On the structure of Milnor K-groups of certain complete discrete valuation fields
par MASATO KURIHARA
RÉSUMÉ. Pour un
exemple
typique de corps de valuation discrètecomplet
K de type II au sens de[12],
nous déterminons les quo- tientsgradués gri K2(K)
pour tout i > 0. Dansl’appendice,
nousdécrivons les
K-groupes
de Milnor d’un certain anneau local à l’aide de modules de différentielles, qui sont liés à la théorie de lacohomologie
syntomique.ABSTRACT. For a
typical example
of acomplete
discrete valuationfield K of type II in the sense of
[12],
we determine thegraded
quotientsgri K2 (K)
for all i > 0. In theAppendix,
we describethe Milnor
K-groups
of a certain local ringby
using differentialmodules,
which are related to thetheory
of syntomiccohomology.
0. Introduction
In the arithmetic of
higher
dimensional localfields,
the MilnorK-theory plays
animportant
role. Forexample,
in local class fieldtheory
of Katoand
Parshin,
the Galois group of the maximal abelian extension is describedby
the MilnorK-group,
and the information on the ramification is in the MilnorK-group,
at least for abelian extensions. So it is veryimportant
toknow the structure of the Milnor
K-groups.
Let K be a
complete
discrete valuationfield,
vK the normalized additive valuation ofK, OK
thering
ofintegers,
mK the maximal ideal ofOK,
and F the residue field.
For q
>0,
the MilnorK-group
has anatural filtration
Ui Kr (K)
which isby
definition thesubgroup generated by {1
+m’, KX,
..., for all i > 0(cf.
We are interested in thegraded quotients
= The structuresof
gr’
were determined in Bloch[1]
and Graham[5]
in the case that K isof
equal
characteristic. But in the case that K is of mixedcharacteristics,
much less is known on the structures
of gr2 Kr (K). They
are determinedby
Bloch and Kato
[2]
in the range that 0 ieKp/(p-1)
where eK =vK(p)
is the absolute ramification index.
They
are also determined in the caseeK =
VK(P)
= 1(and
p >2),
in[14]
for all i > 0. This result wasgeneralized
in J. Nakamura[17]
to the case that K isabsolutely tamely
ramified
(cf.
also[16]
where somespecial totally
ramified case wasdealt).
We also remark that I. Zhukov calculated the Milnor
K-groups
of somehigher
dimensional local fields from a differentpoint
of view([24]).
On the other
hand,
we encounteredstrange phenomena
in[12]
for certainK
(if
K is oftype
II in theterminology
of[12]). Namely,
if K is oftype
II,
for some q we havegri Km (K)
= 0 for some i(even
in the case~F :
FP]
=pq-1),
which neverhappens
in theequal
characteristic case. Atypical example
of acomplete
discrete valuation field oftype
II is K =KO’Vp7T-)
where
Ko
is the fraction field of thecompletion
of the localization ofZp [T]
atthe
prime
ideal(p).
The aim of this article is to determine allgri K2 (K)
for this
typical example
oftype
II(Theorem 1.1),
and togive
a directconsequence of the theorem on the abelian extensions
(Corollary 1.3). (For
the structure of the
p-adic completion
of see alsoCorollary 1.4).
I would like to thank K.Kato and
Jinya
Nakamura. The main resultof this article is an answer to their
question.
I would also like to thank I.B.Fesenko for his interest inmy old
results on the MilnorK-groups
of com-plete
discrete valuation fields. This paper wasprepared during
mystay
atUniversity
ofNottingham
in 1996. I would like to express my sinceregrat-
itude to theirhospitality,
and to thesupport
fromEPSRC(GR/L06560).
Finally,
I would like to thank B. Erez for his constant efforts to edit the papersgathered
on the occasion of theLuminy
conference(*).
Notation
For an abelian group A and an
integer
n, the cokernel(resp. kernel)
ofthe
multiplication by
n is denotedby A/n (resp. A[n]),
and the torsionsubgroup
of A is denotedby Ators.
For a commutativering R,
R’ denotesthe group of the units in R. For a discrete valuation field
K,
thering
ofintegers
is denotedby OK,
and the unit group ofOK
is denotedby UK.
