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Second order sliding mode and adaptive observer for synchronization of a chaotic system: a comparative
study
Francisco J. Bejarano, Malek Ghanes, Jean-Pierre Barbot, Leonid Fridman
To cite this version:
Francisco J. Bejarano, Malek Ghanes, Jean-Pierre Barbot, Leonid Fridman. Second order sliding
mode and adaptive observer for synchronization of a chaotic system: a comparative study. IFAC
World Congress, Jul 2008, Séoul, North Korea. �inria-00345027�
observer for synhronization of a haoti
system: a omparative study
Franiso J.Bejarano
∗
Malek Ghanes
∗
Jean-Pierre Barbot
∗
LeonidFridman
∗∗
∗
EquipeCommande desSystèmes(ECS),ENSEA 6Avenue du
Poneau, 95014Cergy-Pontoise, Frane, (e-mail: {Franiso.Bejarano,
Malek.Ghanes, barbot}ensea.fr)
∗∗
NationalAutonomousUniversityof Mexio, EngineeringFaulty,
Divisionof Eletrial Engineering, UNAM04510, Méxio, D.F.,
(e-mail: lfridmanservidor.unam.mx)
Abstrat:
1. INTRODUCTION
2. PROBLEMSTATEMENT
Considerthefollowinghaotisystem
˙
x
1(t) = a(x
2(t) − x
1(t)) + x
2(t) x
3(t) + m
1(t)
˙
x
2(t) = b (x
1(t) + x
2(t)) − x
1(t) x
3(t)
˙
x
3(t) = − cx
3(t) − ex
4(t) + x
1(t) x
2(t) + m
1(t)
˙
x
4(t) = f x
3(t) − dx
4(t) + x
1(t) x
3(t) + m
2(t) y
1(t) = x
1(t)
y
2(t) = x
2(t)
(1)
where
x
i∈ R
(i = 1, 2, 3, 4
)arethe statesof thesystem;m
1 andm
2 representthe informationto be transmitted, whih for the observation problem are onsidered as theunknowninputs;
y
1andy
2aretheoutputsofthesystem,these arethesignalstobesentbyapublihannel.
Assumption. 2.1. The signals
m
1 andm
2 are assumedto be dierentiable, bounded and with the derivative
bounded.
Thegoalistoreonstrutthestates
x
3andx
4whihallowsto reonstrut the messages
m
1 andm
2. For ahievingsuh a goal two approahes are tested, namely, an ob-
serverbasedonthesuper-twistingalgorithmthatbasially
allows to obtain information from the derivatives of the
outputandonsequentlytoreonstrutthestatesandthe
messages(unknowninputs),and anadaptiveobserver.A
omparisonbetweenthesetwomethods willbedisussed.
Itshouldbenotiethatasingularityappearsinthepoint
x
1= 0
,thatis,fromtheoutputsx
1andx
2 isnotpossibletoknowthestates
x
3andx
4andonsequentlyneitherthe messagesm
1andm
2.3. SUPER-TWISTING OBSERVER
First in ordertogenerateanewoutput,namelythevari-
able
x
3,weusethesuper-twistingalgorithmfordesigning theobserverforx ˆ
3 in thefollowingway:
˙
x
a,1= b (x
1+ x
2) + v
1v
1= ˆ x
1,3+ λ
1| s
1|
1/2sign s ˆ
x
1,3= α
1sign s s
1= x
2− x
a,1(2)
Inthisway,thederivativeof
s
1 takestheform˙
s
1= − x
1x
3− v
1 (3)Choosingthegains
λ
1≥
(α1+M1−θ1)(1+θ)q
2 α1+M1
and
α
1>
M
1≥
dtd(x
1x
3)
(0 < θ < 1
), we get, aording to(Levant, 93), (Levant, 98), and (Davila, 05), the seond
orderslidingmotion,thatis,
s (t) = 0
,s ˙ (t) = 0
aftersomenite time
T
1. Notie that fors = 0
,v
1= ˆ x
3; therefore,from(3),weget
ˆ
x
1,3(t) ≡ − x
1(t) x
3(t)
(4)From (4) we an reonstrut
x
3(t)
providedx
1(t) 6 = 0
.Thus,theobserverfor
x
3 isdesignedin theformˆ x
3(t) =
− x ˆ
1,3(t)
x
1(t)
if| x
1(t) | ≥ ε ˆ
x
3(t − τ)
if| x
1(t) | < ε
(5)
where
τ
andε
areenoughsmallonstants1.Thus,wegettheidentity
ˆ
x
3(t) ≡ x
3(t)
for| x
1(t) | ≥ ε
.Reonstrution of
x
4 Now, deningy ¯
3(t) = x
3(t)
asa new output, we an rewrite the dynami equations in
(1)asalinearsystemwithoutputinjetionandunknown
inputs,thatis,
1
The onstant τ is hosen enough small but bigger than the sampling time used during the realization of the observer. The
onstantεshouldbehosensuientlybigtoavoidthesingularity, butalsoshouldbenotiethatanyestimationinthiszone annot
beonsideredasanaeptable estimation.
