C OMPOSITIO M ATHEMATICA
N ORIO E JIRI
Minimal deformation of a non-full minimal surface in S
4(1)
Compositio Mathematica, tome 90, n
o2 (1994), p. 183-209
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
NORIO EJIRI
Nagoya University, Department of Mathematics, College of General Education, Chikusa-ku, Nagoya 464, Japan
Received 4 March 1991; accepted in final form 9 December 1992 Dedicated to Professor Tadasi Nagano on his sixtieth birthday
1. Introduction
Let
M
be a compact Riemann surfaceand g
aholomorphic
map ofM
ontoS’(1).
We denoteby 0394g
theLaplacian
for the branched metric inducedby
g.Then we call the number of
eigenfunctions
witheigenvalues
smaller than 2index
of g,
the space ofeigenfunctions
witheigenvalue
2 null spaceof g
and thedimension of the null space
nullity of
g. Note that the index is same as the Morse index with respect to the area functional of acomplete
minimal surface of finite curvature whose(extended)
Gauss mapis g (see [F])
and the elementof the
nullity
spacecorresponds
to a bounded Jacobi field of the minimal surface. Since thepull
back functions of coordinate functions onS’(1)
c R3(which
are called linearfunctions)
areeigenfunctions
witheigenvalue 2,
thenullity
is not less than 3. We call theeigenfunction
ofeigenvalue
2 other than coordinate functions an extraeigenfunction.
In[E-K1]
and[M-R],
analge-
braic
constructing
method of extraeigenfunction
isgiven
as anapplication
ofa characterization of extra
eigenfunctions.
THEOREM.
([E-Kl]
and[M-R]). Let g
be aholomorphic
mapof
a compact Riemannsurface M
ontoS2(1).
Then thenullity of g
4if and only if there
existsa
complete, finitely branched,
minimalsurface
withplanar
ends andfinite
totalcurvature whose
(extended)
Gauss map is g.As another
point
ofview,
we would like to considerwhy
extraeigenfunctions
occur. Note that a
holomorphic
map ofM
ontoS2(1)
is a non-full branched minimal immersion inS3(1).
The indexof g
isequivalent
to the index of theJacobi operator of the minimal surface in
S’(1)
and the null space is taken asthe space of the Jacobi fields. So an extra
eigenfunction corresponds
to anon-Killing
Jacobi field. We can determine all Jacobi fields of the non-full minimal surface inS’(1) [E-K1]
and[M-R].
Thus an extraeigenfunction
isclosely
related to minimal deformations of a non-full minimal surface. Gen-erally,
we do not know the existence of a minimal deformation for agiven
Jacobian field. Note that we have a local minimal deformation for a
given
Jacobi field
[L].
When there exists a minimal deformation such that full minimal surfaces converge to a non-full minimal surface inS3(1),
there existsan extra
eigenfunction. Precisely,
we have thefollowing. Let g
be a holomor-phic
map ofM
ontoS2(1).
LetI/It
be a smooth1-parameter family
ofweakly
conformal full harmonic maps in
Sk(1) (k > 3)
except t = 0 and03C80
= g.Then we consider an operator 0 +
2e(03C8t)
for a fixed Riemannian metriccompatible
with the conformal structure ofM,
where A is theLaplacian
for the metric and
e(03C8t)
is the energy function of03C8t.
Note thatf
satisfies0394f
+2e(tp,)f
= 0 if andonly
iff
satisfiesàpf
+2 f
= 0. Since039403C8t03C8t
+203C8t
=0.
dim{f: Af
+2e(03C8t)f
=0}
k + 1. Sincee(03C8t)
is smooth on t, the spectrumfor 0 +
2e(03C8t)
are continuous on tby [K-S]
and hence thenullity of g k + 1.
It is natural to consider a
problem
whether all extraeigenfunction
comesfrom as above. That
is,
if aholomorphic
map ofM
ontoS’(1)
admits an extraeigenfunction, then, is g
a limit of a one parameterfamily
of full minimal surfaces inSN(1)(N ~ 3)?
In the case of the genus ofM
=0,
we should consider N ~4,
because there does not exist a full minimal surface of genus 0 inS3(1).
