R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
A NTÓNIO O RNELAS
Parametrization of Carathéodory multifunctions
Rendiconti del Seminario Matematico della Università di Padova, tome 83 (1990), p. 33-44
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Carathéodory
ANTÓNIO ORNELAS
(*)
1. Introduction.
Let F: be a multifunction which is
Lipschitz
with con-stant I and has values bounded
by
m. We show that co can berepresented
asf (x, U),
with U the unit closed ball in Rn andf Lipschitz
with constant6n(21 + m). Existing representations
were:either with U the unit closed ball in Rn but
f just
continuous in(x, u)
(Ekeland-Valadier [3]);
or withf Lipschitz
in(x, u)
but U in someinfinite dimensional space
(LeDonne-Marchi [6]).
More
generally,
let F: be a multifunction with.F’( ~ , x)
measurable and
.F(t, ~ ) uniformly
continuous. We show that coF(t, x)
can be
represented
asf (t, x, U),
where U is either the unit closed ball in Rn(in
case the valuesF(t, x)
arecompact)
or U = Rn(in
case thevalues
F(t, x)
areunbounded).
As tof,
we obtainf(.,
x,u)
meas-urable and
f (t, ~ , ~ ) uniformly
continuous(with
modulus of con-tinuity equal
to that ofF(t, ·) multiplied by
aconstant).
A consequence of this is that differential inclusions in R" with con-
vex valued
multifunctions,
continuousin x,
do notgeneralize
diffe-rential
equations
with control in Rn. Infact,
consider theCauchy problem
in R"(*) Indirizzo dell’A.:
Dept.
Matematica, Universidade deEvora, Largo
dos
Colegiais,
7000Evora, Portogallo.
Also on leave from Universidade de
tvora
andsupported by
InstitutoNacional de
Investigagiio
Cientifica,Portugal.
with
F(t, x)
measurable in t and continuous in x. As above we canconstruct a function
u)
and a convex closed set U in Rn suchthat co
F(t, x)
=f (t, x, U).
Moreover U iscompact provided
thevalues
F(t, x)
arecompact,
andt(t, ~ , u)
isLipschitz provided .F’(t, ~ )
is
Lipschitz. Finally by
animplicit
function lemma of theFilippov type
we show that any solution of(CP)
also solves the differentialequation
with control in R" :Reduction of differential inclusions in Rn
(with
continuous convex-valued
multifunctions)
to control differentialequations
wasknown,
but the
regularity
conditions were notcompletely satisfactory. Namely, either f
wasnon-Lipschitz
forLipschitz
F(Ekeland-Valadier [3])
or U was infinite dimensional
(LeDonne-Marchi [6]
orLojasiewicz-
Plis-Suarez
[8]
added to loffe[5]).
General information on multifunctions and differential inclusions
can be found in
[1].
2.
Assumptions.
Let I be a
Lebesgue
measurable set in llgn(or,
moregenerally,
a
separable
metrizable spacetogether
with aa-algebra A
which isthe
completion
of the Borela-algebra
of I relative to alocally
finitepositive
measurep).
Let X be an open or closed set in Rn(or,
moregenerally,
aseparable
space metrizablecomplete,
with a distance dand Borel
a-algebra
We consider multifunctions .F’ with valuesI’(t, x)
either boundedby
a lineargrowth condition-hypothesis (FLB)-or unbounded-hypothesis (FU).
HYPOTHESIS
(FLB).
F: is a multifunction with:(a)
valuesF(t, X) compact;
(b) F(-, x) measurable;
(c) 3a,
~n : I - R+ measurable such that(d)
X iscompact,
I isa-compact, F(t, ·)
is continuous for a.e. t.HYPOTHESIS is a multifunction with:
(a’)
valuesF(t, x) closed;
(b’) I’{ ~ , x) measurable;
(d’)
3w: I X R+ - R+ such that:dl(F(t, x), F(t, x)) w(t, d(x, x)) ,
with
w( ~ , r) measurable, ~(~ ’)
continuous concave,w(t, 0) = 0
for a.e. t.
