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www.elsevier.com/locate/anihpc

Point-condensation phenomena and saturation effect for the one-dimensional Gierer–Meinhardt system

Kotaro Morimoto

1

Department of Mathematics and Information Sciences, Tokyo Metropolitan University, 1-1 Minami-Ohsawa, Hachioji, Tokyo 192-0397, Japan Received 1 October 2009; received in revised form 11 December 2009; accepted 11 December 2009

Available online 7 January 2010

Abstract

In this paper, we are concerned with peak solutions to the following one-dimensional Gierer–Meinhardt system with saturation:

⎧⎪

⎪⎪

⎪⎪

⎪⎩

0=ε2AA+ A2

H (1+κA2)+σ, A >0, x∈(−1,1), 0=DHH+A2, H >0, x∈(−1,1), A(±1)=H(±1)=0,

whereε, D >0,κ0,σ0. The saturation effect of the activator is given by the parameterκ. We will give a sufficient condition ofκfor which point-condensation phenomena emerge. More precisely, for fixedD >0, we will show that the Gierer–Meinhardt system admits a peak solution whenεis sufficiently small under the assumption:κdepends onε, namely,κ=κ(ε), and there exists a limit limε0κε2=κ0for certainκ0∈ [0,∞).

©2010 Elsevier Masson SAS. All rights reserved.

MSC:35K57; 35Q80; 92C15

Keywords:Gierer–Meinhardt system; Saturation effect; Pattern formation; Nonlinear elliptic system

1. Introduction

In this paper, we are concerned with the following system of ordinary differential equations:

⎧⎪

⎪⎪

⎪⎪

⎪⎩

0=ε2AA+ A2

H (1+κA2)+σ, A >0, x∈(−1,1), 0=DHH+A2, H >0, x∈(−1,1), A(±1)=H(±1)=0,

(1)

E-mail address:[email protected].

1 Supported by Research Fellowships of Japan Society for the Promotion of Science for Young Scientists.

0294-1449/$ – see front matter ©2010 Elsevier Masson SAS. All rights reserved.

doi:10.1016/j.anihpc.2010.01.003

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where unknowns areA=A(x)andH=H (x).ε >0,D >0,κ0 andσ0 are constants. This system arises as a steady-state problem of the 1-dimensional Gierer–Meinhardt system with saturation which was proposed by A. Gierer and H. Meinhardt [4]. The general Gierer–Meinhardt system is written by

⎧⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

⎪⎪

⎪⎪

At=ε2AA+ Ap

Hq(1+κAp)+σ, A >0, x∈Ω, t >0, τ Ht=DHH+ Ar

Hs, H >0, x∈Ω, t >0,

∂A

∂ν =∂H

∂ν =0, x∂Ω, t >0,

A(x,0)=A0(x), H (x,0)=H0(x), xΩ,

(2)

whereA=A(x, t )andH=H (x, t ),τ >0,is the Laplace operator inRN,Ωis a bounded smooth domain inRN, ν is the unit outer normal to∂Ω. The exponents satisfy the conditionsp >1,q, r >0,s0, and 0< (p−1)/q <

r/(s+1). The unknownsA(x, t )andH (x, t )represent the concentrations of an activator and an inhibitor, respectively, atxΩ and timet >0.A0andH0are their initial data. One of the parameters of (2),κ stands for the degree of a saturation effect to the reaction term of the activator. The termσ0 is the source term.σ represent the source rate of the activator. This system expresses some models of biological pattern formation. It is known that (2) has various kinds of striking solutions whenεis small andDis large. In particular, we are mainly interested in a solution such that the activatorAis concentrated at a finite number of points inΩ. Such a solution is called a “peak solution”. Peak solutions represent point-condensation phenomena of the activator. Whenκ=0 (no saturation case), a lot of methods to construct peak solutions were established by many mathematicians. However, whenκ >0, it is not trivial whether a peak solution also exists or not. Whenκ >0 is fixed independently ofε, due to the bistable nonlinearity, solutions with transition layers may exist. Indeed, M. del Pino [3] showed the existence of solutions with multiple layers when the domainΩ is a ball. See also [1,16,7].