For a Galois module M and an
integer
r EZ, M(r)
means the Tate twist.We fix an odd
prime
number pthroughout
this paper.1. Statement of the result
Let
Ko
be acomplete
discrete valuation field with residue field F. Weassume that
Ko
is of characteristic 0 and F is of characteristic p >0,
andthat p is a
prime
element of theinteger ring OKo
ofKo.
We further assumethat
[F : FP]
= p and p is odd.We denote
by S2F
the module of absolute Kahler differentials Fora
positive integer
n, we define thesubgroups BnS2F by
= dF cSZF
and =
Bn+152F/B1SZF
for rt > 0 whereC-1
is the inverse Cartier operator(cf. [6] 0.2).
Thengives
anincreasing
filtration onS2F.
We fix a
p-base t
ofF, namely F
=FP(t) . (Recall
that we areassuming [F : FP]
=p.)
We take alifting
T EUKo
of thep-base t
ofF,
and defineK = This is a discrete valuation field of
type
II in the sense of[12].
In this
article,
westudy
the structure ofK2(K)
=K2m(K).
Asusual,
we denote the
symbol by (which
is the class of a 0 b inK2 (K) = KX 0 KX j J
where J is thesubgroup generated by
a ~(1 - a)
for a EKX B ~l~).
We write thecomposition
ofK2(K) additively.
For i >0,
we define
U2K2(K)
to be thesubgroup
ofK2(K) generated by
where
UK
= 1 + We are interested in thegraded quotients
We also use a
slightly
differentsubgroup Ui K2(K)
whichis, by definition,
the
subgroup generated
We haveIt is known that
K2(K)/U1K2(K) - K2(F). Further, by
Blochand Kato
[2] (cf.
Remark1.2), gri K2(K)
is determined in the range 1 i p + 1 in our case(note
that eK =vK(p)
=p).
In thisarticle,
we prove Theorem 1.1. Weput
7r =f/PT
which is aprime
elerraentof OK.
(1) If
i > p + 1 and i isprime
to p, we havegr’ K2(K)
= 0.(2)
For i =2p,
we haveLf2PK2(K)
C and thehomorraorphism
x ~ the class
of ~l
+p7PY, 7r}
(x
is alifting of
x toOK)
induces anisomorphism
(3)
For i = np such that n >3,
we haveLfnPK2(K)
CUnp+1 K2(K),
andthe
homomorphism
the classof (iF
is alifting of x
toOK) gives
anisorrcorphism
Remark 1.2. We recall results of Bloch and Kato
[2].
Let K be acomplete
discrete valuation field of mixed characteristics
(0, p)
with residue fieldF,
and 7r be a
prime
element ofOK.
Thehomomorphisms
and
(x and y are liftings
of xand y
toOK,
and the classes of thesymbols
do notdepend
on thechoices)
aresurjective. They
determined the kernels of the abovehomomorphisms
in the range 0 iep~(p - 1)
where e =vK(p).
In
particular,
for ourK,
the abovehomomorphisms (2)
and(3)
induceisomorphisms
We also remark the
surjectivity
of(2)
and(3) implies
thatis
generated by
theimage
of and thatis
generated by
theimage
of in our case.Let
U’(K2(K)lp)
be the filtration onK2(K)lp,
induced from the fil- trationUiK2(K).
Weput gr’(K2(K)lp) =
Bloch and Kato
[2]
also determined the structure ofgrz (K2 (K) /p)
for gen-eral
complete
discrete valuation field K. In our case,(2)
and(3)
induceisomorphisms
, -, , , - , - , ,
These results will be used in the
subsequent
sections.Corollary
1.3. K does not have acyclic
extension which istotally ramified
and which is
of degree p3.
Proof. Let
M/K
be atotally ramified, cyclic
extension ofdegree p~.
Inorder to show n
2,
sinceM/K
iswildly ramified,
it suffices to showthat
p2(U1K2(K)/U1K2(K)nNM/KK2(M))
= 0 whereNM/K
is the normmap. In
fact,
if K is a 2-dimensional local field in the sense of Kato[8]
andParshin
[18],
this is clear from theisomorphism
theorem of local class fieldtheory
In
general
case,U1K2(K)/U1K2(K) fl N M/KK2(M)
contains an elementof order
p~ by
Lemma(3.3.4)
in[12].
