A hierarchy of non-hydrostatic models for free-surface flows
Yohan Penel 1
1
Team ANGE (CEREMA, Inria, UPMC, CNRS)
Joint work with
E. Fern´ andez-Nieto (Univ. Sevilla, Spain) M. Parisot & J. Sainte-Marie (ANGE)
Collaborators: E. Audusse (Univ. Paris 13), T. Morales de Luna (Univ. C´ ordoba, Spain)
XVI International Conference on Hyperbolic Problems
Theory, Numerics, Applications
Aachen – August, 4th. 2016
Outline
1 Introduction
2 Derivation of the hierarchy of models
3 Energy
4 Linear wave analysis
5 Conclusion
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Literature about free-surface flows
Free-surface incompressible Euler equations
Shallow water equations Hydrostatic pressure
Homogeneous velocity
Shallow water assumption
Literature about free-surface flows
Free-surface incompressible Euler equations
Shallow water equations Hydrostatic pressure
Homogeneous velocity
Shallow water assumption
A. Barr´e de Saint-Venant,Th´eorie du mouvement non permanent des eaux, avec application aux crues des rivi`eres et `a l’introduction des mar´ees dans leurs lits(C. R. Acad. Sci.73, 1871)
J.-F. Gerbeau, B. Perthame,Derivation of viscous Saint-Venant system for laminar shallow water; numerical validation (Discrete Contin. Dyn. Syst. Ser. B1(1), 2001)
S. Ferrari, F. Saleri,A new two-dimensional Shallow Water model including pressure effects and slow varying bottom topography (Math. Model. Numer. Anal.38(2), 2004)
F. Marche,Derivation of a new two-dimensional viscous shallow water model with varying topography, bottom friction and capillary effects (Eur. J. Mech. B Fluids26(1), 2007)
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Literature about free-surface flows
Free-surface incompressible Euler equations
Shallow water equations hhh hhh hh h
Hydrostatic pressure
Homogeneous velocity
Shallow water assumption
F. Serre,Contribution `a l’´etude des ´ecoulements permanents et variables dans les canaux(La Houille Blanche6, 1953) A.E. Green, P.M. Naghdi,A derivation of equations for wave propagation in water of variable depth(J. Fluid Mech.78(2), 1976) M.-O. Bristeau, J. Sainte-Marie,Derivation of a non-hydrostatic shallow water model; Comparison with Saint-Venant and Boussinesq systems (Discrete Contin. Dyn. Syst. Ser. B10(4), 2008)
D. Lannes, P. Bonneton,Derivation of asymptotic two-dimensional time-dependent equations for surface water wave propagation(Phys. Fluids 21(1), 2009)
Peregrine ’67, Madsenet al.’91 ’96 ’03 ’06, Nwogu ’93, Casulliet al.’95 ’99, Yamazakiet al.’09, . . .
Literature about free-surface flows
Free-surface incompressible Euler equations
Shallow water equations Hydrostatic pressure
hhh hhh Homogeneous velocity hhh hhh hhh
hhh h
Shallow water assumption
E. Audusse, M.-O. Bristeau, B. Perthame, J. Sainte-Marie,A multilayer Saint-Venant system with mass exchanges for Shallow Water flows.
Derivation and numerical validation(Math. Model. Numer. Anal.45(1), 2011)
F. Bouchut, V. Zeitlin,A robust well-balanced scheme for multi-layer shallow water equations(Discrete Contin. Dyn. Syst. Ser. B13(4), 2010) E.D. Fern´andez-Nieto, E.H. Kon´e, T. Morales de Luna, R. B¨urger,A multilayer shallow water system for polydisperse sedimentation(J. Comput.
Phys.238, 2013)
Castroet al.’01 ’04 ’10, Narbonaet al.’09 ’13, Rambaud ’11, . . .
