A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
S UNG J. L EE
M. Z UHAIR N ASHED
Algebraic and topological selections of multi-valued linear relations
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 17, n
o1 (1990), p. 111-126
<http://www.numdam.org/item?id=ASNSP_1990_4_17_1_111_0>
© Scuola Normale Superiore, Pisa, 1990, tous droits réservés.
L’accès aux archives de la revue « Annali della Scuola Normale Superiore di Pisa, Classe di Scienze » (http://www.sns.it/it/edizioni/riviste/annaliscienze/) implique l’accord avec les conditions générales d’utilisation (http://www.numdam.org/conditions). Toute utilisa- tion commerciale ou impression systématique est constitutive d’une infraction pénale.
Toute copie ou impression de ce fichier doit contenir la présente mention de copyright.
Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
of Multi-Valued Linear Relations
SUNG J. LEE - M. ZUHAIR
NASHED1
1. - Introduction
In this paper we
develop
acomprehensive theory
ofalgebraic
andtopological single-valued
linear selections of a multi-valued linear relation.Let
X, Y
be(real
orcomplex)
vector spaces. A vectorsubspace (or simply
a
subspace,
or a linearmanifold)
M of X x Y is called a linear relation. Weidentify
M also as the"graph"
of a multi-valued linearmapping
definedby M(x) := {y : (x, y)
EM}
whereDom M,
the domain ofM,
consists of thosex E X such that
M(x)
is not empty. The null space and the range of M aredenoted
by
Null M andRange M, respectively.
Thegraph
inverse of M isdenoted
by M-1.
If Z is another vector space and S is a linear relation in Y x Z, then thecomposition
,SM is definedby
Let M be an
arbitrary,
but fixed linear relation in X x Y. Analgebraic
operator part(or algebraic selection)
R of M is(the graph of)
asingle-valued
linearoperator
with Dom R = Dom M such that R C M.Equivalently,
R = Null Pwhere P is an
algebraic projector (i.e.,
a linearidempotent operator)
of Monto
Moo
:={0}
xM(O).
If P satisfies the extra condition P(x, 0) = (0,0)
for all x ENull M,
then R is called aprincipal algebraic operator part Qf
M.Equivalently,
aprincipal algebraic operator
part is analgebraic
selection R such that Null R = Null M. If X and Y are normed linear spaces, then analgebraic
selection
(resp.,
aprincipal algebraic selection)
R of M is called atopological
operator part or
topological
selection(resp.,
aprincipal topological
operator part orprincipal topological selection)
of M if the associatedprojector
1? iscontinuous. ’
We now describe
briefly
the contents of this paper. In§2
wedevelop
the
theory
ofalgebraic
linear selections of linear relations. In§3
westudy
Pervenuto alla Redazione il 25 Maggio 1988 e in forma definitiva il 22 Luglio 1989.
1 Research was partially supported by a grant from the United States Army.
topological
andw*-topological
operator parts and some invariantproperties.
Unlike
algebraic operator
parts,topological operator
parts do notalways
exist.Moreover,
the existence of atopological
operator part ofM-1
does notimply
the existence of a
principal topological
operator part ofM-1.
We will show that the latter situation never occurs when M issingle-valued.
The
theory
of linear relations in functionalanalysis
was initiatedby
vonNeumann
[ 11], [12].
In the case whenX, Y are
Hilbert spaces and M isclosed,
Arens[ 1 ]
was the first to note that is asingle-valued
selectionof M.
Coddington
andDijksma [3] generalized
thisconcept
to a Banach spacecase: If M is
closed,
then a vectorsubspace
R of M is an"operator part"
ofM if R is a
single-valued,
closed and M is the direct sum of R andMoo.
We have extended this concept to the case when M is notnecessarily
closed. Our definitionrequires only
the use of continuousprojectors.
The
study
of multi-valued operatorequations (inclusions)
hasgained
considerable
importance
in recent years due to theincreasing
occurrenceof multi-valued linear or nonlinear
mappings
in various areas ofanalysis,
differential
equations,
continuummechanics,
controltheory,
and mathematical economics. Various results on(single-valued)
selections of multi-valued nonlinear relations have been obtainedby
manyauthors,
such as Michael’s continuous selectiontheorem, Caratheodory-type
selectiontheorems,
measurableselections,
minimalselections,
etc.(See,
e.g., Aubin and Cellina[2]
and related references citedtherein).
