2Awhereai2Aiand a(i)2 L
i6j2IAj. Then (ul)(a)(ul)(ai)(ul)(a(i))h0(a)h(ai)2Dj. It follows that (ul)(a(i))0 by settingai0. Sincegjacts as the identity map onDj, we get (gjuj33Di)(lj33Ai)h. Letuigjuj33Di 2Hom(Di;Dj).
Thenhuidi.
Next we need to show that the mapuiis unique with that property. Let u0ibe another such map, and note that l(A(i))ker (gi). Letu02End(D) with u0j33Diu0i and u0(ker (gi)) f0g. It follows that h0u0l and since l?D, we infer thatuu0and thusuiu0i.
Let aP
i ai2ker (l) where ai2Ai. Then 0P
il(ai)P
ili(ai) P
i gi(li(ai))2L
i2IDi and it follows thatl(ai)0 for all i2I. This shows that ker (l)L
i2I(Ai\ker (l))ker (l) and (c) follows.
Now assume thatIis finite. ThenidDlP
i2IliP
i2Igil P
i2Igi
l and it follows thatidDP
i2Igi. p
COROLLARY1. Given abelian groups D and AL
i2IAi with I finite.
Letl2Hom(A;D). Ifl?D, then DL
i2IDianddilj33Ai2Hom(Ai;Di) satisfiesdi?Dj for all i;j2I.
Conversely, if DL
i2IDi and li2Hom(Ai;Di) with li?Dj for all i;j2I, thenlL
i2Ili?D.
COROLLARY2. Let AL
i2IAiwith finite index set I and K a subgroup of A. The canonical mapp:A!A=K is a localization if and only if
(1)The canonical mapspi:Ai!Ai=(K\Ai)are localizations for all i2I and
(2)K L
i2I(K\Ai)andpi?(Aj=(K\Aj))for all i;j2I.
PROOF. It follows from Proposition 2 that (1) and (2) are necessary.
Suppose (1) and (2) hold. Let W2Hom(A;A=K) and note that A=K L
i2I(Ai=(Ai\K)) because of (2). There existWji:Ai!Aj=(Ai\K) such that W is represented by the matrix [Wji]]. For each Wji there is a unique cji:Ai=(Ai\K)!Aj=(Aj\K) such thatWjicjipi. It follows from the definitions thatc[cji]2End(A=K) is the desired map. p COROLLARY 3. With the above notation, if AiAj then DiDj for any i;j2I.
PROOF. Let sji:Ai!Aj be an isomorphism with sij:Aj !Ai the inverse map. Extend sji to s0ji:A!A by setting s0ji(Aa) f0g for all i6a2I. Thenls0ji2Hom(A;D) and there exists a uniquedji2End(D) such that
(1)ls0jidjil. In a similar fashion we get (2)ls0ij0 dijl:
It follows that gjllj(ls0ji)s0ij(djil)s0ijdji(ls0ij) (djidij)l. We infer
(3)gjdjidijas well asgidijdji. It follows that
(4)gidijdijdjidijdijgjandgjdjidjidijdjidjigi.
Taking the restrictions toDj,Diwe get
(5)dijj33Dj gidijj33Dj :Dj!Dias well asdjij33Digjdjij33Di:Di!Dj. The equations (3) now imply that dijj33Djanddjij33Di are a pair of inverse
isomorphisms and we haveDiDj. p
PROPOSITION 3. Same notations as above. If D is slender, then DL
i2IDi.
PROOF. Since l is a localization, we have that Q
i2I Hom(Ai;D) HomÿL
i2IAi;D
Hom(A;D)End(D). The latter isomorphism:End(D)! Hom(A;D) is given byWWlfor allW2End(D). Let#denote the inverse of.
Pick an elementd2D.
Define a mapsd:End(D)!Dbysd(W)W(d) for allW2End(D). This gives rise to a homomorphismtd:Q
i2IHom(Ai;D)!D. SinceDis slender, there exists a cofinite subset J ofI such that tdÿ Q
i2JHom(Ai;D)
f0g.
