A NNALES DE L ’I. H. P., SECTION C
B. P ERTHAME
Some remarks on quasi-variational inequalities and the associated impulsive control problem
Annales de l’I. H. P., section C, tome 2, n
o3 (1985), p. 237-260
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Some remarks
onquasi-variational inequalities
and the associated impulsive control problem
B. PERTHAME
E. N. S., 45, rue d’Ulm, 75230 Paris, Cedex 05
Vol. 2, n° 3, 1985, p. 237-260. Analyse non linéaire
ABSTRACT. - We
study Quasi-Variational Inequalities:
In
general, (1)
has nosolution,
we prove here that(1)
has aunique
maxi-mum subsolution that we caracterize. Then we compare the
implicit
obstacle
(2)
and the obstacle :and we
finally
showthat,
undergeneral assumptions,
the solution of(1)
is Holder continuous.
Key-words : Quasi-Variational Inequalities, Implicit obstacle, maximum subsolution,
Holder continuity, impulsive control.
RESUME. - Nous etudions les
Inequations Quasi-Variationnelles :
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire - Vol. 2, 0294-1449 85/03/237/24/S 4.30/(E) Gauthier-Villars
En
general (1)
n’a pas desolution,
nous montrons ici que(1)
admet uneunique
sous-solution maximale que nous caracterisons. Nous comparons ensuite l’obstacleimplicite (2)
et l’obstacle :et nous finissons par montrer que, sous des
hypotheses generales,
la solu-tion de
(1)
est holderienne.Mots-clefs : Inéquations Quasi-Varationnelles, obstacle implicite, sous-solution maxi- male, continuite Holderienne, controle impulsionnel.
We
study
here theQuasi-Variational Inequalities (Q.
V.I.)
and theassociated stochastic
impulsive
controlproblem:
where Q is a
regular (C3)
connected open set of and M isgiven by :
The
problem (1)
was introduced in A. Bensoussan and J. L. Lions[1 ] (more
recent results may be found in
[3 ]).
Atypical
result is thefollowing
if weassume ~p -
0, f >_-
0 and coincreasing,
then(1)
has aunique
solutionwhich is in
Here we will relax these
assumptions
and answer thefollowing questions.
If we take
general
~pand f, (1)
has ingeneral
no solution because of a diffi-culty involving
theboundary
condition : there is no reason apriori
that Mushould be above ~p on aQ. And if in
general
there is no solution of(1),
the
question
is to determine in which sense(1) might
be solved and whether thecorresponding
solution is theoptimal
cost function for the associatedimpulse
controlproblem
which ismeaningful
without any condition.If the solution of
(1)
is notcontinuous,
then formula(2)
has no clearmeaning
and onegenerally
defines theimplicit
obstacleby:
But it is not clear
(and
to ourknowledge
it has never been checked before!)
that Mu =
M + u (at
least for u EC(Q)).
We also answer here thatquestion.
The last
question
that westudy
is to findgeneral
localregularity results,
Annales de l’Institut Henri Poincaré - Analyse non linéaire
say in
C°~°‘,
which do not involve theboundary
data Such aregularity
has
already
beenproved by
J. Frehse and U. Mosco[9 ].
Here we statean
analogous
result but ourproof
iscompletely
different from the one in[9 ].
In a first
part
we show that(1)
has aunique
maximal subsolution which is the solution of:Here we cannot look after solutions in
H~
since this space is notadapted
to the obstacle Mu
and,
inparticular,
qJ AMu ~ H1/2(~03A9).
But under ageneral assumption
introduced in B. Perthame[16],
qJ A Mu and Muare continuous so that we can deal with continuous solution of
(3)
calledviscosity
solution. This kind of solution(a particular
case of the notion introduced in M. G. Crandall and P. L. Lions[7],
P. L. Lions[13 ] [14 ])
allows us to solve
(3)
with the classicalargument
of B. Hanouzet and J. L.Joly [10 ].
Remark that inAppendix
2 we proveequivalence
betweendifferent notions of solution of the obstacle
problem.