In this paper, we
give
apositive
answer, that if the genus ofM
=0,
then theabove observation is
generically
yes.First
of all,
wegive
a relation between minimal surfaces in R3 and the twistortheory.
Fix a horizontal line pl in the 3-dimensionalcomplex projective
space p3of holomorphic
sectional curvatures 1. Let g be aholomorphic
mapof a simply
connected domain D in C into P 1 without
ramification
locus. 1hen a minimalsurface
with the Gauss map g induces aninfinitesimal
horizontaldeformations of g in
p3 and the converse is also true. Note that this is a localcorrespondence.
As a
global result,
we get thefollowing.
THEOREM A.
Let g
be aholomorphic
mapof M
ontoP1.
Then g admits anon-linear
infinitesimal
horizontal(holomorphic) deformation
in p3if
andonly if
there exist a
complete, finitely
branched minimalsurface of planar
endsand finite
total curvature whose
(extended)
Gauss map is g and it’sconjugate
minimalsurface
exists.Using
Theorem A and the results on the moduli space of harmonic maps of S2 intoS4(1) by
Loo[Loo],
we obtain a formula to calculate thenullity
of aholomorphic
map of S2 ontoS2(1).
LetG(2, d
+1)
be the Grassmannian ofplanes
inCd+1.
Let[P 039B Q]
denote theplane spanned by
two vectorsP = (ad, ..., a0)
andQ = (bd, ...,b0).
Then we get apoint [a2a -
2, ...,03B10]
ofP2d-2 such that
Then
’Pd
is a branchedcovering
map ofG(2, d
+1)
onto p2d-2 . Letf
be aholomorphic
map of P 1 onto P 1 ofdegree
d. Thenf
isgiven by
a rationalfunction of the form
Q(z)/P(z),
whereand
such that ai,
biEC.
Note thatmax{degree
ofP, degree
ofQ} = d
andthe resultant of
P(z)
andQ(z)
is not zero. LetP, Q
denote vectors(ad, ad-1, ..., a1, a0), (bd, bd-1, ..., b1, b0) ~ Cd+1, respectively.
Then we obtainthe
following.
THEOREM B. Let
P(z)/Q(z)
be aholomorphic
mapof
S2 ontoS2(1) of degree
d
defined by polynomials P(z)
andQ(z).
ThenLet
M,,
be the space ofmeromorphic
functions ofdegree
d onP’,
which isP( Cd+
1 XCd+1 - R) ~ P2d+2,
where R is the irreducible resultant divisor.A ~ G L(2, C) acts on Cd+
1 x Cd+1:Thus we obtain an action of
PSL(2, C)
onP(Cd+1
x Cd+1 -A),
where 0394 ={(P, Q):
P 039BQ
=01.
The orbit space isG(2, d
+1).
SoMd
is the total space ofa
PSL(2, C)-bundle
onG(2, d
+1)-the image
of Bl. Note that the action offor
P(z)/Q(z)
isgiven by
Theorem B states that
holomorphic
maps ofS2
ontoS2(1)
ofdegree d
with anextra
eigenfunction
is the total space of aPSL(2, C)-principal
bundle on 9l[the
ramification locus of
03A8d-the resultant].
Note that 91 is ahypersurface
withsingularities (see,
forexample, [Nam])
inG(2,
d +1).
Furthermore Theorem B is apositive
answer for aproblem posed
in[M-R]
and[E-K2].
THEOREM C.
Let g
be aholomorphic
mapof
S2 ontoS2(1) of degree
d.Then, if g is
an elementof PSL(2, C)-principal
bundle on theregular
partof 9î,
then g hasexactly
two extraeigenfunctions
and admitsi/rt of
S2 intoS4(1)
such that1/10
= g and03C8t (t
~0) gives
afull
branched minimalsurface of
genus 0 inS4(1).
Furthermore a
holomor-phic
map with extraeigenfunctions
is a limitof
theseholomorphic
maps.2. Infinitesimal horizontal deformation
Let p3 be the 3-dimensioàxàl
complex projective
space with constant holo-morphic
sectional curvature 1. Then p3 is the twistor space ofS4(1).
