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2. Homotopy groups in pro-artinian categories

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M IC H E L B R IO N

O N T H E F U N D A M E N TA L G R O U P S O F C O M M U TAT I V E A L G E B R A IC G R O U P S

S U R L E S G R O U P E S F O N D A M E N TA U X D E S G R O U P E S A L G É B R IQ U E S C O M M U TAT IF S

Abstract. — Consider the abelian category C of commutative group schemes of finite type over a field k, its full subcategory F of finite group schemes, and the associated pro- category Pro(C) (resp. Pro(F)) of pro-algebraic (resp. profinite) group schemes. When k is perfect, we show that the profinite fundamental group $1 : Pro(C) Pro(F) is left exact and commutes with base change under algebraic field extensions; as a consequence, the higher profinite homotopy functors$ivanish fori>2. Along the way, we describe the indecomposable projective objects of Pro(C) over an arbitrary fieldk.

Résumé. — Considérons la catégorie abélienneCdes schémas en groupes de type fini sur un corpsk, la sous-catégorie pleineF des schémas en groupes finis, et la catégorie correspondante Pro(C) (resp. Pro(F)) des groupes proalgébriques (resp. profinis). Lorsquek est parfait, nous montrons que le groupe fondamental profini$1 : Pro(C) Pro(F) est exact à gauche et commute aux extensions algébriques de corps ; il en résulte que les groupes d’homotopie profinis supérieurs$i sont nuls pour i>2. Au passsage, nous décrivons les objects projectifs indécomposables de Pro(C) sur un corpskarbitraire.

Keywords:commutative algebraic groups, fundamental groups.

2010Mathematics Subject Classification:14K05, 14L15, 18E15, 20G07.

DOI:https://doi.org/10.5802/ahl.25

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1. Introduction

Every real Lie groupG gives rise to two exact sequences

0→G0Gπ0(G)→0, 0→π1(G)→GeG0 →0,

where G0 denotes the identity component, Ge its universal cover, and π0(G), π1(G) are discrete groups; moreover, the second homotopy group π2(G) vanishes. This classical result has a remarkable analogue for commutative algebraic groups over an algebraically closed field k, as shown by Serre and Oort via a categorical ap- proach (see [Ser60, Oor66]). More specifically, consider the category C of commu- tative k-group schemes of finite type, and the full subcategory F of finite group schemes; then C is an artinian abelian category, and F is a Serre subcategory. Let Pro(C) (resp. Pro(F)) denote the associated pro-category, consisting of pro-algebraic (resp. profinite) group schemes; recall that these categories have enough projectives, andC (resp. F) is equivalent to the full subcategory of Pro(C) (resp. Pro(F)) con- sisting of artinian objects. Assigning to each object of Pro(C) its largest profinite quotient yields a right exact functor

$0 : Pro(C)−→Pro(F).

It turns out that the left derived functors,

$i :=Li$0 : Pro(C)−→Pro(F),

vanish for i > 2; equivalently, $1 is left exact. Moreover, $0, $1 fit in an exact sequence

0−→$1(G)−→Ge −→G−→$0(G)−→0

for any G∈Pro(C) (see [Ser60, 6.2, 10.2] when k has characteristic 0, and [Oor66, II.7, II.14] in positive characteristics).

The construction of the “profinite homotopy functors” $i makes sense over an arbitrary fieldk; it is easy to extend the above exact sequence to this setting. The main result of this paper generalizes those of Serre and Oort as follows:

Theorem 1.1. — When k is perfect, the functor $1 : Pro(C) → Pro(F) is left exact and commutes with base change under algebraic field extensions. As a consequence, the higher profinite homotopy functors $i vanish for i>2.

Our approach is independent of the general theory of étale homotopy groups of schemes (see e.g. [AM69, Fri82]). We rather develop an ad hoc theory of homotopy groups in the setting of pairs (A,B), where A is an artinian abelian category, and B a Serre subcategory of A. For this, we build on constructions and results of Gabriel (see [Gab62, Chap. III]) and on further developments in [Bri19], recalled in Subsection 2.1. These may be conveniently formulated in terms of orthogonal or perpendicular categories (see [BR07, II.2] and [GL91] for these two notions).

Homotopy groups are introduced in Subsection 2.2, which generalizes results of Demazure and Gabriel on the profinite homotopy groups of affine group schemes (see [DG70, V.3.3]). Subsection 2.4 investigates compatibility properties of homotopy

groups in the presence of a Serre subcategoryC of B.

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In Section 3, we first apply this formalism to the categoryC of (commutative) alge- braic groups, and its full subcategory L of linear algebraic groups, over an arbitrary fieldk; then Pro(L) is equivalent to the category of affine k-group schemes, in view of [DG70, V.2.2.2]. The resulting homotopy functor π1C,L turns out to be left exact (Proposition 3.3). We then consider the pair (C,F), and obtain the left exactness of

$1 =πC,F1 when k is perfect; in addition, we show that the profinite universal cover Ge has homological dimension at most 1 for any G∈Pro(C) (Theorem 3.5).

When G is an abelian variety over an arbitrary field k, we construct a minimal projective resolution of Ge (Theorem 3.10). We also describe the projective objects of Pro(C) (Proposition 3.11); for this, we use results of Demazure and Gabriel on the projectives of Pro(L) over a perfect field (see [DG70, V.3.7]), combined with properties of the isogeny category C/F (see [Bri17]). We then show that the profinite homotopy functors commute with base change under separable algebraic field extensions (Proposition 3.15), thereby completing the proof of the main result.

As an application of the above developments, we obtain a spectral sequence à la Milne (see [Mil70]), which relates the extension groups inC and in the corresponding category over a Galois extension of k. Further applications, to the structure of homogeneous vector bundles over abelian varieties, are presented in [Bri18].

