Galois Embedding of Algebraic Variety and its Application to Abelian Surface.
HISAOYOSHIHARA(*)
ABSTRACT- We define a Galois embedding of a projective varietyVandgive a cri- terion whether an embedding is Galois or not. Then we consider several re- presentations of the Galois group. Following the methoddevelopedin the first half, we consider the structure of an abelian surface with the Galois embedding in the latter half. We give a complete list of all possible groups andshow that the abelian surface is isogenous to the square of an elliptic curve.
1. Introduction.
The main purpose of this article is to present a new viewpoint for the study of projective varieties. Letkbe the groundfieldof our discussion, we assume it to be the fieldof complex numbers, however most results hold also for an algebraically closedfieldof characteristic zero. Let V be a nonsingular projective algebraic variety of dimensionnwith a very ample divisor D; we denote this by a pair (V;D). Let f fD:V,!PN be the embedding of V associatedwith the complete linear system jDj, where N1dimH0(V;O(D)). Suppose that W is a linear subvariety of PN satisfying dim WN n 1 andW\f(V) ;. Consider the projection pW with the center W, pW:PN >W0, where W0 is an n-dimensional linear subvariety not meetingW. The compositionppWfis a surjective morphism fromV toW0Pn.
Let Kk(V) and K0k(W0) be the function fields of V andW0 re- spectively. The covering map p induces a finite extension of fields p:K0 ,!K of degreeddegf(V)Dn, which is the self-intersection
(*) Indirizzo dell'A.: Department of Mathematics, Faculty of Science, Niigata University, Niigata 950-2181, Japan
E-mail:yosihara@math.sc.niigata-u.ac.jp
2000 Mathematics Subject Classification number : 14N10, 14J99, 14K99
number ofD. It is easy to see that the structure of this extension does not depend on the choice ofW0 but only onW, hence we denote byKW the Galois closure of this extension andbyGWGal(KW=K0) the Galois group of KW=K0. Note that GW is isomorphic to the monodromy group of the coveringp:V !W0, see [4].
DEFINITION1.1. In the above situation we callGWthe Galois group at W. If the extensionK=K0is Galois, we callfandWa Galois embedding and a Galois subspace for the embedding respectively.
DEFINITION1.2. A nonsingular projective algebraic varietyVis saidto have a Galois embedding if there exist a very ample divisorDsatisfying that the embedding associated withjDjhas a Galois subspace. In this case the pair (V;D) is said to define a Galois embedding.
IfWis the Galois subspace andTis a projective transformation ofPN, thenT(W) is a Galois subspace of the embeddingTf. Therefore the ex- istence of Galois subspace does not depend on the choice of the basis giving the embedding.
REMARK1.3. For a projective varietyV, by taking a linear subvariety, we can define a Galois subspace and Galois group similarly as above. Suppose thatVis not normally embedded and there exists a linear subvarietyWsuch that the projectionpWinduces a Galois extension of fields . Then, takingDas a hyperplane section ofV in the embedding, we infer readily that (V;D) defines a Galois embedding with the same Galois group in the above sense.
By this remark, for the study of Galois subspaces, it is sufficient to consider the case whereV is normally embedded.
We have studied Galois subspaces and Galois groups for hypersurfaces in [13], [14] and[15] andspace curves in [2] and[17]. The idea introduced above is a generalization of the ones usedin these studies. In what follows, we give a criterion for an embedding to be Galois or not and show the existence of several representations of the Galois group when (V;D) d e- fines a Galois embedding. Second we study the structure of abelian sur- faces and their Galois groups when the surface has Galois embedding.
