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Malliavin calculus for stochastic differential equations driven by a fractional Brownian motion
David Nualart, Bruno Saussereau
To cite this version:
David Nualart, Bruno Saussereau. Malliavin calculus for stochastic differential equations driven by
a fractional Brownian motion. Stochastic Processes and their Applications, Elsevier, 2009, 119 (2),
pp.391-409. �10.1016/j.spa.2008.02.016�. �hal-00485648�
Malliavin calculus for stochastic differential equations driven by a fractional Brownian
motion.
David Nualart
∗Department of Mathematics
University of Kansas Lawrence, Kansas, 66045, USA
Bruno Saussereau
D´ epartement de Math´ ematiques Universit´ e de Franche-Comt´ e
16, Route de Gray 25030 Besan¸con, France October 26, 2006
1 Introduction
Let B = {B
t, t ≥ 0} be an m−dimensional fractional Brownian motion (fBm in short) of Hurst parameter H ∈ (0, 1). That is, B is a centered Gaussian process with the covariance function E (B
siB
tj) = R
H(s, t)δ
ij, where
R
H(s, t) = 1
2 t
2H+ s
2H− |t − s|
2H. (1)
If H =
12, B is a Brownian motion. From (1), it follows that E |B
t− B
s|
2= m|t − s|
Hso the process B has α-H¨ older continuous paths for all α ∈ (0, H).
We refer to [11] and references therein for further information about fBm and stochastic integration with respect to this process.
In this article we fix
12< H < 1 and we consider the solution {X
t, t ∈ [0,T ]}
of the following stochastic differential equation on R
dX
ti= x
i0+
m
X
j=1
Z
t 0σ
ij(X
s)dB
sj+ Z
t0
b
i(X
s)ds , t ∈ [0,T ] , (2)
i = 1, . . . , d, where x
0∈ R
dis the initial value of the process X .
∗Partially supported by the NSF Grant DMS 0604207
The stochastic integral in (2) is a path-wise Riemann-Stieltjes integral (see Young [15]). Suppose that σ has bounded partial derivatives which are H¨ older continuous of order λ >
H1−1, and b is Lipschitz, then there is a unique solution to Equation (2) which has H¨ older continuous trajectories of order H − ε, for any ε > 0. This result has been proved by Lyons in [6] in the case b = 0, using the p-variation norm. The theory of rough paths analysis introduced by Lyons in [7] was used by Coutin and Qian to prove an existence and uniqueness result for Equation (2) in the case H ∈ (
14,
12) (see [2]).
The Riemann-Stieltjes integral appearing in Equation (2) can be expressed as a Lebesgue integral using a fractional integration by parts formula (see Z¨ ahle [16]). Using this formula for the Riemann-Stieltjes integral, Nualart and R˘ a¸scanu have established in [12] the existence of a unique solution for a class of general differential equations that includes (2).
The main purpose of our work is to study the regularity of the solution to Equation (2) in the sense of Malliavin calculus, and to show the absolute continuity for the law of X
tfor t > 0, assuming an ellipticitity condition on the coefficient σ. First we establish a general result on the regularity with respect to the driven function for the solution of deterministic equations, using the techniques of fractional calculus developed in [12]. This allows us to deduce the differentiability of the solution to Equation (2) in the direction of the Cameron- Martin space. These results are related to those proved by Lyons and Dong Li in [8] on the smoothness of Itˆ o maps for such equations in term of Fr´ echet-Gˆ ateaux differentiability.
The regularity results obtained here have been used in a recent paper by Bau- doin and Hairer [1] to show the smoothness of the density under a hypoellipticity H¨ ormander’s condition. This result requires also the existence of moments for the iterated derivatives, which has been established in [4]. In [9], the existence of a density for the solution of a one-dimensional equation is shown.
The paper is organized as follows. In Section 2 we establish the Fr´ echet differentiability with respect to the input function for deterministic differential equations driven by H¨ older continuous functons. Section 3 is devoted to analyze stochastic differential equations driven by a fBm with Hurst parameter H ∈ (
12, 1), the main result being the differentiability of the solution in the directions of the Cameron-Martin space. In Section 4 we prove the absolute continuity of the solution under ellipticity assumptions. The proofs of some technical results are given in the Appendix.
2 Deterministic differential equations driven by rough functions
We first introduce some preliminaries. Given a measurable function f : [0,T ] → R
dand α ∈ (0,
12), we will make use of the notation
∆
αt(f ) = |f (t)| + Z
t0
|f (t) − f (s)|
|t − s|
α+1ds.
We denote by W
1α(0, T ; R
d) the space of measurable functions f : [0,T ] → R
dsuch that
kf k
α,1:= sup
t∈[0,T]
∆
αt(f ) < ∞ .
For any 0 < λ ≤ 1, denote by C
λ(0, T ; R
d) the space of λ-H¨ older continuous functions f : [0,T ] → R
d, equipped with the norm
kf k
λ:= kf k
∞+ sup
0≤s<t≤T
|f (t) − f (s)|
(t − s)
λ,
where kf k
∞:= sup
t∈[0,T]|f (t)|. We denote by W
21−α(0, T ; R
m) the space of measurable functions g : [0,T ] → R
msuch that
kgk
1−α,2:= sup
0≤s<t≤T
|g(t) − g(s)|
(t − s)
1−α+ Z
ts
|g(y) − g(s)|
(y − s)
2−αdy
< ∞ . Clearly for any ε > 0 such that 1 − α+ ε ≤ 1 we have
C
α+ε(0,T ; R
d) ⊂ W
1α(0, T ; R
d) and
C
1−α+ε(0, T ; R
m) ⊂ W
21−α(0, T ; R
m) ⊂ C
1−α(0, T ; R
m) . For d = m = 1 we simply write W
1α(0, T ), C
λ(0,T ), and W
21−α(0, T ).