We denote
by
co .F the multifunction such that each valueco
F(t, x)
is the closed convex hull ofF(t, x).
It is well known that co .F verifieshypothesis (FLB)
or(FU) provided
.F does(see [4]).
PROPOSITION 1.
verify hypothesis (FLB).
Then 1~’ verifies
hypthesis (FU) also, namely
it verifies(d’)
with3. Parametrization of
multifunctions.
THEOREM 1. Let .F’
verify hypothesis (FU). Suppose
moreoverthat each value
F(t, x)
iscompact,
and setThen there exists a function the unit
closed ball in
Rn,
such that:(ii) f ( ~ , x, ~c)
ismeasurable;
If moreover
.F’,
zv arejointly
continuous thenf
is continuous.COROLLARY 1. - Let F
verify hypothesis (FU).
Let U be a convex closed set in and let
verify:
has inverse
for a.e. t;
(y) h( ~, x, ~)
andh-1( ~, x, ~)
aremeasurable;
are jointly
continuous for a.e. t.Then there exists a function such that
(i), (ii)
of Th. 1 hold and:
COROLLARY 2.
verify hypothesis (FU).
Then, setting h(t, x, u)
= u inCorollary 1,
the conclusions of Theorem 1 hold with U = andx)
- 1.(The
finalpart
pro- vided F isjointly h-continuous.)
THEOREM 2. Let I’
verify hypothesis (FU)
and let I beor-compact
Then there exists a
a-compact
set E in a Banach space, a function 99: X xE -+ Rn and a multifunction I -+ E such that:(ii) ’l1(.)
is measurable with convex closedvalues;
(iii) q;(x, .)
is linearnonexpansive;
(iv) Iq;(x, ~c) - u) 1: 6nw(t, d(x, x)),
VUE for a.e. t.If moreover .1~ is
integrably
bounded then the valuesflL(t)
arecompact
for a.e. t.4. Intermediate results and
proofs.
PROOF OF PROPOSITION 1.
Apply
theScorza-Dragoni property
in1.2
(ii)
to obtain a sequence(Ik)
ofcompact disjoint
sets such thatI
= Io
uX, X
is a nullset, Io =
andcoFl1kxx, rnllk
are continuous. Set 2 and:
It is clear that
vk( ~ )
isnondecreasing
andvk(r) 2ak
r+
2mk . SinceIk,
IX are
compact
andI’k
isjointly h-continuous,
we must havevk(r)
- 0as r ~
0,
otherwise a contradiction would follow.By
a lemma of McShane[9],
there exists a continuous concavefunction
R+ ~ R+such that
Wk(O)
=0,
1~ vk(r),
henceLEMMA 1. Let 3l be any
family
ofnonempty
closed/convex
sets inRn such that dl
(K, .K)
oo in K. LetB(y, g)
be the closed ballaround y
with radiusr(y, .K) :
_v3d(y, K).
Then the map
is well
defined,
verifiesP(y, IT) === fy} whenever y e K,
and:REMARK. This lemma refines and
simplifies
the construction of LeDonne-Marchi. We havechanged
theexpansion
constant from 2to
~/3
in the definition of the radius r because we believe this value to be the bestpossible.
Moreprecisely,
we believe that theLipschitz
constant 3 for the above intersection cannot be
improved,
and thatit is not obtainable unless one uses the
expansion
constantMoreover,
in the definition of the radius r we do not use the Hausdorff distance between twosets,
asLeDonne-Marchi,
but ratherthe distance from a
point
to a set. This is notonly conceptually
aim-pler
but also seems better fitted forapplications (as
in Theorem1).
PROOF.
(a)
First wefix y*
in Rn and prove thatChoose any
K, K
in ~ and anyy E P(y* , K).
SetE* : = d(y* , .g),
F.:= dl
(K, .g).
We may suppose that E* , E >0,
otherwisejust
takey : = y* , y
respectively.