Hereafter we use the following notation andconvention:
Aut(V) : the automorphism group of a varietyV ha1; ;ami: the subgroup generatedbya1; ;am
Zm: the cyclic group of orderm
Dm: the dihedral group of order2m (f) : the divisor defined by a functionf jGj: the order of a groupG
: the linear equivalence of divisors 1m: the unit matrix of sizem
G(k;m) : the Grassmanian parametrizingk-planes in m-dimen- sional projective spacePm
em:exp (2p
p 1
=m) r:e6
D1D2 : the intersection number of two divisorsD1 andD2 on a surface
D2: the self-intersection number of a divisorDon a surface [a1;. . .;am] : the diagonal matrix with entriesa1;. . .;am
Acknowledgments. This research was startedwhen the author visited Dipartimento di Matematica, Universita' degli studi di Pavia. He thanks the Department for allowing him to use the facilities. He expresses sincere thanks Professor Pirola who gave him useful suggestions andProfessor Fukuma for giving him useful information. He thanks also the referee for carefully reading the manuscript and giving the suitable suggestions for improvements.
2. Statement of results.
By definition, ifWis the Galois subspace, then each elementsofGWis an automorphism of KKW over K0. Therefore it induces a birational transformation of V over V0. This implies that GW can be viewedas a subgroup ofBir(V=W0), the group of birational transformations ofV over W0. Further we can say the following:
REPRESENTATION1. The element of GW turns out to be regular on V, hence we have a representation
a:GW ,!Aut(V):
(1)
Therefore, if the order ofAut(V) is small, thenV cannot have a Galois embedding. On the other hand, we have examples such that there exist infinitely many distinct Galois embeddings, see Example 4.1.
When (V;D) defines a Galois embedding, we identifyf(V) withV. Let Hbe a hyperplane ofPNcontainingWandD0be the intersection divisor of
V and H. SinceD0D ands(D0)D0, for any s2GW, we see that s induces an automorphism ofH0(V;O(D)).
REPRESENTATION2. We have a second representation b:GW ,!PGL(N;C):
(2)
In the case where W is a Galois subspace we identify s2GW with b(s)2PGL(N;C) hereafter. SinceGW is a finite subgroup ofAut(V), we can consider the quotient V=GW andlet pG be the quotient morphism, pG:V !V=GW.
PROPOSITION2.1. If(V; D)defines a Galois embedding with the Galois subspaceW such that the projection ispW :PN >W0, then there exists an isomorphismg:V =GW !W0satisfyinggpGp. Hence the projec- tion p is a finite morphism and the fixed loci of GW consist of only divisors.
Therefore,pturns out to be a Galois covering in the sense of Namba [7].
Now we present the criterion that (V;D) defines a Galois embedding.
THEOREM2.2. The pair(V;D)defines a Galois embedding if and only if the following conditions hold
1) There exists a subgroupGofAut(V)satisfying thatjGj Dn. 2) There exists a G-invariant linear subspaceL ofH0(V;O(D))of dimensionn1such that, for anys2G, the restrictionsjLis a multiple of the identity.
3) The linear systemLhas no base points.
It is easy to see thats2GWinduces an automorphism ofW, hence we obtain another representation ofGWas follows. Take a basisff0;f1;. . .;fNg ofH0(V;O(D)) satisfying thatff0;f1;. . .;fngis a basis ofLin Theorem 2.2.
Then we have the representation
b1(s)
ls ...
.. . ...
ls ...
...
0 ... Ms
0 BB BB BB BB
@
1 CC CC CC CC A :
Since the representation is completely reducible, we get another re- presentation using a direct sum decomposition:
b2(s)ls1n1M0s: Thus we can define
g(s)M0s2PGL(N n 1;C):
Thereforesinduces an automorphism onWgiven byM0s. REPRESENTATION3. We get a third representation
g:GW !PGL(N n 1;C):
(3)
LetG1andG2be the kernel andimage ofgrespectively.
THEOREM2.3. We have an exact sequence of groups 1 !G1 !G !g G2 !1;
where G1is a cyclic group.
COROLLARY2.4. IfN n1, thenGis a cyclic group.
This implies that the Galois group is cyclic if the codimension of the embedding is one (cf. [15]). Furthermore we have another representation.
