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Localizations of tensor products

MANFREDDUGAS(*) - KELLYACEVES(*) - BRADLEYWAGNER(*)

ABSTRACT- A homomorphisml:A!BbetweenR-modules is called a localization if for allW2HomR(A;B) there is a uniquec2HomR(B;B) such thatWˆcl. We investigate localizations of tensor products of torsion-free abelian groups. For example, we show that the natural multiplication mapm:RR!Ris a local- ization if and only ifRis an E-ring.

KEYWORDS. Torsion-free abelian groups, tensor products, localizations.

MATHEMATICSSUBJECTCLASSIFICATION(1991). Primary 20K30, 15A15; Secondary 46M05.

1. Introduction

LetRdenote some ring. Many notions in the theory ofR-modules can be stated in terms of some universal property. Here are some examples:

(1) TheR-moduleFisfreewith basisBifBis a subset ofFsuch that for any R-moduleXand any functionf :B!Xthere exists a unique homo- morphismW:F!Xsuch thatWj33Bˆf.

(2) TheR-moduleGissmall, if for each familyfXi:i2IgofR-modules theabeliangroupHomRÿ

G;L

i2IXi

isnaturallyisomorphictoL

i2IHomR(G;Xi).

(3) TheR-moduleGisstrongly slender[9] if for each familyfXi:i2Ig ofR-modules the abelian groupHomRÿ Q

i2IXi;G

is naturally isomorphic to L

i2IHomR(Xi;G).

(*) Indirizzo degli A.: Department of Mathematics, Baylor University, Waco, Texas 76798, USA.

E-mail: [email protected] [email protected] [email protected]

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(4) Let l2HomR(A;B) be a homomorphism. We call l a split homomorphism if for any R-module X and any W2HomR(A;X) there exists some c2HomR(B;X) such that Wˆcl. If one considers the case of XˆA and WˆidA, then it is easy to see that l is indeed a splitting homomorphism, i.e.lis injective andl(A) is a direct summand of B.

(5) TheR-moduleG isinjectiveif for any R-module X and any sub- module K of X and any W2HomR(K;G) there exists some c2 HomR(X;G) such that Wˆcj33K. Note that ``projective'' is the dual of

``injective''.

(6) Tensor products: To simplify notation, let us assume RˆZ. Let A;BandTbe abelian groups andt:AB!Ta bilinear map. The pair (T;t) is atensor productofAandB, if for any abelian groupX and any bilinear map s:AB!X, there exists a unique c2Hom(T;X) such thatsˆct. It is well known, of course, that tensor products exist and are unique up to isomorphism.

It would be easy to continue this list. All these definitions can be modified by restricting theX's. Let us do this. We get

(1s) In (1), replace ``X'' by ``F''. A moduleFsatisfying (1s) is calledself- freewith basisB, c.f. [5].

(2s) In (2), replace all the ``Xi'' by ``G''. Such a moduleGis calledself- small. This notion has been studied by many authors, c.f. [3] and the literature referenced there.

(3s) In (3), replace all the ``Xi'' by ``G''. Such a module is calledstrongly self-slender, c.f. [9].

(4s) In (4) replace ``X'' by ``B'' and add the condition that the mapcis unique. Such a homomorphism l:A!B is called a localization of A.

There is a large amount of literature on localizations. See for instance [6]

and [7] and the papers referenced there.

(5s) In (5), replace ``X'' by ``G''. Then G is called quasi-injective. If RˆZandKis restricted top-pure subgroups ofG, thenGis calledquasi- p-pure-injective, or qppi for short. Again, there is a lot of literature on this topic dating back to the 1970's, c.f. [1] or [13].

In this paper we focus on a specification (6s) of (6):

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DEFINITION1. Let R be a ring, AˆAR a right R-module, BˆRB a left R-module and T some Abelian group. Following[12, page 207], we call a map t:AB!T a middle linear map if t is bilinear and t(ar;b)ˆt(a;rb)for all a2A;b2B and r2R. Let MidlinR(A;B;T)de- note the set of all middle linear maps from AB into T. We call the pair (T;t) a qutensor productof A;B over R if for all s2MidlinR(A;B;T), there exists auniquehomomorphismc2HomZ(T;T)such thatsˆct.

The map:AB!ARB is a middle linear map with(a;b)ˆab for all a2A;b2B.

It follows from the definitions that qutensor products are a combination of the notions in (4s) and (6):

The pair (T;t) is a qutensor product of the modulesA;Bif and only if there exists a localization l:ARB!T such that tˆl , where :AB!ARBis the natural map with(a;b)ˆabfor alla2A andb2B.

In this paper we concern ourselves with localizations of tensor products of torsion-free abelian groupsA;B.

After some preliminaries in Section 2, we study localizations of ar- bitrary direct sums of modules in Section 3. In Section 4, we look at surjective localizations and find conditions for p-reduced torsion-free abelian groups having ap-reduced tensor product. In Section 5, we use the absolute E-rings constructed in [10] and [11] to obtain absolute localizations of torsion-free abelian groups that are p-reduced for in- finitely many primes p. In Section 6, we present some examples of some surprising properties of tensor products of reduced torsion-free abelian groups. For example, there exists a strongly indecomposable reduced abelian group G such that GG is reduced and completely decomposable. In Section 7, we consider torsion-free abelian groups of finite rank whosep-rank is less than their rank. We find an example of such a groupGof rank 4 and p-rank 2 such thatGGis not reduced, but G has no pure subgroups of rank at least 2 but of p-rank 1. (It is well known that GGis notp-reduced if Ghas rank at least 2 andp- rank 1.) We also find a quasi-isomorphism invariant for such groups. In the last section, we take a glimpse at zero product determinated al- gebras, c.f. [4]. Let 12Rbe a ring. Then there exists an epimorphism m:RZR!Rwith m(ab)ˆabfor alla;b2R. We show thatmis a localization if and only if R is an E-ring.

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2. Definitions and First Results Recall the following, well established

DEFINITION 2. Let M;L;X be modules over some ring and l2 Hom(M;L). Then l?X provided that for any a2Hom(M;X) there is auniqueb2Hom(L;X)such thataˆbl. Ifl?L, thenlis called a localization of M. Abusing notations, sometimes L is called a local- ization of M.