To prove the aboveinequality
we needonly
find a
point y
inP(y*, K)
such thatTo find y, choose
points
yi , y, in K such thatIf
~y* - y2 ~ ~ ~/3 ~*
then take y : = y2 . Otherwise but in thesegment ]yl, y,[ certainly
there exists somepoint y
such thatIy* - y
==ý3
E* , hence y EP(y*, K).
Ifly
-y
3e then(a)
isproved.
Otherwise
by
the claim below we haveBut this is absurd because y E
P(y* , .K)
henceTherefore
(a)
isproved.
Trigonometrical
claim : Ifyi
> 3E then 3z E]y* , y[
such that:In
fact,
as we provebelow,
in thetriangle
y, y, y* theangle
0
+ at y
verifies sen 0 >1/~/3,
inparticular
6 > 0. Therefore in thesegment ]y* , y[ certainly
there exists apoint z
such that in thetriangle
y* , y, z theangle at y
is~/2.
Thisimplies
that>
ly* - y
[ =ý3e*,
and sincewe have
Iz - y~
>ý3£.
To prove sen 0 >
1/ý3,
setand notice that we
only
need to show that 0 > (Xo. Since ao -j8o
=- ao --~- ~ j2,
it isenough
to prove that6-)-yr/2>~2013Xo2013~o’
Toprove this notice that in the
triangle
y* , y, yl theangle
aat y
verifies=
1/V3,
hence a ~ ao . In fact we must have0 c
a ao and ao because the later isincompatible
withthe fact that the
angle
a has anadjacent
side which islarger
that theopposite
side.Similarly,
in thetriangle
y, y, y, theangle @ at y
verifiesIn fact we must have
inside the claim and because the later would
imply
hence
y - y - y2 ~ c ~. Finally,
to show that 0+ n/2
>> ~ - ao - we
distinguish
thefollowing possibilities:
(i)
let y be in the y*, y,,y2-plane,
in the same side of the yi , y,- line as y* ; then theinequality
6+ n/2 = n -
>> ao -
~o
isobvious;
(ii)
let y be in the 2/~~iyy2-plane,
in the side of they2-line opposite
to y* , and let then 6--E-
= ~z - oc+
(iii)
as in(ii)
but witha c ~8 ~80;
then(iv)
let y be outsidethe y*, y2-plane
and let theprojection y’
of y onto that
plane
fall in the side of they2-line opposite
to y* and let the
angle projection
of theangle fl
on thatplane, verify 0 #’ cx;
then 0+ n/2
> ~ - ceo > ao -(v)
as in(iv)
but then(vi)
as in(iv)
buty’
in the same side as y*; then it is clear that the situation is similar to that in(i),
the differencebeing
that 0
+
This proves the claim.(b)
Now considerpoints y,
y in and setsK,
K in Jt.Setting
E : =
K), e : = K),
andusing (a)
one obtains:To prove Theorem 1 we need the
following
result:PROPOSITION 2
(Bressan [2]).
Denoteby
Xn thefamily
of non-empty compact
convex sets in R". Then there exists a map or: Rn that selects apoint
E g for each g and verifies:PROOF OF THEOREM 1.
Clearly M(., x)
is measurable andConsider the function h : I X U --~
h(t, x, u) :
=.M~(t, x) u.
Clearly h(t, x, ~ )
is anhomeomorphism
between the ball TJ and the ball of radius1tl (t, x) ;
lethw(t,
x,y) :
=M(t,
be the inversehomeomorphism.
Project
nowh(t,
x,u)
into coI’(t, x),
i.e. setwhere a is the selection in
Proposition
2 and P is the multivaluedprojection
in Lemma 2.CZairn.
/(’
x,u)
is measurable.To prove
this,
notice first thatl~lo( ~ )
is measurableby
Himmel-berg [4,
Theorem5.8].
ThenM( ~ , x)
andh( ~ ,
x,u)
are measurable.Consider the closed ball
B(.,
x,u)
of radiusaround
h( ~ , x, u).
