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Riemann–Hilbert problem approach for two-dimensional flow inverse scattering
Alexey Agaltsov, Roman Novikov
To cite this version:
Alexey Agaltsov, Roman Novikov. Riemann–Hilbert problem approach for two-dimensional flow in-
verse scattering. Journal of Mathematical Physics, American Institute of Physics (AIP), 2014, 55 (10),
pp.103502. �hal-00939283�
two-dimensional ow inverse sattering
∗
A.D.Agaltsov 1
,R.G.Novikov 2
Abstrat
We onsider inverse sattering for the time-harmoni wave equa-
tionwithrst-order perturbation intwodimensions. This problem
arisesinpartiularin theaoustitomographyofmovinguid. We
onsider linearized and nonlinearizedreonstrution algorithms for
this problem of inverse sattering. Our nonlinearized reonstru-
tionalgorithm isbasedon thenon-loal RiemannHilbert problem
approah. Comparisonswithpreeding resultsaregiven.
Keywords: aoustitomography,movinguid,waveequationwith
rst-order perturbation, inverse sattering, RiemannHilbert prob-
lem.
1 Introdution
Weonsider theequation
− ∆ψ − 2iA(x) ∇ ψ + V (x)ψ = Eψ, x = (x
1, x
2) ∈ R
2, E > 0,
(1.1)where
∆ = ∂
x21+ ∂
x22,∇ = (∂
x1, ∂
x2)
,∂
xk= ∂/∂x
k,k = 1
,2
,andA = (A
1, A
2)
and
V
are vetor and salar potentials onR
2, respetively. In addition we assumethatA
1,A
2 andV
are suiently regular funtions onR
2with suientdeayatinnity.
(1.2)
Equation (1.1) anbe onsidered asa model equation for the time-harmoni
exp( − iωt)
aoustipressureψ
inatwo-dimensionalmovinguid,seee.g.[RW℄, [RE℄.InthissettingE = ω
c
0 2, A(x) = ω c
0u(x), V (x) = 1 − n
2(x) ω c
0 2,
(1.3)where
c
0 isareferenesoundspeed,n(x)
isasalarindexofrefration,u(x)
isanormalizeduidveloityvetor.
∗
ThemainpartoftheworkwasfullledduringthestageoftherstauthorintheCentre
deMathematiquesAppliqueesofEolePolytehniqueinOtoberDeember2013
1
119991,LomonosovMosowStateUniversity,FaultyofComputationalMathematisand
Cybernetis,Mosow,Russia;email: agaletsgmail.om
2
CNRS(UMR7641),CentredeMathematiques Appliquees,EolePolytehnique, 91128
Palaiseau, Frane; IEPTRAS, 117997, Mosow, Russia; Mosow Institute of Physis and
Tehnology,Dolgoprudny,Russia;email: novikovmap.polytehnique.fr
equationatxed energy
E
withmagnetipotentialA
andeletripotentialv
,where
V (x) = A
2(x) − i div A(x) + v(x)
= A
21(x) + A
22(x) − i
∂A
1(x)
∂x
1+ ∂A
2(x)
∂x
2+ v(x),
(1.4)
seee.g. [HN1℄,[ER2℄.
Forequation(1.1)weonsiderthelassialsatteringsolutions
ψ
+ontinu-ousandboundedon
R
2withtheirrstderivativesandspeiedbythefollowing asymptotisas| x | → ∞
:ψ
+(x, k) = e
ikx+ C( | k | ) e
i|k||x|| x |
1/2f
k, | k | x
| x |
+ o 1
| x |
1/2,
(1.5)x ∈ R
2, k ∈ R
2, k
2= E, C( | k | ) = − πi √
2πe
−iπ/4| k |
1/2,
where apriori unknownfuntion
f = f (k, l)
,k
,l ∈ R
2,k
2= l
2= E
, arisingin(1.5)isthelassialsatteringamplitudefor(1.1).