REPRESENTATION4. We have a fourth representation d:GW ,!Aut(C);
(4)
where C is a smooth curve in V given by V\L such that L is a general linear subvariety ofPNwith dimension N n1containing W.
Note that there may exist several Galois subspaces andGalois groups for one embedding (see, for example [2]). Generally we have the fol- lowing.
PROPOSITION2.5. Suppose that(V; D)defines a Galois embedding and letWi(i1;2)be Galois subspaces such thatW16W2. ThenG16G2in Aut(V), whereGiis the Galois groupatWi.
COROLLARY2.6. IfV is of general type, then there are at most finitely many Galois subspaces for one embedding.
REMARK 2.7. It may happen that there exist infinitely many Galois subspaces for one embedding if the Kodaira dimension ofV is small. For example, if V P1 anddegD3, i.e., f(V) is a twistedcubic, then the Galois lines form two dimensional locally closed subvariety of the Grass- mannianG(1;3) (cf. [17]).
3. Abelian Surfaces.
We apply the methods developed in the previous sections to the study of abelian varietiesA. In the case where dimA1 anddegD3 or 4, we have studied in detail in [2]. Hereafter we restrict ourselves to the case wheredimA2.
First we consider several necessary conditions that (A;D) defines a Galois embedding.
PROPOSITION3.1. Suppose that A has the Galois embedding with a Galois group G. Let Rp be the ramification divisor for the projection p:A !W0. Then, each component ofRp is a translation of an abelian subvariety of dimension n 1 and Rp(n1)D. In particular, Rp is very ample andRpn(n1)njGj.
COROLLARY3.2. Simple abelian varieties do not have Galois embed- dings.
We have further results. To state them, we needto prepare some no- tation. LetG be a subgroup ofAut(A). Thens2Ghas the complex re- presentation ~szM(s)zt(s), where M(s)2GL(n;C), z2Cn and t(s)2Cn. Fixing the representation, we put G0 fs2Gj M(s)1ng andH fM(s)js2Gg. Then, we have the following exact sequence of groups
1 !G0 !G !H !1:
Suppose thatAhas a Galois embedding with the Galois groupG. Then, BA=G0is also an abelian variety andHG=G0is a subgroup ofAut(B).
Moreover, it is easy to see thatB=His isomorphic toA=GW0. Using the notation above, we have the following.
THEOREM3.3. If A has a Galois embedding, then H is not an abelian group.
COROLLARY 3.4. There exists no abelian embedding of an abelian variety of dimension2, i.e., the Galois embedding whose Galois groupis abelian does not exist.
Note that these phenomena do not appear for elliptic curves. In fact, for an elliptic curve we haveHZm, wherem2;3;4 or 6. Moreover it may happen thatGis an abelian group (cf. [2]). We study the structure ofHin detail in the case of abelian surfaces.
LEMMA 3.5. Let A be an abelian surface. Assume that G is a finite automorphism group of A satisfying that A=G is isomorphic toP2and let p:A !P2be the quotient morphism. Ifdegp10, thenp(l)D is very ample for each line l inP2.
Combining Theorem 2.2 andLemma 3.5 together, we infer readily the following.
COROLLARY3.6. Under the same assumption and notation of Lemma 3.5, the pair(A; D)defines a Galois embedding.
Making use of the results of [5], we obtain the following theorem.
THEOREM3.7. If an abelian surface A has the Galois embedding, then H is isomorphic to one of the following:
1) D3
2) D4
3) the semi-direct product of groups: Z2j H0, where H0D4 or ZmZm (m3;4;6)
To state case(3)more precisely, we put Z2 haiand H0 hb;ci. Then the actions of Z2on H0are as follows:In the former case H0D4, we have ababc2; acac; c41; b21 and bcbc 1. In the latter case H0ZmZm, we have abab 1; acac 1; bm cm1and bccb.