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Literature about free-surface flows
Free-surface incompressible Euler equations
Shallow water equations hhh hhh hh h
Hydrostatic pressure
hhh hhh Homogeneous velocity hhh hhh hhh
hhh h
Shallow water assumption
Derivation of multilayer non-hydrostatic models
M. Zijlema, G.S. Stelling,Further experiences with computing non-hydrostatic free-surface flows involving water waves(Int. J. Numer. Methods Fluids48(2), 2005)
Y. Bai, K.F. Cheung,Dispersion and nonlinearity of multi-layer non-hydrostatic free-surface flow(J. Fluid Mech.726, 2013)
Fluid domain
z = z
b(x) z = η(t, x)
H(t,x) u = (u,w)
x z
Water height:
H(t , x ) = η(t , x) − z b (x)
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Euler equations
Model
∂ x u + ∂ z w = 0
∂ t u + ∂ x (u 2 + p) + ∂ z (uw) = 0
∂ t w + ∂ x (uw) + ∂ z (w 2 + p) = −g set in the domain Ω(t ) =
(x, z ) ∈ R 2
z b (x ) ≤ z ≤ η(t, x) Boundary conditions
∂ t η(t, x) + u t, x , η(t, x)
∂ x η(t, x) − w t, x, η(t , x)
= 0 p t, x, η(t , x)
= p atm (t, x) u t, x, z b (x)
z b 0 (x) − w t , x, z b (x )
= 0 together with well-prepared initial conditions
Pressure fields p(t, x, z ) = p atm (t , x) + g η(t, x) − z
+ q(t , x , z )
Euler equations
Model
∂ x u + ∂ z w = 0
∂ t u + ∂ x (u 2 + q) + ∂ z (uw) = −∂ x (g η + p atm )
∂ t w + ∂ x (uw) + ∂ z (w 2 + q) = 0 set in the domain Ω(t ) =
(x, z ) ∈ R 2
z b (x ) ≤ z ≤ η(t, x) Boundary conditions
∂ t η(t, x) + u t, x , η(t, x)
∂ x η(t, x) − w t, x, η(t , x)
= 0 q t, x, η(t, x)
= 0 u t, x, z b (x)
z b 0 (x) − w t , x, z b (x )
= 0
together with well-prepared initial conditions
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Multilayer framework
z = z
b(x) = z
1/2(x) z = η(t, x) = z
L+1/2(t, x)
z = z
α−1/2(t, x) z = z
α+1/2(t, x) H(t, x) h
α(t, x)
x z
Height decomposition: h α (t, x) = ` α H(t , x) with ` α ∈ (0, 1) and P L
α=1 ` α = 1
Multilayer framework
z = z
b(x) = z
1/2(x) z = η(t, x) = z
L+1/2(t, x)
z = z
α−1/2(t, x) z = z
α+1/2(t, x) H(t, x) h
α(t, x)
x z
Height decomposition: h α (t, x) = ` α H(t , x) with ` α ∈ (0, 1) and P L
α=1 ` α = 1 Homogeneous mesh: ` α = 1
L
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Multilayer framework
z = z
b(x) = z
1/2(x) z = η(t, x) = z
L+1/2(t, x)
z = z
α−1/2(t, x) z = z
α+1/2(t, x) H(t, x) h
α(t, x)
x z
Notations
[[f ]] α+1/2 = f α+1/2 + − f α+1/2 − , e f α+1/2 = γ α+1/2 f α+1/2 − + (1 − γ α+1/2 )f α+1/2 +
Multilayer framework
z = z
b(x) = z
1/2(x) z = η(t, x) = z
L+1/2(t, x)
z = z
α−1/2(t, x) z = z
α+1/2(t, x) H(t, x) h
α(t, x)
x z
Notations
hf i α (t, x) = 1 h α (t, x)
Z z
α+1/2(t,x) z
α−1/2(t,x)
f (t , x, z ) dz
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Multilayer framework
z = z
b(x) = z
1/2(x) z = η(t, x) = z
L+1/2(t, x)
z = z
α−1/2(t, x) z = z
α+1/2(t, x) H(t, x) h
α(t, x)
x z
Notations
n α+1/2 = (−∂ x z α+1/2 , 1) T
Discontinuous Galerkin framework
Let us be given a velocity field satisfying