Given potentials
A
,V
, to determineψ
+ andf
one an use the followingLippmannShwingerintegralequation(1.6)andformula(1.8)(seee.g. [HN1℄):
ψ
+(x, k) = e
ikx+ Z
R2
G
+(x − y, k) ×
× − 2iA(y) ∇
yψ
+(y, k) + V (y)ψ
+(y, k) dy,
(1.6)
G
+(x, k) = − (2π)
−2Z
R2
e
iξxdξ
ξ
2− k
2− i0 = − i
4 H
01( | x || k | ),
(1.7)where
x ∈ R
2,k ∈ R
2,k
2= E
,H
01 istheHankelfuntionoftherstkind;f (k, l) = (2π)
−2Z
R2
e
−ily− 2iA(y) ∇
yψ
+(y, k) + V (y)ψ
+(y, k)
dy,
(1.8)where
k ∈ R
2,l ∈ R
2,k
2= l
2= E
. Atually, we onsider (1.6) and itsdierentiatedversion,where
∇
isappliedtobothsidedof(1.6),asasystemoflinearintegralequationsfor
ψ
+and∇ ψ
+.Oneanseethatthesatteringamplitude
f
forequation(1.1)at xedE
isdenedon
M
E=
k ∈ R
2, l ∈ R
2: k
2= l
2= E , E > 0.
(1.9)Notethat
f
onM
E isinvariantwithrespettothegaugetransformationsA → A + ∇ ϕ,
V → V − i∆ϕ + ( ∇ ϕ)
2+ 2A ∇ ϕ,
(1.10)
where
ϕ
isasuientlyregularfuntion onR
2withsuientdeayatinnity, seee.g. [HN2℄,[ER2℄. Inaddition,ψ
+ istransformedasψ
+→ e
−iϕψ
+ (1.11)Inthis work weonsider thefollowinginverse satteringproblem forequa-
tion(1.1)underassumptions(1.2):
Problem 1.1. Given satteringamplitude
f
onM
E at xedE > 0
, nd po-tentials
A
andV
onR
2 (atleastapproximately).Problem 1.1 for the ase when
A ≡ 0
wasstudied, in partiular, in [N1℄,[GM℄,[N3℄,[GN2℄,[N4℄, [BBMRS℄,[BAR℄andin [N2℄,[Buk℄.
Problem1.1 forthegeneralasewasonsidered,inpartiular, onpage457
of[N3℄andin[X℄.
Problem1.1isalsorelatedwithseveralotherinverseproblemsfortheShrodinger
equationinmagnetield(andforthetime-harmoniwaveequationwithrst-
orderperturbation)in dimension
d ≥ 2
. Conerning these otherinverseprob-lemssee[DKN℄,[Sh℄,[HN2℄,[Nor℄,[RW℄,[RE℄,[BBS℄,[ER1℄,[NSU℄,[A℄,[ER2℄,
[Ni℄,[WY℄,[GT℄,[IY℄andreferenestherein.
Notethatapproximatending
A
andV
inProblem1.1means,inpartiular,ndingmodulotransformations(1.10) . However,forreal-valued
A
andV
thereis no gauge nonuniqueness (1.10) in Problem 1.1! In addition,
A
andV
offormulas(1.3)(ofmovinguidaoustis)arerealif
n
isreal.Inthisworkwearemainlymotivatedbyappliationstotheaoustitomog-
raphyofmovinguiddisribedin [Nor℄,[RW℄,[RE℄, [BBS℄.Notethat intheir
reonstrution results works [Nor℄, [RW℄, [RE℄, [BBS℄ proeed from near-eld
sattering data (e.g. from some near eld information on
ψ
+) instead of thesatteringamplitude
f
. Butitisalsoknownthatnear-eldsatteringdataanbetransformedintovaluesof
f
,see e.g. [Ber℄,[BBS℄.Resultsofthepresentworkanbedesribedasfollows:
InSetion 2wegiveformulasforsolvingProblem1.1 inthe Bornapproxi-
mation. Toourknowledgethese formulaswerenotyet givenexpliitely in the
literaturefortheasewhen
A 6≡ 0
. Theseformulasareprovedin Setion5.In Setion 3wegive anonlinearizedreonstrution algorithm for Problem
1.1. For the ase when
A ≡ 0
this algorithm is redued to the algorithm of[N4℄and wasimplementednumerially in [BAR℄. Forthegeneral asethis al-
gorithmanbealsoregardedassimpliationanddevelopmentofthealgorithm
mentioned on page 457 of [N3℄ and based on the RiemannHilbertManakov
problemapproahof[GN1℄,[N1℄. Aderivationofthereonstrutionalgorithm
ofSetion3isgivenin Setion6.