˙ x
1˙ x
2˙ x
3˙ x
4
=
-
a a 0 0 b b 0 0 0 0
-c
-e 0 0 f
-d
| {z }
A
x
1x
2x
3x
4
| {z }
x
+
y
2y ¯
3-
y
1y ¯
3y
1y
2y
1y ¯
3
| {z }
φ(y1,y2,¯y3)
+
1 0 0 0 1 0 0 1
| {z }
D
m
1m
2| {z }
w
" y
1y
2¯ y
3#
| {z }
¯ y
=
" 1 0 0 0 0 1 0 0 0 0 1 0
#
| {z } x
C
(6)
Now, let
z
be dened by the solution of the followingdierentialequation
z = Az + φ (y
1, y
2, y ¯
3)
Thus,dening
e
z= x − z
weobtainthedynamiequationfor
e
ze
z(t) = Ae
z(t) + Dw (t) y
z= Ce
z(7)
Hene, the system (7) is basially a linear system with
unknown inputs, just the sort of systems onsidered in
(Bejarano,07).Then,forthereonstrutionof
x
4wefollowin essene, but with a little modiation, the algorithm
proposed in (Bejarano, 07). That is, the basi idea pro-
posedin(Bejarano,07)istoobtainanalgebraiexpression
of
e
z in termsofthe outputy
z anditsderivatives.Thus, wegettheequalities2
y
z= Ce
zd
dt (CD)
⊥y
z= (CD)
⊥CAe
zthusweget
3
e
z(t) =
C
(CD)
⊥CA
+y
z(t) (CD)
⊥y
z(t)
(8)
Sine wealready know therst3 states,we solve(8) for
e
z,4,thefourthstateofe
z.Thus,e
z,4= 1
e [ ˙ e
z,1− e ˙
z,3+ a (e
z,1− e
z,2)
− ce
z,3+ e
z,1e
z,2− e
z,2e
z,3]
(9)
3.1 Realization ofthe observerusing super-twisting
To redue the fast dynami and have asmaller gains in
thesuper-twistingalgorithm,wedesignthefollowinglike-
linear estimator
x ˜
whose dynamis is governed by thefollowingdierentialequation
˜
x =
− c − e f − d
| {z }
A¯
˜ x +
y
1y
2y
1y ¯
3+ L (¯ y
3− y ˜
3)
˜
y
3= [ 1 0 ]
| {z }
C¯
˜ x
(10)
The matrix
L
is hosen so that the eigenvalues of the matrixA ¯ − L C ¯
havenegativerealpart.Inthis waywe
havethatthedynamiequationsfor
¯ e = ˜ x − x
3x
4are
2 Y⊥
isafullrowrankmatrixsuhthatY⊥Y = 0.
3
The matrix X+ isdened to be the pseudo-inverse of X. The matrixonsideredin(8)belongsto sortofmatriesoffullolumn
rank.Hene,insuhaase,X+= XTX
−1XT
.