[[u]] α+1/2 · n α+1/2 = 0 ⇐⇒ [[w ]] α+1/2 = [[u]] α+1/2 ∂ x z α+1/2 Toy model
∂ t R + ∂ x (u R + P ) + ∂ z (w R + Q ) = S (1) where R , P , Q and S take values in R p
Semi-discrete formulation over each layer L α = (z α+1/2 , z α−1/2 )
∂ t (h α R α ) + ∂ x (h α [u R α + P α ]) + F α+1/2 R − F α−1/2 R = h α S α
where
F α+1/2 R = Υ α+1/2 R e α+1/2 − P f α+1/2 ∂ x z α+1/2 + Q e α+1/2
Υ α+1/2 = w e α+1/2 − ∂ t z α+1/2 − e u α+1/2 ∂ x z α+1/2
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Discontinuous Galerkin framework
Let us be given a velocity field satisfying
[[u]] α+1/2 · n α+1/2 = 0 ⇐⇒ [[w ]] α+1/2 = [[u]] α+1/2 ∂ x z α+1/2 Toy model
∂ t R + ∂ x (u R + P ) + ∂ z (w R + Q ) = S (1) where R , P , Q and S take values in R p
Semi-discrete formulation over each layer L α = (z α+1/2 , z α−1/2 )
∂ t (h α R α ) + ∂ x (h α [u R α + P α ]) + F α+1/2 R − F α−1/2 R = h α S α
where
F α+1/2 R = Υ α+1/2 R e α+1/2 − P f α+1/2 ∂ x z α+1/2 + Q e α+1/2
Υ α+1/2 = w α+1/2 − − ∂ t z α+1/2 − u − α+1/2 ∂ x z α+1/2
Discontinuous Galerkin framework
Let us be given a velocity field satisfying
[[u]] α+1/2 · n α+1/2 = 0 ⇐⇒ [[w ]] α+1/2 = [[u]] α+1/2 ∂ x z α+1/2 Toy model
∂ t R + ∂ x (u R + P ) + ∂ z (w R + Q ) = S (1) where R , P , Q and S take values in R p
Semi-discrete formulation over each layer L α = (z α+1/2 , z α−1/2 )
∂ t (h α R α ) + ∂ x (h α [u R α + P α ]) + F α+1/2 R − F α−1/2 R = h α S α
where
F α+1/2 R = Υ α+1/2 R e α+1/2 − P f α+1/2 ∂ x z α+1/2 + Q e α+1/2
Υ α+1/2 = w α+1/2 + − ∂ t z α+1/2 − u + α+1/2 ∂ x z α+1/2
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Main idea
Discontinuities across layer interfaces allowed provided jump conditions
∂ t Z[[ R ]] z=Z + ∂ x Z[[u R + P ]] z=Z − [[w R + Q ]] z=Z = 0 or equivalently
Υ[[ R ]] − ∂ x Z[[ P ]] + [[ Q ]] = 0 Integrating Eq. (1) over a layer L α yields
h α h S i α = ∂ t (h α h R i α ) − R α+1/2 − ∂ t z α+1/2 + R α−1/2 + ∂ t z α−1/2
+ ∂ x (h α hu R + P i α ) − (u − α+1/2 R α+1/2 − + P α+1/2 − )∂ x z α+1/2 + (u α−1/2 + R α−1/2 + + P α−1/2 + )∂ x z α−1/2
+ w α+1/2 − R α+1/2 − + Q − α+1/2 − w α−1/2 + R α−1/2 + + Q + α−1/2
Main idea
Discontinuities across layer interfaces allowed provided jump conditions
∂ t Z[[ R ]] z=Z + ∂ x Z[[u R + P ]] z=Z − [[w R + Q ]] z=Z = 0 or equivalently
Υ[[ R ]] − ∂ x Z[[ P ]] + [[ Q ]] = 0 Integrating Eq. (1) over a layer L α yields
h α h S i α = ∂ t (h α h R i α ) + ∂ x (h α hu R + P i α ) + h
R α+1/2 − Υ α+1/2 − P α+1/2 − ∂ x z α+1/2 + Q α+1/2 − i
− h
R α−1/2 + Υ α−1/2 − P α−1/2 + ∂ x z α−1/2 + Q + α−1/2 i
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Main idea
Discontinuities across layer interfaces allowed provided jump conditions
∂ t Z[[ R ]] z=Z + ∂ x Z[[u R + P ]] z=Z − [[w R + Q ]] z=Z = 0 or equivalently
Υ[[ R ]] − ∂ x Z[[ P ]] + [[ Q ]] = 0 Integrating Eq. (1) over a layer L α yields
h α h S i α = ∂ t (h α h R i α ) + ∂ x (h α hu R + P i α ) + h
R e α+1/2 Υ α+1/2 − P f α+1/2 ∂ x z α+1/2 + Q e α+1/2
i
− h
R e α−1/2 Υ α−1/2 − P f α−1/2 ∂ x z α−1/2 + Q e α−1/2
