A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
L. A. C AFFARELLI N. M. R IVIÈRE
Smoothness and analyticity of free boundaries in variational inequalities
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 3, n
o2 (1976), p. 289-310
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http://www.numdam.org/
Analyticity
in Variational Inequalities.
L. A. CAFFARELLI
(*) (**) -
N. M.RIVIÈRE (*) (***)
dedicated to Hans
Lewy
The
study
of freeboundary problems
consistsbasically
of twoparts;
the
study
of thetopological
structure and thestudy
of the differentiable structure.The
techniques
for thestudy
of the differentiable structure were laid downby
H.Lewy
in a series of papers[8], [9], [10]
andapplied
laterby
H.
Lewy
and G.Stampacchia [11]
in the linear case andby
D. Kinderlehrer[6]
in the minimal surface case. In
brief,
suchtechniques
were based on theanalytic
continuation of a conformalmapping, requiring
some apriori topological knowledge
of the freeboundary
andanalyticity
of the data.To obtain the necessary
topological
structure conditions ofgeometric type,
such as
convexity
of theboundary
andconcavity
of theobstacle,
wereimposed.
In this paper we localize the
analysis
of the freeboundary
and removethe
artifically imposed, geometric
conditions. Moreover a more flexible useof
quasi-conformal
extensions of conformalmappings yields regularity
ofthe free
boundary according
to the smoothness of the data. The use ofquasi-conformal
extensions wasalready
consideredby
D. Kinderlehrer[7],
where he obtains the character of the free
boundary
whenassuming
a
priori topological
behaviour.The paper is
organized
as follows. In the firstparagraph
we prove a series of lemmas which allows the localstudy
of the freeboundary.
(*)
School of Mathematics,University
of Minnesota.(**)
The author wassupported by Consejo
deInvestigaciones
Cientificas yT6cnicas, Argentina.
(***)
The author waspartially supported by
NSFgiant
G.P. 43212.Pervenuto alla Redazione il 21
Maggio
1975 e in forma definitiva il 25 Settem- bre 1975.19 - delia Scuola Norm. Sup. di Pida
In the second
paragraph
westudy specifically
the two dimensional freeboundary problem arising
from the variationalinequality
that solves theminimal energy
problem (Laplace’s equation)
above agiven
obstacle.In the third
paragraph
westudy
the nonlinear case as considered in[1],
and we extend the
regularity
results of the linear case; inparticular
we obtainthe
regularity
of the freeboundary
of a minimal surface above agiven
obstacle.
In the fourth
paragraph
westudy
the nowhere densepart
of the set ofcoincidence considered in the
previous paragraphs.
Finally,
in the lastparagraph
wegive
a briefapplication
of thetechniques
of the first
paragraph
to the Stefanproblem
and a number ofexamples
areconstructed to exhibit the
topological
behavior of the freeboundary
of theproblems
considered inparagraphs
2 and 3.1. -
Density properties
of the freeboundary.
In this
paragraph
we show someelementary properties
of a freeboundary.
Although
the lemmas of this section are valid forquasilinear elliptic operators
of second
order,
as we will see in Section3,
in this firstparagraph
we willlimit ourselves to the
Laplace equation.
Lemma 1.1 shows a
density property
of the set of non-coincidence at itsboundary points,
Lemma 1.2 estimates the area of a sequence of surfacesapproximating
the freeboundary,
and Lemma 1.3 shows that the solu- tion u can be extended in a C2 way across the non-denseparts
of the coin- cidence set.Finally,
Lemma 1.4 shows how a local construction of amapping
considered
by Lewy
andStampacchia [9],
preserves, in some weakform,
the
property
ofmapping
the non-coincidence set into the coincidence set.LEMMA. 1.1. Let D be a
bounded, connected,
open set of Rn and u a real valued function defined in17 satisfying:
Consider an open
set, 0,
and assume thatu(x)
=0, ’ou(x)
= 0 whenx E
8Q
r) 0. Then for each x E 0 n 8Q thereexists y
=y(x)
E 30n f?
suchthat
PROOF. For x c- 0 r) 3D set
qz(z)
=Clearly
n it is
superharmonic
in .~ and =0,
= 0.Assume first that there exists a
ball, B,
B c S2 and such that x E aB(such
x’s are dense in aS~ since Q isopen); then,
in virtue of the strict maximumprinciple,
must benegative
at somepoint
y, y Et’) 0).