¯
e (t) = A ¯ − LC
¯
e (t) + w (t)
where
w
isdenedin(6).Henewegetsomeupperboundsforthenormof
e ¯
andforthenormofe ¯
thatisk e ¯ (t) k ≤ γ exp ( − λt) k ¯ e (0) k + µ k w (t) k
γ
,λ
,µ
arepositiveonstantsThatis,withtheestimator(10),
e ¯
isonstrainedtostayedinazonedependingontheamplitudeof
m
1 andm
2;andthiszone anbemadesmallerbymovingtheeigenvalues
of
A ¯ − LC
moreto theleftin thelefthalf-plane.
Then, following the algebrai expression obtained in (9)
we design the observer for
x
4 using the super-twisting algorithmasfollows
˙ x
a,2= 1
e [a (x
2− x
1) + c x ˆ
3− x
1x
2+ x
2x ˆ
3] + ˜ x
4+ v
2v
2= v
2,1+ λ
2| s
2| sign s
2,v ˙
2,1= α sign s
2s
2= 1
e (x
1− x
3) − x
a,2ˆ x
4(t) =
x ˜
4+ v
2,1 if| x
1(t) | ≥ ε ˆ
x
4(t − τ)
if| x
1(t) | < ε
where
x ˜
4 istheseondomponentof thevetorx ˜
denedin(10).Then,thetimederivativeof
s
2 is˙
s
2= x
4− x ˜
4+ v
2Thus, for
λ
2≥
(α2+M1−θ2)(1+θ)q
2 α2+M2
and
α
2> M
2≥
dtd(x
4− x ˜
4)
(0 < θ < 1
), after some nite timeT
2, weget
s
2= 0
ands ˙
2= 0
;therefore,ˆ
x
4≡ x
4 for| x
1(t) | ≥ ε
.3.2 Messages reonstrution
Thereonstrution of
m
1ismadein thefollowingway
˙
x
a,3= a (x
2− x
1) + x
2x ˆ
3+ v
3v
3= v
3,1+ λ
3| s
3| sign s
3˙
v
3,1= α
3sign s
3ˆ m
1=
v
3,1 if| x
1(t) | ≥ ε ˆ
m
1(t − τ)
if| x
1(t) | < ε s
3= x
1− x
3aThus,for
α
3andλ
3satisfyingλ
3≥
(α3+M1−3θ)(1+θ)q
2 α3+M3and
α
3> M
3≥ | m ˙
1|
(0 < θ < 1
),after somenite time,we get the equalities
s
3= 0
,s ˙
3= 0
. Thus, we get theequality
ˆ
m
1≡ m
1, for| x
1(t) | ≥ ε
Thereonstrutionof
m
2ismadeinasimilarway,thatis,
˙
x
a,4= b (x
1+ x
2) + f x
3− dx
4+ v
4v
4= v
4,1+ λ
4| s
4| sign s
4˙
v
4,1= α
4sign s
4ˆ m
2=
v
4,1 if| x
1(t) | ≥ ε ˆ
m
2(t − τ)
if| x
1(t) | < ε s
4= x
2+ x
4− x
a,4Thus, taking into aount(1) and the derivativeof
x
a,4,withthehoosingof
α
4 andλ
4 satisfyingthe inequalitiesλ
4≥
(α4+M1−θ4)(1+θ)q
2 α4+M4
and
α
4> M
4≥ | m ˙
2|
(0 <
θ < 1
)(see,(Levant,93),(Levant,98)),weget,aftersomenitetime,
ˆ
m
2≡ m
2 for| x
1(t) | ≥ ε
mationofthestate
x
3,itissuientwithtousex
1(t) 6 = 0
instead of
| x
1(t) | ≥ ε
, but the justiation is given inthe following lines. It is known that during the realiza-
tion of the super-twisting algorithm
s
1 ands ˙
1 are notexatly zero, hene,instead of having (4) we really have
the equality
x ˆ
1,3(t) = − x
1(t) x
3(t) + ∆ (t)
, where∆
representstheestimation errorandwhihdoesnottends
tozero.Then,afterdividingover
x
1,ityieldstheequality¯
x
3:= −
ˆxx1,31= x
3−
x∆1, whih means that, when
x
1 isverylosetozero,theerrorbetween
x ¯
3 andx
3isequaltoO (1/x
1)
. Therefore, in a small neighborhood ofx
1= 0
,theerrorbetween
x ¯
3 andx
3 isextremelybig.Thisjustifythestrutureof
x ˆ
3.4. ADAPTIVEOBSERVER
Themodelofahaotisystem(1)anberewritteninthe
followinginteronnetedompatform
X ˙
1= A
1(y
2)X
1+ g
1(y, X
1, X
2) + φ
1(t) y
1= C
1X
1(11)
X ˙
2= A
2(y
1)X
2+ g
2(y, X
2, X
1) + φ
2(t) y
2= C
2X
2(12)
where
X
1= (x
1, x
3, x
4, x
5)
T is the state of the rstsubsystem with
x
5:= m
2,X
2= (x
2, x
3, x
6)
T is thestateoftheseond subsystemwith
x
6:= m
1.y = [x
1, x
2]
T aretheoutputofthewholesystem,and
A
1(y
2) =
0 y
20 0 0 0 − c 0 0 0 0 1 0 0 0 0
,A
2(y
1) =
0 − y
10 0 0 1 0 0 0
!
