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A classification of isomorphisms and isometries on
functions spaces.
Mohammed Bachir
To cite this version:
Mohammed Bachir. A classification of isomorphisms and isometries on functions spaces.. 2014.
�hal-01082632�
fun tions spa es.
Mohammed Ba hir November14, 2014
Laboratoire SAMM 4543, Université Paris 1 Panthéon-Sorbonne, Centre P.M.F.90 rue Tolbia 75634 Paris edex 13
Email : Mohammed.Ba hiruniv-paris1.fr
Abstra t. We establishin thisarti le aformulawhi h will allowto lassifyisometries as well as partial isometries between spa es of fun tions. Our result applies in a non ompa t framework and for abstra t lassof fun tions spa es in luded in the spa e of ontinuous and bounded fun tions on omplete metri spa e. The resultof this arti le isinparti ular ageneralizationoftheBana h-Stonetheorem. Weusethe te hniquesof dierentiabilityasinthe original proofofBana hfor onvexfun tionsgeneralizingthe norm ofuniform onvergen e. Weusealso adualityresultin a non onvex framework.
Keyword, phrase: The Bana h-Stone theorem, isometries and isomorphisms, dif-ferentiability, duality.
1 Itrodu tion.
The lassi al Bana h-Stone theorem say thatif
K
andL
are ompa t spa es andT
is an isomorphism from(C(K), k.k
∞
)
onto(C(L), k.k
∞
)
(whereC(K)
andC(L)
denotes the spa es of all real valued ontinuous fun tions onK
andL
respe tively) then, the mapT
isan isometry if and only ifthere existsan homeomorphismπ : L → K
and a ontinuous mapǫ : L → {±1}
su hthatT ϕ(y) = ǫ(y)ϕ ◦ π(y); ∀y ∈ L, ∀ϕ ∈ C(K).
(1)TheBana h-Stonetheoremwasinvestedbyseveralauthorsindiversedire tionsmaking waytoseveraladvan esand publi ationsforexample byD.Amir[1℄,J.Araujo[2℄,[3 ℄, J. Araujoand J.Font [4 ℄,E. Behrends [10℄,[11 ℄, M. Cambern [12℄,B. Cengiz, [13 ℄,M. Garrido and J. Jaramillo [18℄, [19℄, K. Jarosz [23 ℄, K. Jarosz and V. Pathak, [24℄, D. Vieiera [26℄, N. Weaver [27 ℄. The list remaining still long, we send ba kto the arti le of M. Garridoand J.Jaramillo [17℄ for ahistory of ontributions anda more omplete list.
of isomorphisms between fun tions spa es resulting totally or partially from homeo-morphisms. We establish our result in the non ompa t framework for abstra t lass of fun tions spa es in luded lassi al spa es. To be more lear, we give the following example. Suppose that
X
andY
aretwo Bana h spa es and supposethat thereexists an homeomorphismπ : Y → X
preserving norms i.ekπ(y)kX
= kykY
for ally ∈ Y
. Letus denote byH
k.k
X
,k.k
Y
(Y, X)
the lassof allhomeomorphism fromY
ontoX
pre-serving norms and byC
b
(X)
the spa e of all ontinuous bounded fun tionsonX
. LetT : (Cb(X), k.k∞) → (Cb(Y ), k.k∞)
be anisomorphism.Question 1. Under what ondition the isomorphism
T
omes anoni ally as in the formula(1)from the lassofthe homeomorphismsπ ∈ H
k.k
X
,k.k
Y
(X, Y )
? The answer to this question is thatT
omes anoni ally formπ ∈ H
k.k
X
,k.k
Y
(X, Y )
ifand only if,itsatisesthe following ondition
sup
y∈Y
{|T ϕ(y)| − kykY
} = sup
x∈X
{|ϕ(x)| − kxkX
} , ∀ϕ ∈ Cb
(X).
(2)Thus the lass ofall isomorphisms
T
satisfying(2)is in bije tionwith the set{ǫ : Y → {±1}
ontinuous} × H
k.k
X
,k.k
Y
(Y, X).
For example, when
X = Y = R
(whi h are in parti ular onne ted spa es), we have that the isomorphismsT : Cb(R) → Cb(R)
that satisfysup
y∈R
{|T ϕ(y)| − |y|} =
sup
x∈R
{|ϕ(x)| − |x|} , ∀ϕ ∈ Cb
(R)
are exa tly four isometries orresponding to the homeomorphismssatisfying|π(x)| = |x|
for allx ∈ R
whi hareπ(x) = x
orπ(x) = −x
for allx ∈ R
:(1) T1ϕ(y) = ϕ(y)
forallϕ ∈ Cb
(R)
andally ∈ R
. Theidentity map.(2) T2ϕ(y) = −ϕ(y)
for allϕ ∈ Cb(R)
and ally ∈ R
.(3) T
3
ϕ(y) = ϕ(−y)
for allϕ ∈ C
b
(R)
and ally ∈ R
.(4) T
4
ϕ(y) = −ϕ(−y)
for allϕ ∈ C
b
(R)
and ally ∈ R
.Our main result Theorem 1 gives a general lassi ation in the spirit mentioned in the example above. Moregenerally, a lassof homeomorphism
π
given bya fun tional onstraintf ◦ π = g
for xed lower semi ontinuous and bounded from belowfun tionsf
andg
, hara terize the lass of isomorphism satisfyingsup
y∈Y
{|T ϕ(y)| − g(y)} =
sup
x∈X
{|ϕ(x)| − f (x)}
for allϕ ∈ C
b
(X)
. In the parti ular ase wheref = 0
onX
andg = 0
onY
we re over the lassof allisometries fork.k∞
. Before giving our main result Theorem1 below, we aregoingto introdu e explanatory ommutative diagrams orresponding to our lassi ation.1.1 The ommutative diagrams for the lassi al Bana h-Stone theo-rem.