On the other hand observe that > 0 when z E 0 n aS2. Hence 0 for some y E a 0 n
Q
and the lemma follows for such x.When x is not in the
boundary
of a ball contained inQ,
there exists asequence,
{x.1,
for which theproperty
holds and Xm -+ x as m - 00. Since convergesuniformly
inSZ
to can not bestrictly positive
inaO
() lJ
and the lemma followsLEMMA 1.2. Under the
assumptions of
Lemma1.1, if further
u E01.1(,Q);
then:
(i )
Given and aball, B(x, e), B(x, ~O ) c 0 ;
there exists 6(b fixed)
and y =y(x)
EaB(x, e)
such thatB(y, be)
() 0 c Q.(ii) I f Q
is a cubeof
side I contained in0,
there exist constants M and a;.M an
integer,
0 a1;
such thatif
wedecompose Q
into Mkncubes, of
side lM-k where k is anarbitrary positive integer,
andform
then has at most cubes. In
particular
the areaof verifies
and
PROOF. To prove
(i)
weapply
Lemma 1.1 toB(x, e)
instead of 0.Hence,
there exists such that
therefore,
since Vu is
Lipchitz
continuous inS~,
there exists6, depending
on theLipchitz
constant
only,
such thatu(z)
andVu(z)
can not vanishsimultaneously
whenz E B(y,
that isB(y, be)
c Q.Given a
cube, Q,
wepartition
it into Mnsubcubes,
of side?/if;
to prove
part (ii)
it suffices to show that for Mlarge,
butindependent
ofQ,
at least one of the cubes of the
partition
does not intersect The resultwould then follow
by
induction withrespect
to k.Let
Qo
be one of the central cubes of thepartition
and assume thatIn virtue of
(i)
there existsy(xo)
EoB(xl, l/2)
such thatB(y, 8,
If M is chosenlarge enough,
there must existQi
cc B(y, 6,
and the lemma follows.LEMMA 1.3. Under the
hypothesis of
.Lemma 1.2 assumefurther
that d u = g,with g
Holder continuous inS2 r’10.
Then du= g in
r) 0.PROOF. It suffices to show
that, given
zo E r1e(92),
4u = g in thesense of distributions in a
neighborhood
of xo.Let Q
be a small cube centeredat x, Q
c 0and
a0’ (Rm)
function withsupport
contained inQ. Following
the notation of Lemma 1.2In virtue of the fact that
m( I7k) --~ 0
ask -~ oo,
1(II)
tends to zero.On the other hand
Since,
for andit follows that P tends to zero as k tends to
infinity.
Also
I- I-
and the lemma follows.
Finally,
in this firstparagraph
we want tostudy
a « reflexion » function that willprovide
us with the localtopological
behavior needed to obtain the smoothness of theboundary.
Assume thehypothesis
of Lemma1.3,
and let the coordinates be fixed at a
point
xo ofSuppose
alsothat g
has aLipschitz extension g,
to aneighborhood
of xo .Under such
assumptions, using
standardarguments,
we may constructa
function,
y, solution of theequation
in aneighborhood
of xo, and such that11 and
In a small
neighborhood, Uo,
of xo,Vy
is adiffeomorphism
of the formHence,
there exists a well defined function~(x), ~ verifying
when
Clearly,
We want to prove thefollowing
LEMMA 1.4.
If
x EZ7o
r1D,
and there exists a ballB,
B cC(Q),
x EaB,
then there exists a sequence
~xn~,
Xn ES~,
Xn --~ x, such thatE(xn)
Ee(Q).
PROOF. Assume that the coordinate axes have been chosen so that in a
small
neighborhood
of x,and l a linear function.
We may assume that
Uo
is so small that ai 0 for every i.Let us consider the
ellipsoid
We can choose
s( )
~ 0with e
-0,
suchthat, by
theargument
of Lemma1.1,
the function
h(y)
=u(y) + (1- 8(e)) ICXi(yi- xi)2
is subharmonic in and hence has apositive
maximum at apoint
z E ~O eo.The
gradient
of hverifies, by
the strict maximumprinciple,
with
~, > 0 (Vh(z)
is normal to atz).
