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Non-standard couples of angles of rotations

Mostapha Benhenda

To cite this version:

Mostapha Benhenda. Non-standard couples of angles of rotations. 2012. �hal-00669028�

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Non-standard couples of angles of rotations

Mostapha Benhenda

February 10, 2012

Abstract

LetMbe a smooth compact connected manifold, on which there exists an ef- fective smooth circle actionSt preserving a positive smooth volume. We show that onM, the smooth closure of the smooth volume-preserving conjugation class of some Liouville rotationsSα of angleαcontains a smooth volume-preserving diffeomorphismT that is metrically isomorphic to an irrational rotationRβon the circle, withα,±β, and withαandβchosen either rationally dependent or ratio- nally independent. In particular, ifMis the closed annulus [0,1]ה1,Madmits a smooth ergodic pseudo-rotationTof angleαthat is metrically isomorphic to the rotationRβ. Moreover,Tis smoothly tangent toSαon the boundary ofM.

1 Introduction

Let = [0,1]ה1 be the closed annulus andT be a homeomorphism isotopic to the identity. Therotation setof T measures the asymptotic speeds of rotation of the orbits ofT around the annulus. It generalizes the notion of rotation number of a circle homeomorphism, introduced by Poincaré. T is an irrational pseudo-rotation if its rotation set is reduced to a single irrational numberα, called theangleofT. A broad question is raised by Béguin et al. [3]: what are the similarities between the dynamics of the rigid rotationSαof angleαand the dynamics of an irrational pseudo-rotationT of angleα?

From a topological viewpoint, a similarity betweenSαandT has been shown by Béguin et al. [3]: the rotationSα is in the closure of the conjugacy class ofT. Their result is analogous to a theorem by Kwapisz [11] on the torus”2(in this case, the angle of a pseudo-rotation is an element of”2). Jäger [9] and Wang [12] also investigated this broad question. However, there are also possible differences betweenSα andT. From a metric viewpoint, Anosov and Katok [1] constructed a smooth pseudo-rotation of that is metrically isomorphic to an ergodic translation of”2. Béguin et al. [2]

constructed on”2 a pseudo-rotation that is minimal, uniquely ergodic, but with pos- itive entropy. In this paper, we construct a smooth pseudo-rotation of angleαthat is metrically isomorphic to an irrational rotationRβwithα,±β. This is a construction of a non-standard smooth realization, based on the method of approximation by succes- sive conjugations (see [5] for a presentation), a method that is often fruitful in smooth realization problems.

Laboratoire d’Analyse, Geometrie et Applications, Paris 13 University, 99 Avenue J.B. Clement, 93430 Villetaneuse, France. Part of this work was accomplished during the TEMPUS Summer School on dynamical systems held at the PMF University of Tuzla, Bosnia and Herzegovina. I would like to thank Elvis Barakovic and Dino Bojadzija for hospitality in Tuzla, and Muharem Avdispahic, Huse Fatkic, Senada Kalabusic and Amil Pecenkovic for hospitality in Sarajevo. Contact: mostaphabenhenda@gmail.com

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We recall that asmooth realizationof an abstract system (X,f, ν) is a triplet (M,T, µ), whereM is a smooth compact manifold,µa smooth measure onM andT a smooth µ-preserving diffeomorphism of M, such that (M,T, µ) is metrically isomorphic to (X,f, ν) (when (M, µ) and (X, ν) are implied, we just say thatTis metrically isomorphic to f). Moreover, a smooth realization isnon-standardif MandXare not diffeomor- phic.

Suppose there exists an ergodic pseudo-rotationT of angleαthat is a non-standard smooth realization of a rotationRβon the circle. Then the couple (α, β) is called anon- standard couple of angles. In this paper, we show that there exists non-standard couple of angles (α, β), such thatα,±β, withαandβchosen either rationally dependent or rationally independent.

Anosov and Katok [1] showed the existence of an angleα such that (α, α) is a non-standard couple of angles. Fayad et al. [7] showed that for anyαLiouville, (α, α) is a non-standard couple of angles. The question arises about the existence of a non- standard couple of angles (α, β) withα,β.