Inparticular
it appears that theviscosity
solution is also the classical solution inHloc.
We prove in a second
part
that thisanalytical
solution is the one weshould
expect
in view of the associatedimpulsive
controlproblem.
Thisis a verification
analogous
to the one in[3 ] [17] which clearly
shows thatthe above notion is the correct one.
We
give
in a thirdpart
somecomparison
results on Mu andM + u.
There are two main results : ifQis
sufficiently
smooth(CN)
thenMu = M + u
a. e. and if Mu or
M + u
is continuous then Mu =M + u everywhere (remark
Mu and
M + u
are definedpointwise
and not almosteverywhere).
Finally
we prove that when co is continuous and a smallenough,
then the solution of(1)
is inC°~ .
The method is toreplace
Muby
an other obstacle which is in and which is builtlocally
with thehelp
of
general properties
oi iwiu. Remark that we cangive
anexample
withvery
regular
data where u isonly (cf.
B. Perthame[18 ]),
and thatin
general
noregularity
up to theboundary
holds.I.
Q. V. I.
WITHOUT THE EXISTENCE OF A SUBSOLUTION1.
Assumptions
and main results.This section is devoted to the
Q.
V. 1.:Vol.
We prove
(1)
has aunique
maximum subsolution and that it is the solu- tion of:,
Here we call subsolution of
(1)
any u EC(Q), satisfying :
where we have set :
We assume :
where k is a
positive
constant, co :(f~+)N
-+ is a lower semi-continuous sub-additive function withco(0)
= 0and ~ >_
0means ~ = (~ 1, ... , ~N)
0. I
We will also assume that the
boundary
data satisfies :These
assumptions
will allow us to deal with continuous solutions of(1)
or
(3)
which are calledviscosity
solutions. Recall that P. L. Lions[13 ] [14]
has introduced the notion of
viscosity
solution ofgeneral
second orderequations adapting
to second orderequations
the notion introducedby
M. G. Grandall and P. L. Lions
[7]
for first orderequations.
A veryparti-
cular
application
of this notionyield
that thefollowing
obstacleproblem :
has a
unique viscosity
solution u EC(Q)
if the obstacle ~I’ EC(Q).
In thisparticular setting
u isnothing
else that the limit inC(Q)
of allregularized
obstacle
problems
with nice standard solutions.(The
different notions of solution of(10)
are collected inAppendix
2 where we prove theequivalence
of these
notions).
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
In the
following
we will callviscosity solution
of(3)
a continuous func- tion u such that AMu,
Mu EC(Q)
and u is aviscosity
solutionof
(10)
with T = Mu.Remarks.
1)
Below it will beproved that,
underassumption (9)
andwith the definition of Mu in
(2),
wealways
have Mu EC(Q)
when u EC(Q)
and A Mu.
2)
In theparticular
case treatedhere,
the notion ofviscosity
solutionis
equivalent
to and :moreover in
Appendix
2 it isproved
that M EH ~ .
3) Exactly
as in B. Perthame[16 where
theassumption
has been intro- duced toget
thecontinuity
of thesolution,
oneeasily
checks that(9)
may bereplaced by :
where w is any continuous super solution
of ( 1 )
such that w ~p . Then we can state the :THEOREM 1. - Under
assumptions (5)-(9), equation (1)
has aunique
maximal subsolution u and it is the
unique
solutionof (3).
If
03C6 E andM003C6
E(resp.
islocally semi-concave)
thenu E
(resp.
Let us recall that a function u E is said to be
locally
semi-concave if for each open set U~ c U~ c S2 there exist a constant C such that :or, in other words: is concave on convex subsets of O.
The end of this section is devoted to the
proof
ofTheorem 1,
it is divided in threeparts :
first we build adecreasing
process that isuniformly converging
to a solution of
(3) (this
is a variant of the « usual »proof
due to B. Hanouzet and J. L.Joly [10 ]).
Here thedifficulty
comes from the fact that theboundary
value of the process
changes
at eachstep.
