• Aucun résultat trouvé

Experimental variogram of the residuals in the universal kriging (UK) model

N/A
N/A
Protected

Academic year: 2022

Partager "Experimental variogram of the residuals in the universal kriging (UK) model "

Copied!
7
0
0

Texte intégral

(1)

Nicolas DESASSIS Didier RENARD

Technical report

Experimental variogram of the residuals in the universal kriging (UK) model

R141210NDES

(2)

MINES ParisTech

Centre de Géosciences – Equipe Géostatistique 35, Rue Saint-Honoré

77300 FONTAINEBLEAU (France) Tél. +33 1 64 69 47 73

Fax. +33 1 64 69 47 05

Equipe Géostatistique

Visa Jacques RIVOIRARD

(3)

Experimental variogram of the residuals in the universal kriging (UK) model

N. Desassis & D. Renard

1 Model and notations

Suppose that we observe y= (y(x1), . . . , y(xn)) the realization of a random function Y(.) at points x1, . . . , xn of a domain D ⊂Rd.

We suppose that for allx∈ D, Y(x) =

p

X

i=0

βifi(x) +R(x) (1)

whereRis an intrinsic random function (IRF) with variogramγ(R), thefi are some functions of the coordinates (e.g polynomial drifts or external drifts) known everywhere (at the data locations and at the prediction sites) and the βi are some real coefficients. Note that the function f0 is equal to 1 for all x∈ D.

The aim of the methodology is to provide some values for the coefficients βi and a model for the variogram γ(R).

We will note

β = (β0, β1, . . . , βp)0 the (p+ 1)-vector of drift coefficients,

Fthe n×(p+ 1) matrix with (i, j)th termfj−1(xi) (the first column of F is the vector 11n, which has its n components equal to 1),

Y= (Y(x1), . . . , Y(xn)) the random vector of Y(.) at observation sites

R= (R(x1), . . . , R(xn)) the vector of the intrinsic random function at observation sites,

(4)

r= (r(x1), . . . , r(xn)) the current realization of R, that means r(xj) = y(xj)

p

X

i=0

βifi(xj).

With these notations, the model (??) can be written

Y=+R (2)

2 The usual way

2.1 Algorithm

The traditional way to determine β and γ is 1. Compute some estimated coefficients ˆβ 2. Compute the estimated residuals ˆr=yFβˆ

3. Estimate the experimental variogram of the estimated residuals ˆγ for different lags h

4. Fit a model γ to the experimental variogram ˆγ.

The point 1. is easily done. In this work, we will consider the least-square estimator:

βˆ= (F0F)−1F0y Then the point 2. becomes

ˆr=yFβˆ=Py where

P=IM with Ithe identity matrix of sizen and

M=F(F0F)−1F0.

(5)

The point 3. is the computation of the variogram of the residuals for different lags h:

ˆ

γr)(h) = 1 N(h)

X

(i,j)∈V(h)

ˆ γijr) where

ˆ

γijr)= 1

2r(xi)r(xˆ j))2,

(i, j)∈ V(h) is the set of pairs (i, j) such as xixj 'hand N(h) stands for the number of such pairs.

2.2 Bias of the methodology

A major limitation of this methodology comes from the fact that the experi- mental variogram computed from the estimated residuals ˆris biased. In other words, if we compute for a given h the expectation of ˆγ( ˆR)(h) the random version of ˆγr)(h) and if we compare with the target γ(R)(h) we have:

E[ˆγ( ˆR)(h)]γ(R)(h).

To see that, first note that we can write the estimated residuals as follows:

Rˆ =PY=P(Fβ+R) = PR (3) since PF=FMF=FF(F0F)−1F0F= 0.

Now, let’s compute E[ˆγij( ˆR)] where ˆγij( ˆR) is the random version of ˆγijr).

E[ˆγij( ˆR)] = 1

2E[( ˆR(xi)R(xˆ j))2]

= 1

2Var( ˆR(xi)R(xˆ j)) since E[ ˆR(xi)] = 0.