Note that (li)#gifor alli2Iandtd(lj)0 for allj2J. But now we have 0td(lj)gj(d) for allj2J. We infer thatP
i2Igi(d) is a finite sum for all d2Dand thusgP
i2Igi2End(D) withgllidDl. It follows that gidDand thusDL
i2IDi. p
DEFINITION3. Let(A;D)be a pair of abelian groups. We call this pair relatively semi-rigid,if each06W2Hom(A;D)is injective.
For example, if AZ and D is torsion-free, then the pair (A;D) is relatively semi-rigid.
PROPOSITION4. Let I be an index set and Ai, Dibe abelian groups for all i2I. Moreover, letli2Hom(Ai;Di)for all i2I such that:
(1) li?Djfor all i;j2I.
(2) For all i2I, we have that the pair(Ai;Dj)is relatively semi-rigid for all but finitely many j2I.
ThenlL
i2Ili:AL
i2IAi!DL
i2IDiis a localization, i.e.l?D.
PROOF. Let W2Hom(A;D). Then W[Wji] where Wji2Hom(Ai;Dj) and for alli2Iandai2Aiwe haveWji(ai)0 for all but finitely manyj2I.
By (2) we infer thatWji0 for all but finitely manyj2I. By (1), there exist uniquegji2Hom(Di;Dj) such thatWjigjili. Note thatgji0 whenever Wji0. This implies thatg[gji]2End(D) andWgl. The uniqueness
ofgwith that property follows immediately. p
COROLLARY4. Let I be an index set and Ai, Dibe abelian groups for all i2I. Moreover, letli2Hom(Ai;Di)for all i2I such that:
(1)li?Dj for all i;j2I.
(2)For all i2I, we have that Hom(Ai;Dj)0for all but finitely many j2I.
ThenlL
i2Ili:AL
i2IAi!DL
i2IDiis a localization, i.e.l?D.
4. Surjective Localization
PROPOSITION5. Let B be a subgroup of the abelian group A such that:
(1) B is fully invariant in A.
(2) The natural map End(A)!Hom(A;A=B)is surjective.
Then the canonical mapp:A!A=B is a localization.
PROOF. LetW:A!A=Bbe a homomorphism. By (2), there is some u2End(A) such that Wpu. Define c:A=B!A=B by c(aB) u(a)B. Note that cis well defined by (1) and it follows thatWcp.
Sincepis surjective, we infer thatcis unique with that property. p Let Gbe a torsion-free abelian group. For a2G, let k ka denote the type of a2G and G(t) fg2G:k k g tg. A type t(tp)p2P is called idempotent (or ring) type, if tp2 f0;1g for all primes p2P. Moreover
G
k kdenotes the set of all types of the elements ofG.
PROPOSITION 6. Let G be a torsion-free abelian group. Suppose the typetis an element in Ak kand of ring type, i.e. fort(tp)p2Pwe have tp2 f0;1g. Then (G=G(t))(t) f0g and for all W2Hom(G;G=G(t)) we have G(t)ker (W). Moreover, the natural map p:G!G=G(t) is a localization.
PROOF. Letx2Gsuch thatkxG(t)k t. Letpbe a prime such that tp 1. We have that for all n2N, there is some xn2G such that pnxnÿxkn 2G(t). Nowkn isp-divisible inGand it follows thatxisp- divisible inG. This implies thatx2G(t) and thusxG(t)0. Note that W(G(t))(G=G(t))(t) f0g. Thus W induces a map eW2End(G=G(t)) by eW(xG(t))W(x). It follows that WeWp and eW is unique with this property becausepis surjective. This shows thatpis a localization. p
Letpbe a prime integer. ThenZpz
n:z2Z;n2N;gcd(p;n)1 denotes the ring of integers localized atp. The torsion-free abelian group is calledp-locally free ifGZZp is a freeZp-module.
REMARK 1. Let A0;B0 be pure subgroups of the torsion-free abelian groups A;B respectively. Then A0B0is a pure subgroup of AB.
To see this, note that 0!A0B!AB!(A=A0)B!0 is pure- exact, and 0!A0B0!A0B!A0(B=B0)!0 is pure-exact and purity is transitive. This shows:
PROPOSITION7. Let A;B be torsion-free abelian groups. Then AB is p-reduced if and only if A0B0 is p-reduced for all pure, finite rank subgroups A0;B0of A;B respectively.
