A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
G UANGCAI F ANG
The structure of the critical set in the general mountain pass principle
Annales de la faculté des sciences de Toulouse 6
esérie, tome 3, n
o3 (1994), p. 345-362
<http://www.numdam.org/item?id=AFST_1994_6_3_3_345_0>
© Université Paul Sabatier, 1994, tous droits réservés.
L’accès aux archives de la revue « Annales de la faculté des sciences de Toulouse » (http://picard.ups-tlse.fr/~annales/) implique l’accord avec les conditions générales d’utilisation (http://www.numdam.org/conditions).
Toute utilisation commerciale ou impression systématique est constitu- tive d’une infraction pénale. Toute copie ou impression de ce fichier doit contenir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
- 345 -
The structure of the critical set in the general mountain pass principle
GUANGCAI
FANG(1)
Annales de la Faculté des Sciences de Toulouse Vol. III, nO 3, 1994
RÉSUMÉ. - Nous etudions la structure de l’ensemble critique engendré
par le principe general du col de Ghoussoub-Preiss. Ce faisant, nous étendons et simplifions les resultats de structure de Pucci-Serrin établis dans le contexte du principe du col classique de Ambrosetti-Rabinowitz.
Le result at principal est le suivant : : si les deux points base sont non critiques, alors 1’une des trois assertions suivantes sur 1’ensemble critique correspondant est vraie :
1)
l’ensemble des maxima locaux stricts contient un sous-ensemble fermé qui separe les points de base ;2)
il existe un point selle de type passe-montagne ;3)
il y a au moins un couple d’ensembles disjoints non vides de points selle qui sont aussi points limites de minima locaux. Ces ensembles sont connectes par 1’cnscmblc des minima locaux mais pas par celui des points selle.ABSTRACT. - We study the structure of the critical set generated by the general mountain pass principle of Ghoussoub-Preiss. In the process,
we extend and simplify the structural results of Pucci-Serrin in the context of the classical mountain pass theorem of Ambrosetti-Rabinowitz. . The main result states that if the two "base points" are not critical, then
one of the following three assertions about the corresponding critical set
holds true:
(1~
the set of proper local maxima contains a closed subset that separates the two base points;(2)
there is a saddle point of mountain-pass type;(3)
there is at least one pair of nonempty closed disjoint sets of saddle points that are also limiting points of local minima; these sets areconnected through the set of local minima but not through the set
of saddle points.
(*) Reçu le 02 novembre 1993
(1) Department of Mathematics, University of British Columbia, Vancouver, B.C., Canada V6T 1 Z4
This is a part of the author’s Ph.D dissertation in preparation at the University of British Columbia under the supervision of Dr. N. Ghoussoub.
0. Introduction
In this paper, we shall use the information obtained in a recent result of Ghoussoub-Preiss
[GP]
about the location of min-max criticalpoints,
to describe the structure of the critical set in the Mountain pass theorem of Ambrosetti-Rabinowitz
[AR].
We will not beusing
Morsetheory
andthe functionals are
only supposed
to beC1.
We will usesystematically
the
methodology
initiated in[GP]
to reprove,simplify
and extend various related results establishedby
Hofer[H],
Pucci-Serrin[PS1, 2, 3]
andGhoussoub-Preiss
[GP].
To state the refined version of the Mountain pass
theorem,
we need thefollowing:
DEFINITION
(a).2014
A closed subset Hof
a Banach space X is said toseparate
twopoints
u and v inX, if
u and vbelong
to twodisjoint
connectedcomponents of
X~
H .We will also need the
following compactness
condition.DEFINITION
(b).2014 A C1-function 03C6
: X -- IR is said toverify
thePalais-Smale condition around the set F at the level c
(in
shortif
every sequence in X
verifying
has a
convergent subsequence.
We will denote
by Kc
the set of criticalpoints of p
at the level c. We letalso
r~
be the set of all continuouspaths joining
twopoints u
and v inX,
that is:
where
C( ~0,1~; X ~
is the space of all X -valued continuous functions on~0,1~ .