Suppose that g ∈ W
21−α(0, T ) and f ∈ W
1α(0, T ). In [16], Z¨ ahle introduced the generalized Stieltjes integral
Z
T 0f
tdg
t= (−1)
αZ
T0
D
α0+f
(t) D
1−αT−g
T−(t)dt, (3)
defined in terms of the fractional derivative operators D
α0+f(x) = 1
Γ(1 − α) f (x)
x
α+ α Z
x0
f (x) − f (y) (x − y)
α+1dy
, and
D
Tα−g
T−(x) = (−1)
αΓ(1 − α)
g(x) − g(T ) (T − x)
α+ α
Z
T xg(x) − g(y) (x − y)
α+1dy
! . We refer to [13] for further details on fractional operators. Z¨ ahle proved that if f ∈ C
α+ε(0, T ), then this integral coincides with the Riemann-Stieltjes integral, which exists by the results of Young (see [15]). Using formula (3), Nualart and R˘ a¸scanu have derived the following estimates (see [12], Propositions 4.1 and 4.3).
Proposition 1 Fix 0 < α <
12. Given two functions g ∈ W
21−α(0, T ) and f ∈ W
1α(0, T ), we denote G
t(f ) = R
t0
f
sdg
sand F
t(f ) = R
t 0f
sds.
(i) The function G(f ) belongs to C
1−α(0, T ) and we have
∆
αt(G(f )) ≤ c
α,Tkgk
1−α,2Z
t0
(t − r)
−2α+ t
−α∆
αr(f )dr , (4)
kG(f )k
1−α≤ c
α,Tkgk
1−α,2kf k
α,1, (5)
with a constant c
α,Twhich depends only on α and T . (ii) The function F (f ) belongs to C
1(0, T ) and moreover
∆
αt(F (f )) ≤ c
α,TZ
t 0|f
s|
(t − s)
αds , (6)
kF (f )k
1≤ c
Tkf k
∞, (7) with a constant c
α,Twhich depends only on α and T .
We first study deterministic differential equations driven by H¨ older con- tinuous functions of order stricktly larger that
12. Fix 0 < α <
12. Let g ∈ W
21−α(0, T ; R
m) and consider the deterministic differential equation on R
dx
it= x
i0+ Z
t0
b
i(x
s)ds +
m
X
j=1
Z
t 0σ
ij(x
s)dg
sj, t ∈ [0,T ] , (8) i = 1, . . . , d, where x
0∈ R
d.
For any integer k ≥ 1 we denote by C
bkthe class of real-valued functions on R
dwhich are k times continuously differentiable with bounded partial deriva- tives up to the kth order. We also denote by C
b∞the class of infinitely differen- tiable functions on R
dwith bounded partial derivatives of all orders.
In [12], the authors prove that Equation (8) has a unique solution x ∈ W
1α(0, T ; R
d) which is moreover (1 − α)-H¨ older continuous, if b
i, σ
ij∈ C
b1and the partial derivatives of σ
ijare H¨ older contiuous of order λ >
H1− 1.
In this section we will show the differentiability of the mapping g → x(g).
For a function ϕ from R
pto R , we set ∂
kϕ =
∂x∂ϕx
.
The first setp is to establish the existence and uniqueness of a solution for linear equations that are generalizations of (8). The iterated derivatives of the solution of Equation (8) satisfy these kind of equations.
Proposition 2 Fix g ∈ W
21−α(0, T ; R
m) and consider the following linear equa- tion:
y
t= w
t+ Z
t0
B
sy
sds + Z
t0
S
sy
sdg
s, (9)
where w ∈ C
1−α(0, T ; R
d), S ∈ C
1−α(0, T ; R
d×d×m) and B ∈ C
1−α(0, T ; R
d×d).
There exists a unique solution y ∈ C
1−α(0, T ; R
d) of Equation (9) which satisfies kyk
α,1≤ c
1kwk
α,1exp
c
2kgk
1 1−2α
1−α,2
(kBk
∞+ kSk
1−α)
, (10)
where c
1and c
2depend only on α and T .
Proof. The existence and uniqueness of a solution can be established fol- lowing the same lines as in the proof of Theorem 5.1 of [12]. Let us prove the estimate (10). Set F
tB= R
t0
B
sy
sds and G
St= R
t0
S
sy
sdg
s. Using (4) we have
∆
αt(G
S) ≤ c
α,Tkgk
1−α,2Z
t0
(t − s)
−2α+ s
−α∆
αs(Sy)ds
≤ c
α,Tkgk
1−α,2Z
t0
(t − s)
−2α+ s
−α|y
s|
× Z
s0
kSk
1−α(s − r)
1−α(s − r)
α+1dr
ds
+ kSk
1−αZ
t 0(t − s)
−2α+ s
−α∆
αs(y)ds
!
≤ c
α,Tkgk
1−α,2kSk
1−αZ
t0
(t − s)
−2α+ s
−α∆
αs(y)ds, where the constant c
α,Tmay vary from line to line but depends only on α and T. On the other hand, using (6) we get
∆
αt(F
B) ≤ c
α,TkBk
∞Z
t0
|y
s| (t − s)
αds . Then the above inequalities yield that
∆
αt(y) ≤ kwk
α,∞+ c
α,T(Λ
α(g) kSk
1−α+ kBk
∞) Z
t0
(t − s)
−2α+ s
−αh
sds . Applying a Gronwall-type Lemma (see Lemma 7.6 in [12]) we derive the estimate (10).
The following technical lemma is a basic ingredient in the proof of the Fr´ echet differentiability of the mapping x → x(g), where x is the solution of Equation (8).
