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Stabilization of second order evolution equations with unbounded feedback with delay

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DOI:10.1051/cocv/2009007 www.esaim-cocv.org

STABILIZATION OF SECOND ORDER EVOLUTION EQUATIONS WITH UNBOUNDED FEEDBACK WITH DELAY

Serge Nicaise

1

and Julie Valein

1

Abstract. We consider abstract second order evolution equations with unbounded feedback with de- lay. Existence results are obtained under some realistic assumptions. Sufficient and explicit conditions are derived that guarantee the exponential or polynomial stability. Some new examples that enter into our abstract framework are presented.

Mathematics Subject Classification.93D15, 93C20.

Received April 16, 2008. Revised September 19, 2008 and December 1st, 2008.

Published online April 21, 2009.

1. Introduction

Time-delay often appears in many biological, electrical engineering systems and mechanical applications [1,11,21], and in many cases, in particular for distributed parameter systems, even arbitrarily small delays in the feedback may destabilize the system, see e.g. [8–10,12,15–17,20,23]. The stability issue of systems with delay is, therefore, of theoretical and practical importance.

We further remark that some techniques developed recently [16,17] in order to obtain some existence results and decay rates have some similarities. We therefore propose to consider an abstract setting as large as possible in order to contain a quite large class of problems with time delay feedbacks. In a second step we prove existence and stability results in this setting under realistic assumptions. Finally in order to show the usefulness of our approach, we give some examples where our abstract framework can be applied. For a similar approach, we refer to the paper in preparation [4]. Without delay such an approach was developed in [3].

Before going on, let us present our abstract framework. Let H be a real Hilbert space with norm and inner product denoted respectively by .H and (., .)H. LetA : D(A)→H be a self-adjoint positive operator with a compact inverse in H. LetV :=D(A12) be the domain of A12. Denote byD(A12) the dual space of D(A12) obtained by means of the inner product in H.

Further, fori= 1,2, letUi be a real Hilbert space (which will be identified to its dual space) with norm and inner product denoted respectively by.Ui and (., .)Ui and letBi∈ L(Ui, D(A12)).

Keywords and phrases. Second order evolution equations, wave equations, delay, stabilization functional.

1 Universit´e de Valenciennes et du Hainaut Cambr´esis, LAMAV, FR CNRS 2956, Institut des Sciences et Techniques of Valenciennes, 59313 Valenciennes Cedex 9, France. [email protected];

[email protected]

Article published by EDP Sciences c EDP Sciences, SMAI 2009

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We consider the system described by

⎧⎪

⎪⎨

⎪⎪

¨

ω(t) +Aω(t) +B1u1(t) +B2u2(t−τ) = 0, t >0 ω(0) =ω0,ω(0) =˙ ω1,

u2(t−τ) =f0(t−τ),0< t < τ,

(1.1)

wheret∈[0,∞) represents the time,τ is a positive constant which represents the delay,ω : [0,∞)→H is the state of the system and u1∈L2([0,∞), U1),u2∈L2([−τ,∞), U2) are the input functions. Most of the linear equations modelling the vibrations of elastic structures with distributed control with delay can be written in the form (1.1), whereω stands for the displacement field.

In many problems, coming in particular from elasticity, the input ui are given in the feedback formui(t) = Biω(t), which corresponds to colocated actuators and sensors. We obtain in this way the closed loop system˙

⎧⎪

⎪⎨

⎪⎪

¨

ω(t) +Aω(t) +B1B1ω(t) +˙ B2B2ω(t˙ −τ) = 0, t >0 ω(0) =ω0,ω(0) =˙ ω1,

B2ω(t˙ −τ) =f0(t−τ), 0< t < τ.

(1.2)

The first natural question is the well-posedness of this system. In Section 2 we will give a sufficient condition that guarantees that this system (1.2) is well-posed, where we closely follow the approach developed in [16] for the wave equation. Secondly, we may ask if this system is dissipative. We show in Section 3 that the condition

∃0< α <1,∀u∈V,B2u2U2 ≤αB1u2U1 (1.3) guarantees the energy is decreasing; under this condition, using a result from [5] (see also [22]) we pertain a necessary and sufficient condition for the decay to zero of the energy. Note that this last condition is independent of the delay and therefore under the condition (1.3), our system is strongly stable if and only if the same system without delay is strongly stable. Note further that if (1.3) is not satisfied, there exist cases where some instabilities may appear (see [16,17,23] for the wave equation). Hence this assumption seems realistic.