The selection theorems for nonlinear relations do notprovide
much information aboutalgebraic
andtopological
linear selections for multi-valued linear relations. The results of this papercomplement
and do notoverlap
withexisting
selection theorems in the literature.The authors express their
gratitude
to Professor Earl A.Coddington,
whoseinsightful
comments on an earlier draft of this paper have led to a considerableimprovement,
both in content andexposition.
2. -
Algebraic Operator
Parts of Multi-Valued LinearMappings
Throughout
thissection,
X and Y are(real
orcomplex)
vector spaces and M is a linear relation contained in theproduct
space X x Y. We denoteby Moo.
IfMl
andM2
aresubspaces of X x Y, Mi+M2 :=
ml C
Ml, m2
EM2}.
DEFINITION 2.1. A
subspace (a
vectorsubspace) R
of M is called a linear selection or analgebraic
operator part of M if Dom R = Dom M and R is thegraph
of asingle-valued
linearoperator
such that R c M.PROPOSITION 2.1. The
following
statements areequivalent: (i)
R is a linearselection
of
M.(ii)
R is asubspace
and M is the directalgebraic
sumof
Rand
Moo. (iii)
R = Null Pfor
somealgebraic projector
Pof
M ontoMoo.
PROOF. Assume
(i).
It is clear thatR4-Moo
is analgebraic
direct sum andthat M D Let
(x, y)
E M. Then(x, y) - (x, R(x)) _ (0, y -
E M.Thus
(x, y) = (0, y - R(x))
+(x, R(x))
EM,,.4-R.
Hence(i) implies (ii).
Assume(ii).
Then there exists analgebraic projector
P of M ontoMoo
such thatR = Null P . Thus
(ii) implies (iii).
Now assume(iii).
Then it is clear that R isa
subspace
of M and Dom M = Dom R.Suppose (0, y)
E R. Then(0, y)
E M and so(0, y)
EMoo. Therefore, I~ (o, y) - (0, y).
But(0, y)
E Null P. Hence P(0, y) = (0,0)
and so y = 0. Thus R issingle-valued.
Hence(iii) implies (i). n By
the aboveproposition,
analgebraic
selection R determines analgebraic projector
P, andconversely,
analgebraic projector
P of M ontoMoo
determinesan
algebraic
selection of M. For this reason, we will say that R isgenerated by
P, and denote itby Rp
to indicate itsdependence
on P - The existence of a selection is a consequence of the Axiom of Choice. A linear selection of Malways
exists sinceMoo
isalways algebrically complemented
in M, orequivalently
there exists analgebraic projector
P of M ontoMoo.
By considering
analgebraic
operator part of we caneasily
characterize all solutions of a linear inclusion. The
following proposition
isimmediate from the definition of an
algebraic operator
part.PROPOSITION 2.2. Let R be an
algebraic
selectionof M-1.
Then Dom R =Range M, Range R
c DomM.Moreover, (x, y)
E Mif
andonly if
y E
Range
M and x =R(y)
+ ufor
some u E Null M .In what follows we state results
mainly
foroperator parts
ofMT 1,
ratherthan M, since we are interested in
solvability
of linear inclusions and selection theorems for inversemappings. Analogous
results foroperator
parts of M followimmediately
from those forM-1 by replacing M-1 by
M, and Null Mby M(o).
A linear relation M may have "nonlinear selections". Forexample
ifM = X x Y, then every
single-valued mapping
with domain X and range in Y is a "selection" of M. In this paper we shallonly
be interested in linear selections of multi-valued linearmappings.
PROPOSITION 2.3. Let R be an
arbitrary algebraic
operator partof
Then M = MRM, and RMR is the direct sum
of
R and101
xRM(O).
Inparticular,
R is analgebraic
operator partof
RMR.PROOF. Take
(x, y)
E M. Then x =R(y)
+ u for some u E Null M. Inparticular, (y, x - u)
E R, and(x - u, y)
E M. Thus(x, y)
E MRM.Suppose
now
(x, y)
E MRM. Then(x, z)
EM, (z, h)
E R and(h, y)
E M for some z, h.In
particular, (h, z)
E M. Thus(0, y-z)
E M, and so(x, y) = (0, y-z)+(x, z)
E M.This shows that M = MRM. Take any
(y, x)
in RMR. Then(y, h)
ER, (h, z)
E M and(z, x)
E R for someh, z.
