R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
J OHN C. L ENNOX
A. M OHAMMADI H ASSANABADI J AMES W IEGOLD
Some commutativity criteria
Rendiconti del Seminario Matematico della Università di Padova, tome 84 (1990), p. 135-141
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Commutativity
JOHN C. LENNOX - A. MOHAMMADI HASSANABADI - JAMES WIEGOLD
(*)
1. Introduction.
In
[5]
B. H. Neumannproved
thefollowing elegant
result as anapplication
ofRamsey’s
Theorem[6]:
THEOREM A. All sets of
mutually non-commuting
elements of agroup G
are finite if andonly
if G iscentre-by-finite.
See
[1], [3]
and[4]
for some variations on this theme. Wepresent
here some further results of the same
general type,
the differencebeing
that the outcome ofimposing
this or that condition turns out to becommutativity.
To state our first
theorem,
we define an n-set in a group G to be any subset ofcardinality exactly
n : G is said to be aPn-group
if= Y~’ for all n-sets X’ and Y in G.
THEOREM B. For every
positive integer n,
infinitePn-groups
areabelian.
Following
thespirit
of[4],
we consider the classPn
of groups G such that every infinite set of n-sets in G contains apair X,
Y ofdifferent members such that XY = YX. The content of Theorem A is that the
Pi -groups
areprecisely
thecentre-by-finite
groups.(*)
Indirizzodegli
AA.: John C. Lennox and JamesWiegold:
School of Mathematics,University
of Wales,College
of Cardiff, Cardiff CF2 4AG, Wales;A. Mohammadi Hassanabadi:
Department
of Mathematics,University
of Isfahn, Isfahan, Iran.The second author is most
grateful
to the School of Mathematics, Uni-versity
of Wales,College
of Cardiff, for their very warmhospitality during
the
period
of this research.136
We have been able to show that infinite
P*2 -groups
and infiniteP3 -groups
arecommutative,
and believe that our methods will show that infiniteP/J-groups
are abelian when n is not toolarge. Indeed,
non-abelian infinite
P/J-groups
must besomething
like Tarski groups,as Theorems C and D below show.
THEOREM C. For every
% > 2, P:-groups possessing
infinite abeliansubgroups
are abelian. Inparticular, non-periodic
and infinitelocally
finite
P:-groups
are abelia,n forn ~ 2.
COROLLARY 1.
Every
infiniteP*2-group
is abelian.Theorem C tells us that to prove that all infinite
P:-groups
areabelian,
we need do itonly
forfinitely generated periodic
groups.In this
context,
we have:THEOREM D. For every
n ~ 2,
everyfinitely generated P:-group
with a proper infinite
subgroup
is abelian.COROLLARY 2.
Every
infiniteP3 -group
is abelian.2. Proofs.
To prove Theorem
B,
assume for a contradiction that G is aninfinite
Pn-group
with elements xand y
such thatxy =1=
yx. Choose elements ai , a2 , ... , which are different from each other and fromx and y. Then
whence we
get:
for
suitable i, j, k,
m. Thus aiaj = xy, = 01531/ or acm= yx-1
for somei., j, k,
m. Now = y, and define agraph
1~ onthe vertex set ~
by declaring
that there is anedge j oining u
to vif and
only
if and xy.By Ramsey’s
Theorem[6],
r contains an infinitecomplete
sub-graph
or an infinitetotally
disconnectedsubgraph.
If the latterholds,
we have an infinite sequence ui, ... , un, ... of vertices with no
edges
between them. Without loss of
generality,
we many assume that Then since > Thus ’US’U1 = xy. Simi-larly
~y, so that = xy,contradicting
the fact that ~c3 ~ U4 - Thus we conclude that there is an infinite sequencetl, t2, ...
of ele-ments of X such that for all i and
j. All
we need is thefirst n - 1 of these to
falsify
theequation
so that G is not a
Pn-group
after all.The reader will observe that Theorem B holds for
quasigroups
as well as for groups.
