R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
G IULIANO A RTICO
U MBERTO M ARCONI
On the compactness of minimal spectrum
Rendiconti del Seminario Matematico della Università di Padova, tome 56 (1976), p. 79-84
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Compactness Spectrum.
GIULIANO ARTICO - UMBERTO MARCONI
(*)
0. Introduction.
Let A be a commutative
ring
with1;
denoteby Spec(A)
the setof all
prime
ideals of Aequipped
with the hull-kerneltopology, by Min(A)
thesubspace consisting
of minimalprime
ideals. Henriksen and Jerison[HJ]
found some sufficient conditions for thecompactness
of
Min(A); subsequently, Quentel [Q]
discovered anequivalent
con-dition. Here we
give
another characterization of thecompactness
of
Min(A ),
which seems togive
morelight
to thetopological situation;
this
characterization,
among otherthings,
allows us to show that the class of(weakly)
Baerrings
coincides with the class ofrings
such that:1)
their minimalspectrum
iscompact;
and2)
everyprime
ideal containsa
unique
minimalprime
ideal.We shall
always
deal withrings
without non-zeronilpotents;
but ofcourse all
purely topological
results areindependent
of thishypothesis.
1. All
rings
are commutative and with 1.Spec(A)
denotes the set ofprime
ideals ofA, equipped
with the Zariskitopology;
i.e.Spec(A)
has as a base of open sets the setsD(a)
=Spec(A ) -
==
~P
EP~ . Thus,
thesubspace Min(A )
of minimalprime
ideals has
f D°(a) D(a)
f1Min(A) :
a EA}
as a base of open sets.For the sake of
simplicity,
we assume that A issemiprime (that is,
A has no non-zero
nilpotents); however,
it will be clear that all results(*)
Indirizzo dell’A.: Istituto di MatematicaApplicata,
Università di Padova, Padova,Italy.
Lavoro
eseguito
nell’ambito deiGruppi
di Ricerca Matematica del C.N.R.80
obtained here hold in the
general
case, with some obvious modifica- tion(e.g.,
the nilradical of A inplace
of the zeroideal).
The sets are
clopen
inMin(A) ; for, denoting by Ann(a)
theannihilator of a, we have
D°(a)
=Min(A) - YO(a)
=VO(Ann(a)) (if
I is an ideal ofA, V(I)
is its hull inSpec(A),
and =V(I)
nt1
Min(A)), (see [HJ]).
Thus is a space with aclopen basis, and, being Toy
it is also a Hausdorff space.LEMMA. Let A be a
semiprime ring,
P aprime
idealof
A. Thefol- lowing
areequivalent:
i)
P is ac minimalprime.
ii)
For everya E P, Ann(a) ~ P.
iii)
For everyfinitely generated
ideal I contained inP,
P.Thus, if
A issemiprime
and I isfinitely generated, Ann(I)
= 0iff vo(l) =
0.PROOF. The
equivalence
ofi)
andii)
isproved
in[HJ,1.1 ] . iii) implies ii): trivial, ii) implies iii):
letgenerate I ;
for each i =
1, ... ,
~cchoose bi
EP;
then b= b1 ... bn
EE Ann (I ) - P.
Plainly, iii)
shows that no minimalprime
ideal can contain afinitely generated
ideal whose annihilator is zero;conversely,
if I isfinitely generated
andAnn(I)
contains a non-zeroelement b, then,
since A issemiprime,
there exist some minimalprime
ideal which does not containb ;
every suchprime necessarily belongs
toTHEOREM. Let A be a
semiprime ring.
Thefollowing
areequivalent:
1)
Thefamily of
a EA}
is au subbasefor
thetopology o f Min(A ).
2) Min(A) is a compact
space.3)
For every element a EA,
there exists af inite
numberof
elements
a1, ... , an E A
such thataai = 0 for
eachi = 1, ... , n
andAnn
..., an,a)
= 0.PROOF.
1) implies 2). By
Alexander’s subbase theorem it isenough
to showthat,
if B is a subset of A such thatn DO(a)
=0y
aeB
then there exists a finite number of elements in
B,
say ... , an such that Let us observe thatx)
coincides with theset of minimal
prime
idealsdisjoint
from B. If S is themultiplicative
set
generated by B,
aprime
ideal doesn’t meet S if andonly
if it doesn’t meet B.Now,
zerobelongs
to Sfor, otherwise,
there would exist aprime ideal,
and then a minimalprime
one,disjoint
from B. Butif zero
belongs
toS,
there exist aI, ..., an E B such that theirproduct
is zero, and so
2) implies 3).