We recall that
by
theLipschitz
character ofVu,
there is a ballB* (z,
S~.Since B* cannot intersect the ball
lying
in andtangent to x,
the
point z
mustlay
in a coneC,
with vertex at x and whose axis is theprolongation
of the radius ofBl passing through x (C = ~y : (y - x, v) ~
where v is the exterior normal to
Bl
atx).
On the other
hand, by
definitionBy
the aboveformula,
weget
That is
To
complete
theproof
we will show that A remainslarger
than a fixednumber
~,o
> 0 - 0. The conclusion will then follow since z lies in the cone C mentioned above.LEMMA 1.5. With the
hypothesis of
thepreceeding lemma,
let A bedefined
as
before (See (*)).
A remains
larger
than afixed positive
constant~,o
as e tends to zero.PROOF. The
ellipsoid E(e)
contains a ballBe’ tangent
from inside toE(e)
at the
point z,
withe’ = Ce
andsatisfying
thatIn order to prove our lemma we make the
following
claimwith C
positive independent
of e.We
postpone
theproof
of the claim andproceed
with the lemma.Observe that the
Lipschitz
character of the derivatives of uimply
thath(w) - h(z)
is less than -lOe2,
as a function of w, over a subset ofproportional
to its total area. This can be shownnoticing that,
if= inf
h(w)
thetangent
derivatives of h vanish at w° and therefore theproperty
followsintegrating
the derivatives of halong
meridianspassing through
wo.Finally,
observe that the harmonic functiong(w)
whose value on8Be’
is
h(w) - h(z),
boundsh(w) - h(z)
from above in(Be)O. But,
sinceg(w)
isless than or
equal
to -°e2
on aproportional part
ofo"g(z)
-CQ (8v
denotes the normalderivative)
and the lemma follows.PROOF OF CLAIM: Notice that for
[jE7(p)~-E7(~/2)]n3(~)~0y
since
by hypothesis
there exists a ball contained in andtangent
to x.An
elementary geometric
constructionprovides
us with a chain ofballs,
~m)~m=°,
where kdepends only
on n, and suchBo =Be’,
and Therefore
h(w) - h(z)
since
u(w) = 0,
andh(z) > 0.
Proceeding inductively, h(x,)
-h(z)
and the claim follows.2. - The
topological
behaviour of the freeboundary.
We now turn our attention to the free
boundary problem arising
fromvariational
inequalities.
Let D be a bounded connected open set of
.Rn ;
p, theobstacle,
a realvalued function defined on .Rn
satisfying
do not vanish
simultaneously.
Let v be the least
superharmonic vanishing
at aD andverifying
This function can be
obtained,
forinstance, by minimizing
on the convex set of
H~(D)
definedby
and it is known that v has
Lipschitz
first derivatives in anycompact
sub-set of D
(see
Frehse[3],
Brezis-Kinderlehrer[1]).
The function v, defines two sets
and
Observe that for
LEMMA 2.1. Under the
preceeding
conditions has af inite
numberof
connected
eomponents
andAgg
0 on A.PROOF. j!2 contains a
neighborhood
of aD and hence we can chose acompact
set g(a
finite union ofcubes)
such thatA c K,
K c D and CK hasfinitely
many connectedcomponents.
On the other
hand,
since4q
do not vanishsimultaneously
and v is
superharmonic
we havehave a finite number of
components
that intersectK;
is a
component
By b )
andc)
there are at most as manycomponents
of S~ contained in Kas those of
Vi
and this proves the firstpart
of the lemma.To obtain the second
part,
consider in virtue of our assump- tions(4q
do not vanishsimultaneously),
the conesatisfies
Cs c VI
for small valuesof 8,
8> 0. On such cone, v - 99 is super- harmonic andstrictly positive,
and isLipschitz
henceThe
preceeding
lemma shows that we are in the conditions of the firstparagraph
of this work. Thatis, Jgg
C E 0 in aneighborhood flL,
of Aand
hence,
if we consider u = v - 99, we have thefollowing
situationb)
4u has aLipschitz
extension from Q n’B1 toD
r1 U.c) u
hasLipschitz
first derivatives on ‘l~.d)
u and Vu vanish in n’11.Lemmas 1.1 to 1.3 show that the free
boundary
ofQ, aQ,
has measurezero and that in S~* _
(D)°,
dv = 0. Hence it is natural to redefine D* asthe non coincidence
set,
and A* = D - S~* as the coincidence set(see also § 4).