Thenr( ~ , x, u)
is measurableby Himmelberg [4,
Theorem
3.5,
Theorem6.5],
and sinceby Himmelberg [4,
Theorem3.5,
Theorem4.1], B( ~, x, u)
and itsintersection with co
.F( ~ , x)
are measurable. Therefore this inter- section is a measurable map:7 2013~J~;
and since a: is con-tinuous, /(’
x,u)
is measurable.It is easy to prove
(iii) using
theLipschitz properties
of or and P :It is clear that if 1~
is jointly
h-continuous then.1V1° ( ~ )
iscontinuous;
and if also w is
jointly
continuous then If isjointly
continuous hence h isjointly
continuous. Then the ball B is continuous and its intersec- tion with co .F’ iscontinuous, by
theh-continuity
of co .F. This meansthat the intersection is a continuous map: I x -2T X U - and since
or: is
continuous,
yf
isjointly
continuous.To prove
(i)
fix somete7y x E X ;
then for any y E coF(t, x),
set u :=
h- 1 (t, x, y), obtaining
uE U, h(t,
x,u)
= y, hencef (t, x, u)
==
aoP(y,
coF(t, x))
= y because y E coI’(t, x) already.
This meansthat co
I’(t, x)
cf (t,
x,U),
and since theopposite
inclusion isobvious, (i)
isproved.
+PROOF OF THEOREM 2. Since I is
a-compact,
we can use the Scorza-Dragoni property
in[7]
to write JY’ a null set and10
= UIk,
where(Ik)
is a sequence ofcompact disjoint
sets such thatFk : =
is tsc with closedgraph,
Wk:== is continuous.If moreover there exists m: I -R+ such that
c m(t),
and m is measurable then we may also suppose thatmIlle
iscontinuous. Let
C°(X, R")
be the Banach space of continuous bounded maps u : X --~ Rn with the usual sup norm.Set,
for t E7o ?
and,
in case .h isintegrably bounded,
Set
Ek : = U E(t),
and let E be the closed convex hull ofU Clearly
telk kEN
each bounded subset of
E(t)
istotally bounded,
inparticular E(t)
is
compact provided F
isintegrably bounded;
ingeneral E(t)
isa-compact.
SinceIk
iscompact and wk
isjointly continuous,
eachbounded subset of
Ek
istotally bounded;
inparticular Ek
isor-compact,
hence E is
cr-compact.
Define the
function
to be the evaluation mapu)
:=then
clearly (iii)
holds. Define the multifunction ’l1by:
Since c
E(t), (iv)
holds. Since coF(t, x)
andE(t)
are convexclosed, %(t)
is convex closed. Inparticular flL(t)
iscompact
in case Fis
integrably
bounded. Set now ~. SinceFk, Wk, mk
haveclosed
graph,
oneeasily
shows that%k
has closedgraph.
Inparticular
%0:=
has measurablegraph. By Himmelberg [4,
Theorem3.5], U0
is measurable hence U is measurable.Finally,
to prove(i),
fix anyt E Io , then,
for any setu(x) := aroP(y,
coF(t, x)). Clearly
u EE(t),
andu E
flL(t) ;
moreoveru)
=u(x)
= y, so that coF(t, x)
c%(t)).
Since the
opposite
inclusion isobvious, (i)
isproved.
+5.
Application
to differential inclusions.Let I be an
interval,
bounded orunbounded,
and let S2 be an openor closed set in Let 1~ : I
x ~2 -~
Rn be a multifunction with values either boundedby
a lineargrowth condition-hypothesis (FLB)-or unbounded-hypothesis (FU).
Notice thathypothesis (FLB) (d)
nowsimply
asks the boundedness of I and thecontinuity
of.F’(t, ~ ) ;
infact I is
already a-compact,
and for X we can take anadequate
com-pact
subset ofS~, using
anexponential
apriori
estimate for solutions of(CP)
based on Gronwall’sinequality (see [1,
Theorem2.4.1]
forexample),
andsupposing
either Qlarge enough
or I smallenough.
