C OMPOSITIO M ATHEMATICA
H. M IRKIL
A counterexample to discrete spectral synthesis
Compositio Mathematica, tome 14 (1959-1960), p. 269-273
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by H. Mirkil
Malliavin
[2]
hasproved
thatspectral synthesis
holds for the convolutionalgebra Ll(G)
of alocally compact
abelian group Gprecisely
when G iscompact, i.e., precisely
whenLl(G)
hasdiscrete character space.
Question:
Doesspectral synthesis
holdfor an
arbitrary
commutativesemi-simple
Banachalgebra
Awith discrete maximal ideal space M? Answer: No. Not even when
primary
ideals are absent atinfinity.
We exhibit a counter-example
thatarises,
infact,
as a convolutionalgebra
on thecircle.
§
1. Definitions.Let us say that
spectral synthesis
holds for A(with
Mdiscrete or
not)
if each closed ideal is the intersection ofregular
maximal ideals.
(Historically
andlogically
the above label should beapplied
rather to anequivalent property
of the dual space A*:that each weak-star closed invariant
subspace
of A * isgenerated by multiplicative
functionals. But here we shall be more concerned with thealgebra
Aitself.)
Instudying spectral synthesis
it isusual to
require
in advance that A beSilov-regular :
for eachpoint
m eM,
and for eachneighborhood
V of m, there is somex e A with
x(m)
= 1 and x = 0 outside V. See[1]
p. 83.(An algebra
A with discrète M isalways Silov-regular,
and in fact contains everyfinitely-non-zero
sequence,i.e.,
everycomplex
function x on M such that
x(m) ~
0 forfinitely
many monly.)
When A is
Silov-regular, spectral synthesis
can be reformulatedas follows. For each
(not necessarily closed)
idealI ~ A,
definethe set
Z(I) ~
Mconsisting
of the common zeroes of the x e I.For each closed subset
N M,
define the idealK(N)
Aconsisting
of all xE A that vanishidentically
onN,
and also theideal
J(N)
Aconsisting
of allcompact-supported x ~
A thatvanish
identically
on open setscontaining
N.(When
M isdiscrete, J(N)
issimply
all thefinitely-non-zero
sequences that vanishidentically
onN. )
Then for every ideal I withZ(I)
= N onecan prove that
J(N) I K(N). (The proof
isespecially
easy270
with discrete
M.)
Hence a necessary and sufficient condition forspectral synthesis
in aSilov-regular
A is thatK(N)
be the closure ofJ(N)
for each closed N M. In otherwords,
every ideal is determinedby
its zeroes.§
2. The Tauberian property.In
particular,
a trivial necessary condition forspectral synthesis
in a
Silov-regular
A is that the idealJ(oo) consisting
of all com-pact-supported
x e A(hence,
when M isdiscrete, consisting
ofall
finitely-non-zero sequences)
be dense in A. Such an A is called Tauberian.(Notice, however,
that when M isdiscrete,
x e A need not be
approximable
in the moststraightforward
wayby
its own"partial
sums." Forinstance,
take A = the Fourier transform of the convolutionalgebra
of continuous functions onthe circle. Then one needs
Fejer sums.)
An ideal I withempty Z(I )
is sometimes called aprimary
ideal atinfinity.
To say that A is Tauberian is to say it contains no proper closedprimary
ideals at
infinity. (Primary
ideals at finite distance can occur ingeneral,
but not when M isdiscrète.)
Non-Tauberian
algebras
are easy to comeby.
Here is onewith discrete M. Let A consist of all
complex
sequencesx={x(m)}
for which
limm mx(m)
exists and is finite.Put ~x~ =
sup,.mlx(m)l.
Since the most
general
continuous funetional e is of the form(x, 03BE~ = 03A3mx(m)03BE(m),
withIm |03BE(m)| m finite,
then the mostgeneral multiplicative functional p
is of theform ~ x, 03BC~
=x(m)
for some fixed m. Hence the maximal ideal space M is the
positive integers.
But the closure ofJ( oo )
in A consists of all sequences y for whichlimm
my(m)
= 0. Hence A isnon-Tauberian,
andspectral synthesis
fails for A in a trivial anduninteresting
way. We needonly
restrict our attention to the closedsubalgebra J(~)
inorder to have
spectral synthesis
workbeautifully. Moreover,
acertain natural extension of
spectral synthesis
holds even for thealgebra
Aitself,
viz. every closed ideal is the intersection ofregular
maximal ideals and closedprimary
ideals.§
3. Construction of thecounterexample.
Now for a Tauberian
algebra
in whichspectral synthesis genuinely
fails. Consider the vectorspace E
of203C0-periodic
com-plex
functionssquare-integrable
on(-n, 03C0)
and continuous onthe closed subinterval
[-n/2, n/2].
(i)
The normmakes E a Banach space.
(ii)
Withordinary
convolution asmultiplication, E
is a Banachalgebra.
For whenf,
g eL2(-03C0, 03C0),
thenI*g
isperiodic-continuous (in fact,
hasabsolutely convergent
Fourierseries).
To see thatthe
multiplicative inequality ~f*g~ ~ ~f~ ~g~ holds,
write203C0 ~f~2
for the first term in the definitionof ~f~.