.We shall make a
systematic
use of thefollowing
1. Structure of the critical set in the
separating
set FTHEOREM 1
(Ghoussoub-Preiss).
- Let p : X ~ IR be aC1-function
ona Banach space X . For two
points
u and v inX,
, consider the numberand suppose F is a closed subset
of
X thatseparates
u and v and such thatIf
~pverifies
then F nKc
is nonempty.
Remark
(a~.
In the case where F =~~p
>c~,
that is whenmax~ ~p(u~, ~p(v) }
c, the above theorem reduces to the well known moun-tain pass theorem of Ambrosetti-Rabinowitz.
To
classify
the varioustypes
of criticalpoints,
we use thefollowing
notations:
(Recall
that x is said to be a saddlepoint
if in eachneighborhood
of z thereexist two
points y
and z such that~p(y~ ~p(z~.~
THEOREM 2. - Under the
hypothesis of
Theorem1,
assume F nPc
contains no
compact
set thatseparates
u and v, then either F nMc ~
0 or.
Proof.
-Suppose
that F nM~
=~
= F nSc.
Since Fseparates
u andv we can use a result of
Whyburn [Ku, chap. VIII, § 57; III,
theorem1]
tofind a closed connected subset
F
C F that alsoseparates u
and v. Note thatF
nKc = F n Pc
and the latter isrelatively
open inF
whileF
nKc
isclosed. Since F is
connected,
then eitherF ~ Pc
=0
orFnPc
=F.
But the first case isimpossible
sinceby
Theorem 1 we have F = F nK~ 7~ ~.
Hence
F ~ Pc
which isimpossible by assumption
and the claim isproved. 0
COROLLARY 3.2014 Under the
hypothesis of Theorem 1,
assume 03C6verifies
and that u, v ~ Mc.
If Pc
does not contain aCompact
subset thatseparates
u and v, then Sc~ 0.
In
particular,
c, 03C6verifies (PS)c
and X isinfinite
dimensional,
tlten5’c ~ 0.
.Proof .
First observe thatKe
is thedisjoint
unionof Sc, Mc
andPc.
By
thecondition,
we know that.K~
iscompact. Suppose Sc
=0.
For each x EMc,
there exists a such that CLc.
Let
Then
M~
C N CLc.
Since u, v~ M~
andM~
iscompact,
we may assume that u, v~
N. Nowput Fo
= It is clear thatinfx~F0 03C6(x)
> cand that
Fo separates
u, v.Moreover, Fo
n(Mc
U =~. By
Theorem2, P~
nFo
and henceP~
must contain acompact
subset thatseparates
u, v. A contradiction thatcompletes
theproof. 0
Remark
~b~.
- Theorem 2 andCorollary
3improve
earlier resultsby
Pucci and Serrin and
they
are due to Ghoussoub-Preiss~GP~.
Thenext Theorem 4 appears in
~GP~
andimprove
the results of Hofer~H~
andPucci-Serrin
~PS2~
that appear inCorollary
5.DEFINITION
(c) (Hofer).- Say
that apoint
x inKc
isof
mountain-pass
type if for
anyneighborhood
Nof
x, the set{x
E N~ 5p~x~ c~
isnonempty
and notpath
connected. We denoteby Hc
the setof
criticalpoints of
mountain passtype
at the level c.THEOREM 4. - With the
hypothesis of
Theorem1,
we have:(1) Either F ~ Mc ~ Ø
.(2) If F ~ Pc
contains nocompact
set thatseparates
u and v, then either F nM~ ~ ~
or F nKc
contains a saddlepoint of
mountain passtype.
Here is an immediate
corollary:
COROLLARY 5. - With the
hypothesis of
Theorem1,
assumethen:
(1~
eitherM~ ~ Mc ~ 0
orHc ~ ~;
(2) if
X isinfinite dimensional,
then eitherM~ ~ Mc ~ ~
orKc
containsa saddle
point of
mountain passtype.
Proof.