If3Iin(A)
is acompact
space, then is an opencompact set,
and therfore it is a finite union of basic opensets,
thatis
VO(a)
=D°(a1)
u...V D°(an).
SinceDO(ai)
is contained inVO(a)
for each i =
1, ... ,
n, every minimalprime
ideal contains aai , and so aai = 0 for each i.Moreover,
the above relationimplies
thatY°(a1,
..., an,a)
=ø; by
theLemma, Ann(a1,
..., an,a)
= 0.3) implies 1).
Choose a basic open set Let a1,..., an be the elementsgiven by 3). By
theLemma,
the ideal I =(aI, ...,
an ,a)
iscontained in no minimal
prime;
thisimplies
thatD°(a) D Y°(a1)
t1 ... r1r1 but since 0 for
every i
=1,
..., n,equality actually
holds.
REMARK 1. Condition
3)
is due toQuentel [Q, Proposition 4].
REMARK 2. Condition
1)
allows us to state Theorem 3.4 of[H.J]
in the
following
way:« The
following
conditions on aring
A without non zeronilpotents
are
equivalent:
a) Min(A)
iscompact and,
for everyx, y E A,
there exists z E A such thatAnn(x)
t1Ann(y)
=Ann(z).
b)
Thefamily
of sets is a base for the open sets ofMin(A).
c)
For each x E A there exists x’ E A such thatAnn (Ann(x’ ))
-Ann(x).
)>; ;thus,
theassumption
ofcompactness
ofMin(A)
in con-dition
b)
is redundant.Notice also that condition
3)
of the Theorem may be written asf ollows :
3 bis )
For each there exist ai, ... , an such thatAnn (a)
= Ann(Ann(ai ,
... ,1 an))
gwhich thus appears as a
weakening
of conditionc)
in the above theorem.82
2. In paper
[K],
Kist proves theequivalence
of thefollowing
conditions:
a)
There exists a continuous function ofSpec(A)
ontoMin(A )
which is the
identity
onMin(A).
b)
A is a Baerring,
that is the annihilator ideal of each element in A isgenerated by
anidempotent.
This
implies that,
in a Baerring,
everyprime
ideal contains aunique
minimal
prime
ideal and thatMin(.A )
iscompact.
We shall prove that these two last conditions characterize the Baerrings. First,
we needtwo Lemmas:
LEMMA a. Let P be a
prime
idealof
A and letOp
be the intersectionof
theprime
ideals contained in P. ThenOp
coincides with the idealof
the elements
of
A whose annihilator is not contained in P.(For
aproof,
one may look at[DMO,
p.460]).
LEMMA
f3.
Let A be asemiprime ring.
Thefollowing
areequivalent:
i) Every prime
ideal contains aunique
minimalprime
ideal.ii) If
a, b are elementsof
A such that ab =0,
thenAnn(a) + + Ann(b)
= A.iii)
For every a,b E A, Ann (a) + Ann(b)
=Ann(ab) .
PROOF,
i) implies ii).
Ifi) holds,
then for every maximal idealM, OM
is theunique
minimalprime
contained in M. IfAnn(a) + Ann(b)
is contained in
then,
sinceOM
isprime,
either a or bbelong
toOM :
this is absurd for the characterization ofOM given
in Lemma a.ii) implies iii).
Of courseAnn(a) + Ann(b) is‘ contained
inAnn(ab).
If x
belongs
toAnn(ab),
then(xa) b
=x(acb)
= 0 and so there existand
z E Ann(b)
such that 1 = y-f-
z, hence x = xy+
xz,with and
xZEAnn(b).
iii) implies i).
If P is aprime ideal,
let us see thatOp
isprime,
too. In
fact,
if abbelongs
toOp,
there exists an element x EAnn(ab)
that doesn’t
belong
to P.According
toiii), x
== ~+
z,with y
eAnn(a)
and z E
Ann(b);
hence eitherP,
orP; by
Lemma cx, this isequivalent
to orb E 0 p .
Now we can state the
following
theorem.THEOREM. Let A be a
semiprime ring.
Thefollowing
areequivalent : 1 )
A is a Baerring.