Infact,
we consider p3 = the reductivehomogeneous
spaceSO(5)/1
xU(2)
andS4(1)
=SO(5)11
xSO(4). Let p
be theprojection
ofS(5)1
xU(2)
onSO(5)/
1 x
SO(4)
definedby p(a(1
xU(2))= a(1
xSO(4)). Then p
is a Riemanniansubmersion,
which is called the Penrose map. Let H and V denote theprojections
of the tangent space .of p3 onto thesubspaces
of horizontal and vertical vectors,respectively.
For apoint a(1
xU(2))
inP3,
the tangent space is identified with the space 03C4, which isgiven by
The metric and the
complex
structure J aregiven by
Horizontal vectors are
given by
vertical vectors are
given by
O’Neill
[O’N]
defined two tensor fields J and A for a Riemannian submer- sion. For the Penrose map p, since vertical fibres aretotally geodesic,
J = 0holds. Let X and Y be vectors at q =
p(a(1
xU(2)) and
andY
arehorizontal lifts at
a(1
xU (2)), respectively.
Thenwhere a =
(q,
el, e2, e3,e4),
and R is the curvature tensor ofS4(1).
LetS2(1)
be a fixed
totally geodesic
surface inS4(1).
Then we have a horizontal line Pl in p3 such thatp(P’)
=S2(1).
We have a horizontal line Pl in p3 such thatp(pl)
=S2(1).
Then we obtain three vector bundles1/, X,
J on pl such thatV is
spanned by
vertical vectors, N isspanned by horizontal,
normal vectors, :!7 isspanned by horizontal, tengential
vectors. It is easy to see that these areJ-invariant.
1/c, .;VC,
JC arecomplexified
vector bundles of1/, N,
9-.Furthermore let V1,0 and V0,1 are line subbundles
spanned by
type(1, 0)-
vectors and type
(0, l)-vectors, respectively. Similarly
we can define line bundles%1,°, N0,1 J1,0 J0,1.
Since the normal bundle ofS2(1)
inS4(1)
isa trivial
bundle,
there exist two orthonormal vector fields for the normal bundle. Thus we obtain a vector fieldE2
of N0,1with
squarelength
2globally
defined on
P1, i.e.,
Let V and -W
be the covariant differentiation and the curvature tensor ofP3, respectively. Using
the formula for A[O’N],
we obtain thefollowing.
LEMMA 2.1
(see,
forexample, [El]
and[E-S]).
Let
E1 be a
tangentvector field locally defined of J0,1
such thatThen
V EtE2
is a vertical vectorfield of
type(0, 1)
and squarelength 2,
which is denotedby E3.
Furthermorehold. Let to be the connection
form for
Vgiven by
and
p21dzl2
be themetric for
acomplex
coordinate z = x +iy of
Pl. We setThen
Proof.
It isenough
to prove the last statement.Let
M
be a compact Riemann surfaceand g
aholomorphic
map ofM
ontoS2(1).
Then we may considerthat g
is a map ofM
onto P’(into P’).
LetF(g*(N
+V).
For V EF(g*(N
+1/)),
V isgiven by
where
f
is a function onM and 03BE ~ 0393 g*(V1,0)).
We consider the conditionwhere V is an infinitesimal horizontal deformation of g. Let
0,
be a variationof g
such that the variational vector field at t = 0 is V Then V is aninfinitesimal horizontal deformation
of g
if andonly if,
for any vertical fieldU,
we have
where X is a tangent vector field. Let z = x +
iy
be acomplex
coordinate ofM.
ThenSince VvU
isvertical, ~~*(~/~z), VvU
= 0. We getwhich
implies
that V is a horizontal deformationof g
if andonly
ifThus we obtain the
following.
LEM MA 2.2. V =
f E2
+f E2 + 03BE + 03BE
is aninfinitesimal
horizontaldeformation
ç
is aholomorphic
sectionof g*(V 1,0),
Proof.
Since the ramification locusof g are
isolatedpoints,
it isenough
toprove
(2.1)
and(2.2)
on thepoints
except ramification locus.Using
acomplex
coordinate z, we put
and
E1E2
=E3.
Then there exists a function h suchthat 03BE
=hE3 . By
Lemma2.1, we get
So we get
So the first
equation, together
withVE,E2
=E3, implies (2.2).
The secondequation
saysthat 03BE ( = hE 3)
isholomorphic
ing*(V1,0). Q.E.D.