Theconcavity
of theoperator
which associates ~p A Mu to u enables us to conclude. In the secondpart
we state the
uniqueness
resultand finally
we prove theregularity.
Vol.
2. Existence of a solution.
Throughout
section I we will assume thatf >__ 0,
qJ > 0. Indeed(7)
enables us to make such an
assumption by adding
constants to u and q. and a
positive
function tof
We can now define thefollowing
process : uo eC(Q)
is the solution of:r A ,
then we define u 1 as the solution of:
and
by induction,
The existence of this sequence is
justified by
the:LEMMA 1. - For
each n >_
0Mun
EProof
It iseasily
checked(cf. [16 ])
that underassumption (9) Muo
is continuous on Q.
So,
we assumeby
induction thatfor n >_ 0, Mun
iscontinuous and we prove that
Mun + 1
is also continuous. We know(see [l6 ])
that
Mun+ 1
is lower semi-continuous. Let us prove it is upper semi-conti-nuous.
j
Let : I
~o ~ 4;
1 ifthen,
on a
neighbourhood of xo
we have :and the result is
proved.
If xo + we will prove that :and this prove that
Mun+ 1 is
upper semi-continuous at xo since :But
(12)
is deduced from the:LEMMA 2. -
0, then
v(xo + ço)
=Mv(xo + ~ o) -
k.’
Indeed take v = in lemma
2,
then:Annales de l’Institut Henri Poincaré - Analyse non linéaire
since un is a
decreasing sequence).
But xo+ ~
E r and thus we haveand
(12)
isproved, concluding
theproof
of Lemma 1.Proof of
Lemma 2. - Noticethat,
if r~> 0,
xo +~o
+ ~ E5,
then :and, taking
the infimum over0,
we find :since
equality
holdsfor 11
=0,
Lemma 2 isproved.
Remarks.
1)
This also proves Remark 1 in I .1: take un+ 1 _-- un --_ u in theproof
of Lemma 1.2)
Theargument
used above is very similar to the one introduced in L.Caffarelli and A. Friedman
[5] [6 ].
As mentionned in the
proof
of Lemma1,
the sequence Un isdecreasing,
0 since
f >_ 0,
qJ> 0,
so that un converges to some function u;moreover we have :
PROPOSITION 1. - The sequence un converges
uniformly
to u EC(SZ)
which is a
viscosity
solutionof (3)
and 0 _ u uo.Proof
- Theproof
below isadapted
from B. Hanouzet and J. L.Joly [10].
Notice that
(3)
is forexample
deduced from the «stability »
ofviscosity
solutions of second order
equations by
uniform convergence. Let us provethe uniform convergence of n
choose p
e]0,1 [
such that-
,k ~
~ ~u0~L~
and assume that for some 0 e[o, 1 ] and some n >__
0 we have :then,
since M is a concavemapping :
Let us call z the solution of the obstacle
problem (10)
withand vo the solution of
then, applying
the maximumprinciple (regularizing Mun
ifnecessary)
and
noticing
that:one
easily
checks that :But the choice
of p
shows that: vo and thus we obtain:un + 1 - Un+ 2
C ~(1 -
1 .Since uo - uo,
iterating
the aboveinequalities
we obtain:and this proves
Proposition
1.Remark. - Of course this also proves that
Mun
convergesuniformly
to Mu hence u is a
viscosity
solution of(3).
3.
Uniqueness.
We must prove two results : that the solution of
(3)
isunique
and alsothat it is the maximum subsolution. This last
point
isclear,
if a functionw E C(S2)
satisfies :(this actually
means that w is aviscosity
subsolution of(1)
if Mw EC(Q)) then, recalling
the result of P. L. Lions[13 ], w
uo since forexample
wis a
viscosity
subsolution of(11).
We deduce that:and so
w
u 1. An easy induction proves thatw
un foreach n >__
0 andPROPOSITION 2. - Under the
assumptions of
theoreml, if
w Eis a
viscosity
solutionof (3),
then w = u.Proof
- Wealready
know thatw _
u. First we show that ~w >_ 0:we know
(by
the remark in I2°)
that Mw EC(Q)
so we can build asequence
E such that Mw in
C(Q).