Next we show that qutensors are exactly the localizations of the or- dinary tensor product of the modules.

PROPOSITION1. Let ARandRB be modules andt2MidlinR(A;B;D).

Then t factors through , i.e. there exists l:ARB!D such that tˆl . Moreover, (D;t) is a qutensor product of A;B if and only if l:ARB!D is a localization of ARB.

PROOF. By the universal property of the tensor product, there is a uniquel2Hom(ARB;D) such thattˆl . Assume thatlis a local- ization and lets:AB!Dbe a bilinear map. By the universal property of the tensor product, there exists a unique mapd2Hom(ARB;D) such thatsˆd . Then there is a uniqueb2End(D) such thatdˆbland we have thatsˆbl ˆbt. On the other hand, assume thatsˆgt.

We infer that gtˆgl ˆbl and thus glˆbl. We con- clude thatgˆband we have that (D;t) is a qutensor ofA;B.

For the other direction, leta2Hom(ARB;D) and putsˆa , a middle linear map from AB into D. Thus there exists a unique b2End(D) such thatsˆbt and thusa ˆbl , which implies that aˆbl. If b02End(D) is some other map with aˆb0l, then sˆa ˆb0l ˆbl and we infer btˆb0t and thus bˆb0. This shows thatlis a localization. p

3. Localizations of Direct Sums of Modules We begin with:

PROPOSITION 2. Let l:AˆL

i2IAi!D be a localization, i.e. l?D.

Then there exists a setfgi:i2Ig of orthogonal idempotents in End(D) such that:

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(a) For Diˆgi(D) we have that D0ˆL

i2IDiD and diˆlj33Ai2 Hom(Ai;Di).

(b) dj?Difor all i;j2I:

(c) ker (l)ˆL

i2I(Ai\ker (l)).

(d) If the index set I is finite, then DˆD0.

PROOF. Define li:A!D by lij33Aiˆlj33Ai and li(Aj)ˆ f0g for all i6ˆj2I. Then there exist uniquegi2End(D) such that

liˆgilfor alli2I.

Let aˆP

j2Iaj2A where aj2Aj. Then (gili)(a)ˆ(gili)(ai)ˆ (gil)(ai)ˆli(ai)ˆli(a) and we have:

liˆgilifor alli2I.

Now we have (g2i)lˆgi(gil)ˆgiliˆliˆgil and we infer thatgiis an idempotent element ofEnd(D).

Let i6ˆj2I and a2A as above. Then (gigjl)(a)ˆ(gilj)(a)ˆ gi(lj(aj))ˆgi(l(aj))ˆli(aj)ˆ0. This shows that (gigj)lˆ0ˆ0l and it follows thatgigjˆ0 for alli6ˆj2I. We infer thatfgi:i2Igis a set of orthogonal idempotents and thus D0ˆL

i2IDi is a submodule of D whereDiˆgi(D).

Let ai2Ai. Then l(ai)ˆli(ai)ˆgi(li(ai))gi(D)ˆDi. This shows thatdi2Hom(Ai;Di).

Note thatDˆDiker (gi) andgj(D)ker (gi) for alli6ˆj2I.

To show thatdiˆlj33Ai:Ai!Diis orthogonal toDj, leth2Hom(Ai;Dj) for somej2I. Thenhnaturally extends to a maph0fromAtoDby setting the maph0equal to 0 on the other summands ofA. Then there exists a unique mapu:D!Dsuch thath0ˆul. Letaˆai‡a(i) 2Awhereai2Aiand a(i)2 L

i6ˆj2IAj. Then (ul)(a)ˆ(ul)(ai)‡(ul)(a(i))ˆh0(a)ˆh(ai)2Dj. It follows that (ul)(a(i))ˆ0 by settingaiˆ0. Sincegjacts as the identity map onDj, we get (gjuj33Di)(lj33Ai)ˆh. Letuiˆgjuj33Di 2Hom(Di;Dj).

Thenhˆuidi.

Next we need to show that the mapuiis unique with that property. Let u0ibe another such map, and note that l(A(i))ker (gi). Letu02End(D) with u0j33Diˆu0i and u0(ker (gi))ˆ f0g. It follows that h0ˆu0l and since l?D, we infer thatuˆu0and thusuiˆu0i.

Let aˆP

i ai2ker (l) where ai2Ai. Then 0ˆP

il(ai)ˆP

ili(ai)ˆ P

i gi(li(ai))2L

i2IDi and it follows thatl(ai)ˆ0 for all i2I. This shows that ker (l)L

i2I(Ai\ker (l))ker (l) and (c) follows.

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Now assume thatIis finite. ThenidDlˆP

i2IliˆP

i2Igilˆ P

i2Igi

l and it follows thatidDˆP

i2Igi. p

COROLLARY1. Given abelian groups D and AˆL

i2IAi with I finite.

Letl2Hom(A;D). Ifl?D, then DˆL

i2IDianddiˆlj33Ai2Hom(Ai;Di) satisfiesdi?Dj for all i;j2I.

Conversely, if DˆL

i2IDi and li2Hom(Ai;Di) with li?Dj for all i;j2I, thenlˆL

i2Ili?D.

COROLLARY2. Let AˆL

i2IAiwith finite index set I and K a subgroup of A. The canonical mapp:A!A=K is a localization if and only if

(1)The canonical mapspi:Ai!Ai=(K\Ai)are localizations for all i2I and

(2)K ˆL

i2I(K\Ai)andpi?(Aj=(K\Aj))for all i;j2I.

PROOF. It follows from Proposition 2 that (1) and (2) are necessary.

Suppose (1) and (2) hold. Let W2Hom(A;A=K) and note that A=K L

i2I(Ai=(Ai\K)) because of (2). There existWji:Ai!Aj=(Ai\K) such that W is represented by the matrix [Wji]]. For each Wji there is a unique cji:Ai=(Ai\K)!Aj=(Aj\K) such thatWjiˆcjipi. It follows from the definitions thatcˆ[cji]2End(A=K) is the desired map. p COROLLARY 3. With the above notation, if AiAj then DiDj for any i;j2I.