We recall that H. Brezis and D. Kinderlehrer
[1,
Theorem3]
show that 11uis
locally
of bounded variation.They
also observethat,
if4q
isnegative
then
a.e.)
is of bounded variation. has finiteperimeter
in the sense of De
Giorgi).
The sameargument
shows in our case that A*has finite
perimeter.
In the n-dimensional case each connected
component
of(~l.*)°
has finiteperimeter [2,
LemmaIV]. (Notice
that(8Q*)
nD =8[(A*)°]
and its measureis
zero).
For the
remaining part
of thisparagraph
we will restrict ouranalysis
to the two dimensional case.
In such case,
applying
Theorem I of[2]
it follows that theboundary
ofeach connected
component
of(A *)°
is formed of a finite number of recti- fiable Jordan curves.In order to
apply
the reflectiontechniques
of H.Lewy,
we will provethat,
once a finite nunber ofpoints
is deleted from each Jordan curve in aneighborhood
of any otherpoint
of the curve, theonly boundary
of D* isthe curve itself.
Let C be a connected
component
of(1J.*)°,
Xo EaC,
and alsoB(x°,
small ball where
Jgg
0. We may assume that C ~CB(xo, ro)
~0.
Let~C~~
the connected
components
of such that Xo E Notice thatthere are a finite number of them
(at most,
as many as connected com-ponents
hasQ*).
Let us fix one of
them, Ci,
whoseboundary
iscomposed
of a Jordancurve
.1~, passing through
xo .( C1
isagain
of finiteperimeter
and Theorem 1 of[2] applies).
Observe that anycomponent
of Q* r1B(xo, ro)
must inter- sectaB(xo, ro).
Let y
and ~
be as in Lemma 1.4. Choose r1, such that the HessianH(u + ~) ~=
0(V(u + y)
isanalytic)
inoB(xo, rl)
n Sz*. Let a besmall
enough
such that~(B(xo, aro))
cB(xo, ro/2).
In the next two lemmas we look at the local behaviour of the
mappings
in
B(xo,
and show thatexcept
for a finite number ofexceptional points
maps the non-coincidence set into the coincidence set.
We have
already shown,
Lemma1.4, that ~
crosses theboundary
nearany
point
ofro).
In the first lemma we will show that the number ofcomponents that ~
maps into01
is finite. In the second we prove that each of thesecomponents
attaches to h and theexceptional points
will bethose where two of such
components
meet.LEMMA 2.2. Let G =
~-1(01)
nB(xo, rl),
G = UGi (Gi
connected compo- nentsof G); then,
the numberof components Gi,
such thatGi
i (’)oB(xo, aro)
-=1=ø,
is
finite. Moreover, i f
cu, is a connectedcomponent of
Sz* ~G,
and‘lb r1
B(xo, aro) ~ ~
then U r1[aB(xo, rl)
~G] # 0.
PROOF. Since
11q>O, Q*Ue(B(xo,r))
isconnected, 0 C r C ro .
Assume that
91
cB(xo, r1)
U0. Since 8
is open c and r1[Q*
ue(B(xo, r1))]
= 0(since
c( 8G)
~.J( aS2*)) .
On the other
hand,
In
fact,
ifara)
and( C2
acomponent
ofro/2))
we can construct a bundle of
disjoint paths
in with a fixedpoint
of G. The
images
of thispaths join ~(x)
with apoint
ofC; since, 01
has at most a finite number of
points (see [2]) and ~
restricted to anycompact
subset of ,S~ has finitemultiplicity,
there exists apath 6
such that~(6)
intersects
aC,, strictly
before than001. Being
open,(1) follows,
but then8(flL) D
S~* ue(B(xo,
and that isimpossible.
Let us see now that there are
finitely
many setsGi .
If
Gz
iscompactly
contained inB(xo,
in virtue of the factthat $
isopen,
$(Gi) :) 0
moreover,since $
isLipschitz (p(C)
denotesthe
Lebesgue
measure ofC). Therefore,
there areonly
a finite number ofGs
icompactly
contained inB(xo, ri).
On the other hand if
infinitely
manycomponents Gi
reach theboundary
of
B(xo,
let y be a limitpoi.n.t
of them.Clearly y 0
since~(G)
nB(xo, ro/2) ~ ~
and therefore it would be > ao forinfinitely
many i.Hence the Jacobian
of $
does not vanish in aneighborhood B(y, e)
of y, and
~)
is adiffeomorphism
that maps G ontoCl
r1~(B).