COROLLARY3.8. IfAhas a Galois embedding, then the abelian surface BA=G0is isomorphic toEEfor some elliptic curveE.
REMARK 3.9. Although we have jHj 72, the order jGj can be arbi- trarily large. In fact, for anym2 there exist examples withjGj 8m2in Example 4.5 below.
REMARK3.10. In the case whereW\f(A)6 ;there exist examples of Galois embeddings such thatHis an abelian group, see Remark 4.8 below.
4. Examples.
EXAMPLE 4.1. Let E be the elliptic curve C=V, where V(1;t) is a periodmatrix such that =t>0. Letaandb be the automorphisms ofE defined bya(z) zandb(z)z1=mrespectively, wherez2Candm is a positive integer2. Let Gbe the subgroup ofAut(E) generatedby a;b. Then G ha;bi Dm; the dihedral group of order 2m. Let y24x3pxqbe the Weierstrass normal form ofEandKC(x;y).
Then the fixedfieldof K by G is rationalC(t), where t2C(x). Putting D(t)1 ; the divisor of poles oft, we infer readily that degD2mand (E;D) defines a Galois embedding for eachm.
We present several examples of abelian surfaces, to which we can apply Corollary 3.6. In order to check thatA=Gis isomorphic toP2, we can use the following lemmas. Using the notation in Section 3, we put H1 fM(s)2Hj detM(s)1g andlet F(G) be the set of the fixed points of G, i.e., the set fx2Aj 9s2G; s6id; s(x)xg. Then the lemmas can be statedas follows (cf. [12, Theorem 2.1]):
LEMMA4.2. If H satisfies all of the following conditions, then A=G is rational.
1) H6H1.
2) IfHis cyclic, then no eigenvalue of the generator is1.
3) IfHhas the representation 1 0
0 1
; 1 0
0 1
or
0 1
1 0
; 1 0
0 1
,then F(G)is not a finite set.
Since we have a morphismp:A !A=G, ifA=Gis smooth, thenC20 for each curveC onA=G. Moreover we can sayC2>0 ifHhas an irre- ducible representation (cf. [11, Corollary 3.3.3]).
LEMMA4.3. If A=G is smooth and rational and H is irreducible, then A=G is isomorphic toP2.
Now, let us state examples.
EXAMPLE4.4. LetAbe the abelian surface with the periodmatrix V 1 r2 t tr2
1 r t tr
1 r2
1 r
1 0 t 0
0 1 0 t
;
where =t>0. Clearly we have AEE where EC=(1;t). Letting z2C2andvibe thei-th column vector ofV(1i4), we definetito be the translation onAsuch thattizzvi=m, wheremis an integer2.
Letaandbbe the automorphism ofAsuch that the complex representa- tions are
0 11 0
and r 0
0 r2
respectively. PutG0 ht1;. . .;t4iandG hG0;a;bi. ThenG0 is a normal subgroup ofGandG=G0D3. Clearly we havejGj 6m4. Looking at the fixedloci ofH, we infer thatA=Gis smooth.
EXAMPLE4.5. LetEbe the elliptic curve in Example 4.1, andletAbe the abelian surface EE. We define several automorphisms on A as follows: leta,bandcbe the homomorphisms whose complex representa- tions are
0 11 0
; 1 0
0 1
; 1 0
0 1
respectively. Lett1andt2be translations onAdefined by t1zzt 1
m; 0
and t2zzt 0; 1 m
;
wherez2C2andmis an integer2. PutG0 ht1;t2iandG hG0;a;bi.
ThenG0is a normal subgroup ofGandG=G0D4. ClearlyjGj 8m2. We can make use of Corollary 3.6 andLemma 4.2 to prove that (A;D) define a Galois embedding. In another way we can show this as follows (the proof will be done at the end of the paper): letDand G be the elliptic curves inA defined by
D z
z j z2E
and G z
z
jz2E
;
respectively. Clearly D2G20 andit is easy to see that DG4.