PROOF. Let sji:Ai!Aj be an isomorphism with sij:Aj !Ai the inverse map. Extend sji to s0ji:A!A by setting s0ji(Aa)ˆ f0g for all i6ˆa2I. Thenls0ji2Hom(A;D) and there exists a uniquedji2End(D) such that

(1)ls0jiˆdjil. In a similar fashion we get (2)ls0ij0 ˆdijl:

It follows that gjlˆljˆ(ls0ji)s0ijˆ(djil)s0ijˆdji(ls0ij)ˆ (djidij)l. We infer

(3)gjˆdjidijas well asgiˆdijdji. It follows that

(4)gidijˆdijdjidijˆdijgjandgjdjiˆdjidijdjiˆdjigi.

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Taking the restrictions toDj,Diwe get

(5)dijj33Dj ˆgidijj33Dj :Dj!Dias well asdjij33Diˆgjdjij33Di:Di!Dj. The equations (3) now imply that dijj33Djanddjij33Di are a pair of inverse

isomorphisms and we haveDiDj. p

PROPOSITION 3. Same notations as above. If D is slender, then DˆL

i2IDi.

PROOF. Since l is a localization, we have that Q

i2I Hom(Ai;D) HomÿL

i2IAi;D

ˆHom(A;D)End(D). The latter isomorphism:End(D)! Hom(A;D) is given byWˆWlfor allW2End(D). Let#denote the inverse of.

Pick an elementd2D.

Define a mapsd:End(D)!Dbysd(W)ˆW(d) for allW2End(D). This gives rise to a homomorphismtd:Q

i2IHom(Ai;D)!D. SinceDis slender, there exists a cofinite subset J ofI such that tdÿ Q

i2JHom(Ai;D)

ˆ f0g.

Note that (li)#ˆgifor alli2Iandtd(lj)ˆ0 for allj2J. But now we have 0ˆtd(lj)ˆgj(d) for allj2J. We infer thatP

i2Igi(d) is a finite sum for all d2Dand thusgˆP

i2Igi2End(D) withglˆlˆidDl. It follows that gˆidDand thusDˆL

i2IDi. p

DEFINITION3. Let(A;D)be a pair of abelian groups. We call this pair relatively semi-rigid,if each06ˆW2Hom(A;D)is injective.

For example, if AZ and D is torsion-free, then the pair (A;D) is relatively semi-rigid.

PROPOSITION4. Let I be an index set and Ai, Dibe abelian groups for all i2I. Moreover, letli2Hom(Ai;Di)for all i2I such that:

(1) li?Djfor all i;j2I.

(2) For all i2I, we have that the pair(Ai;Dj)is relatively semi-rigid for all but finitely many j2I.

ThenlˆL

i2Ili:AˆL

i2IAi!DˆL

i2IDiis a localization, i.e.l?D.

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PROOF. Let W2Hom(A;D). Then Wˆ[Wji] where Wji2Hom(Ai;Dj) and for alli2Iandai2Aiwe haveWji(ai)ˆ0 for all but finitely manyj2I.

By (2) we infer thatWjiˆ0 for all but finitely manyj2I. By (1), there exist uniquegji2Hom(Di;Dj) such thatWjiˆgjili. Note thatgjiˆ0 whenever Wjiˆ0. This implies thatgˆ[gji]2End(D) andWˆgl. The uniqueness

ofgwith that property follows immediately. p

COROLLARY4. Let I be an index set and Ai, Dibe abelian groups for all i2I. Moreover, letli2Hom(Ai;Di)for all i2I such that:

(1)li?Dj for all i;j2I.

(2)For all i2I, we have that Hom(Ai;Dj)ˆ0for all but finitely many j2I.

ThenlˆL

i2Ili:AˆL

i2IAi!DˆL

i2IDiis a localization, i.e.l?D.

4. Surjective Localization

PROPOSITION5. Let B be a subgroup of the abelian group A such that:

(1) B is fully invariant in A.

(2) The natural map End(A)!Hom(A;A=B)is surjective.

Then the canonical mapp:A!A=B is a localization.

PROOF. LetW:A!A=Bbe a homomorphism. By (2), there is some u2End(A) such that Wˆpu. Define c:A=B!A=B by c(a‡B)ˆ u(a)‡B. Note that cis well defined by (1) and it follows thatWˆcp.

Sincepis surjective, we infer thatcis unique with that property. p Let Gbe a torsion-free abelian group. For a2G, let k ka denote the type of a2G and G(t)ˆ fg2G:k k g tg. A type tˆ(tp)p2P is called idempotent (or ring) type, if tp2 f0;1g for all primes p2P. Moreover

G

k kdenotes the set of all types of the elements ofG.

PROPOSITION 6. Let G be a torsion-free abelian group. Suppose the typetis an element in Ak kand of ring type, i.e. fortˆ(tp)p2Pwe have tp2 f0;1g. Then (G=G(t))(t)ˆ f0g and for all W2Hom(G;G=G(t)) we have G(t)ker (W). Moreover, the natural map p:G!G=G(t) is a localization.

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PROOF. Letx2Gsuch thatkx‡G(t)k t. Letpbe a prime such that tpˆ 1. We have that for all n2N, there is some xn2G such that pnxnÿxˆkn 2G(t). Nowkn isp-divisible inGand it follows thatxisp- divisible inG. This implies thatx2G(t) and thusx‡G(t)ˆ0. Note that W(G(t))(G=G(t))(t)ˆ f0g. Thus W induces a map eW2End(G=G(t)) by eW(x‡G(t))ˆW(x). It follows that WˆeWp and eW is unique with this property becausepis surjective. This shows thatpis a localization. p

Letpbe a prime integer. ThenZpˆz

n:z2Z;n2N;gcd(p;n)ˆ1 denotes the ring of integers localized atp. The torsion-free abelian group is calledp-locally free ifGZZp is a freeZp-module.

REMARK 1. Let A0;B0 be pure subgroups of the torsion-free abelian groups A;B respectively. Then A0B0is a pure subgroup of AB.