So it suffices to showWe will first prove that
UP+2K2(K)
CN M / K K 2 (M). If j
issufficiently large, UK
= 1 +mK
is in(KX)pn,
soUjK2(K)
is inpnK2(K),
hencein
NM/KK2(M).
Soby
Theoreml.l,
in order to proveUp+2 K2 (K)
cNM/KK2(M),
it suffices to show is inNMIKK2(M).
SinceM/K
is
totally ramified,
there is aprime
element ~r’ ofOK
such that 7r’ ENM/K(MX). Hence,
thesubgroup ,7rl
is contained inNM/KK2(M).
We note that is
generated by 7r’l
andU’K2 (K)
for all i > 0.Hence,
Theorem l.l also tells us that isgenerated by 7r’l
and
Uj K2 (K)
forsufficiently large j.
This shows that is inIn order to describe the structure of
K2(K),
we need thefollowing
ex-ponential homomorphism
introduced in[12]
Lemma 2.4(see
also Lemma2.2 in
§2).
We defineK2(K)^ (
resp.f2bK )
to be thep-adic completion
ofK2 (K) (resp. °bK). Then,
there is ahomomorphism
such that a - db H
f exp(p2ab),bl
for a EOK
and b E Hereexp(x)
=Concerning K2(K)^,
we haveCorollary
1.4. Let K be as in Theorem l.l.Then,
theimage of
is and the kernel is the
Zp -module generated by
da with a EOK
and
b(pdJr /Jr - dT/T)
with b EOK.
We will prove this
corollary
in the end of§3.
2.
p-torsions
ofK2(K)
Let (
be aprimitive p-th
root ofunity.
We defineLo
=Ko (()
andL =
K(()
=LO(1r)
where 7rP =pT
as in Theorem 1.1.Let be the filtration on
K2 (L)
definedsimilarly (UiK2(L)
isa
subgroup generated
+mi, L" }
where mL is the maximal ideal ofOL).
SinceL/K
is atotally
ramified extension ofdegree
p -1,
we havenatural maps
U’K2(K)
~U(p-1)iK2(L).
We also use the filtration on
K2 (L) /p,
induced from the filtrationU2K2(L).
If 7y is inUi(K2(L)jp) B U’+’(K2(L)lp),
we writefilL(’q)
= i. We also note that sinceL/K is
ofdegreep-1,
2013~U(p-1)i(K2(L)/p)
isinjective.
Our aim in this section is to prove the
following
Lemma 2.1.Lemma 2.1.
Suppose
a E, "’.,
. - ...
Ko’-
. - , , . , . , . , , ,We introduced the map
expp2
inCorollary 1.4,
but moregenerally,
wecan define
expp
as in thefollowing lemma,
whoseproof
will be done inAppendix Corollary
A2.10(see
also RemarkA2.11).
The existenceofexpp2
follows at once from the existence of
expp.
For moregeneral exponential homomorphism (exp,
with smallervK(c)),
see[15].
Lemma 2.2. Let K be a
complete
discrete valuationfield of
mixed char- acteristics(O,p).
As in91,
we denoteby (resp.
thep-adic completion of K2(K) (resp. Ql
Then there exists ahomomorphisms
such that a -
(exp(pab) b} for a
EOK
and b EOK B f 0 1 -
We use the
following
consequence of Lemma 2.2.Corollary
2.3. In the notationof Lemma 2.2,
we have- - 1) - - __ ,_ -,
for
any c EOK.
Proof. In
fact, ~l
=expp (p-2 log(l -~p2c) ~ dp). Hence, by
Lemma2.2 and
dp
=0,
weget
the conclusion.We also use the
following
lemma in Kato~7~.
Lemma 2.4.
(Lemma
6 inProof of Lemma 2.4.
Using
thislemma,
we havePut 7rL =
(( - 1)/1f,
and u =pl(( - I)P-1.
Then 1f£ is aprime
element ofOL,
and u is a unit ofZp [(].
Since 7rP =pT,
we haveSince u =
vP(1
+w(~’ - 1))
for some v, w inThus,
we obtain Lemma 2.1(1).
Put x =
a mod p
E F. Lemma 2.1(2)
follows from Lemma 2.1(1).