It is worthy to recall that two ergodic rotationsRαandRβ on the circle are metri- cally isomorphic if and only ifβ=±α. Ifβ=α, the isomorphism is the identity, and if β=−α, an isomorphism is given by a symmetry of axis going through the center of the circle. Therefore, by applying the result of Fayad et al. [7], it becomes trivial to find a non-standard couple of angles (α,−α). Our result shows that if, instead of consider- ing metric automorphisms of the circle, we consider metric isomorphisms between the circle and the annulus, the situation becomes richer: we can haveα,±β, withαand βeither rationally dependent or rationally independent. However,αneeds to be Liou- ville. Indeed, a result by Herman (with a proof published by Fayad and Krikorian [6]) implies that if a smooth quasi-rotationT of the closed annulus has Diophantine angle (i.e. non-Liouville), thenT cannot be ergodic (and a fortiori,T cannot be metrically isomorphic to an ergodic rotation). However, the situation whereαis Liouville andβ is Diophantine, though not addressed in this paper, is not excluded yet. The existence of this situation would reply positively to the open question about the existence of a non-standard smooth realization of a Diophantine circle rotation [5].

More generally, let Mbe a smooth compact connected manifold of dimensiond, on which there exists an effective smooth circle actionStpreserving a positive smooth measureµ. Let Aα be the smooth conjugation class of the rotationSα, and ¯Aα its closure in the smooth topology. IfM =”1and ifαis Diophantine, then ¯Aα =Aαby Herman-Yoccoz theorem [14] (indeed, by continuity, the rotation number of a diffeo- morphismT ∈ A¯αisα). On the other hand, whenαis Liouville, ¯Aα ,Aα. In this paper, ifMhas a dimensiond ≥2, then for some Liouvilleα, we show that ¯Aαcon- tains non-standard smooth realizations of circle rotationsRβ, withα,±β, and withα andβchosen either rationally dependent or rationally independent. In this case, (α, β) is still called anon-standard couple of angles. More precisely, we show the following theorem:

Theorem 1.1. Let M be a smooth compact connected manifold of dimension d ≥ 2, on which there exists an effective smooth circle action(St)t∈”1 preserving a positive smooth measureµ. For any u,v∈”1, for any >0, there exist(α, β)∈”1ה1in a -neighborhood of(u,v), T∈Diff(M, µ), such that T ∈A¯αand such that the rotation Rβ of angleβon”1is metrically isomorphic to T . Moreover,βcan be chosen either rationally dependent or rationally independent ofα.

Theorem 1.1 generalizes the particular caseM=[0,1]d−1ה1:

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Theorem 1.2. Let d ≥ 2, M = [0,1]d−1ה1,µthe Lebesgue measure. For t ∈”1, let St : M → M defined by St(x,s) = (x,s+t). For any u,v ∈ ”1, for any > 0, there exist(α, β)∈ ”1ה1in a-neighborhood of(u,v), T ∈Diff(M, µ), such that for any j∈Ž,(DjT)|∂M=(DjSα)|∂Mand such that the rotation Rβof angleβon”1is metrically isomorphic to T . Moreover,βcan be chosen either rationally dependent or rationally independent ofα.

In the case of the closed annulusM =[0,1]ה1, we obtain:

Corollary 1.3. Let M = [0,1]ה1,µthe Lebesgue measure. For t ∈ ”1, let St : M → M defined by St(x,s) = (x,s+t). For any u,v ∈ ”1, for any > 0, there exist(α, β)∈”1ה1in a-neighborhood of(u,v), T ∈Diff(M, µ)a pseudo-rotation of angleα, such that the rotation Rβ of angleβon”1 is metrically isomorphic to T . Moreover,βcan be chosen either rationally dependent or rationally independent ofα.

To show these results, we suitably modify one of Anosov and Katok’s construc- tions. In [1], they constructed ergodic translations on the torus”h,h≥2, of coordinates (β1, ..., βh), translations that admit non-standard smooth realizations on [0,1]d−1ה1, d ≥2, such thatT|∂M is a rotation of angleα. Moreover, in his construction,α ,βi, i=1, ...,h. In our paper [4], we show that oneβican be an arbitrarily chosen Liouville number. However, this construction does not apply directly to the one-dimensional case. This is why, to obtain our result, though we essentially follow [4], we still need some substantial modifications.

1.1 Definitions

Let Diff(M, µ) be the class of smooth diffeomorphisms ofMpreserving the Lebesgue measureµ. ForB∈Diff(M, µ) and j∈Ž, letDjBbe the jthderivative ofBif j>0, and the−jthderivative ofB−1if j<0. Forx∈M, let|DjB(x)|be the norm ofDjB(x) atx. We denotekBkk=max0<|j|≤kmaxx∈M|DjB(x)|.

Afinite measurable partitionξ¯ of a measured manifold (N, ν) is the equivalence class of a finite setξof disjoint measurable subsets ofN whose union isN, modulo sets ofν-measure zero. In most of this paper, we do not distinguish a partitionξwith its equivalent class ¯ξmodulo sets ofν-measure zero. In these cases, both are denotedξ.