Inparticular (y, h), -(z, h), (z, x)
are in
M-1.
Thus(y, x)
This shows thatRMR c M-1.
Take any(z, x)
E RMR. Then(z, x 1 )
ER, (x 1, y)
EM, (y, x)
E R for some ziand
y.Then ,
(0, y - z) =
E M and(R(z), y)
EM,
x =R(y).
ThusR(z)
=R(y)+k
for some k E Null M. Hence x =
R(z) - k
=R(z)
+R(y - z).
Since y - z EM(O)
and x =R(z)+R(y-z),
we see that(z, x) = (z, R(z)+R(y-z))
EThus RMR =
({O}
xRM(0))+R. Clearly
thisalgebraic
sum is direct..REMARK 2.1. It is not
always
true that R = RMR for anyalgebraic operator
part R ofM-l (see Example
2.1below).
But theequality
holds if Mis
single-valued
or, moregenerally,
if R is aprincipal algebraic
operator part ofM-1
as defined below(see
Theorem2.6).
Suppose
now that P is analgebraic projector
ofRange
M ontoM(o)
and let P := 0 x P : M -~{0}
xM(O),
be definedby l~ (x, y) _ (0, P(y))
forall
(x, y)
E M. Then P is analgebraic projector
and issurjective.
Thus NullP =
{(x, y)
E M :P(y)
=01
is analgebraic
operatorpart
of M. This motivates thefollowing
definition.DEFINITION 2.2. R C X x Y is called a
principal algebraic
operator part of M if R :=f (x, y)
E M :P(y)
=0}
for somealgebraic projector
P ofRange
M onto
M(O).
To indicate thedependence
on P, we also write R =Rp.
REMARK 2.2. It is easy to show that R is a
principal algebraic
part of M if andonly
if R = Null P for somealgebraic projector
P of M ontoMoo
such that P
(x, 0) = (o, 0)
for all x E Null M.Equivalently, R
is analgebraic
selection such that Null R = Null M. It follows from the construction
preceding
Definition 2.2 that a
principal algebraic operator
partalways
exists. We will see soon that not everyalgebraic operator
part isprincipal.
THEOREM 2.4. Let R := Null P be an
algebraic
operator partof M-1,
where P is an
algebraic projector of M-1
onto{o} XNull M. Define
I~ 2by
P
(y, X) = (0, P2(y, x)), for
all(x, y)
E M. Then we have thefollowing:
(i)
Null R ={y
EM(o) : 0)
=0}
cM(o).
(ii)
Null R =M(O) if
andonly if
the mapQ defined by Q(x)
=x), (x, y)
E M, issingle-valued. Equivalently,
R is aprincipal algebraic
operator partof
.(iii) If
M is asingle-valued,
then everyalgebraic
operator partof M-1
is aprincipal
operator partof
PROOF.
(i)
is easy to check.(ii)
Assume that Null R =M(O). Suppose
that
(x, y), (x, z)
are in M. Then(0,
y -z)
E M, and soP2(y, x) - X) = p2(y - z, 0)
= 0. ThusQ
issingle-valued. Conversely,
suppose thatQ
issingle-
valued. Let y E
M(O),
sof y, 0} E M-1.
Since(0,0)
EM-1,
0 =Q(O) = JP2(y, 0).
Thus y E Null
R,
and so Null R =M(O).
This proves the firstpart
of(ii).
Thesecond part of
(ii)
then followsimmediately
from Remark 2.2.Finally, (iii)
isan immediate consequence of
(i)
and(ii). ·
Note that the converse to
part (iii)
of Theorem 2.4 is false: Let M =(0) x S,
where S is any
subspace.
ThenM-1
1 is the zerooperator
with domain S. Thus(trivially)
everyalgebraic
selection ofM-’
isprincipal,
but M is notsingle-
valued.
EXAMPLE 2.1. In this
example,
there exists aunique principal algebraic
selection and all other selections are
nonprincipal.
Let M ={(x, x+a) :
x, aThen Null M = Dom M =
Range
M = X. Thus anyalgebraic projector
of DomM onto Null M is the
identity
operator.Consequently,
theonly principal
operator part ofM-1
1 is the zero operator on X. Now let P :M‘1 ~ {0}x
Null M bedefined
by
P(x, x
+a) = (0, a) for x,
a E X. Thenp 2
= P and P is onto; thusRp
:= Null P ={(x, x) : x
EX}
is analgebraic
operator part ofMoreover,
the inclusion
Rp
cRp MRp
is proper andRp
M is notsingle-valued.