Observe that
8-1(T)
intersectsinfinitely
many timesaB(y, e/4)
andaB(y, alternatively, contradicting
the fact that3Ci
is a Jordan Curve(Ci
hasfinite
perimeter
and hence itsboundary
is a rectifiable JordanCurve.)
We recall
that, by
Lemma1.4,
anypoint y
of7~,
notbelonging
toaB (xo , ro/2),
verifies y EG.
Let
.r* (t ), (a c t ~ b ),
be aportion
of r1aB (xo , ocro) 0.
If
z(ti), x(t2) E F*, they
divide F in two open arcs,h1
andFa.
Let
F7
=F2
LEMMA 2.3.
I f x(tl), x(t2)
EGo
thenfor r:
or itfollows.
that:for
anythere exists
verifying (B (x, ~ (x) ~ c Go.
PROOF. Let an, 7
bnEGo,
anbn -> x(t,),
and11n
apoligonal
arc,11 n c Go, joining
an withIf we consider the Jordan curves (Xn, formed
by Fi, 11 n
and two smallsegments;
andfln,
formedby 4n
and two smallsegments,
then eitherany
compact
subarc of lies in the interior of~8n
forinfinitely
manyn’s,
or any
compact
subarc of.I’2
lies in the interior of an forinfinitely
many n’s.It suffices to consider either
possibility.
Assume the first
possibility
holds and We will argueby
con-tradiction. If the lemma were to fail we may find a sequence xn
Go
and moreover
Each zn
canbe joined
to apoint
of(S~* ~ G)
r1r1
B(xo, by
an arcBy
a similarargument
to that in thepreceeding
lemma we may construct n,, so that ~cn c
C(C
UGo).
It
is, then,
clear that we canextend
to an arcnn joining
xn with apoint
ofrl )
UGo ) .
Choosing adequate subsequences
we may assume that xn lies in the in- terior offl, and,
sincen£
can intersectflm only
in the smallsegments
nearx(t2)
we may therefore also assumethat xn
does not lie in the interior of( k ~ 1 )
and thatn:
intersectsfIn
for the first timealways
in the smallsegment
nearx(tl).
Let us remove two small balls
B(x(tl))
andB(x)
andanalyze
the situation.Between the
portion
ofn£
andn:+1
fromB(x)
toB(x(tl))
there is an arcof
An9
henceGo- (B(x)
uB(x(t,))
hasinfinitely
many connected compo-nents, Gn,
each onecontaining
an arcdn joining B(x)
withB(x(t,,)).
To
complete
the lemma it suffices to show that$(G*)
contains a fixed com-ponent
of which is a contradiction since then for every n.To show
this,
we consider a « diameter »separating
x fromx(tl) (where by
a « diameter » we mean theimage
of a diameterby
a conformalmapping
from the
disk).
The arcs of11n
above mentioned intersect this c diameter » ifB(x)
andB(x(tl))
have been chosen smallenough and
thatcompletes
the
proof.
At this
point
of ourwork,
we have shown that for each connected com-ponent
C ofA*,
itsboundary, a C,
isexcept
for a finite number ofpoints,
«
clean >>,
thatis,
if x e 3 C and is not anexceptional point
there is aneigh-
borhood .~1 of x that is divided
by
a Jordan arc into two con-nected, simply
connecteddomains, D1
andD2 c Q.
Hence onthe domain we are in the conditions of the theorem 1 of Kinderlehrer
[7]
and therefore the curve .1~ has a
parametrization (a 1).
The resultsin
[7]
that interest us can be resumed as follows:be a conformal
mapping
from aportion, H,
of the halfplane
Rj
=~(x, y), y > 0}
ontoD2
that carries asegment, (a, b)
of the z.axis ontoin a one to one fashion. Then w E
01,«,
a1,
up to(a, b)
and atany
point b),
eitherw (z)
=a(z - zo) +
orw (z) boO.
In the second case,
centering
w at zo andletting & = 1, w(z)
= Z2+ +
= x2 -y2 + i2xy + 0 ((x2 + Y2)(2+a)/2 )
in aneighborhood of (0, 0),
that
is, w(z)
forms aquadratic
cusp.,D2 being
the exterior of it.But, by
theproperties
of the reflexionmapping
considered in Lemma1.4; identity (1.41);
near
(0, 0) ~
would not reflect the noncoincidence setD2
into the coincidenceset, property
which must hold onD2. Therefore,
7" is differentiable and has a nonzerotangent
at eachpoint.
