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Contents lists available atScienceDirect

Journal of Mathematical Analysis and Applications

www.elsevier.com/locate/jmaa

Multiple positive solutions for a Dirichlet problem involving critical Sobolev exponent

Tiexiang Li

a

, Tsung-fang Wu

b

,∗

aDepartment of Mathematics, Southeast University, Nanjing 211189, PR China

bDepartment of Applied Mathematics, National University of Kaohsiung, Kaohsiung 811, Taiwan

a r t i c l e i n f o a b s t r a c t

Article history:

Received 30 September 2009 Available online 16 March 2010 Submitted by J. Wei

Keywords:

Ljusternik–Schnirelmann category Multiple positive solutions Critical Sobolev exponent Nehari manifold

In this paper, we study the decomposition of the Nehari manifold via the combination of concave and convex nonlinearities. Furthermore, we use this result and the Ljusternik–

Schnirelmann category to prove that the existence of multiple positive solutions for a Dirichlet problem involving critical Sobolev exponent.

©2010 Elsevier Inc. All rights reserved.

1. Introduction

In this paper, we study the multiplicity of positive solutions for the following semilinear elliptic problem:

u

=

fλ

(

x

)|

u

|

q2u

+

g

(

x

)|

u

|

p2u in

Ω,

u

=

0 in

∂Ω,

(Eλ)

where 1

<

q

<

2

<

p2

=

N2N2 (N3),

Ω

RN is a bounded domain with smooth boundary, the parameter

λ >

0 and the weight functions fλ

= λ

f+

+

f−(f±

= ±

max

{

f

,

0

}

),g are continuous on

Ω

which satisfy the following condition:

(

Q

)

there exist a non-empty closed setM

= {

x

Ω |

g

(

x

) =

maxx∈Ωg

(

x

)

1

}

and

ρ >

N

2 such that M

x

Ω

f

(

x

) >

0

and

g

(

z

)

g

(

x

) =

O

|

x

z

|

ρ

asx

zand uniformly inz

M

.

Remark 1.1.LetMr

= {

x

RN

|

dist

(

x

,

M

) <

r

}

forr

>

0. Then by the condition

(

Q

)

, we may assume that there exist two positive constantsC0andr0such that

f

(

x

),

g

(

x

) >

0 for allx

Mr0

Ω

*

Corresponding author.

E-mail addresses:txli@seu.edu.cn(T. Li),tfwu@nuk.edu.tw(T.-f. Wu).

0022-247X/$ – see front matter ©2010 Elsevier Inc. All rights reserved.

doi:10.1016/j.jmaa.2010.03.022

(2)

and

g

(

z

)

g

(

x

)

C0

|

x

z

|

ρ for allx

BN

(

z

,

r0

)

and for allz

M

.

That the existence and multiplicity of positive solutions of Eq.

(

Eλ

)

may be influenced by the concave and convex nonlinearities. These issues have been the focus of a great deal of research in recent years. When the weight functions

λ

and g

1, Ambrosetti, Brezis and Cerami [1] has proved that there exists

λ

0

>

0 such that Eq.

(

)

admits at least two positive solutions for

λ(

0

, λ

0

)

, a positive solution for

λ = λ

0 and no positive solution for

λ > λ

0. Actually, Adimurthy, Pacella and Yadava [2], Ouyang and Shi [20] and Tang [22] proved that there exists

λ

0

>

0 such that Eq.

(

Eλ

)

in unit ball BN

(

0

;

1

)

has exactly two positive solutions for all

λ(

0

, λ

0

)

, has exactly one positive solution for

λ = λ

0 and no positive solution for all

λ > λ

0. When the weight functions f

,

g are sign-changing, Brown and Wu [6,7], de Figueiredo, Gossez and Ubilla [14], Hsu and Lin [15] and Wu [25,26] they proved that Eq.