Moreover, all partitions considered in this paper are representatives of a finite measur- able partition. The distance between two finite measurable partitionsξandξ0is defined by:

d(ξ, ξ0)=inf X

c∈ξ,c0∈ξ0

ν(c∆c0)

A partitionξ0issubordinateto a partitionξif any element ofξis a union of ele- ments ofξ0, modulo sets ofν-measure zero. In this case, ifB(ξ) denotes the completed algebra generated byξ, thenB(ξ)⊂ B(ξ0). The inclusion mapi: B(ξ)→ B(ξ0) will be denotedξ ,→ ξ0. This notation also means thatξ0issubordinatetoξ. A sequence of partitionsξnismonotonicif for anyn,ξn ,→ ξn+1. These definitions and properties are independent of the choice of the representativesξandξ0of the equivalence classes ξ¯and ¯ξ0.

A measure-preserving bijective bimeasurable mapT : (M1, µ1,B1)→(M2, µ2,B2) induces anisomorphismof measure algebras, still denotedT : (µ1,B1)→ (µ2,B2). If ξ1, ξ2 are partitions, and ifB1 =B(ξ1) andB2 =B(ξ2), we denoteT : ξ1 → ξ2this induced isomorphism of measure algebras. IfM1 =M212andB1 =B2, thenT

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is ameasure-preserving transformation. Its induced isomorphism is anautomorphism (see [8, p.43] and [13]).

Ametric isomorphism Lof measure-preserving transformationsT1 : (M1, µ1,B1)→ (M1, µ1,B1),T2: (M2, µ2,B2)→(M2, µ2,B2) is a measure-preserving bijective bimea- surable map L : (M1, µ1,B1) → (M2, µ2,B2) such that LT1 = T2L a.e. For con- venience, when the measure is the Lebesgue measure and the algebra is the Bore- lian algebra, we omit to mention the measures and algebras, and we simply say that L: (M1,T1)→(M2,T2) is a metric isomorphism.

Let ¯ξbe a measurable partition andξa representative of this equivalent class mod- ulo sets ofµ-measure zero. Forx∈ M, we denoteξ(x) the element of the partitionξ such thatx∈ξ(x). A sequences of partitionsξnof measurable setsgeneratesif there is a set of full measureFsuch that for anyx∈F,

{x}=F\

n≥1

ξn(x)

This property of generation is independent of the choice of the representativesξnof the equivalent class ¯ξnand therefore, we will say that the sequence of measurable par- titions ¯ξngenerates. LetM/ξdenote the equivalent class of the algebra generated byξ, modulo sets ofµ-measure zero.M/ξis independent of the choice of the representative ξof the equivalent class ¯ξ. If T : M1 → M2 is a measure-preserving map such that T(ξ1)=ξ2µ-almost everywhere, we can define a quotient map:T/ξ1:M/ξ1→M/ξ2. Aneffective actionof a groupGonM is an action such that there is a set of full measureF ⊂ Msuch that for anyx∈ F, there isg ∈Gsuch thatgx ,x. A smooth effective circle action (St)t∈”1 on M can be seen as a 1-periodic smooth flow (St)t≥0, we denoteAα ={B−1SαB,B∈Diff(M, µ)}. WhenM =[0,1]d−1ה1, we consider the periodic flowStdefined by:

St: [0,1]d−1ה1 →[0,1]d−1ה1 (x,s) 7→(x,t+s mod 1)

Fora,b∈”1, let [a,b[ be the positively oriented circular sector betweenaandb, with aincluded andbexcluded.

A sequenceTnofµ-preserving mapsweakly convergestoT if, for any measurable setE,µ(TnE∆E)→0, whereA∆B=(A−B)∪(B−A).

Forγ∈’, we denote:|γ| mod 1=mink∈š|k+γ|

Fort∈”1or’, andA⊂Iה1, we denote

t+A={(x,t+s mod 1),(x,s)∈A}

SupposeM=[0,1]ה1is the closed annulus. Let ˜M =[0,1]גbe the universal covering of M andp2 : [0,1]ג → ’the second coordinate projection. LetT be a homeomorphism of Misotopic to the identity and ˜T its lift to ˜M. Therotation set Rot( ˜T) of ˜T is defined by:

Rot( ˜T)=\

k≥0

[

n≥k

(p2( ˜T( ˜x))−p2( ˜x) n /x˜∈M˜

)

We let the rotation set ofT,Rot(T), be the equivalent class modulo 1 ofRot( ˜T).