THEOREM1. Let A;B be torsion-free, p-reduced abelian groups such that all pure, finite rank subgroups of A are p-locally free. Then AB is p-reduced.
PROOF. If there exists a non-zero element win AB of infinitep- height, then there exists a pure, finite subgroupA0ofAsuch thatwis an element ofA0B. Now consider the localization (A0B)pofA0Bat the primep. We have (A0B)pA0pBpP
k BpasZp-modules sinceA0pis a freeZp-module of some rankk. SinceBisp-reduced, theZp-moduleBphas no elements of infinitep-height, which shows that no such elementwexists.
p By an assertion of Warfield's, a torsion-free groupGof finite rankmis p-locally free if and only if mrp(G):dimZ=pZ(G=pG). For the con- venience of the reader, here is an outline of the proof:
LetfaipG:1imgbe a basis ofG=pGandB P
1imaiZ. Then fai:1imgisp-independent andBis ap-basic subgroup ofG, i.e.Bis a free,p-pure subgroup of GandG=Bisp-divisible and a torsion group with (G=B)[p] f0g:It follows thatGZpBZpis a freeZp-module.
COROLLARY5. Let A;B be torsion-free, p-reduced abelian groups such that for all pure, finite rank subgroups A0of A the rank of A0is equal to the p-rank rp(A0)of A0. Then AB is p-reduced.
5. Absolute Localizations
LetAbe some algebraic structure that has some propertyP. ThenA has propertyPabsolutelyifAhas propertyPin any generic extension of the set-theoretic universe in whichAwas originally constructed. Letk(v) denote the first v-ErdoÈs cardinal. In a remarkable paper [10], GoÈbel, Herden and Shelah constructed absolute E-ringsRof cardinalitylfor any infinite cardinal l<k(v). Inspecting their proof, one realizes that the following result was shown:
THEOREM2. [10] Let l<k(v) be a cardinal and Z[X](resp. Q[X]) the polynomial ring in l commuting variable over Z (resp. Q). Then there exists a countable familyfLi:i<vgof ideals of Z[X]such that
(1)Each Liis a direct summand of the abelian groupZ[X]and (2)fW2EndQ(Q[X]):W(QLi)QLifor all i<vg Q[X]absolutely.
This version will appear in [11].
We will use this result to construct absolute localizations. First we show:
LEMMA1. Let A be a commutativeQ-algebra andFa family of ideals of A such thatfW2EndQ(A):W(J)J for all J2 Fg A. Let V be aQ-vector space. Then fW2HomQ(A;VQA):W(J)VQJ for all J2 Fg HomA(A;VQA).
PROOF. Let B be a basis of the vector spaceV. Let pb:VQA! bA be the natural projection with pb(cA) f0g for all b6c2B.
Let W2 fW2HomQ(A;VQA):W(J)VQJ for all J2 Fg. Then pbW:A!bAA and (pbW)(J)pb(VQJ)bJJ. Thus,
by hypothesis, (pbW)(x)((pbW)(1))x for all x2A. It follows that W(x) P
b2Bpb(W(x))P
b2B((pbW)(1))xW(1)x and W is A-linear. p LetGbeatorsion-free abeliangroupandP fpi:i<vganinfinite set of prime integers such thatGisp-reduced for allp2P. Lettidenote the type of the subring Z1
pi
of Q. With the notations of Theorem 2, let R Z[X]P
i<vZ1 pi
LiQ[X]. ThenRis the absolute E-ring constructed in [10]. Note thatR=Z[X] is a torsion abelian group. By (1) we haveZ[X] LiTi as abelian groups. Then R=Z[X]P
i<v(Z[X]Z1 pi
Li)=Z[X] P
i<v
ÿTiZ1 pi
Li
=(TiLi)P
i<v
ÿZ1 pi
Li
=Liwhere thei-th summand is a divisiblepi-group. This shows thatR(ti)Z1
pi
Lifor alli<v. Now letW2EndZ(R). ThenW Z1
pi Li
W(R(ti))R(ti)Z 1 pi
Li. Letc2 EndQ(Q[X]) be the unique homomorphism induced byW. Thenc(QLi) QLifor alli<vand Theorem 2 supplies somed2Q[X] withcd. Since dc(1)W(1)2R, we haveWdfor somed2R, i.e.Ris an E-ring.