g
1(y, X
2, X
1) =
a(y
1− y
2) + x
6− ex
4+ y
1y
2+ x
6f x
3− dx
4+ y
1x
30
g
2(y, X
2, X
1) =
b(y
1+ y
2)
− cx
3− ex
4+ y
1y
20
!
φ
i(t) =
" 0 0
˙ m
i#
,
i = 1, 2
C
1= ( 1 0 0 0 )
,C
2= ( 1 0 0 )
.Remark. 4.1. The hoie of the variables of eah subsys-
tem hasbeen onsideredin order to separatein one sub-
systemthemessage
m
1 andintheother onethemessagem
2. It is lear that other hoie an be onsidered inordertorepresentthesesubsystemsprovidedtheneessary
onditionstodesignanadaptivearesatised.
Next, let us introdue an adaptive observer in order to
estimatethesystem'sstateandtheunknowninputssimul-
taneously. It is basedon interonnetion betweenseveral
subsystemswhihsatises somerequiredproperties, suh
that thepropertyof inputspersisteny((Hammouri, 90),
(Ghanes, 06)).
Atrst,letusintroduethefollowingassumptionsinorder
to establishthe results onerning the adaptiveobserver
1. The signals
X
1 andX
2 are assumed bounded andto be regularly persistent ((Hammouri, 90), (Ghanes,
06)) in order to guarantee the observability property of
subsystems(11)and(12),respetively.
2.
A
1(y
2)
andA
2(y
1)
areuniformly bounded.3.
g
1(y, X
1, X
2)
is globally Lipshitz with respet toX
2anduniformlywithrespetto
(y, X
1)
.4.
g
2(y, X
2, X
1)
isgloballyLipshitzwithrespetX
1 anduniformlywithrespetto
(y, X
2)
.5.Theunknownfuntions
m ˙
i(t)
(i = 1, 2
)areassumedtobebounded.
Then,anadaptiveobserverforinteronnetedsubsystems
(11)and(12)estimatingthestateand unknownparame-
tersisgivenby
Z ˙
1= A
1(y
2)Z
1+ g
1(y, Z
1, Z
2) + S
1−1C
1T(y
1− y ˆ
1) S ˙
1= − θ
1S
1− A
T1(y
2)S
1− S
1A
1(y
2) + C
1TC
1ˆ
y
1= C
1Z
1(13)
Z ˙
2= A
2(y
1)Z
2+ g
2(y, Z
2, Z
1) + S
2−1C
2T(y
2− y ˆ
2) S ˙
2= − θ
2S
2− A
T2(y
1)S
2− S
2A
2(y
1) + C
2TC
2ˆ
y
2= C
2Z
2(14)
where
Z
1= (ˆ x
1, x ˆ
3, x ˆ
4, x ˆ
5)
T;Z
2= (ˆ x
2, x ˆ
3, x ˆ
6)
TS
i= S
iT> 0
,i = 1, 2
. Note thatS
1−1C
1T andS
2−1C
2T are thegainsoftheobservers(13)and(14),respetively.