i
Spaces of approximation
q
α−1/2, e u
α−1/2, w e
α−1/2q
α+1/2, e u
α+1/2, w e
α+1/2z = z
α−1/2z = z
αz = z
α+1/2w
α−1/2+w
α+1/2−w
αu
α,q
αu(t , x) =
L
X
α=1
u α (t, x) 1 {L
α(t,x)} (z ) + E L
w (t, x) =
L
X
α=1
w α (t, x) − z − z α (t , x )
∂ x u α (t, x)
1 {L
α(t,x)} (z ) + E L 0
q continuous over the water column
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Core of the models
Applying the previous semi-discretisation to the Euler equations leads to
∂ t h α + ∂ x (h α u α ) + Υ α+1/2 − Υ α−1/2 = 0
∂ t (h α u α ) + ∂ x h α u 2 α + h α q α
+ U α+1/2 − U α−1/2 = −h α ∂ x (g η + p atm )
∂ t (h α w α ) + ∂ x (h α u α w α ) + W α+1/2 − W α−1/2 = 0
with
U α+1/2 = e u α+1/2 Υ α+1/2 − ∂ x z α+1/2 q α+1/2 W α+1/2 = w e α+1/2 Υ α+1/2 + q α+1/2 and
Υ α+1/2 = w e α+1/2 − ∂ t z α+1/2 − e u α+1/2 ∂ x z α+1/2
Core of the models
Applying the previous semi-discretisation to the Euler equations leads to
∂ t h α + ∂ x (h α u α ) + Υ α+1/2 − Υ α−1/2 = 0
∂ t (h α u α ) + ∂ x h α u 2 α + h α q α
+ U α+1/2 − U α−1/2 = −h α ∂ x (g η + p atm )
∂ t (h α w α ) + ∂ x (h α u α w α ) + W α+1/2 − W α−1/2 = 0
with
U α+1/2 = e u α+1/2 Υ α+1/2 − ∂ x z α+1/2 q α+1/2 W α+1/2 = w e α+1/2 Υ α+1/2 + q α+1/2 and
Υ α+1/2 =
L
X
β=α+1
∂ x h β
u β − u
where u =
L
X
α=1
` α u α
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Core of the models
Applying the previous semi-discretisation to the Euler equations leads to
∂ t H + ∂ x Hu
= 0
∂ t (h α u α ) + ∂ x h α u 2 α + h α q α
+ U α+1/2 − U α−1/2 = −h α ∂ x (g η + p atm )
∂ t (h α w α ) + ∂ x (h α u α w α ) + W α+1/2 − W α−1/2 = 0
with
U α+1/2 = e u α+1/2 Υ α+1/2 − ∂ x z α+1/2 q α+1/2 W α+1/2 = w e α+1/2 Υ α+1/2 + q α+1/2 and
Υ α+1/2 =
L
X
β=α+1
∂ x h β
u β − u
where u =
L
X
α=1
` α u α
Requirements for the P 1 choice
Additional equation
∂ t (zw) + ∂ x (zuw) + ∂ z z (w 2 + q)
= w 2 + q.
which is discretised as
∂ t (h α hzw i α ) + ∂ x (h α u α hzw i α ) + F α+1/2 zw − F α−1/2 zw = h α
w 2 + q
α
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Requirements for the P 1 choice (S 1 model)
Additional equation
∂ t (zw) + ∂ x (zuw) + ∂ z z (w 2 + q)
= w 2 + q.
which is discretised as
∂ t (h α hzw i α ) + ∂ x (h α u α hzw i α ) + F α+1/2 zw − F α−1/2 zw = h α
w 2 + q
α
Let us introduce the signed standard deviation σ α = − h
α∂
xu
α2 √
3 such that w 2
α = w 2 α + σ α 2 , hzwi α = z α w α + h α σ α 2 √
3
Requirements for the P 1 choice (S 1 model)
Additional equation
∂ t (zw) + ∂ x (zuw) + ∂ z z (w 2 + q)
= w 2 + q.
which is discretised as
∂ t (h α hzw i α ) + ∂ x (h α u α hzw i α ) + F α+1/2 zw − F α−1/2 zw = h α
w 2 + q
α
Then
∂ t (h α z α w α ) + ∂ x (h α z α u α w α ) + ∂ t h 2 α σ α
2 √ 3
+ ∂ x
h 2 α σ α u α
2 √ 3
+ z α+1/2 ( w e α+1/2 Υ α+1/2 + q α+1/2 ) − z α−1/2 ( w e α−1/2 Υ α−1/2 + q α−1/2 )
= h α w 2 α + σ α 2 + q α
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Requirements for the P 1 choice (S 1 model)
Additional equation
∂ t (zw) + ∂ x (zuw) + ∂ z z (w 2 + q)
= w 2 + q.