Now, let’s first remark that

R(xˆ i)R(xˆ j) = (Pi.Pj.)R,

where Pi. and Pj. are respectively the row vectors of the ith and the jth line of P.

(6)

It follows that ˆR(xi)R(xˆ j) can be seen as an authorized linear combi- nation (ALC) of the elements ofR. Indeed, let’s compute S(Pi.), the sum of the components of Pi..

S(Pi.) = 1S(Mi.)

= 1Mi.11n

= 0

since MF=F and the first column of Fis equal to 11n. Therefore, we can compute the variance of the ALC.

First, note that (??) implies:

R(xˆ i)R(xˆ j) =R(xi)Mi.R(R(xj)Mj.R)

=R(xi)R(xj)

n

X

k=1

MikR(xi) +

n

X

k=1

MjkR(xj) whereMij stands for the (i, j)th term of the matrix M.

Therefore, we have

E[ˆγij( ˆR)] = 1

2Var(R(xi)R(xj)) +bij

wherebij, the bias associated to the pair (i, j), can be written:

bij =

n

X

k=1

(MikMjk)(γ(R)(hik)γ(R)(hjk))

+

n

X

k=1 n

X

l=1

MikMjl MikMil+MjkMjl 2

γ(R)(hkl)

(4)

wherehkl stands for the separation vectorxkxl. The total bias for the lagh is:

B(h) = 1 N(h)

X

(i,j)∈V(h)

bij. (5)

To compute the total bias associated to the experimental variogram at lag h, we need to know the value of the variogram at all the distances which is exactly the quantity we are trying to compute. To circumvent this difficulty, we use the iterative procedure described in the next section.

(7)

3 Bias correction

To perform the bias correction, we propose the following algorithm (inspired from the one of Beckers and Bogaert, 1998):

Algorithm to compute γˆ(r)(h) Initialisation:

At step 0 do:

(a) Compute ˆγr)(h), the experimental variogram of the estimated residuals.

(b) Set ˆγ(r)(h) = ˆγr)(h).

Iterations:

At stepn do:

(a) Fit a model γ(n) on ˆγ(r)(h).

(b) Compute the bias B(n)(h) by using equations (??) and (??) with γ(R) =γ(n).

(c) Compute the corrected experimental variogram ˆ

γ(r)= ˆγr)B(n)(h)

Note that step (a) at stepn can be performed with the algorithm of Desassis and Renard (2012).

References

Beckers, F. and Bogaert, P. (1998) Nonstationarity of the mean and unbi- ased variogram estimation: extension of the weighted least-square method.

Mathematical Geology 30 (2)

Desassis N, Renard D (2013) Automatic Variogram Modeling by Iterative Least Squares: Univariate and Multivariate Cases. Mathematical Geo- sciences 45:453–470

Références

Documents relatifs

A relationship between CEPLIS and EPBS would be of benefit to EPBS in pursuing our agenda in Brussels.. Last year in Athens we were examining

But for finite depth foliations (which have two sided branching), there are many examples where it is impossible to make the pseudo-Anosov flow transverse to the foliation [Mo5] and

We prove a theorem concerning the quotient structure that parallels the gener- alized dual girth conjecture proved in [1] and the Holmes–Thompson dual volumes theorem [6], which in

98 The debate revolved around ‘the lack of democracy at the international level and the resulting concentration of economic and political power of the North; the rigged rules of the

i) We need two image charges, one for each one of the real charges producing the constant external electric field.. The first term is just the potential due to the external field

Estimation of the regional variogram: relative standard deviation S E (h) in the Gaussian case for a spherical covariance with range a (on the left) and for a variogram of type |h| α

In recent years the idea of a guaranteed minimum income has received considerable attention, 2 and the response to the pandemic has, in effect, amounted to something like

- Nikos Koutsiaras, Department of Political Science and Public Administration, University of Athens [European integration, Employment and Labour Market Policy, Social