C OMPOSITIO M ATHEMATICA
O LIVIER M ATHIEU
On some modular representations of affine Kac- Moody algebras at the critical level
Compositio Mathematica, tome 102, n
o3 (1996), p. 305-312
<http://www.numdam.org/item?id=CM_1996__102_3_305_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
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On some modular representations of affine Kac-Moody algebras at the critical level
OLIVIER MATHIEU
© 1996 Kluwer Academic Publishers. Printed in the Netherlands.
IRMA (UA 1 du CNRS), Université Louis Pasteur, 67000, Strasbourg, France
e-mail: mathieu@math.u-strasbg.fr
Received 20 April 1995; accepted in final form 2 May 1995
Introduction
Let k be a field of
arbitrary characteristic,
let g be an affineKac-Moody algebra
and let U be the
Chevalley-Kostant algebra
associated to g. Recall that when has characteristic zero, U is theenveloping algebra
of g. However in characteristic p, U contains the restrictedenveloping algebra together
with some divided powers(see
Section 1 for aprecise definition).
For anyweight a,
denoteby 1 ( À )
thesimple highest weight
U-module withhighest weight
À.The aim of this paper is to prove the
following
two theorems.THEOREM 1. We have
ch(l(-03C1))
=e-03C103A0a~0394+re 1/(l - e-a).
THEOREM 2. Assume k is a
field of characteristic
p. We havech(l((p- 1)03C1))
=For fields of characteristic
0,
Theorem 1(which
has beenconjectured by
V. G. Kac and D. Kazhdan
[KK])
wasalready
known. It has beenproved by
M. Wakimoto
[Wk],
N. Wallach[Wl] (in the sl(2) case),
J. M. Ku[Ku] (in general),
T.Hayashi [H] (for
classicaltype
affine Liealgebras),
B.Feigin
andE. Frenkel
[FF3], [F] (in general).
See also related resultsby
R.Goodman,
N.Wallach
[GW]
and F. Malikov[Ml].
To prove Theorem
1,
we need to prove thefollowing
twoinequalities.
First inequality : ch(l(-03C1)) e-03C103A003B1~0394+re 1/(1 - e-03B1).
Second
inequality: ch(l(-03C1)) e-PTI EA+ 1/(1- e-03B1).
The
proof
of the firstinequality is based
on characteristic p methods. When k isa field of characteristic p, we use the
isomorphism l(-p) - l((p- 1)03C1) ~ F*l(-03C1)
(where
F is the Frobeniusmorphism
ofU)
and theintegrability
of the modulel((p-1)03C1).
306
To prove the second
inequality,
we can restrict ourself to the case where k hascharacteristic zero. Thus this
inequality
follows from thepreviously
cited works.In
particular
thispart
of theproof
is notindependent
of these works. However note that the secondinequality
followsobviously
from the existence of the restrictedWakimoto module
Wp (as
defined in[Wk], [FF1], [FF2]).
It turns out that Theorem 1 and Theorem 2 are
actually equivalent.
Ourapproach provides
a verysimple proof
of the firstinequality (especially
withoutusing
Kazdhan-Kac determinant formula
[KK]).
Itgives
a newproof
of theirreducibility
of the Wakimoto module with
highest weight -p (see [Wk], [FF3]).
Moreover weget
that the reductions in finite characteristics of the Z-form ofl(-p)
are sim-ple
modules. For a field of characteristic p, this proves that theSteinberg
moduleL((p-1)03C1) (i.e.
the maximalintegrable quotient
of the Verma module withhighest weight (p - 1 )p)
is notsimple
what contrasts with the modulartheory
of finitedimensional Lie
algebras.
In aforthcoming
paper[Mt4],
a similar method will be used tostudy
the structure of theendomorphism ring
of the Verma module withhighest weight -p.
1. Modular
Kac-Moody algebras
(1.1)
Let A =(aij)i,j~I
be ageneralized
Cartanmatrix,
let(hQ, (hi)i~I, (03B1i)i~I)
be a realization of A over
Q (in
the sense ofKac,
see[K])
andlet hZ
be anintegral
realization of A
(see [Mtl ],
ch.1).
LetQ
be the root lattice and set P =Let
gQ be theKac-Moody algebra
overQ
associated to A.By definition,
gQ isgenerated by hQ, (ei)i~I, (fi)i~I
and definedby
some local relations and Serre relations(i.e.
it is the maximal
choice).
