A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
A NTJE C HRISTENSEN S TEPHAN R OSEBROCK
On the impossibility of a generalization of the
HOMFLY - Polynomial to Labelled Oriented Graphs
Annales de la faculté des sciences de Toulouse 6
esérie, tome 5, n
o3 (1996), p. 407-419
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- 407 -
On the Impossibility of
aGeneralization of the HOMFLY 2014 Polynomial
to Labelled Oriented Graphs(*)
ANTJE
CHRISTENSEN(1)
and STEPHANROSEBROCK(2)
Annales de la Faculte des Sciences de Toulouse Vol. V, n° 3, 1996
RÉSUMÉ. 2014 Nous montrons que toute generalisation du polynôme
HOMFLY à des graphes nommes orientes
(LOGs)
est presque triviale.Ainsi la géométrie des entrelacs est indispensable pour le calcul du polynôme. De plus cela nous montre que ce polynôme ne peut pas etre utilise comme invariant pour les groupes LOG.
ABSTRACT. - We show that any generalization of the HOMFLY poly- nomial to labelled oriented graphs
(LOGs)
is almost trivial. This means on the one hand that the geometry of links is essential for computingthis polynomial. On the other hand it shows that this polynomial cannot
serve as an invariant for LOG groups.
1.
Motivation,
Definitions and Main ResultsConsider a group
presentation:
D = ...,~~, Ri,
, ... whereeach relator is of the form
xixj
=xjxk
. We canassign
a labelled orientedgraph (LOG) r(D)
to Dby defining
a vertex i for everygenerator
Xi andan oriented
edge
from i to k labelledby j
for the relatorXiXj
= . We also call D a labelled orientedgraph
if there is nodanger
ofambiguity.
From a
regular projection
of an oriented tame link L in1I~3,
you can read off aWirtinger presentation
D of the knot group ~r1(JB?3 B L) (see
forinstance
[8]).
Thispresentation
has the form of a labelled orientedgraph r(D),
where eachcomponent
ofF(D)
is a circle or asingle
vertex. The(*) ~ Reçu le 30 mars 1994
(1) Fakultat fur Mathematik, Ruhr-Universitat Bochum, Universitatsstr. 150, 44780 Bochum
(Germany)
(2) Hauptstr. 38, 65779 Kelkheim
(Germany)
latter shows up, whenever there is a
component
withoutselfcrossings
in Lwhich
only
overcrosses othercomponents.
Let P be the set of those labelled orientedgraphs,
where eachcomponent
is a circle or asingle
vertex. Theorientation on the link
components
induces an orientation on the circles of thecorresponding
LOG. We define C to be the set of the LOGs in P where each circle has an orientation. Not every LOG r E C may be realized as a linkprojection
of a tame link L in(see [10]
for a discussion of the realization of such groups as knotgroups).
There are many statements which are true for link(or knot) complements
in3-space,
but it is not known whetherthey
hold for the standard2-complexes
of some moregeneral
class of LOGs
(for example asphericity
of a knotcomplement
orresidually
finiteness of knot
groups).
LOGs also show up in connection with Whitehead’s
asphericity conjec-
ture
(see
forexample [3], [4]
or[9]).
In this case the LOG F has the form ofa tree and is called a labelled oriented tree
(LOT). Spines
ofcomplements
of ribbon-disks in the 4-ball are
homotopy equivalent
to LOTs[4].
It wouldbe most
interesting
to find new invariants for LOT and LOG groups.Let K be the set of all
regular projections
oforiented,
tame links in the3-sphere
under theequivalence
relation of ambientisotopy.
Tworegular projections
of ambientisotope
links differonly by
a finite sequence of the so-called Reidemeister moves(see
forexample ~1~).
Let
~~+, K- , ~~o
E K be threeprojections
which differonly
in onecrossing
as shown infigure
2. Let T E J( be the trivial knot without anycrossing.
Thefollowing
theorem was shown in 1985by
several differentauthors
(see
forexample [7]):
THEOREM 1.1.2014 There is
exactly
one map P : Jh --~Z~.~~1 , ]
which
satisfies:
(1) P(T)
=1,
(~~ .~ ~ P(I{+)
+.~-1 ~ P(~i_)
+ ~ - = 0 and(3)
P is invariant under Reidemeister moves.It is natural to
ask,
whether there is apurely algebraic
version of this theorem which does not use thegeometry.
