C OMPOSITIO M ATHEMATICA
K. G YÖRY
C. L. S TEWART
R. T IJDEMAN
On prime factors of sums of integers I
Compositio Mathematica, tome 59, n
o1 (1986), p. 81-88
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81
ON PRIME FACTORS OF SUMS OF INTEGERS I
K.
Györy,
C.L. Stewart * and R.Tijdeman
@ Martinus Nijhoff Publishers, Dordrecht - Printed in the Netherlands
§1.
IntroductionFor any
integer n larger
than one let03C9(n)
denote the number of distinctprime
factors of n and letpen)
denote thegreatest prime
factor of n.For any set X
let X) |
denote thecardinality
of X. In 1934 Erdôs and Turàn[4] proved
that if A is a finite set ofpositive integers with |A| =
kthen, for k 2,
where
CI
is aneffectively computable positive
constant.By
theprime
number theorem this
implies
that there existintegers
al and a2 in A for whichwhere,
C2
is aneffectively computable positive
constant.Erdôs and Turàn
(cf. [3,
p.36] conjectured
that for every w there is anf(w)
so that if A and B are finite sets ofpositive integers
with|A| = |B| = k f(w)
thenWe shall prove this
conjecture
withf(w) = eC3W. Moreover,
it suffices that one set has at least k elements and the other at least two.THEOREM 1: Let A and B be
finite
setsof positive integers with 1 A | 1 B |
2. Put k
= | A|.
Thenwhere
C4
is aneffectively computable positive
constant.* The research of the second author was supported in part by Grant A3528 from the Natural Sciences and Engineering Research Council of Canada.
82
Note that Theorem 1 covers
(1).
For theproof
of Theorem 1 we shall make use of a result of Evertse[6] proved by applying
a modification of amethod of Thue and
Siegel involving hypergeometric
functions. Theproof
of Erdôs and Turàn of(1)
iselementary.
Stewart andTijdeman [12]
have
given
anelementary proof
of a weaker version of Theorem 1where,
in
(2), C4 log k
isreplaced by C5(log l)/log log
1 withl= |B|.
Thissuffices to establish the
conjecture
of Erdôs and Turàn withf(w)
=wc6w.
On
combining
theprime
number theorem with Theorem 1 we obtain thefollowing
result.(In
fact the n thprime
exceeds nlog n,
see Rosserand Schoenfeld
[9],
formula(3.12).)
COROLLARY 1: Let A and B be
finite
setsof positive integers
with|A| |B| 2 and put 1 A
= k. Then there exist a in A and b in B such thatwhere
C7
is aneffectively computable positive
constant.We are able to
improve
upon(3)
if there aresufficiently large
terms ofthe form a + b and the
greatest
common divisor of all such terms is one.By adding
the smallest term of B to the terms of A andsubtracting
itfrom the terms of B we may suppose, without loss of
generality,
that thesmallest term of B is zero. We shall state our next theorem with this observation in mind.
THEOREM 2: Let E be a
positive
realnumber,
let k be aninteger
with k 2and let al a2 ... ak and b be
positive integers. If
then
for
k >k0(~),
wherek0(~)
is apositive
real number which iseffectively computable
in termsof
E andCg
is aneffectively computable positive
constant.
Further, if
a,, a2, b runthrough positive integers
such thatthen
For the
proof
of(5)
we use estimates for linear forms in thelogarithms
of
algebraic
numbers due in thecomplex
case to Baker[1]
and in thep-adic
case to van der Poorten[7].
For theproof
of(6)
weappeal
to aresult of Evertse
[5]; alternatively
we could use a similar result of van der Poorten and Schlickewei[8].
These resultsdepend
in turn on the work of Schlickewei on thep-adic
version of theThue-Siegel-Roth-Schmidt
theo-rem.
We remark that it is
possible
toimprove
upon the estimates(3)
and(5)
if A and B are dense subsets
of NI
for someinteger
N. Forexample, Sàrkôzy
and Stewart[11]
have used theHardy-Littlewood
circlemethod to prove that
if 1 AI»
Nand 1 BI»
N then there exist a in A and b in B for which(P(a + b) >> N. Further, Balog
andSàrkôzy [2],
see also
[10],
have used thelarge
sieveinequality
to prove that if|A| |B| >
100N(log N)2
and N issufficiently large
then there exist a in A and b in B for whichThe second author would like to thank the
University
of Leiden for thehospitality
he receivedduring
a visit in the fall of1984,
at which timethe
greater part
of this paper was written.§2. Preliminary
lemmasLet al, ... , an be non-zero
integers
with absolute values at mostA1, ... , An respectively
and letbl, ... , bn
beintegers
with absolute values at most B.We shall assume that
A1, ... , An
and B are all at least 3. Putwhere,
for any real number x,log x
denotes theprincipal
branch of thelogarithm
of x.Further, put
LEMMA 1:
If
039B ~ 0 thenwhere
C9
is aneffectively computable positive
constant.84
PROOF: This follows from Theorem 2 of
[1].
DFor any non-zero rational number x and any
prime number p
there isa
unique integer a
such thatp-ax
is thequotient
of twointegers coprime
with p. We denote a
by ordpx.