Let us call such a ringRan (GHS)-E-ring with prime number setP.
LEMMA2. Let B be a torsion-free abelian group and R,tias above. If B(ti) f0g, then(BR)(ti)BR(ti). (Here ``'' is understood to mean
``Z''.)
PROOF. Consider the short exact sequence 0!Z[X]!R! R=Z[X]L
i<v
ÿZ1 pi
Li
=Li
!0, which gives rise to the sequence 0!BZ[X]!BR!L
i<vBÿ Z1
pi Li
=Li
!0. Note thatZ[X]
is a free abelian group and thusBZ[X] is isomorphic to a direct sum of copies of B and thus has no elements of infinite pi-height. Let x2(BR)(ti), i.e. x has infinite pi-height in BR. We may assume thatx2BZ[X]. ThenZ1
pi
xBR andÿ Z1
pi
xB
Z[X]
= BZ[X]
is a pi-torsion group. We infer that Z1 pi
xBÿ Z[X] Z1
pi
Li
Bÿ
TiZ1 pi
Li
with Ti free abelian. It follows that Z1
pi
xBZ 1 pi
Li and the claim follows. p
We are now ready for the following:
THEOREM3. Let B be a torsion-free abelian group and P an infinite set of prime integers such that B is p-reduced for all p2P. Let R be a (GHS)- E-ring with prime number set P. Then the natural mapa:B!BZR is an absolute localization of B.
PROOF. Note thata(x)x1 for allx2B. It follows from Lemma 2 that BR is an E(R)-module. By Proposition 1.2 in [6] we obtain that EndZ(BR)EndR(BR). By Proposition 1.1 in [6] the mapais a lo- calization ofB.
6. Examples
The following is a well-known and highly instructive example.
EXAMPLE1. Even if A is p-reduced, the tensor product AA might not be p-reduced:
Letpbe prime,Jp the ring ofp-adic numbers,Zpthe ring of integers localized atp, andp2JpÿZp, a unit. Thus
p lim
n!1zn;
zn2Zp, in thep-adic topology withp6 jznandpnj(pÿzn) inJp.
Let A h1;piJp, the pure subgroup of Jp generated by 1 and p.
ThenAA h11;1p;p1;ppi is a pure subgroup of rank 4 of JpJp.
Since ppÿpznp(pÿzn) we have pnj(ppÿpzn). Simi- larly pnj(ppÿznp). Hence pnj[(ppÿpzn)ÿ(ppÿznp)] (1pÿp1)zn. Then there must existanandbnin the integers such that 1znanpnbn. Hencepnj(1pÿp1)znan(1pÿp1)(1ÿpnbn) which impliespnj(1pÿp1) for alln<v.
SinceAis aZp-module this means 061pÿp1 is a divisible ele- ment. HenceAAis not reduced.
EXAMPLE2. Even if A is strongly indecomposable, the tensor product AA might be completely decomposable:
Given distinct primes p, q, r, defineAe1Z1 p
e2Z1 q
(e1e2)Z1 r .
Then A is strongly indecomposable of rank 2 with End(A)Z. We have
AAb1Z1 p
b2Z 1 pq
b3Z 1 pq
b4Z1 q
(b1b3)Z 1 rp
(b2b4)Z[1
rq](b1b2)Z 1 pr
(b3b4)Z 1 qr
(b1b2b3b4)Z1 r
whereb1e1e1; b2e1e2; b3e2e1; b4e2e2. Definerbyr(b1)b1b2;andr(bi)0 for 2i4. Then r(AA)(b1b2)Z1
p
(b1b2)Z 1 rp
(b1b2)Z 1 pr
(b1b2)Z1 r
(b1b2)Z 1 pr
.
and thusr(AA)AA, i.e.r2End(AA) withr2r.
Definesbys(b4)b3b4;ands(bi)0 for 1i3. Then s(AA)(b3b4)Z 1
qr
(b3b4)Z 1 qr
(b3b4)Z1 q
(b3b4)Z1 r
(b3b4)Z 1 qr
AAand thus s2End(AA); s2s.srrs0.