Let us denoteby wn
the solu-Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
- tion of
(10)
for T = so that ~ ~~ w inC(Q)
and(see [16]).
Takexn ~ 03A9
so that : Min = asxeQ
we may assume
(at
least if n islarge enough)
thatwn(xn) Mwn(xn).
If xn ~ 0393
we deduce that03C6(xn) ~ 0,
if not the maximumprinciple
shows that
>
0 and in both cases 0 and thus w > 0.We now prove
Proposition
2 with thehelp
of B. Hanouzet and J. L.Joly
method. We have :
by
the samearguments
as inProposition
1 weget
and
sou __
wandProposition
2 isproved.
4.
Regularity.
Here we assume that E n
C(Q) (Resp.
thatM003C6
islocally semi-concave)
and we prove that u E(resp.
We
only
sketch theproof
since it isnearly
the same as in[16].
Oneintroduces :
and one
easily
proves that there exists some open set G(for
thetopology
of
Q)
such that :~
0
~
0
and so u E
(resp.
u ENow,
as Mu « takes its values » in F and with theregularity
ofMocp
one can prove that Mu is in(resp. locally semi-concave)
andapplying
classical results on the obstacleproblem
this proves that u E(Resp.
u E and theproof
of Theorem 1 is
completed.
Remarks.
1 )
Inparticular
if Q is convex the solutionbelongs
to, when ~p E Indeed
Muo
EC(Q)
and islocally
semi-concave and this isenough by
remark 3 in 1.1(cf. [1~ ], [18 ]).
2)
Of course these results extend to Hamilton-Jacobi-Bellman equa- tions(see
P. L. Lions[12 ],
L. C. Evans and P. L. Lions[8 ]).
The associatedQ. V. I.
is :(For
results on thisproblem
see S. Lehnart[11 ],
B. Perthame[16 ]).
Vol.
II. THE IMPULSIVE CONTROL PROBLEM
Our purpose,
here,
is togive
the stochasticinterpretation
of u, the solu-tion of
(3),
in terms of control of diffusion processes. Two remarks are to bedevelopped
below :first, despite
of thejumps
the process is constrainedto
stay
inQ;
next, thechange
ofboundary
data(from
qJto qJ
AMu)
doesnot induce any
change
on theoptimal
cost function.1. The
optimal
cost function. _Let
(Q, F, Ft, P, Wt)
be a standard spacecomposed by
aprobability
space
(Q, F, P)
with aright-continuous increasing
filtration ofcomplete
sub-a
algebra Ft
and a Browian motion wr inFt adapted.
For any sequences~
1G 2
... C~n... , C~n
n ~ oo, ofstopping
times and03BE1,
...,03BEn,
...of FOn-random
variables in(R+)n
we can defineby
induction :and :
we set :
We will say that such a
system
~ is admissible if E Q whenever Then we defineand the cost function of this
system
is:and the
optimal
cost function is:Remark.
1)
With our definition of admissiblesystems
we know that and so(15)
ismeaningful.
2)
Here we have takenc(x) _
~, tosimplify
notations but thefollowing
results still hold with any
c(x)
> 0.THEOREM 2. - Under the
assumptions of
Theorem1,
the solution uof(3)
is theoptimal
castfunction given by (16)
Annales de l’Institut Henri Poincaré - Analyse non linéaire
Proof 2014 z) u _
v : This is clear in view of A. Bensoussan and J. L. Lions[4]
or P. L. Lions
[.l3 ] :
u is solution of theQ. V. I. (1) with cp
= qJ .A Muso that it is the
optimal
cost function for a cost function definedby (15) with
inplace
of qJ. These cost functions are lessthan j(x, A)
since(p
qJso that u _ v.
ii ) u >__
v : Here wegive
anoptimal
admissiblesystem
as in[3 ] [I 7 ].