We introduce the shadow system of (2). Dividing the second equation in (2) by Dand taking the limitD→ ∞ formally, we haveH=0 inΩ and ∂H∂ν =0 on∂Ω. This means thatH (x, t )does not depend onx, and hence we can regardH (x, t )=ξ(t ). Thus we have the following system which is called the shadow system of (2):

⎧⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

⎪⎪

⎪⎪

⎪⎪

At=ε2AA+ Ap

ξq(1+κAp)+σ, A >0, x∈Ω, t >0, τ ξt= 1

|Ω|

Ω

ξ+Ar ξs

dx, ξ >0, t >0,

∂A

∂ν =0, x∂Ω, t >0,

A(x,0)=A0(x), ξ(0)=ξ0, xΩ.

(3)

For this shadow system, in the case(p, q, r, s)=(2,1,2,0),σ=0,κ >0, J. Wei and M. Winter [22] showed that the shadow system (3) admits a stationary solution concentrating at one point of the boundary for sufficiently smallε, and the stability was studied. In [8], multi-boundary peak stationary solutions to (3) has been constructed for sufficiently small ε in the case whereΩ ⊂RN is axially symmetric with respect toxN-axis,(p, q, r, s)=(2,1,2,0),σ =0, κ >0,N 5. Moreover, multi-boundary peak stationary solutions to the original Gierer–Meinhardt system (2) was constructed near the solution to the shadow system (3) for sufficiently largeDby using the implicit function theorem.

The result was extended to the case σ >0 in [10]. In [22,8,10], it was supposed thatκ0 depends on ε, namely κ =κ(ε), and there exists a limitκε2Nκ0∈ [0,∞)asε→0 for certainκ0. This condition is called a “weak saturation” condition. This condition gives one of the sufficient conditions for which peak solutions appear.

The method, namely, to find a stationary solution to (2) near the stationary solution to the shadow system (3) by the implicit function theorem, is one of the methods to construct a solution to the Gierer–Meinhardt system (2), which was developed from the work by W.-M. Ni and I. Takagi [14]. In general, the number D must be large enough in the method. However, the following question arises, “forD >0 given arbitrarily, does the Gierer–Meinhardt system (2) possess a peak solution under the weak saturation condition?”. The purpose of this paper is to construct a 1-peak solution concentrating at x=0 to the 1-dimensional Gierer–Meinhardt system (1) for any fixed finiteD (which is called the strong coupling case) under the weak saturation condition.

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We give remarks on other related results. For fixedκ >0, M. Mimura, M. Tabata and Y. Hosono [1] showed the existence of interior transition layers by using the singular perturbation method in the caseN =1. Y. Nishiura [15] showed that, for some 1-dimensional reaction–diffusion systems including the Gierer–Meinhardt system (2), the bifurcating branch emanating from a uniform state continues to exist until it is connected to the singularly perturbed solutions when one of the diffusion constants is sufficiently large. Multi-peak stationary solutions to (2) were first constructed by I. Takagi [17] in the caseκ=0,N=1. Moreover, its stability was discussed in [5]. In the caseκ=0 andN =1, J. Wei and M. Winter [23] studied the existence and stability of symmetric and asymmetric multi-peak stationary solutions to (2), and they showed that multi-peak stationary solutions are generated by exactly two types of peaks if the peaks are separated. In the caseκ=0 andN=2, multi-interior peak stationary solutions were constructed and the stability was discussed in [19–21]. With respect to the stability analysis for the Gierer–Meinhardt system and its shadow system, see [12,7,9], and the references therein. Some a priori estimate for a stationary solutions to (2) were given in [6,2,13]. For other results related to the Gierer–Meinhardt system, see [11,18,24] and the references therein.

Finally, we state remarks on our notation. For a domainΩ⊂R, we use standard Lebesgue spaces and Sobolev spacesL2(Ω),L(Ω),H2(Ω), and so on, with the usual norm. Throughout this paper, unless otherwise stated, we use the symbolsC, C, C, c, c, cas positive constants, but they need not have the same value in each situation.

This paper is composed as follows. In Section 2, we will state our main results, Theorem 1 and Theorem 2. In Section 3, we will prepare some lemmas and state an outline of our construction of a solution. In Section 4, we will give some estimates in order to prove the theorems. In Sections 5 and 6, we will give the proofs of Theorems 1 and 2.