Note that (1ÿrÿs)(bi)
ÿb2 fori1 b2 fori2 b3 fori3 ÿb3 fori4 8>
>>
><
>>
>>
:
and (1ÿrÿs)(AA) ÿb2Z1 p
b2Z 1 pq
b3Z 1 pq
ÿb3Z1 q
(ÿb2b3)Z 1 rp
(b2ÿb3)Z[1
rq]000
b2Z 1 pq
b3Z 1 pq
(b2ÿb3)Z 1 pqr
:C.
Observe thatC(b2ÿb3)Z 1 pqr
b2Z 1 pq
, and thus
AA(b1b2)Z 1 pr
|{z}
im(r)
(b3b4)Z 1 qr
|{z}
im(s)
(b2ÿb3)Z 1 pqr
b2Z 1 pq
|{z}
im(1ÿrÿs)C
is
completely decomposable.
7. Torsion-free Abelian Groups of Finite Rank with Small p-rank Again, letJpdenote the ring ofp-adic integers and ``'' means ``Z''.
We viewJpJpas a rightJp-module. (Of course,JpJpis also a left Jp-module, but we need to pick a side.)
LetDdenote the divisible part of the torsion-free groupJpJp. There is a natural (surjective) mapm:JpJp!Jpwithm(ab)ab. SinceJp
isp-reduced, we haveDker (m).
Let w P
1inaibi P
1in(ai1)bi2ker (m) and v P
1in(1aiÿ ai1)bi. Then v2D as shown in Example 1. Note that 01m(w)
1 P
1inaibi
P
1in(1ai)biwv. This shows that w ÿv2D and thusDker (m).
We record this as:
REMARK2. We have JpJpD(1Jp)andm:JpJp!Jpis a surjective homomorphism such that Dker (m) is the divisible part of JpJp.
LetGbe a torsion-free group andZpthe ring of integers localized at the primep. Then eachy2GZphas the formya1
nfor somea2G and integernrelatively prime top. An easy argument shows thatGisp- reduced if and only ifGZpisp-reduced.
LetAbe a torsion-free,p-reduced group of, say, rank 2 andp-rank 1. It is easy to see that there exists ap-pure subgroupA0ofJpsuch that 12A0 andAA0.
NOTATION 1. Let G be a p-reduced, torsion-freeZp-module of finite rank nm and nrp(G)dimZ=pZ(G=pG)for some prime p. Then G
can be represented as a pure subgroup of L
1ineiJp generated by B L
1ineiZp together with elements uj P
1ineipij for 1jm and P [pij]2Matnm(Jp). We callPa representing matrix for G. Of course, the matrixP is not uniquely determined by G. Moreover, we may, and will, make the convention thatpij0wheneverpij2Zp.
Fomin [8] has shown that if the entries of the matrixPare algebraically independent (overZp) andGGis notp-reduced butGisp-reduced, then rp(G)1. The following example shows that this rather strong hypothesis onP is needed:
EXAMPLE3. There exists a p-reduced torsion-freeZp-module G such that rank(G)4, rp(G)2and GG is not p-reduced. Moreover, G does not contain a pure subgroup A with rp(A)1and rank(A)2.
PROOF. Pick an odd prime p and a;b;g2N. such that
pa ,
pb
,
p 2g JpÿZp and the field extensions Q[
pb
;
pa
] and Q[
pb
;pg] have dimension 4 over Q with pg2=Q[
pb
;
pa
]. Let ue1
pa
e2
pbg and ve1
pab
e2pg. Let Ge1Zpe2Zp;u;v
e1Jpe2Jp. Let w e1e1a(bÿ1)e2e2g(1ÿb)uuÿvv2GG L
1i;j2Jp(eiej)Jp. We claim that
wis ap-divisible element ofG:
Note thatw
e1e1a(bÿ1)
pa
e1e1
pa
ÿ
pab
e1e1
p ab
pa
e1e2
pbg
ÿ
pab
e1e2pg
pbg
e2e1
pa
ÿpge2e1
p ab
e2e2g(1ÿb)
pbg
e2e2
pbg
ÿpge2pge2 :
Each term in a square bracket is in the divisible part ofJpeiejJpand thusw60 is a divisible element ofGG.