(

Eλ

)

has at least two positive solutions when

λ

is sufficiently small. Furthermore, if p

=

2 and f

,

g

C

(Ω)

satisfy the following conditions:

(

D1

)

BN

(

2

δ

0

) \

BN

0

)Ω

for some

δ

0

>

0, where BN

(

r

) = {

x

RN

| |

x

| <

r

}

;

(

D2

)

f

=

f+

f−, where f±

: Ω

Rare continuous functions and there exists a domain BN

(

2

δ

0

) \

BN

0

)ΘΩ

of classC1such that for allx

Θ

, f

(

x

) =

0, f+

(

x

) >

0 and for allx

Ω\Θ

, f

(

x

)

0, f+

(

x

) =

0;

(

D3

)

theN-ball BN

(

2

δ

0

)Ω

such that for allx

BN

0

)

, 0

<

g

(

x

) <

1 and for allx

Ω\

BN

(

2

δ

0

)

, 0g

(

x

) <

1;

(

D4

)

g

(

x

) =

0 for allx

BN

(

2

δ

0

) \

BN

0

)

,

then Wu [27] proved that Eq.

(

Eλ

)

has at least three positive solutions when

λ

is sufficiently small.

The main purpose of this paper is to consider the relation between the number of solutions and the topology of the global maxima set of weight function g. Our main result improves a recent multiplicity result of [15,25,27]. The following theorem is our main result.

Theorem 1.1.Suppose that p

=

2. Then for each

δ <

r0there exists

Λ

δ

>

0such that for

λ < Λ

δ, Eq.

(

Eλ

)

has at least catMδ

(

M

) +

1 positive solutions.

Hereaftercatis the Ljusternik–Schnirelmann category (see e.g. [17]).

In the following sections, we proceed to proof Theorem 1.1. We use the variational methods to find positive solutions of Eq.

(

Eλ

)

. Associated with Eq.

(

Eλ

)

, we consider the energy functional JλinH01

(Ω)

,

Jλ

(

u

) =

1

2

u

2H1

1 q

Ω

fλ

|

u

|

qdx

1 2

Ω

g

|

u

|

2dx

where

u

H1

= (

Ω

|∇

u

|

2dx

)

1/2 is the standard norm in H01

(Ω)

. It is well known that the solutions of Eq.

(

Eλ

)

are the critical points of the energy functional JλinH01

(Ω)

.

This paper is organized as follows. In Section 2, we give some notations and preliminaries. In Section 3, we discuss some concentration behavior. In Section 4, we prove Theorem 1.1.

2. Notations and preliminaries

Throughout this paper, we denote by S the best Sobolev constant for the embedding ofD1,2

(

RN

)

intoL2

(

RN

)

which is given by

S

=

inf

uD1,2(RN)\{0}

RN

|∇

u

|

2dx

(

RN

|

u

|

2dx

)

2/2

>

0

.

(2.1)

It is well known that Sis independent of

Ω

RN in the sense that if S

(Ω) =

inf

uH10(Ω)\{0}

Ω

|∇

u

|

2dx

(

Ω

|

u

|

2dx

)

2/2

>

0

,

then S

(Ω) =

S

(

RN

) =

S, and the function uε

(

x

) = ε

(N2)/2

( ε

2

+ |

x

|

2

)

(N2)/2

, ε >

0 andx

∈ R

N

,

is an extremal function for the minimum problem

(

2

.

1

)

. Moreover, for each

ε >

0, vε

(

x

) = [

N

(

N

2

) ε

2

]

(N2)/4

( ε

2

+ |

x

|

2

)

(N2)/2 (2.2)

(3)

which is a positive solution of critical problem:

u

= |

u

|

22u in

R

N (2.3)

with RN

|∇

|

2dx

=

RN

|

|

2dx

=

SN2.

We define the Palais–Smale (simply by (PS)) sequences, (PS)-values, and (PS)-conditions in H10

(Ω)

for Jλas follows.

Definition 2.1.

(i) For

β

R, a sequence

{

un

}

is a

(

PS

)

β-sequence in H10

(Ω)

for Jλif Jλ

(

un

) = β +

o

(

1

)

; and Jλ

(

un

) =

o

(

1

)

; strongly in H1

(Ω)

asn

→ ∞

.

(ii) Jλsatisfies the

(

PS

)

β-condition inH01

(Ω)

if every

(

PS

)

β-sequence in H01

(Ω)

for Jλcontains a convergent subsequence.

As the energy functional is not bounded below on H10

(Ω)

, it is useful to consider the functional on the Nehari manifold

Nλ

=

u

H10

(Ω) \{

0

}

Jλ

(

u

),

u

=

0

.