To see this, note that 0!A0B!AB!(A=A0)B!0 is pure- exact, and 0!A0B0!A0B!A0(B=B0)!0 is pure-exact and purity is transitive. This shows:

PROPOSITION7. Let A;B be torsion-free abelian groups. Then AB is p-reduced if and only if A0B0 is p-reduced for all pure, finite rank subgroups A0;B0of A;B respectively.

THEOREM1. Let A;B be torsion-free, p-reduced abelian groups such that all pure, finite rank subgroups of A are p-locally free. Then AB is p-reduced.

PROOF. If there exists a non-zero element win AB of infinitep- height, then there exists a pure, finite subgroupA0ofAsuch thatwis an element ofA0B. Now consider the localization (A0B)pofA0Bat the primep. We have (A0B)pA0pBpP

k BpasZp-modules sinceA0pis a freeZp-module of some rankk. SinceBisp-reduced, theZp-moduleBphas no elements of infinitep-height, which shows that no such elementwexists.

p By an assertion of Warfield's, a torsion-free groupGof finite rankmis p-locally free if and only if mˆrp(G):ˆdimZ=pZ(G=pG). For the con- venience of the reader, here is an outline of the proof:

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Letfai‡pG:1imgbe a basis ofG=pGandBˆ P

1imaiZ. Then fai:1imgisp-independent andBis ap-basic subgroup ofG, i.e.Bis a free,p-pure subgroup of GandG=Bisp-divisible and a torsion group with (G=B)[p]ˆ f0g:It follows thatGZpˆBZpis a freeZp-module.

COROLLARY5. Let A;B be torsion-free, p-reduced abelian groups such that for all pure, finite rank subgroups A0of A the rank of A0is equal to the p-rank rp(A0)of A0. Then AB is p-reduced.

5. Absolute Localizations

LetAbe some algebraic structure that has some propertyP. ThenA has propertyPabsolutelyifAhas propertyPin any generic extension of the set-theoretic universe in whichAwas originally constructed. Letk(v) denote the first v-ErdoÈs cardinal. In a remarkable paper [10], GoÈbel, Herden and Shelah constructed absolute E-ringsRof cardinalitylfor any infinite cardinal l<k(v). Inspecting their proof, one realizes that the following result was shown:

THEOREM2. [10] Let l<k(v) be a cardinal and Z[X](resp. Q[X]) the polynomial ring in l commuting variable over Z (resp. Q). Then there exists a countable familyfLi:i<vgof ideals of Z[X]such that

(1)Each Liis a direct summand of the abelian groupZ[X]and (2)fW2EndQ(Q[X]):W(QLi)QLifor all i<vg ˆQ[X]absolutely.

This version will appear in [11].

We will use this result to construct absolute localizations. First we show:

LEMMA1. Let A be a commutativeQ-algebra andFa family of ideals of A such thatfW2EndQ(A):W(J)J for all J2 Fg ˆA. Let V be aQ-vector space. Then fW2HomQ(A;VQA):W(J)VQJ for all J2 Fg ˆ HomA(A;VQA).

PROOF. Let B be a basis of the vector spaceV. Let pb:VQA! bA be the natural projection with pb(cA)ˆ f0g for all b6ˆc2B.

Let W2 fW2HomQ(A;VQA):W(J)VQJ for all J2 Fg. Then pbW:A!bAA and (pbW)(J)pb(VQJ)ˆbJJ. Thus,

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by hypothesis, (pbW)(x)ˆ((pbW)(1))x for all x2A. It follows that W(x)ˆ P

b2Bpb(W(x))ˆP

b2B((pbW)(1))xˆW(1)x and W is A-linear. p LetGbeatorsion-free abeliangroupandPˆ fpi:i<vganinfinite set of prime integers such thatGisp-reduced for allp2P. Lettidenote the type of the subring Z1

pi

of Q. With the notations of Theorem 2, let Rˆ Z[X]‡P

i<vZ1 pi

LiQ[X]. ThenRis the absolute E-ring constructed in [10]. Note thatR=Z[X] is a torsion abelian group. By (1) we haveZ[X]ˆ LiTi as abelian groups. Then R=Z[X]ˆP

i<v(Z[X]‡Z1 pi

Li)=Z[X]ˆ P

i<v

ÿTiZ1 pi

Li

=(TiLi)P

i<v

ÿZ1 pi

Li

=Liwhere thei-th summand is a divisiblepi-group. This shows thatR(ti)ˆZ1

pi

Lifor alli<v. Now letW2EndZ(R). ThenW…Z1

pi Li

ˆW(R(ti))R(ti)ˆZ 1 pi

Li. Letc2 EndQ(Q[X]) be the unique homomorphism induced byW. Thenc(QLi) QLifor alli<vand Theorem 2 supplies somed2Q[X] withcˆd. Since dˆc(1)ˆW(1)2R, we haveWˆdfor somed2R, i.e.Ris an E-ring.

Let us call such a ringRan (GHS)-E-ring with prime number setP.

LEMMA2. Let B be a torsion-free abelian group and R,tias above. If B(ti)ˆ f0g, then(BR)(ti)ˆBR(ti). (Here ``'' is understood to mean

``Z''.)

PROOF. Consider the short exact sequence 0!Z[X]!R! R=Z[X]L

i<v

ÿZ1 pi

Li

=Li

!0, which gives rise to the sequence 0!BZ[X]!BR!L

i<vBÿ Z1

pi Li

=Li

!0. Note thatZ[X]

is a free abelian group and thusBZ[X] is isomorphic to a direct sum of copies of B and thus has no elements of infinite pi-height. Let x2(BR)(ti), i.e. x has infinite pi-height in BR. We may assume thatx2BZ[X]. ThenZ1

pi

xBR andÿ Z1

pi

x‡B

Z[X]

= BZ[X]

… † is a pi-torsion group. We infer that Z1 pi

xBÿ Z[X]‡ Z1

pi

Li

ˆBÿ

TiZ1 pi

Li

with Ti free abelian. It follows that Z1

pi

xBZ 1 pi

Li and the claim follows. p

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We are now ready for the following:

THEOREM3. Let B be a torsion-free abelian group and P an infinite set of prime integers such that B is p-reduced for all p2P. Let R be a (GHS)- E-ring with prime number set P. Then the natural mapa:B!BZR is an absolute localization of B.