InBy
Lemma2.2,
we haveHence
by (5) (6)
and(7),
we obtainFirst of
all,
= 0 inK2(L)~.
Infact,
if we write du =w.d(
for some w E
Zp[~],
Since (
By
the samemethod, = 0,
hence the second term of theright
hand side of(8)
isequal
to7r I (from
7rL =(~-1)/~).
Hence
by (8)
we have(recall
that =pT). Thus,
we havegot
Lemma 2.1(3).
We go back to Lemma 2.1
(4).
For p = 3 and i = p +3, by
the samemethod,
we obtainBut the
right
hand side is zeroby Corollary
2.3.3. Proof of the theorem
3.1. First of
all,
we prove Theorem 1.1(1).
Let i be aninteger
such that~ -f- I i. Then
by
Lemma 2.1(1),
we havefor a E
0 Ko. Hence, taking
themultiplication by
p, weget
U’K2(K)
for all i with(i, p)
= 1 and thesurjectivity
of(2) implies
thatis
generated by
theimage
of it follows from{1 -
EUi+1K2(K)
thatUiK2(K)
= for all i with(i, p)
= 1.We remark that
by [12]
Theorem2.2,
if i >2p
and i isprime
to p, wealready
knewgri
= 0 isgenerated by 7rT’-ld7r - dT,
andisomorphic
toOK/(p)).
So theproblem
wasonly
to showgri K2(K)
= 0for i such that p + 1 i
2p.
3.2. Next we
proceed
to i =2p. By
7rP =pT,
we have p ~ dT =Hence, expp(p - dT)
=d7r/7r), namely
(this
also follows from[12]
Theorem2.2).
For a E
UKo, by
anelementary
calculationwe know that FP is contained in the kernel of the map z -
{1
+7rl
in
(3)
from F togr2P K2(K)
becauseof U2PK2 (K)
=Next we assume that a E
UKo
and x = amod p
is not in FP. We will prove{1 U2p+1K2(K).
Let L =K ((), Ui(K2(L)/p),
be as in§2. Since x 0 FP, by
Remark 1.2(iv)
we havefilK( {I
+ modp)
= p andLet A =
Gal(L/K)
be the Galois group ofL/K.
Consider thefollowing
commutative
diagram
of exact sequenceswhere P1 is the restriction to the A-invariant
part
of themap ->
f,x (we
usedK2(K)/p),
and P2 is the map induced from themultiplication by
p(a mod p H
pamodp2).
The left vertical arrow isbijective,
and the centraland the
right
vertical arrows are alsobijective by Mercurjev
and Suslin.This
diagram
says that the kernel of p2 isequal
to theimage
of~~,
L"I A
in The filtration
UL
= I +mL
on Lx induces a filtration onand its
graded quotients
are calculated as=
ul/ui+1
if i== -I modp - 1,
and = 0 otherwise((LX /UL 0 Z/p(l))~
also
vanishes).
Since theimage
of 1 +(7ri/(( - 1))UK,, generates Imagepl
C(K2(L)lp)", then n
can bewritten as q -
~~, 1+(~r2/(~-1))ai} (mod U(p-1)i+1K2(L))
for some i > 0with ai
EUKo. Hence, by
Lemma 2.1(2),
we have# (p - l)p.
Therefore
by (9), fl
+ does notbelong
to{~, L" }~
in=
K2(K)/p.
Soby
the above exact sequence,~
0 ingrP K2(K). Hence,
the kernel of the map{1
+p7rPiF, 7r I
fromF to
gr~ K2(K),
coincides with FP. Thiscompletes
theproof
of Theorem1.1 (2).
3.3. We next prove
(3)
of Theorem 1.1. Let n > 3.By
the same methodas in
3.2,
we haveUnPK2(K)
=(this
also follows from[12]
Theorem
2.2),
inparticular,
the map issurjective.
Suppose
that a EOKo . By Corollary 2.3,
we havein
~"2(~)~?
hence weget
Since n >
3,
the above formulaimplies
Recall that we fixed a
p-base t
of F such thatT mod p
= t. We definesubgroups
of Fby
= for n > 0.Suppose
that x is in,~n-2.
Let a = x be alifting
of x toOKo .