Let
T : C(K) → C(L)
be an isomorphism, andletH0,0
(L, K)
be the set ofall homeo-morphism fromL
ontoK
ifsu h homeomorphism exists. The left diagram ommutesC(K)
T
//
k.k
∞
$$
■
■
■
■
■
■
■
■
■
C(L)
k.k
∞
R
⇔
∃π : L
π
//
0
❅
❅
❅
❅
❅
❅
❅
❅
K
0
R
k.k∞
◦ T = k.k∞
⇔ ∃π ∈ H0,0
(L, K)
su h thatT
omes anoni allyfromπ
1.2 The ommutative diagrams for the lassi ation result. Let
(X, d)
and(Y, d
′
)
be a omplete metri spa es. Let
A ⊂ Cb(X)
andB ⊂ Cb
(Y )
be aBana hspa essatisfying ertaingeneralaxioms(Thisaxiomsareveriedfor lassi al and known fun tion spa es. See Axioms 1 and the examples in Proposition 2). Letf : X → R ∪ {+∞}
andg : Y → R ∪ {+∞}
betwo lower semi ontinuousand bounded frombelowfun tionswithnonemptydomainsi.edom(f ) := {x ∈ X : f (x) < +∞} 6= ∅
anddom(g) 6= ∅
. Wedenotebydom(f )
anddom(g)
the losure ofdom(f )
anddom(g)
inX
andY
respe tively. WedenotebyHf,g(Y, X)
the lassofallhomeomorphismfromdom(g)
ontodom(f )
ifsu hhomeomorphism exists. Wegivebelowthediagramsofour lassi ation result. The leftdiagram ommutes ifandonly thatof right also.Let
T : A → B
bean isomorphism,A
T
//
F
❅
❅
❅
❅
❅
❅
❅
❅
B
G
R
⇔ ∃π : dom(g)
π
//
g
&&
▲
▲
▲
▲
▲
▲
▲
▲
▲
▲
▲
dom(f )
f
R
∪ {+∞}
G◦T = F ⇔ ∃π ∈ Hf,g
(Y, X)
su hthatf ◦π = g
ondom(g)
and T omes anoni ally fromπ
ondom(g).
WhereF(ϕ) := sup
x∈X
{|ϕ(x)| − f (x)} , ∀ϕ ∈ A
G(ψ) := sup
y∈Y
{|ψ(y)| − g(y)} , ∀ψ ∈ B.
We re over the lassi al real valued Bana h-Stone theorem in the ase of omplete metri spa es
X
andY
withA = C
b
(X)
,B = C
b
(Y )
,f = 0
onX
andg = 0
onY
. The situationin Question 1. orrespond tof = k.kX
andg = k.kY
. Ourmain resultis then the following theorem.1.3 The main result.
Theorem 1 Let
X
andY
be two omplete metri spa es andA ⊂ Cb(X)
andB ⊂
Cb(Y )
be two Bana hspa es satisfyingthe axiomsA1
-A4
(with the same propertyP
β
. See Axioms 1 and the examples in Proposition 2). Let
T : A → B
be an isomorphism and letf : X → R ∪ {+∞}
andg : Y → R ∪ {+∞}
be lower semi ontinuous and bounded frombelow withnonempty domains. Then(1) ⇔ (2)
.(1)
For allϕ ∈ A
, we havesup
y∈Y
{|T ϕ(y)| − g(y)} = sup
x∈X
{|ϕ(x)| − f (x)}
.(2)
There exist an homeomorphismπ : dom(g) → dom(f )
and a ontinuous fun tionε : dom(g) → {+1, −1}
su h that, for ally ∈ dom(g)
andallϕ ∈ A
we haveT ϕ(y) = ε(y)ϕ ◦ π(y)
and
g(y) = f ◦ π(y).
Remark 1 Note that from
(2)
we obtainsup
y∈dom(g)
|T ϕ(y)| = sup
x∈dom(f )
|ϕ(x)|
,∀ϕ ∈ A
. Itfollowsthat, ifdom(f ) = X
anddom(g) = Y
thenthe ondition(1)
implies in parti ular thatT
is isometri for the normk.k∞
. So using lower semi ontinuous fun tions su h thatdom(f ) = X
anddom(g) = Y
willpermit to lassify isometries for the normk.k∞
. Inthe general ase Theorem1permitto lassifyisomorphismsnotne -essary isometries satisfyingsup
y∈E
|T ϕ(y)| = sup
x∈F
|ϕ(x)|
,∀ϕ ∈ A
for someE ⊂ X
andF ⊂ Y
.As an immediate onsequen e of the above theorem is the following general Bana h-Stone result.