Probably
it fails forsemigroups.
Our
proof
of Theorem C rests on thefollowing
technicallemma,
whose
proof
we omit.LEMMA 1. Let T be an infinite subset of an abelian group. Then there exist two infinite sequences al , ... , an , ... and
a’ 17 4%’ 27
... ,I an7 f
...of elements of T such that ~ whenever
i 0 j.
To prove Theorem
C,
we first prove it in the case where G has infinite centre. Let n be aninteger greater
than 1 and G an infinitePn
group withelements x, y
such that Let ... ,tn-2
be figed distinct elements of the centre Z ofG; then,
for any z, w Et2 ,
... , 7Itl
....7 tn-2 w
is an n-set. Fur-ther,
=Xz.,w,
if andonly
if z = z’ and w = since yx.Since we are
assuming Z
to beinfinite,
we can use the Lemmato construct infinite sequences Zl, Z27 ... and wl, w2, ... of elements of Z different from
t1, t2,
... ,tn_2
and such that wheneveri =1= j.
Now consider the n setsXZ¡,W¡.
There areinfinitely
many ofthem,
so thatfor some different i and
j. Writing
out thisequality yields,
after asmall
calculation,
the contradiction that = Thiscompletes
the
proof
of ourspecial
case of Theorem C.To
complete
theproof
ingeneral,
we shall show that the existenceof an infinite abelian
subgroup implies
that the centre is infinite.First,
another technical result.138
LEMMA 2. Let G be a group, y T an infinite subset of G
and g
anelement of G not
commuting
with any element of T. Then T hasan infinite subset S such that S n Sg = 0.
PROOF. We construct the elements of S
by
induction. Choose any element 81 ofT,
when n =0.
Assume that we havefound different elements ... , sn of T such that
... , sn~
r1r’1
1811
S2, ... , =0.
For s,+, we choose any element inthen
{81
s2 , ... ,clearly
fails to intersect s2 , ... , and theinduction is
complete.
The situation is now that G is a
P*
group,n ~ 2, having
an infiniteabelian
subgroup
A. To show that G isabelian,
it isenough
to showthat
A, g)
has infinite centre for every g inA,
andapply
thespecial
case done above to establish that A centralizes g, so that A is central in G and
again
thespecial
caseapplies.
For this it isenough
to showthat every
element g
of G commutes with some element of every infinite subset ofA ;
for we can express A as adisjoint
union of infi-nitely
many infinitesubsets,
thusproducing infinitely
many elements of Acommuting
with g. This will show thatA, g)
has infinitecentre,
since A is abelian.
Thus,
for acontradiction,
let T be an infinite subset of Ahaving
no element
commuting
with g. Choose an infinite subset S of Taccording
to Lemma2; by
theP,*,-property,
there exist different elements ai, ... , Ibi , b2 ,
...,bn_i
of S such thatThe element a1g must appear on the
right-hand
side of thisequation.
It must be of the form or gas. The first three cases are
impossible since g
would be in A and thus commute witheverything
in
A ;
and it is not gas since S m 59 =0.
Thus T must have a non-trivial elemenet
commuting with g
afterall,
and thiscompletes
theproof
of Theorem C.To prove
Corollary 1,
let G be an infiniteP*2-group.
It will beenough
if we show that G iscentre-by-finite,
for then G has infinitecentre and Theorem C
applies.
This is where Theorem A comes in:we prove that (~ is a
Pi -group.
To thisend,
let X be an infinite subset of (~. Then there areinfinitely
many 2-sets{1, x~
with sothat
for some different x
and y
inG,
thatis,
But then xy is one of
1,
x, y or yx and in all cases xy = yx. Thus (~ is aPi -group,
asrequired.
For Theorem
D,
let (~ be afinitely generated P.*-group
with aproper infinite
subgroup H,
andlet g
be any element outside H.It will be
enough
for us to show thatCH(g)
is infinite. This is be-cause Q’- is
generated by finitely
many elements outsideH,
and we have
C,,(gl):= Hl
is infinite so thatby
the sameargument H,
isinfinite,
and so on. Thisprocedure
leads to an infi-nite
subgroup centralizing
gl , g2l ... , thatis,
to an infinite centralsubgroup.