When the ground fieldk has characteristic p > 0, the prime-to-p part$(p1 0) of the profinite fundamental group commutes with arbitrary field extensions, and hence is left exact (Proposition 3.17). But over an imperfect fieldk, the functors $0, $1 do not commute with purely inseparable field extensions, nor does the pro-étale p-primary part of $1 (see Remarks 3.19, 3.20 and 3.21). In this setting, it seems very likely that $2 is nontrivial, but we have no explicit example for this; also, the profinite fundamental group scheme $1 deserves further investigation, already for smooth connected unipotent groups.

Finally, it would be interesting to relate the above (affine, profinite or pro-étale) fundamental groups with further notions of fundamental group schemes considered in the literature. In this direction, note that the profinite fundamental group of any abelian variety A coincides with Nori’s fundamental group scheme (defined in [Nor76, Nor82]), as shown by Nori himself in [Nor83]. Also, whenkis algebraically closed, the affine fundamental group of A coincides with its S-fundamental group scheme introduced by Langer in [Lan11], as follows from [Lan12, Thm. 6.1].

Acknowledgments. Many thanks to Cyril Demarche, Mathieu Florence, Roy Joshua, Bruno Kahn, Chu Gia Vuong Nguyen and Takeshi Saito for very helpful discussions on the topics of this paper. Special thanks to the referee for a careful reading of the paper and valuable comments.

2. Homotopy groups in pro-artinian categories

2.1. Pro-artinian categories and colocalizing subcategories

Consider an artinian abelian category A, and the associated pro-category Pro(A).

Then Pro(A) is a pro-artinian category in the sense of [DG70, V.2.2]; equivalently,

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the opposite category is a Grothendieck category. Moreover, A is equivalent to the Serre subcategory of Pro(A) consisting of artinian objects (see [DG70, V.2.3.1]). Let B be a Serre subcategory of A; then we may view Pro(B) as a Serre subcategory of Pro(A), stable under inverse limits (see [Bri19, Lem. 2.11]). We denote by Pro(B) the full subcategory of Pro(A) with objects those X such that HomPro(A)(X, Y) = 0 for all Y ∈ Pro(B) (this is the left orthogonal subcategory to Pro(B) in Pro(A) in the sense of [BR07, II.1]).

Lemma 2.1. — Let X ∈Pro(A).

(1) XPro(B) if and only if HomPro(A)(X, Y) = 0 for all Y ∈ B.

(2) X has a smallest subobject XB in Pro(A)such that X/XB ∈Pro(B). More- over,XBPro(B).

(3) For any morphism f :XY inPro(A), we havef(XB)⊂YB with equality if f is an epimorphism. If in addition f is essential and YPro(B), then XPro(B).

Proof. —

(1). — Let Y ∈ Pro(B). Then Y = limYi, where Yi ∈ B. Therefore, we have HomPro(A)(X, Y) = limHomA(X, Yi) = 0.

(2). — Let (Xi)i∈I be a family of subobjects of X such that X/Xi ∈Pro(B) for all i. ThenX/(∩i∈IXi) is a subobject of Qi∈IX/Xi, and hence an object of Pro(B).

This shows the existence ofXB.

If there exists a nonzero morphism f : XBY for some Y ∈ Pro(B), then X0 := Ker(f) is a subobject ofXB such thatXB/X0 is a nonzero object of Pro(B). It follows thatX/X0 ∈Pro(B), contradicting the minimality of XB. So XBPro(B).

(3). — The composition XBXYY /YB is zero, hence f(XB) ⊂ YB. If f is an epimorphism, then it induces an epimorphism X/XBY /f(XB). So Y /f(XB) ∈ Pro(B), i.e., YBf(XB). Hence YB = f(XB). If in addition f is essential and YPro(B), then Y =f(XB) and hence XB =X.

In view of Lemma 2.1, everyX ∈Pro(A) lies in a unique exact sequence

(2.1) 0−→XB −→X −→XB −→0,

where XBPro(B) and XB ∈ Pro(B). Moreover, every f ∈ HomPro(A)(X, Y) induces compatible morphisms

fB :XB −→YB, fB :XB −→YB. This defines a functor

π0 =π0A,B : Pro(A)−→Pro(B), X 7−→XB. Since HomPro(A)(XB, Y) = 0 for any Y ∈Pro(B), the natural map

HomPro(B)(XB, Y)−→HomPro(A)(X, Y)

is an isomorphism. In other words, π0 is left adjoint to the inclusion of Pro(B) in Pro(A). As a consequence,π0 is right exact and sends any projective object of Pro(A) to a projective object of Pro(B).

Lemma 2.2. — The functor π0 commutes with filtered inverse limits.

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Proof. — Consider a filtered inverse system (Xi) of objects of Pro(A). This yields a filtered inverse system (XiB) of objects ofPro(B); moreover, we have an isomorphism

lim HomPro(A)(XiB, Y)−→= HomPro(A)(lim

XiB, Y)

for any Y ∈ A (see [DG70, V.2.3.3]). Thus, HomPro(A)(limXiB, Y) = 0 for any Y ∈ B. In view of Lemma 2.1, it follows that limXiBPro(B). Also, we have an isomorphism

(lim Xi)/(lim

XiB)∼= lim

(Xi)B

by exactness of inverse limits (see [DG70, V.2.2]). So (limXi)/(limXiB) is an

object of Pro(B); this yields the assertion.

We denote by

Q=QA,B : Pro(A)−→Pro(A)/Pro(B)

the quotient functor. Then Q is exact, and commutes with inverse limits in view of [Gab62, III.4.Prop. 9]. Also, recall from [Gab62, III.4.Prop. 8, Cor. 1] thatQ has a left adjoint: the cosection,

C =CA,B : Pro(A)/Pro(B)−→Pro(A),

which also commutes with inverse limits and sends projectives to projectives. In other words, Pro(B) is a colocalizing subcategory of Pro(A), in the dual sense of [Gab62, III.2]. Conversely, every colocalizing subcategory of Pro(A) is equivalent to Pro(B) for a unique Serre subcategory B of A, in view of [Gab62, III.4.Prop. 10]

and [Bri19, Rem. 2.13]. Moreover, Pro(A)/Pro(B) is equivalent to Pro(A/B) by [Bri19, Prop. 2.12].