Next we consider the condition that V is an infinitesimal
holomorphic
deformation of
g. V
isholomorphic
if andonly
if the(1, 0)-component
V1,0 ofV satisfies
Thus V is infinitesimal
homomorphic
if andonly if 03BE
isholomorphic
ing*(V1,0)
andThis
completes
thefollowing.
LEMMA 2.3. V =
f E2
+f E2 + 03BE + 03BE
is aninfinitesimal holomorphic deforma-
tion
if
andonly if
ç
is aholomorphic
sectionof V1,0, (2.3)
We prove that an infinitesimal horizontal deformation is also an infinitesimal
holomorphic
deformation.LEMMA 2.4. Let V be an
infinitesimal
horizontaldeformation of
g. Then V isan
infinitesimal holomorphic deformation.
Proof. Since 03BE
isholomorphic,
zeropoints of 03BE
is isolated. So it isenough
togive
aproof
forpoints
except ramification locusof g
and zeropoints
of03BE.
LetV =
f E2
+f E2 + 03BE + Z
be an infinitesimal horizontal deformation.Then 03BE
isholomorphic
ing*(V1,0)
andWe get a covariant differentiation of both sides
by ~/~z.
So we obtain
First of
all,
we calculate the second part of theright
hand side.Next we calculate the third part.
On the other
hand,
since p3 hasholomorphic
sectional curvature1,
we obtainFurthermore we calculate the first part.
Thus we obtain
Since
Va/a1.E2 is
non-zero, we get aproof. Q.E.D.
Now we consider the condition for
f
such that V =f E2
+fE2 + 03BE
+03BE ~ 0393(g*(N
+Y))
is an infinitesimal horizontal deformation. Note that V must be an infinitesimalholomorphic
deformation and hence satisfies(2.4). Thus 03BE
is determined
by f
asfor a
point
where~~/~zE2, E3~
does not vanish. We denote itby 03BEf.
Sincep2IdZl2
is the metric inducedby
g. ThenSet
and choose
E3
definedby E1E2
=E3.
Thus we obtain a localexpression
of1/ bY
Thus the
singularity of 03BEf
holdsonly
at zerosof s,
thatis,
apoint
of theramification locus of g.
LEMMA 2.5.
f E2
+f E2 + 03BEf + 03BEf satisfies (2.2) if and only if
Proof.
Sinceand
by
Lemma2.1,
we obtainÇf
forf
which satisfies(2.7)
is notgenerally holomorphic
inV1,0.
We obtainanother condition
that Çf
isholomorphic.
LEMMA
2.6. 03BEf
is aholomorphic
sectionof N1,0 if
andonly if
Proof.
Remark that
(2.8) implies
Hessf(a/bz, ôlôz)
= 0. Note that V =f E2
+f E2 + 03BEf + 03BEf
is an infinitesimalholomorphic
deformation if andonly
iff
satisfies(2.8). Furthermore,
the condition that V becomes an infinitesimal horizontal deformationrequires (2.7)
instead of(2.8).
So we need toinvestigate
acomplex
valued function on
M
which satisfiesFirst of
all,
westudy
local solutions of(2.9).
Let U be asimply
connectedopen set of
R2( = C)
and z acomplex
coordinate on U. Let xi 1 be a branched minimal immersion of U into R3. Then x1 is given by
where 03A6 =
(ojoz)X
1 andcl E R3.
Since U issimply connected,
there exists aconjugate
branched minimal surface whose branchedimmersion
isgiven by
Let g
be the Gauss map of U intoS2(1).
Then we can define a functionf by
~~1 + i~2, g~.
Sincewe obtain
So
and
and hence
Thus
f
satisfies(2.9). Conversely
let g be a non-constantholomorphic
map of U intoS2(1)
without branchedpoints.
Letf
=fi
+if2
be a function on Usatisfying (2.9).
Thenfi
satisfies(2.7). Generally
we have thefollowing.
LEMMA 2.7
(see,
forexample, [E3]).
Let h be areal-valued function
on U whichsatisfies (2.7)
andgrad
h thegradient
vectorfields
on Ufor
the metric inducedby
g. Weidentify grad
h withg*(grad h)
and may consider thatgrad
h is a vectorfield
in R3. Then the map Xhof
U into R3by
x,, =
hg
+grad
his a branched minimal immersion
of
U into R3 or a constant map. Xh is a constant mapif
andonly if
hsatisfies (2.8).