There is a
triangular decomposition
gQ =nÉ Q9 hQ ~ nQ
wheren+ (respectively
nQ )
is thesubalgebra generated by (ei)i~I (respectively by (fi)i~I).
Denoteby
UQ , U+Q , U0Q, UQ
theenveloping algebras of gQ, n+Q, hQ
andn-
Following
Tits[T1], [T2] (see
also[Mi]),
we denoteby UZ (respectively Ui, U+Z, U0Z)
thesubring
ofU generated hy
the elementse(n)i, f(n)i, (h n) (respec-
tively by f(n)i, by e(n)i, by (h n))
wherei, n, h
runs overI, Z+, hZ.
We set gz =g
nUZ. Similarly
there is atriangular decomposition
gz= n+Z ~ hZ ~ nZ.
wheren±Z = n±Q ~ U~Z.
Let W be the
Wely
group of gQ, and let A(respectively 0-, 0394+, 0 é)
be theset of roots
(respectively
ofnegative
roots, ofpositive
roots, of realpositive roots).
For
any A
E P we will denoteby lQ(03BB)
theunique
irreduciblehighest weight
module over
Q
withhighest weight À,
see[K].
For any
simple
root a = ai, denoteby Ufl
besubring generated by U+Z, U0Z
andthe elements
f(n)i, n
0. Some natural duals of theHopf Z-algebras U±Z , U0Z
andU03B1Z
are defined in[Mt1] (see
Ch.1). They
are denotedrespectively by Z[U±], Z[H]
and
Z[P,].
Recall thatZ[U±]
arepolynomial algebras
over Z([Mt2],
see Lemma 2and its
proof). Roughly speaking,
theseHopf algebras
are the Z-forms of thespace of
regular
functions over,respectively,
theunipotent
radicalsUt
of the twoopposite
Borelsubgroups,
the Cartansubgroups
H and the minimalparabolic
sub-groups
Pa.
(1.2)
From now we denoteby
k aperfect
field of finite characteristic p. The tensorproduct
of k with gZ,ni, hz, Uz, ut, U0Z, T’y Z[U±], Z[H]
andZ[P03B1]
willbe denoted
by
g,n±, h, U, U±, U°, Ua, k[U±], k[H]
andk[P03B1].
For any À eP,
letl(03BB)
be theunique
irreduciblehighest weight
module withhighest weight À,
andlet VÀ be its
highest weight
vector. For any dominantweight
À EP,
letL(À)
bethe maximal
integrable quotient
of the Verma module withhighest weight
03BB. Alsodenote
by VÀ
itshighest weight
vector.LEMMA 1.3. There is a k-linear
morphism of algebras
F: U ~ Uuniquely defined
on thegenerators of
Uby F(e(n)i)
=F(f(n)i) = F(h n)
= 0if p
does notdivide n and
F(e(pn)i)
=e(n)i, F(f(pn)i)
=ln), F((h pn))
=(h n) for
any i El,
n E
Z+
and h EhZ.
Proof.
We canidentify V+
with the space ofright invariant,
leftAd(U:L)
locally nilpotent differential operators
of thek-algebra k[U±] .
Ask[U±] has
no zerodivisors and is
naturally
defined overF ,
there is a natural k-linearisomorphism
03C3± :
(k[U±]])p ~ k[U±]. For any u ~ U±, we have u.(k[U±])p
C(k[U±])p. Define
k-algebra morphisms Ff : V+ - Ut by
the formulaF±(u)
= Qt o v o03C3-1±,
where v is the restriction of u to
(k [U:L ])P.
Define in a similar way themorphisms Fo, Fa
of thek-algebras U°, Ua.
As we have
U ~ U+ ~ Uo 0 U-,
we can define a k-linear map F : U ~ Uby
F =F + Q9 Fo Q9
F-. To check that F is amorphism
ofalgebras,
it sufficesto prove that
F(xy)
=F(x)F(y)
at least when x is one of thegenerators
of U.There is a
simple
root a such that xbelongs
toUa
and we can assumethat y
= z.wwhere z e
U+ ~ U°
and w e U-. It is clear that the restriction of F toUa
is
precisely Fa.