PROOF. Note thata(x)ˆx1 for allx2B. It follows from Lemma 2 that BR is an E(R)-module. By Proposition 1.2 in [6] we obtain that EndZ(BR)ˆEndR(BR). By Proposition 1.1 in [6] the mapais a lo- calization ofB.

6. Examples

The following is a well-known and highly instructive example.

EXAMPLE1. Even if A is p-reduced, the tensor product AA might not be p-reduced:

Letpbe prime,Jp the ring ofp-adic numbers,Zpthe ring of integers localized atp, andp2JpÿZp, a unit. Thus

pˆ lim

n!1zn;

zn2Zp, in thep-adic topology withp6 jznandpnj(pÿzn) inJp.

Let Aˆ h1;piJp, the pure subgroup of Jp generated by 1 and p.

ThenAAˆ h11;1p;p1;ppi is a pure subgroup of rank 4 of JpJp.

Since ppÿpznˆp(pÿzn) we have pnj(ppÿpzn). Simi- larly pnj(ppÿznp). Hence pnj[(ppÿpzn)ÿ(ppÿznp)]ˆ (1pÿp1)zn. Then there must existanandbnin the integers such that 1ˆznan‡pnbn. Hencepnj(1pÿp1)znanˆ(1pÿp1)(1ÿpnbn) which impliespnj(1pÿp1) for alln<v.

SinceAis aZp-module this means 06ˆ1pÿp1 is a divisible ele- ment. HenceAAis not reduced.

EXAMPLE2. Even if A is strongly indecomposable, the tensor product AA might be completely decomposable:

Given distinct primes p, q, r, defineAˆe1Z1 p

e2Z1 q

‡(e1‡e2)Z1 r .

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Then A is strongly indecomposable of rank 2 with End(A)ˆZ. We have

AAˆb1Z1 p

b2Z 1 pq

b3Z 1 pq

b4Z1 q

‡

‡(b1‡b3)Z 1 rp

‡(b2‡b4)Z[1

rq]‡(b1‡b2)Z 1 pr

‡

‡(b3‡b4)Z 1 qr

‡(b1‡b2‡b3‡b4)Z1 r

whereb1ˆe1e1; b2ˆe1e2; b3ˆe2e1; b4ˆe2e2. Definerbyr(b1)ˆb1‡b2;andr(bi)ˆ0 for 2i4. Then r(AA)ˆ(b1‡b2)Z1

p

‡(b1‡b2)Z 1 rp

‡

‡(b1‡b2)Z 1 pr

‡(b1‡b2)Z1 r

ˆ(b1‡b2)Z 1 pr

.

and thusr(AA)AA, i.e.r2End(AA) withr2ˆr.

Definesbys(b4)ˆb3‡b4;ands(bi)ˆ0 for 1i3. Then s(AA)ˆ(b3‡b4)Z 1

qr

‡(b3‡b4)Z 1 qr

‡

‡(b3‡b4)Z1 q

‡(b3‡b4)Z1 r

ˆ

ˆ(b3‡b4)Z 1 qr

AAand thus s2End(AA); s2ˆs.srˆrsˆ0.

Note that (1ÿrÿs)(bi

ÿb2 foriˆ1 b2 foriˆ2 b3 foriˆ3 ÿb3 foriˆ4 8>

>>

><

>>

>>

:

and (1ÿrÿs)(AA)ˆ ÿb2Z1 p

‡b2Z 1 pq

‡b3Z 1 pq

ÿb3Z1 q

‡

‡(ÿb2‡b3)Z 1 rp

‡(b2ÿb3)Z[1

rq]‡0‡0‡0ˆ

ˆb2Z 1 pq

‡b3Z 1 pq

‡(b2ÿb3)Z 1 pqr

ˆ:C.

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Observe thatCˆ(b2ÿb3)Z 1 pqr

b2Z 1 pq

, and thus

AAˆ(b1‡b2)Z 1 pr

|‚‚‚‚‚‚‚‚‚‚‚{z‚‚‚‚‚‚‚‚‚‚‚}

im(r)

(b3‡b4)Z 1 qr

|‚‚‚‚‚‚‚‚‚‚‚‚{z‚‚‚‚‚‚‚‚‚‚‚‚}

im(s)

(b2ÿb3)Z 1 pqr

b2Z 1 pq

|‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚{z‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚‚}

im(1ÿrÿs)ˆC

is

completely decomposable.

7. Torsion-free Abelian Groups of Finite Rank with Small p-rank Again, letJpdenote the ring ofp-adic integers and ``'' means ``Z''.

We viewJpJpas a rightJp-module. (Of course,JpJpis also a left Jp-module, but we need to pick a side.)

LetDdenote the divisible part of the torsion-free groupJpJp. There is a natural (surjective) mapm:JpJp!Jpwithm(ab)ˆab. SinceJp

isp-reduced, we haveDker (m).

Let wˆ P

1inaibiˆ P

1in(ai1)bi2ker (m) and vˆ P

1in(1aiÿ ai1)bi. Then v2D as shown in Example 1. Note that 0ˆ1m(w)ˆ

1 P

1inaibi

ˆ P

1in(1ai)biˆw‡v. This shows that wˆ ÿv2D and thusDˆker (m).

We record this as:

REMARK2. We have JpJpˆD(1Jp)andm:JpJp!Jpis a surjective homomorphism such that Dˆker (m) is the divisible part of JpJp.

LetGbe a torsion-free group andZpthe ring of integers localized at the primep. Then eachy2GZphas the formyˆa1

nfor somea2G and integernrelatively prime top. An easy argument shows thatGisp- reduced if and only ifGZpisp-reduced.

LetAbe a torsion-free,p-reduced group of, say, rank 2 andp-rank 1. It is easy to see that there exists ap-pure subgroupA0ofJpsuch that 12A0 andAA0.

NOTATION 1. Let G be a p-reduced, torsion-freeZp-module of finite rank n‡m and nˆrp(G)ˆdimZ=pZ(G=pG)for some prime p. Then G

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can be represented as a pure subgroup of L

1ineiJp generated by Bˆ L

1ineiZp together with elements uj ˆ P

1ineipij for 1jm and P ˆ[pij]2Matnm(Jp). We callPa representing matrix for G. Of course, the matrixP is not uniquely determined by G. Moreover, we may, and will, make the convention thatpijˆ0wheneverpij2Zp.