Noticethat
Rp
is one-to-one eventhough
M is notsingle-valued.
Thisphenomenon
contrasts with the fact that a
principal algebraic
selection ofM-1
is one-to-oneif and
only
if M issingle-valued (see below).
REMARK 2.3. Let R be a
principal algebraic
operator part ofM-1.
Then Null R =M(0). Consequently, R
is one- to-one if andonly
if M issingle-valued.
We now
investigate
the structure,form,
and distinctiveproperties
ofprincipal algebraic
operatorparts (Theorems 2.6, 2.5,
2.7 and2.10; Proposition 2.11;
andCorollary 2.12).
Thegraph
of an operator A will be denotedby
and the restriction of a relation M to a set ,S will be denoted
by Mis.
THEOREM 2.5. Let R :=
{ (y, x) : (y, x)
EP(x)
=0},
where P is analgebraic projector of
Dom M onto Null M. ThenRange R
=Dom Mn Null P,
and R =[gr(I-P)IM-1.
Moreover,if
M issingle-valued,
then R =(MINull P)-l.
PROOF.
Clearly Range R
= Dom Mn Null P. Take any(y, x)
E R. Then(x, y)
E M andP(x)
= 0. NowP(x)
= 0 if andonly
if x =(I - P)(z)
for somez as the range of I - P is Null P. Thus
(y, x) = (y, z - P(z)), and,
sinceP(z)
ENull M, (y, z)
But then(z - P(z), y)
E M andP(z - P(z))
= 0. This shows that R = The last part of the theorem is obvious.THEOREM 2.6. Let R be an
algebraic
selectionof M-l.
Then thefollowing
are
equivalent: (i)
R is aprincipal algebraic
selectionof M-’. (ii)
RM issingle-valued. (iii)
R = RMR.PROOF.
By Proposition 2.3,
RMR =7!+({0}
xRM(0)).
Inparticular, RMR(0)
=RM(0).
Thisimmediately yields
that(ii)
and(iii)
areequivalent.
Asume
(i).
Since R isprincipal, by
Remark2.3,
Null R =M(0).
But thenRM(O) = {R(z) : z
EM(0)} _ JR(z) : z
eNull R} - {0}.
Hence R = RMR.Assume
(iii).
Then(ii)
also holds. Thus RM issingle-valued.
Define Pby P(x)
= x -RM(x)
for x E Dom M. Thenby (iii),
P is analgebraic projector
of Dom M. We will show that
P)IM-’
= R.Clearly
=R. Take any
(y, x)
E Then(y, z)
E(z, h)
E M and(h, x)
E R for some z, h. Inparticular, y - h
EM(0).
ThusR(y - h)
= 0, and sox =
R(h)
=R(y).
Hence(y, x)
E R. Therefore R = RMR. This shows that R isprincipal
and so(iii) implies (ii). *
-REMARK 2.4. In the above theorem
RM(0) =
y EM(O)}.
Henceif M is
single-valued,
then anyalgebraic
selection ofM~
1 is aprincipal
selection. Thus there is a subtle
difference,
which heretofore seems to have beenundiscovered,
between selections of a multi-valued linearmapping
Mwhose inverse is
single-valued
and those of a multi-valued linearmapping
Mwhose inverse is also multi-valued.
THEOREM 2.7. Let R be a
principal algebraic
selectionof M-1 given by
Then MR ={(x,
x +s) :
x ERange M,
s EM(o)},
andRM =
(I - P)x) : x
EDom M } .
PROOF. Take
(x, y)
E MR. Then(x, h)
ER, (h, y)
E M. Thus x, y ERange M, h
=R(x)
=R(y)
+ k for some k E Null M. HenceR(x - y)
= k and sok = 0 as R is
principal.
Thus(0, x - y)
EM(O)
and so y = x + s for some s EM(O). Conversely,
suppose that x ERange M, s
EM(O) and y
= x + s. Then(0, x - y)
E M and so 0 =R(x) - R(y)
+ k for some k E Null M. But k = 0 ask E Null Pn
Range
P. ThusR(x)
=R(y).
Let h =R(x).