Corollary 1 Let
X
andY
be two omplete metri spa es. LetA ⊂ Cb(X)
andB ⊂
C
b
(Y )
be two Bana hspa es satisfyingthe axiomsA
1
-A
4
(withthe same propertyP
β
). Let
E
be a losed subset ofX
andF
be a losed subset ofY
. LetT : A → B
be an isomorphism. Thensup
y∈F
|T ϕ(y)| = sup
x∈E
|ϕ(x)|
forall
ϕ ∈ A
ifandonlyifthere existsanhomeomorphismπ : F → E
anda ontinuous mapε : F → {−1, +1}
su h that for ally ∈ F
and allϕ ∈ A
we haveT ϕ(y) =
ε(y)ϕ ◦ π(y)
.Proof. It su es to apply Theorem 1with the indi ator fun tions
f = i
E
andg = i
F
whereiE
(respe tively,iF
) isequal to0
onE
(respe tively, onF
)and+∞
otherwise. Remark 2 Were overthe lassi alversionoftheBana h-Stonetheoremfromtheabove orollary by takingE = X
andF = Y
.Note thatthere are situation where an isomorphism isnot anisometry but partially isometri . Indeed, Let
K
andL
betwo metri and ompa t non homeomorphi spa es su h thatC(K)
andC(L)
areisomorphi andletT
1
: C(K) → C(L)
bean isomorphis-m. Thissituation existsfor exampleforC[0, 1]
andC([0, 1] × [0, 1])
. A.A.Milutin[25 ℄ proved thatifK
andL
are both un ountable ompa t metri spa es, thenC(K)
andC(L)
arealwayslinearly isomorphi . LetR
andS
two homeomorphi omplete metri spa es su h thatR ∩ K = ∅
andS ∩ L = ∅
and letπ : S → R
an homeomorphism. Letus onsider the mapT : Cb
(K ∪ R) → Cb
(L ∪ S)
dened byT (ϕ)(y) = T1(ϕ
|K
)(y)
ify ∈ L
andT (ϕ)(y) = ϕ ◦ π(y)
ify ∈ S
for allϕ ∈ Cb(K ∪ R)
. Whereϕ
|K
de-notes the restri tion ofϕ
toK
. ThemapT
isan isomorphism not isometri satisfyingsup
y∈S
|T ϕ(y)| = sup
x∈R
|ϕ(x)|
for allϕ ∈ Cb(K ∪ R)
.and Theorem 4(See Se tion 2.4) whi h were establishedin [7℄ together with Lemma 1 (SeeSe tion 2.3)whi h isa onsequen e ofthe well knownDeville-Godefroy-Ziler v ari-ational prin iple [14 ℄. We us the general version of this prin iple whi h also worksfor ompletemetri spa esandisdutoR.DevilleandJ.Rivalski[16℄. Alsoletusnotethat a similar result of our main result Theorem 1 an be established in a ve torial frame for abstra t subspa es of the spa e of all ontinuous and bounded
Z
-valued fun tionsC
b
(X, Z)
. Some onditions on the Bana h spa eZ
are ne essary like the smoothness of the norm ofZ
. The proof being more te hni al and requiring others intermediate results, we omit it in this arti le but we send ba k to the thesis [5℄ (see also [6℄) for a ve torial Bana h-Stone theorem. Let us mention here that the rst resultabout the ve torial Bana h-Stone theorem is due to E. Behrends[10 ℄, [11 ℄. Others results about the ve torvaluedBana h-Stone theoremwasestablishedbyJ.Araujoin[2 ℄,[3 ℄and by K. Jaros in [23 ℄.Remark 3 In Theorem 1 above, we an have more information about the homeomor-phism
π
. More the spa esA
andB
are regular more the homeomorphismπ
is it also. For exemple ifA = C
u
b
(X)
andB = C
u
b
(Y )
(the spa es of uniformly ontinuous and bounded) we obtain thatπ
is uniformly ontinuous as well asπ
−1
. If
A = Lipb(X)
andB = Lip
b
(Y )
(the spa es of all Lips hitz bounded map) andX
andY
are quasi- onvexe thenπ
is bi-Lips hitz. This follow from the fa t that ifϕ ◦ π
is Lips hitz for allϕ ∈ Lipb(X)
thenπ
is Lips hitz. See Theorem44
in the paper of M.Garrido and J. Jaramillo [17℄. It is also known from the paper of J. Gutiérrez and J. Llavona [21℄ (See also [22℄) that ifp ◦ π
isC
k
smooth fun tion ( in this ase
X
is assumed to be a Bana h spa e) for allp ∈ X
∗
(the topologi al dual of
X
) thenπ
is of lassC
k−1
. So in the ase where
A = C
k
b
(X)
andB = C
k
b
(Y )
(the spa e okk
-times ontinuously Fré het dierentiable fun tionf
su h thatf
,f
′
...,
f
(k)
are uniformly bounded) we an dedu e, using the omposition
α ◦ p
wherep ∈ X
∗
and
α : R → R
be a desirable very smooth fun tion, thatπ
isC
k−1
dieomorphism. Note that if moreover
X
has the S hur propertythenfromthe paperof M.Ba hirandG.Lan ien [8℄we an dedu e thatπ
is of lassC
k
. We draw the attention here on the fa t that the S hur property and the axiom
A
3
(See Axioms1)are notstill ompatible ininnitedimension, forexample the spa eX = l
1
(N)
whi h has the S hur property does not admit a Lips hitz and
C
1
smoothbump fun tion (See [15℄).
Thispaper is organised asfollow. In se tion2. we introdu e the axioms whi h we shall use in this arti le and we give examples satisfying them. We also give tools and preliminaries result whi h will permit us to give the proof of our main theorem. In se tion 3. We give the proofof our main resultTheorem 1.
2 Tools and preliminaries results.
Toproveour mainresultweneedtoestablish ertainlemmasandtore allotherresults already established.
Let
(X, d)
bea ompletemetri spa es and(A, k.k)
a Bana hspa ein luded inCb
(X)
. Byδ
wedenotetheDira mapand byδ
x
the Dira massasso iatedto thepointx ∈ X
. ByA
∗
wedenote the topologi al dualof
A
. Wehaveδ : X → A
∗
x → δx
and for all
x ∈ X
,δx
: A → R
ϕ → ϕ(x).
Denition 1 (The property
P
β
) Let
(X, d)
be a omplete metri spa e and(A, k.k)
a Bana h spa e in luded inCb(X)
. We say thatA
has the propertyP
F
(respe tively,
P
G
) if, for ea h sequen e(xn)n
⊂ X
wehave:(x
n
)
n
onverges in(X, d)
if and only if the asso iated sequen e of the Dira masses(δx
n
)n
onverges in(A
∗
, k.k
∗
)
(respe tively, in(A
∗
, w
∗
)
). Wherek.k
∗
denotes the dual norm and
w
∗
the weak-startopology.