The
following
lemma is a refinement of the result of D. Kinderlehrer[7].
We
improve
the reflexionmapping
to obtain as muchregularity
of the freeboundary
as that ofVq.
We will also
keep
track of the Ckcontinuity
norms in order to proveanalyticity
of the freeboundary.
We mustpoint
out that asimplier
reflexionargument yields
theanalyticity
in the linear case(see [11]). However,
the estimates are needed in the nonlinear case where a direct reflexion ar- .
gument
fails.Let
Zo E r
and assume that for a fixed r.Let us fix
r’
r,depending only
onC,
r, q, such that(r¡
to bechosen
later).
We will prove :LEMMA. Let w be a
conformal mapping from
thehalf
circle intoD c
B (zo , r’)
nf2*, mapping
thesegment (-1, 1 ) (boundary
diametero f
thehalf circle)
onto asegment of
F(.1~
is known to be01,(/,), z,v(o)
= zo.Assume that w is
Lipschitz
with constantA
in such domain and thatfor toE(-1, 1)
Then,
underhypothesis (a)
and(b), w(t) verifies
where
M a universal constant, A
depending only
on the second derivativesPROOF.
Suppose
that 0 =w(to)
and defineThen ‘
since
choosmg q = r (E, C)
smallenough
Furthermore,
we canchoose q
so small that theimplicit
functionproblem:
for z has a
unique solution $ = 8(z)
which isLipschitz
continuous with constant Adepending only
on the second derivatives of 99.Hence
Now,
weproceed
to extend the conformalmapping quasi-conformally
tothe whole
disk;
set(Remember
that Qdepends
onto.
Toconstruct ~
wedevelope
aroundo =
w(to)) .
kIn virtue of Green’s
identity
and is the value of the above
integrals
for t =to,
we obtain the desired bound for and therequired
estimate forAs an immediate consequence of the lemma we have the
following:
THEOREM I. E and G is a connected
component of A*,
then aGis
composed of
af inite
numberof
Jordan arcs with a Ck+I’anondegenerated
parametrization. Moreover, if
is realanalytic,
the Jordan arcs are realanalytic,.
Observe that the
argument actually
shows that there is a virtualextension,
across the free
boundary,
of thesolution, u,
which is in the class C11+2,a.In the case studied
by
H.Lewy
and G.Stampacchia (D
convexand q concave)
where it is known that(ll*)°
hasonly
onecomponent
and S~* ismapped
into(~.*) by ~,
theboundary
of(~1.*)°
is a Jordan curve, withno
exceptional points.
3. - The non-linear case.
In this section we want
to
show how thepreceeding
methodsapply
alsoto the non-linear case treated
by
H. Brezis and D. Kinderlehrer[1],
inparticular
to the minimal surfaceequation.
In this case we
study
theregularity
of the solution u to a variationalproblem
of the formon the convex set of functions
(q
theobstale), v
eHo(D). (a,
islocally
a
strictly coercitive, C~,
vectorfield,
and C 0 on9j9);
such that and
Scp
do not vanishsimultaneously.
As
before,
we have twosets,
and
Brezis and Kinderlehrer
[1]
prove that u e in aneighborhood
ofA.
the
system being
"i
uniformly elliptic
for bounded Du.By exactly
the samereasoning
as in Lemma2.1, using
now, instead of the strict maximumprinciple,
Lemma2,
of MacNabb[12],
we prove thefollowing
lemma.LEMMA 3.1.
b)
Q has afinite
n2cmberof
connectedcomponents.
To
apply
the results of Lemmas 1.1 to 1.4 to this case webegin linearizing
the
problem.
LEMMA 3.2. For x E
S2,
let g be1 f
we extend gby
=0,
g isLipschitz
in aneighborhood of
A.PROOF. The
Lipschitz
characterof g
in the interior of S2 follows from the interior Schauder estimates of the second derivatives of u. TheLipschitz
constantbeing
fixed whenever the distance between thepoints
isBut near the
boundary
of Aand that
completes
theproof.
For the linearized
problem
it is easy to obtain theequivalents
ofLemmas 1.1 to 1.3.