IfRot(T)={α}is a singleton, and ifT is isotopic to the identity, thenT is apseudo- rotation. Note that, ifT|∂M =Sα|∂M, thenT is isotopic to the identity. Indeed,

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t ∈ [0,1] 7→ S is a continuous path between the identity map andSα, and by Alexander’s trick, any homeomorphism equal to the identity on the boundary is isotopic to the identity. In this paper, all the diffeomorphisms that we construct are equal to a rotation on the boundary and therefore, they are all isotopic to the identity.

1.2 Basic steps of the proof

The metric isomorphism of theorem 1.2 is obtained as the limit of isomorphisms of finite algebras: indeed, we use the lemma [1, p.18]:

Lemma 1.4. Let M1and M2be Lebesgue spaces and letξ(i)n (i=1,2) be monotonic and generating sequences of finite measurable partitions of Mi. Let Tn(i)be automorphisms of Misuch that Tn(i)ξn(i)(i)n and Tn(i) →T(i)in the weak topology. Suppose there are metric isomorphisms Ln:M1n(1)→M2(2)n such that

LnTn(1)(1)n =Tn(2)(2)n Ln and

Ln+1ξ(1)n(2)n then(M1,T1)and(M2,T2)are metrically isomorphic.

Said otherwise, if we have generating sequences of partitions and sequences of automorphisms Tn(i) weakly converging towards T(i), and if, for any integer n, the fol- lowing diagram commutes:

ξ(1)n

Tn(1) 55 Ln //

 _

ξn(2) _ ii Tn(2)

ξ(1)n+1

Tn+1(1) 22 Ln+1 //ξ(2)n+1ll Tn+1(2) then(M1,T1)and(M2,T2)are metrically isomorphic.

The proof of theorem 1.2 is in two steps. In the first step (lemma 1.5), we determine sufficient conditions on a sequence (Rpn

qnbn)n≥0of periodic rotations of”1such that there exists sequences of finite partitions and automorphisms satisfying the assumptions of lemma 1.4 withM11,M2 =M,Tn(1) =Rpn

qnbn,Tn(2) =Tn, whereTnis also smooth diffeomorphism, and such that the limitT in the smooth topology of the sequenceTn

is smooth, andT ∈A¯αforα=limpn/qn.

In the second step (lemma 1.6), we construct sequences of integers satisfying the conditions of the first step, such that pn/qn → α,bnpn/qn → β, with (α, β) that can be chosen arbitrarily close to any (u,v) ∈ ”1ה1 , and with (α, β) either rationally dependent or rationally independent.

Lemma 1.5. There exists an explicit sequence of integers R1(n)≥n, such that, if there exist increasing sequences of integers pn,qn,an,bn∈Ž, and a sequence sn∈šsuch that, for any integer n,

1. (primality) anbn−snqn=1.

2. (monotonicity) qndivides qn+1and qn<qn+1.

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3. (isomorphism) qndivides an+1−an.

4. (convergence of the diffeomorphism, generation) 0<

pn+1

qn+1

−pn

qn

≤ 1

(bn+1qn)R1(n) then all these assumptions imply that there areα, β∈”1such that

pn

qn

mod1α, pn

qn

bnmod1β

and there is a smooth ergodic measure-preserving diffeomorphism T of M such that for any j ∈ Ž,(DjT)|∂M = (DjSα)|∂M and such that(”1,Rβ,Leb)is metrically isomorphic to(M,T, µ).

Lemma 1.6. For any u,v ∈ ”1, for any > 0, there exist (α, β) ∈ ”1ה1 in a- neighborhood of(u,v), such that there exist sequences of integers pn,qn,an,bn ∈Ž, sn∈šsatisfying the assumptions of lemma 1.5, such that

pn

qnmod1α, pn

qnbnmod1β

Moreover,βcan be chosen either rationally dependent ofαor rationally indepen- dent ofα.

We divide the proof of lemma 1.5 in two main parts. In the first part of the proof, we elaborate sufficient conditions onBn ∈Diff(M, µ), whereM =[0,1]d−1ה1, so that ifTn = B−1n Spn

qnBn weakly converges towards an automorphismT, then there exists a metric isomorphism between (”1,Rβ,Leb) and (M,T, µ). To that end, we apply lemma 1.4: we construct a monotonous and generating sequence of partitionsξnofMand a sequence of isomorphisms ¯Kn : ”1n → M/ξn, whereζn ={[i/qn,(i+1)/qn[,i = 0, ...,qn−1}, such that ¯KnRpn

qn =Tnnand ¯Kn+1|ζ

n =K¯n. In the construction of this isomorphism, assumption 3 is important. Moreover, we will see that the elements of ξn are not the most elementary, because they must be chosen in a way that ensures the monotonicity of the sequence ¯Kn. This condition of monotonicity induces com- binatorial constraints on the elements of the partitionξn. Though it follows a similar scheme, the construction of the sequence ¯Kndiffers from [4], especially because the assumption 1 is new.