Lemma 3 Let x be the solution of (8). Assume b
i, σ
ij∈ C
b3. Then the mapping F : W
21−α(0, T ; R
m) × W
1α(0, T ; R
d) → W
1α(0, T ; R
d)
defined by
(h, x) 7→ F (h, x) := x − x
0− Z
·0
b(x
s)ds − Z
·0
σ(x
s)d(g
s+ h
s) (11)
is Fr´ echet differentiable and we have for any (h, x) ∈ W
21−α(0, T ; R
m)×W
1α(0, T ; R
d),
k ∈ W
21−α(0, T ; R
m), v ∈ W
1α(0, T ; R
d), and i = 1, . . . , d D
1F(h, x)(k)
it= −
m
X
j=1
Z
t 0σ
ij(x
s)dk
sj, (12)
D
2F (h, x)(v)
it= v
it−
d
X
k=1
Z
t 0∂
kb(x
s)v
skds −
d
X
k=1 m
X
j=1
Z
t 0∂
kσ
ij(x
s)v
ksd(g
sj+ h
js).
(13)
Proof. For (h, x) and (˜ h, x) in ˜ W
21−α(0, T ; R
m) × W
1α(0, T ; R
d) we have F (h, x)
t− F (˜ h, x) ˜
t= x
t− x ˜
t+
Z
t 0(b(x
s) − b(˜ x
s)) ds
− Z
t0
(σ(x
s) − σ(˜ x
s)) (g
s+ h
s) − Z
t0
σ(˜ x
s)(h
s− h ˜
s).
Using Proposition 1 one easily deduce that
F(h, x) − F (˜ h, x) ˜
α,1≤ (1 + c
α,Tk∂bk
∞) kx − ˜ xk
α,∞+ c
α,Tkg + hk
1−α,2kσ(x) − σ(˜ x)k
α,∞+ c
α,Tkσ(x)k
α,∞h − ˜ h
1−α,2
.
Since σ is a Lipschitz function we have kσ(x)k
α,1≤ |σ(0)|+k∂σk
∞kxk
α,1. Using the fact that for any x
1, x
2, x
3and x
4:
|σ(x
1) − σ(x
2) − σ(x
3) + σ(x
4)| ≤ k∂σk
∞|x
1− x
2− x
3+ x
4|
+ k∂
2σk
∞|x
1− x
3| (|x
1− x
2| + |x
3− x
4|) , it follows that
kσ(x) − σ(˜ x)k
α,1≤ k∂σk
∞+ k∂
2σk
∞(kxk
α,1+ k xk ˜
α,1)
kx − xk ˜
α,1. Consequently, there exists a constant C depending on α, T and the coefficients b and σ such that
F (h, x) − F (˜ h, x) ˜
α,1≤ (1 + C (kxk
α,1+ k˜ xk
α,1) kg + hk
1−α,2) kx − xk ˜
α,1+C(1 + kxk
α,1) kh − ˜ hk
1−α,2, which implies that F is continuous.
We now prove that it is differentiable with respect to x. Thanks to Propo- sition 1, it holds that D
2F defined in (13) satisfies
kD
2F (h, x)(v)k
α,1≤ c kvk
α,1,
and, therefore, it is continuous. Let us now check that for any h ∈ W
21−α(0, T ; R
m), D
2F is the Fr´ echet derivative (with respect to x) of (h, x) 7→ F (h, x). We have
F (h, x + v)
t− F(h, x)
t− D
2F (h, x)(v)
t= Z
t0
(b(x
s) − b(x
s+ v
s) + ∂b(x
s)v
s) ds +
Z
t 0(σ(x
s) − σ(x
s+ v
s) + ∂σ(x
s)v
s) d(g
s+ h
s). (14) By the mean value theorem we can write
|b(x
s) − b(x
s+ v
s) + ∂b(x
s)v
s| ≤ k∂
2bk
∞|v
s|
2and thanks to (7) one easily remarks that
Z
· 0(b(x
s) − b(x
s+ v
s) + ∂b(x
s)v
s) ds
1≤ c
α,Tk∂
2bk
∞kvk
2α,1. Similar computations for the second term of the right hand side of (14) yield
Z
· 0(σ(x
s) − σ(x
s+ v
s) + ∂σ(x
s)v
s) d(g
s+ h
s)
α,1≤ c
α,Tk∂
2σk
∞+ k∂
3σk
∞kxk
α,1kg + hk
1−α,2kvk
2α,1. Thus it follows that
kF(h, x + v) − F (h, x) − D
2F (h, x)(v)k
α,1≤ C kg + hk
1−α,2kvk
2α,1, where C depends on α, T , k∂
2bk
∞, k∂
2σk
∞, k∂
3σk
∞and kxk
α,1. Then (h, x) 7→
F(h, x) is Fr´ echet differentiable with respect to x and (13) holds. Similar argu- ments give the differentiability with respect to h and Formula (12).
Proposition 4 Let x be the solution of Equation (8). Assume b
i, σ
ij∈ C
b3. The mapping g → x(g) from W
21−α(0, T ; R
m) into W
1α(0, T ; R
d) is Fr´ echet differentiable and for any h ∈ W
21−α(0, T ; R
m) its derivative in the direction h is given by
D
hx
it=
m
X
j=1
Z
t 0Φ
ijt(s)dh
js, (15)
where for i = 1, . . . , d, j = 1, . . . , m, 0 ≤ s ≤ t ≤ T , s 7→ Φ
ijt(s) satisfies:
Φ
ijt(s) = σ
ij(x
s) +
d
X
k=1
Z
t s∂
kb
i(x
u)Φ
k,ju(s)du +
d
X
k=1 m
X
l=1
Z
t s∂
kσ
il(x
u)Φ
k,ju(s)dg
ul,
(16)
and Φ
ijt(s) = 0 if s > t.