InSetion4weshowthatin theBornapproximationthealgorithm ofSe-
tion3isreduedtoformulasofSetion2. RelatedproofsaregiveninSetion7.
Inasimilarwaywithresultsof[NS℄thereonstrutionalgorithmofSetion3
anbegeneralizedto themulti-hannelase. Thisgeneralizationwill begiven
inasubsequentwork.
InthepresentworkwearefousedonapproximatereonstrutionsforProb-
lem 1.1, admitting stable numerial implementation. Issues related with the-
orems of uniqueness and examples of nonuniqueness for Problem 1.1 will be
onsideredinasubsequentwork.
If
A = (A
1, A
2)
andV
satisfy(1.2)andare suientlysmall, thenproeedingfrom(1.6),(1.8)wehavethefollowingBornapproximationformulasfordiret
sattering:
ψ
+(x, k) ≈ e
ikx, ∇ ψ
+(x, k) ≈ e
ikxik, f (k, l) ≈ f
lin(k, l),
(2.1)
f
lin(k, l) == (2π)
def −2Z
R2
e
i(k−l)x2kA(x) + V (x)
dx,
(2.2)where
x
,k
,l ∈ R
2,k
2= l
2= E
. Inpartiular, formulas(2.1)anbespeiedas(2.14).
Notethat
f
linonM
E isinvariantwithrespettothegaugetransformationsA → A + ∇ ϕ, V → V − i∆ϕ,
(2.3)where
ϕ
isasuientlyregularfuntion onR
2withsuientdeayatinnity.This invariane follows from (2.2), (2.3), integrating by parts and using that
k
2− l
2= 0
. Weonsider(2.3)asalinearizationof (1.10)forsmallA
,V
andϕ
.Inthissetionweonsiderthefollowinglinearizedinversesatteringproblem
forequation(1.1)under assumptions(1.2) :
Problem2.1. Givenlinearizedsatteringamplitude
f
linonM
EatxedE > 0
,ndpotentials
A
andV
onR
2 (atleastapproximately).Notethatapproximatending
A
andV
inProblem2.1means,inpartiular,ndingmodulotransformations(2.3). However,inasimilarwaywithProblem
1.1, thereis nogaugenonuniqueness (2.3)in Problem 2.1 forthease ofreal-
valued
A
andV
.Problem2.1isalinearizationofProblem1.1.
TostudyProblem 2.1 itis onvenientto introdue
ϕ
div,A
div,0,V
div,0 andϕ
±,A
±,0,V
±,0suhthat:∆ϕ
div(x) = − div A(x), ϕ
div(x) → 0
as| x | → ∞ , A
div,0(x) = A(x) + ∇ ϕ
div(x), V
div,0(x) = V (x) − i∆ϕ
div(x),
(2.4)
where
x ∈ R
2;∂
zϕ
−(x) = − 1
2 (A
1(x) − iA
2(x)), ϕ
−(x) → 0
as| x | → ∞ , A
−,0(x) = A(x) + ∇ ϕ
−(x), V
−,0(x) = V (x) − i∆ϕ
−(x),
(2.5)
∂
¯zϕ
+(x) = − 1
2 (A
1(x) + iA
2(x)), ϕ
+(x) → 0
as| x | → ∞ , A
+,0(x) = A(x) + ∇ ϕ
+(x), V
+,0(x) = V (x) − i∆ϕ
+(x),
(2.6)
∂
z= 1
2 (∂
x1− i∂
x2), ∂
z¯= 1
2 (∂
x1+ i∂
x2), x = (x
1, x
2) ∈ R
2.
(2.7)Oneanseethat
div A
div,0(x) = 0, A
−1,0(x) − iA
−2,0(x) = 0, A
+,01(x) + iA
+,02(x) = 0,
where
x ∈ R
2,A
±,0= (A
±1,0, A
±2,0)
.Itisalsoonvenienttotransformformula(2.2)to theform
f
lin(k, l) − f
lin( − l, − k) = 2(k + l) A(k b − l),
f
lin(k, l) + f
lin( − l, − k) = 2(k − l) A(k b − l) + 2 V b (k − l),
(2.8)
A(p) = (2π) b
−2Z
R2
e
ipxA(x) dx, V b (p) = (2π)
−2Z
R2
e
ipxV (x) dx,
(2.9)where
(k, l) ∈ M
E,p ∈ R
2. Notethat(k, l) ∈ M
E= ⇒ k − l ∈ B
2√E,
p ∈ B
2√E= ⇒ p = k − l
forsome(k, l) ∈ M
E,
(2.10)
where
B
r= { p ∈ R
2: | p | ≤ r } , r > 0.