In the second part of the proof, we construct diffeomorphismsTn = B−1n S pn

qnBn onM stabilizingξn, obtained by successive conjugations from the rotationSpn

qn. The conjugacy Bn is constructed explicitly. In this second part, we essentially follow [4]

(which elaborated on [7]), except for the obtention of the generation of the sequence of partitions (ξn)n≥1, for which we need to slightly modify the construction.

Another change with respect to [4] is in the construction of the limit anglesαand β, i.e. in the proof of lemma 1.6.

1.3 Construction of the limit angles α and β: proof of lemma 1.6.

1.3.1 The caseβ=pα

Letu,v∈ ”1and >0. Let p0,q0,b0be positive integers such that gcd(b0,q0) =1, and such that:

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p0

q0

−u mod 1

≤ 2,

p0b0

q0

−v mod 1

≤ 2

By the Bezout theorem, there are integersa0,s0, witha0>0, such thata0b0−s0q0= 1.

Suppose we have definedpk,qk,ak,bk,sk, satisfying the assumptions of lemma 1.5, up to the rankk=n, and let us definepn+1,qn+1,an+1,bn+1,sn+1. (we will havesn=1 forn≥1). Letbn+1 =bn.

Letcnbe an integer sufficiently large so thatcn≥(bn+1qn)R1(n)andcn≥bn+12n+1/ (bn = b0 is constant here, but this more general definition is used for the case (α, β) rationally independent). Let

an+1=an+sncnqn Therefore, assumption 3 holds. Let also

qn+1=qnsn(1+cnbn) Therefore, assumption 2 holds. Moreover, we have:

an+1bn+1−qn+1 =1

Therefore, assumption 1 holds, with sn+1 =1. Moreover, let pn+1 = pn qn+1

qn +1.

Sinceqn+1 ≥(bn+1qn)R1(n), we have:

0<

pn+1 qn+1

− pn qn

= 1

qn+1

≤ 1

(bn+1qn)R1(n) Therefore, assumption 4 holds. Moreover,

pn

qn

bn= p0

q0

b0+

n−1

X

k=0

pk+1

qk+1

bk+1−pk

qk

bk

!

= mod 1

p0

q0

b0+

n−1

X

k=0

pk+1

qk+1

− pk

qk

!

bk+1= p0

q0

b0+

n−1

X

k=0

bk+1

qk+1

Since 1/qn+1≤/(2n+1bn+1), we get:

pn qn

bn− p0 q0

b0

≤ 2 Therefore,

pn

qn

bn→β with|β−u| ≤

Likewise,

pn

qn

→α with|α−v| ≤. Moreover, we haveβ=b0α.

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1.3.2 The case(α, β)rationally independent

The beginning of the construction is the same as in the caseβ = pα, except that we take:

bn+1=bn+qn

qn+1=snqn(1+cnbn+cnqn+an) This ensures thatbn→+∞asn→+∞, and that

an+1bn+1−qn+1 =1

It only remains to show that the limit angles (α, β) are rationally independent. To that aim, it suffices to show that the translation of vector (α, β) on the torus ”2 is ergodic. We follow the proof of the ergodicity of the limit translation in [4], with a slight modification. We recall a theorem by Katok and Stepin [10]:

Theorem 1.7(Katok-Stepin [10]). Let U be an automorphism of a Lebesgue space (N, ν), let(Un)n≥1be a sequence of measure-preserving transformations, and let(χn)n≥1

be a sequence of finite partitions of N with measurable elements. Suppose that:

• Unpermutes the elements ofχncyclically.

• (χn)n≥1generates.

• P

c∈χnν(U(c)∆Un(c))=o(1/|χn|)(where|χn|is the cardinal ofχn).

then U is ergodic.

Letγ(n) =(1,bn),gn=gcd(pn,qn). LetΓ(n) ⊂”2a fundamental domain of the flow (T(n))t≥0on”2, whereT(n) is the translation of vectortγ(n). Note that the diameter of Γ(n)is less than 1/bn. Let

Γ0,n= [

0≤t<gn

qn

T(n)Γ(n) We have the lemma:

Lemma 1.8. Letζˆnbe the partition defined by:

ζˆn= (

Γi,n=Tignγ

(n)

qn Γ0,n,i=0, ...,qn

gn −1 )

Tqnpnγ(n) is a cyclic permutation onζˆn, andζˆngenerates.