COROLLARY 3. - Let F
verify hypothesis (FU).
Then the
Cauchy problem (CP)
has the sameabsolutely
continuoussolutions as the control differential
equation
where
f ,
U are as in Theorem 1 orCorollary
1 orCorollary
2.If moreover
.F’, w are j ointly
h-continuous then for each continu-ously
differentiable solution x of(CP)
there exists a continuous con-trol u : I ~ ZT such that
A
special
case which appears morecommonly
inapplications
iscovered
by
thesimpler:
COROLLARY 4. Let F: be a multifunction with com-
pact
valuesF(t, x)
boundedby m(t),
such thatF(., x)
is measurableand
T’(t, ~ )
isLipschitz
with constantZ(t),
with?~(’)
andZ( - ) integrable.
Then the
Cauchy problem ( CP)
has the sameabsolutely
con-tinuous
solutions as the control differentialequation
where is measurable in t and
Lipschitz
in(x, u)
with constant
6n[2l(t) + m(t)],
and B is the unit closed ball in Rn.PROPOSITION 3. Let F
verify hypothesis (FU).
Let
f ,
U be as in Theorem 1 orCorollary
1 orCorollary
2.Then for each
x : I --~- ~,
measurableverifying y(t)
EE co
F(t, x(t))
a.e. there exists u: I - U measurable such thaty(t)
=If moreover
F, ware jointly
h-continuous and x, y are continuous then u is continuous.PROOF. Consider the
homeomorphism h
as inCorollary
1 or Corol-lary
2 or Theorem1,
and setu(t)
:=h-1 (t, x(t), y(t)) .
PROOF OF COROLLARY 3. For each solution x of
(CPR)
sety(t) : = x’(t)
andapply Proposition
3.Acknowledgement.
I wish to thank ProfessorArrigo
Cellina and ananonymous referee for
suggesting
theproblem.
REFERENCES
[1] J. P. AUBIN - A. CELLINA,
Differential
inclusions,Springer,
1984.[2] A. BRESSAN, Misure di curvatura e selezione
Lipschitziane, preprint
1979.[3] I. EKELAND - M. VALADIER,
Representation of
set-valued maps, J. Math.Anal.
Appl.,
35(1971),
pp. 621-629.[4] C. J. HIMMELBERG, Measurable relations, Fund. Math., 87
(1975),
pp. 53-72.[5]
A. D. IOFFE,Representation of
set-valuedmappings. -
II :Application
todifferential inclusions,
SIAM J. ControlOptim.,
21(1983),
pp. 641-651.[6]
A. LEDONNE - M. V. MARCHI,Representation of Lipschitz compact
convexvalued
mappings,
Rend. Ac. Naz.Lincei,
68(1980),
pp. 278-280.[7]
S. LOJASIEWICZjr.,
Some theoremsof Scorza-Dragoni
typefor multifunctions
withapplications
to theproblem of
existenceof
solutionsfor differential
multivaluedequations, preprint
255(1982),
Inst. of Math., Polish Ac. Sci., Warsaw.[8]
S. LOJASIEWICZjr. -
A. PLIS - R.SUAREZ, Necessary
conditionsfor
non-linear control systems,
preprint
139(1979),
Inst. of Math., Polish Ac. of Sciences, Warsaw.[9] E. J.
MCSHANE,
Extensionof
the rangeof functions,
Bull. Amer. Math.Soc., 40
(1934),
pp. 837-842.[10]
S. LOJASIEWICZjr.,
Parametrizationof
convex sets, submitted to J.Ap- proximation Theory.
REMARKS ADDED IN PROOF:
(a) after
sending
this paper forpublication
I have constructed anexample showing
that theLipschitz
constant 3 for the multivaluedprojection (Lemma
1) is bestpossible;
(b)
four months aftersending
this paper forpublication
I have received thepreprint [10]
which extends my multivaluedprojection
to Hilbert space.Using
the sameproof
as in Lemma 1 the extension to Hilbert space is trivial.Manoscritto