LEMMA 3.3. Under the same
hypothesis
as Lemma1.1,
but now,S(u)
instead
of
Then, u(y)
>Oly - xol2 for
somep oint
y on00,
the constant 0depending
on the modulus
of elliplicity of SV.
LEMMA 3.4. Under the same
hypothesis of
Lemma1.2,
withS~
insteado f LI,
the same conclusions hold.LEMMA 3.5. Under the same
hypothesis o f
Lemma 3.4. Assumefurther
that
S(u)
=f
onQ,
wheref
has aLipschitz
extension to(we keep
thenotation
of
Lemma1.3).
Then u is a solutionof S(u)
=f
in(D)O
r’~ 0.PROOF. As in Lemma
1.3,
we can show thatand therefore the extension of u to
(5)°
follows.We define S~* and
11.*
as in Section 2.To prove the
equivalent
of Lemma 1.4 we can reduce our situationpointwise
to that of the lemma.However,
since in this paper weapply
itto the two dimensional case
only, by
means of a Beltrami transformationwe can reduce
(g
aLipschitz
function different from 0 in aneighborhood
of the freeboundary)
to
(o
denotescomposition)
where h isagain Lipschitz,
h # 0
in aneighborhood
of andvu v -B VoL.1 ).
The
mapping
wbeing
adiffeomorphism,
the results of Theorem 1apply
to our new 11.* and hence it remains valid for the
general,
non-linear case:THEOREM 3.
I f
connectedcomponent of A*,
00 iscomposed by a finite of parametrizable
arcs,ri,
each oneof
which islocally
the
only boundary
between A* and Q*.From now on we restrict our attention to one of the
C’,’
arcs,r, separating
a
portion,
of SZ* from acomponent, C,
ofA*.
We recall
that, by
construction(see
the linearcase)
such arcs have acontinuous
tangent. Therefore,
a conformalmapping, t(z),
fromD,
intoa
portion
of the halfplane, {(.r, y),
y >0}, carrying
r into asegment (a, b)
of the real line is on any
compact
subarc of h(understood
as a uni-form interior estimate
(i)) .
Let usfix,
as in the linear case, apoint
zo and such thatAlso,
assume thatfor
)
See 0. D. KELLOG, On the derivativesof
harmonicfunction
on theboundary,
TAMS,
33(1931),
pp. 486-510.(1
theLipschitz
constant ofVu, V92
inBr(zo).
Let us choose awith ~O,
small,
to be chosen later.Finally
letz(t)
be aLipschitz
conformalmapping
from the half circleinto
mapping (-1, 1 )
intoF, (z(O)
=zo).
We are
going
to prove,inductively,
that if andthen
z(t)
E up toIm(t)
=0, (k > 1). Moreover,
we willkeep
track ofthe constants in order to obtain
analyticity
wheneverVgg
andq)
areanalytic.
Let us first observe for any oc I up to h. To prove
it,
observe that is bounded and hence is also bounded. Com-
posing
Duow with a conformalmapping,
we reduce theproblem
to ahalf space
problem
where theLaplacian
of thecomposition
isbounded,
thecomposition
takesDqowol boundary
values on(a, b )
and thereforeCk°«
up to 7~. Therefore Vu has a
C~°« extension, Vu,
to aneighborhood
of anycompact
subarc of .I’.Let us assume that on
Br, Vu
has norm smaller than C.LEMMA 3.6.
Assume, inductively,
thatfor
and
(where fl
is alarge
constant andwhere
where d = 1-
it,, 1,
A is theLipschitz
constantof z(t)
on A andCo
an absoluteconstant.
Also,
PROOF. Since 0 =
z(to),
then20 - Annati detla Scuola Norm. Sup. di Pisa
Let
Set
if e
is chosen smallenough depending
on0, Â
and the modulus ofellipticity
of then S* remains
strictly elliptic
on Let p be the Beltrami coefficient associated to ~S*.Clearly
,u is a realanalytic
function(T
an absolute constantdepending only
on the definition of p as a rationalfunction,
inparticular
as aseries,
onl,ul
1- 6 with 6depending only
on that is onC,
and A.Therefore,
there is aunique
realanalytic
Beltrami transformationf =I biizizi verifying bko
= and suchthat if
f-- = ~ bîi,
as well asb’, verify
C’
again
an absolute constant.On the new coordinate
system,
andV(u - q)
vanish onMoreover,
around 0 =f (o), they verify
where and
T(/) depend only
on the Beltramitransformation,
areanalytic,
and with bounds for its coefficients for the same
type
as before.Let us now consider a conformal
mapping C(i?)
of the halfcircle,
~. ontoThen 77i = with
í1
=p(z(t)). Hence, í1
is of classCk~«,
with the sametype
of constants as those and z and thereforeq(t)
is a functionon to,
with anasymptotic development n(t)
(This
can beeasily
checkedwriting
q as thecomposition
of aparticular
solution with a conformal
mapping.)