Proof. Tpnqnγ(n)is a cyclic permutation on ˆζnbecausegn=gcd(pn,qn).

To the vector space’2, we give the normk(x1,x2)k=max1≤i≤2|xi|and we consider its induced norm on”2.

Since

pn+1−qn+1

qn

pn =1 thenpn+1andqqn+1

n are relatively prime. Sincegn+1dividespn+1andqn+1, thengn+1 dividesqn. In particular,gn+1 ≤qn(this is the slight difference with the proof in [4]:

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in [4], we do not have: gcd(pn+1,qqn+1

n ) = 1. But on the other hand, in [4], we have:

gcd(pn+1,qqn+1

n )=gcd(pn+1,qn+1). The important point is that in both cases,gnis small enough).

Moreover, by assumption 3 of lemma 1.5, bn+1qn

qn+1

≤ 1

(bn+1qn)R1(n)−1n→+0 Therefore,

diam(Γ0,n)≤max 1 bn

,gn(n)k qn

!

≤max 1 bn

,qn−1bn

qn

!

n→+0

It shows that ˆζngenerates.

It remains to estimateP

c∈ζˆnµ2

Tαc∆Tpnqnγ(n)c

, whereµ2 is the Lebesgue measure on”2. We have the lemma:

Lemma 1.9. We have:

X

c∈ζˆn

µ2

T(α,β)c∆Tpnqnγ(n)c

=o(gn/qn)=o(1/|ζˆn|)

Proof. We have:

X

c∈ζˆn

µ2

T(α,β)c∆Tpnqnγ(n)c

=X

k≥n

X

c∈ζˆk

µ2

Tpk+1qk+1γ(k+1)c∆Tpkqkγ(k)c =X

k≥n

X

c∈ζˆk

µ2

Tpk+1qk+1γ(k+1)qkpkγ(k)c∆c

Letτnbe the (h−1)-volume of the border of an element of ˆζn. We have:

µ2

Tqk+1pk+1γ(k+1)pkqkγ(k)c∆c

≤τk

pk+1

qk+1

γ(k+1)− pk

qkγ(k)k

pk+1

qk+1

− pk

qk

! γ(k+1)

k

bk+1

qk+1

Moreover,

τn≤2 1 bn

+gnbn qn

!

≤2 1 bn

+qn−1bn qn

!

Therefore,

X

c∈ζˆn

µ2

T(α,β)c∆Tpnqnγ(n)c

=o(gn/qn)

By combining lemmas 1.8 and 1.9, and by applying theorem 1.7, we obtain that the translation of vector (α, β) is ergodic with respect to the Lebesgue measure.

This completes the proof of lemma 1.6.

Let us make one remark. We were not able to show our theorem for anyαLiou- ville, because conditions 1-3 of lemma 1.5 introduce arithmetical constraints on the denominators of the convergents ofα. These conditions are analogous to those, in [4], which limit the set of possible translations of theh-dimensional torus,h≥2, that admit a non-standard smooth realization.

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A sufficient condition forαLiouville to belong to a non-standard couple of angles (α, β) withα ,±β, is the following: if, for the sequence p0n,q0n of convergents ofα, there exist positive integerscn,dn, withdn≤qR(n)n for a fixed sequenceR(n), such that we can write:

q0n+1=1+cnbn+dnan+cndnqn

then there isβ, ±αsuch that (α, β) is a non-standard couple of angles. (in this construction, we takebn+1=bn+dnqn, withdn∈Ž)

The rest of the paper is dedicated to the proof of lemma 1.5. Part of lemma 1.5 is straightforward, namely, the convergence modulo 1 of pqn

n andqpn

nbntowardsαandβ respectively:

Partial proof of lemma 1.5. By assumption 2, forn≥2,qn ≥2. By assumption 3, and sinceR1(n)≥n,pn/qnis Cauchy, and converges.

To show the convergence modulo 1 ofqpn

nbn, we note that assumptions 1 at ranksn andn+1, and assumption 3 at ranknimply thatqndividesbn+1−bn. Indeed, let us writebn+1=bn+k, withkinteger, and let us show thatqndividesk. By the assumption 3 at rankn,an+1=an+cnqn, withcninteger. Therefore,

1+sn+1qn+1=an+1bn+1=(an+cnqn)(bn+k)=anbn+ank+qn(cnbn+cnk) Therefore,

qn sn+1

qn+1

qn

−sn−cnbn−cnk

!