Proof. We apply the implicit function theorem to the functional F defined by (11) in Lemma 3. For any (h, x), F (h, x) belongs to C
1−α(0, T ; R
d) thanks to Proposition 1. Since x is a solution of (8), one remarks that F (0, x) = 0. Thanks to Lemma 3, the mapping F is Fr´ echet differentiable with first partial derivatives with respect to h given by (12) and the first partial derivative with respect to x is given by (13). We have to check that D
2F (0, x) is a linear homeomorphism from W
1α(0, T ; R
d) to C
1−α(0, T ; R
d). By the open map theorem it suffices to show that it is bijective and continuous. We apply Proposition 2 with t 7→ B
t= ∂b(x
t) and t 7→ S
t= ∂σ(x
t) which are (1 − α)- H¨ older continuous. Thus
D
2F (0, x)(v)
it= v
ti−
d
X
k=1
Z
t 0∂
kb
i(x
s)v
skds −
d
X
k=1 m
X
j=1
Z
t 0∂
kσ
ij(x
s)v
ksdg
jsis a one-to-one mapping thanks to the existence and uniqueness result of Equa- tion (8).
Now we fix w ∈ C
1−α(0, T ; R
d). Thanks to Proposition 2, there exists v ∈ W
1α(0, T ; R
d) such that w = D
2F (0, x)(v), hence D
2F(0, x) is onto and then it is a bijection. We already know that it is continuous. By the implicit function theorem g 7→ x(g) is continuously Fr´ echet differentiable and
Dx = −D
2F (0, x)
−1◦ D
1F (0, x) . (17) So for any k ∈ W
21−α(0, T ; R
m), −Dx(k) is the unique solution of the differential equation
w
ti= −Dx(k)
it+
d
X
k=1
Z
t 0∂
kb(x
s)Dx(k)
ksds +
d
X
k=1 m
X
j=1
Z
t 0∂
kσ
ij(x
s)Dx(k)
ksdg
jswith w
ti= D
1F(0, x)(k)
t= − P
m j=1R
t0
σ
ij(x
s)dk
js. On the other hand, from Equation (16) we get
m
X
j=1
Z
t 0Φ
ijt(s)dh
js=
m
X
j=1
Z
t 0σ
ij(x
s)dh
js+
m
X
j=1
Z
t 0d
X
k=1
Z
t s∂
kb
i(x
u)Φ
k,ju(s)du
! ds
+
m
X
j=1
Z
t 0d
X
k=1 m
X
l=1
Z
t s∂
kσ
il(x
u)Φ
k,ju(s)dg
ul!
dh
js. (18)
Using Fubini’s theorem we can invert the order of integration in the second
integral of the right hand side of (18). The treatment of the third integral is
more involved. Thanks to Proposition 9 in the Appendix, ∂
kσ
il(x
u)Φ
k,ju(s) is
H¨ older continuous of order 1 − α in both variables (u, s). As a consequence, we
can apply Fubini’s theorem for the Riemann-Stieltjes integrals and we obtain
m
X
j=1
Z
t 0Φ
ijt(s)dh
js=
m
X
j=1
Z
t 0σ
ij(x
s)dh
js+
d
X
k=1
Z
t 0∂
kb
i(x
u)
m
X
j=1
Z
u 0Φ
k,ju(s)ds
du
+
d
X
k=1 m
X
l=1
Z
t 0∂
kσ
il(x
u)
m
X
j=1
Z
u 0Φ
k,ju(s)dh
js
dg
lu. Hence t 7→ P
mj=1
R
t0
Φ
ijt(s)dh
jsis a solution of Equation (16) and by uniqueness we get the result.
If the coefficients b and σ are infinitely differentiable, the mapping g → x(g) is actually infinitely Fr´ echet differentiable. The proof of this result uses essentially the same arguments as in the case of first order derivatives, but the notation is more involved. We state here the result and present the proof in the Appendix.
Proposition 5 Assume b
i, σ
ij∈ C
b∞. Then the solution x to Equation (8) is infinitely continuously Fr´ echet differentiable. Moreover, for any (h
1, . . . , h
n) ∈ (W
11−α(0, T ; R
m))
n, it holds that
D
h1,...,hnx
it=
m
X
i1,...,in=1
Z
t 0. . . Z
t0
Φ
i,it 1,...,in(r
1, . . . , r
n)dh
i11(r
1)dh
i22(r
2) . . . dh
inn(r
n) , (19) where the functions Φ
i,it 1,...,in(r
1, . . . , r
n) for t ≥ r
1∨ . . . ∨ r
nare defined recur- sively by
Φ
i,it 1,...,in(r
1, . . . , r
n) =
n
X
i0=1
A
ii0,i1,...,i0−1,i0+1,...,in
(r
i0, r
1, . . . , , r
i0−1, r
i0+1, . . . , r
n) +
Z
t r1∨...∨rnB
ii1,...,in(r
1, . . . , r
n; s)ds +
m
X
l=1
Z
t r1∨...∨rnA
il,i1,...,in(r
1, . . . , r
n; s)dg
ls, (20) and 0 if t < r
1∨ . . . ∨ r
n. We have denoted
A
ij,i1,...,in(r
1, . . . , r
n; s) = X
I1∪...∪Iν
d
X
k1,...,kν=1
∂
k1. . . ∂
kνσ
ij(x
s)
× Φ
ks1,i(I1)(r(I
1)) . . . Φ
ksν,i(Iν)(r(I
ν)), B
ii1,...,in(r
1, . . . , r
n; s) = X
I1∪...∪Iν
d
X
k1,...,kν=1
∂
k1. . . ∂
kνb
i(x
s)
× Φ
ks1,i(I1)(r(I
1)) . . . Φ
ksν,i(Iν)(r(I
ν)) ,
where the first sums are extended to the set of all partitions I
1∪ . . . ∪ I
νof
{1, . . . , n}.
3 Stochastic Differential Equations driven by a fractional Brownian motion
Let Ω = C
0([0, T ]; R
m) be the Banach space of continuous functions, null at time 0, equipped with the supremum norm. Fix H ∈ (
12, 1). Let P be the unique probability measure on Ω such that the canonical process {B
t, t ∈ [0, T ]} is an m-dimensional fractional Brownian motion with Hurst parameter H.