In a third step, again under the condition (1.3) and a certain boundedness assumption from [3] between the resolvent operator ofAand of the operatorsB1andB2, see condition (4.1), we prove that the exponential decay of the system (1.2) follows from a certain observability estimate. Again this observability estimate is independent of the delay term B2B2ω(t˙ −τ) and therefore, under the conditions (1.3) and (4.1), the exponential decay of the system (1.2) follows from the exponential decay of the same system without delay. Nevertheless we give the dependence of the decay rate with respect to the delay, in particular we show that if the delay increases the decay rate decreases. This is the content of Section 4. A similar analysis for the polynomial decay is performed in Section 5 by weakening the observability estimate. Again we show that if the delay increases the decay rate decreases. In view of some applications, Section 6 is devoted to the proof of these two observability estimates by using a frequency domain method and a reduction to some conditions between the eigenvectors ofAand the feedback operatorB1.

Finally we finish this paper by considering in Section 7 different examples where our abstract framework can be applied. To our knowledge, all the examples, with the exception of the first one, are new.

2. Well-posedness of the system

We aim to show that system (1.2) is well-posed. For that purpose, we use semi-group theory and an idea from [16] (see also [17]). Let us introduce the auxiliary variablez(ρ, t) =B2ω(t˙ −τ ρ) forρ∈(0, 1) andt >0.

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Note thatzverifies the transport equation for 0< ρ <1 andt >0

⎧⎪

⎪⎨

⎪⎪

τ∂z∂t+∂z∂ρ = 0 z(0, t) =B2ω(t)˙

z(ρ,0) =B2ω(−τ ρ) =˙ f0(−τ ρ).

(2.1)

Therefore, the system (1.2) is equivalent to

⎧⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎩

¨

ω(t) +Aω(t) +B1B1ω(t) +˙ B2z(1, t) = 0, t >0 τ∂z∂t+∂z∂ρ = 0, t >0, 0< ρ <1

ω(0) =ω0, ω(0) =˙ ω1, z(ρ,0) =f0(−τ ρ),0< ρ <1 z(0, t) =B2ω(t), t >˙ 0.

(2.2)

If we introduce

U := (ω,ω, z)˙ T, thenU satisfies

U= ( ˙ω,ω,¨ z)˙ T =

˙

ω,−Aω(t)−B1B1ω(t)˙ −B2z(1, t),−1 τ

∂z

∂ρ T

· Consequently the system (1.2) may be rewritten as the first order evolution equation

U=AU

U(0) = (ω0, ω1, f0(−τ.)), (2.3)

where the operatorAis defined by

A

⎜⎝ ω u z

⎟⎠=

⎜⎝

u

−Aω−B1B1u−B2z(1)

τ1∂ρ∂z

⎟⎠,

with domain

D(A) :={(ω, u, z)∈V ×V ×H1((0,1), U2);z(0) =B2u, Aω+B1B1u+B2z(1)∈H}·

Now, we introduce the Hilbert space

H=V ×H×L2((0,1), U2) equipped with the usual inner product

ω u z

,

ω˜

˜ u

˜ z

=

A12ω, A12ω˜

H+ (u,u)˜ H+ 1

0

(z(ρ),z(ρ))˜ U2dρ. (2.4)

Let us suppose now that

∃0< α≤1,∀u∈V,B2u2U2≤αB1u2U1. (2.5) Under this condition, we will show that the operatorAgenerates aC0-semigroup inH.

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For that purpose, we choose a positive real numberξsuch that 1≤ξ≤ 2

α−1. (2.6)

This constant exists because 0< α≤1.

We now introduce the following inner product onH

ω u z

,

ω˜

˜ u

˜ z

H

=

A12ω, A12ω˜

H+ (u,u)˜ H+τ ξ 1

0

(z(ρ),z(ρ))˜ U2dρ.

This new inner product is clearly equivalent to the usual inner product (2.4) onH.