2. Main results

We need some preliminaries to state our main results. We introduce a solution denoted bywδ to the following problem:

ww+fδ(w)=0, w >0,inR, w(0)=max

y∈Rw(y), w(y)→0 as|y| → ∞, (4)

fδ(w):= w2

1+δw2. (5)

It is known that, there exists a constantδ>0, the problem (4) has a unique solutionwδ for eachδ∈ [0, δ), andwδ is radially symmetric, namely,wδ(y)=wδ(y),y∈R. This fact was established in [22]. The numberδis given by

δ=sup δ >0: there existsa >0 such that a 0

t+fδ(t ) dt=0

. For fixedD >0, letGD(x, z)be Green’s function to

DGxx(x, z)G(x, z)= −δz(x) in(−1,1),

Gx(±1, z)=0. (6)

GD(x, z)can be written explicitly GD(x, z)=

θ

sinh(2θ )cosh[θ (1+x)]cosh[θ (1z)], −1< x < z,

θ

sinh(2θ )cosh[θ (1x)]cosh[θ (1+z)], z < x <1, (7)

whereθ:=D1/2. We put αD:= 1

GD(0,0). (8)

Moreover, the non-smooth part ofGD(x, z)is given by KD

|xz|

= 1 2√

De

1

D|xz|. (9)

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LetHD(x, z)be the regular part ofGD(x, z), GD(x, z)=KD

|xz|

HD(x, z).

HD(x, z)isCin bothxandz.

Next, we prepare a cut-off function. Let χC0(R)be a function such that, 0χ1,χ (x)=0 for|x|<1, χ (x)=1 for|x|>2. Letr0be a fixed constant such that 0< r0<1/2, for example,r0=1/10. We will use a cut-off function in the formχ (rx

0). Note thatχ (rx

0)=0 for|x|>2r0. We suppose the following assumption on the constantκ in (1).

(A) κ0 depends onε, and there exists a limit

εlim0κε2=κ0 (10)

for someκ0∈ [0,∞).

Let us state our main results. We first state a result in the caseσ=0.

Theorem 1.Letσ=0. FixD >0arbitrarily. We suppose(A), and let the valueκ0α2Dbe sufficiently small. Then, for sufficiently smallε >0,(1)admits a1-peak radially symmetric solution(Aε(x), Hε(x))such thatAε(x)concentrates atx=0. More precisely, there existsδε∈ [0, δ)for eachεsufficiently small such thatδεδ0asε→0for some δ0∈ [0, δ)which is decided byκ0andDand satisfies

δ0

R

wδ2

0(y) dy 2

=κ0α2D, (11)

andAεtakes the form:

Aε(x)= 1 ε

Rw2δ

ε

αDwδε

x ε

χ

x r0

+εφε

x ε

, x(−1,1), (12)

where αD is defined by(8),wδ is the unique solution to(4), andφε(y)is a radially symmetric function onΩε:=

(1ε,1ε)such that

φε H2ε)C (13)

holds for some constantC >0independent ofε.Hεhas the following property:

Hε(0)= 1 ε

Rw2δ

ε

αD+O(ε)

asε→0. (14)

Next, we state a result in the caseσ=0.

Theorem 2.Letσ >0. We assume the same assumption onκas in Theorem1. Then,(1)admits a radially symmetric solution providedεis sufficiently small. More precisely, if we fixσ >0andγ(0,1/2), there existsεˆ1>0such that, for all ε(0,εˆ1)andσ(0, σ ),(1)admits a radially symmetric solution(Aε,σ(x), Hε,σ(x)), andAε,σ takes the form:

Aε,σ(x)= 1 ε

Rwδε

αDwδε

x ε

χ

x r0

+εφε

x ε

+εγφε,σ

x ε

+σ, x(−1,1), (15) whereδεandφεare given in Theorem1, andφε,σ(y)is a radially symmetric function onΩεsuch that

φε,σ H2ε)σ (16)

holds, andHε,σ satisfies

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Hε,σ(0)= 1 ε

Rwδ2

ε

αD+O(ε)+ σ+σ2

O εγ

, (17)

asε→0, whereO(ε)andO(εγ)are independent ofσ.

Remark 3.The setting of the domain(−1,1)is not essential. For givenk∈N, if we construct a 1-peak solution to (1) on smaller domain in advance, then we can obtain ak-peak symmetric solution to (1) by reflections.

Remark 4.The assumption “κ0α2Dis sufficiently small” in Theorem 1 is due to some technical reason. See Remark 14 stated later.