ThenHence
and also
Hence
(iii)
Thetrigonometric polynomials
form a densesubalgebra
of ét. For
they
areuniformly
dense in the space of203C0-periodic
continuous functions. And the continuous functions are L2-dense in
L2( -n, n).
(iv)
The mostgeneral
non-zeromultiplicative functional
ond’ is of the form
for some fixed m.
For, by (iii)
it isenough that p
have this form for eachtrigonometric
monomial pn(definition: Pn(s) = eins).
And because the p. are
orthogonal idempotents,
then03BC(pm)
= 1for some one Pm while
03BC(pn)
= 0for n ~
m.Finally,
we define thealgebra
E as the Fourier transform of àf. The elements x of E are thus the double-ended sequences(x(m))
that arise as Fourier coefficients of thef e
é. Underpointwise multiplication,
E is analgebra isomorphic
to the con-volution
algebra
J. Andby transporting
the é norm to E wemake it also a Banach
algebra. By (iv)
E has theintegers
asmaximal ideal space. And
by (iii)
E is Tauberian.§
4.Approximate
units.Returning momentarily
to ageneral
commutative semi-simple
Banachalgebra A,
let us say that an x ~ A has ap-272
proximate
units if xbelongs
to the closure of theprincipal
ideal Ax.
(Among
the variouspossible
notions ofapproximate unit,
this isperhaps
the very weakest. In an LIalgebra,
forinstance, there
always
exists asingle
bounded net{yv}
such thatyv*x
converges to x for allx.)
Ourpresent
interest inapproximate
units stems from the
following
fact(essentially
due toDitkin).
In order that
spectral synthesis
holdfor
a Tauberian A with discrete M it is necessary andsufficient
that every x ~ A haveapproximate
units.
Necessity:
Let N M be the zeroes of x ~ A. Then also N =Z(Ax).
It follows thatK(N)
coincides with the closure ofAx,
since these two ideals have the same zeroes. Inparticular, since x e K(N),
then xbelongs
to the closure of Ax.Sufficiency:
Define N as above. We must
approximate
xby something
inJ(N).
Choose
y e A
suchthat ~x - yx~ 03B5.
And choosew ~ J(~)
such that
11 y - w~
s. Then wx ej(N)
and§
5. An element without units.We have to find some unitless element x in our
algebra
E.That
spectral synthesis
must then fail for Edepends,
of course,only
on the first half of Ditkin’s theorem. It will be more con-venient to work
directly
with the convolutionalgebra
E. Weclaim that the characteristic function
f
of the closed interval[-n/2, n/2]
does not haveapproximate
units in E. More ex-plicitly,
we claim that iff(s)
= 1for |s| ~ n/2
andf(s)
= 0 for03C0/2 Isl ~ 03C0, then 1 Ig
*f
-III
>1/5
for all g e fff.For
suppose, ~g*f - f~ 1/5.
Inparticular, |(g*f )(-03C0/2)-1|
1f5 and |(g*f)(03C0/2) - Il
~1/5.
In terms of the indefiniteintegral
G= 1 J g(s)ds, we can write
To sum up,
On the other
hand,
let us write x and Jrespectively
for theelements of E
corresponding
to the above elementsf
and g of E.We are
supposing ~yx - x~ ~ 1/5,
hence(y(o)x(o) - x(0)|~1/5.
But
x(0) = 1 203C003C0-03C0f(s)ds = 1/2,
and y(0) = 1 203C003C0-03C0 g(s)ds
= G(z);
hence
1(1/2)G(n) - 1/2| ~ 1/5,
or|G(03C0) - 1| ~ 2/5.
This estimate contradicts the estimate obtained in the last para-
graph.
Hence x e E does not haveapproximate
units andspectral synthesis
fails for E.§
6. Charactermultipliability.
In
conclusion,
let uspoint
out that thepathology
of E has itssource in the fact that the
multiplier algebra
for E does not contain most functions z of the formz(m) = 03B6m
for fixedcomplex
03B6 of modulus 1. Or what is the
same, 0
is not translation-in- variant. For suppose, that the commutativesemi-simple
TauberianBanach
algebra
A has a discrete abelian group G as maximal ideal space. And suppose thatfor
every x ~ A and every characterz on G we have zx E A. Then
spectral synthesis
must holdfor
A.Proof:
By
the closedgraph theorem,
eachmapping x ~
zx iscontinuous A ~ A. And because A is
Tauberian,
thenby Silov [3]
p. 9 and p. 13, eachmapping
z ~ zx iscontinuous é -
A.With all this
continuity
it islegitimate
to use A-valuedintegration,
and then the
approximate units yv
inL1(G)
will work also for A.Hence
spectral synthesis
must hold for A.REFERENCES L. H. LOOMIS,
[1] Introduction to Abstract Harmonic Analysis, van Nostrand, 1953.
P. MALLIAVIN,
[2] Impossibilité de la synthèse spectrale sur les groupes abéliens non compacts
Inst. des Hautes Etudes Scientifiques, Publications Maths. 2 (1959), 61-68.
G. E. SILOV,
[3] "Homogeneous rings of functions," Uspehi Matem. Nauk N. S. 6 (1951),
A.M.S. Translation 92.
[Oblatum 26 september 1959].