Theorem C nowapplies.
To show that
CH(g)
is infinite wheng ~ H,
we prove that every infinite subset T of .~1 contains an elementcentralizing g,
and reasonas before. If T contains no element
centralizing
g, choose an infinite subse t S of T with S =0;
since (~ is inP:,
there are differentelements ... ,
b1, b2,
... ,satisfying equation (*).
Nowg is outside
.H~,
whereas the ai andbj
are inside.H;
since S n Sg =0, equation (*)
forces us to deduce that alg = gal,just
as in theproof
of Theorem
C;
and theproof
of Theorem D iscomplete.
Finally,
we establishCorollary
2by proving
that every infiniteperiodic Pt-group
contains a non-central element with infinite cen-tralizer. Theorem D then
applies
to show that everyfinitely
gen- erated infiniteperiodic P§J-poup
isabelian,
which isenough
for ourpurposes.
Thus let g be an element of an infinite
periodic P. -group
(~.Firstly,
we shown hat g cannot have cofinite
conjugacy
class. Infact,
moreis true:
LEMMA 3. Let be a
periodic
group with a cofiniteconjugacy
class of elements. Then (~ is finite.
140
PROOF.
Let g
be an element with cofiniteconjugacy
class.By
Ditsman’s
Lemma,
thesubgroup N generated by
the elements notconjugate to g
isfinite,
andG/N
is aperiodic
group in which the non-trivial elements aremutually conjugate.
Butthen,
is ofprime exponent, p
say, and there existelements x, y
ofG/N
withx1l = x-1. Since = x, this means that p =
2, G/N
iselementary
abelian and of order at most 2.
Returning
now to theproof
ofCorollary 2,
let G be an infiniteperiodic P*3-group and g
an element outside the centre of G. Lemma 3 tells usthat g
does not have cofiniteconjugacy class,
so thatinfinitely
many elements of G fail to be
conjugate
to g. Our aim ofproving C~(g)
infinite will be realizedby showing
that every infinite set T of elements notconjugate to g
contains an elementcentralizing
g.Any
T without suchcentralizing
elements has an infinite subset Swith S r1 Sg =
0, and,
since G is in there are different elementsa, b
of S such thatWhat are the
possibilities
on theright
hand side for theelement ag
of the left hand side ~ Not
1, c~, g, g2
or ga,since g
does not centralize a.Not
ba, since g
is notconjugate
to b.Thus ag
must be b. The verysame
reasoning gives
that theelement ga
of theright-hand
side mustalso be
b ; and g
does commute with a after all. Thiscompletes
theproof
ofCorollary
2.Finally,
we shall deal with finitePn-groups
in a later paper. It turns our that almost all finitePn-groups
forgiven n
are commu-tative, though
not all: every group of order t is inPn
whenevern >
t/2.
REFERENCES
[1] M. CURZIO - J. C. LENNOX - A. RHEMTULLA - J. WIEGOLD,
Groups
withmany
permutable subgroups,
to appear in J. Austral. Math. Soc.(Series A).
[2]
L. FUCHS, AbelianGroups, Budapest,
1958.[3] J. R. J. GROVES, A
conjecture of
Lennox andWiegold concerning
super- soluble groups, J. Austral. Math. Soc.(Series A),
35(1983),
pp. 218-220.[4] J. C. LENNOX - J. WIEGOLD, Extensions
of
aproblem of
Paul Erdös ongroups, J. Austral. Math. Soc.
(Series A),
31 (1981), pp. 459-463.[5] B. H. NEUMANN, A
problem of
Paul Erdös on groups, J. Austral. Math.Soc.
(Series A),
21(1976),
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Proc. London Math. Soc., 30 (1930), pp. 264-286.Manoscritto pervenuto in redazione il 17