We denote by E the set of step functions on [0, T ] with values in R
m. Let H be the Hilbert space defined as the closure of E with respect to the scalar product
1
[0,t1], . . . , 1
[0,tm], 1
[0,s1], . . . , 1
[0,sm]H
=
m
X
i=1
R
H(t
i, s
i).
We recall that
R
H(t, s) = Z
t∧s0
K
H(t, r)K
H(s, r)dr, where K
H(t, s) is the square integrable kernel defined by
K
H(t, s) = c
Hs
12−HZ
ts
(u − s)
H−32u
H−12du for t > s, where c
H= q
H(2H−1)β(2−2H,H−12)
and β denotes the Beta function. We put K
H(t, s) = 0 if t ≤ s.
The mapping 1
[0,t1], ..., 1
[0,tm]7→ P
mi=1
B
itican be extended to an isometry between H and the Gaussian space H
1(B) spanned by B. We denote this isometry by ϕ 7→ B(ϕ).
We introduce the operator K
H∗: E → L
2(0, T ; R
m) defined by:
K
H∗1
[0,t1], ..., 1
[0,tm]= (K
H(t
1, .), ..., K
H(t
m, .)) .
For any ϕ, ψ ∈ E , hϕ, ψi
H= hK
H∗ϕ, K
H∗ψi
L2(0,T;Rm)= E (B(ϕ)B(ψ)) and then K
H∗provides an isometry between the Hilbert space H and a closed subspace of L
2(0, T ; R
m).
We denote K
H: L
2(0, T ; R
m) → H
H:= K
HL
2(0, T ; R
m)
the operator defined by
(K
Hh)(t) :=
Z
t 0K
H(t, s)h(s)ds .
The space H
His the fractional version of the Cameron-Martin space. In the case of a classical Brownian motion, K
H(t, s) = 1
[0,t](s), K
H∗is the identity map on L
2(0, T ; R
m), and H
His the space of continuous functions, vanishing at zero, with a square integrable derivative.
We finally denote by R
H= K
H◦ K
∗H: H → H
Hthe operator R
Hϕ =
Z
· 0K
H(·, s) (K
∗Hϕ) (s)ds .
We remark that for any ϕ ∈ H, R
Hϕ is H¨ older continuous of order H . Indeed, (R
Hϕ)
i(t) =
Z
T 0K
H∗1
[0,t]i(s) (K
H∗ϕ)
i(s)ds = E B
tiB
i(ϕ) , and consequently
(R
Hϕ)
i(t) − (R
Hϕ)
i(s)
≤ E |B
ti− B
is|
21/2kϕk
H≤ kϕk
H|t − s|
H. Notice also that R
H1
[0,t]= R
H(t, ·), and, as a consequence, H
His the Repro- ducing Kernel Hilbert Space associated with the Gaussian process B.
The injection R
H: H → Ω embeds H densely into Ω and for any ϕ ∈ Ω
∗⊂ H we have
E
e
ihB,ϕi= exp
− 1 2 kϕk
2H.
As a consequence, (Ω, H, P ) is an abstract Wiener space in the sense of Gross.
Notice that the choices of the Hilbert space and its embedding into Ω are not unique and in [3] the authors have made another (but equivalent) choice for the underlying Hilbert space.
Let {X
t, t ∈ [0,T ]} be the solution of the stochastic differential equation (2), and assume that the coefficients are infinitely differentiable which are bounded together with all their derivatives. Fix 1 − H < α <
12. Then the trajectories of the fractional Brownian motion belong almost surely to C
1−α+ε(0, T ; R
m) ⊂ W
21−α(0, T ; R
m) if ε < H +α−1. Therefore, by Proposition 5, the mapping ω 7→
X(ω) is infinitely Fr´ echet differentiable from W
21−α(0, T ; R
m) into W
1α(0, T ; R
d).
On the other hand, we have seen that H
H⊂ C
H(0, T ; R
m) ⊂ W
21−α(0, T ; R
m).
As a consequence, the following iterated derivatives exists D
RHϕ1,...,RHϕ1X
ti= d
dε
1· · · d
dε
nX
ti(ω + ε
1R
Hϕ
1+ · · · + ε
nR
Hϕ
n)|
ε1=···=εn=0, for all ϕ
i∈ H. In this way we have proved the following result.
Theorem 6 Let H > 1/2 and assume that b
i, σ
ij∈ C
b3. Then the stochastic process X solution of the stochastic differential equation (2) is almost surely differentiable in the directions of the Cameron-Martin space. If b
i, σ
ij∈ C
b∞, then X is almost surely infinitely differentiable in the directions of the Cameron- Martin space.
The iterated derivative D
RHϕ1,...,RHϕ1X
ticoincides with
D
nX
ti, ϕ
1⊗ · · · ⊗ ϕ
nH⊗
, where D
nis the iterated derivative in the Malliavin calculus sense. In fact, if F is a smooth cylindrical random variable of the form
F = f (B(ϕ
1), . . . , B(ϕ
m))
with f ∈ C
b∞( R
m), ϕ
i∈ H, then the Malliavin derivative DF is the H-valued random variable defined by
hDF, hi
H=
m
X
i=1
∂
if (B(ϕ
1), . . . , B(ϕ
m))hϕ
i, hi
H= d
dε f (B(ϕ
1) + εhϕ
1, hi
H, . . . , B(ϕ
m) + εhϕ
m, hi
H)
ε=0, and one can easily see that
B(ϕ
1)(ω + εR
Hh) = B (ϕ
1)(ω) + εhϕ
1, hi
H.
We recall here that D
k,pis the closure of the space of smooth and cylindrical random variable with respect to the norm
kFk
k,p=
E(|F|
p) +
k
X
j=1
E(
D
jF
p H⊗j
)
1 p
,
and D
k,plocis the set of random variables F such that there exist a sequence {(Ω
n, F
n), n ≥ 1} such that Ω
n↑ Ω a.s, F
n∈ D
k,pand F = F
na.s. on Ω
n.