Thus,u

Nλif and only if

u

2H1

Ω

|

u

|

qdx

Ω

g

|

u

|

2dx

=

0

.

Moreover, we have the following results.

Lemma 2.2.The energy functional Jλis coercive and bounded below onNλ.

Proof. Ifu

Nλ, then by the Young and Sobolev inequalities Jλ

(

u

) =

1

N

u

2H1

1

q

1 2

Ω

fλ

|

u

|

qdx (2.4)

1

N

u

2H1

λ

2

q

q2

f+

LqSq2

u

qH1 (2.5)

1

N

u

2H1

1

N

u

2H1

D

λ

2/(2q)

= −

D0

λ

2/(2q)

,

(2.6)

whereq

=

22q andD is a positive constant depending onq

,

N

,

S and

f+

Lq∗. Thus, Jλis coercive and bounded below onNλ. 2

Define

ψ

λ

(

u

) =

Jλ

(

u

),

u

=

u

2H1

Ω

fλ

|

u

|

qdx

Ω

g

|

u

|

2dx

.

Then foru

Nλ,

ψ

λ

(

u

),

u

=

2

u

2H1

q

Ω

|

u

|

qdx

2

Ω

g

|

u

|

2dx

= −

4

N

2

u

2H1

q

2

Ω

fλ

|

u

|

qdx (2.7)

= (

2

q

)

u

2H1

2

q

Ω

g

|

u

|

2dx

.

(2.8)

Similarly to the method used in [26], we splitNλinto three parts:

N+λ

=

u

Nλ

ψ

λ

(

u

),

u

>

0

;

N0λ

=

u

Nλ

ψ

λ

(

u

),

u

=

0

;

Nλ

=

u

Nλ

ψ

λ

(

u

),

u

<

0

.

We now derive some basic properties ofN+λ,N0λandNλ.

(4)

Lemma 2.3.Suppose that u0is a local minimizer for JλonNλand that u0

/

N0λ. Then Jλ

(

u0

) =

0in H1

(Ω)

. Furthermore, if u0is a non-trivial nonnegative function in

Ω

, then u0is a positive solution of Eq.

(

Eλ

)

.

Proof. Similarly the argument in [8, Theorem 2.3] (or see [3]), we have Jλ

(

u0

) =

0 in H1

(Ω)

. This implies u0 is a weak solution of Eq.

(

Eλ

)

. Now, ifu0 is a non-trivial nonnegative function in

Ω

, then by [13, Lemma 2.1], we haveu0

L

(Ω)

. Moreover, we can apply the Harnack inequality due to [23] in order to getu0 is positive in

Ω

. 2

Lemma 2.4.For each

λ >

0we have the following:

(i) For any u

N+λ, we have Ω

|

u

|

qdx

>

0.

(ii) For any u

N0λ, we have Ω fλ

|

u

|

qdx

>

0and Ωg

|

u

|

2dx

>

0.

(iii) For any u

Nλ, we have Ωg

|

u

|

2dx

>

0.

Proof. The result now follows immediately from

(

2

.

7

)

and

(

2

.

8

)

. 2

Let

Λ

1

=

S

N(2q) 4 +q

2

f+

Lq∗

(

22qq

)

(N−2)(2−q)4

(

222q

)

. Then by an argument similar to that the proof Lemma 2.1 in [26], we have N0λ

= ∅

for all

λ(

0

, Λ

1

)

. Thus, we can writeNλ

=

N+λ

Nλ and define

α

λ+

=

inf

uN+λ Jλ

(

u

)

and

α

λ

=

inf

uNλ Jλ

(

u

).

Moreover, we have the following result, whose proof can be found in [27, Theorem 3.1].

Theorem 2.5.We have the following:

(i)

α

+λ

<

0for all

λ(

0

, Λ

1

)

.

(ii) If

λ < Λ

2

=

q2

Λ

1, then

α

λ

>

c0for some c0

>

0.

In particular,

α

+λ

=

infuNλ

(

u

)

for all

λ(

0

, Λ

2

)

.

For each u

H10

(Ω) \{

0

}

with Ωg

|

u

|

2dx

>

0, we write

tmax

=

(

2

q

)

u

2H1

(

2

q

)

Ωg

|

u

|

2dx

N42

>

0

.