- It isenough
toapply
Theorem 4 to the set F =8~c,p
>c~
andto notice that no local minimum can be on such a set.
To prove Theorem
4,
we shall need thefollowing topological
lemma.Throughout
this paper, we denoteby e)
the open ball in the Banach space X which is centered at ae and with radius e > 0.LEMMA 6. - Let
Fo
be a closed subsetof
X thatseparates
two distinctpoints
u and v . LetZz (i
=1, 2,
..., n~
be nmutually disjoint
open subsetsof X
such that u,Zi.
. Let G be an open subsetof X ~Fo
and denoteby Yi
= Then thefollowing
holds:(i)
the setFl
= ~(~ni=1 ~Yi) separates
u and v.(ii) if Ai (i
=1, 2,
..., n~
are nnonempty
connectedcomponents of
Gand
for
each i(1
in ) TZ
C(Zi n aAZ)
is arelatively
open subsetof aYi
such thatTi
n 8L =0 for
any connectedcomponent
Lof
Gwith L
~ Ai,
then the setF2
= UaYi,TZ)
alsoseparates
u and v.Proof
(i)
Since G CX ~Fo,
we haveClearly Fi
is closed and u,f ~ Fi.
We needonly
to show that for any 96r~,
If
g~~0,1~~
n(Fo B fi) 7" 0,
we are done. Otherwiseso that if
g ([0,1])
n(~ni=1 ~Yi)
=Ø,
theng([0,1]) C ~ni=1 YZ C ~ni=1 ZZ
which contradicts that u, v
~ Z2.
(ii)
We first prove thefollowing
claims: fori, j
=1, 2,
... , n, we have:(a) Ti ~ Yi ~ ~Yi, Ti ~ G = Ø and Ai ~ F2 = Ø;
(b) Tj ~ Yi = Ø and Ti ~ Tj = Ø if i ~ j;
(c) ZZ
n(8G B Ti)
caY2 B TZ.
.(a)
Since G is open, it is clear from the definition ofTZ
thatTi
CZi
n 8Gso that
TZ
CYZ
naY2
andTi
n G =~
for i =1, 2,
... , n. On the otherhand, Ai ~ Yj cAZn{Z3BG)
(c)
Since G is open, we have that for any x EZZ
n 8GB Ti, G,
hencex E
Zi B
G and x EYZ.
.Moreover,
for any x E8G B TZ
and any E > 0 there is y EB { x, E)
n G.Clearly
y~ Y2
so that x E~Yi
. SinceTi ~ Zi
n{ aG B Ti )
=Ø,
we have that x E
aYi B Ti
.Back to the
proof
of theLemma,
we note first that the setF2
is closedand is
equal
toClearly u, v tf. F2
and we needonly
to show that for any g Eg ~[0, i]~
nF2 ~ ~.
Suppose not,
and take go Er~
such thatgo ~ [0,1] ~
nF2
=0.
We shallwork toward a contradiction.
First
by (1),
we haveLet
il
be the first iE {1,
...,n}
such thatgo ([0, 1])
nTi ~ 0.
We shall finda gZl E
r~
such thatTo do
this,
we define thefollowing
times:We shall show the
following:
Indeed,
it is clear that0 sl
s2tl t2.
Since u,v ~ Zi,
wehave 0 sl and
t2
1. On the otherhand, go(t2) ~ ZZ1
since the latter is open, whilegO(t1) E aYil n Ti1
sincego ([0,1])
nF2
=Ø,
hence(a) yields
that
go(tl ) E ~Yi1
nTil
=Ti1
CZi1
. Modulo a similarreasoning
for sl, s2,(d)
and(e)
are therefore verified.To prove
(f),
we note first thatgo(t)
E G for t E(si s2 )
LJ(tl , ~2 ),
sinceotherwise
go(t) E Yzl
which contradicts(4)
and(5). So,
for any t E(tl, t2)~
go(t) E U
for some connectedcomponent
U of G. If , we havethat
Ti1
n 8U =0
and sincego(tl )
ETi1,
we see thatg0(t1) ~
8U. Hencethere must be
t3
E(t l t)
such thatgO(t3)
E 8U C 8GB Ti1
.By (c)
we seethat
F2
which is a contradiction. So U =Ail
andconsequently, go(t)
EA21
for all t E(tl, t2),
and(f)
isproved.