Thenby [14] Proposition 2.3,
weget
Let
Kz(Ko)
~K2 (K)
be the natural map.Then,
we haveiK/Ko(Un K2(Ko))
CUnpK2(K),
butby
the formula(11),
C also holds. Hence
by (12), (13),
andiK/Ko(UnK2(Ko))
CU(n+’)PK2 (K),
we know that{1
+ is inNamely,
is in the kernel of the map(10).
Since is
generated by
the elements of the form~dt/t
suchthat x E F and 1 i
pn-2 - l,
isisomorphic
to and weobtain a
surjective homomorphism
We
proceed
to theproof
of theinjectivity
of(14).
We assume that7r I
is in the kernel ofK2(K)jpn-1
~K2(K)/pn (a mod pn-1 H
As in
3.2,
we consider a commutativediagram
of exact se-quences with vertical
bijective
arrowswhere P1 is the restriction to of the map
L~/(L~)P(1)
~KZ(L)~p’‘ 1;
x E-->{~, x} I (we
also used(K2(L)~pn 1)~ - K2(K)/pn-1).
From this
diagram,
we know that{1
+pn-la,
is in theimage
of pi. Wewrite
{1
+ ={~, c}
for some c E Soby
theargument
in3.2,
c is in for some i > 1. If c was inULP yi-p
for some i with I i p, we would have
by
Lemma 2.1(2) c}
modp) = (p-1)i.
But is zero inK2(L)/p (because
1 E so c must be in We write c = CIC2 with
ci E
Ur~2(1)Ó
and c2 EU~ 1»P+1)-P(1)p. Again by the same argument
using
Lemma 2.1(2),
C2 must be inULP l~~p+2)-P(1)~. By Lemma 2.1 (3)
and
(4),
we can writefor some c3 E
OKa
inK2(L)/p~-1.
LetNLIL,, : K2(L)
->K2(Lo)
bethe norm
homomorphism. Taking
the normNL/Lo
of the both sides of theequation (15),
weget
where is the
trace,
and we used =pTC3 TrL/Lo(7r2)
=0. On the other
hand,
the left hand side of(16)
isequal
to{1
by Corollary
2.3.Hence,
theequation (16) implies
thatf 1 T}
= 0in
K2(Lo)~pn-1,
hence inK2(Ko)/pn-1.
In the
proof
of[14] Corollary 2.5,
we showed thatexpp2
induceswhich is
injective.
In we have{1
+pn-la, T }
=0,
henceby
theinjectvity
of the above map, we know that modpn-2
is ind(OKo/pn-2).
Thisimplies
that x -dt/t
is inwhere x =
a mod p
E F([6]
Corollaire 2.3.14 inChapter 0). Hence,
x is in
Bn-2. Thus,
the kernel of the map(10)
coincides with.13n_z. Namely,
the map
(14)
isbijective.
Thiscompletes
theproof
of Theorem I.I.3.4.
Finally
we proveCorollary
1.4. Let A4 be theZp-submodule
ofgenerated by da
with a EOK
anddT/T)
with b EOK-
Itfollows from 7rP =
pT
that =p2Td7r/7r
=pdT
in .Hence,
theexistence of
expp implies
thatdT/T)
is in the kernel ofexpp2.
Further,
da is also in the kernel ofexpp2 by
Lemma A2.3 inAppendix.
Soexpp2
factorsthrough SZoK /.Nl. Since b(pd7r/7r - dT/T)
E A4,
is
generated by
the classes of the formcd7r/7r.
We defineFil’
to be theZp-submodule
ofgenerated by
the classes of withi -
2p,
and considergri
=Fil’ /
We can
easily
see thatgr’
= 0 for i which isprime
to p. Infact,
if i isprime
to p, for a EUK, a7rid7r/7r
=ai-1d7ri = -7rida (mod A4).
We canwrite da =
a1dT
+aiTpd7r/ir
+a27rd7r/7r (mod M)
for some al,a2 E
Ox,
hencea7r’d7r/7r
is in For i2p,
we also havegr’
= 0.Suppose
that n > 3 and consider ahomomorphism
This does not
depend
on the choice of x.Suppose
that x is in(for
~n-2,
see theprevious subsection).