Theorem 2.1. Under the assumption (2.5), for an initial datum U0 ∈ H, there exists a unique solution U ∈C([0, +∞),H)to system (2.3). Moreover, ifU0∈D(A), then

U ∈C([0,+∞), D(A))∩C1([0, +∞),H).

Proof. By Lumer-Phillips’ theorem, it suffices to show thatA is m-dissipative (see Def. 3.3.1 and Thms. 1.4.3 and 1.4.6 of [18]).

We first prove thatAis dissipative. TakeU = (ω, u, z)∈D(A). Then

AU, UH =

⎛⎜⎝

u

−Aω−B1B1u−B2z(1)

1τ∂z∂ρ

⎟⎠,

⎜⎝ ω u z

⎟⎠

H

=

A12u, A12ω

H(Aω+B1B1u+B2z(1), u)H−ξ1

0

∂z

∂ρ(ρ), z(ρ)

U2

dρ.

Since+B1B1u+B2z(1)∈H,we obtain AU, UH =

A12u, A12ω

H− Aω, uV, V − B1B1u, uV, V − B2z(1), uV, V

−ξ 1

0

∂z

∂ρ(ρ), z(ρ)

U2

= Aω, uV, V − Aω, uV, V − B1u2U1(z(1), B2u)U2

−ξ 1

0

∂z

∂ρ(ρ), z(ρ)

U2

dρ, by duality. By integrating by parts, we obtain

1

0

∂z

∂ρ(ρ), z(ρ)

U2

dρ= 1

0

z(ρ), ∂z

∂ρ(ρ)

U2

dρ+ (z(1)2U2− z(0)2U2),

and thus 1

0

∂z

∂ρ(ρ), z(ρ)

U2

dρ= 1

2(z(1)2U2− B2u2U2).

Therefore, by Cauchy-Schwarz’s inequality, we find

AU, UH = − B1u2U1(z(1), B2u)U2−ξ

2z(1)2U2+ξ

2B2u2U2

≤ − B1u2U1+ 1

2 −ξ 2

z(1)2U2+ 1

2+ξ 2

B2u2U2.

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By (2.5), we obtain

AU, UH α

2 +ξα 2 1

B1u2U1+ 1

2 −ξ 2

z(1)2U2

with α2+ξα2 10 and 12ξ2 0 becauseξsatisfies condition (2.6). This shows thatAU, UH0 and then the dissipativeness ofA.

Let us now prove thatλI− Ais surjective for someλ >0.

Let (f, g, h)T ∈ H.We look forU = (ω, u, z)T ∈D(A) solution of

(λI− A)

ω u z

⎠=

f g h

or equivalently

⎧⎨

λω−u=f

λu++B1B1u+B2z(1) =g λz+1τ∂z∂ρ =h.

(2.7) Suppose that we have found ωwith the appropriate regularity. Then, we have

u=−f+λω∈V.

We can then determinez,indeedz satisfies the differential equation λz+1

τ

∂z

∂ρ =h

and the boundary conditionz(0) =B2u=−B2f +λB2ω.Thereforez is explicitly given by z(ρ) =λB2ωe−λτρ−B2fe−λτρ+τe−λτρ

ρ

0

eλτσh(σ)dσ.

This means that once ωis found with the appropriate properties, we can findz andu.In particular, we have z(1) =λB2ωe−λτ−B2fe−λτ+τe−λτ

1

0

eλτσh(σ)dσ=λB2ωe−λτ+z0, (2.8) wherez0=−B2fe−λτ+τe−λτ1

0 eλτσh(σ)dσ is a fixed element ofU2depending only on f andh.

It remains to findω.By (2.7),ω must satisfy

λ2ω++λB1B1ω+B2z(1) =g+B1B1f+λf, and thus by (2.8),

λ2ω++λB1B1ω+λe−λτB2B2ω=g+B1B1f+λf−B2z0=:q, whereq∈V. We take then the duality brackets., .V, V withφ∈V:

λ2ω++λB1B1ω+λe−λτB2B2ω, φ

V, V =q, φV, V.