Now let 06ge1a1e2a2ubvc2G. We claim thatgp2=Gfor all p2JpÿZp. This allows us to infer thatGhas no pure subgroupAwith rank(A)2 andp-rankrp(A)1.
Letg0e1a01e2a02ub0vc02Gsuch thatgpg0.
W.l.o.g. we may assume that all coefficients are integers. Using matrix notation, we get
a1b
pa
c
pab a2b
pbg
cpg
" #
p a01b0
pa
c0
pab a02b0
pbg
c0pg
" #
.
Case 1:a1b
pa
c
pab
606a2b
pbg
cpg. In this case we havep2Q[
pa
;
pb
]\Q[
pb
;pg]Q[
pb
] and w.l.o.g.
we may assume thatp
pb
and we get a1b
pa
c
pab a2b
pbg
cpg
" #
b p
b
p a1b
pab
cb
pa
b
p a2c
pbg
bbpg
" #
a01b0
pa
c0
pab a02b0
pbg
c0pg
" #
and we infer the equations:
a10a01;bc0;cbb0as well as
a20a02;cb0;bbc0 and thus bbb andcbc. We now have thatb0candg0, a contradiction.
Case 2:a1b
pa
c
pab
0 buta2b
pbg
cp 6g 0 (or vice versa).
In this case we have that a01b0c00a1 bc and thus a2pa02, a contradiction top2=Zp. p A possible choice for p;a;b;g satisfying our hypotheses would be p19, a7, b11 and g17, because these are distinct primes and 827 mod 19, 7211 mod 19 and 6217 mod 19. Therefore, by Hensel's Lemma, we have that
p7
;
p11
;
p17
2J19.
Next we will introduce a quasi-isomorphism invariant for our groupG.
Let GeiZp;uj;1in;1jk
L
1ineiJp be a p-reduced group of ranknkandrp(G)nwhereuj P
1ineipijwithpij2Jp. Let G0De0iZp;u0j;1in0;1jk0E
L
1ine0iJpbe another such group withu0j P
1in0e0ip0ijfor 1jk0.
Assume that for allb;1bn0, the setsPb f1;p0bj :1jk0gare linearly independent over the field extensionKQÿpij;1in;1jk
. ThenGG0isp-reduced:
We haveGG0L
i;jeie0jZpP
i;jeiu0jZpP
i;juie0jZpP
i;juiu0jZp. Lety P
1i;jneie0jaijP
i;jeiu0jbijP
i;juie0jcijP
i;juiu0jdij2GG0.
Note that theeae0bentry ofyis yabeae0baabP
j eae0bp0bjbajP
i paieae0bcibP
i;j pai(eae0b)p0bjdij: Ifyis a divisible element, then, by Remark 2, we have
0m(yab)aabP
j p0bjbajP
i paicibP
i;jpaip0bjdij
aabP
i paicib
P
j p0bj bajP
i paidij
for alla;b.
By our hypothesis that f1;p0bj:1jk0g is linearly independent over the field extension KQÿpij;1in;1jk
, we infer that aabP
i paicib0 and it follows thatP
i uicib2 L
1jnejZp. This is a con- tradiction tonkrank(G) unless allaab 0cib.
We infer that P
j p0bj(bajP
i paidij)0 >for all a;b and thus bajP
i paidij0 for alla;j. Again, it follows thatP
i uidij2 L
1gnegZpand thusdij0 for alli;j. Now we infer thatbaj0 for alla;jand we have that y0.
PROPOSITION 8. Let GeiZp;uj;1in;1jk
L
1ineiJp
be a p-reduced group of rank nk and rp(G)n where uj P
1ineipij with pij2Jp. Let G0
e0iZp;u0j;1in;1jk
L
1ineiJp be another such group with u0j P
1ineip0ij. Let K (K0)be the field extension ofQgenerated by the elementspij(p0ij).
If G is quasi-isomorphic to G0, then KK0. PROOF. Note that GD L
1ineiZp
L
1ikuiZpE
L
1ineiJp whereui P
1jnejpjifor somepji2Jp. PutP [pji]2Matnk(Jp).