Thealgebraic analogues
of linkprojections
are the labelled orientedgraphs
of the set C. Forthese,
theReidemeister moves and the
triples 7~-}-, ~i _ ,
havealgebraic analogues:
(SZ 1 )
If r contains anedge
whose label is also the label of one of itsbounding vertices,
cancel thisedge
andidentify
the twobounding
vertices.
(SZ 1 ) -1 Separate
anarbitrary
vertex a into two verticesa’, a"
and insertbetween them an
edge
witharbitrary
orientation whose label is eithera’
ora"
.(f22)
If r contains twoedges
with the same label andopposite
orienta-tions which have a common
boundary vertex,
cancel theseedges
and
identify
the threebordering
vertices.(f22)-1 Separate
anarbitrary
vertex into three vertices andjoin
themby
a
pair
ofedges
withopposite
orientations such that theresulting
component
of thegraph
isagain
a circle. Label theedges by
thesame
arbitrary
label from the set of vertex labels of F.There is also an
algebraic analogue
of(H3).
Butremarkably enough
wecan prove our theorem without
making
use of this move. Hence we omit itsdescription,
as it is ratherlengthy
because we have todistinguish
betweenthe different combinations of orientations of the arcs.
Let r be a LOG two of whose
components
are oriented intervals withstarting
vertices c, d and end vertices a, b. r is not inC,
it isjust
ahelping
device forconstructing
atriple (F-}-, F-, Fo)
of LOGs in C whichare
analogous
to~i_, !(o)
as follows:r-}- Identify
band d and insert between a and c anedge
labelled b = dwhich is oriented with the orientation of the obtained circle.
r-
Identify
a and c and insert between band d anedge
labelled a = cwhich is oriented
against
the orientation of the obtained cirle.Fo Identify
a and d on the one hand and 6 and c on the other hand.The extremal case may occur where one
(or both)
of the intervals does not contain anyedges,
hence itsstarting
and end vertex are the same. Toinsert an
edge
between them means here toadjoin
aloop
to the vertex.The relation between
F~-,
F- andro
is called a switch relation.Exchang- ing
one of these three LOGsby
any of the other two is called a switch.Let
r(T)
E C be thegraph corresponding
to theprojection
of the trivial knot without anycrossing.
It consists of asingle
vertex.Now we have the tools to
generalize
theorem 1.1 to LOGs in C. Un-fortunately,
the HOMFLYpolynomial
for LOGs in C is nolonger highly
distinctive as it is for links in R. It
only
detects theparity
of the numberof
components:
THEOREM 1.2. -
Let Q
be a mapfrom
C to a commutativering
Rof
Laurent
polynomials
in the variables l and m whichsatisfies:
(1)
=1,
(2) £ . ~{r+)
+~-1 ~ ~(r_) ~
m . = 0(3) Q is
invariant under Reidemeister moves.Then
m2
=(£ + .~-1 )2
inR,
andQ is of
thefollowing form:
~+~-1
if
f E C has an odd numberof compon ents
_
- m if I‘ E C has an even number of components.
This means that the HOMFLY
polynomial
cannot begeneralized
to allLOGs without
getting (almost)
trivial. Hence apurely algebraic
versionof theorem 1.1 is not
possible.
The HOMFLYpolynomial
is not even aninteresting
invariant of the class C of LOGs. Thisimplies
that it is neitheran
interesting
invariant of LOTsby
thefollowing argument:
Assume that S :
.A -~ Z j .~~1 , ]
is a map whichgeneralizes
theHOMFLY-polynomial
to some set A of LOGs which contains the set of LOTs. Letr+
EA
be a LOT. ThenFo
in many cases has twocomponents
where onecomponent
ishomotopic
to acircle,
and every circle appears in this way. Hence the class P has to be contained inA.
LetI),
Ian index
set,
be the set of allgraphs
in C obtained fromro by orienting
thecomponents.