(2.11)Wedene
C
N,σ( R
2) =
u ∈ C
N( R
2) : k u k
N,σ< + ∞ , k u k
N,σ= max
|n|6N
sup
x∈R2
(1 + | x |
2)
σ/2| ∂
nu(x) | , N ∈ N ∪ { 0 } , σ > 0,
(2.12)where
C
N( R
2)
isthespaeofN
-timesontinouslydierentiableomplex-valued funtionsonR
2,∂
n= ∂
xn11∂
xn22, n = (n
1, n
2) ∈ N ∪ { 0 }
2, | n | = n
1+ n
2.
(2.13)Notethatif
A
1,A
2,V ∈ C
0,σ( R
2)
forsomeσ > 2
andk A
jk
0,σ≤ q
,j = 1
,2
,k V k
0,σ≤ q
, thenψ
+(x, k) = e
ikx+ O(q), ∇ ψ
+(x, k) = e
ikxik + O(q), f (k, l) = f
lin(k, l) + O(q
2)
asq → +0,
(2.14)
uniformlywithrepsetto
x
,k
,l ∈ R
2,k
2= l
2= E
,atxedE > 0
.Theorem 2.1. Suppose that
A
1,A
2,V
are real-valued andA
1,A
2,V ∈
C
N,σ( R
2)
for someN ≥ 3
,σ > 2
. Then the following formulas for solvingA(k b − l) = f
lin(k, l) − f
lin(l, k) 2
k − l
| k − l |
2+ f
lin(k, l) − f
lin( − l, − k) 2
k + l
| k + l |
2, V b (k − l) = f
lin(l, k) + f
lin( − l, − k)
2 ,
(2.15)where
A b
,V b
are denedby (2.9)and(k, l) ∈ M
E;A(x) = A
appr(x, E) + A
err(x, E), x ∈ R
2, E > 0, A
appr(x, E) =
Z
|p|≤2√ E
e
−ipxA(p) b dp, A
err(x, E) = Z
|p|≥2√ E
e
−ipxA(p) b dp,
(2.16)V (x) = V
appr(x, E) + V
err(x, E), x ∈ R
2, E > 0,
V
appr(x, E) = Z
|p|≤2√ E
e
−ipxV b (p) dp, V
err(x, E) = Z
|p|≥2√ E
e
−ipxV b (p) dp,
(2.17)where
A(p) b
andV b (p)
for| p | ≤ 2 √
E
aregiven intermsoff
lin onM
E aordingto (2.10), (2.15)and
| A
err,j(x, E) | ≤ c
1(N, σ) k A
jk
N,σE
−N2−2,
(2.18)| V
err(x, E) | ≤ c
1(N, σ) k V k
N,σE
−N2−2,
(2.19)where
x ∈ R
2,j = 1
,2
,A
err= (A
err,1, A
err,2)
,E ≥
14 andc
1(N, σ) = 4
(N − 2)(σ − 2) .