We denoteby
τ
β
the weak-star topology ifβ = G
andthe normtopology ifβ = F
. The ru ial propertyP
β
is related to the geometry of the Bana h spa e
A
and is onne ted to the dierentiability to the supremum normk.k
∞
for more detail see the arti le [7℄. Thefollowing proposition follow easily fromthe above denition.Proposition 1 Let
(X, d)
be a omplet metri spa e and(A, k.k)
be a Bana h spa e in luded inCb(X)
whi h separate the pointsofX
.(1)
Suppose thatA
has the propertyP
F
then
δ(X) := {δx
: x ∈ X}
is losed for the norm topology inA
∗
andthe map
δ : (X, d) → (δ(X), k.k
∗
)
x 7→ δx
is an homeomorphism.
(2)
SupposethatA
hasthepropertyP
G
then
δ(X) := {δx
: x ∈ X}
issequentially losed for the weak-startopology inA
∗
andthe map
δ : (X, d) → (δ(X), w
∗
)
x 7→ δx
is an sequential homeomorphism. Themapδ : X → A
∗
x → δx
isanonlinearanalogoustothe anoni allinearisometry
i : Z → Z
∗∗
where
Z
isBana h spa e andZ
∗∗
its bidual. The map
δ
permit to linearize the metri spa eX
inA
∗
( See thepaperofGodefroy-Kalton[20 ℄ when
A
isthe setofallLips hitzmaponX
that vani h at some point).Wegive now the general axioms thatthe spa e
A
hasto satisfyin ourresults.Axiome 1 In all the arti le
(X, d)
isa omplet metri spa e andA
isa lass of fun -tionsspa es in luded inC
b
(X)
su h that :(A
1
)
the spa e(A, k.k)
is a Bana h spa e andk.k ≥ k.k∞
.(A
2
)
the spa eA
separate the pointsofX
and ontain the onstants.(A
3
)
for ea hn ∈ N
∗
, there exists a positive onstant
Mn
su h that for ea hx ∈ X
there exists a fun tionh
n
: X → [0, 1]
su h thath
n
∈ A
,khnk ≤ Mn
,h
n
(x) = 1
anddiam(supp(hn)) <
n
1
.(A4)
the spa eA
has the propertyP
β
(
β = F
orβ = G
).Remark 4 : These axioms are satised by various and lassi al spa es of fun tions. We give below some examples. Let us mention here, that the axiom
(A
3
)
is related to the variational prin iple of Deville-Godefroy-Zizler [14℄ and Deville-Rivalski [16℄ and the axiom(A
4
)
was introdu ed and studied in [7℄.By the spa e
C
u
b
(X)
we denote the Bana h spa e ofall bounded uniformly ontinuous fun tion onX
, byLip
α
b
(X)
the Bana h spa e of allα
-Holder and bounded fun tions onX (0 < α ≤ 1)
, byC
k
b
(X)
the Bana h spa e of allk
-times ontinuously Fré het dierentiablefun tionsf
su h thatf
,f
′
, ...,
f
(k)
areuniformly bounded, by
C
1,α
b
(X)
(
0 < α ≤ 1
)the Bana hspa eofallFré het dierentiablefun tionsf
onX
su hthatf
andf
′
areuniformlybounded onX and
f
′
is
α
-Holder. FinallybyC
1,u
b
(X)
we denote the Bana h spa eof all Fré het dierentiablefun tionsf
onX
su h thatf
andf
′
are uniformlybounded onX and
f
′
isuniformly ontinuous. All thesespa es areprovided with their natural norm
k.k
ofBana h spa ethatsatisfyk.k ≥ k.k∞
(See[7℄).Proposition 2 We have,
(1)
For every omplete metri spa eX
, the spa esCb(X)
,C
u
b
(X)
andLip
α
b
(X)
(0 <
α ≤ 1
)satisfy the axioms(A
1
)
-(A
4
)
(2)
IfX
is a Bana h spa e having a bump fun tion (that is a fun tion with a non empty and bounded support) inA = C
k
b
(X)
(k ∈ N
∗
) (respe tively, inA = C
1,α
b
(X)
(0 < α ≤ 1
) orA = C
1,u
b
(X)
), thenA
satisfy the axioms(A
1
)
-(A
4
)
.Proof. Theproof isan onsequen e ofProposition 3,Proposition4 andProposition 5 below.
Proposition 3 Allofthespa es
A
mentionedintheexamplesabove,satisfytheaxioms(A
1
)
and(A
2
)
.Proof. Theaxiom
(A1)
followfromthe denitions ofthe spa es and therenorms (See [7℄). Thesespa es ontainthe onstants. To sethatthese spa esseparatethe pointsofX
, letx 6= y
inX
. Inthe ase ofthe spa esC
b
(X)
,C
u
b
(X)
andLip
α
b
(X)
where(X, d)
is a metri spa e, Letus setφ(.) := min(d(x, .), 1) ∈ Lip
α
b
(X) ⊂ C
b
u
(X) ⊂ Cb(X)
. We haveφ(x) = 0
andϕ(y) = min(d(x, y), 1) > 0
. Soϕ(x) 6= ϕ(y)
and thus these spa es separate the points ofX
. In the ase whereX
is a Bana h spa e andA = C
k
b
(X)
(
k ∈ N
∗
) orC
1,α
b
(X)
(0 < α ≤ 1
) orC
1,u
b
(X)
, sin ex 6= y
, then by the Hanh-Bana h theorem,thereexistsp ∈ X
∗
su hthat
p(x) 6= p(y)
. We onstru tthenamapγ : R → R
su h thatγ ◦ p ∈ A
andγ(p(x)) = p(x)
andγ(p(y)) = p(y)
. ThusA
separatethe point ofX
.The following proposition isin [7℄.