The constants 7~ are boundedby
Applying
Lemma3.6, C(r¡)
has aasymptotic development,
and henceso does
z(~(r~)(t))
aroundto.
The estimate forVzu
as a func-tion
of 27, provided
is chosenlarge enough
to absorve the constants that appear in standard apriori
estimates.4. - The non-dense
part
of the freeboundary.
We would like now to discuss the
remaining part
of A.First,
we notice thatA-A*
is a false coincidence set in the sensethat
can bereplaced by
another(h c- Co’ (92))
still satis-fying
ourhypothesis
and such that u is still the solution of the variationalproblem,
but =A*.
To construct
h,
we consider aCo function g
such that(where
.H~ is a suitableneighborhood
ofaA) and g
= 0 on the rest of D.Set h = yg. For y small
enough
the condition thatS(q; - h)
andVS(99 - h)
do not vanish
simultaneously
is still fulfilled.On the other
hand,
the fact thatS(u)
= 0 acrossA -A*
shows thatlocally
is contained in an arc of a differentiable curve.If the
a~’s
are realanalytic
functions of Duand
is also realanalytic,
the set
A -A*
islocally
ananalytic
arc or an isolatedpoint (Notice
thatif there exists a sequence of
points
xn ofd. ~ ~1.* accumulating
on apoint x
not in
A*, they
mustlay
in ananalytic
arc,T,
near ~; then(u - q) ow
hasto be the solution to the
Cauchy problem
Vv = 0 onr,
11v= 4 [(u
-q)ow],
once the
problem
has been linearizedby
means of the Beltrami transfor-mation, w).
Furthermore,
since the ballproperty
of Lemma 1.2(resp. 3.4)
has to hold at both sides of the curve1~,
we have twopossibilities:
either 1~’ is aclosed
analytic
curve or itsclosure, P,
is a new arc,7~*y eventually closed,
with its end
points (point) laying
in 11*(Precisely
1~* ~ r consists of theseend
points (end point)).
In the linear case, this second
possibility
can also be excluded.THEOREM 5. In the linear case with a real
analytic obstacle,
iscomposed of
isolatedpoints plus
af inite
numberof
closedanalytic
curves.PROOF. The
Lewy-Stampacchia [11],
reflectionfunction,
let us call it w, is defined in a uniformneighborhood
of all.Let us choose a
neighborhood
H in such a waythat,
ifw(x) 0 A, w(w(x))
is
again defined,
and let zo be an endpoint
ofF,
xo e A*. Then there aretwo
components,
and82,
of Q nB(x°, eo)
that have P as commonboundary.
If
(11.*)°
has a finite number of connectedcomponents
in aneighborhood
of
by
means of the reflection w it follows that is ananalytically parametrizable
arc,part
of which is .1~.Hence,
the arc is the same for81
and
S2
and that is notpossible. Therefore,
one ofthem,
let us saySi
has tohave
boundary points
in common withinfinitely
manycomponents
ofin any
neighborhood
of a?o-On the other
hand,
near1’,
w mapsS,
intoS2,
andw(w(x))
= x(wow
isanalytic
andw(x) = x
on7~).
Hence in asubneighborhood
of a?o?w(Si)
cB2
and
w(w(x))
= x which means that coB2
but that is notpossible
5. -
On the Stefanproblem
and other remarks.In this last section we will make a few remarks that we
postponed
forthe purpose of
continuity.
Let us first mention the Stefanproblem
astreated
by
Friedman and Kinderlehrer[4].
There,
we have two domains S~ and 11. inDx[O, oo]. (D
a domain inl~n)
and a
function,
u,verifying
a) u
E in the variable x for fixed t.(Personal
communication of DavidKinderlehrer.)
e) cxJ ,
0(T
denotes the DeGeorgi
n-dimensionalperimeter).
Hence Lemmas 1.1 and 1.2