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Moreover:

λ2ω++λB1B1ω+λe−λτB2B2ω, φ

V, V

=λ2ω, φV, V +Aω, φV, V +λ(B1B1ω, φV, V + e−λτB2B2ω, φV, V)

=λ2(ω, φ)H+

A12ω, A12φ

H+λ((B1ω, B1φ)U1+ e−λτ(B2ω, B2φ)U2) becauseω∈V ⊂H. Consequently, we arrive at the problem

λ2(ω, φ)H+

A12ω, A12φ

H+λ((B1ω, B1φ)U

1+ e−λτ(B2ω, B2φ)U

2) =q, φV, V . (2.9) The left hand side of (2.9) is continuous and coercive on V.Indeed, we have

λ2(ω, φ)H+

A12ω, A12φ

H+λ((B1ω, B1φ)U

1+ e−λτ(B2ω, B2φ)U

2)

λ2ωHφH+A12ω

H

A12φ

H+λ(B1ωU1B1φU1+ e−λτB2ωU2B2φU2)

≤Cλ2ωVφH+A122ωV φV +λ(B12L(V, U1)ωV φV + e−λτB22L(V, U2)ωV φV)

≤CωV φV , and forφ=ω∈V

λ2ω2H+

A12ω, A12ω

H+λ(B1ω2U1+ e−λτB2ω2U2)≥A12ω2

H≥Cω2V .

Therefore, this problem (2.9) has a unique solutionω∈V by Lax-Milgram’s lemma. Moreover+B1B1u+ B2z(1) =g+λf−λ2ω∈H.In summary, we have found (ω, u, z)T ∈D(A) satisfying (2.7).

Remark 2.2. We deduce from Theorem2.1thatD(A) is dense inH(see [18]).

Remark 2.3. For initial data (ω0, ω1, f0(−τ.))T inD(A), we easily show that the solution (ω(t), u(t), z(t))T = T(t)(ω0, ω1, f0(−τ.))T, whereT(t) is the semigroup generated byA, is indeed solution of (1.2) in the sense that

u(t) = ˙ω(t), and

z(ρ, t) =B2(t−τ ρ), andω satisfies (1.2).

3. The energy

We now restrict hypothesis (2.5) to obtain the decay of the energy. Namely, we suppose that (1.3) holds, namely

∃0< α <1,∀u∈V,B2u2U2≤αB1u2U1.

For an initial datum (ω0, ω1, f0(−τ.))T ∈ H, Theorem 2.1 guarantees the existence of a weak solution (ω(t), u(t), z(t))T = T(t)(ω0, ω1, f0(−τ.))T. Hence the associated energy (which corresponds to the inner product onH) is defined by

E(t) := 1 2

A12ω(t)2

H+u(t)2H+τ ξ 1

0

z(ρ, t)2U2

,

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whereξ is a positive constant satisfying

1< ξ < 2

α−1, (3.1)

that exists because 0< α <1.

Note that by Remark2.3for initial data inD(A), this energy takes the form

E(t) := 1 2

A12ω2

H+ω˙ 2H+τ ξ 1

0

B2ω(t˙ −τ ρ)2U2

. (3.2)

3.1. Decay of the energy

Proposition 3.1. If(1.3)holds, then for all0, ω1, f0(−τ.))T ∈D(A), the energy of the corresponding regular solution of (1.2)(i.e. (ω,ω, B˙ 2ω(t˙ −τ ρ))T ∈C([0,+), D(A))∩C1([0,+),H)) is non-increasing and there exist two positive constantsC1 andC2 depending only onαandξ such that

−C2

B1ω(t)˙ 2U1+B2ω(t˙ −τ)2U2

≤E(t)≤ −C1

B1ω(t)˙ 2U1+B2ω(t˙ −τ)2U2

. (3.3)

