A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
L. A. C AFFARELLI
N. M. R IVIÈRE
On the rectifiability of domains with finite perimeter
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 3, n
o2 (1976), p. 177-186
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On the Rectifiability of Domains with Finite Perimeter.
L. A. CAFFARELLI
(*) (**) -
N. M.RIVIÈRE (*) (***)
In the
study
of free boundaries in variationalinequalities
it arisesnaturally
thequestion
ofregularity
of domains with finiteperimeter
in thesense of
Caccioppoli [1]
and DeGiorgi [3].
In twodimensions,
forinstance,
with the
rectifiability
of thetopological boundary
of suchdomains;
whichwe prove in the context of this paper; the tools
developed by
H.Lewy [6],
and H.
Lewy
and G.Stampacchia [7]
can be utilized to show furtherregularity
of the freeboundaries,
see[7], [5], [2].
The domains inquestion usually verify
thefollowing
two conditions:(A)
The interior of itscomplement
iscomposed
offinitely
many connectedcomponents. (B)
Thepoints
in theboundary
of the domain areof uniform
positive density
withrespect
to the interior of itscomplement,
see
[2].
In the two dimensional case either conditionyields
the rectifia-bility
of the domain. In the notation ofgeometric
measuretheory (1)
ourresults prove that the irreducible currents associated with are the
boundary
curves of the connectedcomponents
of E. In the n-dimensionalcase condition
(B) implies
theadditivity
of theperimeter
of ,S~ in terms of its connectedcomponents.
Domains with finite
perimeter.
Following
the notation of DeGiorgi [3],
set(*)
School ofMathematics, University
of Minnesota(**)
The author wassupported by Consejo
deInvestigaciones
Cientificas y Tecnicas,Argentina.
(***)
The author waspartially supported by
N.S.F.grant
G.P. 43212.(1)
H. FEDERER, Geometric MeasureTheory,
p. 421,Springer Verlag,
1969.Pervenuto alla Redazione il 22 Gennaio 1975 e in forma definitiva il 4
Agosto
1975.12 - Annali della Scuola Norm. Sup. di Pisa
If XE denotes the characteristic function of
E,
we define itsperimeter
asIn
[3]
it is shown that if is a sequence ofpolygonal
setsconverging
in measure to
E,
thenMoreover when E has finite
perimeter
there is a sequence ofpolygonal
domains
~~n~,
such that nn converges in measure to E andDenote with CE the
complement
of E and withEo
its interior.m(E)
will denote theLebesgue
measure, for a measurable set E.LEMMA. I. Let Q be an open set
of finite perimeter.
The sequence,of polygonal
domainsconverging
to Q in measure andapproximating
its per- imeter can be chosen so that:(i) If .g1
andX2
arecompact sets, .g1
andX2
c(eQ)O; then, for X1cnn
andX2c(enn)o.
(ii) I f m ( ~x,
when denotes theboundary of Q),
e eo, and a > 0independently of
e and xo; then 7rn c c Q.PROOF. We follow the construction of De
Giorgi [3]
of apolygonal
sequence of
functions, ~gk~,
defined from .Rn into R such that ifthen
(b)
Whenc 1 /k.
Here 4 denotes the sym- metricdifference;
A A B =(A
nB’ )
u(A’
mB).
Observe
that,
in virtue of(b)
and aprevious remark,
lim for081.
179
On the other
hand, by
Fatou’s lemma and(a),
Therefore
S(Q)
=lim (!k(O)
in a setE, m(E
n(0, 1))
= 1.Given n,
chooseA~
so small that n when x Eg2
and~ 1- r~
whenxEKI.
Then if we choose7tk(O)
such that 0 E(2~, 1 - q )
n Eand
part (i)
follows.To prove
part (ii),
observe first that when0:
uniformly
for Observe also thatWÂX.o(x)
satisfies the heatequation
in the(z, I) variables,
when moreover forsuch x,
0+ as 1 - 0+.