We write xdt/t
asin
3.3,
and take alifting
a =dT /T where 55i
is alifting
ofx2 to We have
pn-2 ad7r/7r
-(mod A4)
= db(mod Filnp )
for some b E
OKo . Hence, pn-2 ad7r/7r
EA4,
andBn-2
is in the kernel of(17).
So the restriction of(17)
togives
asurjective homomorphism Fpn 2
2013grnp
as in 3.3. This is alsoinjective
because thecomposite --~ grnp grnp K2 (K)
with the induced mapby expp2
isbijective
by
Theorem 1.1(3). Therefore, comparing gri
with we knowthat
expp2 :
isbijective.
Appendix
A. Milnor.K-groups
of a localring
over aring
ofp-adic integers
In this
appendix,
we show the existenceof expp (Corollary A2.10).
To doso, we describe the Milnor
K-groups
of a localring
over acomplete
discretevaluation
ring
of mixedcharacteristics, by using
the modules of differen- tials with certain divided powerenvelopes. (For
theprecise
statement, seeProposition
AI.3 and TheoremA2.2.)
Thisdescription
is related to thetheory
ofsyntomic cohomology developed by
Fontaine andMessing.
On a
variety
over acomplete
discrete valuationring
of mixed characteris-tics,
Fontaine andMessing [4] developed
thetheory
ofsyntomic cohomology
which relates the etale
cohomology
of thegeneric
fiber with thecrystalline
cohomology
of thespecial
fiber. In[9]
Kato studied theimage
of the syn- tomiccohomology
in the derivedcategory
of the etalesites,
and considered thesyntomic complex
on the etale site. He also used the MilnorK-groups
in order to relate the
syntomic complex
with thep-adic
etalevanishing
cy-cles,
and obtain anisomorphism
between the sheaf of the MilnorK-groups
and the
cohomology
of thesyntomic complex
aftertensoring
with an al-gebraically
closed field([9] Chap.I 4.3, 4.11, 4.12).
Ourdescription
of theMilnor
K-groups
says that thisisomorphism
exists withouttensoring
withan
algebraically
closed field(for
theprecise
statement cf. Remark A2.12(28)).
Thisappendix
is a part of the author’s master’s thesis in 1986.A.I. Smooth case.
A.1.1. Let A be a
complete
discrete valuationring
of mixed characteris- tics(0,p).
We further assume that p is an oddprime number,
and that Ais
absolutely unramified, namely pA
is the maximal ideal of A. We denoteby
F =A/pA
the residue field of A.Let
(R, rrzR)
be a localring
over A such thatR/pR
isessentially
smoothover
F,
and R is flat over A.Further,
we assume that R isp-adically complete,
i.e. RlimR/pnR,
- and define B =R[[X]].
In thissection,
westudy
the MilnorK-group
of B.(One
can deal with moregeneral rings by
the method in this
section,
but forsimplicity
we restrict ourselves to theabove
ring.)
Since
R/pR
isessentially
smooth overF, R/pR
has ap-base. Namely,
there exists a
family (ea)aEL
of elements ofR/pR
such that any a ER/pR
can be written
uniquely
aswhere as E
R/pR,
and s ranges over all functions L 2013~{0, l, ..., p - 1}
with finite supports.
For a
ring A, S2A
denotes the module of Kahler differentials. Let ea beas
above,
then(dex)
is a basis of the free module * We consider alifting
I c R of ap-base
Thenf dT; T E 11 gives
a basis of the free R-moduleÖk
whereÖk
is thep-adic completion
ofS2R.
Since R islocal,
we can take I from R’. In the
following,
we fix I such that I C R~.For the
lifting
I of ap-base,
we can take anendomorphism f
of Rsuch that
f (T)
= TP for anyT E I,
and that(mod p)
for anyx E R. We fix this
endomorphism f ,
and call it the frobeniusendomorphism
relative to I.
We
put
B =R[[X]].