Let W:G!G0 be a quasi-isomorphism. Then there exist matrices A[aij]2Matnn(Q);B[bij]2Matkn(Q) such that
W(ei)P
j e0jajiP
j u0jbji. Now
W(ui)P
j W(ej)pjiP
j
P
a e0aaajP
b u0bbbj
pji
P
j
P
a e0aaajP
b
P
a
ÿe0ap0ab bbj
pji
P
a e0a P
j
aajpjiP
b p0abbbjpji
P
a e0a [AP]ai[P0BP]ai.
SinceW(ui)2G0for all 1ik, we have that W(ui)P
j e0jxjiP
j u0jyjiP
a e0axaiP
j
ÿ P
a e0ap0aj yji
P
a e0a
xaiP
j p0ajyji
. LetX[xai]2Matnk(Q) and Y[yai]2Matkk(Q). We now have a matrix equation
APP0BPXP0Y ofnkmatrices, which is equivalent to P0(BPÿY)XÿAP whereBPÿY is a squarekkmatrix.
Note that W(ei)P
j e0jajiP
j u0jbjiP
a e0aaaiP
j
P
a e0ap0ajbjiP
a e0a(AP0B)ai. SinceWis injective, the square matrix A X
B Y
2Mat(nk)(nk)(Q) is invertible.
Assume that there is someT2Matkk(Jp) such that (BPÿY)T0:
Then 0P0(BPÿY)T(XÿAP)T.
This implies that A X B Y
PTÿT
APTÿXT BPTÿYT
0
0 . Since A XB Y
is invertible, we infer thatT0. It follows thatBPÿY is in- vertible.
Let KQÿpij;1in;1jk
and K0Qÿ
p0ij;1in;1jk . Then BPÿY2Matmm(K) and so is (BPÿY)ÿ1, which implies P02 Matkk(K) and thusK0K. By symmetry it follows thatKK0. p LetAbe an E-ring. LetW2Hom(AA;A). The groupAAcontains subgroups of the form Ab and aA. There exists a surjective map ib:A!Ab with ib(x)xb for all x2A. Then cbWib:A!A
and since A is an E-ring, there is some sb2A such that cb(x) W(xb)xsb for all x2A. By a similar argument, there are elements pa2Asuch thatW(ay)ypa for ally;a2A.
Note that W(ab)bpasba. It follows that s1p1. Fora1 we getsbbp1and thusW(ab)abp1for alla;b2A.
We conclude thatWp1m where m2Hom(AA;A) is the map with m(ab)abfor alla;b2A. We have shown:
PROPOSITION9. If A is an E-ring, then the mapm:AA!A with m(ab)ab for all a;b2A is a localization.
8. Zero Product Determined Algebras
The following definition can be found in [4] and elsewhere:
DEFINITION4. Let A be an algebra over the commutative ring C. Then A is calledzero product determinedif for any C-module X and every C- bilinear maph j i:AA!X the following holds:
If for all a;b2A, ab0 implies ah jbi 0, then there exists some T2HomC(A2;X)with xh jyi T(xy)for all x;y2A. As usual A2denotes the C-submodule of A generated by the set of products xy for x;y2A.
REMARK3. Let C be a commutative ring and X some C-module. We will always assume that X is a C-bimodule with sxxs for all x2X and all s2C. Let X;Y;W be C-modules. Then each C-linear map
j
h i:XY!W is automatically a middle linear map, i.e. xsh jyi xjsy
h i for all x2X;y2Y and s2C. This means that h j i factors through XCY. We will write ``'' instead of ``C''.
PROPOSITION 10. Let A be a C-algebra. Consider the maps AA! AA!m A2spanCfxy:x;y2Agwherem(xy)xy.
The following are equivalent:
(a) Let X be some C-module andu2HomC(AA;X). Ifker (m ) ker (u ), then there exists some T2HomC(A2;X)making the following diagram commutative: AA ! AA !m A2
#u #T
X
:Note that if 12A, then AA2.
(b) A is zero product determined.
(c) Let X be some C-module andu2HomC(AA;X). Ifker (m ) ker (u ), thenker (m)ker (u).