Put Dit1i(D) and Gjt1j(G), where 1i;jm 1. Note that Dit2m i(D) and Gjt2j(G). Then put
DD0D1 Dm 1G0G1 Gm 1;
where we assumeD0Dand G0G. We haveD28m2 andinfer that Dis very ample ifm2. We see from Theorem 2.2 that (A;D) d efines a Galois embedding with Galois group G.
EXAMPLE 4.6. Let Abe the abelian surface C2=V such thatV is the periodmatrix
1 0 i (1i)=2 0 1 0 (1i)=2
; whereie4:
Recalling Theorem 3.7, we define the homomorphisms a,bandc, whose complex representations are
01 01
; 0 1
1 0
; i 0
0 i
respectively. Put G ha;b;ci. Then GZ2j D4 and GAut(A) and A=GP2.
EXAMPLE4.7. LetEbe the elliptic curve Ein Example 4.1 such that tem; m3; 4 or 6. Let A be the abelian surface EE. We define automorphisms onAas follows: leta,bandcbe the homomorphisms whose complex representations are
0 11 0
; t 0
0 1
; 1 0
0 t
respectively. Let G ha;b;ci. Clearly we have a2bmcm1, bccb; caab and baac, and jGj 2m2. Moreover we have GZ2j (ZmZm). PutE1E f0gandE2 f0g E, where 0 is the zero element ofE, then putDm(E1E2), clearly we haveD22m2. It is well known thatDis very ample ifm3. We see from Theorem 2.2 that (A;D) defines a Galois embedding whose Galois group is isomorphic toG.
Let us examine the casem3 in a different point of view. SinceEis defined by the Weierstrass normal form y24x31, we have that C(A)C(x;y;x0;y0), wherey024x031. The automorphismsa,bandc induce the ones ofC(A) as follows:
(i) a interchangesxandx0,yandy0. (ii) b(x)r2xandbfixesy;x0andy0. (iii) c(x0)r2x0 andc fixesx;yandy0.
Therefore, the fixedfieldC(A)G is C(yy0;yy0), andwe have (yy0)D0 and (yy0)D0. Embedding by 3(E1E2) is the
composition of the embedding EE,!P2P2 followedby the Segre embedding P2P2,!P8. Using homogeneous coordinates (X;Y;Z) [resp. (X0;Y0;Z0)] satisfying that xX=Z; yY=Z [resp.
x0X0=Z0;y0Y0=Z0], we can express this embedding as f(X;Y;Z;X0;Y0;Z0)(XX0;YX0;ZX0;XY0;. . .;ZZ0):
Letting (T0; ;T8) be a set of homogeneous coordinates of P8, we can express the Galois subspace by T5T7T4T80.
REMARK4.8. In the situation of the latter half of Example 4.7, letWbe the linear subspace defined byT5 T7T80. Consider the projection pWwith the centerW. In this casef(A)\Wconsists of nine sets of points.
The projectionpWjAinduces the extension of fieldsC(A)=C(W0), which is a Galois extension with the Galois group isomorphic toZ3Z3.
EXAMPLE4.9. Take the elliptic curveEin Example 4.7 such thatm3.
If we take different actions of band c, then we can get different Galois subspaces. To show this, first we recall the result of Galois subspaces (i.e., Galois points) for plane elliptic curves. LetEbe a smooth cubic inP2. If there exists a Galois point, thenEis projectively equivalent to the curve defined by Y2Z4X3Z3 andit has just three Galois points (X:Y:Z)(1:0:0);(0:
p 3
:1) and(0:
p 3
:1). Then we have three projections p:P2 !P1 given by p(X:Y :Z)(Y :Z);
(X:Y
p 3
Z) and(X:Y
p 3
Z), which yields Galois covering pjE:E !P1. By taking these projections, we can findnine Galois sub- spaces for the embedding EEP8. For example, if we take p1(X:Y:Z)(Y:Z) andp2(X:Y:Z)(X:Y
p 3
Z), then the fixed fieldof C(A) by G is equal to C(yu;yu), where u(y0
p 3 )=x0.