Inparticular
onegets F(x.z)
=F(x).F(z). Using
that F- is amorphism
ofalgebras,
onegets F(a.w)
=F(a).F(iu)
for any a E U. So weget F(x.y)
=F(x.z.w)
=F(x.z).F(w)
=F(x).F(z).F(w)
=F(x).F(z.w) =
F( x ).F(y).
0(1.4)
For a restricted Liealgebra
a overk,
denoteby u(a)
its restrictedenveloping algebra,
see[J].
The Liealgebra
g is a restricted Liealgebra.
As g is the sum ofthe three Lie
algebras n±
andh,
it suffices to describe thep-structure
on each of these three Liesub-algebras.
Thep-structure x ~ x[p]
onn±
issimply given by
the
requirement
thatx[p]
is the derivation xp onk[U±]. Over h
therequirement
ish[p]
= h forany h ~ h ~ Z/pZ.
As U is anHopf algebra,
the natural mapu(g)
- Uis one-to-one.
A
weight 03BB E P is
called restricted if we have0 + 03BB(hi) p - 1
for anyi e I. However the use of the same
terminology
’restricted’ forweights
and forrepresentations
ismeaningless. E.g.
asg-module,
any U-module is restricted.308
(1.5)
Let O be thecategory
of all U-modules M which arelocally nilpotent
asU+-module
and such that M =~03BB~PM03BB
asU°-module,
where allweight
spacesMa
are finite dimensional. There is an involution of Uexchanging
thegenerators
e(n)i
andf(n)i.
Thus one defines the 0 dualM#
of M as the vector space~03BB~P(M*03BB)
where the action is twisted
by
this involution.For a formal
expression
A= 03A303BB~Pm03BBe03BB,
set FA= EaEpmaepv.
Thus forany module M E
O,
we haveF ch(M)
=ch(F*M)
andch(M#)
=ch(M).
(1.6)
In order togive
anotherdescription
of the modularKac-Moody algebras (Proposition 1.7),
we will introduce a few other notations. We will useonly part
ofProposition 1.7,
which is stated here forclarity
and for a future reference[Mt4].
Set
n’- = 03A3i~I Ad(U-) f2.
When k isinfinite,
it is clear thatn’-
is the span ofAd(V)(fi),
where V is thesubgroup
of theadjoint
groupgenerated by
the elementsexp(t.fj) (t
Ek, j
EI).
Thus it is clear thatr/’
is a restricted ideal of n-.LEMMA 1.7. Let À be a
restricted weight,
and let L be a nonzeroquotient of L( À).
Then we have L =
u(n’-).v03BB.
Assume now that L issimple.
Then L.issimple
asg-module
and we haveHO( n+, L)
=k.v03BB.
Set L’ =
u(n’-).v03BB
and let i E I and u eu(n’-).
As we havef(m)i.v03BB
= 0 forany m p, we
get
Hence L’ is a U--submodule of L. Thus we
get
L = L’. Assume now that L issimple.
Then L isisomorphic
to its 0-dualL#.
Thusby duality H°(n+, L)
is onedimensional. It follows that L is
simple
asg-module.
PROPOSITION 1.8.
(1.7.1) The module L((p-1).03C1) is u(n-)-free with generator
v(p-1).03C1.
(1.7.2)
We haven’-
= n-. Inparticularg
isgenerated by h, (ei)iei
and(fi)i~I
as U-module.
(1.7.3)
Assumethat p > - ai,j, for any
ij4 j.
As Liealgebra, g is generated by (ei)iei
and(fi)i~I.
Proof.
Recall thatch(L(p - I)p)
isgiven by Weyl-Kac
formula[Mtl]. By using
the denominatorformula,
weget
where ma is the
multiplicity
of the root a. So weget ch(L((p - I)p) =
e(p-1).03C1 ch(u(n-)). By
Lemma1.6,
the natural map O :u(n’-) --+ L((p - 1)p),
u H
u. V(p-l)p
issurjective.
Hence theu(n-)-module L((p - 1).p)
is free and wehave
n’-
= n-.Moreover it follows that U-
= u(n)- ~ I,
where I is the left idealgenerated by
the
f(n)i
where i~ I and n
p. Underhypothesis (1.7.3),
we haveAd(I)(fi) = 0,
hence n- is
generated
as au(n)- by
thefi.
It followseasily
that n- isgenerated by
thefi,
i e I. As a similar result holds forn+,
assertion(1.7.3)
isproved.