By [Gab62, III.2.Cor.], the essential image ofC consists of thoseX ∈Pro(A) such that

(2.2) HomPro(A)(X, Y) = 0 = Ext1Pro(A)(X, Y) for allY ∈Pro(B)

(these are the objects of the left perpendicular subcategory to Pro(B) in Pro(A), as defined in [GL91]). Moreover, for anyX ∈Pro(A), the adjunction mapCQ(X)X has its kernel and cokernel in Pro(B) (see [GL91, III.2.Prop. 3]). This yields an exact sequence in Pro(A)

(2.3) 0−→Y1 −→ι Xf−→ρ X −→γ Y0 −→0,

where we set Xf = XfA,B := CQ(X) (in particular, XfPro(B)), and we have Y0, Y1 ∈Pro(B). Note that the long exact sequence (2.3) depends functorially onX.

Also, note the natural isomorphism

HomPro(A)(X, Yf )∼= HomPro(A)/Pro(B)(Q(X), Q(Y)) for any Y ∈Pro(A). In particular, if X, Y ∈ A then

(2.4) HomPro(A)(X, Yf )∼= HomA/B(Q(X), Q(Y)).

Lemma 2.3. — With the above notation, we haveρ(X) =f XB and the induced epimorphism η:XfXB is essential. Also, there are functorial isomorphisms

π0(XB)−→= Y0, HomPro(B)(Y1, Y)−→= Ext1Pro(A)(XB, Y) for all Y ∈Pro(B).

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Proof. — In view of (2.2) and the exact sequence 0−→Y1 −→Xf−→ρ(X)f −→0,

we obtain the vanishing of HomPro(A)(ρ(X), Yf ) and an isomorphism HomPro(B)(Y1, Y)−→= Ext1Pro(A)(ρ(X), Yf )

for allY ∈Pro(B). Thus, ρ(X)fPro(B). SinceX/ρ(X)f ∼=Y0 ∈Pro(B), it follows that ρ(X) =f XB.

It remains to show that η:XfXB is essential. Let Z be a subobject of Xfsuch that the compositionZXfXB is an epimorphism. ThenXf=Y1+Z and hence X/Zf ∼= Y1/(Y1Z) ∈ Pro(B). As XfPro(B), it follows that Y1/(Y1Z) = 0,

i.e., Y1 is a subobject of Z. Thus, Z =X.f

Lemma 2.4. — With the notation of the exact sequence (2.3), the following conditions are equivalent for X ∈Pro(A):

(1) Y0 =Y1 = 0.

(2) HomPro(A)(X, Y) = 0 = Ext1Pro(A)(X, Y)for all Y ∈Pro(B).

(3) HomPro(A)(X, Y) = 0 = Ext1Pro(A)(X, Y)for all Y ∈ B.

Proof. — The equivalence (1)⇔(2) holds by [Gab62, III.2.Cor.]. As (2)⇒(3) is obvious, it suffices to show that (3)⇒(1).

Let X ∈ Pro(A) satisfy (3), and Y ∈ Pro(B). Then HomPro(A)(X, Y) = 0 by Lemma 2.1 (1). Consider an essential epimorphism f : PX, where P ∈ Pro(A) is projective (such a projective cover of X exists in view of [Gab62, II.6.Thm. 2]).

Then PPro(B) by Lemma 2.1 (3). So the exact sequence 0−→X0 −→P −→f X −→0 yields isomorphisms

(2.5) HomPro(A)(X0, Y)−→= Ext1Pro(A)(X, Y)

for all Y ∈ Pro(B). In particular, HomPro(A)(X0, Y) = 0 for all Y ∈ B. It follows that X0Pro(B) by using Lemma 2.1 (1). Thus, Ext1Pro(A)(X, Y) = 0 for all

Y ∈Pro(B).

2.2. Homotopy groups We denote by

πi =πiA,B :=Liπ0A,B : Pro(A)−→Pro(B) (i>0)

the left derived functors of the right exact functorπ0. In view of Lemma 2.2 together with [DG70, V.2.3.8], the ith homotopy functor πi commutes with filtered inverse limits for anyi>0. Also, for any exact sequence

0−→X1 −→X −→X2 −→0 in Pro(A), we have an associated homotopy exact sequence

(2.6) · · · →πi+1(X2)→πi(X1)→πi(X)→πi(X2)→πi−1(X1)→ · · ·

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Lemma 2.5. — Assume that every projective object of Pro(B) is projective in Pro(A). Then:

(1) πi(Y) = 0 for all Y ∈Pro(B) and i>1.

(2) πi(XB)−→= πi(X) for all X ∈Pro(A) and i>1.

Proof. —

(1). — Let P be a projective resolution ofY in Pro(B). Then π0(P) = P is still a projective resolution ofY in Pro(A).

(2). — This follows from (1) in view of the exact sequence (2.1).

Lemma 2.6. — With the assumption of Lemma 2.5, there is a functorial isomor- phismπ1(X)∼=Y1 for any X ∈Pro(A).

Proof. — The exact sequence (2.1) yields an isomorphism Q(XB) → Q(X) in Pro(A)/Pro(B), and hence an isomorphismCQ(XB)→CQ(X) in Pro(A). In turn, this yields an isomorphismY1(XB)→Y1(X) in Pro(B), where Y1(XB) denotes the kernel of the adjunction map CQ(XB)→XB, andY1(X) is defined similarly. Thus, we may assume that XPro(B). We then have an exact sequence

0−→Y1 −→Xf−→X−→0, which yields an exact sequence

π1(X)f −→π1(X)−→Y1 −→π0(X).f

Moreover,π0(X) = 0 by Lemma 2.4. So it suffices to show thatf π1(X) = 0.f As in the proof of Lemma 2.4, consider an exact sequence

0−→X0 −→P −→f Xf−→0,

where P is projective and f is essential. We obtain an exact sequence π1(P)−→π1(X)f −→π0(X0)−→π0(P).