By the results of Kusuoka (see [5], Theorem 5.2 or [10], Proposition 4.1.3), Theorem 6 implies that X
tibelongs to the space D
k,plocfor all p > 1 and any integer k.
Now we give the equations satisfied by the derivatives of the process X.
Proposition 7 If we denote (i
1, . . . , i
n) ∈ {1, . . . , m}
na multi-index, the n- th derivative in the sense of Malliavin calculus satisfies the following linear equation a.s.:
D
ir11,...,i,...,rnnX
ti=
n
X
i0=1
α
ii0,i1,...,i0−1,i0+1,...,in(r
i0, r
1, . . . , , r
i0−1, r
i0+1, . . . , r
n) +
Z
t r1∨...∨rnβ
ii1,...,in
(r
1, . . . , r
n; s)ds +
m
X
l=1
Z
t r1∨...∨rnα
il,i1,...,in
(r
1, . . . , r
n; s)dB
sl, (21) if t ≥ r
1∨ . . . ∨ r
n, and D
ir1,...,in1,...,rn
X
ti= 0 otherwise. In the above equation, we have denoted
α
ij,i1,...,in(r
1, . . . , r
n; s) = X
I1∪...∪Iν
d
X
k1,...,kν=1
∂
k1. . . ∂
kνσ
ij(X
s) D
r(Ii(I1)1)
X
sk1. . . D
i(Ir(Iν)ν)
X
skν, β
ii1,...,in(r
1, . . . , r
n; s) = X
I1∪...∪Iν
d
X
k1,...,kν=1
∂
k1. . . ∂
kνb
i(X
s) D
i(Ir(I1)1)
X
sk1. . . D
r(Ii(Iν)ν)
X
skν,
where the first sums are extended to the set of all partitions I
1∪ . . . ∪ I
νof {1, . . . , n} and for any subset K = {i
1, . . . , i
η} of {1, . . . , n}, we put D
r(K)i(K)the derivative operator D
ri1i1,...,i,...,rηiη.
For the first order derivative, Equation (21) reads as follows: for i = 1, . . . , d, j = 1, . . . , m,
D
jsX
ti= σ
ij(X
s)+
d
X
k=1
Z
t s∂
kb
i(X
u)D
jsX
ukdu +
d
X
k=1 m
X
l=1
Z
t s∂
kσ
il(X
u)D
jsX
ukdB
lu, if s ≤ t and 0 if s > t.
Proof. We use the representation result on the deterministic equation given by (19) in Proposition 5. For any h = (h
1, . . . , h
n) with h
i∈ H, we have
D
RHh1,...,RHhnX
ti=
m
X
i1,...,in=1
Z
t 0. . . Z
t0
Φ
i,it 1,...,in(r
1, . . . , r
n)
×d(R
Hh
1)
i1(r
1) · · · d(R
Hh
n)
in(r
n). (22) We denote K
H∗ ⊗nthe map from H
⊗ninto L
2(0, T ; R
m)
⊗ndefined for ϕ ∈ H
⊗nby
K
∗ ⊗nHϕ
(s
1, . . . , s
n) = Z
Ts1
. . . Z
Tsn
ϕ(r
1, . . . , r
n) ∂K
H∂r
1(r
1, s
1) · · · ∂K
H∂r
n(r
n, s
n)dr
1. . . dr
n. It holds that
hϕ, ψi
H⊗n= X
ξ∈{1,...,m}n
Z
[0,T]n
K
∗ ⊗nHϕ
ξ(s
1, . . . , s
n) K
∗ ⊗nHψ
ξ(s
1, . . . , s
n)ds
1. . . ds
n. Thanks to Step 3 in the proof Proposition 5, for any 1 ≤ k ≤ n,
s
k7→
Z
[0,t]k−1
Φ
i,it 1,...,in(s
1, ..., s
k−1, s
k, s
k+1, . . . , s
n)dh
i11(s
1) · · · dh
ik−1k−1(s
k−1) belongs to C
1−α(0, T ) and we can apply n times Lemma 11 from Appendix.
This yields that almost surely D
RHh1,...,RHhnX
ti=
m
X
i1,...,in=1
Z
t 0. . . Z
t0
Φ
i,it 1,...,in(r
1, . . . , r
n) Z
r10
∂K
H∂r
1(r
1, u) (K
H∗h
1)
i1(u)du
× · · · × Z
rn0
∂K
H∂r
n(r
n, u) (K
∗Hh
1)
in(u)du
dr
1· · · dr
n=
m
X
i1,...,in=1
Z
T 0· · · Z
T0
K
∗ ⊗nHΦ
iti1,...,in(s
1, . . . , s
n)
×
n
Y
l=1
(K
∗Hh
l)
il(s
i)ds
1. . . ds
n=
Φ
it, h
1⊗ ... ⊗ h
n⊗n
,
and the result is proved.
4 Absolute continuity of the law of the solution
The fact that for H >
12, the solution of Equation (8) belongs to the localized domain of the Malliavin derivative operator D will imply the absolute continuity of the law of X
tfor all T > 0 under suitable nondegeneracy conditions.
Theorem 8 Let H > 1/2 and assume that b
i, σ
ij∈ C
b3. Suppose that the following nondegeneracy condition on the coefficient σ holds:
(H) The vector space spanned by
σ
1j(x
0), . . . , σ
dj(x
0)
, 1 ≤ j ≤ m is R
d. Then for any t > 0, the law of the random vector X
tis absolutely continuous with respect to the Lebesgue measure on R
d.