~LEMMA 1.9
(Steinberg
tensorproduct theorem).
Let03BB, 03BC, 03BD ~
P. AssumeÀ = Jl
+ p.vand y is
restricted. Then we havel(À)
=l(03BC) ~ F*l(03BD)
andch(l(03BB))
=ch(l(03BC)).Fch(l(03BD)).
Proof. Let x,
y be nonzerohighest weight
vectors of1(p), F*l(v)
and let Z bethe space of
U+
invariant vectors ofl(03BC) ~ F*l(v).
Note thatn+
actstrivially
onF*l(v).
Soby
Lemma1.6,
weget H°(n+, l(03BC) ~ F*l(03BD))
=k.x 0 F*l(v).
HenceZ is the space of
U+-invariant
vectorsof k.x 0 F*1(v),
i.e. Z =k.x 0
y.By using
the
duality
incategory O,
we alsoget
thatl(03BC) ~ F*l(v)
isgenerated by x 0
y as U--module. Hence1 (y)
0F*l(v)
issimple.
As itshighest weight
isÀ,
this moduleis
isomorphic to l(03BB).
~LEMMA 1.10. We have
ch(l(-03C1))
=ch(l((p- 1)03C1)).F ch(l(-03C1))).
Proof. Apply
theprevious
lemmato 03BB = -03C1, 03BC,
=(p - 1)p, v
= -p.Note as
corollary
thatch(l(-p))
isuniquely
determinedby ch(l((p - 1 )p) )
andconversely.
~2. The first
inequality
For any a e
0394+re,
letfa
be a basis of ga. For w eW,
set039403C9 = {a
EA+lw.a
EA-}
and set nw =~03B1~039403C9g-03B1.
Let 8i, be a reduceddecomposition
of w where 1 =1( w).
Set03B21
= ai,/32
= Sil ai2’ ...,/31
=si1...sil-103B1il, where 1 =
L(w).
Recall that we haveAw
={03B21,...,03B2l}.
SetLEMMA 2.1.
(2.1.1) We have chu(nw) = 03A0(03A3).
(2.1.2)
The dimensionof u(nw)(p-1)(w-1.03C1-p) is exactly
one, andFw is a
basisof this
vector space.(2.1.3) For any
nonzero element u Eu(nw),
thereexists u’
Eu( nw)
such thatu’.u
=Fw.
Proof.
For a n dimensional vector spaceV,
let SY be thequotient
of SVby
the idealgenerated by
all the elementsxp, x E V.
In other words SV is the restrictedenveloping algebra
of the commutative Liealgebra
V endowed witha trivial
p-structure.
Note thatu(nw)
has a natural filtration(Fs)s0
definedby F0
= k andFs+
1= Fs
+nw.Fs for s
0. The associatedgraded
vector space iscanonically isomorphic
withSnw.
The assertion on the character follows. Then an310
easy calculation shows that
H°(V, SV)
is one dimensional. This space isexactly
the space of elements of
degree n(p - 1)
inSV
and it iscanonically isomorphic
with
(nV)~(p-1).
Thus theisomorphism Fl(p-1)/Fl(p-1)-1 ~ lnw
induces amap o, :
u(nw) ~ (/Blnw)Q9p-l.
We have03C3(Fw) = (f03B21 ... f(J1 )Q9(p-l).
HenceFw
is not zero
(see [Mt3], proof of Lemma
6.3.2 for moredetails).
Note that (p-1)(w-1.03C1-03C1)- is not a weight of u(nw) (for any j, 1 j l).
Hence
Fw
isn.",-invariant
for the left action. ThusFw
is theonly (up
toscalar)
leftinvariant vector in
u(nw).
The Liealgebra
nw isnilpotent
and the leftmultiplication by
any basis elementJ (Ji
is anilpotent endomorphism.
Hence for the leftaction,
u(nw)
is anilpotent n",-module
and any nonzero submoduleof u(nw)
contains anonzero invariant vector. Thus for any nonzero u e
u(nw),
we canfind u’
such thatu’.u
=Fw.
~For now on, we will denote the
highest weight
vector ofl((p - 1)p) by
v.LEMMA 2.2. The
u(nw)-module u(nw).v is free.
Proof. By
an easy inductionon j
we prove thatf(p-1)03B2j. f(p-1)03B2j-1 ... f(p-1)03B21.v
isa nonzero extremal
weight
vector of1((p - 1)p).