3. Basic analysis and preliminaries

In this section, we prepare some lemmas to prove Theorem 1 and state the outline of our construction. We first define some function spaces as follows:

L2r(R):=

uL2(R): u(x)=u(x), x∈R

, (18)

Hr2(R):=H2(R)L2r(R), (19)

and for a domain(a, a),a(0,), L2r(a, a):=

uL2(a, a): u(x)=u(x), x(a, a)

, (20)

Hr2(a, a):=H2(a, a)L2r(a, a), (21)

Hr,ν2 (a, a):=

uHr2(a, a): u(±a)=0

. (22)

Because we will frequently use rescaling, we introduce the following notations.

Definition 5.PutΩε:=(1ε,1ε).

For a functionu:(−1,1)→R, letu(y):=u(εy),yΩε.

Inversely, for a functionv:Ωε→R, letv(x):=v(xε),x(−1,1).

3.1. Basic analysis

For the unique solutionwδto (4), let us state some known facts. After that, we state some new lemmas.

Lemma 6.For eachδ∈ [0, δ), the unique radially symmetric solutionwδhas the following properties:

(i) wδC(R).

(ii) Let

Lδ:= d2

dx2−1+fδ(wδ):H2(R)L2(R),

wherefδ(wδ)=2wδ/(1+δwδ2). Then,Ker(Lδ)=span{wδ}.

(iii) If we restrict the domain toDom(Lδ)=Hr2(R), thenLδhas a bounded inverseLδ1:L2r(R)Hr2(R).

(iv) If we fixδ(0, δ), then there exist constantsC, c >0such that wδ(y),

dnwδ dyn (y)

Cec|y|, y∈R, n=1,2, (23) holds for anyδ∈ [0, δ].

Proof. (i)–(iii) have been proven in Lemma 2.2 of [22]. (iv) have been proven in Lemma 2.4 of [8]. 2 We state continuity and differentiability ofwδonδ.

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Lemma 7.As aC1(R)-valued function ofδ,wδsatisfies the following:

(i) wδis continuous inδ∈ [0, δ)with respect to theC1(R)-norm.

(ii) wδis of classC1((0, δ), C1(R)).

Proof. This fact was proven in Lemma 2.3 of [22] (see also Lemma 2.3 of [8]). 2

Let us denote the derivatives of wδ inx and inδ by wδ(x)and dwδ, respectively. Next, we state some useful formulae.

Lemma 8.The following identities hold:

Lδwδ=fδ(wδ)wδfδ(wδ), (24)

Lδdwδ

=fδ2(wδ), (25)

Lδ

wδ+2δdwδ +1

2y·wδ

=wδ, (26)

Lδ

wδ+2δdwδ

=fδ(wδ). (27)

Proof. These facts were proven in Lemma 2.3 of [22]. 2

Lemma 9.wδbinCloc2 (R)holds asδδ, whereb >0is the second positive root oft+fδ(t )=0,t∈R.

Proof. This fact was proven in Lemma 2.3 of [22]. 2 Lemma 10.For anyδ(0, δ), it holds that

d

−∞

w2δ(y) dy

>0. (28)

Proof. This fact was proven in Lemma 2.6 of [22]. 2

Lemma 11.For fixedδ(0, δ), there exists constantC >0such that dwδ

H2(R)

C (29)

holds for anyδ(0, δ).

Proof. It is easy to see thatLδ1is bounded uniformly inδ∈ [0, δ]. By using (25) and Lemma 6(iv), we can estimate by some constantsC, C>0 independent ofδ∈ [0, δ]as follows:

dwδ

H2(R)

=Lδ1fδ2(wδ)

H2(R)Cfδ2(wδ)

L2(R)C. (30)

Hence we complete the proof. 2 Lemma 12.

(i) For eachδ∈ [0, δ), ifφHr2(R)satisfies the following:

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φφ+fδ(wδγ

Rwδφ

Rwδ2 fδ(wδ)=0 inR, (31)

γ=

Rw2δ

Rw2δ+2δ

Rwδdwδ, (32)

thenφ=0.

(ii) There existsδ1(0, δ)such that, forδ∈ [0, δ1), ifφHr2(R)satisfies the following:

φφ+fδ(wδγ

Rfδ(wδ

Rw2δ wδ=0 inR, (33)

γ=

Rw2δ

RLδ1(wδ)fδ(wδ), (34)

thenφ=0.