Then(x, h)
E R and(h, y)
E M and so(x, y)
E MR. This proves the statement about MR. Take any(x, y)
E RM. Then(x, z)
E M and(z, y)
E R. Thus x EDom M,
y ERange R, y
=R(z), x
=R(z)
+ u for some u E Null M. Then x = y + u. HenceP(x)
=P(y)
+ u = u as y ERange
Rn Null M. This shows that y = x -P(x)
and(x, x - P(x))
E RM. Butby
Theorem2.6,
RM issingle-valued.
Therefore(RM)(x)
= x -P(x)
for all x E Dom M. ~We remark here that the conclusions of Theorem 2.7 can be stated
equivalently
as 1 and RM CP).
This is insharp
contrastwith inner and outer inverses of
single-valued
linear operators(see [8]).
In some
applications,
it is notenough
to know one operator part ofM-1.
We may need to choose aparticular
selection which satisfies a certainpreferential
property, or to determine among alloperator parts
a selection that would minimize aprescribed operator
norm or that would have a minimalproperty
withrespect
to an inducedpartial ordering. Examples
of the first type include linearizedanalysis
in bifurcationtheory
and alternativemethods,
where aparticular
inner inverse is to be selected.Examples
of the second type arise in controltheory
and constrained minimizationproblems (see,
e.g.,[4], [6], [7]).
Often we are also interested indeterming properties (e.g., continuity, compactness, etc.)
that are invariant withrespect
to various selections ofoperator parts.
These considerationsrequire
that(i)
we obtain tractabledescriptions
andcharacterizations of all operator parts in terms of
a fixed
operatorpart,
and(ii)
wedetermine
relationships
between twooperator parts corresponding
to two distinctchoices of
projectors. Suppose
thatRl
is agiven algebraic operator part
of M andR2
is thegraph
asingle-valued
linearoperator
defined on Dom M.Clearly
if
R2
is also analgebraic
selection ofM,
theng(x)
:=R1 (x) - R2(x) E M(O)
for all x E Dom M. The converse is false. In order thatR2
be also analgebraic selection, g(x)
mustsatisfy
more subtle conditions. We next address thisproblem
and the related
questions (i)
and(ii)
mentioned above.In order to describe all
possible algebraic
selections ofM-1
we need thefollowing
fundamental lemma which followseasily
fromSobczyk’s
lemma[10];
see also
[8].
LEMMA 2.8. let
Po
be anarbitrary
but fixedalgebraic projector
of a vectorspace Y onto a
subspace
X of Y. Then P is analgebraic projector
of Y ontoX if and
only
if P= Po
+ A for some linear operator A : Y --+ X such thatAy
= 0 for all y E X. The above result remains valid ifX,
Y are normed linear spaces andPo, A
arerequired
further to be continuous.We establish a fundamental
relationship
between any twoalgebraic
operator parts ofM-1.
THEOREM 2.9. Let
Ro = principal algebraic
operator partof M-1
1 wherePo :
Dom M -; Null M is analgebraic projector
onto. Then(i)
R is analgebraic
operator partof M-’ if
andonly if R(y) = Ro(y) -
A2(y, Ro(y» for
all y ERange
M,for
some linear operatorA2 :
Null M such thatA2(0, x)
= 0for
all x E Null M.(ii)
For anyalgebraic
operator part Rof M-1, (I - Po)R(y)
=Ro(y) for
ally E
Range
M.(iii) If R := P)]M-1
is anyprincipal algebraic
operator partof M-’
(where
P : Dom M --+ Null M is analgebraic projector onto),
thenRo(y) = (I - Po)R(y), R(y) = (I -
for all y ERange
M.PROOF. We show first that R is an
algebraic
operator part ofM-1
if andonly
iffor some linear operator
A2 : ; M -1 >
Null M such thatA2(0, x)
= 0 for all x E Null M. Define Pby
P(y, x)
:=(0, Po(x)), (y, x)
Then P is analgebraic projector
fromM-1
onto{0}x
Null M. It follows from Lemma 2.8 thatQ
isan
algebraic projector
fromM-1
onto{0}x
Null M if andonly
iffor some linear operator A from
M~ ~ into 101 x
Null M such thatx) = (0, 0)
for all x E Null M. We can write A in the formA(y, x) _ (0, A2(y, x)), (y, x)
EThen
A2
is a linear map intoNull M,
andA2(0, x)
= 0 for all x E NullM.
Moreover, Q(y, x) = (0, Po(x)
+A2(y, x)).