=ank

Thus,qndividesank. Sinceqnis relatively prime withan, thenqndividesk. There- fore,bn/qn=bn+1/qnmod 1. Therefore,

pn+1bn+1 qn+1

−pnbn qn

=mod1

pn+1 qn+1

− pn qn

|bn+1| ≤ 1 (bn+1qn)R1(n)−1 Since forn≥1,qn≥2 andR1(n)−1≥n−1, then the sequencepnbn

qn mod 1

n≥1

is Cauchy, and converges.

To show lemma 1.5, it remains to show that there is a smooth ergodic measure- preserving diffeomorphismT of M such thatT ∈ A¯α and such that (”1,Rβ,Leb) is metrically isomorphic to (M,T, µ).

2 The metric isomorphism

In this section, our aim is to elaborate sufficient conditions onBn∈Diff(M, µ), where M =[0,1]d−1ה1, so that ifTn =B−1n Spn

qnBnweakly converges towards an automor- phismT, then there exists a metric isomorphism between (”1,Rβ,Leb) and (M,T, µ).

To that end, we use lemma 1.4: we construct a monotonous and generating se- quence of partitionsξn of Mand a sequence of isomorphisms ¯Kn: ”1n → M/ξn, where ζn = {[i/qn,(i +1)/qn[,i = 0, ...,qn −1}, such that ¯KnRpn

qn = Tnn and K¯n+1|ζ

n =K¯n.

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ζnis a partition of”1that is monotonic (becauseqndividesqn+1) and that generates (becauseqn→+∞). Letηn={I×[j/qn,(j+1)/qn[,j=0, ...,qn−1}.ηnis a monotonic partition ofM.

The following lemma is straightforward, but important:

Lemma 2.1. Let anand qntwo relatively prime integers, and let Kn: ζn → ηn

hi

qn,i+q1

n

h 7→ I×hian

qn,iaqn+1

n

h

Knis a metric isomorphism such that KnR1 qn =San

qnKn. In other words, the following diagram commutes:

ζn

R1

qn 88 Kn //ηn San

gg qn

This lemma is related with two basic observations: the first is that bothR1

qn andSan

qn

are isomorphic to cyclic permutations of{0, ...,qn−1}(this set is given the counting measure, i.e.µ(A)=#A); the second observation is that two cyclic permutations of the same order are always conjugated.

The following lemma combines lemma 2.1 with the facts thatζn,→ζn+1and ηn,→ηn+1:

Lemma 2.2. Let an,an+1,qn,qn+1 ∈ Ž such thatgcd(an,qn) = gcd(an+1,qn+1) = 1, such that qn divides qn+1 and such that qndivides an+1−an. There exists a partition ηnn+1 ,→ ηn+1 of M stable by San

qn, and there exists a metric isomorphism Knn+1 : ζn → ηnn+1 such that Knn+1 = Kn+1|ζn and such that Knn+1R1

qn = San

qnKnn+1. There exists also a metric isomorphism Cnn+1 : ηn → ηnn+1such that Cnn+1San

qn = San

qnCnn+1 and Knn+1 = Cnn+1Kn. Said otherwise, we have the following commutative diagram:

ζn R1

qn 88 Kn //

Id

ηn gg Sanqn

Cn+1n

ζn

R1

qn 88 K

n+1n //

 _

ηnn+ _1 ll Sanqn

ζn+1

R 1 qn+1 22

Kn+1 //ηn+1 San+1

hh qn+1

Proof. Since gcd(an+1,qn+1)=1, then by lemma 2.1,Kn+1is an isomorphism. More- over, sinceqndividesqn+1, thenζn,→ζn+1. Therefore, we can define the isomorphism Knn+1=Kn+1|ζn. Letηnn+1=Knn+1n). We haveηnn+1,→ηn+1.

It remains to show thatKnn+1R1 qn = San

qnKnn+1 (it automatically implies thatηnn+1 is stable bySan

qn, and that there isCnn+1n → ηnn+1such thatCnn+1San

qn =San

qnCnn+1). Let 0≤i≤qn−1. We have:

Knn+1R1 qn

"

i qn,i+1

qn

"!

=Kn+1R1 qn











qn+1 qn −1

[

k=0

"

i qn + k

qn+1, i

qn +k+1 qn+1

"











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=Kn+1











qn+1qn −1

[

k=0

"

i+1 qn

+ k qn+1

,i+1 qn

+k+1 qn+1

"











=

qn+1qn −1

[

k=0

Kn+1

"1+i qn

+ k qn+1

,1+i qn

+k+1 qn+1

"!