Proof. We already know by Theorem 6 that X
tibelongs to D
1,2locfor all t ∈ [0, T ] and for i = 1, ..., d. Then, thanks to [10], Theorem 2.1.2, it suffices to show that the Malliavin covariance matrix of X
tdefined by
Q
ijt= D
DX
ti, DX
tjE
H
is invertible almost surely. We first deduce another expression for the matrix Q
t. We stress the fact that K
∗His an isometry between H and a closed subspace of L
2(0, T ; R
m). Let {e
n, n ≥ 1} be a complete orthonormal system in this closed subspace. The elements f
n= (K
∗H)
−1(e
n) for a complete orthonormal system of H. Then it holds almost surely that
DX
ti= X
n≥1
DX
ti, f
nH
f
n, and consequently
Q
ijt= X
n≥1
DX
ti, f
nH
D
DX
tj, f
nE
H
.
Suppose now that the Malliavin covariance matrix is not almost surely invertible, that is P (det Q
t= 0) > 0. Then there exists a vector v ∈ R
d, v 6= 0, such that v
TQ
tv = 0. Our aim is to prove that condition (H) cannot be satisfied. One may write
v
TQ
tv = X
n≥1
hhDX
t, f
ni
H, vi
Rd
2
.
From (22) it follows that
DX
ti, f
nH
= D
RHfnX
ti,
and thanks to the representation (17), the directional derivative D
RHfnX
tisat- isfies
D
RHfnX
ti= D
2F(0, X)
−1◦ D
1F (0, X)
(R
Hf
n)
it. It follows that
0 =
D
2F (0, X )
−1◦ D
1F(0, X)
(R
Hf
n)
t, v
Rd
.
Since D
2F(0, X)
−1is a linear homeomorphism, there exists v
0∈ R
d, v
06= 0, such that
0 = hD
1F (0, X)(R
Hf
n)
t, v
0i
Rd=
d
X
i=1
m
X
j=1
Z
t 0σ
ij(X
s)d(R
Hf
n)
js
v
0i=
*
dX
i=1
v
i0σ
i(X )1
[0,t], f
n+
H
holds true for any n ≥ 1 (where σ
idenotes the ith row of the matrix σ). Then 0 =
d
X
i=1
v
i0σ
i(X )1
[0,t]H
and this yields that for all j = 1, ..., m and s ∈ [0, t]
d
X
i=1
v
0iσ
ij(X
s) = 0.
Taking s = 0 we get P
di=1
v
0iσ
ij(x
0) = 0 for all j = 1, ..., m and this contradicts (H). Then the law of the solution of the stochastic differential equation (2) at any time t > 0 is absolutely continuous with respect to the Lebesgue measure on R
d.
5 Appendix
The next proposition provides the joint continuity property of the solution of the equations similar to Equation (16) satisfied by the kernel of the derivative.
Proposition 9 Fix γ, B, S ∈ C
1−α(0, T ) and g ∈ W
21−α(0, T ) and consider the equation
ρ
t(s) = γ(s) + Z
ts
B
uρ
u(s)du + Z
ts
S
uρ
u(s)dg
u(23) if s ≤ t and ρ
t(s) = 0 if s > t. Then the solution is a H¨ older continuous function of order 1 − α in both variables.
Proof. First notice that kρ
·(s)k
α,1is uniformly bounded in s, by the esti- mate (10). Hence, the function ρ
t(s) is H¨ older continuous in t, uniformly in s by (5) and (7). On the other hand, for s
0≤ s ≤ t we have
ρ
t(s) − ρ
t(s
0) = |w(s, s
0) + Z
ts
B
u(ρ
u(s) − ρ
u(s
0)) du +
Z
t sS
u(ρ
u(s) − ρ
u(s
0)) dg
u, (24)
where
w(s, s
0) = γ(s) − γ(s
0) + Z
ss0
B
uρ
u(s)du + Z
ss0
S
uρ
u(s)dg
u. (25) Proposition 2 yields the estimate
sup
s∈[0,T]
kρ
·(s)k
α,1≤ c
1kγk
α,1exp
c
2kgk
1 1−2α
1−α,2
( kBk
∞+ kSk
1−α)
. (26) Substituting (26) into (25) yields
|w(s, s
0)| ≤ kγk
1−α(s − s
0)
1−α+ kBk
∞sup
s
kρ
·(s)k
α,1(s − s
0) + ckSk
α,1kgk
1−α,2sup
s
kρ
·(s)k
α,1(s − s
0)
1−α≤ c
1(s − s
0)
1−α. (27)
Then Proposition 2 applied to Equation (24) and the Estimate (27) imply that kρ
·(s) − ρ
·(s
0)k
α,1≤ c
1(s − s
0)
1−αexp
c
2kgk
1 1−2α
1−α,2
( kBk
∞+ kSk
1−α)
. Therefore, ρ
t(s) is H¨ older continuous in the variable s, uniformly in t. This completes the proof of the proposition.
For the proof of Proposition 5 we need the following technical lemma.
Lemma 10 Suppose that we are given a mapping g 7→ v
gfrom W
21−α(0, T ; R
m) to W
1α(0, T ; R
M) which is continuously Fr´ echet differentiable. Consider five bounded differentiable functions a
0, . . ., a
4from R
dto R
d×m×M, R
d×M, R
d×d, R
d×m×Mand R
d×m×d, respectively. We moreover assume that these functions have bounded derivatives up to order two. Let y ∈ W
1α(0, T ; R
d) be the solution of the following equation
y
t= Z
t0
a
0(x
gr)v
grdk
r+ Z
t0
{a
1(x
gr)v
gr+ a
2(x
gr)y
r} dr+
Z
t 0{a
3(x
gr)v
gr+ a
4(x
gr)y
r} dg
r, (28) where k ∈ W
21−α(0, T ; R
m) and x
gis the unique solution of (8) which is already continuously Fr´ echet differentiable.