Now
by
definition of analgebraic
operatorpart,
R is analgebraic
operator part ofM-1
I if andonly
if R =M-1 n Null Q
for someQ
as in(2.2).
But thenR =
{(x, y)
Ex)
+Po(x)
=0 1’
for some suchA2.
This proves assertion(2.1).
Take(y, x)
E R.Ro(y)
+ u for some u E Null M, andand so
Thus
(2.1 )
can be rewritten asWe now prove
(ii).
SinceRange
A cNull M,
we have for all y ERange
M, (I - (I - (I -
=R0(v).
Suppose
now that R is as in(iii).
Thenusing (i),
for all x ERange
M,as
Range
A c Null A. ·REMARK 2.5. It follows from the above theorem that for any two
algebraic operator
partsR1, R2
ofM-l, (I - Po)RI(y) = (I - Po)R2(y),
for all y ERange M,
wherePo
is anyalgebraic projector
of Dom M onto Null M.We now
provide
animportant
characterization(and
describe thegeneral form)
of aprincipal algebraic operator
ofM-1.
THEOREM 2.10. Let R be the
graph of a single-valued
linear operator onRange M
into Dom M. Then R is aprincipal algebraic
operator partof M -I if
andonly if
thefollowing
two conditions aresatisfied:
(i) RM(O) = {0}; equivalently
RM issingle-valued.
(ii)
The map P on Dom Mdefined by P(x)
:= x -RM(x)
is analgebraic projector of
Dom M onto Null M.Moreover,
when(i)
and(ii) hold,
R =P)IM-1.
PROOF. The
"only
if" part follows from Theorems 2.6 and 2.7. Assume that(i), (ii)
hold. Since =RM,
we see that =RMM-l.
But R c Thus
By
definition of aprincipal algebraic
operatorpart
ofM-1, R,
is aprincipal
algebraic
operator ofM-’.
Since R andRl
aresingle-valued
and Dom R =Dom R1,
it follows from(2.4)
that R =The
following proposition provides
severalalgebraic operational
characterizations of a
principal algebraic
operator part ofM-1.
PROPOSITION 2.11. Let R be the
graph of a single-valued
linear operatoron
Range M into
Dom M. Thenthe following
areequivalent:
(i)
R is aprincipal algebraic
operator partof M-1.
(ii) RM(0) = {0},
M = MRM and Null RM = Null M.(iii) R = RMR, M = MRM,
Null RM = Null M.(iv)
R = RMR, Null RM = Null M.Moreover, if
anyof (ii), (iii), (iv) holds,
then R =P)]M-1
whereP(x)
:= x -RM(x) for
all x E Dom M.PROOF. Assume
(i).
Thenby Proposition 2.10, RM(0) = {0},
Null RM =Null M.
By Proposition 2.3,
M = MRM. Thus(i) implies (ii).
Assume(ii).
Then I - RM defines an
algebraic projector
of Dom M onto Null M. Thus(ii) implies (i),
and moreover, R =[gr(I - P)]Mr 1.
Thus(i)
and(ii)
areequivalent.
Clearly (iii) implies (ii),
and(iii) implies (iv).
Assume(ii).
Then since(ii)
and
(i)
areequivalent, by Proposition 2.3,
R = RMR. Hence(ii) implies (iii).
Assume
(iv).
ThenRM(0) = {0},
and I - RM defines analgebraic projector
of Dom M onto Null M. Thus
by Proposition 2.10,
R is aprincipal algebraic
operator part of
M-1,
and so(iv) implies (i)..
COROLLARY 2.12. Assume that M is
single-valued.
Let R be thegraph
ofa linear
operator
onRange M into
Dom M. Then thefollowing
areequivalent:
(i)
R is analgebraic operator
part ofM-1. (ii)
R is aprincipal algebraic operator part
of(iii)
R =RMR,
Null RM = Null M.(iv)
M = MRM.PROOF. The
equivalence
of(i)
and(ii)
follows from the definition ofan
algebraic
operatorpart
and part(iii)
of Theorem 2.4. SinceR, M are single-valued, RM(0) = {0}.
When M =MRM,
Null M = Null RM. Thus theremaining
assertions follow fromProposition
2.11. *3. -
Topological
Selections of Multi-Valued LinearMappings
In the
previous
section we have defined and studiedalgebraic
operatorparts.