ThenS(I~o)
must be aquotient
ofQ(rb)
for all i E I. Butthen theorem 1.2 says that S is
(almost)
trivial.Here is an overview of the
proof
of theorem 1.2. We startby establishing
the relation between the variables:
LEMMA 1.3. -
Suppose
there is a mapQ from
C to some commutativering
Rof
La’urentpolynomials
in the variables .~ and m whichsatisfies (~~, (2) and (3) of
theorem Thenm2
={.~
+.~-1 ) 2
in R.Next we show the existence of such a
polynomial:
LEMMA 1.4. -
Any
LOG r E C can be reducedby
switches and Reide- meister moves to the trivial LOGI‘(T)
E C.For link
diagrams,
this is obvious:Any
link can be trivializedby switching crossings.
Hence the assertion is true for those LOGs in C which can be realized as links inR~.
We have to show that the other LOGs inC, too,
can be reduced to the trivial LOG
r(T).
Theproof
isby
induction on thenumber of
edges.
We then prove the main theorem
by calculating
the actual values ofQ.
For a
given
LOGF,
lemma 1.4provides
us with a sequence of switches which reduces F to the trivial LOGr(T).
We gothrough
this sequence in the inversedirection, starting
withF(T)
whosepolynomial
isgiven by
condition
(1).
At everystep,
we calculateQ using
formula(2)
andreplacing m2 by ~~’
+.~-1 ~ 2,
as we may because of lemma 1.3.In the last section we mention
briefly
some results aboutgeometric analogues
of the LOGs of C . .2. Proofs
Proof of lemma 1.3
The stated
equality
arises from thefollowing example.
Let F be the LOG
depicted
infigure
3. Take it asFo.
Then the associatedr+
and r- both can be reduced to the trivialgraph by
Reidemeister moves.By
condition(1)
we know thatQ
takes the value 1 on these.Hence, by
condition
(2),
weget
Now consider
r~ depicted
infigure
4.By
the sameargument
as forF,
weget
Now consider r as F- and
I‘~
asF+ ,
seefigure
4. The associatedFo
istrivial. Hence condition
(2) yields
Proof of lemma 1.4
Let n be the number of
edges
in F. We use induction on n. For n =0,
rconsists of k vertices. If k =
1,
then = 1 because of condition(1).
Fork > 1
regard
r asFo.
The associatedr+
and F- can be reducedby (Ql)
to the
graph
whichonly
consists of k - 1vertices,
seefigure
5.Continueing
this process on
I‘+
andF-,
wefinally
reach the trivialgraph r(T).
Now assume all
graphs
with at most nedges
can be reduced tor(T).
Let r contain n + 1
edges.
We have todistinguish
several cases:Case 1
A
component
of F contains a vertex and anedge
which have the samelabel. Then there is an innermost of such
pairs,
that is one that bounds apart F’
of r which does not contain such apair.
Let a be the label of the chosenpair.
Choose anarbitrary edge
b inT~. Depending
on the orientation ofb, regard
F asF-~.
or as F-. The associatedFo
hasonly
nedges,
henceby assumption
it can be reduced tor(T).
F- orI‘+, respectively,
has stilln + 1
edges,
but thepart corresponding
tor’
has oneedge
less thanr’
itself. We
repeat
thisoperation
until there are noedges
left in the thepart
corresponding
toT~.
Then the vertex and theedge
a lie next to each otherand hence can be cancelled
by (S~ 1 ) .
We are left withonly n edges,
and theassumption
holds.Case 2
There is no such
pair
as in the first case. Choose anarbitrary component I of F .
Then all the verticescarrying
the same labels as theedges
inI‘
lie inother
components
of F. Hence all theedges
of r can betransported
to theseother
components by
switches. In each switchrelation, Fo
hasonly n edges
so that the
assumption
holds for it. We are left withr only containing
asingle
vertex which we call a.Case ~.1. . - h contains an
edge
labelled a . Thenregard
F asro . Figure 6
shows the switch relation in the case where a is orientedagainst
the orientation of the circle in which it lies. For the other
orientation,
the switch relation isanalogous.
BothF+
and r- obtain a newedge by
thisoperation,
so thatthey
both have n + 2edges.
But now we can cancel twoedges by
Reidemeister moves, hence we come down to nedges
pergraph,
and the
assumption
holds.Case ~. - r does not contain an
edge
labelled a. Then choose a secondcomponent
andtransport
all itsedges
to othercomponents by
switches.Doing this,
the firstcomponent
does not obtain anyedges,
as there is noedge
a in the secondcomponent.