Then we have the following lemma.

Lemma 2.6.For each u

H10

(Ω) \{

0

}

we have the following:

(i) If Ω

|

u

|

qdx0, then there is a unique t

=

t

(

u

) >

tmaxsuch that tu

Nλ and huis increasing on

(

0

,

t

)

and decreasing on

(

t

,)

. Moreover,

Jλ

tu

=

sup

t0 Jλ

(

tu

).

(2.9)

(ii) If Ω fλ

|

u

|

qdx

>

0, then there are unique0

<

t+

=

t+

(

u

) <

tmax

<

t such that t+u

N+λ, tu

Nλ, hu is decreasing on

(

0

,

t+

)

, increasing on

(

t+

,

t

)

and decreasing on

(

t

, ∞)

. Moreover,

Jλ

t+u

=

inf

0ttmax

Jλ

(

tu

) ;

Jλ

tu

=

sup

tt+

Jλ

(

tu

).

(2.10)

Proof. The proof is almost the same as the in [26, Lemma 2.4]. 2 Forc

>

0, we define

J0c

(

u

) =

1

2

u

2H1

c 2

Ω

g

|

u

|

2dx

;

Nc0

=

u

H10

(Ω)\{

0

}

Jc0

(

u

),

u

=

0

.

Note thatNc0

=

N0

=

N0 forc

=

1 and for eachu

Nλ there is a uniquetu

>

0 such thattuu

N0. Moreover, we have the following result, whose proof can be found in [25, Lemma 5.2].

(5)

Lemma 2.7.Let q

=

22q. Then for each u

Nλ we have the following:

(i) There is a unique tc

(

u

) >

0such that tc

(

u

)

u

Nc0and

sup

t0 Jc0

(

tu

) =

J0c

tc

(

u

)

u

=

1 N

u

2H1

c Ωg

|

u

|

2dx

N22

.

(ii)

Jλ

(

u

) (

1

λ)

N2 J0

(

tuu

)λ(

2

q

)

2q

f+

LqS2q

22q

and

Jλ

(

u

) (

1

+ λ)

N2 J0

(

tuu

) + λ(

2

q

)

2q

f+

LqS2q

22q

.

3. Concentration behavior

First, we consider the following critical problem:

u

= |

u

|

22u in

Ω,

u

H10

(Ω).

(

E0)

Associated with Eq.

(

E0

)

, we consider the energy functional J inH10

(Ω)

, J

(

u

) =

1

2

u

2H1

1 2

Ω

|

u

|

2dx

.

It is well known that inf

uN(RN)

J

(

u

) =

inf

uN(Ω)J

(

u

) =

1

NSN2 for all domain

Ω ⊂ R

N

,

where N

R

N

=

u

D1,2

R

N

\{

0

}

J

(

u

),

u

=

0

and

N

(Ω) =

u

H10

(Ω)\{

0

} (

u

),

u

=

0

are the Nehari manifolds. Actually, infuN(Ω)J

(

u

)

is never attained on a domain

Ω

RN. Following the method of [4]

and Remark 1.1, let

η

C0

(

RN

)

be a radially symmetric function such that 0

η

1,

|∇ η |

C and

η (

x

) =

1

, |

x

|

r0

/

2

,

0

, |

x

|

r0

.

For anyz

M, let

wε,z

(

x

) = η (

x

z

)

vε

(

x

z

),

(3.1)

where

(

x

)

as in

(

2

.

2

)

. Then, by an argument similar to that the proof Lemma 4.2 in [16] (or see Struwe [21]), we have

wε,z

2H1

=

SN2

+

O

ε

N2

uniformly inz

M

.

(3.2)

Moreover, we have the following results.

Lemma 3.1.We have uinf∈N0

J0

(

u

) =

inf

uN(Ω)J

(

u

) =

1 NSN2

.

Furthermore, Eq.

(

E0

)

does not admit any positive solution u0such that J0

(

u0

) =

N1SN2.

(6)

Proof. Letwε,zbe as in

(

3

.