(2.20)Theorem2.2. Supposethat
A
1,A
2,V ∈ C
N,σ( R
2)
forsomeN ≥ 4
andσ > 2
.Let
A
div,0,V
div,0 bedenedaordingto (2.4). Thenthe followingformulas forsolvingProblem 2.1arevalid:
b
A
div,0(k − l) = f
lin(k, l) − f
lin( − l, − k) 2
k + l
| k + l |
2, V b
div,0(k − l) = f
lin(k, l) + f
lin( − l, − k)
2 ,
(2.21)
where
A b
div,0,V b
div,0 aretheFouriertransformsofA
div,0,V
div,0 (see (2.9))and(k, l) ∈ M
E;A
div,0(x) = A
div,0appr(x, E) + A
div,0err(x, E), x ∈ R
2, E > 0,
(2.22)A
div,0appr(x, E) =
Z
|p|≤2√ E
e
−ipxA b
div,0(p) dp, A
div,0err(x, E) = Z
|p|≥2√ E
e
−ipxA b
div,0(p) dp, V
div,0(x) = V
apprdiv,0(x, E) + V
errdiv,0(x, E), x ∈ R
2, E > 0,
(2.23)V
apprdiv,0(x, E) =
Z
|p|≤2√ E
e
−ipxV b
div,0(p) dp, V
errdiv,0(x, E) = Z
|p|≥2√ E
e
−ipxV b
div,0(p) dp,
where
A b
div,0(p)
andV b
div,0(p)
for| p | ≤ 2 √
E
are given in termsoff
lin onM
Eaording to(2.10) , (2.21)and
| A
div,0err,j(x, E) | ≤ (1 + √
2)c
1(N, σ) k A k
N,σE
−N−22,
(2.24)| V
errdiv,0(x, E) | ≤ c
1(N, σ)
k V k
N,σE
−N2−2+ √
2 k A k
N,σE
−N2−3,
(2.25)k A k
N,σ= max k A
1k
N,σ, k A
2k
N,σ,
(2.26)where
x ∈ R
2,j = 1
,2
,E ≥
14,A
div,0err= (A
div,0err,1, A
div,0err,2)
andc
1(N, σ)
isdenedby (2.20). Furthermore, if
div A = 0
thenA
div,0= A
,V
div,0= V
.Theorem2.3. Supposethat
A
1,A
2,V ∈ C
N,σ( R
2)
forsomeN ≥ 4
andσ > 2
.Let
A
±,0,V
±,0 bedenedaording to(2.5)(2.6). Then thefollowingformulas forsolving Problem 2.1arevalid:A b
±1,0(k − l) = 1 2
f (k, l) − f ( − l, − k)
k
1+ l
1± i(k
2+ l
2) , A b
±2,0(k − l) = ± i A b
±1,0(k − l), V b
±,0(k − l) = (l
1± il
2)f (k, l) + (k
1± ik
2)f ( − l, − k)
k
1+ l
1± i(k
2+ l
2) ,
(2.27)
where
A b
±,0,V b
±,0 are the Fourier transforms ofA
±,0,V
±,0 (see (2.9)) and(k, l) ∈ M
E;A
±,0(x) = A
±appr,0(x, E) + A
±err,0(x, E), x ∈ R
2, E > 0,
(2.28)A
±appr,0(x, E) =
Z
|p|≤2√ E
e
−ipxA b
±,0(p) dp, A
±err,0(x, E) = Z
|p|≥2√ E
e
−ipxA b
±,0(p) dp, V
±,0(x) = V
appr±,0(x, E) + V
err±,0(x, E), x ∈ R
2, E > 0,
(2.29)V
appr±,0(x, E) =
Z
|p|≤2√ E
e
−ipxV b
±,0(p) dp, V
err±,0(x, E) = Z
|p|≥2√ E
e
−ipxV b
±,0(p) dp,
where
A b
±,0(p)
andV b
±,0(p)
for| p | ≤ 2 √
E
are given in terms off
lin onM
Eaording to(2.10) , (2.27)and
| A
±err,j,0(x, E) | ≤ (1 + √
2)c
1(N, σ) k A k
N,σE
−N−22,
(2.30)| V
err±,0| ≤ c
1(N, σ)
k V k
N,σE
−N2−2+ √
2 k A k
N,σE
−N−23,
(2.31)where
x ∈ R
2,j = 1
,2
,A
±err,0= (A
±err,1,0, A
±err,2,0)
,k A k
N,σ is dened by (2.23)and
c
1(N, σ)
isgiven by (2.20). Furthermore, ifA
1± iA
2= 0
thenA = A
±,0,V = V
±,0.Theorems2.12.3areprovedin Setion5.
3.1. Some notations. Tostudy Problem1.1 itis onvenienttointrodue
ϕ
div,A
div,V
divandϕ
±,A
±,V
±,whereϕ
divandϕ
± aredenedaordingto(2.4)(2.6)and
A
div= A + ∇ ϕ
div, V
div= V − i∆ϕ
div+ ( ∇ ϕ
div)
2+ 2A ∇ ϕ
div, A
±= A + ∇ ϕ
±, V
±= V − i∆ϕ
±+ ( ∇ ϕ
±)
2+ 2A ∇ ϕ
±.