Since now
Ail
ispath connected,
then for sls21
s2t1 t21 t2,
wecan use a
path
inAZ1
tojoin go(sZ1 )
andgo(t21 ).
In this way, weget
apath
gi1 E
r~
such that g21([0,1]) nTi1 = 0
and gi1([0,1]) n11 = 0
for1 i ii
,since
by (a), Ail
nTi = 0
for all i =1, 2,
..., , n. On the otherhand,
sinceAil
nF2
=~,
weget
that gi1([0,1])
nF2 = 0
and(3)
is established.Next,
leti2
be the first i E{1,
...,, n~
such that gil~~0,1~)
nTZ ~ ~.
Clearly ii i2
n. In the same way, we can construct gZ2 Er~
such thatBy iterating
a finite number oftimes,
we willget
a g~ eI‘v
such that forBut this contradicts assertion
(i)
and the lemma isproved. D Proof of Theorem 4
(1) Suppose F n Kc
contains no criticalpoints
ofmountain-pass type
andF n
Me = 0.
We claim that:there exist
finitely
manycomponents of Ge,
Indeed,
otherwise we could find a sequence xi in F nKc
and a sequence of differentcomponents
ofG~
such that(x2, Ci)
-~ 0. But then anylimit
point
of the sequence x2 would be a criticalpoint for p
of mountain- passtype belonging
toF,
thuscontradicting
our initialassumption.
Hence(*)
is verified.Let now
Mi
= F nCi.
Since anypoint
ofwould be a critical
point
ofMountain-pass type,
we may find for each i =1,
..., p an open setNi
such that:Since F n
Me = 0,
we may also assume thatObserve that for each i
(1 i n),
for any x EMi
there must besuch that n U =
0
for anycomponent
U ofGe
with U~ G~.
PutThen
Ti C N2
n8Ci
and isrelatively
open in8fi.
NowBy
Lemma6,
Fseparates u
and v, hence F n which isclearly
acontradiction since
Mi C T2
and F nMe
=0.
(2)
Since Fseparates u
and v, we canagain
use the result ofWhyburn
mentioned above to
get
a closed connected subsetF
alsoseparating u
andv and such that
F
= 8U = aV where U and V are twocomponents
containing u
and vrespectively.
Assume F n0.
The set K = F nPc
is an open subset relative to F. If K is not
closed,
then any a? EKBK
is asaddle
point
sinceF
nMe
=0. Moreover,
if H is any openneighborhood
of a? not
intersecting Me
and suchthat ~p
c onH,
then both sets U n Hand V n H meet the set
~Sp c~.
This shows that x is a saddlepoint
ofmountain pass
type.
Assume now K is closed. Then it is a
clopen
set in the connected space F. Hence either K = F or K =0.
In the first case F is then contained inPc
and since itseparates
u and v, weget
a contradiction. In the second case, note thatby part (1)
F nKc
contains apoint
of mountain passtype.
Such a
point
isnecessarily
a saddlepoint
since F nMe == 0
and F nPc.
This
clearly
finishes theproof
of Theorem 4. DFor the
sequel,
we shall need thefollowing concept.
2. Structure of the critical set at the level c
DEFINITION
(d).