Therefore, by
virtue of the maximumprinciple WÂXn(x),
x ECS2,
must reach its maximum at apoint (XO,
withThat is
a’
1 when(x, A)
E CQ X(0,
Choose 0 E .E r1
(a’,1) ;
in virtue of the observationsabove,
fornl large enough Using part (i)
of the lemma we can choose n2;by
inductionpart (ii)
follows.LEMMA II. Let Q c
1~2, be a
bounded open set such that(a)
8Q =(b) C(Q)° = U D,, Di connected. If further T(S2) 00,
then theboundary of
each
of
its conneetedcomponents is
aceessibZe.Moreover, if
C is a connectedcomponents of Q, given converging
to x, x Ea C,
there exists a Jordanarc,
[0, 1) ~ C,
and asubsequence
such thatr(tk)
= xnx and t ~ 1-.PROOF. Let xo E
aC,
setBk(xo)
={x, Ix
-zo[ l/k}. Take xnl
E r1 Cand let
Sl
be the collection ofpolygonal
curvesjoning xnl
withLet a = inf
~d(l~’),
T eS,}, d(-)
denotes the diameter of the set.Choose rl,
yjoining Xnl with Xn2’
such that2a, Xn2
EB2(xo)
r1 C.Repeating
the aboveargument inductively
we obtain a sequence ofpoly-
gonal
curves,Xn1c
with suchthat,
andak The lemma follows if we show that CXk - 0 as k ~ 00 :
We argue
by contradiction;
suppose there exists a sequence,~ak~,
suchthat E
Bk(x°)
r1 C. Considerko
solarge
that thenxnk’
belong
todifferent components
of If other-wise,
Xnkand x., belong
to the same connectedcomponent,
thend(F,)
E,contradicting
the fact that CXk > E.Call
~7~
the connectedcomponent
of C r1{x, jx
-xo E} containing
k > Again by
virtue of the fact thatd(rk)
> E,{x, = s f4) /
0.Let
hk
be apolygonal
arcjoining
Xnk with apoint
of{x, Ix- xol =
Set and T, from
[o, 2~) onto S,
the standardtransformation into
polar
coordinates. Observe that when EEkl, y~/2,
there exists0 ; 0,. 0 0,;
On the other hand if n(~S~)° _ ~
andS’t
n(CS2)0
=ø,
rie/2;
since 8Q =there exists a connected
component
ofDi,
By hypothesis
there are at mostm+1
radii such that,Sr
n 0.Finally
we restrict our attention to a finite number ofpolygonal paths P,,
dividing
the set into N different re-gions.
In eachregion
we can construct acompact
setgt composed
of radialsegments K, c (CQ)°,
such that theperimeter
of the circularprojection
ofKi
into a
given
radius exceedse/16. By
Lemma I we may choose nn; such thata consequence, on each
region
theperimeter
of must exceede/16
and therefore > NE/16.
This contradicts our
hypothesis
on the finiteness of theperimeter
of S2 andthe lemma follows.
REMARK I. Let Q be as in Lemma
II,
thenCj
r1Ck
consistsof
at mostpoints.
PROOF. If two
points belong
to the commonboundary
ofC,
andC,
thereare two Jordan arcs,
by
virtue of LemmaII,
thefirst joining
them inC~
thesecond in
Ck. Together they
form a Jordan curve whose interior must con-tain a
component
of since 8Q =8C(Q)°.
REMARK II. Under the
assumptions o f
Lemma II theboundary of
eachof
the connectedcomponents, C~ , of
,S2 iscomposed of
at most m Jordan curves.PROOF.
Clearly
iscomposed
of at most m connectedcomponents.
Let
E1
be the unboundedcomponent
of and C* = then(i) C, c C*; (ii) (iii)
C* is connected andsimply
connected.In virtue of Lemma II every
prime
end» of C* consists ofexactly
one
point
which is asimplepoint,
since 00* =oE1.
As a consequence8C*
is a Jordan curve
(see [8],
Secs. 7 and8).
The othercomponents,
reduce to the above case
by
an inversionmapping.
Next we will
« separate »
two connectedcomponents, Ci
andO2,
of S~by
a Jordan curve contained in
C(Q)°
and a finite number of small balls.By
RemarkII, given s > 0,
there are at mostm+1 balls,
9of radius E such that if
181
LEMMA III. With the above
notation,
let E be a connectedcomponent of C2.
There exists a
f inite
nmberof
ballsfB,,},
at most m+ 2, of
radius less than 8 such that(i) Bk
n E =ø, (ii)
There exists a Jordan curve,r,
contained inseparating from
E.PROOF. In virtue of Remark I we may assume that
O2
is contained in the exterior of the exterior Jordan arc ofCi (applying
an inversion ifneeded).
We may cover the finite holes of
C1
and assume that01
is connected andsimply
connected. Since
Cl
r1 E= 0,
we may choose6,
such that if x cCl,
9 y EE, [x- yj>2~.
Consider since aS2 = then xo E Observe that if then for
any 6 > 0
there exists apolygonal
arc, y, con- tained inDl
andconnecting {~
with{x, ~x - z ~ C ~~ .