1

)

and define g

:

RN

Rby g

(

x

) =

g

(

x

),

ifx

Ω,

0

,

ifx

Ω

c

,

as an extension of g. Then, by Lemma 2.6, there is a uniquet0

(

wε,z

) >

0 such thatt0

(

wε,z

)

wε,z

N0for all

ε >

0, that is

t0

(

wε,z

)

wε,z

2

H1

=

Ω

g

t0

(

wε,z

)

wε,z

2dx

and so

t0

(

wε,z

)

4/(N2)

=

Ωg

|

wε,z

|

2dx

wε,z

2H1

.

(3.3)

By the definition of, we get that

Ω

g

|

wε,z

|

2dx

=

BN(z,2r0)

g

(

x

) η (

x

z

)

vε

(

x

z

)

2dx

=

RN

[

N

(

N

2

) ε

2

]

N/2g

(

x

+

z

) η

2

(

x

) ( ε

2

+ |

x

|

2

)

N dx

.

Thus, by the condition

(

Q

)

,

0

1

[

N

(

N

2

) ε

2

]

N/2

RN

|

vε

|

2dx

Ω

g

|

wε,z

|

2dx

=

RN\BN(0,r0/2)

[

1

g

(

x

+

z

) η

2

(

x

)]

( ε

2

+ |

x

|

2

)

N dx

+

BN(0,r0/2)

[

1

g

(

x

+

z

)]

( ε

2

+ |

x

|

2

)

N dx

RN\BN(0,r0/2) 1

|

x

|

2Ndx

+

C0

BN(0,r0/2)

|

x

|

ρ

( ε

2

+ |

x

|

2

)

Ndx

N

ω

N

r0/2

r−(N+1)dr

+

C0N

ω

N

ε

2

r0/2

0

rρN+1dr

= ω

N

r0 2

N

+

C0N

ω

N

ε

2

( ρ(

N

2

))

r0

2

ρ−(N2)

=

C1

+

C2

ε

2 for allz

M

,

(3.4)

where

ω

N is the volume of the unit ball BN

(

0

,

1

)

inRN. Then εlim→0

Ω

g

|

wε,z

|

2dx

=

SN2 uniformly inz

M

.

(3.5)

From the condition

(

Q

)

and the same argument of

(

3

.

5

)

, we have εlim→0

Ω

f

|

wε,z

|

2dx

=

0 uniformly inz

M

.

(3.6)

By

(

3

.

2

)

,

(

3

.

5

)

and

(

3

.

6

)

,

εlim→0t0

(

wε,z

) =

1 and lim

ε0

wε,z

2H1

=

SN2 uniformly inz

M

.

Thus, uinf∈N0

J0

(

u

)

J0

t0

(

wε,z

)

wε,z

1

NSN2 as

ε

0

and so inf

uN0

J0

(

u

)

inf

uN(Ω)J

(

u

) =

1 NSN2

.

(7)

Letu

N0. Then, by Lemma 2.6(i), J0

(

u

) =

supt0 J0

(

tu

)

. Moreover, there is a uniquetu

>

0 such thattuu

N

(Ω)

. Thus, J0

(

u

)

J0

(

tuu

)

J

(

tuu

)

1

NSN2

.

This implies infuN0 J0

(

u

)

1NSN2. Therefore, uinf∈N0

J0

(

u

) =

inf

uN(Ω)J

(

u

) =

1 NSN2

.

Next, we will show that Eq.

(

E0

)

does not admit any solution u0 such that J0

(

u0

) =

infuN0 J0

(

u

)

. Suppose the contrary.

Then we can assume that there existsu0

N0 such that J0

(

u0

) =

infuN0 J0

(

u

)

. Since J0

(

u0

) =

J0

(|

u0

|)

and

|

u0

| ∈

N0, by Lemma 2.3, we may assume thatu0 is a positive solution of Eq.

(

E0

)

. Moreover, by Lemma 2.6(i), J0

(

u0

) =

supt0 J0

(

tu0

)

. Thus, there is a uniquetu0

>

0 such thattu0u0

N

(Ω)

and so

1

NSN2

=

inf

uN0

J0

(

u

) =

J0

(

u0

)

J0

(

tu0u0

)

=

J

(

tu0u0

) +

t2

u0

2

Ω

(

1

g

)|

u0

|

2dx

1

NSN2

+

t

2 u0

2

Ω

(

1

g

) |

u0

|

2dx

.