Let ~
be measurable function in such that :we can find a standard space
(Q, F, Ft, P,
where we solve :let
C~1
be the first time wheny° belongs to ~ _ ~
u =Mu ~ (%~
1 = + ocifrø is not
reached), ~
1 =(1
isanything
measurable ifC~1
= +oo )
and
by
induction’
and
G~n + 1
is the firsttime yl
enters ~ and~~‘ + 1
=1 )~.
From
[2 ] we
know the :LEMMA 3. - For any n
> 0,
one has :Remarks. 1
°)
andyx(i)
are in theset (
u Mu~,
indeed wheneverreaches {u
=Mu ~
itjumps
to come backin { u Mu ~.
Inparti-
cular
u( yx(2)) 10 ~ ~ _
oo ) . _2°)
One checks as in[~] ]
that n ~ + oo ;indeed
foreach n,
u( yX-1(~n)) _
+~n) > k, and,
since u iscontinuous,
>_ L > o.Since n ~
0 weobtain 1
+ ...+ n ~ Ln
and the formula:on
{~ oo }
shows that~
m + oo.In
(17)
we remark that :but we have :
since
Un __ ~
whenever oo. Thusadding (17)
foreach n >_
0 andusing
remark
2,
weget
and this means that
u >__
w and theorem 2 isproved.
III. SOME REMARKS ON THE OPERATOR M
The
operator
M which defines theQ.
V. I. is notalways given by (2).
Indeed when one deals with discontinuous solution the
operator
Mu has no clearmeaning
and theQ.
V. I. isgenerally
defined with an ope- ratorM + :
From a stochastical
viewpoint
it is also natural to consider admissiblesystems
such that thejumps ç
at apoint x
are constrained tosatisfy x + ~
E Qand no
longer
It will rise an otheroperator,
defined for x E 12:M +
is defined for any bounded from below measurable function and M- for u EC(Q).
Here wegive
the relation betweenM, M -,
M + .1.
Regularity
ofM, M-, M+.
PROPOSITION 3. - Let u E
C(Q)
then Mu is lower semi-continuous on ~(I.s.c.),
M _ u is upper semi-continuous(u.
s.c.)
and Mu _ M -u on S2.Proof
Theregularity
of Mu and theinequality
are clear. The other results are based on thefollowing
remark: take un EC(Q)
adecreasing
sequence such that u,~ n ~ u
pointwise
then decreases to M _ u.Now if we choose un such that
un > ~ ~
u and un‘~
on
Q,
then it iseasily
checked that is continuous and so, that Mu is u. s. c.PROPOSITION 4. -
If
u is u. s. c. then M-u is u. s. c. moreover,i~
co iscontinuous and u is u. s. c. then M -u = M + u on Q.
Proof
Theproof
ofProposition
3directly
proves the firstpart
ofAnnales de l’lnstitut Henri Poincaré - Analyse non linéaire
Proposition
4.Moreover,
if co is continuousand un
is chosen as above it is clear thatM + Un
= so that:M _ u _ M + u _ M+un
n ~M + u
onQ,
andProposition
4 isproved.
2. Relation between M and M-
(or M + ).
PROPOSITION 5.
- If Co is continuous,
u E and Q isof
classCN
then Mu =
M + u
a. e.Proof of Proposition
5. Let us introduce some notations : F will be the set ofpoints
wherepossibly M + u(x),
and will denoteby Tr( y)
thetangent hyperplane
to ~SZ at y andv( y)
the unit outward normal to aSZ at y. Then we have :F c
G== { ~- EO, 3y
> x, y E(ei, y-x)=O
for some i and x Ewhere is the canonical basis of
[RN.
This result has beenproved
in
[15 ],
but it is notprecise enough.
In fact we haveF c Gn
where :nN
Gi 1 - ~ x E ~,
y> ~ E)~
N such that :.