(3.1)
Inthis setion wegiveanonlinearizedalgorithm for approximate nding
A
±,V
± andA
div,V
div onR
2 fromf
onM
E. This algorithm takesinto aountmultiplesatteringeetsandanberegardedasanonlinearversionofformulas
for
A
±appr,0 ,V
appr±,0,
A
div,0appr ,V
apprdiv,0of (2.28),(2.29),(2.22),(2.23) .
Itisonvenienttousethefollowingnotations:
z = x
1+ ix
2, z ¯ = x
1− ix
2,
(3.2)λ = E
−1/2(k
1+ ik
2), λ
′= E
−1/2(l
1+ il
2),
(3.3)where
x = (x
1, x
2) ∈ R
2,k = (k
1, k
2) ∈ Σ
E,l = (l
1, l
2) ∈ Σ
E,Σ
E=
m = (m
1, m
2) ∈ C
2: m
21+ m
22= E , E > 0.
(3.4)Inthese notations
k
1= 1
2 E
1/2(λ + λ
−1), k
2= i
2 E
1/2(λ
−1− λ),
(3.5)l
1= 1
2 E
1/2(λ
′+ λ
′−1), l
2= i
2 E
1/2(λ
′−1− λ
′),
(3.6)exp(ikx) = exp
i
2 E
1/2(λ¯ z + λ
−1z)
,
(3.7)where
λ
,λ
′∈ C \ { 0 }
,z ∈ C
2,k
,l ∈ Σ
E.Inaddition,usingformulas(1.9),(3.3),(3.4),(3.5),(3.6)oneansee that
Σ
E∼ = C \ { 0 } , Σ
E∩ R
2= S
1√E
∼ = T, M
E∼ = T × T,
(3.8)
where
S
1r=
m ∈ R
2: | m | = r , r > 0, T =
λ ∈ C : | λ | = 1 .
(3.9)
Inaddition,thefuntions
ψ
+,f
of(1.5)(1.8)anbewritten asψ
+= ψ
+(z, λ, E), f = f (λ, λ
′, E),
(3.10)where
λ
,λ
′∈ T
,z ∈ C
,E > 0
.nding
A
±,V
± andA
div,V
div onR
2 fromf
onM
E hasthefollowingshemef −→ h
±−→ µ
+−→ µ
±−→ A
±appr, V
appr±−→ A
divappr, V
apprdiv(3.11)
andonsistsofthefollowingsteps:
Step1. Find funtions
h
±(λ, λ
′, E)
,λ
,λ
′∈ T
, from thefollowing linearintegralequations:
h
±(λ, λ
′, E) − πi Z
T
h
±(λ, λ
′′, E)χ
± i λ
λ
′′− λ
′′λ
×
× f (λ
′′, λ
′, E) | dλ
′′| = f (λ, λ
′, E),
(3.12)
where
χ(s) =
1
fors ≥ 0,
0
fors < 0
. (3.13)Step2. Solvethefollowinglinearintegralequationfor
µ
+(z, λ, E)
,z ∈ C
,λ ∈ T
,E > 0
:µ
+(z, λ, E) + Z
T
B(λ, λ
′, z, E)µ
+(z, λ
′, E) | dλ
′| = 1,
(3.14)where
B(λ, λ
′, z, E) = 1 2
Z
T
h
−(ζ, λ
′, z, E)χ
− i ζ
λ
′− λ
′ζ
dζ ζ − λ(1 − 0) −
− 1 2
Z
T
h
+(ζ, λ
′, z, E)χ
i ζ
λ
′− λ
′ζ
dζ
ζ − λ(1 + 0) ,
(3.15)h
±(λ, λ
′, z, E) ==
defh
±(λ, λ
′, E) ×
× exp
− i
√ E
2 (λ − λ
′)¯ z + (λ
−1− λ
′−1)z ,
(3.16)
and
λ
,λ
′∈ T
,z ∈ C
,E > 0
.Step3. Denefuntions
µ
±(z, λ, E)
,z ∈ C
,λ ∈ T
,E > 0
,byformulasµ
±(z, λ, E) = µ
+(z, λ, E) + πi
Z
T
h
±(λ, λ
′, z, E) ×
× χ
± i λ
λ
′− λ
′λ
µ
+(z, λ
′, E) | dλ
′| ,
(3.17)
where funtions
h
±(λ, λ
′, z, E)
are given by (3.16) andχ
is dened by(3.13).