Moreover, π0(P) = 0 by Lemma 2.1 (3), and π1(P) = 0 by definition. Thus, we have π1(X)f ∼=π0(X0). Also, recall from (2.2) that Ext1Pro(A)(X, Yf ) = 0 for allY ∈Pro(B).

Using the isomorphism (2.5), this yields HomPro(A)(X0, Y) = 0, and henceπ0(X0) = 0.

Thus,π1(X) = 0 as desired.f

In view of Lemmas 2.3 and 2.6, the exact sequence (2.3) can be rewritten in a more suggestive way. Namely, with the assumption of Lemma 2.5, we have an exact sequence for anyX ∈Pro(A):

(2.7) 0−→π1(X)−→ιX Xf−→ρX X −→γX π0(X)−→0.

In particular, whenXPro(B), we obtain an extension

(2.8) 0−→π1(X)−→Xf−→X −→0.

Using Lemmas 2.3 and 2.6 again, this yields in turn:

Corollary 2.7. — With the assumption of Lemma 2.5, let XPro(B)and Y ∈ Pro(B). Then HomPro(A)1(X), Y) →= Ext1Pro(A)(X, Y) via pushout by the extension (2.8).

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In other words, (2.8) is the universal extension ofX by an object of Pro(B). We now record a similar uniqueness result for the exact sequence (2.7), to be used in Subsection 3.2.

Lemma 2.8. — With the assumption of Lemma 2.5, consider an exact sequence

(2.9) 0−→Y1 −→X0 −→X −→Y0 −→0

inPro(A), where Y0, Y1 ∈Pro(B) and X0 is in the essential image ofC. Then there is a commutative diagram of exact sequences

0 //π1(X) //

f1

Xf //

f0

X //

f

π0(X) //

f0

0

0 //Y1 //X0 //X //Y0 // 0, where f1, f0, f, f0 are isomorphisms.

Proof. — Cut the exact sequence (2.9) in two short exact sequences 0−→Y1 −→X0 −→X00 −→0, 0−→X00 −→X −→Y0 −→0.

Since X0 is an object of Pro(B), so is X00. As Y0 ∈ B, we obtain a commutative diagram of exact sequences

0 // XB //

f00

X //

f

π0(X) //

f0

0

0 // X00 //X //Y0 // 0,

where the vertical arrows are isomorphisms. As a consequence, we may replace X with XB, and assume that π0(X) = 0 =Y0.

Also, the induced morphism Q(X0) →Q(X) is an isomorphism, and hence so is CQ(X0) → CQ(X) = X. Since the adjunctionf CQ(X0) → X0 is an isomorphism, this yields an isomorphism Xf∼=X0. Thus, we may further assume that (2.9) is of the form

0−→Y1 −→Xf−→X−→0.

Then the associated map HomPro(B)(Y1, Y)→Ext1Pro(A)(X, Y) is an isomorphism for all Y ∈Pro(B), by Lemma 2.4. In view of the uniqueness of the universal extension of X by an object of Pro(B), this completes the proof.

Next, we obtain two reformulations of the left exactness of the functorπ1:

Lemma 2.9. — With the assumption of Lemma 2.5, the following conditions are equivalent:

(1) The cosection functor C : Pro(A)/Pro(B)→Pro(A)is exact.

(2) π1 is left exact.

(3) πi = 0 for all i>2.

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Proof. —

(1)⇒(2). — Consider an exact sequence

0−→X1 −→X −→X2 −→0

in Pro(A). Then we have a commutative diagram of exact sequences 0 //Xf1 //

Xf //

Xf2 //

0

0 //X1 //X //X2 //0.

In view of the exact sequence (2.7) and its analogues forX1, X2, the snake lemma yields an exact sequence

0→π1(X1)→π1(X)→π1(X2)→π0(X1)→π0(X)→π0(X2)→0.

In particular,π1 is left exact.

(2)⇒(1). — This follows from the dual statement of [Gab62, III.3.Prop. 7].

(2)⇒(3). — This is obtained by a standard argument that we recall for complete- ness. LetX ∈Pro(A) and choose a projective cover

0−→X0 −→P −→X −→0.

As πi(P) = 0 for all i>1, we obtain isomorphisms πi(X)→= πi−1(X0) for all i>2.

SinceX0 is a subobject ofP, we have π1(X0) = 0 by left exactness, henceπ2(X) = 0.

Iterating this argument completes the proof.

(3)⇒(2). — This follows from the homotopy exact sequence (2.6).

Finally, we record an easy and useful divisibility property of homotopy groups. For anyX ∈Pro(A) and any integern, we denote bynX ∈EndA(X) the multiplication byn, and byX[n] its kernel. We say that X is divisible (resp. uniquely divisible) if nX is an epimorphism (resp. an isomorphism) for any n >1.

Lemma 2.10. — With the assumption of Lemma 2.5, let X be an object of Pro(A). Assume thatX is divisible and X[n]∈Pro(B)for any n>1(in particular, πi(X[n]) = 0 for any such n and any i > 1). Then Xf and the πi(X) (i > 2) are uniquely divisible. Moreover, there is an exact sequence

0−→π1(X)−→n π1(X)−→X[n]−→π0(X)−→n π0(X)−→0 for any n>1.

Proof. — By assumption, we have an exact sequence

(2.10) 0−→X[n]−→X −→nX X −→0

for anyn >1. Thus,nX induces an automorphism ofQ(X), and hence of CQ(X) = X. In other words,f Xfis uniquely divisible. The remaining assertions follow from the

homotopy exact sequence associated with (2.10).

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2.3. Structure of projective objects

In this subsection, we consider an artinian abelian category A and a Serre sub- category B such that every projective object of Pro(B) is projective in Pro(A).