On theother hand the
points
zo and z divide theboundary
ofCi
into two Jordanarcs, and 1’". Note that
either y together
with r’ and both ballsseparates
T"from E or
else y together
with .1"’ and both ballsseparate
from E.Parametrize
8Ci
with{Z, iz I = 1} = SI-9 F(81)
=aC2, f ($,,)
= XO.Using
the above
argument
let ul be the endpoint
of thelongest
arc, to the left of~o,
such that for z in the open arc,
(i) F(z)
E(ii)
isseparated
from Eby
thecorresponding
arc y, thecomplementary
arc of ina C1
and theballs
{x, ix - x,, I 6{, {x, ~x - z ~ ~~ .
As a consequence is sepa- rated from Eby
an arc c thecomplementary
arc of andtwo balls of radius 2b centered at xo and
F(ui).
It follows from the construction that either UI =
$0,
and the lemmafollows,
or else If werepeat
the construction induc- tioninductively
after at most m+1 steps, ~o
and theseparation
process is
completed.
00
THEOREM I. Let Q be as in Lemma
II,
thenif ~J C;, C;
connectedcomponents
;=1(ii) composed of
af inite number,
at most m,o f rectifiable
Jordancurves,
r;k,
andk
PROOF. To prove
(i)
weseparate, recursively,
eachcomponent
from allthe others
using
Lemma III.Let Xl E
01,
x2 EO2,
in virtue of Lemma III we may select afamily
ofballs,
radius less than El and a Jordan curve,h,
such thatseparates
where denotesthe connected
component
of(B))°) containing
z;.k
As a consequence of Lemma
I,
we may choose apolygonal
domain ap-proximating
suchthat;
and where.g1
is acompact
set of connected
interior,
Next we «
separate» Ci
fromO2
and03 by
the above processremoving
at most 4m
+
6 balls of radius less than E2; and so on. In this fashion weconstruct a sequence of
polygonal domains,
associated to the sequence En,sn - 0
as n - oo and to the sequenceKncn:,
whereC(Kn)) -> 0
If
Bn
denotes the connectedcomponent
ofn£ containing gn
observethat,
by construction,
On the other handm(C,,
r~C(Bn)) m( 01
r1 ~0,
as n - 00.Hence,
sinceA S2) --> 0,
we have
Cl)
- 0 and m([ U C;] A [n£
n -0,
asTherefore
NACII)
->0 m(I j->2
nthat is
On the other hand the
sublinearity
of theperimeter yields
=S( Ci) + + T( U C;)
andproperty (i)
followsby
induction.;~2
To
complete
theproof
we analizea C1.
Note that
aC,,
iscomposed
of at most m Jordan curves,1’?,
two ofwhich intersect in at most one
point. Adding
to01
at most mballs,
of radius el we may «
separate »
all the Jordan curves in thefollowing
sense :let
A;
be a connectedcomponent
ofC(C1)°, Fj
= if,C11= 01 U U
x.Bk
and
XiEAi,
we may select apolygonal approximation,
a., ofC11
such thateach xj belongs
to different connectedcomponents
of Weproceed inductively
to construct a sequence(xn)
associated to sn, en ~ 0Let x£
be thesimply
connected closure of nn(i.e.
the set ofpoints
thatcan not be
joined
toinfinity
withoutcrossing n’). Clearly ~’(~n) c ~’(~n) c
-E- bn -
Let D =
11
cC,
andf n
the conformalmapping
from Donto 7r,*
such that = XO. If
H1(D)
denotes the space ofanalytic
functions on Dwhose Ll-norm over circumferences of fixed radius remains
uniformly
183
bounded
(see [9]),
thenTherefore
and,
since = xa, in virtue of Harnack’s Theorem there exists asubsequence (which
wereadily
suchthat
f n
converges to a limitf, uniformly
inD. By
Fatton’s lemmaAt this
point
we make use ofCaratheodory’s Theorem, (see
Theorem 2.1of
[8])
and choose our so thatf
is a conformalmapping
from Donto the kernel of the said sequence, see Def. on pg. 33 of
[8].
In virtue of Lemma
I, Gxp
= whereA1
denotes the unboundedcomponent
of HenceTo
complete
theargument,
for each xj EA;,
consider the connectedcomponent
ofC(nn)° containing
x f,T;n,
form itssimply
connectedclosure,
T~ ,
thenrepeating
theargument
above it follows thatlength (1 ~’3 )
Therefore,
sinceT(n*) + I T(an)
and -~(Ol),
as n - oo, wehave
(1-’f).
Finally 01
is a connected domain boundedby
at most m rectifiable Jordancurves and the converse
inequality
followsrestricting
the conformalmappings
to subcircles of radius less than one.