Proof. Deriving (3.2), we obtain

E(t) =

A12ω, A12ω˙

H+ ( ˙ω,ω)¨ H+τ ξ 1

0

(B2ω(t˙ −τ ρ), B2ω(t¨ −τ ρ))U

2

= Aω,ω˙ V,V ( ˙ω, Aω+B1B1ω˙ +B2B2ω(t˙ −τ))H +ξτ

1

0

(B2ω(t˙ −τ ρ), B2ω(t¨ −τ ρ))U2

= Aω,ω˙ V,V − ω, Aω˙ +B1B1ω˙ +B2B2ω(t˙ −τ)V, V

+ξτ 1

0

(B2ω(t˙ −τ ρ), B2ω(t¨ −τ ρ))U2dρ,

because+B1B1ω˙ +B2B2ω(t˙ −τ)∈H.Then

E(t) = Aω,ω˙ V,V − ω, Aω˙ V, V− ω, B˙ 1B1ω˙ V, V− ω, B˙ 2B2ω(t˙ −τ)V, V

+ξτ 1

0

(B2ω(t˙ −τ ρ), B2ω(t¨ −τ ρ))U2

= − B1ω˙ 2U1(B2ω, B˙ 2ω(t˙ −τ))U2 +ξτ

1

0

(B2ω(t˙ −τ ρ), B2ω(t¨ −τ ρ))U2dρ.

Moreover, recalling thatz(ρ, t) =B2ω(t˙ −τ ρ), we see that 1

0

(B2ω(t˙ −τ ρ), B2ω(t¨ −τ ρ))U

2dρ =

1

0

z(ρ, t), ∂z

∂t(ρ, t)

U2

= 1 τ

1

0

z(ρ, t), ∂z

∂ρ(ρ, t)

U2

dρ,

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because ∂z∂ρ(ρ, t) =−τ∂z∂t(ρ, t).Then, we have 1

0

(B2ω(t˙ −τ ρ), B2ω(t¨ −τ ρ))U2dρ = 1 2τ

1

0

∂ρz(ρ, t)2U2

= 1

2τ(z(1, t)2U2− z(0, t)2U2)

= 1

2τ(B2ω(t˙ −τ)2U2− B2ω(t)˙ 2U2).

Consequently,

E(t) =− B1ω˙ 2U1(B2ω, B˙ 2ω(t˙ −τ))U2−ξ

2B2ω(t˙ −τ)2U2+ξ

2B2ω(t)˙ 2U2. Cauchy-Schwarz’s inequality yields

E(t)≤ − B1ω˙2U1+ 1

2+ξ 2

B2ω(t)˙ 2U2 + 1

2 −ξ 2

B2ω(t˙ −τ)2U2 and

E(t)≥ − B1ω˙2U1+

1 2 +ξ

2

B2ω(t)˙ 2U2 1

2+ξ 2

B2ω(t˙ −τ)2U2. Therefore, by (1.3), these estimates leads to

E(t)≤ −C1

B1ω(t)˙ 2U1+B2ω(t˙ −τ)2U2

with

C1= min

1−ξα 2 −α

2

, ξ

2 1 2

which is positive according to the assumption (3.1), and to E(t)≥ −C2

B1ω˙ 2U1+B2ω(t˙ −τ)2U2

with

C2= max

1, ξ+ 1 2

which is also positive.

Remark 3.2. Integrating the expression (3.3) between 0 andT,we obtain T

0

B1ω(t)˙ 2U1+B2ω(t˙ −τ)2U2 dt 1

C1(E(0)−E(T)) 1 C1E(0).

This estimate implies thatB1ω(.)˙ ∈L2((0, T), U1) andB2ω(.˙ −τ)∈L2((0, T), U2).

Remark 3.3. If (1.3) is not satisfied, there exist cases where instabilities may appear, see [16,17,23] for the wave equation. Hence this condition appears to be quite realistic.

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3.2. Decay of the energy to 0

We give a necessary and sufficient condition that guarantees the decay to 0 of the energy.

Proposition 3.4. Assume that (1.3)holds. Then, for all initial data inH, we have

t→∞limE(t) = 0 (3.4)

if and only if for any (non zero) eigenvectorϕ∈D(A)of A, we have

B1ϕ= 0. (3.5)

Remark 3.5. Notice that this necessary and sufficient condition is the same than in the case without delay (see [22]) and therefore, the system (1.2) with delay is strongly stable (i.e.the energy tends to zero) if and only if the system without delay (i.e.forB2= 0) is strongly stable.

Proof. Let us show that (3.5) implies (3.4). For that purpose we closely follow [22].

