• Aucun résultat trouvé

Free subgroups of the orthogonal group

N/A
N/A
Protected

Academic year: 2022

Partager "Free subgroups of the orthogonal group"

Copied!
4
0
0

Texte intégral

(1)

C OMPOSITIO M ATHEMATICA

J. DE G ROOT T. D EKKER

Free subgroups of the orthogonal group

Compositio Mathematica, tome 12 (1954-1956), p. 134-136

<http://www.numdam.org/item?id=CM_1954-1956__12__134_0>

© Foundation Compositio Mathematica, 1954-1956, tous droits réser- vés.

L’accès aux archives de la revue « Compositio Mathematica » (http:

//http://www.compositio.nl/) implique l’accord avec les conditions gé- nérales d’utilisation (http://www.numdam.org/conditions). Toute utili- sation commerciale ou impression systématique est constitutive d’une infraction pénale. Toute copie ou impression de ce fichier doit conte- nir la présente mention de copyright.

Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques

http://www.numdam.org/

(2)

Free

subgroups

of

the orthogonal group

by

J. de Groot and T. Dekker

1. Let Gn be the group of all proper

orthogonal

transforma- tions in Euclidean space En

(therefore represented by

real or-

thogonal

n-matrices

(aik)

with determinant

+ 1).

We shall prove in this note

- using

the axiom of choice -, that for n &#x3E; 2 G"

contains a free

(non Abelian) subgroup

with

just-

as many

freé generators

as the

potency

of Gn itself

(which

is the

potency

of real

numbers).

The theorem is clear, if we can prove it for G3.

Hausdorff [1]

showed how to find two rotations f/J and 03C8 in G3 which are

independent except

for the relations

rp2 = 1p3

= 1.

Robinson

[2]

showed that rp1J)(fJ1p and

~03C82~03C82 generate

a free group of rank two. Since any free group of rank two contains a

subgroup

of

rank Ko (comp.

Kurosch

[3] f.i.),

it is

already

clear that G3 contains a free

subgroup Go

with an

infinite,

but countable number of free

generators.

Thèse results are used

essentially

to prove certain theorems

concerning

congruence relations for subsets of a

sphere (comp.

f.i. Hausdorff

[1],

Robinson

[2],

Dekker and de Groot

[4]).

The

rotationgroup G2, being commutative, obviously

does not

contain a free non Abelian

subgroup.

Moreover the group

o f

all

congruent mappings of

E2 on

itself

does not contain a

free

non

Abelian

subgroup. Indeed,

suppose the

congruent mappings

ce

and P generate

a free

subgroup.

Then ex,2 and

P2

are rotations or

translations. It follows that y and 03B4 defined

by

are

translations,

whieh

yields

to

=

ôy.

Hence there exists a

non-trivial relation between oc and

03B2, q.e.d.

2. LFMMA. Let F =

{f03B1}

be a

family o f potency

F x

of functions f03B1(x1,

x2, ...,

xn) ~

0 each

analytic (in

terms of power-

series)

in its n real variables xi. Then there are real values ai

(i

= 1, 2, ...,

n),

such that

f03B1(ai)

=1= 0

for

any

fa.

E F.

(3)

135

PROOF. For n = 1 the lemma is trivial. Consider

f03B1(x1, ..., xn )

for a fixed a and for

0 ~ xi ~

1. There is

only

a finite number

of values x1 = b such that for a fixed b :

Irx (b,

x2, ...,

xn )

~ 0

(otherwise

the

analytic

function of one variable

f03B1(x1,

c2, C3, ...,

cn)

should vanish

identically

for fixed but

arbitrary xi

= ci

(1 i ~ n ).

From this follows

f03B1(xi) ~ 0 ).

For each a we leave out this finite number of values xi. Because F s there remains a number xl = al such that for each a:

f03B1(a1,

x2,

..., xn) ~

o.

This is for any a a function of n - 1

variables, satisfying

the

conditions of the lemma. Hence we find

by

induction: there are

real values

a;(1

= 2, ...,

n )

such that

f03B1(a1,

a2,

..., an )

~ 0 for

any

f03B1

E F

q.e.d.

3. THEOREM. The group Gn

of

all rotations

o f

n-dimensional Euclidean space

(n

&#x3E;

2) for

which the

origin

is a

f ixed point

con-

tains a

free (non Abelian) subgroup

with N

free generators.

PROOF. We have to prove the theorem for G3. Let

Go

be defined

as in 1.,

Go being

a free

subgroup

of G3 with rank Mo. We shall prove

by

transfinite induction the existence of a free

subgroup

of

rank X.