Let us prove that
F c Gn :
take some xo EF,
as xo E G there existsnN ~
y > x,
y ~ ~03A9
and some eil such that(etl, y - x)
= 0. We mayalways
choose ei2 ... eik ... ein such that : for 1
__ j k, y - x) ~
0for j >
k. Now assume that it means that for some 1> k, (eil, v( y)) ~
0.Since y > x then y + s e; > x for E small
enough,
and either y - E eil EQ,
or
y +
E eiz E Q for a smallenough.
In both cases weget
thatM+u(xo)
=Mu(xo),
indeed we know that
M + u(xo) >_- Mu(xo)
andThis
yields
a contradiction and thusx E Gk.
We now conclude with the :LEMMA 4. - For 1
_ k _ N,
meas(Gk)
= 0.STEP 1. - We prove that
Gi
is of zero measure and it isenough
toprove that
Vol.
v( y)
isparallel
to eN and(eN,
y -x)
=0 ~
is of zero mesure. Since theset of y E a~ such that
v(y)
isparallel
to eN iscompact,
it can be coveredby
a finite number of open setswhere fi
ECN and Oi
is an open set.Denoting y’ = ( y 1
...YN - 1)
it remains to prove that for these func- the sets : .is of zero measure. But :
Denoting by
theLebesgue
measure on R wehave, applying
Sard’sTheorem:
thus H is of zero measure and we conclude the first
step:
meas(Gi)
= 0.STEP 2. - In the same way we prove that
Gk
is of zero measure fork > 1: it is
enough
to prove thatHk
is of zero measure where :By
theimplicit
function Theorem andchanging eN
into some N - k+ 1,
if necessary we have
locally :
and it is
enough
tostudy
the set:But its measure is less than :
... ,
yN - k + 1 ~~
this last term is the measure of the critical values of the function
Annales de l’Institut Henri Poincaré - Analyse non linéaire
and so is zero
by
Sard’s theorem. This concludes theproof
of Lemma 4and of
Proposition
5.It is
quite
easier toget
thefollowing comparison Proposition
in whichwe consider M-u and Mu are defined for x E 0:
PROPOSITION 6. -
If
u EC(S~),
andco is a non-negative,
sub-additivefunction
such thatco(o)
--_0,
then the setof discontinuity points
in 03A9of M-u
is also the set
ofdiscontinuity points in
QofMu
and it is also the setof points
where
M _ u(x) ~ Mu(x).
COROLLARY. -
lf u
EC(Q),
M -u = Mu a. e. in Baire Sense.This is because we know that the set of
discontinuity
of a 1. s. c.(or
u. s.c.)
function is rare in Baire sense.
Proposition
6 isclearly
deduced from thefollowing :
LEMMA 5. - Under the
assumptions of Proposition
6:Let us prove the second
equality
which is the most difficult one : we knowthat lim sup and we shall prove
that:
Take xn
> xp and xn xo, +CO(çn)
+ + 0.Extracting
asubsequence
if necessary weassume: 03BEn
n~~03BE.
Since xn +03BEn -
xp>
xp >0,
we can find an EnE En n~~0,
x0 + 03BEn + En>
0and We have then :
Remark.
2014 1)
Here we have used the threeproperties
of co : co is subaddi-tive, co( ç) .~t
0 and co is 1. s. c. To prove the firstequality
ofProposition
6we
only
need co to be 1. s. c.2)
A useful consequence ofProposition
6 is that the solution of(3)
isalso the solution of:
in other words u is also the solution of the
impulsive
controlproblem
where the admissible
systems
are defined in such away that the processyx(t ) stays
in Q(and
nolonger
inQ)
and thestopping
time’! is the firstVol. 3-1985.
exit time from Q
(and
nolonger
fromQ).
This remark alsoapplies
to theresults
proved
in[16 ] for Q. V.
I. associated to Hamilton-Jacobi-Bellmanequations.
IV. HOLDER CONTINUITY OF THE SOLUTION OF
Q.
V. I.In this section we prove a
general
Holdercontinuity
result for theQ.