First, we show that Ahas no eigenvalue on the imaginary axis. If it is not the case, let iω be an eigenvalue ofAwhereω∈R. Letϕbe an eigenvector associated with iω. Thenϕis of the form

ϕ=

z iωz iωe−iωτρB2z

,

with

−ω2z+Az+ iωB1B1z+ iωe−iωτB2B2z= 0. (3.6) It is an immediate consequence of the identity (iωI− A)ϕ= 0.

First we notice that ω = 0 since forω = 0, the above identity reduces to Az = 0 with z∈D(A). Since by hypothesisAis invertible, we getz= 0 and therefore 0 is not an eigenvalue ofA.

We now take the duality bracket., .V, V between (3.6) andz∈V:

0 =

−ω2z+Az+ iωB1B1z+ iωe−iωτB2B2z, z

V, V

=

(−ω2I+A)z, z

V, V + iωB1z2U1+ iωe−iωτB2z2U2. We look at the imaginary part of this expression to obtain

ω

B1z2U1+ cos(ωτ)B2z2U2

= 0, which implies, becauseω= 0,

B1z2U1+ cos(ωτ)B2z2U2= 0.

We deduce that

0 =B1z2U1 + cos(ωτ)B2z2U2 ≥ B1z2U1− B2z2U2 (1−α)B1z2U1 0, by (1.3) withα <1.Consequently

B1zU1 = 0 which implies

B1z= 0. (3.7)

Moreover, by (3.6), (3.7) and (1.3), we have

Az=ω2z.

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Therefore,z is an eigenvector ofAof associated eigenvalueω2such that B1z= 0,

which contradicts (3.5). Thus,Ahas no eigenvalue on the imaginary axis.

Now, we can apply the main theorem of Arendt and Batty [5]: Asσ(A)∩iRis empty (because the surjectivity of (iωI− A) is equivalent to the injectivity of−ω2+A−iωB1B1iωeiωτB2B2), we obtain (3.4).

Let us show that (3.4) implies (3.5). For that purpose we use a contradiction argument. Suppose that there exists an eigenvectorϕofAof associated eigenvalueλ2 such that

B1ϕ= 0.

Let us set

ω(., t) =ϕcos(λt).

Thenω is solution of (1.2) and satisfies

E(t) =E(0) because

B1ω(t)˙ 2U1 =λ2sin2(λt)B1ϕ2U1 = 0 and

B2ω(t˙ −τ)2U2 = λ2sin2(λ(t−τ))B2ϕ2U2

αλ2sin2(λ(t−τ))B1ϕ2U1= 0,

by (1.3). This means that we have obtained a solution of system (1.2) with a constant energy, which

contradicts (3.4).

4. The exponential stability 4.1. A priori estimate

In order to obtain the characterization of decay properties of the damped systemviaobservability inequalities for the conservative system we will use the following assumption from [3]:

Ifβ >0 is fixed andCβ ={λ∈C=β}, the function

λ∈Cβ→H(λ) =λB2I+A)−1B∈ L(U) is bounded, (4.1) whereB ∈ L(U, V) withU a Hilbert space.

We consider the evolution system

¨

y(t) +Ay(t) =Bv(t)

y(0) = ˙y(0) = 0, (4.2)

and the following conservative system

φ(t) +¨ Aφ(t) = 0

φ(0) =ω0,φ(0) =˙ ω1. (4.3)

Let us recall the two following results proved in [3]:

Lemma 4.1. Suppose thatv∈L2(0, T;U)and that the solutionsφof(4.3)are such thatBφ(.)∈H1(0, T;U) and there exists a constant C >0such that

(Bφ)(.)L2(0,T;U)≤C(ω0, ω1)V×H ∀(ω0, ω1)∈V ×H.

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Then the system (4.2)admits a unique solution having the regularity y∈C(0, T;V)∩C1(0, T;H).

Proposition 4.2. Suppose thatv ∈L2(0, T;U)and that the system (4.2)admits a unique solution having the regularity

y∈C(0, T;V)∩C1(0, T;H).

Then hypothesis (4.1)holds if and only if By(.)∈H1(0, T;U)and there exists a constant C >0independent of T such that

(By)(.)L2(0,T;U)≤CeβTvL2(0,T;U).