which is discretised as
∂ t (h α hzw i α ) + ∂ x (h α u α hzw i α ) + F α+1/2 zw − F α−1/2 zw = h α
w 2 + q
α
Then
∂ t (h α σ α ) + ∂ x (h α σ α u α ) = 2 √ 3
q α − q α+1/2 + q α−1/2 2
− Υ α+1/2
h α ∂ x u α
12 + w e α+1/2 − w α
2
+Υ α−1/2
h α ∂ x u α
12 + w α − w e α−1/2 2
Requirements for the P 1 choice (S 1/2 model)
Additional equation
∂ t (zw) + ∂ x (zuw) + ∂ z z (w 2 + q)
= w 2 + q.
which is discretised as
∂ t (h α hzw i α ) + ∂ x (h α u α hzw i α ) + F α+1/2 zw − F α−1/2 zw = h α
w 2 + q
α
Rather using a Hermitte interpolation leads to
zw |L
α≈ z α w α + (z − z α )(w α − z α ∂ x u α ), w |L 2
α≈ w 2 α − 2(z − z α )w α ∂ x u α
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Requirements for the P 1 choice (S 1/2 model)
Additional equation
∂ t (zw) + ∂ x (zuw) + ∂ z z (w 2 + q)
= w 2 + q.
which is discretised as
∂ t (h α hzw i α ) + ∂ x (h α u α hzw i α ) + F α+1/2 zw − F α−1/2 zw = h α
w 2 + q
α
Then
∂ t (h α z α w α ) + ∂ x (h α z α u α w α ) + z α+1/2 q α+1/2 − z α−1/2 q α−1/2 + Υ α+1/2
z α+1/2 w e α+1/2 + H 2
4L 2 (∂ ] x u) α+1/2
− Υ α−1/2
z α−1/2 w e α−1/2 + H 2
4L 2 (∂ ] x u) α−1/2
= h α w 2 α + q α
Requirements for the P 1 choice (S 1/2 model)
Additional equation
∂ t (zw) + ∂ x (zuw) + ∂ z z (w 2 + q)
= w 2 + q.
which is discretised as
∂ t (h α hzw i α ) + ∂ x (h α u α hzw i α ) + F α+1/2 zw − F α−1/2 zw = h α
w 2 + q
α
Then
q α = q α+1/2 + q α−1/2
2 + Υ α+1/2 H
4L (∂ ] x u) α+1/2 + w e α+1/2 − w α
2
− Υ α−1/2 H
4L (∂ ] x u) α−1/2 + w α − w e α−1/2 2
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
S 1 model
∂ t H + ∂ x Hu
= 0
∂ t (h α u α ) + ∂ x h α u 2 α + h α q α
+ U α+1/2 − U α−1/2 = −h α ∂ x (g η + p atm )
∂ t (h α w α ) + ∂ x (h α u α w α ) + W α+1/2 − W α−1/2 = 0
∂ t (h α σ α ) + ∂ x (h α σ α u α ) = 2 √ 3
q α − q α+1/2 + q α−1/2 2
−Υ α+1/2
h α ∂ x u α
12 + w e α+1/2 − w α 2
+ Υ α−1/2
h α ∂ x u α
12 + w α − w e α−1/2 2
∂ x u α + w α+1/2 − − w α
h α /2 = 0 σ α = − h α ∂ x u α
2 √ 3 w α−1/2 + − u α ∂ x z α−1/2 +
α−1
X
β=1
∂ x (h β u β ) = 0
S 1/2 model
∂ t H + ∂ x Hu
= 0
∂ t (h α u α ) + ∂ x h α u 2 α + h α q α
+ U α+1/2 − U α−1/2 = −h α ∂ x (g η + p atm )
∂ t (h α w α ) + ∂ x (h α u α w α ) + W α+1/2 − W α−1/2 = 0 q α = q α+1/2 + q α−1/2
2 + Υ α+1/2
H
4L (∂ ] x u) α+1/2 + w e α+1/2 − w α 2
− Υ α−1/2 H
4L (∂ ] x u) α−1/2 + w α − w e α−1/2 2
∂ x u α +
w α+1/2 − − w α
h α /2 = 0 σ α = − h α ∂ x u α
2 √ 3 w α−1/2 + − u α ∂ x z α−1/2 +
α−1
X
β=1
∂ x (h β u β ) = 0
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
S 0 model
∂ t H + ∂ x Hu
= 0
∂ t (h α u α ) + ∂ x h α u 2 α + h α q α