Then g 7→ y is continuously Fr´ echet differentiable and the directional deriva- tive in the direction h ∈ W
21−α(0, T ; R
m) is the unique solution of
D
hy
t= Z
t0
{∂a
0(x
r)D
hx
rv
r+ a
0(x
r)D
hv
r} dk
r+ Z
t0
{a
3(x
r)v
r+ a
4(x
r)y
r} dh
r+
Z
t 0{∂a
1(x
r)D
hx
rv
r+ a
1(x
r)D
hv
r+ ∂a
2(x
r)D
hx
ry
r+ a
2(x
r)D
hy
r} dr +
Z
t 0{∂a
3(x
r)D
hx
rv
r+ a
3(x
r)D
hv
r+ ∂a
4(x
r)D
hx
ry
r+ a
4(x
r)D
hy
r} dg
r.
(29)
Proof. We introduce the map
W
21−α(0, T ; R
m) × W
1α(0, T ; R
d) → C
1−α(0, T ; R
d) ⊂ W
1α(0, T ; R
d) (h, y) 7→ F(h, y)(t) := y
t−
Z
t 0a
0(x
g+hr)v
g+hrdk
r− Z
t0
a
1(x
g+hr)v
rg+h+ a
2(x
g+hr)y
rdr
− Z
t0
a
3(x
g+hr)v
rg+h+ a
4(x
g+hr)y
rd(g
r+ h
r) . One has F(0, y) = 0 since y is the solution of (28). As in Lemma 3 we can show
that F is Fr´ echet differentiable and D
1F (0, y)
t= −
Z
t 0{∂a
0(x
r)Dx(h)
rv
r+ a
0(x
r)Dv(h)
r} dk
r− Z
t0
{a
3(x
r)v
r+ a
4(x
r)y
r} dh
r− Z
t0
{∂a
1(x
r)Dx(h)
rv
r+ a
1(x
r)Dv(h)
r+ ∂a
2(x
r)Dx(h)
ry
r} dr
− Z
t0
{∂a
3(x
r)Dx(h)
rv
r+ a
3(x
r)Dv(h)
r+ ∂a
4(x
r)Dx(h)
ry
r} dg
rD
2F(0, y)(z)
t= z
t−
Z
t 0a
4(x
r)z
rdg
r− Z
t0
a
2(x
r)z
rdr ,
for any z ∈ W
1α(0, T ; R
d). Then, using Proposition 2 and the same arguments as in the proof of Proposition 4 we conclude that g 7→ y is continuously Fr´ echet differentiable and it has a directional derivative in the direction h satisfying (29).
Proof of Proposition 5. The proof of Proposition 5 is divided into several steps. We begin by proving that x is infinitely Fr´ echet differentiable. Then we show that Equation (20) has a unique solution and derive some of its properties.
Finally we prove that (19) holds.
Step 1 We begin by proving by induction that x is infinitely Fr´ echet continu- ously differentiable. We introduce some notation in order to write the equations satisfied by the higher order directional derivatives.
Let n ≥ 1 and for i = 1, . . . , n, h
i= (h
1i, . . . , h
mi) ∈ W
21−α(0, T ; R
m). For any subset K = {ε
1, . . . , ε
η} of {1, . . . , n}, we denote by D
j(K)the iterated directional derivative
D
j(K)x = D
hε1,...,hεη
x = D
ηx(h
ε1, ..., h
εη),
where D
ηdenotes the iterated Fr´ echet derivative of order η. Define for i = 1, ..., d and j = 1, ..., m
α
ij(h
1, . . . , h
n; s) = X
I1∪...∪Iν
d
X
k1,...,kν=1
∂
k1. . . ∂
kνσ
ij(x
s) D
j(I1)x
ks1. . . D
j(Iν)x
ksν,
β
i(h
1, . . . , h
n; s) = X
I1∪...∪Iν
d
X
k1,...,kν=1
∂
k1. . . ∂
kνb
i(x
s) D
j(I1)x
ks1. . . D
j(Iν)x
ksν, where the first sums are extended to the set of all partitions I
1∪ . . . ∪ I
νof {1, . . . , n}. The n-th iterated derivative satisfies the following linear equation:
D
h1,...,hnx
it=
n
X
j0=1 m
X
j=1
Z
t 0α
ij(h
1, . . . , h
j0−1, h
j0+1, . . . , h
n; s)dh
jj0(s)
+ Z
t0
β
i(h
1, . . . , h
n; s)ds +
m
X
j=1
Z
t 0α
ij(h
1, . . . , h
n; s)dg
sj. (30) for i = 1, . . . , n. Now we prove by induction that x is infinitely Fr´ echet dif- ferentiable and (30) holds. The result is true for n = 1 thanks to Proposi- tion 4. Suppose that these properties hold up to the index n. Observe that α
ij(h
1, . . . , h
n; s) is equal to the term corresponding to ν = 1, namely
d
X
k=1
∂
kσ
ij(x
s)D
h1,...,hnx
ks,
plus a polynomial function on the derivatives ∂
k1. . . ∂
kνσ
ij(x
s) with ν ≥ 2, and the functions D
j(I)x
s, with card(I) ≤ n − 1. Therefore, we can apply Lemma 10 with y = D
h1,...,hnx, v the vector function whose entries are the products D
j(I1)x
ks1. . . D
j(Iν)x
ksνfor all the partitions I
1∪ . . . ∪ I
νwith ν ≥ 2 and with appropriate functions a
i, i = 0, . . . , 4. This lemma yields that g 7→ D
h1,...,hnx is continuously Fr´ echet differentiable and the directional derivative of order n + 1 is solution of (30) at the rank n + 1.
Let us now prove by induction that the map (h
1, . . . , h
n) 7→ D
(h1,...,hn)x is multi-linear and continuous. By Proposition 4 this is true for n = 1. Suppose it holds up to n −1, that is, for any subset {ε
1, . . . , ε
n0} of {1, . . . , n} with n
0< n, the maps (h
ε1, . . . , h
εn0
) 7→ D
hε1,...,hεn
0