Inparticular
weget Fw.v ~
0.Using
Lemma 2.1.3 we deduce that the mapu(nw)
~l((p - 1)p), u H
u.v isinjective.
Thusu(nw).v
is free. 0A sequence w =
(wn)n~Z+
of elements of W such0394wn
C0394wn+1
is called anend of W. For an end w of
W,
we setOw
=Un~Z+0394wn
and nw =Un~Z+nwn.
Thus we
get
LEMMA 2.3. For any end 03C9
of W,
theu( nw)-module u( nw).v is free
From now on we will assume that g is affine. Write I =
Io
U{0}
as in[K],
and let 6 be any
positive imaginary
root.Moreover,
choose an element t E Wand h
~ h
with03B1i(h)
> 0 for any i EIo,
such thatt(03BC) = 03BC
+J.L( h)6
for any03BC e
Q.
It is clear that the sequence w =(tn )nEZ+
is an end of W. Forn 0,
set0(n)
=039403C9
U0394t-n. Roughly speaking, 039403C9
contains half of the set ofpositive
realroots.
Indeed,
we haveUn~Z+0394(n) = 0394+re
andtn039403C9 = 039403C9 U -Dt-n.
LEMMA 2.4.
(First inequality)
(2.4.1)
Wehave ch(l(p- 1)03C1)) e(p-1)03C103A003B1~0394+re(1- e-p.03B1)/(1- e-03B1).
(2.4.2) We have ch(l(-03C1)) e-03C103A003B1~0394+re1/(1-e-03B1).
Proof. By Lemma 2.3 we have ch(l((p-1)03C1)) e(p-1)03C103A0a~0394w(1-e-p,03B1)/(1-
e-a). Let n j
0. Recall that we have03A303B1~0394t-n03B1
= P -tn .p.
Thus we deduceAs we have
tn039403C9,
=039403C9 ~ 0394t-n,
weget
Using
the W-invarianceof ch(l(p - 1)p),
weget
By passing
to the limit wefinally get
Thus Assertion
(2.4.1)
isproved.
Moreover(2.4.2)
follows from(2.4.1)
andLemma 1.9.
COROLLARY 2.5.
(2.5.1)
We havech(lQ(-03C1)) e-03C103A003B1~0394+re1/(1- e-a).
(2.5.2)
The restricted Wakimoto moduleW-p of highest weight -p (as defined
in
general by Feigin
and Frenkel[FF1], [FF2])
is irreducible.Proof. Inequality (2.5.1)
follows from Lemma 2.4.2 and thesemicontinuity principle. By
constructionW-03C1
containsl(-p)
assubquotient
and its character ise-PIIaEO é 1/(1 - e-a) (see [FF1], [FF2]).
Thusinequality (2.5.1) implies
thatW-03C1
issimple.
D3. The second
inequality
LEMMA 3.1. Let a E P. The we have
ch(lQ(03BB)) ch(l(03BB)).
Proof.
Setlz(A)
=Uz .V,B.
It is clear thatlz(A)
is aUz-invariant
lattice of1Q(A).
It is clear thatl(A)
is aquotient of k 0 lZ(a).
Thus weget
theinequality
(3.1).
aReferences
concerning
next lemma aregiven
in the introduction. Inparticular
it follows from the construction of the restricted Wakimoto module
W-03C1.
LEMMA 3.2.
[Wk], [GW], [Ku], [H], [FF3].
We have
Ch(iQ( -p)) 5 e-03C103A003B1~0394+re1/(1 - e-a).
312
LEMMA 3.3.
(Second inequality)
(3.3.1) We have ch(l(-03C1)) e-03C103A003B1~0394+re1/(1 - e-a).
(3.3.2) We have ch(l(p-1)03C1) e(p-1)03C103A003B1~0394+re(1 - e-p.03B1)/(1 - e-03B1).
Proof. Inequality (3.3.1)
follows fromLemmas 3.1
and 3.2.Inequality (3.3.2)
follows from
inequality (3.3.1)
and Lemma 1.8. 0 Both Theorems follow from Lemmas 2.4 and 3.3.Ackowledgements
We thank M.
Duflo,
E.Frenkel,
V. G.Kac,
F. Malikov and M. Wakimoto for instructive discussions.References
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