We extendf
to anendomorphism
of Bby f (X)
XP. So
f
satisfies(mod p)
for any x E B. Let XB be the ideal of Bgenerated by
X.Lemma A.1.1. Put
fl = -~~ f : B[l/p]
-lï
=fl
o ... o11 (n
times),
I andThen, for
a EB,
is inBX ,
andEl defines
ahomomorphism (Shafarevich function)
It suffices to show is in B’ for a E B. We define an E B
inductively by
ao = a andwhere =
.f
o ... o.f (rt times),
andIVn (To, - - ., Tn)
is the ivittpolynomials
([19] Chap.II). (It
iseasily
verified thatis divisible
by pn . Hence,
an iswell-defined.) By
the formula of Artin-Hasseexponential
= we haveHence,
E B’.A.1.2. Let be the
(p, X)-adic completion
of For aninteger
r EZ,
let for r >
0,
andf2’
= 0 for r 0. Let r bepositive.
Thenf naturally
acts onÓÉ,
and theimage
is contained in So we candefine
f r
= onWe define
IB
= I U{X}.
Then ... AdTr; Ti E IB ~
is a base ofFor i > 0 we define to be the
subgroup (topologically) generated by
the elements of the form
adT1Â
... AdTr,
andbdT1Â
... l~ dX wherea E
X’B,
b E andTl, ..., Tr
E I.A.1.3. For a
ring k
andq > 0,
the MilnorK-group Kf (k)
isby
definitionwhere J is the
subgroup generated by
the elements of the forma1 0 ...0 aq
such
that ai + aj
=0,
or 1 for some ij. (The
class of a1 0 ... isdenoted
by (at , ..., aq~.)
We will define a
homomorphism Eq
which isregarded
asfrom the module of the differential
(q - I)-forms
to theq-th
Milnor K-group. First of
all,
we remark that in thesymbol {1
+Xa, X)
makes sense for a E B.
Namely,
for any x in the maximal ideal mB, wedefine
{1
+ xa,~~
to beThen,
usual relations like theimage
of1
the notation
{I
+~~,&i,...~g-2~}
also makes sense in where We define to be the(p, X)-adic completion
ofnamely
the
completion
withrespect
to the filtrationwhere Vi
is the sub-group
generated by {I
+(~X)~~...~}.
Let be thesubgroup (topologically) generated by (I
+and (I
+We define
by
where a E B and 1
can be
regarded
asLemma A.1.2.
Eq
vanishes onWe may assume q = 2. So we have to prove
E2(d(Xa))
= 0.By
theadditivity
of theclaim,
we may assume that a is aproduct
of elements ofIB, namely a
=IITi
whereTi
EIB.
Inparticular, f(a)
= aP.Using
Xa =
XI-IT,,
we haveThis
completes
theproof
of Lemma 2.2.Proposition
A.1.3.Eq
induces anisomorphzsm
which preserves the
filtrations.
Proof.
Using
Vostokov’spairing [23],
Kato defined in[9]
asymbol
mapsuch that
and
..., aq~ _
A ... l,Concerning
the map Sf,q we willgive
two remarks. If are inIB (and ~a, Tl, ..., Tq_1 ~
isdefined),
thenHere,
we are allowed to takeTZ
= X . To seethis,
since the definition of iscompatible
with theproduct
structure of the MilnorK-group,
we may assume q = 2 andT1 =
X . Since~a, X ~
isdefined, by
ourconvention,
acan be written as a = I + bX . The
image
of{a, X ~
under thesymbol
map- L-’ --J
which
belongs
to theimage
of 1L--J---/-
Next we remark the
assumption
p > 2 isenough
to show that factorsthrough
Infact, by
thecompatibility
of -3f,q with theproduct
structure of the Milnor
K-group,
theproblem again
reduces to the caseq = 2. So
Chapter
IProposition (3.2)
in[9] implies
the desiredproperty.
We do not need the
q-th
divided power orSn(q)
with q > 2 in[9]
tosee this.
We go back to the
proof
ofProposition
A1.3. We haveThis means that o
Eq
= -id.Thus, Eq
isinjective.
On the other
hand, by [2] (4.2)
and(4.3),
we have asurjective
homo-morphism
such that
where a
E B,
andbi
o This shows that isgenerated by
the elements of theaX i, Tl, ...,
where a EB,
and
Tl , ...,Tq_ 1
are inIB . Hence, .Eq
issurjective,
whichcompletes
theproof.