Proposition 4 [Proposition2.5and2.6,[7℄℄Let
(X, d)
be a omplete metri spa e. We have :(1)
IfA = C
b
(X)
orC
u
b
(X)
thenA
satisfyP
G
(but notP
F
).(2)
IfA = Lip
α
b
(X)
with0 < α ≤ 1
thenA
satisfyP
F
.
b)
Suppose thatX
is Bana h spa e andA = C
k
b
(X)
(k ∈ N
∗
) orC
1,α
b
(X)
(0 < α ≤ 1
) orC
1,u
b
(X)
thenA
satisfyP
F
.We have proved that the above examplesof spa es satisfy the axioms
(A
1
)
,(A
2
)
and(A4)
. These examples satisfy also the axiom(A3)
whenever the spa eX
has a bump fun tioninA
(thatisafun tionwithanonemptyandboundedsupport). Theexisten e of a bump fun tion inC
b
(X)
,C
u
b
(X)
or in Lipα
b
(X)
with0 < α ≤ 1
isalways true by usingthemetrid
onX
. Thisisnotealwaysthe asewhenX
isaBana hspa eforthe spa es of smooth fun tionsA = C
k
b
(X)
(k ∈ N
∗
) orC
1,α
b
(X)
(0 < α ≤ 1
) orC
1,u
b
(X)
. In the last examples the existen e of a bump fun tion is onne ted to the geometry of the Bana h spa eX
. For more information on the existen e of a bump fun tion inC
k
b
(X)
(k ∈ N
∗
)orC
1,α
b
(X)
(0 < α ≤ 1
) orC
1,u
b
(X)
we referto thebookof R.Deville, G. GodefroyandV.Zizler [15 ℄.Proposition 5 we have:
(1)
Forevery ompelete metri spa eX
, thespa esCb(X)
,C
u
b
(X)
andLip
α
b
(X)
satisfy the axiom(A
3
)
(2)
IfX
isa Bana hspa e havinga bum fun tioninA = C
k
b
(X)
(k ∈ N
∗
)(respe tively inC
1,α
b
(X)
(0 < α ≤ 1
) orC
1,u
b
(X)
), thenA
satisfythe axiom(A
3
)
.Proof. Theproofiseasyand an be foundinRemark2.5(SeealsoProposition1.4)in [16℄.
2.3 A useful Lemmas.
We need the following Lemma 1 that is a onsequen e of the Variational prin iple of Deville-Godfroy-Zizler[14 ℄ generalized byDeville-Rivalski [16℄.
Denition 2 We say that a fun tion
f
has a strong minimum atx
ifinf
X
f = f (x)
andd(xn, x) → 0
wheneverf (xn) → f (x)
.Theorem 2 ( [Deville-Godefroy-Zizler [14℄℄ ; [Deville-Rivalski[16℄℄):
Let
(X, d)
be a omplete metri spa e andA ⊂ Cb(X)
be a spa e satisfying the axioms(A
1
)
and(A
3
)
. Letf
be a lower semi ontinuous andbounded frombelowfun tion with non empty domain. Then,{ϕ ∈ A/ f − ϕ
doesnot attain astrong minimum onX}
isσ
-porous in parti ular it is of therst Baire ategory.tinuous and bounded from below withnon empty domain
f : X → R ∪ +∞
(f 6≡ +∞
) the setD(f ) := {x ∈ X/ ∃ϕ
x
∈ A : f − ϕx
has a strong minimumatx}
is densein
dom(f )
.Proof. Let
x ∈ dom(f )
ann ∈ N
∗
. Let
hn
∈ A
as in Theorem 2withhn(x) = 1
. let ussetλ
n
x
:= f (x) − infX
(f ) +
n
3
andapplyingTheorem2to thefun tionf + λ
n
x
hn
, there existsxn
∈ X
andϕ ∈ A
su hthatkϕk <
1
n
andf + λ
n
x
hn
− ϕ
hasastrong minimum atxn
. Supposethatd(x, xn) ≥
1
n
. sin ediam(supp(hn)) <
1
n
andx ∈ supp(hn)
, thenh(xn) = 0
. Thus, we haveinf
X
(f ) − ϕ(xn) ≤ f (xn) − ϕ(xn)
= f (xn) − λ
n
x
hn(xn) − ϕ(xn)
< f (x) − λ
n
x
hn(x) − ϕ(x)
= f (x) − λ
n
x
− ϕ(x)
We dedu t thatλ
n
x
< f (x) − inf
X
(f ) +
n
2
whi h is a ontradi tion with the hoi e ofλ
n
x
. Sod(x, xn) <
1
n
andxn
∈ D(f )
. Itfollows thatD(f )
isdense indom(f )
. Weneed also the following twoLemmas.Lemma 2 Let
Z
bea Bana hspa e andh, k : Z → R
two ontinuous and onvex fun -tions. Suppose that the fun tionz → l(z) := max(h(z), k(z))
is Fré het (respe tively, Gâteaux) dierentiable atz
0
. Thenh
is Fré het (respe tively, Gâteaux) dierentiable atz
0
ork
is Fré het (respe tively, Gâteaux) dierentiable atz
0
andl
′
(z
0
) = h
′
(z
0
)
orl
′
(z
0
) = k
′
(z
0
)