In this section we willstudy
certainalgebraic
operator parts(of
a multi-valued linear
mapping)
which have also sometopological properties,
inparticular
those which are induced
by
continuousprojectors. Throughout
this section X and Y are real orcomplex
Banach spaces, and X* and Y* their(topological)
duals.
Throughout
thissection,
M is a linear manifold in X xY,
and M+ isa linear manifold in Y* x X*. We do not assume that M is closed or M+ is w*-closed. All the results of this section are also valid in
topological
vectorspaces.
DEFINITION 3.1. We say that R is a
topological
operator part(TOP
forshort)
or atopological
selectionof
M if there exists a continuousprojector
Pof the normed space M
(whose
norm is inherited from X xY)
ontoMoo
such that R = Null P. This R will be denotedby Rp
when thedependence
on P isto be
emphasized.
For a
subspace
of theproduct
of two dual spaces, one could define atopological
operator part as in Definition 3.1.However,
this would not lead to"symmetry properties"
that are desirable. There is a moreimportant
definitionthat uses continuous
projectors
in thew*-topology.
DEFINITION 3.2. Let M+ be a linear relation in Y* x X*. Then R+ is called a
w*-topological
operator part(w*-TOP)
of M+ if R+ = NullP+for some
algebraic projector
P + of M+ ontoM~
:={0}
xM~(0)
such that P +is w*-continuous on the normed space M+. This operator part will be denoted
by
By
the abovedefinitions,
atopological
part and aw*-operator
part arealgebraic
selections.REMARK 3.1.
Suppose
that is atopological
operator part of M+where P I is a continuous
projector
of M+ ontoM~.
If can be extendedto a continuous linear
operator
definedeverywhere
on Y* x X*, then is aw*-topological
operator part of The converse is not true.REMARK 3.2. For a linear relation
M, Coddington
andDijksma
used theterm
"operator part"
of M to mean a closedalgebraic
operator part(see,
e.g.,
[3]).
For a closed linear relation M, the notion oftopological
operator part in our sense coincides with the notion of"operator part"
in the sense ofCoddington.
For suppose R is anoperator
part in the sense ofCoddington.
Then M is the direct
algebraic
sum of R andMoo,
and R is closed. Let P be theprojector
of M ontoMoo
such that R = Null P. SinceM, Moo
and R areclosed,
and M is the direct sum of R andMoo,
P must be continuous(see,
e.g., Rudin
[9]).
Hence R is atopological operator
part of M.Conversely,
letM be closed and suppose that S is a
topological operator
part of M. Then ,S = Null P for some continuousprojector
of M ontoMoo.
Thus S is closed since M is closed.Moreover,
S is analgebraic
selection of M. Hence S is anoperator
part
in the sense ofCoddington.
Our notion oftopological
operatorpart
does not assume M to beclosed,
norM(0)
to betopologically complemented.
Moreover, topological
selections in our sense will not be closed ingeneral.
We now consider several
examples
whichhighlight
differentaspects
oftopological
operator parts.EXAMPLE 3.1. A
topological
selection ofM-1 always
exists and is closed if M is closed and Null M istopologically complemented
in X. To provethis,
let P be a continuous
projector
of X ontoNull M,
and define P :M-l --+ {0} x
Null M
by
P(y, x)
=(0, P(x)).
Then P is continuous andsurjective,
and so NullP is a
topological
selection. Since P is continuous andM-1
I isclosed,
Null P is closed.EXAMPLE 3.2. If Dom M is
topologically decomposable
with respect to acontinuous
projector
P : X -X,
thatis,
ifP(Dom M)
=Null M,
thenM-1
1has a
topological operator
part. For, let :=(0, P(x))
for(y, x) E M-1.
Then P is continuous and is onto
(0)xNullm.
In this case .R := NullP =
1(y, x) : P(x)
=0}
is called aprincipal topological operator
part of In view of Theorem2.5,
we may recast definition of aprincipal topological operator part
of M in thefollowing equivalent,
but moreexplicit,
form:DEFINITION 3.3. A
principal topological
operator part of R of M is asubspace
of M of the form R = where P is a continuousprojector
of
Range
M ontoM(0). Similarly,
aw*-topological
operator part R+ of M+ is called aprincipal w*-topological operator
part if .R+ _[gr(I - P+)]M+
for somew*-continuous
projector
PI ofRange
M+ ontoM+(0).