Fomin [8] has shown that if the entries of the matrixPare algebraically independent (overZp) andGGis notp-reduced butGisp-reduced, then rp(G)ˆ1. The following example shows that this rather strong hypothesis onP is needed:

EXAMPLE3. There exists a p-reduced torsion-freeZp-module G such that rank(G)ˆ4, rp(G)ˆ2and GG is not p-reduced. Moreover, G does not contain a pure subgroup A with rp(A)ˆ1and rank(A)ˆ2.

PROOF. Pick an odd prime p and a;b;g2N. such that 

pa , 

pb

 ,

p 2g JpÿZp and the field extensions Q[ 

pb

; 

pa

] and Q[ 

pb

;pg] have dimension 4 over Q with pg2=Q[ 

pb

; 

pa

]. Let uˆe1 

pa

e2 

pbg and vˆe1 

pab

e2pg. Let Gˆe1Zpe2Zp;u;v

e1Jpe2Jp. Let wˆ e1e1a(bÿ1)‡e2e2g(1ÿb)‡uuÿvv2GG L

1i;j2Jp(eiej)Jp. We claim that

wis ap-divisible element ofG:

Note thatwˆ

e1e1a(bÿ1)‡ 

pa

e1e1 

pa

ÿ 

pab

e1e1 

p ab

‡

‡ pa

e1e2 

pbg

ÿ 

pab

e1e2pg

‡

‡ 

pbg

e2e1 

pa

ÿpge2e1 

p ab

‡

‡

e2e2g(1ÿb)‡ 

pbg

e2e2 

pbg

ÿpge2pge2 :

Each term in a square bracket is in the divisible part ofJpeiejJpand thusw6ˆ0 is a divisible element ofGG.

Now let 06ˆgˆe1a1‡e2a2‡ub‡vc2G. We claim thatgp2=Gfor all p2JpÿZp. This allows us to infer thatGhas no pure subgroupAwith rank(A)ˆ2 andp-rankrp(A)ˆ1.

Letg0ˆe1a01‡e2a02‡ub0‡vc02Gsuch thatgpˆg0.

W.l.o.g. we may assume that all coefficients are integers. Using matrix notation, we get

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a1‡b 

pa

‡c 

pab a2‡b 

pbg

‡cpg

" #

pˆ a01‡b0 

pa

‡c0 

pab a02‡b0 

pbg

‡c0pg

" #

.

Case 1:a1‡b 

pa

‡c 

pab

6ˆ06ˆa2‡b 

pbg

‡cpg. In this case we havep2Q[ 

pa

; 

pb

]\Q[ 

pb

;pg]ˆQ[ 

pb

] and w.l.o.g.

we may assume thatpˆ 

pb

and we get a1‡b 

pa

‡c 

pab a2‡b 

pbg

‡cpg

" #

b p ˆ

b

p a1‡b 

pab

‡cb 

pa

b

p a2‡c 

pbg

‡bbpg

" #

ˆ a01‡b0 

pa

‡c0 

pab a02‡b0 

pbg

‡c0pg

" #

and we infer the equations:

a1ˆ0ˆa01;bˆc0;cbˆb0as well as

a2ˆ0ˆa02;cˆb0;bbˆc0 and thus bbˆb andcbˆc. We now have thatbˆ0ˆcandgˆ0, a contradiction.

Case 2:a1‡b 

pa

‡c 

pab

ˆ0 buta2‡b 

pbg

‡cp 6ˆg 0 (or vice versa).

In this case we have that a01ˆb0ˆc0ˆ0ˆa1 ˆbˆc and thus a2pˆa02, a contradiction top2=Zp. p A possible choice for p;a;b;g satisfying our hypotheses would be pˆ19, aˆ7, bˆ11 and gˆ17, because these are distinct primes and 827 mod 19, 7211 mod 19 and 6217 mod 19. Therefore, by Hensel's Lemma, we have that 

p7

; 

p11

; 

p17

2J19.

Next we will introduce a quasi-isomorphism invariant for our groupG.

Let GˆeiZp;uj;1in;1jk

L

1ineiJp be a p-reduced group of rankn‡kandrp(G)ˆnwhereujˆ P

1ineipijwithpij2Jp. Let G0ˆDe0iZp;u0j;1in0;1jk0E

L

1ine0iJpbe another such group withu0jˆ P

1in0e0ip0ijfor 1jk0.

Assume that for allb;1bn0, the setsPbˆ f1;p0bj :1jk0gare linearly independent over the field extensionKˆQÿpij;1in;1jk

. ThenGG0isp-reduced:

We haveGG0ˆL

i;jeie0jZp‡P

i;jeiu0jZp‡P

i;juie0jZp‡P

i;juiu0jZp. Letyˆ P

1i;jneie0jaij‡P

i;jeiu0jbij‡P

i;juie0jcij‡P

i;juiu0jdij2GG0.

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Note that theeae0bentry ofyis yabˆeae0baab‡P

j eae0bp0bjbaj‡P

i paieae0bcib‡P

i;j pai(eae0b)p0bjdij: Ifyis a divisible element, then, by Remark 2, we have

0ˆm(yab)ˆaab‡P

j p0bjbaj‡P

i paicib‡P

i;jpaip0bjdijˆ

ˆ

aab‡P

i paicib

‡P

j p0bj baj‡P

i paidij

for alla;b.

By our hypothesis that f1;p0bj:1jk0g is linearly independent over the field extension KˆQÿpij;1in;1jk

, we infer that aab‡P

i paicibˆ0 and it follows thatP

i uicib2 L

1jnejZp. This is a con- tradiction ton‡kˆrank(G) unless allaab ˆ0ˆcib.

We infer that P

j p0bj(baj‡P

i paidij)ˆ0 >for all a;b and thus baj‡P

i paidijˆ0 for alla;j. Again, it follows thatP

i uidij2 L

1gnegZpand thusdijˆ0 for alli;j. Now we infer thatbajˆ0 for alla;jand we have that yˆ0.