Before the proof, we state some remarks. Lemma 10 implies that

Rwδdwδ >0 for anyδ(0, δ). Hence, we first notice that

0<

Rwδ2

Rw2δ+2δ

Rwδdwδ

1, δ∈ [0, δ). (35)

Secondly, we consider the value of

RLδ1(wδ)fδ(wδ). By using (26) and integration by parts, we have

δlim0

R

Lδ1(wδ)fδ(wδ)=lim

δ0

R

wδ(y)+2δdwδ (y)+1

2y·wδ(y)

fδ wδ(y)

dy

=

R

w03(y)+1

2y·w0(y)w02(y)

dy

=

R

w03(y)−1 6w30(y)

dy

=5 6

R

w03(y) dy >0. (36)

Here, we note thatδ

Rdwδ

fδ(wδ) dy→0 asδ→0 by Lemma 11. Moreover, we see that w0w0+w20=0,

R

w0w0

R

w02+

R

w30=0,

R

w02

+

R

w20=

R

w03. (37)

Therefore,

Rw03>

Rw20. Thus we have

Rw2δ

RLδ1(wδ)fδ(wδ)

δ=0

=

Rw02

5 6

Rw30 <6

5. (38)

Proof. (i) By using (27), the equation (31) can be written as follows:

Lδφ=γ

Rwδφ

Rwδ2 fδ(wδ), φ=γ

Rwδφ

Rw2δ Lδ1 fδ(wδ)

,

R

wδφ=γ

Rwδφ

Rw2δ

R

w2δ+2δ

R

wδdwδ

. Hence,

Rwδφ=0 must be hold by (32). Thus we haveLδφ=0,φHr2(R), and henceφ=0 by Lemma 6(iii).

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(ii) Defineδ1by δ1:=sup

δ(0, δ):

R

Lδ1(wδ)fδ(wδ) >0 forδ(0, δ)

. (39)

Thisδ1is well defined by (36). Then we can prove by the same argument as in the proof of (i). 2 Now, we define an operatorLδonL2(R)with Dom(Lδ)=H2(R)by

Lδφ=φφ+fδ(wδ−2

Rwδφ

Rwδ2 fδ(wδ). (40)

Its conjugate operator is given by Lδψ=ψψ+fδ(wδ−2

Rfδ(wδ

Rw2δ wδ, ψH2(R). (41)

Let us defineδ2by δ2=sup

δ(0, δ1):

Rw2δ

RLδ1(wδ)fδ(wδ)<2 forδ(0, δ)

, (42)

whereδ1is defined by (39). Thisδ2is well defined by (38).

Lemma 13.For the operatorsLδandLδ, andδ2defined above, there hold that (i) Ker(Lδ)Hr2(R)= {0}for anyδ∈ [0, δ),

(ii) Ker(Lδ)Hr2(R)= {0}for anyδ∈ [0, δ2).

Proof. This lemma is a consequence of Lemma 12. 2

Remark 14.We do not know whether Ker(Lδ)Hr2(R)is trivial or not forδ nearδ. If Ker(Lδ)Hr2(R)= {0} holds for allδ∈ [0, δ), then we can remove the assumption “κ0αD2 is sufficiently small” in Theorem 1. However, it seems to be a difficult problem.

3.2. Outline of our construction

We state an outline of our construction. We see by Lemmas 9–11 that there exists uniqueδε∈ [0, δ)such that δε

R

w2δ

ε

2

=κε2α2D (43)

holds for eachε >0. By the assumption (A), in the limitε→0, there hold that δεδ0, δ0

R

wδ2

0

2

=κ0α2D, (44)

as ε→0, for someδ0∈ [0, δ). We assume henceforth that κ0α2D0 is small enough so thatδ0∈ [0, δ2), where δ2 is given by (42). Then we note that there existsδ(0, δ2)such thatδε ∈ [0, δ] holds for allε >0 sufficiently small. Hence, we may assume thatc <

Rwδ2

ε(y) dy < Cholds for allεsufficiently small, the constantsc, C >0 are independent ofε.