Hence the Galois subspace is defined by
T1T5
p 3
T8T4
p 3
T7T20 using the coordinates in the last part of Example 4.7.
5. Proofs.
We use the notation in Introduction. First we prove Representation 1.
Each elements2GWinduces a birational transformation ofVoverW0, we denote it by the same letter s. In the case where dimV1, s is a morphism, so we assume dim V2. For a point P2V we denote by hW;Pithe linear subvariety spannedbyW andP.
LEMMA5.1. IfhW;Pimeets V at d distinct points, thensis regular at P ands(P)is one of the points inhW;Pi \V.
PROOF. The projection p is a finite morphism near p(P) by the hy- pothesis. Sincesis a birational transformation ofVoverW0andpis finite nearp(P) andVis smooth (normal is enough), by Zariski's Main Theorem, we see thatsis a morphism (necessarily an isomorphism) from a suitable
open set of the formp 1(U) containingP. p
IfPdoes not fulfill the assumption of Lemma 5.1, thenp(P)2Dp, where Dpis the divisor of the discriminant ofp. LetUPbe a small neighborhoodof P. Then ZPUP\p 1(Dp) is a set of zero points of some holomorphic function inUP. Lets(s1;. . .;sn) be an expression ofsonUP. Then each si is regular andboundedon UPnZP by Lemma 5.1. By Riemann's Ex- tension Theorem ([3, p. 9]),sis regular atP. Thussis regular onV. Hence it becomes an automorphism ofV.
Next we prove Proposition 2.1. By definition we have a birational mapg:ppG 1:V=GW >W0. LetW1be a general hyperplane ofW0
andletV1p(W1) be a very ample d ivisor. ThenpG(V1) is ample, hence V=GW is a projective variety. Moreover it is normal. Therefore we have only to prove, by Zariski's Main Theorem, that the total transformg(x) [resp. g 1(y)], where x2V=GW [resp. y2W0] do not contain curves.
Since pG is a finite morphism, g(x) contains no curves. Thus, it is suf- ficient to prove that p 1(x) does not contain a curve. Suppose the con- trary. Then, let G be the curve and W1 be a hyperplane in W0 not passing through x. Since p(W1)D, it is a very ample divisor, hence we have p(W1)\G6 ;, which is a contrad iction. Thus g is an iso- morphism. Since pG is a finite morphism, so is p. By the theorem of purity of branch loci, due to Zariski, each component of the loci has codimension one.
Now we prove Theorem 2.2. Suppose that (V;D) defines the Galois embedding f :V,!PN with the Galois subspace W. Then, by definition andRepresentation 1, the first assertion (1) is clear. LetW1be a general hyperplane inW0. ThenV1p(W1) is an irreducible smooth subvariety of codimension one in V by Bertini's theorem, and s(V1)V1 for any s2GW. Take n1 independent general hyperplanes W1i of W0
(i0;1;. . .;n) andlet fi be the section of H0(V;O(D)) defined by the
pullback of W1i by p. Then the linear subspace L generatedby ff0;f1;. . .;fngsatisfies conditions (2) and (3).
Conversely, we assume that conditions (1), (2) and (3) hold.
Letff0;f1;. . .;fNgbe a basis ofH0(V;O(D)), wheref0;f1;. . .;fnare gi- ven in (2). Thenf (f0;f1;. . .;fN) defines an embeddingV,!PN.
Let (X0;X1;. . .;XN) be the corresponding set of homogeneous co- ordinates on PN andlet W be the linear subspace defined by
X0X1. . .Xn0. Since the linear system corresponding toLhas no
base points, we infer thatW\f(V) ;. Therefore the projection induces a morphismp:V !W0. SinceDis ample,pis surjective. HenceKis a fi- nite extension ofK0:k(f1=f0;f2=f0;. . .;fn=f0) and[K:K0]Dn. LetKG be the fixedfieldofKbyG. Then, sinces(fi=f0)fi=f0for anys2G, we see that KGK0. By the assumption jGj Dn we have that KGK0, henceWturns out to be a Galois subspace. This completes the proof.