PROOF. Assume that (a) holds and leth j i:AA!X be aC-bi- linear map such thathajbi 0 wheneverab0. Then there exists a un- iqueu2HomC(AA;X) such thathajbi u(ab) for alla;b2A. Thus u(ab)0 wheneverab0, i.e. ker (m )ker (u ). By clause (a), there is some T2HomC(A2;X) such that uTm. It follows that
ajb
h i (Tm)(ab)T(ab) for alla;b2Aand (b) holds.
For the converse, assume that (b) holds. With the notations in (a), define h j i:AA!Xbyhajbi u(ab) for alla;b2A. Since ker (m ) ker (u ) we have thatab0 implieshajbi 0 for alla;b2A. By clause (b), there exists some T2HomC(A2;X) such that hajbi T(ab) for all a;b2A. Thereforeu(ab)hajbi T(ab)T(m(ab)) for alla;b2A.
This shows thatuTmand (a) follows.
That (a) implies (c), is a trivial consequence of the commutative diagram in (a). For the converse, if ker (m)ker (u), the mapTmay be defined by Tÿ P
i aibi
uÿ P
i aibi
, sinceP
i aibi0 meansmÿ P
i aibi
0. p
Note that the mapTin clause (a) is unique since the mapmis surjective.
DEFINITION5. Let C be a commutative ring and A a C-algebra and X a C-module. Then Hom0C(A;X) fu2HomC(AA;X): If x;y2A with xy0, thenu(xy)0g.
Then A is zero product determined if and only if for any u2Hom0C(A;X) there exists a (unique) T2HomC(A2;X) such that uTm.
Note that for any T2HomC(A2;X) we have that T(m(xy)) T(xy)T(0)0 whenever xy0, i.e. Tm2Hom0C(A;X). This shows that
HomC(A2;X)!mHom0C(A;X)!0 is exact. We have shown:
PROPOSITION11. The C-algebra A is zero product determined if and only if HomC(A2;X)Hom0C(A;X)via the natural map m.
Assume that 12A has no zero divisors and is zero product de- termined. Then Hom0C(A;X)HomC(AA;X)HomC(A;X) via the natural map m.
PROPOSITION12. Let C be an integral domain and A a torsion-free C-algebra with 12A and without zero divisors. Then A is a zero product determined algebra if and only if A is a subring of the field of fractions of C.
PROOF. Note that ker (m ) f(a;0):a2Ag [ f(0;a):a2Ag ker (u ) for all u2HomC(AA;X). Consider the identity map id:AA!AA. If Ais zero-product determined, then there exists a map T:A!AA such that idTm and thus m is an isomorphism.
This shows that theC-rank ofAis 1 and thusAis a subring of the field of
fractions ofC. The converse is obvious. p
COROLLARY 6. The ring Jp of p-adic integers is not zero product determined.
This motivates a weaker condition:
DEFINITION6. Let C be a commutative ring and A a C-algebra. We call A zero product self-determined, if A has the property (a) of Proposition11 with ``X'' replaced by ``A2''.
THEOREM4. Let A be an integral domain. The following are equiva- lent:
(a)The ring A is a zero product self-determinedZ-algebra.
(b)The mapm:AA!A is a (surjective) localization of AA.
(c)The ring A is an E-ring.
PROOF. Because of Proposition 9 and 10, we only have to show that (b) implies (c). To this end, pick anyb2End(A) and consideridAb:AA! AA. Then there exists someT:A!Awithm(idAb)Tmand thus ab(b)T(ab) for alla;b2A. Leta1. Thenb(b)T(b) follows for allb2B and thusab(b)b(ab) for all a;b2A. Now, for b1, we get b(a)ab(1) for alla2A. Sinceb2End(A) was arbitrary, it follows thatAis an E-ring.
Note that the hypothesis that A has no zero divisors was not used in the
previous argument. p
We may use the previous argument and Proposition 9 to obtain the following characterization of E-rings:
COROLLARY 7. Let A be some ring (viewed as a Z-algebra). The following are equivalent:
(a)The natural mapm:AA!A is a localization.
(b)The ring A is an E-ring.
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Manoscritto pervenuto in redazione il 29 Giugno 2013.