=I×

qn+1qn −1

[

k=0

"

an+1

qn +an+1i

qn +an+1k qn+1

,an+1

qn +an+1i

qn +an+1k qn+1 + 1

qn+1

"

Sincean+1/qn=an/qnmod 1, we get:

Knn+1R1

qn

"

i qn

,i+1 qn

"!

=I×

qn+1qn −1

[

k=0

"

an

qn +an+1i

qn +an+1k qn+1

,an

qn +an+1i

qn +an+1k qn+1 + 1

qn+1

"

Therefore,

Knn+1R1

qn

"

i qn

,i+1 qn

"!

=

qn+1qn −1

[

k=0

San

qn

"

an+1i qn

+an+1k qn+1

,an+1i qn

+an+1k qn+1

+ 1 qn+1

"!

=San

qn









 I×

qn+1 qn −1

[

k=0

"an+1i qn

+an+1k qn+1

,an+1i qn

+an+1k qn+1

+ 1 qn+1

"











=San

qnKnn+1 " i

qn

,i+1 qn

"!

Let us denoteR(n)=Knn+1h

0,q1

n

h. We also denoteRni,n+1 =Sian

qnR(n),i =0, ...,qn−1. R(n) is a fundamental domain of San

qn. Moreover, we have:

Cnn+1n → ηnn+1

"

ian

qn,ian+1 qn

"

7→ Rni,n+1,i=0, ...,qn+1−1 Note also thatCnn+1Ran

qn = Ran

qnCnn+1. Moreover, by assumption 1 of lemma 1.5, anbn/qn=1/qnmod 1. Therefore, we get:

Cnn+1R1

qn =Cnn+1Ranbn qn =Ranbn

qn Cnn+1=R1 qnCnn+1

By iterating lemma 2.2, we get a corollary that is important for the construction of the isomorphism:

Corollary 2.3. For any m >n, there are partitionsηmn ,→ ηmn+1 of M such thatηmn is stable by S 1

qn and there exists an isomorphism Kmnn→ηmn such that KnmR1 qn =San

qnKmn and Knm=Knm+1|ηm

n.

Said otherwise, the following diagram commutes:

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ζmn

R1

qn 77 K

nm //

 _

ηmn _hh Sanqn

ζn+1

R 1 qn+1 22

Kmn+1

//ηmn+1 San+1

ll qn+1

Proof. The proof is similar to the corollary 3.2 in [4].

For anynfixed, the sequence of partitions (ηmn)m≥nmust converge whenm→+∞, in order to obtain a full sequence of monotonic partitions. Moreover, the possible limit sequence (i.e. a possibleηn) must generate. Indeed, these assumptions are required to apply lemma 1.4. However, we can check that none of these assumptions are satis- fied, in general. Therefore, to obtain these assumptions, we pull back the partitionηmn by a suitable smooth measure-preserving diffeomorphismBm. The following lemma, already proved in [4], gives the conditions thatBmmust satisfy:

Lemma 2.4([1],[4]). Let Bm∈Diff(M, µ). Let Am+1=Bm+1B−1m. 1. If Am+1S 1

qm =S 1

qmAm+1and if X

m≥0

qmµ

0,qm∆A−1m+1R(m)

<+∞

then for any fixed n, when m → +∞, the sequence of partitionsξmn = B−1mηmn converges. We denoteξn the limit. The sequenceξnis monotonous and Tn = B−1n Spn

qnBnstabilizes eachξn.

2. If, moreover, the sequenceξn =B−1n ηngenerates, then so doesξn.

Cmm+1 is not continuous in general, and Am+1 is its differentiable approximation.

Lemma 2.4 is the reason why we need forMa manifold of dimensiond ≥2. Indeed, if we tookM=”1, we could not find a diffeomorphismBmsatisfying the assumptions of this lemma, except foran = 1 oran = qn−1. The choicean = 1 gives that the rotationRαon the circle is isomorphic to itself. The choicean =qn−1 gives thatRα is isomorphic toR−α. The existence of these two isomorphisms are consistent with the fact, mentioned in the introduction, thatRαandRβare isomorphic, withαirrational, if and only ifα=±β.

By adding to lemma 2.4 the convergence of the sequenceTn, we obtain the required isomorphism:

Corollary 2.5. If both conditions 1. and 2. of lemma 2.4 hold, and if Tn =B−1n S pn

qnBn weakly converges towards an automorphism T , then (”1,Rβ,Leb)and (M,T, µ)are metrically isomorphic.

Proof. By corollary 2.3,KnmR1 qn =San

qnKnm. By iteration, KnmRbn pn

qn =Sanbn pn qn

Knm Sinceanbn/qn=1/qnmod 1, then

KnmRbn pn

qn =Spn

qnKnm

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