Inflation of a hyperelastic spherical balloon
Problem is solved in spherical coordinate system
Local orthonormal frame (basis vectors) is denoted (𝐸𝑟, 𝐸𝜃, 𝐸𝜑) in the undeformed reference configuration and (𝑒𝑟, 𝑒𝜃, 𝑒𝜑) in the deformed configuration
No shear => (𝐸𝑟, 𝐸𝜃, 𝐸𝜑) = (𝑒𝑟, 𝑒𝜃, 𝑒𝜑)
𝐹(𝑟) = [
𝜕𝑟
𝜕𝑅 0 0 0 𝑟
𝑅 0 0 0 𝑟 𝑅]
Incompressibility assumption
𝑣 = 𝑉
𝑉 =4
3𝜋𝑅23−4 3𝜋𝑅13 𝑣 =4
3𝜋𝑟23−4 3𝜋𝑟13 𝑅23− 𝑅13= 𝑟23− 𝑟13
Initial thickness 𝐻, final thickness ℎ
(𝑅1+ 𝐻)3− 𝑅13= (𝑟1+ 𝐻)3− 𝑟13
(𝑅1+ 𝐻)3= (𝑅1+ 𝐻)(𝑅12+ 2𝑅1+ 𝐻2) = 𝑅13+ 2𝐻𝑅12+ 𝑅1𝐻2+ 𝐻𝑅12+ 2𝐻2𝑅1+ 𝐻3 𝑅23− 𝑅13= (𝑅1+ 𝐻)3− 𝑅13= 3𝐻𝑅12+ 3𝑅1𝐻2+ 𝐻3
𝑟23− 𝑟13= 3ℎ𝑟12+ 3𝑟1ℎ2+ ℎ3
3𝐻𝑅12+ 3𝑅1𝐻2+ 𝐻3= 3ℎ𝑟12+ 3𝑟1ℎ2+ ℎ3 Divide by 𝐻𝑅12
3 + 3𝐻 𝑅1+𝐻2
𝑅12 = 3ℎ𝑟12 𝐻𝑅12+ 3 ℎ
𝑅1 ℎ 𝐻
𝑟1
𝑅1+ℎ2 𝑅12
ℎ 𝐻
We introduce:
𝜆 = 𝑟1/𝑅1 𝜇 = ℎ
𝐻 3 + 3𝐻
𝑅1+𝐻2
𝑅12 = 3𝜆2ℎ
𝐻+ 3𝜆2ℎ 𝑟1
ℎ
𝐻+ 𝜆2ℎ2 𝑟12
ℎ 𝐻
3 + 3𝐻 𝑅1+𝐻2
𝑅12 = 3𝜆2𝜇 + 3𝜆𝜇2 𝐻
𝑅1+ 𝜇3𝐻2 𝑅12
1 + 𝐻 𝑅1+ 𝐻2
3𝑅12= 𝜆2𝜇 + 𝜆𝜇2 𝐻
𝑅1+ 𝜇3 𝐻2 3𝑅12
𝐻 𝑅1= 𝛾
Finally we obtain with incompressibility:
1 + 𝛾 +𝛾2
3 = 𝜆2𝜇 + 𝜆𝜇2𝛾 + 𝜇3𝛾2 3
Thin balloon: 𝛾 ≪ 1
𝜆2𝜇 = 1
𝐹(𝑟) = 𝐹 = [
𝜕𝑟
𝜕𝑅≈ 𝜇 0 0
0 𝑟
𝑅≈ 𝜆 0
0 0 𝑟
𝑅≈ 𝜆]
𝐹 = [
1/𝜆2 0 0
0 𝜆 0
0 0 𝜆
]
Cauchy stress:
𝜎 = [
𝜎𝑟𝑟 0 0 0 𝜎𝜃𝜃 0 0 0 𝜎𝜑𝜑
]
−𝑝 ≤ 𝜎𝑟𝑟≤ 0
𝜎𝜃𝜃 = 𝜎𝜑𝜑=?
Laplace law:
𝜎𝜃𝜃= 𝜎𝜑𝜑=𝑃𝑟1
2ℎ =𝑃𝜆3𝑅1 2𝐻 =𝑃𝜆3
2𝛾
𝜎 = 𝑃 [
< 1 0 0 0 𝜆3
2𝛾 0 0 0 𝜆3
2𝛾]
Thin balloon
𝛾 ≪ 1 1 𝛾≫ 1 𝜎𝑟𝑟≪ 𝜎𝜃𝜃 𝜎𝑟𝑟 ≪ 𝜎𝜑𝜑
𝜎 ≈𝑃𝜆3𝑅1
2𝐻 [
0 0 0 0 1 0 0 0 1 ]
Incompressible Hyperelasticity
Strain energy density (equation 10.8 Beatty’s paper)
For Neo Hooke
𝛽 = 0 and ℎ(𝐼1− 3) =𝜇20(𝐼1− 3)
𝜎 = 𝜇0𝐹𝐹𝑇+ 𝑐𝐼
Equilibrium
𝜎 = [ 𝜇0
𝜆4+ 𝑐 0 0
0 𝜇0𝜆2+ 𝑐 0 0 0 𝜇0𝜆2+ 𝑐
] =𝑃𝜆3𝑅1
2𝐻 [
0 0 0 0 1 0 0 0 1 ]
𝜎𝑟𝑟≈ 0
𝑐 = −𝜇0 𝜆4
𝜎 = [
0 0 0
0 𝜇0𝜆2−𝜇0
𝜆4 0
0 0 𝜇0𝜆2−𝜇0 𝜆4]
= 𝜇0(𝜆2− 1 𝜆4) [
0 0 0 0 1 0 0 0 1 ]
Finally:
𝑃𝜆3𝑅1
2𝐻 = 𝜇0(𝜆2− 1 𝜆4)
𝑃 = 𝜇02𝐻 𝑅1 (1
𝜆− 1 𝜆7)
In Beatty’s paper:
There is a maximum pressure
Strain energy density of biological tissue 𝛽 = 0 and ℎ(𝐼1− 3) =𝜇2𝛾0[𝑒𝛾(𝐼1−3) − 1]
𝜎 = 2𝜕ℎ
𝜕𝐼1𝐹𝐹𝑇+ 𝑐𝐼
𝜎 = 𝜇0𝑒𝛾(𝐼1−3) 𝐹𝐹𝑇+ 𝑐𝐼
𝜎 = [
𝜇0𝑒𝛾(𝐼1−3)
𝜆4 + 𝑐 0 0
0 𝜇0𝑒𝛾(𝐼1−3) 𝜆2+ 𝑐 0
0 0 𝜇0𝑒𝛾(𝐼1−3) 𝜆2+ 𝑐]
𝐼1= 2𝜆2+ 1 𝜆4
𝑐 = −𝜇0𝑒𝛾(2𝜆2+
1 𝜆4−3)
𝜆4
𝜎 = 𝜇0𝑒𝛾(2𝜆2+
1 𝜆4−3)
(𝜆2− 1 𝜆4) [
0 0 0 0 1 0 0 0 1 ]
𝑃 = 𝜇0𝑒𝛾(2𝜆2+
1
𝜆4−3) 2𝐻 𝑅1 (1
𝜆− 1 𝜆7)
When 𝜆 becomes large
𝑃 ≈ 𝜇0𝑒𝛾(2𝜆2−3) 2𝐻 𝜆𝑅1