.Proof. Wegive the proof for the fré het dierentiability, the Gâteauxdierentiability is similar. Supposewithout looseof generalitythat
l(z
0
) = h(z
0
)
and letus prove thath
isFré het dierentiable atz
0
andthatl
′
(z
0
) = h
′
(z
0
)
. For ea hz 6= 0
we have:0 ≤
h(z
0
+ z) + h(z
0
− z) − 2h(z0
)
kzk
≤
l(z
0
+ z) + l(z
0
− z) − 2l(z0
)
kzk
Therightmembertendsto
0
whenz
tendsto0
sin el
is onvexandFré hetdierentiable atz
0
. This implies thath
is Fré het dierentiable atz
0
by onvexity. Now, sin el(z) ≥ h(z)
for all∈ Z
andl(z
0
) = h(z
0
)
, then for allt > 0
we haveh
′
(z
0
)(z) − l
′
(z
0
)(z) ≤
h
′
(z
0
)(tz) − l
′
(z
0
)(tz) + l(z
0
+ tz) − h(z
0
+ tz) − l(z
0
) + h(z
0
)
t
=
l(z
0
+ tz) − l(z
0
) − l
′
(z
0
)(tz)
t
+
h(z
0
+ tz) − h(z
0
) − h
′
(z
0
)(tz)
t
So,sendingt
to0
+
,wehaveh
′
(z
0
)(z)−l
′
(z
0
)(z) ≤ 0
,forallz ∈ Z
. Thush
′
(z
Lemma 3 Let
(X, d)
be a omplete metri spa e andA ⊂ Cb(X)
satisfyingthe axiomsA
1
,A
2
andA
4
. Let(λ)
n
⊂ R
su h that|λn| = 1
for alln ∈ N
and let(x
n
)
n
⊂ X
. Suppose thatλnδx
n
onverges for the topologyτβ
(the norm topology or the weak-star topology) to some pointQ ∈ A
∗
. Then
(λn)n
onverges inR
to some real numberλ
su h that|λ| = 1
and(x
n
)
n
onverges tosome pointx
in(X, d)
andwe haveQ = λδ
x
. Proof. Sin eλ
n
δ
x
n
onverges for the topologyτ
β
to some pointQ ∈ A
∗
, then
λnδx
n
(ϕ) → Q(ϕ)
forallϕ ∈ A
. Sin eA
ontainthe onstants,wehaveλn
→ Q(1) := λ
with|λ| = 1
. Now,sin e(λn)n
onverges toλ
andλnδx
n
onverges forthe topologyτβ
toQ
. By dividing byλn
we have thatδx
n
onverges for the topologyτβ
toQ
λ
∈ A
∗
. ThepropertyP
β
impliesthat
(x
n
)
n
onvergestosomepointx ∈ X
andin onsequan e thatδx
n
onverges for the topologyτβ
toδx
. By the uniqueness of the limit we have thatQ = λδx
.2.4 Duality results.
We re all from[7 ℄ the following results whi h are the key of the results of this arti le. Let
(X, d)
be a omplete metri spa e andA
be a lass of fun tions spa e satisfying the axiomsA
1
-A
4
. Forthe proofofTheorem1,we needthe following resultsaboutthe onjuga yf
×
of lower semi ontinuousbounded frombelowfun tion
f
dened byf
×
: A → R
ϕ → sup
x∈X
{ϕ(x) − f (x)}
Wedene the se ond onjuga y of
f
byf
××
: X → R ∪ {+∞}
;
f
××
(x) := sup
ϕ∈A
ϕ(x) − f
×
(ϕ) ; ∀x ∈ X
Proposition 6 ([ Proposition 2.1, [7℄℄): The map
f
×
is onvex and
1
-Lips hitzonA
.The se ond onjugate
f
××
isnot onvexin general, but we have:
Theorem 3 ([ Theorem 2.2, [7℄℄): Le
f
be aboundedfrombelowfun tiononX
and suppose thatA
satisfy the axiomA4
. Then,f
is lower semi ontinuous if and only iff
××
= f
.Finally, we need the following duality theorem between dierentiability and the well posedproblems.
Theorem 4 ([Theorem 2.8, [7℄℄): Let
A ⊂ C
b
(X)
be a lass of Bana h spa e satis-fyingthe axiomsA1
,A2
and the propertyP
F
(respe tively
P
G
). Let
ϕ ∈ A
andf
be a lower semi ontinuous fun tion. Then(1) ⇔ (2)
.(1)
the fun tionf − ϕ
has a strong minimum atsomepoint inX
.(2)
the fun tionf
×
is Fré het dierentiable (respe tively, Gâteaux dierentiable) at
ϕ
onA
.Moreover,inthis asetheFré hetderivative (respe tively,theGâteauxderivative)of
f
×
at
ϕ
is(f
×
)
′
(ϕ) = δ
Lemma 4 We have
sup
x∈X
{|ϕ(x)| − f (x)} = max(f
×
(ϕ), f
×
(−ϕ))
for all
ϕ ∈ A
.Proof. Sin e
|t| = max(t, −t)
onR
,byinverting the supremum andthe maximumwe havesup
x∈X
{|ϕ(x)| − f (x)} = max(sup
x∈X
{ϕ(x) − f (x)} , sup
x∈X
{−ϕ(x) − f (x)})
= max(f
×
(ϕ), f
×
(−ϕ)).