PROPOSITION 8. Let GˆeiZp;uj;1in;1jk

L

1ineiJp

be a p-reduced group of rank n‡k and rp(G)ˆn where ujˆ P

1ineipij with pij2Jp. Let G0ˆ

e0iZp;u0j;1in;1jk

L

1ineiJp be another such group with u0jˆ P

1ineip0ij. Let K (K0)be the field extension ofQgenerated by the elementspij(p0ij).

If G is quasi-isomorphic to G0, then KˆK0. PROOF. Note that GˆD L

1ineiZp

L

1ikuiZpE

L

1ineiJp whereuiˆ P

1jnejpjifor somepji2Jp. PutP ˆ[pji]2Matnk(Jp).

Let W:G!G0 be a quasi-isomorphism. Then there exist matrices Aˆ[aij]2Matnn(Q);Bˆ[bij]2Matkn(Q) such that

W(ei)ˆP

j e0jaji‡P

j u0jbji. Now

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W(ui)ˆP

j W(ej)pjiˆP

j

P

a e0aaaj‡P

b u0bbbj

pjiˆ

ˆP

j

P

a e0aaaj‡P

b

P

a

ÿe0ap0ab bbj

pjiˆ

ˆP

a e0a P

j

aajpji‡P

b p0abbbjpji

ˆ

ˆP

a e0a…[AP]ai‡[P0BP]ai†.

SinceW(ui)2G0for all 1ik, we have that W(ui)ˆP

j e0jxji‡P

j u0jyjiˆP

a e0axai‡P

j

ÿ P

a e0ap0aj yjiˆ

ˆP

a e0a

xai‡P

j p0ajyji

. LetXˆ[xai]2Matnk(Q) and Yˆ[yai]2Matkk(Q). We now have a matrix equation

AP‡P0BPˆX‡P0Y ofnkmatrices, which is equivalent to P0(BPÿY)ˆXÿAP whereBPÿY is a squarekkmatrix.

Note that W(ei)ˆP

j e0jaji‡P

j u0jbjiˆP

a e0aaai‡P

j

P

a e0ap0ajbjiˆP

a e0a(A‡P0B)ai. SinceWis injective, the square matrix A X

B Y

2Mat(n‡k)(n‡k)(Q) is invertible.

Assume that there is someT2Matkk(Jp) such that (BPÿY)Tˆ0:

Then 0ˆP0(BPÿY)Tˆ(XÿAP)T.

This implies that A X B Y

PTÿT

ˆ APTÿXT BPTÿYT

ˆ 0

0 . Since A XB Y

is invertible, we infer thatTˆ0. It follows thatBPÿY is in- vertible.

Let KˆQÿpij;1in;1jk

and K0ˆQÿ

p0ij;1in;1jk . Then BPÿY2Matmm(K) and so is (BPÿY)ÿ1, which implies P02 Matkk(K) and thusK0K. By symmetry it follows thatKˆK0. p LetAbe an E-ring. LetW2Hom(AA;A). The groupAAcontains subgroups of the form Ab and aA. There exists a surjective map ib:A!Ab with ib(x)ˆxb for all x2A. Then cbˆWib:A!A

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and since A is an E-ring, there is some sb2A such that cb(x)ˆ W(xb)ˆxsb for all x2A. By a similar argument, there are elements pa2Asuch thatW(ay)ˆypa for ally;a2A.

Note that W(ab)ˆbpaˆsba. It follows that s1ˆp1. Foraˆ1 we getsbˆbp1and thusW(ab)ˆabp1for alla;b2A.

We conclude thatWˆp1m where m2Hom(AA;A) is the map with m(ab)ˆabfor alla;b2A. We have shown:

PROPOSITION9. If A is an E-ring, then the mapm:AA!A with m(ab)ˆab for all a;b2A is a localization.

8. Zero Product Determined Algebras

The following definition can be found in [4] and elsewhere:

DEFINITION4. Let A be an algebra over the commutative ring C. Then A is calledzero product determinedif for any C-module X and every C- bilinear maph j i:AA!X the following holds:

If for all a;b2A, abˆ0 implies ah jbi ˆ0, then there exists some T2HomC(A2;X)with xh jyi ˆT(xy)for all x;y2A. As usual A2denotes the C-submodule of A generated by the set of products xy for x;y2A.

REMARK3. Let C be a commutative ring and X some C-module. We will always assume that X is a C-bimodule with sxˆxs for all x2X and all s2C. Let X;Y;W be C-modules. Then each C-linear map

j

h i:XY!W is automatically a middle linear map, i.e. xsh jyi ˆ xjsy

h i for all x2X;y2Y and s2C. This means that h j i factors through XCY. We will write ``'' instead of ``C''.

PROPOSITION 10. Let A be a C-algebra. Consider the maps AA! AA!m A2ˆspanCfxy:x;y2Agwherem(xy)ˆxy.

The following are equivalent:

(a) Let X be some C-module andu2HomC(AA;X). Ifker (m ) ker (u ), then there exists some T2HomC(A2;X)making the following diagram commutative: AA ! AA !m A2

#u #T

X

:Note that if 12A, then AˆA2.

(b) A is zero product determined.

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(c) Let X be some C-module andu2HomC(AA;X). Ifker (m ) ker (u ), thenker (m)ker (u).

PROOF. Assume that (a) holds and leth j i:AA!X be aC-bi- linear map such thathajbi ˆ0 wheneverabˆ0. Then there exists a un- iqueu2HomC(AA;X) such thathajbi ˆu(ab) for alla;b2A. Thus u(ab)ˆ0 wheneverabˆ0, i.e. ker (m )ker (u ). By clause (a), there is some T2HomC(A2;X) such that uˆTm. It follows that

ajb

h i ˆ(Tm)(ab)ˆT(ab) for alla;b2Aand (b) holds.

For the converse, assume that (b) holds. With the notations in (a), define h j i:AA!Xbyhajbi ˆu(ab) for alla;b2A. Since ker (m ) ker (u ) we have thatabˆ0 implieshajbi ˆ0 for alla;b2A. By clause (b), there exists some T2HomC(A2;X) such that hajbi ˆT(ab) for all a;b2A. Thereforeu(ab)ˆhajbi ˆT(ab)ˆT(m(ab)) for alla;b2A.