A.2. Smooth local
rings
over a ramified base.A.2.1. In this
section,
we fix aring
B asin ~ 1,
andstudy
aring
Here, u
is a unit ofB,
and is the ideal of Bgenerated by
X e - pu. Weput
= X e - pu. We denoteby
the canonical
homomorphism. (For example,
if A is acomplete
discretevaluation
ring
with mixedcharacteristics,
one can take A as in§Al
suchthat
A/A
is finite andtotally
ramified.Suppose
that R =A,
B =R[[X]],
and
f(X)
= Xe - pu(u
EB X)
is the minimalpolynomial
of aprime
element of A over A.
Then,
A -B/(Xe - pu)
and the above condition onA is
satisfied.)
Let D be the divided power
envelope
of B withrespect
to the idealill, namely
D = r >0].
We also denoteby
the canonical
homomorphism
which is the extensionof 0 :
B -> A.We define J =
Ker(D ~ A). Then, the endomorphism f
of B naturally
extends to D. Since cp = Xe - pu, we have D = r >
0]
=r >
01. Hence, f (J)
cpD
holds. Sofl
=p-11 :
J ) D canbe defined.
Since
~ --l 1 -
can be defined on
can be also defined.
A.2.2. Recall that B =
R[[X]].
We denote theimage
of X in Aby
thesame letter X. For i >
0,
we define =1+XiA.
We note thatis
p-adically complete.
Lemma A.2.1. Let e’ =
[e/(p - 1)]
+ I be the smallestinteger
i such thatI
gives
anisomorphism
The
proof
is standard(cf. [19] Chap.V
Lemme2) .
For an element x e
by
LemmaA2.1,
there is aunique
y E suchthat yP
= x. We denote this elementby xl. By
the sameway, for x e a
unique
element y e such that x, is denotedby x1/pn.
Since is aZp-module,
we also use the notationfor an
integer m with (p, m)
= 1 for x ERecall that D = r >
0] =
r >0].
Let be theideal of D
generated by
all with r > 0. We define ahomomorphism
by
where a E
B,
andEl :
XB - B’ is the map defined in§A.l.
Sinceer >
e ordp (r! )
+ is well-definedby
the above remark.A.2.3.
For q
>0,
we will defineEq,A similarly
as in 1.3. For i >1,
- ^- I
be the
subgroup generated by
be the
q-th
MilnorK-group.
As in1.3,
for i >0,
let(A)
be thesubgroup generated by 11
+Xi A, A x, ...,
andf 1
+and define
Kqm(A)A
to be thecompletion
ofKf (A)
with
respect
to the filtration We denoteby
theclosure of in Note that is
p-adically
complete, namely
= We also note thatby
-
definition,
a naturalhomomorphism
We define
by
where
Ti
EIB .
Recall
that ,
putThe filtration on induces a filtration on
B),
which we denoteby
Our aim in this section is to proveTheorem A.2.2.
Eq,A
induces anisomorphism
which preserves the
filtrations.
A.2.4. Let be the
p-adic completion
of0~-1.
Webegin
with thefollowing
lemma.Lemma A.2.3. There exists a
homomorphism
such that
where a E
A, bi
EAX,
andcontained in the kernel
of expp2.
Proof.
By Corollary
2.5 in[14],
we have ahomomorphism
such that
where a E
B and bi
E B . Consider the exact sequenceSince ill 0 is
clearly
in the kernelof ~
o (2013~ the map
expp2,B
induces the desired homomor-phism
’
Corollary
A.2.4. For any a EA B {0},
inK2(A)^ we
haveProof. In the
proof
of Lemma 2.5 in~12~,
we showed thatThis formula holds for a, b such that
a, b,
a + b EA ~ ~0~,
hence(1)
isreduced to the case a E
AX,
so follows from Lemma A2.3.The
equation (2)
is a consequence of(1).
Infact,
by ( 1 ) .
So we haveBut the latter is zero
again by (1).
A.2.5. We first show
Lemma A.2.5.
Eq,A
vanishes ond(Ul(D 0 flq-2)).
As in Lemma
A 1.2,
it suffices to showbe the Artin-Hasse
exponential.
We haveHence,
Lemma A2.5 is reduced to show thefollowing.
Lemma A.2.6. For any a E
A ~ {0}~
Proof of Lemma A2.6. From . , in order to
prove Lemma A2.6
(1),
it isenough
to show0,
which follows fromCorollary
A2.4(2). By
the samemethod,
LemmaA2.6