Put

cε:= 1 ε

Rwδ2

ε

. (45)

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We consider the following problem foraandh:

⎧⎪

⎪⎪

⎪⎪

⎪⎩

ε2aa+ a2

h(1+δεαD2a2)+σε=0, a >0, x∈(−1,1), Dhh+cεa2=0, h >0, x∈(−1,1), a(±1)=h(±1)=0,

(46)

where σε:= σ

cε. (47)

If we obtain a solution to (46), then we obtain a solution to (1) by puttingA(x)=cεa(x)andH (x)=cεh(x). For UHr,ν2 ε), letT[U]be a unique solution to the following problem forv:

Dvv+cεU2=0, x(−1,1),

v(±1)=0. (48)

Here, the under-bar and over-bar notation is due to Definition 5. Moreover, we put S[U](y):=U(y)U (y)+ U2(y)

T[U](y)(1+δεαD2U2(y)), yΩε. (49) If we can findUHr,ν2 ε)such that,S[U] +σε=0, U >0 inΩε, then we obtain a solution to (46) by putting a(x)=U (x)andh(x)=T[U](x).

Here, we note thatT[U]is written by using Green’s function as follows:

T[U](x)=cε 1

1

GD(x, z)U2(z) dz, x(−1,1), (50)

forUL2ε). In particular,T[U]is radially symmetric providedU is radially symmetric. Now, let us define an approximate functionwεas follows:

wε(x):=αDwδε x

ε

χ x

r0

, (51)

whereαD=GD(0,0)1,wδε is the unique solution to (4) forδ=δε,χis the cut-off function defined in the previous section. We will first consider the case σ =0 and prove Theorem 1 in Section 5. For the purpose, we will seek UHr,ν2 ε)such thatS[U] =0,U >0 inΩεin the formU (y)=wε(y)+εφ(y)for someφHr,ν2 ε). Next, we will consider the caseσ=0 in Section 6. Note thatε=)σ/cεCσ εholds for some constantC >0 independent ofεsufficiently small. Therefore, we can prove Theorem 2 by a perturbation argument.

4. Basic estimates

In this section, we show some basic estimates.

Lemma 15.There existsc1>0such thatT[wε](x)c1,x(−1,1), for allεsufficiently small.

Proof.

T[wε](x)=cε 1

1

GD(x, z)w2ε(z) dx

=α2Dcε 1

1

GD(x, z)w2δ

ε

z ε

χ2 z

r0

dz

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=αD2εcε 1/ε

1/ε

GD(x, εz)w2δ

ε(z)χ2 ε

r0

z

dz

αD2

Rwδ2

ε

θ sinh(2θ )

1/ε

1/ε

w2δ

ε(z)χ2 ε

r0z

dz

= α2D

Rwδ2

0

θ sinh(2θ )

−∞

w2δ

0(z) dz+o(1),

asε→0, whereo(1)is uniform inx(−1,1). This estimate completes the proof. 2 Next, we show the following elementary inequality.

Lemma 16.For the non-smooth partKD(|xz|)ofGD(x, z), the following estimate holds:

KD

|x|

KD

|y| 1 2√ D

1

D|x| − |y|+1 2

1

D 2

|x|2+ |y|2

. (52)

Proof. This lemma is easily verified by (9) and the following elementary inequality:

1− |x|e−|x|1− |x| +1 2|x|2. Thus, we omit the details. 2

Lemma 17.Forwεdefined by(51), it holds that

T[wε](0)=αD+O(ε), (53)

asε→0.

Proof. Note that T[wε](0)=cε

1

1

GD(0, z)wε2(z) dz= αD2

Rwδ2

ε

1/ε

1/ε

GD(0, εz)wδ2ε(z)χ2 ε

r0

z

dz, and the following inequality holds:

|z|<rε0

GD(0, εz)wδ2ε(z) dz 1/ε

1/ε

GD(0, εz)w2δε(z)χ2 ε

r0z

dz

|z|<2rε0

GD(0, εz)wδ2ε(z) dz. (54)

The left-hand side of (54) is written as follows:

(l.h.s.)=GD(0,0)

|z|<rε0

wδ2

ε(z) dz+

|z|<rε0

GD(0, εz)GD(0,0) w2δ

ε(z) dzI+II.

Moreover, notingαD1=GD(0,0), we can estimate by Lemma 6(iv) so that I=αD1

R

w2δ

ε(z) dz

|z|>rε0

wδ2

ε(z) dz

=αD1

R

w2δ

ε(z) dz+e.s.t., (55)

(11)

where “e.s.t.” means “exponentially small term”. Next, we can estimate by Lemma 16 and the mean value theorem as follows:

|II|

|z|<rε0

KD ε|z|

KD(0)wδ2

ε(z) dz+

|z|<rε0

HD(0, εz)HD(0,0)wδ2

ε(z) dz

C

|z|<rε0

ε|z|w2δ

ε(z) dz Cε.