When Xf1 is a constant,
fi
is a linear function and satisfies(2.8).
Sincef
satisfies
(2.9), f2
also satisfies(2.9)
and hencef2
is a linear function. Thusf
isa linear function. Assumed that Xf1 is not a constant.
Then Xf
1gives
abranched minimal surface. Since U is
simply connected,
we obtain aconjugate
minimal surface X2 defined on U. So
~~f1
+i~2, g~
satisfies(2.9). 1
=we know
f
=~Xf1
+’X2, g~.
Next we
study
theglobal
solutions of(2.9).
For aglobal
solution of(2.7),
wehave the
following.
THEOREM 2.3
([E-Kl], [M-R]). Let g be a holomorphic
mapof M
ontoS2(1)
and h a solution
of (2.7).
Without lossof generality,
we may consider that h is not a linearfunction.
Then Xh =hg
+grad
hgives
acomplete, finitely
branchedminimal
surface of planar
ends andfinite
total curvature whose map isdefined
onM - {finite points)
and(extended)
Gauss map is g([E-Kl], [M-R]). If M
hasthe genus
0,
then Xh has aconjugate
minimalsurface.
Generally,
there is noconjugate
minimal surface of the above minimal surface for non-zero genus. But if there exists a solution of(2.9),
we have tworeal solutions of
(2.7)
which are the real part andimaginary
part. These solutionsgive
twocomplete, finitely
branched minimal surface ofplanar
endswhose extended Gauss map is g. One of them is a
conjugate
minimal surface of the otherby (2.8). Conversely
we obtain thefollowing.
PROPOSITION 2.2. Let
f be a function satisfying (2.9)
onM.
Thenf
isconstructed
by
acomplete, finitely
branched minimalsurface of planar
ends andits
conjugate
minimalsurface.
Let
f
be a functionsatisfying (2.9).
Now weinvestigate
the behaviourof 03B6f
at a branch
point q
of g. Let z be acomplex
coordinate such thatz(q) =
0.Then there exists n such that
ôg/ôz
=z"n(z),
wheren(0) ~
0. We setE1 = n(z)/|n(z)|
andE3
=VEtE2. Then 03BEf is given by
By Proposition 2.2,
we have acomplete, finitely
branched minimalsurface x
1of
planar
ends and finite total curvature and itsconjugate
minimal surface X2(whose
extended Gauss maps areg)
such thatf
=~~1
+iX2’ g).
Thus we haveFor
(~/~z)~1 = 03A6,
we obtainLet
be the Laurent
expansion
of 03A6 at0,
where a-k, ... EC3.
We denoteby 1(z)
zk03A6.Then 1 is
holomorphic
and~g, l~ = ~g, l~
=~l, l~
= 0 holds. Wehave pl
andp, such that
Taking
the differentiation of both sidesby 8/8z,
we note thatFor a
planar end,
we have thefollowing.
LEMMA 2.8
([E-Kl]
and[M-R]).
Since
g(O), 1(0)
and1(0)
is a basis ofC3,
we obtainIt is easy to show the
following.
where,
# means non-zerofunctions.
Since
we obtain
Similarly
we obtainUsing
theseestimates,
we have|03BEf|
a constant andhence 03BEf
isholomorphic
at p.
LEMMA 2.10.
Let f be a function satisfying (2.9)
on M. Thenis an
infinitesimal
horizontal(holomorphic) deformation.
By
Theorem 2.3 and Lemma2.10,
we obtain Theorem A.REMARK. We can see that our argument is
closely
related to thetheory
ofholomorphic
null maps[Br].
Infact,
we cangive
a relation between meromor-phic
sections ofV1,0
andholomorphic
null maps ofM - (isolated points}
intoC3.
Precise result in aforthcoming
paper.3. Infinitesimal contact deformation
In this
section,
we use Loo’ notations in[Loo].
Recall the
diagram:
Let N and S denote the north and south
poles
ofS4(1), respectively.
Considerthe two lines
L1 = p-1 (N)
andL2
=p-1(S).
Then we getL1
={[0, 0,
z2,z3]| [z2, z3] ~ P1}
andL2 = {[z0,
z1,0, 0] |[z0, z1] ~ P1}.