Suppose

that for a certain limitnumber « roN

(the

initial-

number

of M)

the groups

G03B2, 03B2

a are

defined,

where

G03B2

is a

free

rotationgroup with M. + 03B2

free

generators

such that

Moreover we assume that for

any P

oc,

the 0 + 03B2

+ 1 free

generators by

which

G03B2+1

is defined consist of

thé Ho + 03B2

free generators of

G03B2 (by

which

G03B2

is

defined)

to which one new

generator

is added.

Now it is

clear,

that for a limitnumber oc the sum

U Gp

=

G(1.

is a

f ree

group. Indeed the

generators

are the union of the

already

defined

generators

of

Gp, f3

a; a relation

(between

a finite

number of

generators)

in

Ga

is

already

a relation in a certain

G03B2

and therefore a trivial one. The theorem is therefore

proved,

if -

given

a certain

G03B2 -

we may define a

rotation y

such

that the

Xo + 7

free

generators

of

G03B2 together with X

are free

generators

of a group

G03B2+1.

A non-trivial relation in

G03B2+1

may be written

(after simplifica- tions)

in the form

(1) g1Xj1 g2~j2

...

gr x’r

= 1

(jl integer,

g, E

G03B2).

We must find a

rotation x

for which no relation

(1)

is true.

(4)

136

Consider a fixed relation

(1).

The g, may be

represented by

matrices with known elements:

The unknown Z can be

expressed

like any rotation under con- sideration as a

product

of three matrices:

(03BE1, E2’ e3

are the so called

angles

of

Euler). Using

the substitutions

(2)

and

(3)

we

get

relation

(1)

in matrixform. This leads to a

finite number of

equations

in the real variables

03BE1, 03BE2, e3.

We show first that at least one of these

equations

does not

vanish

identically (for

all values of

$1, E2, e3).

Indeed the g,

(l

=

1, 2, ...,

r)

of

(1)

may be

expressed uniquely

in a finite number of free

generators

of

G03B2.

If we substitute in

(1) for ~

a free

generator

of

G03B2

not

occurring

in one of these

expressions

gl, the relation

(1)

is

certainly

not fulfilled

(since G03B2

is a free

group).

At least one

of the mentioned

equations

is therefore untrue for well chosen

numbers 03BE1, 03BE2, 03BE3.

We call this

equation

in

03BE1, 03BE2, e3

an

equation

connected with

(1).

The total number of relations

(1)

with

variables

gi ~ G03B2 and i,

has

clearly

a

potency

less

than s.

The

number of connected

equations f03B1(03BE1, e2, 03BE3)

= 0 has therefore

a cardinal less

than s.

From

(3 )

it follows that the

f03B1

are

analytic

in the real variables

03BE1, E2, e3.

Therefore we can

apply

the

preceding

lemma. This

gives

real values a1, a,2, a3 with

1,,,(al,

a2,

a3)

~ 0 for

any oc. The

corresponding ~ (substituting

ai

= Ei

in

(3))

therefore

does not

satisfy

any relation of the form

(1),

which we had to

prove.

REFERENCES HAUSDORFF, F.

[1] Grundzüge der Mengenlehre (1914), p. 4692014472.

ROBINSON, R. M.

[2] Fund. Math. 34 (1947), p. 246-260.

KUROSCH, A. G.

[3] Gruppentheorie, Berlin (1954), p. 274.

DEKKER, T. and DE GROOT, J.

[4] Proc. Int. Congr. Math. (1954), II, p. 209.

Institute of Mathematics

University of Amsterdam.

(Oblatum 18-9-54)

Références

Documents relatifs

An algebraic proof of the fact that Artin braid groups are torsion free was given in [3].. The aim of this note is to observe that the proof of [3], which uses group pre- sentations

Given a subgroup H of G , Linnell's result can be generalized as follows: the pair (G, H) splits as a nite graph of groups with nite edge groups such that each vertex group is nite

Free entropy dimension and the orthogonal free quantum groups..

Free entropy dimension and the orthogonal free quantum groups..

On the adjoint representation of orthogonal free quantum groups.. Roland Vergnioux joint work with

The conditionnaly negative type function associated to c X is the one associated to Brannan’s deformation. In particular the cocycle arising from Brannan’s deformation can be

Free entropy dimension and the orthogonal free quantum groups..

Then one can relate the stabiliser of X to the stabiliser of the attractive lamination (see Theorem 4.2), and later conclude using the fact proved in [2] that the stabilizer of