+ U α+1/2 − U α−1/2 = −h α ∂ x (g η + p atm )
∂ t (h α w α ) + ∂ x (h α u α w α ) + W α+1/2 − W α−1/2 = 0 q α = q α+1/2 + q α−1/2
2
w α − u α ∂ x z α +
α−1
X
β=1
∂ x (h β u β ) + 1
2 ∂ x (h α u α ) = 0
Energy inequality
Denoting K = u
2+w 2
2, smooth solutions to the Euler equations satisfy
∂ t
Z η z
bK + g η + z b
2 + p atm
dz
+ ∂ x
Z η z
bu(K + q + g η + p atm ) dz
= H∂ t p atm . Proposition
Let us assume that γ α+1/2 − 1 2
Υ α+1/2 ≥ 0. If (H, u α , w α , q α ) are smooth solutions to the S 1 -model, then with K α = u
2α+w 2
2α+σ
2α∂ t
" L X
α=1
h α K α + gz α + p atm
#
+ ∂ x
" L X
α=1
h α u α K α + q α + g η + p atm
#
≤ H∂ t p atm .
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Comment
Constraint γ α+1/2 − 1 2
Υ α+1/2 ≥ 0 is equivalent to taking
γ α+1/2 = 1
2 1 + λ sign(Υ α+1/2 ) for any λ ≥ 0, which gives
R e α+1/2 Υ α+1/2 = R α+1/2 + + R α+1/2 −
2 Υ α+1/2 − λ
2 |Υ α+1/2 |
R + α+1/2 − R α+1/2 −
.
The energy inequality is satisfied in particular for γ α+1/2 = 1 2 (λ = 0) and for
γ α+1/2 = 1 {Υ
α+1/2≥0} (λ = 1).
Hydrodynamic balances
Proposition
Let (H, u α , w α , q α+1/2 ) be smooth solutions to the S 1 model. Then
§ The conservation of global volume: ∂ t
Z
R
H(t, x) dx
= 0
§ The balance of horizontal momentum:
∂ t
Z
R
H(t, x)u(t , x ) dx
= − Z
R
H(t , x )∂ x p atm (t , x ) + gH(t, x) + q 1/2 (t, x)
∂ x z b (x) dx
§ The balance of vertical momentum:
∂ t
Z
R
H(t, x)w (t , x) dx
= − Z
R
q 1/2 (t , x ) dx
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion
Dispersion relations
Let us linearise around the so-called lake-at-rest steady state (H 0 , 0, 0, 0).
Proposition
There exists a plane wave solution
H, ˆ ˆ u α , w ˆ α , q ˆ α
e i(kx−ωt) to the linearised S 1
system provided the following dispersion relation holds
ω 2 = k 2 c sw 2 A −1 kH
0
e, ` where c sw = √
gH 0 , ` = (` 1 , . . . , ` L ) ∈ R L , e = (1, . . . , 1) ∈ R L and
A x = I L + x 2 B, with B αβ = − ` 2 α
6 δ αβ + ` β
` max{α,β}
2 +
L
X
γ=max{α,β}+1
` γ
Dispersion relations
Let us linearise around the so-called lake-at-rest steady state (H 0 , 0, 0, 0).
Proposition
There exists a plane wave solution
H, ˆ ˆ u α , w ˆ α , q ˆ α
e i(kx−ωt) to the linearised S 0
system provided the following dispersion relation holds
ω 2 = k 2 c sw 2 A −1 kH
0
e, ` where c sw = √
gH 0 , ` = (` 1 , . . . , ` L ) ∈ R L , e = (1, . . . , 1) ∈ R L and
A x = I L + x 2 B, with B αβ = − ` 2 α
4 δ αβ + ` β
` max{α,β}
2 +
L
X
γ=max{α,β}+1
` γ
1. Introduction 2. Derivation of the hierarchy of models 3. Energy 4. Linear wave analysis 5. Conclusion