Thus
by
Theorem 2.5 anyprincipal topological
operator part and anyprincipal w*-topological operator part
areprincipal algebraic
operator parts.Suppose
now thatX, Y
are Hilbert spaces andM(0)
is closed(M
neednot be
closed).
Then R := M n({0}
x =P)]M,
where P is theorthogonal projector
of Y ontoM(O). Thus,
inparticular,
R is analgebraic operator
of M.Moreover,
if :={0, P(y)}
for all(x, y)
E M, then Pis a continuous
projector
of M onto{0}
xM(0),
and R =Rp.
Hence R is atopological
operator of M. Theassumption
thatM(0)
is closed may bereplaced by
the weakerassumption
that the domain ofMrl
isdecomposable
with respectto an
orthogonal projector, i.e., M(0)
cRange
P andRange
M =M(0)+(Range
M n NullP),
where P is an
orthogonal projector
on Y. This isequivalent
to the conditionP(Dom M- 1) = ~’VI(0),
with Pbeing
anorthogonal projector. Clearly
ifM(0)
isclosed,
then DomM-1
I isorthogonally decomposable,
but the converse is false.This motivates the
following
definition.DEFINITION 3.4.
Suppose X, Y are
Hilbert spaces andDom M-1
isorthogonally decomposable
with respect to anorthogonal projector
P. ThenR :=
P)]M
is called theorthogonal
operator part of M.Orthogonal operator
parts andorthogonal generalized
inverses possess certain extremalproperties.
These have been studiedby
the authors[6], [7]
andapplied
to linear inclusions and minimizationproblems.
EXAMPLE 3.3. A
topological operator
part may not exist. Let T be aunbounded linear
functional
on a Banach space X. Thus Null T is dense in X and so Null T is not closed. Let M = Then R is analgebraic
operatorpart
of M if andonly
if there exists xo c X withT(xo)
= 1 such thatR(t)
= txofor all t E R. For such
R, RT(xo) =
xo and RT = 0 on a dense subset of X. Therefore RT is discontinuous.Suppose
there exists atopological
operatorpart R
of M.Then,
since T issingle-valued, by
Theorem2.4, R
must be aprincipal topological operator
part of Mgenerated by
a continuousprojector
Pof
Range
M = Dom T ontoM(0)
= Null T such that R =P)]M.
But thenby
Theorem2.7,
=RT(x)
= x -P(x)
for all x E Dom T.This,
inparticular, implies
that RT iscontinuous,
a contradiction. Thus hasno
topological
operator part.EXAMPLE 3.4. A
topological
operator part of Malways
exists and is closed if M is closed and if{01
xM(0)
istopologically complemented
in M.This follows from
Example
3.1.However,
neitherassumption
is necessary for the existence of atopological
operator part.EXAMPLE 3.5. A
topological operator
part may not be closed. Forexample,
let M = A x
{0}
where A is a nonclosed vectorsubspace
of X. Then thetopological operator part
of M is Mitself,
and so it is not closed.EXAMPLE 3.6. A
topological operator part
of M can exist even ifM(0)
isnot
complemented
in Y. Forexample,
take M =10}
x A where A is a closedsubspace
of Y which is notcomplemented
in Y. Then{(0, 0)}
is thetopological
operator part of M.
We now
give
a characterization of aprincipal
TOP ofM-1
withoutusing projectors.
THEOREM 3.1. Let R be the
graph of
asingle-valued
linear operatoron
Range
M into Dom M. Then R is aprincipal topological
operator partof M-1 if
andonly if
RM issingle-valued
and continuous, Nul1 RM =Null M,
and M = MRM. Inparticular if,
inaddition,
M issingle-valued,
then R isa
topological
operator partof M-1 if
andonly if
M = MRM and RM iscontinuous.
PROOF. This follows
from Proposition 2.11, Corollary
2.12 andProposition
2.10
by considering
theprojector
P definedby P(x)
= x -RM(x),
x E Dom M..
The existence of a TOP of M does not
always imply
the existence of aprincipal
TOP of M(see
Remark 3.4below).
But we still can relate any two TOP of M via thefollowing
theorem.THEOREM 3.2.
Suppose
that M has atopological
operator part, sayRo
:={(x, y)
E M :y)
=01
whereP2 :
M -->M(O)
is a linear operator such that the map(x, y)
-(0, y)) defines
a continuousprojector of
Monto