2014 ForA,
B twodisjoint
subsetsof
X and anynonempty
subset C
of X,
, we say thatA,
B are connectedthrough
Cif
there is noF C CUAUB both
relatively
closed and open such that A C F and F~B = 0.When A and B are connected
through C,
we also say that C connects A and B or that the space C U A U B is connected between A and B. We refer to Kuratowski[Ku, pp.142-148]
for details.The
following
theorem is animprovement
on the results of Pucci and Serrin[PS3]
that are stated inCorollary
8 below.THEOREM 7. -
With
thehypothesis of Theorem I,
wefurther
assumeu, v
/ Kc and
that pverifies (PS)c. Then
oneof
thefollowing
threeassertions concerning
the setKc
must be true:(I) Pc contains
acompact
subset thatseparates
uand v
;Fig. 1
Kc contains
asaddle point of mountain-pass type;
Fig. 2
(iii)
there arefinitely
manycomponents pf Gc,
sayCy (I
=1, 2,
..., n)
such
thatSc
=S§ and S§
nS(
=$ for (I # j, I I, j n )
where
S§
=Sc
nCi;
moreover there are at least twoof
them
Si1c, Si2c
(ii # 12, 1 ii , 12 n ) such
that the setsMc
n, %
nSi2c
arenonempty
andconnected through Mc .
Fig. 3
COROLLARY 8. - With the
hypothesis of
Theorem1,
assumefurther
that~p
verifies
and that c.If ~’~
does notseparate
0 and e, then at least oneof
thefollowing
two cases occurs:~a~ K~
contains a saddlepoint of mountain-pass type;
~,Q~ M~
intersects at least twocomponents of S~
.Moreover, if Me
hasonly
afinite
numberof components,
then either(a~~ K~
contains a saddlepoint of mountain-pass type,
or(03B2’)
at least onecomponent of Mc
intersects two or morecomponents o f
.To prove Theorem
7,
we shall need thefollowing
twotopological
lemmas.The first is
staightforward.
LEMMA 9. Let M be a subset
of
a Banach space X. .Suppose
M =
Ml
UM2
andMl
nM2
=Ø
.If M1
is both open and closed relative to thesubspace M,
then there exist open setsD1, D2 of
X such thatProof.
- SinceMl
is bothrelatively
open andclosed,
so isM2.
. Hencethere exist open sets
Ei , E2
such thatSet
H1
=nE2)
andH2
=E2, ( E1 n E2).
. ThenM1
C.Hl , M2
CH2
and
Hl
nH2
=0.
SinceEi
is open, for each x E8E2
nEl , 3
> 0 suchthat the ball
B (x,
centered at x with radius is contained in . Let~’x
=dist(x, 8Ei
nE2).
Then~’x
> > 0. SetClearly, M1 C D1,
,M2
CD2
andD1, D2
are open. We now claim thatD1
nD2
=~. Indeed,
ifnot,
say z ED1
nD2,
then there existB(x, E~/4~, B(y, Ey/4~
such that z EB(x, E~/4~
nB(y, Ey/4~.
ThenOn the other
hand, E~ ~ ~ ~ -
andEy ~ ~ x -
whichimply
that-
y~~
> A contradiction whichcompletes
theproof
of thelemma.
LEMMA 10. - Let
S‘Z (i
=1, 2,
..., n)
be nmutually disjoint compact
subsetsof
a Banach space X and let M be anynonempty
subsetof
X. .If for
alli, j (i ~ j; i, j
=1, 2,
..., n~,
the sets,52
n M andS’~
n Marenot connected
through M,
then there are nmutually disjoint
open setsN2 (i
=1, 2,
..., n~
such thatPr~oof .
For each i(i
=1, 2,
... ,n),
we denoteby MZ
thecompact
set
,SZ
n M. Sinceby assumption
none of thepairs M2, M3 (i ~ j;
i, j
=1, 2,
~ ~ ~, n)
are connectedthrough M,
there existby
Lemma 9 open setsOij
andPij (Oij
=Pji,
i~ j; i, j
=1, 2,
..., n)
such thatMZ
COi j,
Mj ~ Pij, Oij ~ Pij = Ø (i ~ j; i, j = 1, 2, ..., n) and
For each i
(i
=1, 2,
...,n),
letThen
Put for each
i (i = 1, 2, ... , n)
Then
by (2.2)-(2.5),
we haveIt is not
generally
true thatMs
U M COz.