Let X be ablow up of p3
along LI
andL2.
Then X isgiven by
X :={([z0,
zi, z2,Z3]1 [y0, y1], [y2, y3]) | z0y1
= ZLYO, Z2Y3 =z3y2}.
Let Y be theprojective
cotangent bundlePT*(P1
1 xP’ )
on Pl x P 1.Let 03C8 : X ~
Y be definedby
Let (T
1 and (J 2be P-I(L 1) and P-l(L2), respectively.
Then we observe that03C8(03C31)
={([y0, y1], [Y2’ Y3]’ [0, 1]): [Yo, y1] ~ P1
and[y2, y3] ~ P1}
andt/1((J 2) = {([y0, Yil, [y2, y3], [1, 0]): [y0, y1] ~ P1
and[y2, y3] ~ P1}.
Let[q]
bea
point
of Y Then we have a tangent linel[q]
ofT(P
1 xP 1 ) such q
annihilate1[,,,
and theplane K[q]
such that X ET[q]
Y satisfiesn*(X)
El[q].
Hence we obtaina
plane
fieldfon 1’:
which is called a contactplane
field. For aholomorphic
map F : 03A3 ~ P1 x
P1,
we have a canonical Gauss liftF
to Y definedby
Note that
*(~/~z) c-
Thatis, F
is a contact curve. We know the relationbetween the horizontal
plane
field on p3 and the contactplane
field on YLet 1 be a horizontal curve in p3 which does not intersect
L1
andL2.
ThenE is also a horizontal curve in X and hence
03C8(03A3)
is a contact curve in YConversely,
if a contact curve does notintersect 03C8(03C31) and 03C8(03C3|),
then thereexists a horizontal
curve Î
such thatÎ
does not intersectL1 and L2, 03C8()
is afinite
covering
of the contact curve.Furthermore,
if V is an infinitesimal horizontal(holomorphic)
deformation ofE,
then Ygives
an infinitesimal contact(holomorphic)
deformation Uof 03C8(03A3).
Let
(s,
t,w)
be acomplex
coordinate of Ycorresponding
s =YIIYOI
t =Y3lY2
and ds + w dt. Then we consider a line s
~ (s,
s,-1) as 03C8(P1).
Thus we mayidentify
aholomorphic
map of P’ onto P’ in p3 with aholomorphic
map of P1onto 03C8(P1)
in Y Letg(z)
beQ(z)/P (z),
whereP(z)
andQ(z)
arepolynomials
such that
max(deg P(z), deg Q(z» = deg
g. Since U is an infinitesimal holo-morphic
deformationof g in Y,
we have threemeromorphic
functionsv’(z), v2(z)
andV3(Z)
on P such thatv
1 and V2 may be considered as infinitesimalholomorphic
deformations of aholomorphic
map gof P
ontoP 1.
It is easy to find two one parameter families ofholomorphic maps h’ and h’
of Ponto
Psuch
thatwhere we consider that
h’
andhÎ
are two one parameter families of meromor-phic
functions.LEMMA 3.2. U is an
infinitesimal
contactdeformation if
andonly if
Proof.
Let0,
be a smooth deformationof g
in Y such that the variation vector field at t = 0 is U.Then,
since U is an infinitesimal contactdeformation,
we getwhich
implies
aproof.
We set
where ad, ... ,
bo
are smooth functions for t.By
the definitionof vl
and v2l we getwhere
Therefore
Set
where
Tj
is defined in the introduction. Lety and 00FF
be two curves inC2d-
1given by
Then we get
03B3(t)
=[03B3(t)]
and03B3(t) = [y(t)].
LEMMA 3.3.
Proof. Using (3.1),
we get thefollowing:
On the other
hand,
sincewe get
This
completes
aproof. Q.E.D.
Without loss
of generality,
we may assume thatQ
andôqlôz
has no commondivisor and
degree
ofQ2(~g/~z)
is 2d - 2.Using
w = -1for 03C8(P1),
we obtainLEMMA 3.4.
where a and
pare polynomials.
Furthermore zerosof
oc are contained in zerosof Q.
Proof.