This implies Ω

(

1

g

) |

u0

|

2dx

=

0, which is a contradiction. This completes the proof. 2 Lemma 3.2.Suppose that

{

un

}

is a minimizing sequence for J0inN0. Then

(i) Ω f

|

un

|

qdx

=

o

(

1

)

; (ii) Ω

(

1

g

)|

un

|

2dx

=

o

(

1

)

. Furthermore,

{

un

}

is a

(

PS

)

1

NSN2-sequence for Jin H01

(Ω)

.

Proof. For eachn, there is a uniquetn

>

0 such thattnun

N

(Ω)

, that is tn2

Ω

|∇

un

|

2dx

=

t2n

Ω

|

un

|

2dx

.

Then, by Lemma 2.6(i),

J0

(

un

)

J0

(

tnun

) =

J

(

tnun

)

t

q n

q

Ω

f

|

un

|

qdx

+

t2

n

2

Ω

(

1

g

) |

un

|

2dx

1

NSN2

t

q n

q

Ω

f

|

un

|

qdx

+

t2

n

2

Ω

(

1

g

) |

un

|

2dx

.

Since J0

(

un

) =

1NSN2

+

o

(

1

)

from Lemma 3.1, we have tnq

q

Ω

f

|

un

|

qdx

=

o

(

1

)

and tn2

2

Ω

(

1

g

)|

un

|

2dx

=

o

(

1

).

We will show that there exists c0

>

0 such thattn

>

c0 for alln. Suppose the contrary. Then we may assume tn

0 as n

→ ∞

. Since

(8)

J0

(

un

) =

1

NSN2

+

o

(

1

)

and

J0

(

un

) =

1

N

un

2H1

+

o

(

1

),

by Lemma 2.2,

un

is uniformly bounded and so

tnun

H1

0 or J

(

tnun

)

0 and this contradicts J

(

tnun

)

N1SN2

>

0.

Thus,

Ω

f

|

un

|

qdx

=

o

(

1

)

and

Ω

(

1

g

) |

un

|

2dx

=

o

(

1

),

this implies

Ω

|∇

un

|

2dx

=

Ω

|

un

|

2dx

+

o

(

1

)

and

J

(

un

) =

1

NSN2

+

o

(

1

).

Similar to the method used in [24, Lemma 7], we have

{

un

}

is a

(

PS

)

1

NSN2-sequence for Jin H10

(Ω)

. 2 For the positive numbersd, consider the filtration of the Nehari manifoldN0 as follows:

N0

(

d

) =

u

N0

J0

(

u

)

1 NSN2

+

d

.

Let

Φ :

H10

(Ω)

RN be a barycenter map defined by

Φ(

u

) =

Ωx

|

u

|

2dx

Ω

|

u

|

2dx

.

(3.7)

Such a map has been constructed in Bartsch and Weth [5], Coron [10], Cerami and Passaseo [11] and Clapp and Weth [12], etc. Then we have the following result.

Lemma 3.3.For each positive number

δ <

r0, there exists dδ

>

0such that

Φ(

u

)

Mδ for all u

N0

(

dδ

).

Proof. Suppose the contrary. Then we can assume that there exist a sequence

{

un

} ∈

N0 and

δ

0

<

r0 such that J0

(

un

) =

1

NSN2

+

o

(

1

)

and

Φ(

un

) /

Mδ0 for alln

.

(3.8)

Then, by Lemma 3.2, we have

{

un

}

is a

(

PS

)

1

NSN2-sequence for J inH10

(Ω)

. It follows from Lemma 2.2 that there exist a subsequence

{

un

}

andu0

H10

(Ω)

such thatun

u0weakly inH10

(Ω)

. Since

Ω

is a bounded domain, by the concentration- compactness principle (see Lions [18,19] or Struwe [21, Theorem 3.1]), there exist two sequences

{

xn

} ⊂ Ω

,

{

Rn

} ⊂

R+, x0

Ω

and a positive solutionv0

D1,2

(R

N

)

of critical problem

(

2

.

3

)

with J

(

v0

) =

N1SN2 such thatxn

x0 andRn

→ ∞

asn

→ ∞

and

un

(

x

)

RnN22v0

Rn

(

x

xn

)

D1,2(RN)

0 asn

→ ∞.

(3.9)

Références

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