3 The proof of Theorem 1.
The proof is given after some steps. The part
(2) ⇒ (1)
is easy. We prove the part(1) ⇒ (2)
.Let
X
andY
be two omplete metri spa es andA ⊂ C
b
(X)
andB ⊂ C
b
(Y )
be two Bana h spa es satisfying the axiomsA1
-A4
with the same propertyP
β
. (See Ax-ioms 1 and the examples in Proposition 2 ). Let
T : A → B
be an isomorphism and letf : X → R ∪ {+∞}
andg : Y → R ∪ {+∞}
be lower semi ontinuous and bounded from below fun tionswith non emptydomains. Suppose thatsup
y∈Y
{|T ϕ(y)| − g(y)} = sup
x∈X
{|ϕ(x)| − f (x)}
Forall
ϕ ∈ A
and denotebyT
∗
: B
∗
→ A
∗
the adjoint of
T
.3.1 The map
T
has the anoni al form.Lemma 5 : Thereexistsamap
π : dom(g) → dom(f )
andamapε : dom(g) → {−1, 1}
su h that for ally ∈ dom(g)
we have :T
∗
δ
y
= ε(y)δ
π(y)
.Remark 5 Theformulaaboveisequivalent to
T ϕ(y) = ε(y)ϕ ◦ π(y)
for ally ∈ dom(g)
and allϕ ∈ A
.Proof. By lemma1, the set
D(g)
isdense indom(g)
. Lety ∈ D(g)
andψy
˜
∈ B
su h thatg − ˜
ψy
hasastrongminimum aty
. Letc ∈ R
su hthatc >
1
2
g
×
(− ˜
ψy
) − g
×
( ˜
ψy
)
and put
ψ
y
= c + ˜
ψ
y
. The fun tiong − ψ
y
has also a strong minimum aty
and satises by the hoi e ofc
the inequalityg
×
(ψy
) > g
×
(−ψy
)
. Sin eg
×
and so al-sog
×
◦ (−IY
)
(where
IY
denotes the identity map onB
) are ontinuous (Lips hitz) by Proposition 6, there exists an open neighborhoodO(ψ
y
) ⊂ B
ofψ
y
su h thatg
×
(ψ) > g
×
(−ψ)
for allψ ∈ O(ψy)
. Thus, we havemax(g
×
(ψ), g
×
(−ψ)) = g
×
(ψ)
on the open set
O(ψy)
. Sin eg − ψy
has a strong minimum aty
, Theorem 4 guar-antees theβ
-dierentiability ofg
×
at
ψ
y
with(g
×
)
′
(ψ
ψ → max(g
×
(ψ), g
×
(−ψ))
andψ → g
×
(ψ)
oin ide on the open set
O(ψy
)
we on- lude thatψ → max(g
×
(ψ), g
×
(−ψ))
is
β
-dierentiable atψ
y
with derivative equal to(g
×
)
′
(ψy
) = δy
. On the other hand, there existsϕy
∈ A
su h thatψy
= T ϕy
by the surje tivity ofT
. The omposition ofβ
-dierentiable fun tion with linear an ontinu-ousmapisagainβ
-dierentiable. Thus,wehavetheβ
-dierentiabilityofthe omposite mapϕ → max(g
×
(T ϕ), g
×
(−T ϕ))
at
ϕy
onA
and the hain rule formulagiveδy
◦ T
as derivative of the fun tionϕ → max(g
×
(T ϕ), g
×
(−T ϕ))
at
ϕy
. But by hypothesis and by Lemma 4,max(g
×
(T ϕ), g
×
(−T ϕ)) = max(f
×
(ϕ), f
×
(−ϕ))
for all
ϕ ∈ A
. We dedu e thatthe fun tionϕ → max(f
×
(ϕ), f
×
(−ϕ))
is also
β
-dierentiable atϕy
onA
with the same derivativeδy
◦ T
. Lemma 2implies thateither the fun tionϕ → f
×
(ϕ)
or the fun tion
ϕ → f
×
(−ϕ)
is
β
-dierentiable atϕy
with the derivative given bythe derivative ofϕ → max(f
×
(ϕ), f
×
(−ϕ))
at
ϕy
that is hereδy
◦ T
. If it is the fun tionϕ → f
×
(ϕ)
,Theorem4assertthatthereexistsπ(y) ∈ D(f )
su hthat(f
×
)
′
(ϕy
) = δ
π(y)
. If it is the fun tionϕ → f
×
(−ϕ)
, Theorem 4 assert the existen e of point
π(y) ∈ X
su h that(f
×
◦ (−IX
))
′
(ϕy) = (f
×
)
′
(−ϕy) ◦ (−IX
) = δ
π(y)
◦ (−IX
) = −δ
π(y)
whereIX
denotes the identity map onA
. By identifying the derivatives of the two equal fun -tionsϕ → max(g
×
(T ϕ), g
×
(−T ϕ)) = max(f
×
(ϕ), f
×
(−ϕ))
we have:
δ
y
◦ T = δπ(y)
orδy
◦ T = −δ
π(y)
. Letus putε(y) = ±1
. Then we have∀ y ∈ D(g) ∃ π(y) ∈ D(f )/ T
∗
δ
y
:= δ
y
◦ T = ε(y)δπ(y)
.
(3)Now, let
y
beanypointofdom(g)
,there existsbyLemma 1asequen es(yn)n
⊂ D(g)
su hthatyn
→ y
. ThepropertyP
β
(axiom
A
4
)impliesthatδy
n
τ
β
→ δy
. Sin eT
∗
is
τβ
toτβ
ontinue (hereτβ
is the normor the weak-startopology) thenT
∗
δy
n
τ
β
→ T
∗
δy
. Sin e(y
n
)
n
⊂ D(g)
, then from (3)there existsπ(y
n
) ∈ D(f )
su h thatT
∗
δ
y
n
= ε(y
n
)δ
π(y
n
)
. Sowe haveε(yn)δ
π(y
n
)
τ
β
→ T
∗
δy
. Lemma 3impliesthe existen eofarealnumber
ε(y) =
±1
andsomepointπ(y) ∈ X
su hthatε(yn) → ε(y)
inR
andπ(yn) → π(y)
inX
. Thusπ(y) ∈ D(f ) = dom(f )
. TheLemma3impliesalsothatT
∗
δy
= ε(y)δ
π(y)
. Thuswehave proved thatthere existsamapπ : dom(g) → dom(f )
and amapε : dom(g) → {−1, 1}
su h thatfor ally ∈ dom(g)
, we haveT
∗
δy
= ε(y)δ
π(y)
.3.2 The map
π
is bije tive. Lemma 5 applied toT
−1
implies the existen eof a map
π
′
: dom(f ) → dom(g)
and a map
ε
′
: dom(f ) → {−1, 1}
su hthatforall
x ∈ dom(f )
wehave(T
−1
)
∗
δx
= ε
′
(x)δ
π
′
(x)
. Weobtain then ,δx
= T
∗
(ε
′
(x)δ
π
′
(x)
)
= ε
′
(x)T
∗
(δ
π
′
(x)
)
= ε
′
(x)ε(π(x))δ
π(π
′
(x))
By applying the above identity to the ostant fun tion
1
we obtainε
′
(x)ε(π(x)) = 1
. Onthe otherhand,sin e thespa e
A
separatethe pointsofX
(axiom(A2)
),we obtainπ(π
′
(x)) = x
. Thisreasoningapplies for allx ∈ dom(f )
. Byinverting the roles ofT
etT
−1
,wehave also
π
′
(π(y)) = y
3.3 The maps
ε
,π
andπ
−1
are ontinuous.
