R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
C. M AGNI
Stability estimates for a linearized Muskat problem
Rendiconti del Seminario Matematico della Università di Padova, tome 104 (2000), p. 43-57
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Muskat Problem.
C.
MAGNI (*)
ABSTRACT - In this paper we
study
theproblem
obtainedby
the linearization (in aparticular geometry)
of the classic Muskatproblem,
a freeboundary problem
which models the
piston-like displacement
of oilby
water in a porous medium.We show that the
stability
of the linearproblem depends
on a parameterwhich is the ratio of the viscosities of the two fluids (this fact agrees with the
experimental
behavior of thedisplacement
front). We also prove that the ill-posed
case can be stabilized(according
to Tikhonov)prescribing
apriori
bounds on the solutions.
1. Introduction.
One of the
commonly employed
devices in oil recovery consists in the forcedinjection
of water into the oil reservoir. Theresulting
under-ground motion,
calledpiston-like displacement,
consists in thedisplace-
ment of one fluid
(the oil) by
another(water).
It was modelled in 1934by
M. Muskat
[11, 12] by
means of a freeboundary problem
where the nor-mal
velocity
of the interface isproportional
to the normal derivative of the solution of a Dirichletproblem
for anelliptic operator.
Let Q = U
S~ 2 (t)
U:E(t)
with whereQ 2(t)
are
regions occupied by
oil and waterrespectively
and:E(t)
is theinterface.
(*) Indirizzo dell’A.:
Dipartimento
di Matematica, via Saldini 50, 20133 Mila-no,
Italy.
Let also
where
k =
permeability
of the porous medium to thefluid,
~
=porosity
of themedium,
,u w =
viscosity
ofwater,
¡.,t 0
= viscosity
of oil.Then we define
and let u be the fluid pressure; it
solves,
at any fixedtime,
thefollowing
transmission
problem
whose surface of
discontinuity
moves in timefollowing
the evolutionequation
where V1i is the normal
velocity
ofThe Muskat
problem
consists inequations (1)
and(2).
The
aspect
of thisproblem
we are most interested in is theanalysis
ofthe free
boundary
motion. Thispoint
of view can bejustified by
the ex-perimental
factthat, during
thedisplacement
of a fluid contained in aporous medium
by
another less viscous one, thedisplacement
front may become unstable. In thepresent
case, when ,u w ,u o,protuberances
oc-cur that may advance
through
the average front(this
effect iscommonly
referred to as
fingering).
Anunderstanding
of thefingering phe-
nomenon is crucial as its occurrence poses severe limitations to the effec- tive oil recovery from the reservoir. The process
commonly
used to avoidthis
phenomenon
consists inincreasing
theviscosity
of the waterinject-
ed in the reservoir
by
means of some additives.This
problem
waspreviously
studied in the sixtiesby
N.Verigin [15],
J. S.
Aronofsky [3]
and A. E.Scheidegger [13, 14]. Then,
around1990,
L.Jiang,
Z. Chien and J.Liang [8, 9] published
somesignificant
paperson a weak formulation of the multidimensional case, and on an
approxi- mating
Muskat model.Recently
J. Mossino and F.Abergel
havepub-
lished some
important
papers on theargument.
Some extension of the Muskatproblem
to theparabolic
case has been studiedby
W. Fulk and R. B. Guenther[7],
J. Cannon and A. Fasano[5]
and L. C. Evans[6].
In this paper we
study
therelationship
between the ratio of the vis- cosities and thestability
of the linearproblem
derived from the Muskatproblem.
When the
geometry
of thesystem
issimple,
the Muskatproblem
hasparticular
solutions(more
or lessexplicit).
We consider the case when the domain is a
strip
in II~nHere the surface can be described
by
the functionand,
ifinitially
it is aplane orthogonal
to they-axis, ao (r)
= co , theprob-
lem has the
particular solution, independent
on x,that is to say the free
boundary
remainsalways
anorthogonal y-axis plane;
this can be shownby
routine calculations.The Muskat
problem
can be linearized near this solution:taking
and
taking
the first orderapproximation
to all the functions in the equa- tions(1)
and(2)
we can find theproblem
satisfiedby
theperturbation
t).
In this paper we
study
theproperties
of thisproblem:
we will findthat it turns out to be
well-posed
orill-posed (just
like the backward heat diffusionproblem) depending
on wheter theparameter
y is smaller orgreater
than one. When y > 1 we can stabilize theproblem according
toTikhonov’s definition: in fact we will prove the
stability
of a class of sol- utions with apriori
bound on thegradient.
2. The linearized
problem.
We notice that in
problem (1)
the time appearsonly
as aparameter.
For every fixed t >
0,
we introduce theauxiliary
unknown functionso that
problem (1)
can be reformulated as follows:with the condition
When
a(r, t ) = c ( t ) problem (3), (4)
takes the solution:with
Then we suppose that the relevant
quantities
of theproblem
have an ex-pansion
of thistype
Put such
expressions
inproblem (3), (4)
andkeep
the first orderapproxi-
mation ;
thentaking
the Fourier transform of(3)
and(4), by
routine cal- culation[see 10]
weget
where
The linearization of the
Cauchy problem (2)
leads to thefollowing problem
where
Denoting by o(_~, t)
thepartial
Fourier transform withrespect
to x ofo (x, t )
weget
whose solution is
Taking
the inverse Fourier transform in(8)
we obtain the formal sol- ution toproblem (6).
Let us now formulate
problem (6)
in theappropriate
functionalspaces.