In order to prove thelemma,
we letThen
By (2.5)
and(2.6),
we see thatM~~
is both open and closed relative toMs
U M.Again by
Lemma9,
there exist two open setsD’
andD~‘
such thatNow for each i
(i
=1, 2,
..., n) put OD
=OZ
nD". By ~2.?)
and(2.9),
wehave
By
thecompactness
ofSi
andM%
we may introduceLet
62
=(1/4) min{ai , 03B41 | i
=1, 2,
...,n}
andThen
Q,
GOiD and Siq
n M =0. By (2.11),
we see that2014 $2 ~ 362.
.By
thecompactness
we may also introducePut
Then
By (2.10),
we have thatR’
nNi) = 0 and Ni n Nj
=~ (i ~ j;
i, j
=1, 2,
..., n~.
FurthermoreHence
By (2.14)
and(2.16),
we also have thatNow let
N 1
=Nl
U{ x
EX S‘q ) b3 ~
UR’
andBy (2.8), (2.12)
and(2.15)
it follows thatBy (2.10), (2.17)
and(2.18),
we see thatSo
(2.19)
and(2.20) imply
thatNi satisfy (2.1).
Thiscompletes
theproof
of the lemma. 0
3. . Proof of Theorem 7
Suppose
assertions(ii)
and(iii)
are not true and let us prove(i).
Thecritical set
Kc
is thedisjoint
union ofSc, Me
andPc.
Alsoby
the(PS)
condition, Kc
iscompact.
It is also clear thatSc
is closed andcompact.
We will assume that5c 7~ 0
since otherwise we concludeby Corollary
3. Westart with the
following:
Claim 1
There exist
finitely
manycomponents
ofG~,
sayCZ (i
=1, 2,
... ,n~
andrh > 0 such that
Indeed,
ifnot,
we could find a sequence xi inSc
and a sequence(Ci) i
ofdifferent
components
ofGc
such thatdist(xi , Ci)
~ 0. But then any limitpoint
of the sequence x2 would be a saddlepoint
ofmountain-pass type
forp, thus
contradicting
ourassumption
that assertion(ii)
is false. Claim 1 is henceproved.
Weclearly
may assume that for all i =1, 2,
..., n.Next for each i =
1, 2,
... , n, letS‘~
=,S~
nCi
.They
all arecompact
andmutually disjoint.
Also we have thatClaim ~
There are n
mutually disjoint
open setsN2 (i
=1, 2,
... ,n~
such thatIndeed,
we have two cases to consider.Case 1
Me
=~.
- This is a trivial case.By
the initialassumption
thatKc,
for each i(i
=1, 2,
...,n~
there exists an openneighborhood NZ
of
S’~
suchthat u, v / Ni.
Since the aremutually disjoint compact sets,
we may take the in such a way that
they
are alsomutually disjoint.
Case 2
0.
2014 In this case we are in a situation where we have nmutually disjoint compact
setsS‘~ (i,
=1, 2,
...,?t)
and anonempty
setMe.
Moreover all the
pairs ,5~
nMe, ,S~ n Me (i 7~ j; i, j
=1; 2, t ... , n)
arenot connected
through Me
since assertion(3.3)
is assumed false.Applying
Lemma
10,
we can then find nmutually disjoint
open setsN2
such that(3.3)
is verified. Since
u, v ~ Kc,
we mayclearly
assume thatNi.
Claim 2 is
proved
in both cases.In order to finish the
proof
of Theorem7,
we still need thefollowing
Claim 3
There exists a closed set
F
such thatF separates
u, v whileWe let for each i
(i
=1, 2,
...,, n):
Then observe that for each i
(1 i n)
there must beB(x,
>0)
such that for any connected
component
Uof Gc
withU,
=0.
Otherwise a? is a saddlepoint
ofmountain-pass type
and this contradicts that assertion(ii)
is assumed false. PutClearly
and
T ~
is open relative toaYi.
. Also ~1 8U =~
for anycomponent
U ofGc
with U~ C2.