Let
yn
∈ dom(g)
su h thatyn
→ y ∈ dom(g)
. Let us prove thatπ(yn) → π(y)
indom(f )
. Indeed, by the propertyP
β
( axiom
A
4
) we have thatδ
y
n
τ
β
→ δy
. Sin eT
isτβ
toτβ
ontinuous thenT
∗
δy
n
τ
β
→ T
∗
δy
for theτβ
topology inA
∗
. In other words
ε(yn)δ
π(y
n
)
τ
β
→ ε(y)δπ(y)
whi h implies by Lemma 3 thatε(yn) → ε(y)
inR
andδ
π(y
n
)
→ δπ(y)
τ
β
inA
∗
. Again by the property
P
β
, we have
π(yn) → π(y)
indom(g)
. Thus,ε
andπ
are ontinuous. The same argument applied toT
−1
shows that
π
−1
is also ontinuous.
3.4 The formula
g
= f ◦ π
ondom(g)
.This formula follow fromthe previous armationstogether with Theoreme 4. Indeed, byhypothesis we have
sup
y∈Y
{|T ϕ(y)| − g(y)} = sup
x∈X
{|ϕ(x)| − f (x)}
forall
ϕ ∈ A
. Sin eg
(respf
)isequalto+∞
onY \dom(g)
(respe tively,onX\dom(f )
) we havesup
y∈dom(g)
{|T ϕ(y)| − g(y)} =
sup
x∈dom(f )
{|ϕ(x)| − f (x)}
for all
ϕ ∈ A
. Sin edom(g)
anddom(f )
arehomeomorphi , then by repla ingT ϕ(y)
in the aboveformulawith its expressionε(y)ϕ(π(y))
fory ∈ dom(g)
, we obtainsup
y∈dom(g)
{|ϕ(π(y))| − g(y)} =
sup
x∈dom(f )
{|ϕ(x)| − f (x)} ,
for all
ϕ ∈ A
. Sin eπ
is bije tive,we obtainbythe hange ofvariablex = π
−1
(y)
sup
x∈dom(f )
|ϕ(x)| − g(π
−1
(x)) =
sup
x∈dom(f )
{|ϕ(x)| − f (x)} ,
for all
ϕ ∈ A
. The above formulais also truefor the fun tionsϕ − inf
X
(ϕ) ≥ 0
for allϕ ∈ A
sin eA
ontain the onstants. Repla ingϕ
byϕ − inf
X
(ϕ) ≥ 0
we obtainsup
x∈dom(f )
ϕ(x) − g(π
−1
(x)) − inf
X
(ϕ) =
sup
x∈dom(f )
{ϕ(x) − f (x)} − inf
X
(ϕ),
for all
ϕ ∈ A(X)
. Sosup
x∈dom(f )
ϕ(x) − g(π
−1
(x)) =
sup
x∈dom(f )
{ϕ(x) − f (x)} ,
for all
ϕ ∈ A
. Let us denote byi
dom(f )
the lower semi ontinuous indi ator fun tion whi h is equal to0
ondom(f )
and equal to+∞
otherwise. Theabove formula an be written asfollowsup
x∈X
n
ϕ(x) −
g(π
−1
(x)) + i
dom(f )
o
= sup
x∈X
n
ϕ(x) −
f (x) + i
dom(f )
o
,
for all
ϕ ∈ A
. In otherwords, byusing the notation ofthe onjuga y (see se tion1.4)g ◦ π
−1
+ i
dom(f )
×
(ϕ) = (f + i
dom(f )
)
×
(ϕ)
for all
ϕ ∈ A
. By passingto the se ond onjuga ywe obtain(g ◦ π
−1
+ i
dom(f )
)
××
(x) =
f + i
dom(f )
××
(x)
for all
x ∈ X
. Sin e the fun tionsf + i
dom(f )
andg ◦ π
−1
+ i
dom(f )
arebounded from below and lower semi ontinuous onX
, then by Theoreme 4, ea h of these fun tions oin ide with hisse ond onjuga y. Thus we haveg ◦ π
−1
+ i
dom(f )
= f + i
dom(f )
whi h isequivalent to
g ◦ π
−1
= f
on
dom(f )
aswellasg = f ◦ π
ondom(g)
. Remark 6 By imitating the above prof, we obtainthe followingversion.Theorem 5 Let
X
andY
be two omplete metri spa es andA ⊂ C
b
(X)
andB ⊂
Cb(Y )
be two Bana hspa es satisfyingthe axiomsA1
-A4
(with the same propertyP
β
. See Axioms 1 and the examples in Proposition 2). Let
T : A → B
be an isomorphism and letf : X → R ∪ {+∞}
andg : Y → R ∪ {+∞}
be lower semi ontinuous and bounded frombelow withnonempty domains. Then(1) ⇔ (2)
.(1) g
×
◦ T = f
×
(i.e for all
ϕ ∈ A
,sup
y∈Y
{T ϕ(y) − g(y)} = sup
x∈X
{ϕ(x) − f (x)}
).(2)
There existan homeomorphismπ : dom(g) → dom(f )
su h that, forally ∈ dom(g)
and allϕ ∈ A
we haveT ϕ(y) = ϕ ◦ π(y)
and
g(y) = f ◦ π(y).
Referen es
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