If zo is not zeropoint
ofQ(z),
thenQt(zo)
is non-zero and henceP(zo)/Q (zo)
isfinite,
whichimplies v3(zo)
isfinite,
because w-coordinate of03C8(P1)
in Y is-1,
and hence zo is not apoint
of zeros of03B1(z). Q.E.D.
Since the left hand side of
(3.2)
isdegree
2d -2,
Since
Q2(ôg/ôz)
is apolynomial P’Q - PQ’
ofdegree
2d - 2 which does nothave common divisor with
Q,
we obtain03B2/03B1
+2(Q’ - Q’/Q)
is constantby
Lemma 3.5.
Using
Lemma3.4,
we get03B3*(0) = *(0).
Thatis,
Now we consider a linear map Q of the
space 0
of infinitesimal contactdeformations into ker
’II d*
at[P
039BQ]
definedby
where
X
1 is the tangent vector of[P,
AQt]
andX 2
is the tangent vector of[Pt
AQt].
Wealready proved X1 - X2
E ker’Pd..
LEMMA 3.5. Q is onto.
Proof. Let 03BE
E ker’Pd-.
Then there is a curvePt(z)/Qt(z)
suchthat 03BE
is the tangent vector of[Pt
AQt]
at t = 0. We define asection 1
of the bundleg*(TPT*(P1
xP1))
Of course, since we use the coordinate
(s,
t,z) of PT*(pl
1 xP 1 ),
forP/Q
= oo,we should prove
that 11
is well-defined. And it is easy.Using ç E ker ’Il d*,
we obtainwhich
implies that q
is an infinitesimal contact deformation and03A9(~)
=03BE.
Q.E.D.
Next we
investigate
the kernel(ker Q)
of Q.Let
Pt/Qt
be a one parameterfamily
ofholomorphic
maps suchthat g
=POIQO.
Then p ·Pt/Qt
is a map of P1 ontoS’(1)
inS4(1),
whichgives
a minimaldeformation of p · g and hence horizontal deformation in p3 and contact
deformation in Y Its infinitesimal contact deformation is called an infinitesimal contact deformation of type 1.
Let It
be a one parametersubgroup
ofisometries
of S4(1).
ThenIt. p. g
is a minimal deformationof p · g.
SinceIt
is aone parameter
subgroup
of isometries of p3 which preservesJe, It·g
is ahorizontal deformation
of g
and hencegives
a contact deformationof g
in YWe call the infinitesimal contact deformation an infinitesimal contact deforma- tion of type 2.
LEMMA 3.6.
Infinitesimal
contactdeformations of
type 1 and type 2 are in ker 03A9.Conversely,
let W be in Ker Q. Then W is the sumof infinitesimal
contactdeformations of
type 1 and type 2.Proof.
LetPt/6t
be a one parameterfamily
ofholomorphic
maps of P’ ontoP
such
thatPo/Qo
=P/03A9.
ThenPt/Qt gives
an horizontal deformationof g
inP3,
which fix P 1 as theimage,
and hence a contact deformationof g
in Y. It isgiven by
the canonical Gauss lifts of mapsIts infinitesimal contact deformation is
which is contained in Ker Q.
Conversely,
for an infinitesimal contact deforma- tion of this formv(ô/ôs)
+v(ô/ôt),
we have a one parameterfamily
ofholomorphic
mapsP,lQt
of P1 onto P’ such thatNext let
I,
be a one parameterfamily
of isometries ofS4(1).
ThenI,
is also aone parameter
family
of isometries of p3 which preserves . ThusIt · g
is ahorizontal deformation
of g
andgives
a contact deformationof g
in Y It is easy to see ([Loo]) that it iswhere
At, Bt
inGL(2, C).
SinceAt. P/Q, Bt · P/Q give
apoint [P 039B Q]
inG(2, d
+1),
the infinitesimal contact deformation of this contact deformation is in Ker Q. These deformationsalways give
non-full branched surface in S4(1).
Conversely,
let V be in Ker Q. We setThen we have one parameter families
Pt/QI’ Pt/Qt
whose variation vector fields03BD1,
03BD2. Since V ~ Ker Qholds,
we getSo there exists one parameter
subgroup At
ofGL(2, C)
such thatWe define a one parameter
family of holomorphic
maps of P into P 1 x Pby
The canonical Gauss lift
gives
a one parameterfamily
of contact curves, whose infinitesimal contact deformation is Vby
Lemma 3.2. So V is a sum of infinitesimal contact deformation of type 1 and type 2.Q.E.D.