Let ω∈ C(0, T;V)∩C1(0, T;H) be the solution of (1.2) with (ω0, ω1, f0(−τ.))T ∈D(A). Then it can be split up in the form

ω=φ+ψ,

whereφis solution of the system without damping (4.3), andψsatisfies ψ(t) +¨ Aψ(t) =−B1B1ω(t)˙ −B2B2ω(t˙ −τ)

ψ(0) = 0,ψ(0) = 0.˙ (4.4)

We now set B = (B1B2)∈ L(U, V) whereU =U1×U2. It is easy to verify thatB = B1

B2

∈ L(V, U).

Thereforeψis solution of

ψ(t) +¨ Aψ(t) =Bv(t)

ψ(0) = 0,ψ(0) = 0,˙ (4.5)

wherev(t) =

−B1ω(t)˙

−B2ω(t˙ −τ)

. In other words,ψis solution of system (4.2) with B = (B1B2)

and by Remark3.2

v=

−B1ω(·)˙

−B2ω(· −˙ τ)

∈L2((0, T), U).

Then ψ = ω−φ C(0, T;V)∩C1(0, T;H). Suppose that hypothesis (4.1) is satisfied for B = (B1B2) and U =U1×U2. By applying Proposition4.2, we obtain

T

0

(Bψ)2Udt≤Ce2βT T

0

v(t)2Udt, which is equivalent to

T

0

((B1ψ)2U1+(B2ψ)2U2)dt≤Ce2βT T

0

(B1ω(t)˙ 2U1+B2ω(t˙ −τ)2U2)dt.

In particular, we have T

0

(B1ψ)2U1dt≤Ce2βT T

0

(B1ω(t)˙ 2U1+B2ω(t˙ −τ)2U2)dt.

(12)

Therefore, since ω=φ+ψ, we have T

0

(B1φ)(t)2U1dt 2 T

0

(B1ω)(t)2U1dt+ T

0

(B1ψ)(t)2U1dt

Ce2βT T

0

(B1ω)(t)˙ 2U1+(B2ω)(t˙ −τ)2U2 dt.

Thus, we have proved the following result:

Lemma 4.3. Suppose that assumption (4.1)is satisfied for B= (B1B2), U =U1×U2. Then the solutionsω of (1.2)andφof (4.3)satisfy

T

0

(B1φ)(t)2U1dt≤Ce2βT T

0

(B1ω(t)˙ 2U1+B2ω(t˙ −τ)2U2)dt, with C >0 independent ofT.

4.2. The stability result

Theorem 4.4. Assume that hypotheses (1.3) and (4.1) are verified forB = (B1B2), U =U1×U2. If there exist a time T >0and a constant C >0 such that the observability estimate

A12ω02

H+ω12H ≤C T

0

(B1φ)(t)2U1dt (4.6)

holds, where φ is solution of (4.3), then system (1.2) is exponentially stable in the energy space: there exist C >0 independent ofτ andν >0 such that, for all initial data in H,

E(t)≤CE(0)e−νt ∀t >0. (4.7)

Proof. Letω be a solution of (1.2) with initial data (ω0, ω1, f0(−τ·))∈D(A).

Without loss of generality, we can always assume that (4.6) holds withT > τ andCindependent ofτ.

Integrating inequality (3.3) of Proposition3.1between 0 andT, we obtain E(0)−E(T) ≥C

T

0

B1ω(t)˙ 2U1+B2ω(t˙ −τ)2U2 dt

C 2

T

0

B1ω(t)˙ 2U1+B2ω(t˙ −τ)2U2 dt+C

2 T

0

B2ω(t˙ −τ)2U2dt

≥Ce−2βT T

0

(B1φ)(t)2U1dt+ T

0

B2ω(t˙ −τ)2U2dt

by Lemma4.3.

By assumption (4.6), we obtain

E(0)−E(T)≥Ce−2βT

A12ω02

H+ω12H+ T

0

B2ω(t˙ −τ)2U2dt

,

withC independent ofτ. AsT > τ, by change of variables, we have T

0

B2ω(t˙ −τ)2U2dt =

T−τ

−τ B2ω(t)˙ 2U2dt

0

−τB2ω(t)˙ 2U2dt=τ 1

0

B2ω(−τ ρ)˙ 2U2dρ.

Références

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