Our aim is to describe the projectives of Pro(A) in terms of those of Pro(B) and Pro(A)/Pro(B)∼= Pro(A/B). We first obtain a generalization of [DG70, V.3.3.9]:

Lemma 2.11. — For any projective object P ∈Pro(A), there is an isomorphism P ∼=PBπ0(P) which is compatible withγP :Pπ0(P). Moreover, Pe ∼=PB.

Proof. — Recall that π0 is left adjoint to the inclusion of Pro(B) in Pro(A). It follows thatπ0(P) is projective in Pro(B), and hence in Pro(A) as well. This yields a compatible isomorphismP ∼=PBπ0(P). In particular,PB is projective, and hence in the essential image of C by (2.2). So the adjunction map CQ(PB) → PB is an isomorphism. AsCQ(PB)→= CQ(P) =Pe, this completes the proof.

Corollary 2.12. — Letf :XY be an epimorphism inPro(A), where Y is an object of Pro(B). Then there exists a subobject Y0 of X such that Y0 ∈ Pro(B) and the composition Y0XY is an epimorphism.

Proof. — We may assume that X is projective. By Lemma 2.11, we may then choose an isomorphism X ∼= Xfπ0(X) compatibly with γX : Xπ0(X). Since π0(f) :π0(X)→π0(Y) is an epimorphism, and γY :Yπ0(Y) is an isomorphism,

the statement holds withY0 =π0(X).

The above corollary asserts that the pair (Pro(A),Pro(B)) satisfies the lifting property introduced in [Bri19, §2.2]. Thus, this property holds for the pair (A,B) as well. Conversely, if (A,B) satisfies the lifting property, then every projective object in Pro(B) is projective in Pro(A) by [Bri19, Lem. 2.14].

Next, recall from [DG70, V.2.4] that every projective object of Pro(A) is a product of indecomposable projectives, unique up to reordering; moreover, the indecompos- able projectives are projective covers of objects ofA. Also, givenX ∈Pro(A) such that Q(X) is projective in Pro(A/B), the adjunction map ρ : Xf = CQ(X)X is the projective cover of X (indeed, C sends projectives to projectives, and ρ is essential by Lemma 2.3). Together with Lemma 2.11, this yields the following result (see also [Gab62, III.3.Cor. 2]):

Corollary 2.13. — The indecomposable projectives ofPro(A)are exactly those of Pro(B) and the X, wheref XPro(B) andQ(X) is indecomposable projective inPro(A/B).

The latter indecomposable projectives can be constructed as follows:

Lemma 2.14. — Let XPro(B).

(1) Consider an exact sequence in Pro(A),

0−→Z −→Y −→f X −→0.

Then f is essential if and only ifZ ∈Pro(B) and YPro(B).

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(2) Assume that Q(X) is projective in Pro(A)/Pro(B). Then the essential epi- morphisms f : YX, where Ker(f) ∈ B, form a filtered inverse system with limit the projective cover ofX in Pro(A).

Proof. —

(1). — Note that f induces an epimorphism Y /YBX/f(XB). Since we have that Y /YB ∈ Pro(B) and X/f(XB) ∈ Pro(B), we must have X/f(XB) = 0, i.e., the compositionYBYX is an epimorphism.

Assume thatf is essential. Then YB =Y, i.e., YPro(B). Also, by the lifting property, we have Z =ZB+W for some subobject W of Z such that W ∈Pro(B).

This yields an exact sequence

0−→Z/W −→Y /W −→X/f(W)−→0

in Pro(A), and hence in Pro(A/B). As X/f(W) ∼= X is projective in the latter category, this sequence is split by some g ∈ HomPro(A/B)(X, Y /W). In view of the assumption thatXPro(B), we may representg by h∈HomPro(A)(X, Y /W0) for someW0Y such that WW0 and W0 ∈Pro(B). Denote by p the composition of morphisms in Pro(A)

X −→h Y /W0 −→X/f(W0)

(where the morphism on the right is induced by f), and by q : XX/f(W0) the quotient morphism in Pro(A). Then p represents the identity endomorphism ofX in Pro(A)/Pro(B); thus, pq represents zero there. Using again the assumption that XPro(B), it follows that pq is zero in Pro(A). In particular, the composition h(X)Y /W0X is an epimorphism. Since f is essential, hmust be an epimorphism as well. Sog is an isomorphism in Pro(A)/Pro(B), hence Z/W ∈ Pro(B). We conclude that Z ∈Pro(B).

Conversely, assume that Z ∈ Pro(B) and YPro(B). Let Y0Y such that the composition Y0YX is an epimorphism. Then Y = Y0 +Z, hence ZYY /Y0 is an epimorphism as well. So Y /Y0 is an object of Pro(B), and hence is zero. We conclude thatf is essential.

(2). — Consider two exact sequences

0−→Zi −→Yi −→fi X −→0 (i= 1,2),

where f1, f2 are essential and Z1, Z2 ∈ B. Then the induced morphism f :Y1×X Y2 =:Y −→X

is an epimorphism with kernelZ1×Z2. In view of (1), it follows that the composition YBYX is an essential epimorphism. Thus, these essential epimorphisms form a filtered inverse system.

Given such an essential epimorphism f : YX, the map ρ : XfX lifts to a morphism ϕY : XfY. Moreover, ϕY is unique (since Ker(f) ∈ Pro(B) and XfPro(B)), and is an epimorphism as well. So we obtain an epimorphism

ϕ:Xf−→lim

Y

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with an obvious notation. To show that ϕ is a monomorphism, consider the family (Ki) of subobjects of Ker(ρ) such that Ker(ρ)/Ki ∈ B. Then X/Kf i ∈ A and ρ factors through an essential epimorphismX/Kf iX; moreover, the corresponding morphism ϕi : XfX/Kf i is just the quotient morphism. Since ∩Ki is zero, this

completes the proof.