DEFINITION. We say that u E
HS(Rn),
with s ER + , if
where û is the Fourier
transform of
u.The linearized Muskat
problem:
we are
given
findo E C( [ 0 , T], HS(Rn»
such that(6)
is satisfied.Now, saying
that theproblem
is wellposed
means that theoperator
which maps the solution to the
date,
isbijective
and that the inverseoperator
is continuous.
To
study
the linearizedoperator
it is advisable toinvestigate
first theproperties
of thesymbol a(~, t), given by (5).
Let us define for convenience
- If y = I
then~ ~)=0.
We note that in this case the solution is
that
is,
when the fluids have the sameviscosity,
for the linearizedprob-
lem the interface moves at a constant
velocity conserving
the sameshape.
- If y 1 then
t)
> 0 for every(~, t).
It is an
increasing
functionI
withpositive
minimumb(t) =
=
( 1 - y) % I
= 0decreasing
in time and theoblique asymptote
a(t) -
g(t)
=( 1 y) ’ a1 |E I
with an inclination which decreases in time.( 1 + y) a(t) -
It is a
decreasing
functionI
withnegative
maximumb(t) =
decreasing
in time and theoblique asymptote
with an inclination which decreases in time.
Then we obtain some estimates of
a(~, t) I independent
on time.LEMMA 1. There exist
positive
constants m andM, independent
on
tirne,
such that theinequalities
hold
for
every t E[ 0, T].
PROOF.
Using
theexpression
ofg(t)
andb(t)
weeasily
derive the fol-lowing
estimatethat is
In the case y 1 since we have
which
easily implies
that: there existpositive
constants cl , C2 > 0 such thatSo
by using
we arrive at the desired result.
In the case y > 1 since
1 , 1 B 1
we have a(0) a(t) Land
proceeding
as in theprevious
case wecomplete
theproof.
COROLLARY.
Ta(t)
is anelliptic pseudodifferential operator of
thefirst order, for
every t E[ 0, T].
3.
Stability
of the linearizedproblem.
By
lemma 1 weeasily
obtain thefollowing
result.THEOREM 1. For every y ~ 1 and
for
every s E Rn theoperator
defined by
is bounded with bounded inverse.
Moreover there exist two
positive
constantsk1, k2
> 0independent
on
time,
such thatPROOF. From the definition of the
operator
it follows thatand
recalling
that when y - 1 isa(~, t) # 0,
we haveMoreover
Then,
’by
"taking k1 = 1
and1~2 = 1 ,
wecomplete
theproof, a
M m
To go on the
following
lemma is useful.LEMMA 2.
If
y 1 then the estimateholds,
wherePROOF. We know that if y 1
Hence
From the
expression
we obtain the
following
result:THEOREM 2.
If
Y 1 thenIf
y > 1 thenPROOF. If y 1 then
Hence
On the other
hand,
if y >1, recalling
thata(~, t ) 0,
we haveand then
Hence
THEOREM 3.
If y 1
thenproblems (6)
iswell-posed.
If y > 1
thenproblem (6)
isill-posed.
PROOF.
By
theorem 2 it followsthat,
ify 1,
for every there exists aunique corresponding
inverseimage Q (x, t)
suchthat
Then
If y > 1 then the
operator
which mapsQ(x, t ) to Q o (x)
is notsurjective
be-cause a random choice of does not
guarantee
thatTo make it
happen,
forexample, ~o(~)
has to go to zero faster than atinfinity,
and this isjust
a limitation on the choice of data.But even if we were to limit the range of the
operator
in a suitableway, the
problem
would still not be stable. j t B Infact, since,
forevery t
E[ o , T],
the functionnot bounded on
R,
it follows that no constant c > 0 such that’
llellC([0, T], Hs) Clle0))Hs
exists.
4. Stabilization.
In the case y > 1 we will prove that the
ill-posed problem
can be sta-bilized
using
the Tikhonov stabilizationtechnique:
thecontinuity
of theinverse linearized
operator
can be restoredby prescribing
someglobal
bounds to solutions.
We will show that we can find a solution
subspace
with this
property:
if we callWA
the W -image by
A andAw
the restriction of A to the set
W,
theoperator
which is the inverse of
Al,y,
turns out to be bounded.THEOREM 4. Let
where
f ’
is the distributional derivativesoff I.
Then, for
every solutiont) of
the linearized Muskatproblem
suchthat
o ( t )
EW,
andfor
every t E[ 0, T],
we havewhere
PROOF.
Saying
thatE W
means thatFurthermore, saying that o
is a solution means that that isThen
Moreover if y > 1
for
every t
andThen
Finally
THEOREM 5.
If
then the
operator Bw:
is bounded and thefollowing
estimate:
holds,
for every such that 0 1.PROOF. Theorem 4 has shown that
hence
By choosing
we obtain
Because of
we have that
Bj,y
is bounded at theorigin.o
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Well-posedness for
aCauchy problem
associated to time de-pendent free
boundaries with nonlocalleading
terms, Commun. in Partial DifferentialEquations,
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of
the multidimensional Muskatproblem
and existenceof
smooth solutions, C. R. Acad. Sci. Paris, 319, serie I (1994), pp. 35-40.[3] J. S. ARONOFSKY, Trans. Aime, 195, 15 (1952).
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ageneralized
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C. R. Acad. Sci. Paris, 317, serie I (1993),pp. 392-332.
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FASANO,
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Ann. Mat. Pura
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Manoscritto pervenuto in redazione il 10 agosto 1998