The proof of Theorem 2.3 is simple. For any s2G1, define a homo- morphism h:G1 !kkn f0g by h(s)ls=ms, where g(s)ls 1n1ms1N n. Sincehis injective andG1is a finite multiplicative sub- group ofk,G1is cyclic.
The proof of Representation 4 is done inductively. Suppose that (V;D) defines a Galois embedding and let Gbe a Galois group for some Galois subspace W. Then, take a general hyperplane W1 of W0 andput V1p(W1). The divisorV1has the following properties:
(i) Ifn2, thenV1is a smooth irreducible variety.
(ii) V1D.
(iii) s(V1)V1for anys2G.
(iv) V1=Gis isomorphic toW1.
Put D1V1\H1, where H1 is a general hyperplane of PN. Then (V1;D1) defines a Galois embedding with the Galois groupG(cf. Remark 1.3). Iterating the above procedures, we get a sequence of pairs (Vi;Di) such that
(V;D)(V1;D1) (Vn 1;Dn 1):
These pairs satisfy the following properties:
(a) Viis a smooth subvariety ofVi 1, which is a hyperplane section ofVi 1, whereDiVi1,V V0 andDV1 (1in 1).
(b) (Vi;Di) defines a Galois embedding, with the same Galois groupG.
In particular, letting C be the curve Vn 1, we get the fourth re- presentation.
Next we prove Proposition 2.5. LethW;Pidenote the linear subvariety spannedbyWanda pointP. Suppose the contrary, i.e.,G1G2. Then, we
infer readily thathW1;Pi \V hW2;Pi \Vfor anyP2V. This implies that hW1\W2;Pi \V hW1;Pi \V. SinceW16W2, we have W1\W2
6W1, therefore we have dim (W1\W2)N n 2. ThusVis containedin a linear subvarietyWe such that dim (pW1(Q)\W)e N n 1, whereQis a general point inW0. Hence we conclude thatVis containedin a hyperplane, which is a contradiction.
We proceedwith the proof of the assertions in Section 3. First we consider Proposition 3.1. By the ramification formula we have KAp( (n1)W1)Rp, whereKAis a canonical divisor ofAandW1 is a hyperplane in W0. Since A is an abelian variety, we have KA0, hence Rp(n1)D.
By the way, we note that ifs2G, whereeszM(s)zt(s), then the matrix partM(s) induces an automorphismbsofAdefined bybszM(s)z.
LetR be a reduced part of the irreducible component ofRp. Then there existss2G(s6id) such thatsjRid. This implies that some translation ofRis containedin the kernel of the homomorphismbs id, wherebsis the homomorphism defined above. This means that R is a translation of an abelian subvariety. Now the proof of Corollary 3.2 is clear, because p:A !W0is not an unramifiedcovering.
Now we consider the proof of Theorem 3.3. Referring to [11, Corollary 3.2.2], sinceB=HPn, we see thatHis generatedby reflections. Suppose that His an abelian group. Then it can be generatedby elements whose complex representations are diagonal matricessi[ai1;. . .;ain] such that aij1 ifi6jandaiiis a root of unity and 61. Take an elements1 and consider the homomorphismh:B !Bdefined byh(z)s1(z) z, where z2Cn. Then h(B) is an elliptic curve E. Since H is assumedto be an abelian group, we have shhs, where s is an automorphism on E induced by s. We infer from this that there exists a morphism h:B=H !P1, which is a contradiction, sinceB=HPn.
In order to prove Lemma 3.5, we make use of the following lemma (cf.
[9], [1]).