2.4. Compatibility properties

Throughout this subsection, we consider an artinian abelian categoryA, a Serre subcategoryBsuch that the pair (A,B) satisfies the lifting property, and in addition a Serre subcategory C of B. We first relate the homotopy functors associated to the three pairs (A,B), (B,C) and (A,C):

Lemma 2.15. — Let X ∈Pro(A).

(1) There is a natural isomorphism π0A,C(X)→= π0B,C0A,B(X)).

(2) There is a spectral sequence πiB,CA,Bj (X))⇒πA,Ci+j(X).

Proof. —

(1). — This follows readily from the definitions.

(2). — Recall thatπ0A,B : Pro(A)→Pro(B) sends projectives to projectives; also, every projective in Pro(B) is obviously acyclic for π0B,C. In view of (1), this yields a

Grothendieck spectral sequence as stated.

Remark 2.16. — When X ∈ B, the above spectral sequence yields isomorphisms πB,Ci (X)→= πA,Ci (X) for alli>0, in view of Lemma 2.5. Alternatively, these isomor- phisms follow from the obvious equality π0B,C(X) =π0A,C(X), since every projective object of Pro(B) is projective in Pro(A).

On the other hand, when XPro(B), the first terms of the spectral sequence yield a natural isomorphism

πA,C1 (X)−→= πB,C01A,B(X)).

This can also be seen directly: consider the universal extension of X by an object of Pro(B),

0−→Y −→Xf−→X −→0,

where Y :=π1A,B(X). Then one may readily check that the induced exact sequence 0−→Y /YC −→X/Yf C −→X −→0

is the universal extension ofX by an object of Pro(C); thus, Y /YC ∼=π1A,B(X). But also Y /YC =π0B,C1A,B(X)).

Next, we investigate the behavior of the homotopy groupsπA,Bi under the quotient functor

QA,C : Pro(A)−→Pro(A)/Pro(C).

We will need the following observation:

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Lemma 2.17. — Assume that the pair (A,C) satisfies the lifting property. Then B/C is a Serre subcategory of A/C, and the quotient (A/C)/(B/C) is naturally equivalent to A/C. Moreover, the pair (A/C,B/C) satisfies the lifting property.

Proof. — Let X ∈ B, Y ∈ A, and let ϕ : XY be an isomorphism in A/C. By [Bri19, Lem. 2.7], there exists a subobject Y0Y inA such that Y0 ∈ C and ϕ is represented by a morphism f :XY /Y0 in A. Then Ker(f) and Coker(f) are objects of C in view of [Gab62, III.1.Lem. 2]. Since B is a Serre subcategory of A containingC, it follows that Y ∈ B. Thus, B/C is a strict subcategory of A/C.

Next, let 0→X1XX2 →0 be an exact sequence in A/C. Then there exists a commutative diagram in that category

0 //X1 //

X //

X2 //

0

0 //Y1 //Y // Y2 //0,

where the vertical arrows are isomorphisms, and the bottom sequence is the image of an exact sequence in A under the quotient functor QA,C (see [Bri19, Lem. 2.9]).

As a consequence, X ∈ B if and only if X1, X2 ∈ B. So B/C is a Serre subcategory of A/C.

The equivalence of categories (A/C)/(B/C) ∼= A/B follows from the universal property of quotient functors.

We now check that (A/C,B/C) satisfies the lifting property. Let ϕ : XY be an epimorphism in A/C. In view of [Bri19, Lem. 2.7] again, replacing Y with an isomorphic object in A/C, we may assume that ϕ is represented by a morphism f : XY in A; then Coker(f) is an object of C by [Gab62, III.1.Lem. 2] again.

Next, we may replaceX, Y withXC, YC, and hence assume thatf is an epimorphism inA. Then there exists a subobject Y0 of X such thatY0 ∈ B and the composition

Y0XY is an epimorphism in A, hence in A/C.

Lemma 2.18. — With the assumption of Lemma 2.17, πiA/C,B/C(X) is naturally isomorphic to the image of πA,Bi (X) inPro(B/C), for any i>0 and X ∈Pro(A).

Proof. — Recall that every projective object in Pro(C) is projective in Pro(A). By the dual statement of [Gab62, III.3.Cor. 3], it follows that the quotient functorQA,C sends projectives to projectives. Thus, it suffices to check the assertion for i= 0.

LetX ∈Pro(A) and consider the exact sequence

0−→XB −→X −→π0A,B(X)−→0

in Pro(A), where XBPro(B). This sequence is still exact in Pro(A/C); thus, it suffices to show thatXBPro(B/C). In view of Lemma 2.1, it suffices in turn to show that every morphismϕ:XBY in Pro(A/C), where Y ∈ B, is zero.

In Pro(A), we have XB = limXi, where Xi ∈ A and the projections XBXi

are epimorphisms. Hence this also holds in Pro(A/C). Since HomPro(A/C)(lim

Xi, Y) = lim

HomA/C(Xi, Y),

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we see that ϕ is represented by a morphism ϕi : XiY in A/C. Using [Bri19, Lem. 2.7], it follows that ϕis represented by a morphism fi :XiY /Y0 inA, for someY0Y such that Y0 ∈ C. The composition XBXiY /Y0 is zero, since Y /Y0 ∈ B. So fi = 0, and ϕ= 0.

3. Fundamental groups of commutative algebraic groups

3.1. The affine fundamental group

Let k be a field. As in the introduction, we consider the artinian abelian category C of commutative k-group schemes of finite type, and the associated pro-category Pro(C) of pro-algebraic groups. We denote byLthe full subcategory ofC with objects the affine (or equivalently, linear) algebraic groups. ThenLis a Serre subcategory of C, as follows from fpqc descent (see e.g. [Sta18, 34.20.18]). Also, recall that Pro(L) is equivalent to the category of commutative affine k-group schemes.