Step4. Funtions
A
±appr,j(x, E)
,V
appr±(x, E)
,x ∈ R
2,j = 1
,2
,E > 0
, aredenedbyformulas
A
−appr,1(x, E) = i
4 a
−z(z, E ), A
−appr,2(x, E) = 1
4 a
−z(z, E), a
−z(z, E) = 4∂
z¯ln
Z
T
µ
+(z, ζ, E) | dζ | ,
V
appr−(x, E) =
√ E π
Z
T
∂
zµ
−(z, ζ, E) dζ,
(3.18)
and
A
+appr,1(x, E) = i
4 a
+z¯(z, E), A
+appr,2(x, E) = − 1
4 a
+¯z(z, E), a
+z¯(z, E) = − 4∂
zln
Z
T
µ
+(z, ζ, E) | dζ | ,
V
appr+(z, E ) = 2i √ E∂
z¯Z
T
µ
+(z, ζ, E) dζ ζ
2Z
T
µ
+(z, ζ, E) dζ ζ
,
(3.19)
where
z
isgivenby(3.2).Step5. Find
A
divappr,j(x, E)
,V
apprdiv(x, E)
,x ∈ R
2,j = 1
,2
,E > 0
,from formulasA
divappr,1(x, E) = i
8 (a
−z(z, E ) + a
+¯z(z, E)), A
divappr,2(x, E) = 1
8 (a
−z(z, E ) − a
+¯z(z, E)),
(3.20)V
apprdiv(x, E) = 1
2 V
appr−(x, E) + V
appr+(z, E)
− 1
8 a
−z(z, E)a
+¯z(z, E ),
where
z
isdenedby(3.2)andfuntionsa
−z,a
+z¯,V
appr±aredenedin(3.18),
(3.19).
Aderivationofthisreonstrutionalgorithmisbasedonthemethod ofthe
RiemannHilbert problem and on the
∂ ¯
-method. This derivation is given inSetion6.
For theasewhen
A ≡ 0
thisalgorithm isreduedtothealgorithmof[N4℄forapproximatiending
V
onR
2fromf
onM
E. Thealgorithmof[N4℄onsistsofthesameaforementionedsteps1,2,3andtheformula
V
appr= V
appr− ,whereV
appr−isdenedin (3.18). Thisalgorithmof[N4℄wasimplementednumerially
in[BAR℄.
Forthegeneralasethisalgorithmanbealsoregardedassimpliationand
development of the algorithm mentioned (in few lines) on page 457 of [N3℄.
Atually, in [N3℄ the part of the algorithm onsisting in nding
µ
± fromh
±mentionedfortheasewhen
A
1= A
1, A
2= A
2, − 2i div A + V = V,
(3.21)i.e. for theself-adjointase, whereasthis assumption is not neessaryfor the
algorithm.
3.3. Properties ofthe algorithm. Let
k u
1k
L2(T)= Z
T
| u
1(λ) |
2| dλ |
1/2,
k u
2k
L2(T2)= Z
T2
| u
2(λ, λ
′) |
2| dλ | | dλ
′|
1/2, T
2= T × T,
(3.22)
where
u
1andu
2aretestfuntions onT
andT
2,respetively.Proposition 3.1. Let
E > 0
be xed. Supposethatf ∈ L
2(T
2), k f k
L2(T2)< 1
π ,
(3.23)where
f = f (λ, λ
′, E)
.Thenequation(3.12)isuniquelysolvableforh
±∈ L
2(T
2)
and
k h
±k
L2(T2)< k f k
L2(T2)1 − π k f k
L2(T2),
(3.24)k B k
L2(T2)< 2π k f k
L2(T2)1 − π k f k
L2(T2),
(3.25)where
B
isdenedby(3.15), (3.16) (atxedz
,E
). In addition, ifk f k
L2(T2)< 1
3π ,
(3.26)then
k B k
L2(T2)< 1
, equation (3.14), at xedz
,E
, is uniquely solvable forµ
+∈ L
2(T )
andk µ
+k
L2(T)< (2π)
1/21 − k B k
L2(T2), k µ
+− 1 k
L2(T)< (2π)
1/2k B k
L2(T2)1 − k B k
L2(T2),
(3.27)k µ
±− 1 k
L2(T)< 3π(2π)
1/2k f k
L2(T2)1 − 3π k f k
L2(T2),
(3.28)where