V. I. :where
f >_
0 anda( . , . )
is the bilinear form associated with A :(Au, v)
=a(u, v)
Indeed if we do not assume
(9)
thegeneral theory developped
in A. Ben-soussan and J. L. Lions
[3 ] shows
that(18)
has aunique
solution inHo,
but it is not continuous in
general
since ourassumptions
on co(see (2))
are too weak. Here we
give
aproof
of the Holdercontinuity
of u underassumption :
,(19)
co is continuous on((f$+)N, co(~) 0,
where cx is an
exponent
tobe precised
in Theorems 3 and 4. Such anassumption
hasalready
been introduced in A.Bensoussan,
J. Frehse andU. Mosco
[4 ],
or J. Frehse and U. Mosco[9] ] to
prove thecontinuity
ofQ.
V. I. withquadratic growth.
The method used here iscompletly
differentof the one in
[4 ] [9 ].
It consists ininterpreting
u as the solution of an obstacleproblem
where the obstacle T has somespecial property. Using
aregularity
result for linear second order
elliptic equations
on open setssatisfying
anexterior cone condition we prove that the solution is Holder continuous.
The
precise
result is thefollowing:
THEOREM 3. - Under
assumptions (5)-(7)
there exist some ao, 0 ao1,
such that
if (19)
holds with 0 a ao then the solutionof (18) belongs
toC0,03B1loc(03A9).
The
proof
of this Theorem is divided in twoparts :
first we prove that the solution u of(18)
is u. s. c., then we prove the Holdercontinuity
of u.Remark. Of course this result extends to the more
general
casewhere f
is
eventually negative
but(18)
has a subsolution. It also extends to anyboundary
data.1. Selection of an u. s. c. solution.
Here we make the
assumptions
of Theorem 3. We know that u is obtainedas the limit of the
decreasing
process as in I: uo is the solution ofAuo
=f,
uo e
C(Q). Then un
is the solution of:Annales de l’Institut Henri Poincaré - Analyse non linéaire
At each
step
we can select a u. s. c. solution un. Indeed if Un-1 is u. s. c.then
M-Un-1
=M+un-i by Proposition
5 since co is continuous(in particular
it doesn’tdepend
on the choice of the u. s. c.selection)
andwe know is u. s. c. Now take a
decreasing
sequence of obstacles03A8p MUn-1
the solution uP of the obstacleproblem
for is continuousp~~
and decreases
with p
to un(moreover
uPp~~
un inHo by
thegeneral theory
in[3 ])
so that we can select an u. s. c. solution un at eachstep.
Finally
since u~ isdecreasing
to u, u has a u. s. c.representant.
2. Holder
continuity
of u in theorem 3.Take a sequence n u in
Q,
un EC(Q)
and assume =II un
islarge enough
so that is continuous and We prove in what follows that eachsolution vn
of the obstacleproblem
for T = M-unbelongs
toC°~
with uniform bounds oncompact
subsets of Q.For any
x0 ~ 03A9
we denoteby d(xo)
the functiond(xo)
= infd(xo, y).
yeon
Since co is subadditive and
by (19)
we have for all y EQ, y --
xo : 1In the
following
we will denoteby:
and we define two open sets :
By
theappendix
1 if a is smallenough ( a ~
in Theorem4
we cansolve:
~ ~ ~
Vol. 2, n° 3-1985.
then we set :
The
Appendix
1 shows thatvxo(y)
is inC°°°‘
if a is smallenough
andI)
vxoIlco,a; ~ D(xo),
whereD(xo) only depends
ond(xo),
and so the obstacle Tdefined below is in
C°~
nC(Q) :
and we conclude
by
the :LEMMA 6. - The solution vn
of the
obstacleproblem for
the obstacle M -un is the solutionof :
Proof
- For any x e Q we have :hence w is a subsolution of
(18)
andw
vn. On the other hand for anyxo E Q we have :
This
implies
vxo,Vxo
i. e. vn ~F and then w; and Lemma 6 isproved.
Now we deduce Theorem 3 from Lemma 6: we notice that the Holder estimates on vn do not
depend
on un and since vn converges to u, Theo-rem 3 is
proved.