LEMMA 2 :
Let p be a prime
number.If af1
...abnn -
1 ~ 0 thenwhere
CIO
is aneffectively computable positive
constant.PROOF: This follows from Theorem 2 of
[7].
~LEMMA 3: Let S be a
finite
setof prime
numbers and let n be apositive integer.
There areonly finitely
manyn-tuples ( xl, ... , xn) of
rationalintegers composed of primes from
S such thatand
for
each proper, non-empty subsetPROOF: This follows from
Corollary
1 of[5],
see also[8].
0Evertse
[6] proved
a result on the number of solutions of theequation
03BBx + p y = 1 in S-units x, y from any fixed
algebraic
number field. Westate and use this result for the rational number field
only.
LEMMA 4: Let
À,
IL and v be non-zerointegers.
Let pl, ... , p,, be distinctprime
numbers. There are at most 3 X72w+3 triples of
relativeprime integers
x, y, z eachcomposed of
p1,..., p,, such that Xx+ ILY
= iz.§3.
Proof of Theorem 1Let al, ... , ak denote the elements of A and let
bl, b2
be elements of B.Let pl, ... , pw be the
primes
which divideEach
element a, yields
a solution x = a,+ bl, y
= a+ b2,
z = 1 of theequasion x - y
=(b1 - b2)z. By
Lemma4,
there are at most 3 X72w+3
such
triples (a, + bl,
ai +b2, 1).
Hencek
3 X72w+3.
Thus w >C4 log k
for some
effectively computable positive
constantC4.
0§4.
Proof of Theorem 2We shall establish
(5)
first. Let cl, c2, ... denoteeffectively computable positive
constants and denoteP(a1... ak(a1 + b ) ... (ak
+b )) by
P forbrevity.
We shall assume that P is at most the k - 1 stprime
sinceotherwise, by
theprime
numbertheorem, P > (1 - ~) k log k
for k >k0(~)
and(5)
holds. Let p1,...,pw be the distinctprime
factors of al ...ak(al
+b)... (ak
+b).
ThenFurther, by
theprime
numbertheorem,
First,
we shall estimate b from below in terms of ak + b.Since log(1
+and,
since ak and ak + b arecomposed
ofprimes
from{p1,...,
pw1,
where ml, ... , mw are
integers
of absolute value at most 2log(ak
+b). By
Lemma
1,
Thus, by (8)
Therefore,
from(9)
and(10)
86
and,
since eitherNext,
we shall estimateord pl b
from above fori = 1,..., w.
Accord-ingly,
assume thatord plb
ispositive. By (4),
there exists aninteger t
with1 t k
suchthat a,
orat + b
iscoprime
with p,. Sinceordplb
ispositive
both atand
at + b
arecoprime
with p,. ThusWe may
writewhere the
integers lm, m
=1,..., W, m =1= i,
are of absolute value at most 2log( ak
+b ). Then, by
Lemma2,
for
i = 1, ... ,
w.Certainly (12)
also holds iford p 1 b
is notpositive.
To each
integer a.
+ b with 1j k
we associate aprime
p =p (i)
such that
as is
possible
since at most w distinctprimes divide aj
+ b. Theprimes p(j) f or j
=1,..., k
are elements of{
p1,...,pw}
and so,by (7),
there aretwo
integers
ar + band as
+ b with 1 rs k
which are associated to the sameprime.
Denote thatprime by
p,.By (13),
Therefore, by (8)
and(11),
Since
ord n
, we also
have
Observe that if
ordpl(ar
+b )
>ordplb
thenordplar
=ordplb
and simi-larly if ordpl(as
+b )
>ordplb
thenordplas
=ordplb. Thus, by (12)
and(14), ordplar
=ordplas
=ordplb provided
thatWe may assume that
(16)
holds since otherwisehence
as
required.
Thereforeand we may
employ
Lemma 2 as before to estimateordp¡(ar/as - 1).
Combining
this estimate with(12)
we obtainA
comparison
of the above estimate with(15)
reveals thatand this
completes
theproof
of(5).
To prove
(6)
we shall suppose that there is aninteger
h and there areinfinitely
manytriples (a1,
a2,b )
ofpositive integers
withg.c.d.
(al, a2, b)
= 1 for whichand we shall show that this leads to a contradiction. Let S be the set of
prime
numbers smaller than h. For eachtriple (al,
a2,b)
as above weput xl
= a,, X2 = - a2, X3= - (al
+b)
and X4 = a2 + b.By (17),
XI, X2, X3 and X4 arecomposed only
ofprimes
from S and sinceg.c.d.
(al,
a2,b)
= 1 we haveg.c.d. (xl,
X2, x3,X4)
= 1.Further,
XI + X2 + x3 + X4 = 0 and nonon-empty
sum of three or fewer terms from{x1,
X2, X3,x4}
is zero. There areinfinitely
manyquadruples
(x1,
x2, x3,x4)
as above.However, by
Lemma 3 with n =4,
there areonly finitely
many suchquadruples
and this contradiction establishes(6).
88
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(Oblatum 28-X-1985)
K. Gyôry
Mathematical Institute Kossuth Lajos University
4010 Debrecen
Hungary C.L. Stewart
Department of Pure Mathematics
University of Waterloo Waterloo, Ontario N2L 3GI Canada R. Tijdeman
Mathematical Institute Leiden University
2300 RA Leiden The Netherlands