Let
g(z) = P(z)/Q (z)
be aholomorphic
map of pl onto P1.Then, identifying
the space of infinitesimal horizontal deformations
of g
in p3 with éfor g in Y,
define a linear map of -9 into Ker
03C8d*.
It is clear that the kernal is inducedby
one parameter isometries of
S4(1)
which fixS’(1).
So dim D - 3 =dimR Ker Vid- .
Since -9 is identified with the null spaceof g by
TheoremA,
we get aproof
of Theorem B.Generally,
let 0 be a branchedcovering
map of an m-dimensionalcomplex
manifold M into an m-dimensional
complex
manifold N. Then the ramification locus of 0 is acomplex hypersurface 91
withsingularities.
For aregular point
p of
9î,
there exists apositive integer
d and coordinateneighborhoods
(z1, ..., zm:U1)
at p and(wl, ...,
wm:U2)
at0(p)
such thatUsing
this fact(see,
forexample, [Nam]),
we notethat, for g
E theregular
part of9l,
the dimension of the null spaceof g
is 5.Furthermore,
there exists two smooth curvesrl(s), ’2(S) in G(2, d
+1)
such thatri(0)
=r2(o)
= g,rI (s) =1= r2(s)
for S ~ 0 and03A8d(r1(s))
=’II d(r 2(S)).
So we get two one parameter families ofholomorphic
mapsP,(z)IQ,(z)
andP,(z)lo,(z)
of Pl onto Plsuch that
[Pt
AQt] ~ [Pl
1Bt]
and03C8d [Pl
039BQt] = 1/1 d [Pl
At]
for t =1= 0. Then the canonical Gauss lift of(Pt(z)/Qt(z), t(z)/t(z)) gives
a contact deformation of g in Y and hence horizontal deformation of g in p3. Since these maps are full for t :00,
we get Theorem C.COROLLARY 3.1. In the space
of holomorphic
mapsof
S2 ontoS2(1) of degree d,
wherenullity
is not less than5, generically,
thenullity
is 5.4. A
problem
We
give
aproblem
on the index for aholomorphic
map of S2 ontoS2(1).
(4.1)
PROBLEM. Let g be aholomorphic
mapof S2
ontôS2(1) of degree
d.Then, If
thenullity of
g = 3 +2v,
thenis the index = 2d - 1 - v?
If
[E2],
westudy equivariant
minimal branched immersion of S2 intoS2m(l)
with type
(m1, ..., mm).
Inparticular,
form = 2,
we obtain some limits ofequivariant
minimal branched immersion of S2 intoS4(1)
with type(m
11m2)
asin
[E-K2].
Thatis,
the limitholomorphic
map isgiven by
where a E C*.
In
[Nay],
if m =1,
then the index =2(m2
+1)
- 2 and thenullity
= 5 hold.By [E-K2],
this one parameterfamily
of branched minimal surfaces preserves themultiplicity
ofeigenvalue
2 andequivariant
branched minimal immersions have themultiplicity
5 foreigenvalue
2.By
thecontinuity
of spectrum,equivariant
branched minimal immersion of type(1, m2)
has2(m2
+1) -
2eigenfunctions
ofeigenvalues
smaller than 2. Since m = 1 means that the branched minimal immersion has no branchedpoint (see,
forexample, [E2]),
we get the
following.
The number
of eigenfunctions of eigenvalues
smaller than 2for
anequivariant
minimal immersionof
S2 intoS4(1) of
area 4nd isequal
to 2d - 2.By
TheoremB,
we see thatg(z)
as in(4.2)
has thenullity
5. So the index of g = the number ofeigenfunctions
witheigenvalues
smaller than 2 forequivariant
branched minimal immersion of S2 intoS4(1)
of type(m1, m2). If
the
problem (4.1)
is true, then we can obtain that the number ofeigenfunctions
with
eigenvalues
smaller than 2 forequivariant
minimal branched surfaces of genus o with area 403C0d inS4(1)
is 2d - 2. Thus we may consider that theproblem (4.1)
is useful to calculate such number for minimal branched surfaces of genus o inS2,(1).
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