2) Every prime
ideact contains aunique
minimalprime
ideal andMin(A)
is acompact
space.3)
retractof Spee (A ),
that is there exists ac continuousfunction 99 of Spec(A)
ontoMin(A)
which is theidentity
onMin(A ).
PROOF.
1) implies 2). Trivially
if A is a Baerring,
condition3)
of Theorem 1 is satisfied and then
Min(A)
is acompact
space. Let ussee that every
prime
ideal contains aunique
minimalprime ideal, proving
that conditionii)
of Lemmafl
holds. Let a, b be elements such that ab = 0 andlet e, f
be theidempotents
whichgenerate Ann(a)
and
Ann(b), respectively.
Since b EAnn(a)
=(e),
there exists c E Asuch that b = ce, hence be = ce2 = ee = b and so
(1- e) b = 0.
Then(1- e) E Ann(b) _ (f),
so thatAnn(a) + Ann(b) = (e) + ( f )
= A.2) implies 3). Lest 99
be the map fromSpec(A)
toMin (A )
definedby (p(P)
=Ope
SinceMin(A)
iscompact,
to prove that (p is a continuous function it isenough
to show that is a closed set(Theorem 1).
This is trivial
because,
from the characterization ofOp given by
theLemma a, we have
qJ+-[DO(a)]
=V(Ann(a)).
3) implies 1).
First we provethat,
ifQ
is a minimalprime
idealcontained in a
prime
idealP,
thenQ
is theimage
of Pby
the retraction 99.In fact P E that is contained in
gg’[99(Q)],
so that99(p)
==
Q.
Hence the retraction maps aprime
ideal into theunique
minimal
prime
ideal contained init;
thereforeV(Ann(a))
=is a
clopen set;
thenAnn(a)
is a direct summand inA,
because in asemiprime ring
an ideal I is a direct summand if andonly
ifV(I)
isa
clopen
set.REMARK 1. A Baer
ring
A isnecessarily semiprime:
assume xnilpotent,
and let n be the smallest nonnegative integer
such thatxn = 0 . We want to show that n =
11
i.e. x = 0 .For, otherwise,
wehave since A is
Baer, Ann(x) = (e),
==
( f ),
withe, f idempotents ;
since x EAnn (xn-l )
then x =x f ,
whichimplies
xn-1=xn-lj
=0, contraddicting
theminimality
of n.REMARK 2. The
ring
A =K[x,
where .g is a field and x, yare indeterminates over
.g,
is aring
whose minimalspectrum
is com-pact,
but it is not a Baerring.
A is a noetherianring;
thenMin(A)
84
is
finite,
hencecompact (and discrete).
It is easy to see that A. is asemiprime ring
with no non trivialidempotents. Using
the fact thatK[z, y]
is aunique
factorizationdomain,
it can be shown thatAnn(x + (xy))
isgenerated by (y + (xy)),
so that A. is not a Baerring.
REMARK 3. If .~ is a
topological
space, denotes thering
ofall real valued continuos functions on
.X;
.~ is said to be anF-space
when every
prime
ideal ofC(X)
contains aunique
minimalprime
ideal[GJ, 14.25].
X is said to bebasically
disconnected if the closure of every cozero-set is an open set[GJ, lH].
One caneasily
prove thatC(X )
is a Baerring
if andonly
if X isbasically
disconnected. There existI’-spaces X
that are notbasically disconnected,
for instance[GJ, 6M, 14.0].
Hence there arerings
in which everyprime
ideal contains a
unique
minimalprime ideal,
withoutbeing
Baerrings.
REFERENCES
[DMO]
G. DE MARCO - A. ORSATTI, Commutativerings in
which everyprime
ideal is contained in a
unique
maximal ideal, Proc. Amer. Math. Soc., 30(1971),
pp. 459-466.[GJ]
L. GILLMAN - M. JERISON,Rings of
continuousfunctions,
Van Nostrand, Princeton, N. J. (1960).[HJ]
M. HENRIKSEN - M. JERISON, The spaceof
minimalprime
idealsof
a commutative
ring,
Trans. Amer. Math. Soc., 115(1965),
pp. 110-130.[K]
J. KIST, Two characterizationsof
cmnmutative Baerrings,
PacificJournal of Math., 50
(1974),
pp. 125-134.[Q]
Y. QUENTEL, Sur lacompacité
du spectre minimal d’un anneau, Bull.Soc. math. France, 99
(1971),
pp. 265-272.Manoscritto