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire
APPENDIX I
CONSTRUCTION OF A BARRIER FUNCTION
FOR AN OPEN SET SATISFYING THE EXTERIOR CONE CONDITION In section IV we need to solve linear elliptic second order equations for open sets satisfying only the exterior cone condition. The purpose of this appendix is to show how to construct a barrier function in such cases (which do not seem to be classical). The results below are
due to K. Miller [15 where one can find another way to prove them.
In this section we are given an operator A and a function f satisfying assumptions (and notations) of section I. We denote B = ~~ bi and by
Cu
the cone:where r = I x j, and we construct a barrier function at the point 0 for the open set : The existence of a barrier function and its regularity are given in the :
THEOREM 4. - Let ,u E [0, 1 [ then there exist a E ]0, 1 [ such that for h E there
is a function v E n such that:
moreover a and ~~ v ~~~.« only depends on Ro, p, A, f and ~~ h Proof - We may assume h(0) = 0 and we look for v satisfying :
We will divide the proof in three parts : computation of Av, lower bound for Av, existence of g and a.
1. Computation of Av.
We assume ,u, + 1 ], and we compute:
Vol.
Introducing y
= - r~ ,
... , r2 ,1
- ~12
we get :2. A lower bound for Av.
We assume 0, g’ >__ 0, g" 0 and we put t = [ - 1, 1 ], then we get :
now we put x = (x’, xN) and 1 so that the coefficient of ra-
2g’(t )
is equal tohere C denotes different constants depending only on
(aij)
and we assume N > 2.Finally we get : _ _
It remains to find some g for which this expression is large enough.
3. Existence of g.
LEMMA 7. - For [0, 1 [ there exist a E ]0, 1 [ and
g~ E C°°( [- ,u, 1 ], ~+),
g~ >_ 1,g~ >-_ 0, g;~
>_ 0 such that :Proof of lemma 7. - We look for such that : then (21) becomes :
Annales de l’Institut Henri Poincaré - Analyse non linéaire
and a straightforward study of the function between the brackets shows that, if K is large enough (depending on and it is positive. Choosing a small enough we get lemma 7.
We can now conclude the proof of Theorem 4; by lemma 7 and choosing g = we have:
Av > where C(,u) is the minimum in (21), C(,u) > 0 ; for C large enough (20)
is satisfied and the dependance of C~ v on ~,, A, f and ~~ h is clear.
Remark. - Of course for each (3, 0 j~ a, and h E
{f~N)
we can find a barrierfunction in
Co°~{C~;)_
Vol.
APPENDIX 2
DIFFERENT NOTIONS OF SOLUTION FOR THE OBSTACLE PROBLEM
Throughout this paper we have used the notion of viscosity solution for the obstacle
problem. An other definition is given in a remark of Section I. On the other hand we could
use the usual definition of variational inequalities. The purpose of this Appendix is to
prove the equivalence between these three notions. Namely, we have, with the notations and assumptions of section I and IV:
PROPOSITION 7. - Let u and ’P belong to C(Q) then the following are equivalent : i) u is a viscosity solution of:
iii ) and u is a solution of the variational inequality associated to ’P i. e. :
iv ) u is the limit of solutions of
all
regularized obstacle problemwith
nice standardsolution (actually this limit holds in C(Q) and weakly in for all Q’ c Q’ c Q). In other words if we consider uE solution of:
with 03A8~ ~ rpE on aSZ, 03A8~ ~ 03A8 in C(SZ) and 03C6~ ~ qJ in then uE ~ u in C(H) and weakly in
Proof - The equivalence between (i) and (ii) is a simple consequence of the notion of viscosity solution as defined in P. L. Lions [13 ].
The
equivalence
between (i ) and (iv) is easily deduced from the stability (under conver-gence in C(Q) of the notion of viscosity solution and the existence results for (23) which
are proved in [2 ] and [16 ]. Remark that the family (ue) is bounded in (and thus the weak convergence holds) since we have:
and for ~ E ~+(SZ) and C large enough:
Annales de l’lnstitut Henri Poincaré - Analyse non linéaire