If the secondcomponent
fits in case2.1,
wecontinue our series of
operations
there. Ifnot,
we treat a thirdcomponent
and so on. If none of thecomponents
fits in case2.1,
we are left with agraph
which does not contain anyedges
at all. Infact,
we do not have togo that far: We can
stop
after the first reduction of the number ofedges,
as the
assumption
then holds.Proof of theorem 1.2
The
proof
isby
induction on(n, r),
wheren(r)
is the number ofedges
of a
given
LOG F EC,
andr(r)
is the number of switches needed toget
the trivial LOGr(T) by
thealgorithm
described in theproof
of lemma 1.4.If we follow the
proof
of lemma1.4,
we see that after any switch the tworesulting
LOGs have either feweredges
than the one we startedwith,
orthey
have the same number ofedges
while the number of switches needed toget
to the trivial LOG is reducedby
one. In case 2.1 this isonly
achievedafter one or two Reidemeister moves. -
For
(n, r)
=(0, 0)
we have F =h(T)
andQ(I‘)
= 1by
condition(1),
hence the
assumption
holds. Now let F E C be a LOG with nedges,
andr switches are needed to
get
the trivial LOGby
thealgorithm
describedin the
proof
of lemma 1.4. Assume that any LOG of C with feweredges
or with the same number of
edges
but fewer switches needed satisfies the assertion of theorem 1.2. Then we know from the discussion above that the two LOGs achieved from Fby
the switchrequired by
thealgorithm
fulfilthe
assumption.
Hence we can calculateQ(r)
from theirpolynomials.
Iffor
example
F =F+
with an odd number ofcomponents,
thenQ(r-) = 1, Q(I‘o) _ -(.~
+.~-1 )/m,
and(2) implies:
There are another five cases to check: r can be
r+,
F- orro,
whereeach time we have to
distinguish
between Fhaving
an odd or even numberof
components.
Appendix:
Geometric Realization of non-link LOGs In[2] Fenn, Rimanyi
and Rourkegeneralized
the notion of the classical braid groups and introduced thepermutation
braid groups.They
aregenerated by
theelementary braids Ui
whichgenerate
the braid groups, and additionalelements T2
which weget
from ~iby replacing
thecrossing by
a blackpoint (fig. 8). Defining
relations are the braid forms of the moves(Q2)
and(SZ3)
and the moves(X2), (X3),
and(~2) depicted
infigure
8.LOGs which cannot be realized as link
projections
can be realized as aclosed
permutation
braid:try
to draw a linkprojection
which realizes apresentation
of a non-linkgroup. You
will findyourself having
toget
onthe other side of an arc without any relation left that tells you to cross it.
In this case introduce a
crossing
ofthe Ti type.
We call such adiagram
a03C3-diagram.
For anexample
seefigure
7.Using
the sameargument
as Alexander used in order to show that every tame link inR~
can berepresented
as a closed braid(see
for instance[6]),
one can show that any
uT-diagram
can be drawn in the form of a closedpermutation
braid. Whenreading
off the LOG from aur-diagram,
thecrossings
ofthe i type
aresimply ignored.
It is easy to show that themoves
depicted
infigure
8 do notchange
the associated LOG.In
[5],
it was shown that this list is in factcomplete:
THEOREM . - Two err
diagrams represent
the same LOGif
andonly if they differ by
afinite
sequenceof
moves(Xl), (X2), (X3),
and(~2).
Hence the classes of LOGs modulo the classical Reidemeister moves
which we treat in this paper are in one-to-one
correspondence
with closedpermutation braids,
and our result is as well valid for these.Reference
[1]
BURDE(G.)
and ZIESCHANG(H.) .
2014 Knots, Walter de Gruyter, 1985.[2]
FENN(R.),
RIMANYI(R.)
and ROURKE(C.) .
2014 The braid-permutation group, In M. E. Bozhüyük, editor, Topics in Knot Theory. Nato A.S.I Series C 399(1993).
[3]
HOWIE(J.) .
2014 Some remarks on a problem of J. H. C. Whitehead, Topology 22(1983),
pp. 475-485.- 419 -
[4]
HOWIE(J.) .
2014 On the asphericity of ribbon disk complements, Trans. Amer.Math. Soc. 289, n°1