By the results of Subsection 2.1, every object of Pro(C) has a largest affine quotient;

this yields a right exact functor

π0C,L: Pro(C)−→Pro(L),

which commutes with filtered inverse limits and extends the affinization functor C → Lconsidered for example in [DG70, III.3.8]. The results of Subsection 2.2 also apply to this setting, in view of the following observation:

Lemma 3.1. — The pair (C,L) satisfies the lifting property.

Proof. — Let G∈ C. By a variant of Chevalley’s structure theorem for algebraic groups (see [Bri17, Thm. 2.3]) that we will use repeatedly, there is an exact sequence

(3.1) 0−→L−→G−→A−→0,

where Lis a linear algebraic group andAis an abelian variety. Letf :GH be an epimorphism, whereHis linear. ThenG0 :=G/(Ker(f)+L) is linear (as a quotient of G/Ker(f)∼=H) and is an abelian variety (as a quotient of G/L∼=A). Thus,G0 = 0, i.e., G= Ker(f) +L. So the composition LGH is an epimorphism.

We now describe the quotient categories C/L and Pro(C)/Pro(L). Consider the full subcategory A of C with objects the abelian varieties; then A is an addi- tive subcategory, but not a Serre subcategory. Denote by A the corresponding isogeny category: the objects of A are those of A, and the morphisms are defined by HomA(G, H) := HomA(G, H)⊗Z Q. Then A is a semi-simple artinian abelian category; its simple objects are exactly the simple abelian varieties, i.e., those having no non-trivial abelian subvariety.

Lemma 3.2. — With the above notation, the composite functor A → C → C/L induces equivalences of categories

A−→ C= /L, Pro(A)−→= Pro(C)/Pro(L).

Moreover, Pro(A) is semi-simple.

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Proof. — Denote by F : A → C/L the composite functor. Then F is essentially surjective by Chevalley’s theorem again. Also, recall from [Gab62, III.1] that

HomC/L(G, H) = lim

HomC(G0, H/H0)

for allG, H ∈ C, whereG0 (resp.H0) runs over the subgroup schemes ofGsuch that G/G0 is linear (resp. the linear subgroup schemes ofH). WhenGand H are abelian varieties, we must have G0 =G; moreover,H0 is finite, or equivalently, contained in the n-torsion subgroup scheme H[n] for some n>1. As a consequence,

HomC/L(G, H) = lim

HomC(G, H/H[n]),

where the direct limit is over the positive integers ordered by divisibility. This yields a natural isomorphism

HomC/L(G, H)−→= HomC(G, H)⊗ZQ

(see e.g. [Bri17, Prop. 3.6] for details), and hence the first equivalence of categories, A ∼=C/L. Since Pro(C/L)∼= Pro(C)/Pro(L), this yields the second equivalence of categories Pro(A)∼= Pro(C)/Pro(L).

To show that Pro(A) is semi-simple, it suffices to check that every object is projective. In view of [DG70, V.2.3.5], it suffices in turn to check that for any object G of Pro(A) and any epimorphism f : G1G2 in A, the induced map HomA(G, G1)→HomA(G, G2) is surjective. But this follows from the existence of a

section off.

Before stating our next result, we introduce some notation. We denote by Q=QC,L: Pro(C)−→Pro(C)/Pro(L)

the quotient functor, and by

C =CC,L: Pro(C)/Pro(L)−→Pro(C) the associated cosection functor. For any abelian varietyA, we set

P(A) :=CQ(A).

Proposition 3.3. — (1) The functor C is exact.

(2) The projective objects of Pro(C)are exactly the products of those of Pro(L) with theP(A), where Ais an abelian variety. Moreover, P(A)is a projective cover ofA in Pro(C), and is uniquely divisible.

Proof. —

(1). — Recall thatCcommutes with inverse limits, and hence with products. Since the category Pro(C)/Pro(L) is semi-simple (Lemma 3.2), this yields the assertion.

(2). — By Lemma 3.1 and [Bri19, Lem. 2.14], every projective object of Pro(L) is projective in Pro(C). In view of the dual statement of [Gab62, III.3.Cor. 2], it follows that the projective objects of Pro(C) are exactly the products of those of Pro(L) with the images under C of projective objects of Pro(C)/Pro(L). Using again the fact that this quotient category is semi-simple, this yields the first assertion.

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LetAbe an abelian variety. Since every affine quotient ofAis trivial, the adjunction mapρ:P(A)→Ais an epimorphism. Also, ρis essential by Lemma 2.3; thus,P(A) is a projective cover of A in Pro(C). The unique divisibility assertion follows from Lemma 2.10, sinceAis divisible and itsn-torsion subgroup schemes are finite for all

n>1.

3.2. The profinite fundamental group

We now consider the Serre subcategory F of L with objects the finite group schemes. As in the introduction, we denote by

$i :=πC,Fi : Pro(C)−→Pro(F)

the profinite homotopy functors. For anyG∈Pro(C), the exact sequence (2.7) may be rewritten as

0−→$1(G)−→Ge −→G−→$0(G)−→0,

where Ge denotes the profinite universal cover of GF := Ker(G→$0(G)).

The pair (C,F) satisfies the lifting property in view of [Bri15, Thm. 1.1]; thus, we may again use the constructions and results of Section 2.

Lemma 3.4. — Let G∈Pro(C) be divisible.

(1) G[n]is profinite for any n >1.

(2) $0(G) = 0.

(3) Ge is the limit of the filtered inverse system (G, nG)n>1, where the positive integers are ordered by divisibility. Also, Ge is uniquely divisible.

(4) $1(G) = limG[n], where the limit is over the above system. Moreover, we have $1(G)/n$1(G)∼=G[n] for any n >1.

(5) $i(G) = 0 for any i>2.

Proof. —

(1). — Let G = limGi, where the Gi are algebraic groups and the projections GGi are epimorphisms. Then the induced map G[n]→limGi[n] is a monomor- phism. Moreover, each Gi is divisible (as a quotient of G); thus, Gi[n] is finite for dimension reasons. So limGi[n] is profinite.