This shows thatuˆTmand (a) follows.

That (a) implies (c), is a trivial consequence of the commutative diagram in (a). For the converse, if ker (m)ker (u), the mapTmay be defined by Tÿ P

i aibi

ˆuÿ P

i aibi

, sinceP

i aibiˆ0 meansmÿ P

i aibi

ˆ0. p

Note that the mapTin clause (a) is unique since the mapmis surjective.

DEFINITION5. Let C be a commutative ring and A a C-algebra and X a C-module. Then Hom0C(A;X)ˆ fu2HomC(AA;X): If x;y2A with xyˆ0, thenu(xy)ˆ0g.

Then A is zero product determined if and only if for any u2Hom0C(A;X) there exists a (unique) T2HomC(A2;X) such that uˆTm.

Note that for any T2HomC(A2;X) we have that T(m(xy))ˆ T(xy)ˆT(0)ˆ0 whenever xyˆ0, i.e. Tm2Hom0C(A;X). This shows that

HomC(A2;X)!mHom0C(A;X)!0 is exact. We have shown:

PROPOSITION11. The C-algebra A is zero product determined if and only if HomC(A2;X)Hom0C(A;X)via the natural map m.

Assume that 12A has no zero divisors and is zero product de- termined. Then Hom0C(A;X)ˆHomC(AA;X)HomC(A;X) via the natural map m.

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PROPOSITION12. Let C be an integral domain and A a torsion-free C-algebra with 12A and without zero divisors. Then A is a zero product determined algebra if and only if A is a subring of the field of fractions of C.

PROOF. Note that ker (m )ˆ f(a;0):a2Ag [ f(0;a):a2Ag ker (u ) for all u2HomC(AA;X). Consider the identity map id:AA!AA. If Ais zero-product determined, then there exists a map T:A!AA such that idˆTm and thus m is an isomorphism.

This shows that theC-rank ofAis 1 and thusAis a subring of the field of

fractions ofC. The converse is obvious. p

COROLLARY 6. The ring Jp of p-adic integers is not zero product determined.

This motivates a weaker condition:

DEFINITION6. Let C be a commutative ring and A a C-algebra. We call A zero product self-determined, if A has the property (a) of Proposition11 with ``X'' replaced by ``A2''.

THEOREM4. Let A be an integral domain. The following are equiva- lent:

(a)The ring A is a zero product self-determinedZ-algebra.

(b)The mapm:AA!A is a (surjective) localization of AA.

(c)The ring A is an E-ring.

PROOF. Because of Proposition 9 and 10, we only have to show that (b) implies (c). To this end, pick anyb2End(A) and consideridAb:AA! AA. Then there exists someT:A!Awithm(idAb)ˆTmand thus ab(b)ˆT(ab) for alla;b2A. Letaˆ1. Thenb(b)ˆT(b) follows for allb2B and thusab(b)ˆb(ab) for all a;b2A. Now, for bˆ1, we get b(a)ˆab(1) for alla2A. Sinceb2End(A) was arbitrary, it follows thatAis an E-ring.

Note that the hypothesis that A has no zero divisors was not used in the

previous argument. p

We may use the previous argument and Proposition 9 to obtain the following characterization of E-rings:

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COROLLARY 7. Let A be some ring (viewed as a Z-algebra). The following are equivalent:

(a)The natural mapm:AA!A is a localization.

(b)The ring A is an E-ring.

REFERENCES

[1] D. ARNOLD - B.O'BRIAN - J.D. REID, Quasipure injective and projective torsion-free abelian groups of finite rank. Proc. London Math. Soc. (3) 38 (1979), pp. 532-544.

[2] S. BREAZ- G. CAÆLUGAÆREANU,Self-c-injective abelian groups. Rend. Sem. Mat.

Univ. Padova116(2006), pp. 193-203.

[3] S. BREAZ- P. SCHULTZ,Dualities for self small groups. Proc. Amer. Math. Soc.

140(2011), no. 1, pp. 69-82.

[4] M. BRESÏAR - M. GRASÏICÏ - J.S. ORTEGA, Zero product determined matrix algebras. Lin. Alg. Appl.430(2009), pp. 1486-1498.

[5] M. DUGAS- S. FEIGELSTOCK,Self-free modules and E-rings. Comm. Algebra 31(2003), no. 3, pp. 1387-1402.

[6] M. DUGAS,Localizations of torsion-free abelian groups. J. Algebra278(2004), pp. 411-429.

[7] M. DUGAS, Localizations of torsion-free abelian groups II. J. Algebra 284 (2005), no. 2, pp. 811-823.

[8] A.A. FOMIN,Tensor products of torsion-free abelian groups, Siberian Math.

J.16(1975), no. 5, pp. 820-827.

[9] R. GOÈBEL- B. GOLDSMITH- O. KOLMAN,On modules which are self slender.

Houston J. Math.35(2009), no. 3, pp. 725-736.

[10] R. GOÈBEL- D. HERDEN- S. SHELAH,Absolute E-rings. Adv. Math.226(2011), no.1, pp. 235-253.

[11] R. GOÈBEL - J. TRLIFAJ, Approximations and endomorphism algebras of modules.Second extended edition. de Gruyter Expositions in Mathematics, 41. Walter de Gruyter GmbH & Co. KG, Berlin, 2012.

[12] T.A. HUNGERFORD,Algebra, Graduate Texts in Mathematics, Springer-Verlag New York Inc. 1974.

[13] R.E. JOHNSON- E.T. WONG,Quasi-injective modules and irreducible rings. J.

London Math. Soc.36(1961), pp. 260-268.

Manoscritto pervenuto in redazione il 29 Giugno 2013.

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The investigation of abe- lian groups with respect to endoprimality was started by Davey and Pit- kethly [1] who, beside results for other kinds of algebraic structures, de-

A maximal finite subgroup M of E has a unique fixed point in T because otherwise the edges of the unique edge path in the tree T connecting two different fixed

rings that we consider in this paper are assumed to be additive sub- groups of a finite dimensional Q-space, so that they are torsion-free abelian groups of finite