Here, we note that,ε2|z|2< ε|z|r0for|z|< r0/ε,

R|z|w2δ

ε(z) dzis bounded uniformly inεsufficiently small since we may assumeδε∈ [0, δ]and we can apply Lemma 6(iv). Hence

l.h.s. of (54)

=αD1

R

wδε+O(ε). (56)

We can see that the right-hand side of (54) have the same behavior as (56). Thus we have T[wε](0)= αD2

Rwδ2

ε

αD1

R

w2δ

ε(z) dz+O(ε)

=αD+O(ε).

Thus we complete the proof. 2

Lemma 18.For some constantC >0, the following estimate holds:

T[wε](εy)T[wε](0)C

ε|y| +ε

, yΩε, (57)

for allεsufficiently small.

Proof.

T[wε](εy)T[wε](0)=cε

1

1

GD(εy, z)GD(0, z)

wε2(z) dz

= α2D

Rw2δ

ε

1/ε

1/ε

GD(εy, εz)GD(0, εz) w2δ

ε(z)χ2 ε

r0z

dz

= α2D

Rw2δ

ε

1/ε

1/ε

KD

ε|yz|

KD

ε|z|

w2δε(z)χ2 ε

r0z

dz

1/ε

1/ε

HD(εy, εz)HD(0, εz) wδ2

ε(z)χ2 ε

r0z

dz

. Now, by Lemma 16, and notingε|z|1 for|z|1/ε, the following estimate holds:

KD

ε|yz|

KD

ε|z||y| − |yz|+ε2

|yz|2+ |z|2 Cε

|y| + |z|

, y, zΩε, for someC, C>0 independent ofε,yandz. Moreover, we can estimate by the Maclaurin expansion as follows:

HD(εy, εz)HD(0, εz)Cε

|y| + |z|

, y, zΩε, for someC>0 independent ofε,yandz. Thus we have

(12)

T[wε](εy)T[wε](0)ε αD2

Rwδ2

ε

C+C 1/ε

1/ε

|y| + |z| wδ2

ε(z) dzC

ε|y| +ε

, yΩε, for someC>0 independent ofεandy. Thus we complete the proof. 2

Lemma 19.There existsC1>0such that S[wε]

L2ε)C1ε, (58)

for allεsufficiently small.

Proof. It is easily to see thatwεwε= −fδε(wδεD+e.s.t. inL2ε)asε→0. Hence, S[wε](y)= −fδε(wδεD+ 1

T[wε](y)

w2ε(y)

1+δεαD2w2ε(y)+e.s.t.

= −fδε(wδεD+ 1 T[wε](y)

α2Dw2δ

ε(y)χ2(rε

0y) 1+δεwδ2

ε(y)χ2(rε

0y)+e.s.t.

= −fδε(wδεD+ α2D

T[wε]fδε(wδε)+e.s.t. inL2ε).

By Lemma 17, we have

fδε(wδεD+ α2D

T[wε]fδε(wδε)=fδε(wδεD

−1+ αD

T[wε](0)+ αD

T[wε](y)αD T[wε](0)

=fδε(wδεD

O(ε)+ αD

T[wε](εy)T[wε](0)

T[wε](0)T[wε](εy) . Moreover, by Lemma 18, the following estimate holds:

fδ

ε(wδε)

T[wε](0)T[wε](εy)2

L2ε)=

Ωε

w4δ

ε

(1+δεw2δ

ε)2

T[wε](0)T[wε](εy)2

dy

C

Ωε

w4δ

ε(y)

ε|y| +ε2

dyCε2,

for some constantsC, C>0 independent ofεsufficiently small. From these estimates and by Lemma 15, we have a conclusion. 2

Next, we give the derivatives ofT andS. The proofs of Lemmas 20, 21 below are uninteresting calculation. So we give their proofs in Appendix A.

Lemma 20. If we regard T as a mapping form L2(−1,1) into L(−1,1), then T is Fréchet differentiable on L2(−1,1), and its derivative atuL2(−1,1)is given by

T[u]φ=2cε

1

1

GD(x, z)u(z)φ(z) dz, φL2(−1,1). (59)

Moreover, for some constantC >0independent ofεsufficiently small, the following estimates hold:

T[u+h] −T[u] −T[u]h

Lε)C h 2

L2ε), (60)

T[u]h

Lε)C u L2ε) h L2ε), (61)

for anyu, hL2ε).

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