(2). — Consider an epimorphism GH, where H ∈ F. Then H is divisible (as a quotient of G) and torsion (as a finite group scheme), hence zero. This yields the assertion.

(3). — Let G0 := limG (limit over the above system). For anyH ∈ C and i>0, we have

ExtiPro(C)(G0, H)∼= lim ExtiPro(C)(G, H)

in view of [DG70, V.2.3.9]. Assume that H ∈ F; then we may choose an integer n>1 such that nH = 0. Thus, ExtiPro(C)(G, H) is killed byn; as a consequence, we have that ExtiPro(C)(G0, H) = 0. Using Lemma 2.4, it follows that the adjunction map CQ(G0)→G0 is an isomorphism.

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The projection π:G0G associated withn = 1, lies in an exact sequence

(3.2) 0−→lim

G[n]−→G0 −→π G−→0,

where limG[n] is profinite. Thus, π induces an isomorphism CQ(G0)→CQ(G) = G. So we may identifye G0 withG. Then (3.2) is identified with the universal profinitee extension ofG, in view of Lemma 2.8.

(4). — The first assertion has just been proved; the second one follows from Lemma 2.10 in view of the vanishing of$0(G).

(5). — By Lemma 2.10 again, the profinite group scheme$i(G) is uniquely divisi- ble for anyi>2. As a consequence, every finite quotient of$i(G) is divisible, hence

zero. This yields the assertion.

We may now prove a large part of our main result:

Theorem 3.5. — Assume that k is perfect.

(1) We have $i = 0 for all i>2; equivalently,$1 is left exact.

(2) The cosection functor C : Pro(C)/Pro(F)→Pro(C) is exact.

(3) The profinite universal cover Ge has projective dimension at most 1, for any G∈Pro(C).

Proof. —

(1). — In view of the homotopy exact sequence and the fact that $i commutes with filtered inverse limits, it suffices to show that$i(G) = 0 for any G∈ C and any i>2. This follows from Lemma 3.4 when Gis an abelian variety. On the other hand, when G ∈ L, we have $i(G) = πL,Fi (G) in view of Remark 2.16 and Lemma 3.1.

So the assertion follows from [DG70, V.3.6.8] in that case. In the general case, just recall that every G ∈ C is an extension of an abelian variety by a linear algebraic group.

(2). — This is just a reformulation of (1) (see Lemma 2.9).

(3). — By the main result of [Bri17], the category C/F has homological dimen- sion 1; hence the same holds for the category Pro(C)/Pro(F) ∼= Pro(C/F) (see e.g. [Bri19, Prop. 2.12, Lem. 2.15]). AsC sends projectives to projectives, this yields

the assertion.

Remark 3.6. — Returning to an arbitrary ground fieldk, consider the full subcate- goryE ofC with objects the finite étale group schemes. ThenE is a Serre subcategory ofF; moreover, the pair (C,E) satisfies the lifting property if and only if k is perfect (see e.g. [Bri15, Thm. 1.1, Rem. 3.3]). The functors

πi :=πiC,E : Pro(C)−→Pro(E)

are the “pro-étale homotopy functors”, considered in [DG70, V.3.4.1] for affine group schemes over perfect fields; note that π0(G) = G/G0 for any G ∈ C, where G0 denotes the neutral component (see e.g. [DG70, II.5.1]). The functor

πF,E0 : Pro(F)→Pro(E)

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is exact in view of [DG70, V.3.1.5]; using Lemma 2.15, this yields natural isomor- phisms

πi(G)−→= πF0,EC,Fi (G))

for allG∈Pro(C) and all i>0. As a consequence, the pro-étale fundamental group π1 is left exact when k is perfect.

3.3. Projective covers of abelian varieties

Consider an abelian varietyA, and its projective coverP(A) in Pro(C). By Propo- sition 3.3, we have an exact sequence in Pro(C)

(3.3) 0−→L(A)−→P(A)−→ρ A−→0,

where L(A) is affine. Also, recall that (3.3) is the universal affine extension of A, that is, the pushout by this extension yields an isomorphism

(3.4) HomPro(L)(L(A), G)−→= Ext1Pro(C)(A, G) for any G∈Pro(L).

Next, note that an algebraic group G is an object of Pro(L) if and only if G is anti-affine, i.e., O(G) = k (as follows from the affinization theorem, see [DG70, III.3.8.2]). In view of Lemma 2.14, it follows that P(A) is the inverse limit of all anti-affine extensions ofA. Using the affinization theorem again, one can deduce that the exact sequence (3.3) is the universal affine extension ofA by a (not necessarily commutative) affinek-group scheme. One can also obtain a structure result forP(A) by using the classification of anti-affine groups (see [Bri09, Thm. 2.7]). We will rather obtain such a result (Theorem 3.10) via an alternative approach, which relatesP(A) to the universal profinite cover ofA.

Consider the exact sequence as in (2.1),

0−→L(A)F −→L(A)−→$0(L(A))−→0.

Then the induced exact sequence

0−→$0(L(A))−→P(A)/L(A)F −→A−→0

is the universal profinite extension ofA, as observed in Remark 2.16. We thus identify

$0(L(A)) with $1(A), and P(A)/L(A)F with the profinite universal cover A. Thise yields an exact sequence

(3.5) 0−→L(A)F −→P(A)−→Ae −→0.

Lemma 3.7. — With the above notation, $i(A) = 0 =e $i(L(A)F) for anyi>0.

Proof. — Since A is divisible, we have $i(A) = 0 for i>2 in view of Lemma 3.4.

Using the homotopy exact sequence associated with the universal profinite extension 0−→$1(A)−→Ae −→A−→0

together with Lemma 2.5, it follows that $i(A) = 0 fore i>2 as well. Also, we have by construction $0(A) = 0 =e $1(A).e

The assertion on the $i(L(A)F) follows by using the exact sequence (3.5).

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