Remark. 4.2. Itisworthnotiingthat
k S
1k
andk S
2k
areboundedfor
θ
1andθ
2largeenoughduetothepersistenyofinputonsideredinassumption4.1.
Now, in order to guarantee the onvergene of the pro-
posedobserver,suientonditionsareestablishedinthe
followingresult.Denotetheestimationerrors:
ǫ
1= X
1− Z
1 andǫ
2= X
2− Z
2whosedynamisaregivenby
ǫ ˙
1= [A
1(y
2) − S
1−1C
1TC
1]ǫ
1+g
1(y, X
1, X
2) − g
1(y, Z
1, Z
2) + φ
1(t)
(15)ǫ ˙
2= [A
2(y
1) − S
2−1C
2TC
2]ǫ
2+g
2(y, X
2, X
1) − g
2(y, Z
2, Z
1) + φ
2(t)
. (16)Thevaluesof
θ
1andθ
2 arehosentosatisfytheinequali-ties
δ
1= (θ
1− Γη) > 0
,δ
2= (θ
2− Γ
η ) > 0
(17)where
Γ = ˜ µ
1+ ˜ µ
2,
withµ ˜
i= √
µiλmin(S1)
√
λmin(S2)
, i = 1, 2;
andµ
1= k
1k
2,µ
2= k
3k
4,η ∈ ]0, 1[
.The parameters
k
1, k
2, k
3,k
4 are positive onstants andλ
min(S
1), λ
min(S
2)
aretheminimaleigenvaluesofS
1andS
2 respetively.Lemma 4.1. Consider the system (13)-(14) and that as-
sumption4.1holds.Then,thesystem(13)-(14)isaprati-
alexponentialobserverforsystem(11)-(12)for
θ
1andθ
2satisfyingtheinequalities(17).Furthermore,theobserver
onvergesarbitrarilyfastwithaonvergeneratexedby
aparameter
δ
,δ = min(δ
1, δ
2)
.Skethofproof 4.1. ConsiderthefollowingLyapunovfun-
tionandidate:
V
o= V
1+ V
2where
V
1= ǫ
T1S
1ǫ
1andV
2= ǫ
T2S
2ǫ
2.k S
1k ≤ k
1;k{ g
1(y, X
1, X
2) − g
1(y, Z
1, Z
2) }k ≤ k
2k ǫ
2k
;k S
2k ≤ k
3;k{ g
2(y, X
2, X
1) − g
2(y, Z
2, Z
1) }k ≤ k
4k ǫ
1k
.k φ
1k ≤ k
5.k φ
2k ≤ k
6.Computingthetimederivativeof
V
o,,byusingtheaboveinequalitiesitfollowsthat
V ˙
o≤ − θ
1ǫ
T1S
1ǫ
1+ 2µ
1k ǫ
1k k ǫ
2k + k φ
1k
(18)− θ
2ǫ
T2S
2ǫ
2+ 2µ
2k ǫ
2k k ǫ
1k + k φ
2k
Now,onsider thatthefollowinginequalitiesaresatised
λ min(S
i) k ǫ
ik
2≤ k ǫ
ik
2Si≤ λ max(S
i) k ǫ
ik
2, i = 1, 2.
Bywriting(18)intermsoffuntions
V
1 andV
2,itfollowsthat
V ˙
o≤ − θ
1V
1− θ
2V
2+ 2(˜ µ
1+ ˜ µ
2) p V
1p V
2+ k
5+ k
6wheretheparameters
µ ˜
1,µ ˜
2,aredenedjustbeforelemma4.1.
Next,byusingthefollowinginequality
√ V
1√
V
2≤
υ2V
1+
1
2υ
V
2,∀ υ ∈ ]0, 1[
,one getV ˙
o≤ − (θ
1− Γ)V
1− (θ
2− Γ
υ )V
2+ k
5+ k
6.
where
Γ
isdenedjust before lemma4.1.Bytaking
δ
andr
suhthatδ = min(δ
1, δ
2)
andr = k
5+k
6one has
V ˙
o≤ − δV
o+ r.