LEMMA 5.2. Let (A;D)be a polarized abelian surface, where D is an ample divisor on A with D2 4d6. Then D is d-very ample unless there exists an effective divisorDon A such that
DD d 1D2<DD=2<d1:
By this lemma it is sufficient to prove that there exists no effective divisorDonAsatisfying thatD20 andDD1 or 2. PutDPr
i1miCi,
wheremiis an integer>0 andCiis an irreducible curve (1ir). Since CiCj0 for anyi;j, we have thatCi20 andCi\Cj ;ifi6j. ThusCi
is an elliptic curve andwe infer readily, by taking a translation, thatDis algebraically equivalent to mE, where Eis an elliptic curve and m>0.
SinceDD1 or 2, we getDE1 or 2. In the former case, we consider the morphismg:A !A=E0, whereE0is a subabelian variety, which is a translation of E. Then Dwill be a section of g, which is a contradiction, since the genus of Dis not less than 6. In the latter case, by taking a translation ofE, we may assume that it does not belong to the ramification divisor of p. Put D2d, which is an even number, and GE
fs2Gjs(E)Eg, which is a subgroup ofG. Letf be the rational map associatedwith jDj. Then f(E) is a rational curve, since DE2. Thus there exists s2G such thats(E)E and s6id, therefore GE6 fidg.
Put G=GE hs1; ;sri, wheresi2G(1ir). Then r<dandris a factor of d. If d egp(E)d0, then p(p(E))d0D. We can put p(p(E))E1 Er, where EE1, Eisi(E). Sinces(D)D, we haveDEi2 for 1ir. Therefore we get 2rd0d, henced01 and rd=2. For 1ir we have E1Ei ErEi2 and Ei20.
Since r5, there exists j satisfying that (E1E2)Ej 0 and E1E21. This is a contradiction, because, since (E1E2)22, the di- visorE1E2is ample (cf. [6, Ch.4, (5.2)]).
The proof of Corollary 3.8 is as follows. Looking at Theorem 1 in [5], we infer easily that except in the case (4;2)1Bis a product type. Concerning the exceptional case, the periodmatrix of the abelian surfaceBC2=V has the expression
V 1 0 i (1i)=2 0 1 0 (1i)=2
; where ie4:
PutB0EiEi, whereEiC=(1;i). ThenBis isogenous toB0, henceB is a singular abelian surface, this impliesBF1F2, whereF1andF2are elliptic curves (cf. [10]). Since the scalar matrix [i;i] acts onB,F1andF2 have the automorphism defined by z7!iz, where z2C, hence we have F1F2Ei.
Finally we mention the proof of the last assertion of Example 4.5.
Thanks to Lemma 5.2 we have only to prove that there does not exist an elliptic curveFsatisfying thatDF2 orDF1. IfDiF0 for some iandfor some elliptic curveF, thenFis a translation ofDi, henceFGj4
(j0;. . .;m 1). This implies DF4m. If DiF1 and GjF1,
then we haveDF2m. Therefore we conclude thatDF2m. Clearly
we haveA=GP2. Take three general linesli(i0;1;2) onA=Gandletfi
be the pull back of liby p:A !A=G. We infer from Theorem 2.2 that (A;D) defines a Galois embedding.
Finally we raise problems.
PROBLEMS
(1) In the situation of Introduction find the set fW2G(N n 1;N)jGWSdg.
In particular, is it true that the codimension of the complement of the set is at least two (cf. [8])?
(2) Suppose that dimLin(V)0, W is close toW0 (in the Grass- manian) andW6W0. Then is it true thatKW is not isomorphic toKW0? (cf. [16])
(3) For an embedding (V;D) findthe structure of Galois groupGW for eachW 2G(N n 1;N).
(5) Find all the Galois subspaces for one Galois embedding. Espe- cially findthe rule of arrangements of Galois subspaces (cf. [2], [15]).
(6) Consider the similar subject in the case wheref(V)\W6 ;.
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Manoscritto pervenuto in redazione il 17 settembre 2005