V
OLKER
K
ESSLER
On the minimum of the unit lattice
Journal de Théorie des Nombres de Bordeaux, tome
3, n
o2 (1991),
p. 377-380
<http://www.numdam.org/item?id=JTNB_1991__3_2_377_0>
© Université Bordeaux 1, 1991, tous droits réservés.
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
On
the
minimum
of the
unit lattice.
PAR VOLKER KESSLER
1. Introduction.
Computations
in lattices oftenrequire
a lower bound for the minimumof the
lattice,
both forpractical purposes
and for a theoreticalanalysis
ofthe
algorithms,
e.g.[1]
and[2].
In this paper we recall two results of Dobrowolski
[3]
andSmyth
[5]
in order toget
such a bound for the unit lattice.2. Lower bound.
Let Ii be a finite extension
of Q
ofdegree
n with maximal order R. For1 i n we denote
by
the n different
embeddings
of K into the field C ofcomplex
numbers. Thefirst rl of those
embeddings
arereal,
the last2r2
embeddings
are non-realand numbered such that the
(rl
+ r2 +i)th
embedding
is thecomplex-conjugation
of the(r,
+i)th
embedding.
Then thelogarithmic
map isgiven
by
with the unit rank r = ri + r2 - 1 and
The kernel of
Log
consistsexactly
of the roots of theunity lying
in K. We define the minamumA(L)
of the unat lattice L :=Log(R*)
by
where
11 II
denotes the Euclidean-
THEOREM : A lower bound
for
the minimumA(L)
isgiven by
which is "a bit"
larger
thanThus the inverse
1/A(L)
isof
themagnitude
0(nl/2+f)
for every
c > 0. PROOF. Let EE R*
be a unit ofdegree
m overQ,
which is no root ofunity.
Without loss ofgenerality
we can assume that m =n, because if
[[Log E~~
islarger
thanp(K’)
for a subfield K’ of li it is alsolarger
thanI~~I~~.
-We are interested in two subsets of the
conjugates
e~,’’’ ,
Since E is no root of
unity
S isnon-empty
and therefore T cannot beempty
because ofN(e)
= 1.We call c
reciprocal
if E isconjugate
i.e. its minimalpolynomial
f(X)
= X "’ + + ... +ao satisfies
If e is
non-reciprocal
we know from the theorem of[5]
thatBut from
N(E)
= 1 it followsThe value
If(r+l)1
I
does not occur in the norm ofLog(E).
But as a consequence of(3)
it does not matter if r + 1 lies inS
or in T and so we can assume without restriction that r +1 ~
S. Thus(The
secondinequality
follows from the well known normequivalence
be-tween 1-norm and Euclidean
norm.)
For
reciprocal
E we knowby
Theorem 1 of[3] :
We now use the
Taylor
series of thelogarithm
(Iyl
1) :
The
inequality
followsdirectly
fromLagrange’s representation
of the resi-due.Applying
(5)
to(4)
yields
Since E is
reciprocal
the inverses of theconjugates
of c are alsoconjugate
to E. This
implies
that the numbers ofconjugates
outside the unit circleequals
the number ofconjugates
inside the unitcircle,
i.eAgain
by
(3)
+1 ~
Swhich is
larger
thanBecause of
2~~~~~~ ) ~
0.001178 we thusproved
the lower bound.REMARK. If the
conjecture
of Schinzel and Zassenhaus[5]
is correct theterm be substituted
by
a constantindependent
of n. This term(
g
n )
bound would be
provable
the best one(up
toconstants).
REFERENCES
[1]
Buchmann, Zur Komplexität der Berechnung von Einheiten und Klassenzahlenal-gebraicher Zahlkörper, Habilitationsschrift Düsseldorf
(1987).
[2]
Buchmann, Kessler, Computing a reduced lattice basis from a generating system, toappear.
[3]
Dobrowolski, On a question of Lehmer and the number of irreducible factors of apolynomial, Acta arithmetica 34
(1979),
391-401.[4]
Schinzel, Zassenhaus, A refinement of two theorems of Kronecker, Mich. Math. J. 12(1965),
81-84.[5]
Smyth, On the product of the conjugates outside the unit circle of an algebraic integer, Bull. London Math. Soc. 3(1971),
169-175.Volker Kessler Siemens AG ZFE ST SN 5
Otto-Hahn Ring 6