(19)Finally, by hoosing
θ
1 andθ
2 suh that the inequalities (17)aresatisedandsuientlylarge,theinequality(19)showsthatarbitrarilyboundedperturbationwillnotresult
in largeerrorestimationdeviations.Thisendstheproof.
5. NUMERICALEXAMPLEANDDISCUSSIONS
Forthesystem(1)weusetheparameters
a = 42.5
,b = 24
,c = 13
,d = 20
,e = 50
,f = 40
.Theparametersused forthesuper-twistingobserverare
α
1= 7 × 10
7,λ
1= 7 × 10
3,α
2= 300
,λ
2= 100
,α
3= 1000
,λ
3= 200, α
4= 600
,λ
4= 300
.Forthe adaptiveobservertheparametersusedare
θ
1= θ
2= 400
.Figures1and2showthetrajetoriesofthestates
x
3andx
4 as well as the ones ofx ˆ
3 andx ˆ
4 for both the super-twisting and the adaptive observers. We an see in the
guresthatthetrajetoriesofthesuper-twistingobserver
onverge muh faster than the ones of the adaptive ob-
server.
Figures 3 and 4show themessages
m
1 andm
2 togetherwith their estimations
m ˆ
1 andm ˆ
2, respetively. In this gures we note that the singularity in the pointx
1= 0
aets more the estimation of the messages made with
the super-twisting than the one made with the adaptive
observer.This is leardue to the explanationof Remark
3.1 and the fat that, in a ball of radio
ε
and enter inx
1= 0
, it is not done a estimation neither of the statesnorofthemessages.
Inordertotestbothobserverswithrespettoparameters
unertainties,weintrodueavariationof1%in thenomi-
0 2 4 6 8 10
−400
−200 0 200 400 600 800
Time [s]
0 0.02 0.04 0.06 0.08
−1 0 1
Fig.1.
x
3(solidline)anditsestimationˆ x
3usingthesuper-twisting(dot line)andadaptive(dashline)observers
0 2 4 6 8 10
−400
−200 0 200 400 600 800
Time [s]
0 0.05
0 0.5 1 1.5
Fig.2.
x
4(solidline)anditsestimationˆ x
4usingthesuper-twisting(dot line)andadaptive(dashline)observers
unertainties aetsthebehaviorofthe observers.Inthe
ase of the adaptive observerthe parameter unertainty
destroyompletelytheestimationofthemessages.Never-
theless,nomatter what observeis used, in this ase,the
estimationofthemessagesanbeonsiderunaeptable.
Remark. 5.1. Forthesuper-twistingobserverwedosome
simulations with
x ˜ = 0
, that is without using a linearestimator.Inthesimulations,notshownhere,weobtained
abiggererrorintheestimationof
x
4whihhadabigeetin the error of the estimation of
m
2. It was due to thefat that using
x ˜ = 0
, the variable to be estimated withthesuper-twistingalgorithmbeame muh faster andfor
having an aeptable estimation the sampling step must
beredueonsiderably.
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0 2 4 6 8 10
−200
−150
−100
−50 0 50 100 150 200 250
Time [s]
0 0.1 0.2
0 20 40 60
Fig.3.Message
m
1(solidline)anditsestimationm ˆ
1usingthesuper-twisting(dot line)andadaptive(dashline)
observers
0 2 4 6 8 10
−150
−100
−50 0 50 100 150
Time [s]
0 0.2 0.4
0 20 40
Fig.4.Message
m
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2usingthesuper-twisting(dot line)andadaptive(dashline)
observers
0 2 4 6 8 10
−200
−100 0 100 200
0 2 4 6 8 10
−2000 0 2000 4000
Time [s]
Fig.5.Message
m
1(solidline)anditsestimationm ˆ
1(dotline) for the system with
1%
of unertainty in theparameters.Abovewith thesuper-twistingobserver,
belowwiththeadaptiveobserver
0 2 4 6 8 10
−100 0 100 200
0 2 4 6 8 10
−2
−1 0 1 2x 104
Time [s]
Fig.6.Message
m
2 (solidline)anditsestimationm ˆ
2 (dotline) for the system with
1%
of unertainty in theparameters.Abovewiththe super-twistingobserver,
belowwiththeadaptiveobserver
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