REMARK. Under the
assumptions of
LemmaII, if
insteadof
thearguments of
Lemmas II andIII, together
with Theorem Iyield
that : and hence the conclusions
of
Theorem I remain valid.LEMMA IV. Let Q c
Rn, be
a boundedregion
with connectedcomponents a i ;
00
Q
= U
Assume thatT(S2)
and that there exists a sequenceof poly-
i=i
gonal regions, n, increasing (i.e.
nn c 7Tn+l co)
such that r1 0and -+ as n -* c>o. Then
i’he sequence can be constructed under condition
(ii) of
Lemma I.PROOF. Let
Bn
be the union of the connectedcomponents
of contained inCi . Clearly m(C1 n ~Bn) ~ 0
andm U Cj u Bn) - 0,
as n -~ oo ;hence j->2
that is
00
Inductively,
it follows thesubadditivity
of the per- imeter proves the theorem. ’ =1THEOREM II. Consider Q c
R2,
open, such thatif
x EaS2, + Be)
nam (B. .),
where 0 a 1 isunif orm for
x E aS2. Writevv
Cj
connectedcomponent ;
thenT(S2) = i
Moreover i’where i=i
(a) Fjk
is arectifiable
Jordan curve and(b)
the setof
limitpoints of (i.e.
x EEi iff
x+ Be
intersects in-finitely
manyh;k
andU Fik)
andH,,(E)
=0, H1(.) represents
the onek
dimensional
Hausdorff
measure.PROOF. In virtue of
(ii),
LemmaI,
the firstpart
of the theorem follows from Lemma IV.To
study
theboundary
ofCj
we set =S2 then, by
the assump- tion madeon 92,
it follows that(C£5)°
= i Observe that =0,
sinceand,
ifm((x + Be)
r~S~) -~- m((x + Be)
n(CS2)0
=m(Be).
that is 8Q is contained in the subset of Q of
points
ofdensity
less than one and hence of measure zero. ThereforeaC;
=8£5
is a set of measure zero. In consequence =S(£5).
But
Q
satisfies the conditions of Theorem II and hence ifU Dlk
k
Dik
connectedcomponents; adik
is a rectifiable Jordan curve;(1-’;k).
k
Finally
if.Ej
is the set of limitpoints
of thefamily
is acovering by
balls of radius less than e, we may divide thefamily
into foursubfamilies {Ufllflc-f,
where all the balls aredisjoint. By assumption
m( Up
n >exm( Up).
On the other handf2 D Then,
for eachfl,
185
either:
(ii)
There exists such that thelength
of isgreater
than orequal
toObserve
that,
if(i) holds,
theisoperimetric inequality
of deGiorgi; [3],
Theorem
VI; yields aj2r2( Up) )C( I (j’2(Dik))’
Therefore in either case~ r ( U~ ) c C~ ~ and,
sinceN~ -
oo as 8 -0,
the theorem follows.Finally,
wepresent
afamily
ofsimple examples showing
that thehypo-
theses of theorems I and II are essential either for the
additivity
of the per- imeter or for therepresentation
of thetopological boundary
of the set.Consider two squares,
Ci
andC2, with
a commonside, I,
and from such side removecountably
manydisjoint balls, ~8~~,
the sum of whoseperimeter
is as small as we
please
and such thatSet i
then
In the same
fashion, placing countably
many balls on the curvesy = x sin
(1/x)
or y = sin(1/x)
we can construct domains S~ such that S~ isa
connected, simply
connected open set of finiteperimeter,
y 3~ =and,
in the firstexample,
itsboundary
is a non rectifiable curve. In the secondexample,
theboundary
is not even a curve.REFERENCES
[1] R. CACCIOPPOLI, Misura e
iutegrazione sugli
insiemi dimensionalmente orientati, Rend. Accad. Lincei, Cl. Sc. fis. mat. nat., SerieVIII, 12,
fasc 1, 2(gen.-feb. 1952),
pp. 3-11, 137-146.
[2] L. A. CAFFARELLI - N. M.
RIVIÈRE,
Smoothness andanalyticity of free
boundariesin variational
inequalities,
Ann. Scuola Norm.Sup. Pisa,
serie IV,3,
pp. 289-310.[3]
E. DE GIORGI, Su una teoriagenerale
della misura(r - 1)-dimensionale
in unospazio
ad r dimensioni, Annali di Matematica pura edapplicata,
SerieIV,
36 (1954), pp. 191-213.
[4] E. DE GIORGI, Nuovi teoremi relativi alle misure
(r
-1)-dimensionale
in unospazio
ad r dimensionali, Ricerche diMatematica,
4(1955),
pp. 95-113.[5]
D. KINDERLEHRER, How a minimalsurface
leaves an obstacle, Actamathematica,
130(1973),
pp. 221-242.[6]
H. LEWY, On minimalsurfaces
withpartly free boundary,
Comm. PureAppl.
Math., 4