. Now letClearly, inf -
c. SinceFn Lc separates
u, v and in view of Claim1,
Claim2, (3.5 and (3.7),
we see that we can apply
Lemma 6 with Az
= C2,
G =
G~, Zi
=Yi
=y{, Ti
=T~
for all i =1, 2,
..., n to conclude thatF separates
u, v. On the otherhand,
sinceMe
n =~,
we haveby (3.3)
and(3.5),
that8Yie
nMe
=0.
Thereforeby (3.2)
and(3.6),
we have1
n UM~)
=~.
HenceF
n(M~
US~) _ ~
and Claim 3 isthus
proved.
Finally by
Theorem2,
we see thatF
nPc
and hencePc
must contain acompact
subset thatseparates u, v
whichimplies
assertion(i).
This finishes theproof
of the theorem. DRemark
(c).
Theorem 7 is still true if instead of ~p verifiesonly
The
proof
also shows that the condition~, 1? ~ K~
can bereplaced by S’~
UMe.
We have the
following surprising corollary concerning
thecardinality
ofthe critical set
Kc generated by
the Mountain pass theorem.COROLLARY 11. -
Suppose dim(X)
> 2. Then under ~hehypothesis of
Theorem
7,
oneof
thefollowing
three assertions must be true:~1~ k~
has a saddlepoint of mountain-pass type;
(2)
thecardinality of Pc
is at least thecontinuum;
(3)
thecardinality of M~
is at least the continuum.- 362 -
Proof.
- IfK~
does not contain a saddlepoint
ofmountain-pass type,
then either assertion
(i)
or assertion(iii)
in Theorem 7 is true. Let usfirst assume that assertion
(iii)
is true. Then there exist twodisjoint nonempty
closed subsets ofKe,
say,M;
andM;
which are connectedthrough Me. Clearly dist(M1c, M2c)
= d > 0. For any 0 03C3d,
letMu
=~ x
EX ~ ~ .
ThenM~
~1M~
=~, M~
CM~
. Weclaim that
8Mu
nMe 7~ 0. Otherwise,
there will be twodisjoint
open setsMu
andXBMu
such thatM;
cMu
,Mu
nM;
=0,
,M~
uM;
uM;
cMu
u .This contradicts that
M;, , M~
are connectedthrough M~.
Now let m~ E8Mu
nM~
. Then we have a mapf
: ~ E( 0, d)
- m~ EM~
.Clearly f
isinj ective
whichimplies
assertion(3).
If
instead,
assertion(i)
of Theorem 7 istrue,
thenPc separates u
andv. Let
Xo
be asubspace
of X of dimension 2containing
u, v and letQ
=Pc n Xo.
ThenQ separates
u, v inXo. Clearly,
thecardinality
ofQ
is at least the continuum. Since
Q
CPc,
thisimplies
assertion(2)
of thecorollary.
References
[AR]
AMBROSETTI(A.)
and RABINOWITZ(P.H.)
.2014 Dual variational methods in critical point theory and applications, J. Funct. Anal. 14(1973),
pp. 349-381.[GP]
GHOUSSOUB(N.)
and PREISS(D.)
.2014 A general mountain pass principle for locating and classifying critical points, Analyse Nonlinéaire 6, n° 5(1989),
pp. 321-330.
[Ku]
KURATOWSKI(K.) .
2014 Topology, Vol. II, Academic Press, New York and London,1968.
[PS1]
PUCCI(P.)
and SERRIN(J.)
.2014 Extensions of the mountain pass theorem,J. Funct. Analysis. 59
(1984),
pp. 185-210.[PS2]
PUCCI(P.)
and SERRIN(J.)
.2014 A mountain pass theorem, J. Diff. Eq. 60(1985),
pp. 142-149.[PS3]
PUCCI(P.)
and SERRIN(J.) .
2014 The structure of the critical set in the mountain pass theorem, Trans. A.M.S. 91, n° 1(1987),
pp. 115-132.[H]
HOFER(H.) .
2014 A geometric description of the neighbourhood of a critical point given by the mountain pass theorem, J. London Math. Soc. 31(1985),
pp. 566-570.