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Nonlinear Analysis
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Existence of multiple positive solutions for nonhomogeneous elliptic problems in R
NTiexiang Li
a, Tsung-fang Wu
b,∗aDepartment of Mathematics, Southeast University, Nanjing 211189, PR China
bDepartment of Applied Mathematics, National University of Kaohsiung, Kaohsiung 811, Taiwan
a r t i c l e i n f o
Article history:
Received 31 October 2011 Accepted 17 May 2012 Communicated by S. Ahmad Keywords:
Nonhomogeneous elliptic problems Palais–Smale
Multiple positive solutions
a b s t r a c t
In this paper, we study the multiplicity of positive solutions for the nonhomogeneous elliptic problem:−∆u+λu = f(x)up−1+µh(x)inRN. We will show how the shape of the graph off(x)affects the number of positive solutions.
©2012 Elsevier Ltd. All rights reserved.
1. Introduction
In this paper, we study the multiplicity of positive solutions for the following nonhomogeneous elliptic problem:
−
∆u+ λ
u=
f(
x)
up−1+ µ
h(
x)
inRN,
u
>
0 inRN,
u
∈
H1
RN
, (
Eλ,µ)
where 2
<
p<
N2N−2(
N≥
3) ,
the parametersλ, µ >
0,
f∈
C
RN
andh
∈
L2
RN
\ {
0}
withh≥
0.
Under the assumption
µ ̸=
0, our equation(Eλ,µ)can be regarded as a perturbation problem of the following semilinear elliptic equation:
−
∆u+ λ
u=
f(
x)
up−1 inRN,
u
>
0 inRN,
u
∈
H1
RN
.
(1)
It is known that the existence of positive solutions of Eq.(1)is affected by the shape of the graph off
(
x)
. This has been the focus of a great deal of research by several authors (see [1–7] etc.). Furthermore, iff is a positive constant, then Eq.(1) has a unique radially symmetric positive solution (see [8,9]).Whenf
≡
1,
his the exponential decay andµ
small, Hirano [10] and Zhu [11] showed that Eq.(Eλ,µ)admits at least two positive solutions. Generalizations of the results of [10,11] were made by Cao and Zhou [12], Jeanjean [13] and Adachi and Tanaka [14,15]. In [15] Adachi and Tanaka showed the existence of at least four positive solutions of Eq.(Eλ,µ)under the following assumptions:∗Corresponding author. Tel.: +886 7 591 9519; fax: +886 7 591 9344.
E-mail addresses:txli@seu.edu.cn(T. Li),tfwu@nuk.edu.tw(T.-f. Wu).
0362-546X/$ – see front matter©2012 Elsevier Ltd. All rights reserved.
doi:10.1016/j.na.2012.05.012
(f1) f
(
x) →
1 as|
x| → ∞ ,
(f2) f
(
x) ∈ (
0,
1]
for allx∈
RNandf(
x) ̸≡
1,
(f3) there existδ >
0 andC>
0 such thatf
(
x) −
1≥ −
Cexp( − (
2+ δ) |
x| )
for allx∈
RN,
andµ
sufficiently small. In [12–14], the general equations
−
∆u+ λ
u=
g(
x,
u) + µ
h(
x)
inRN,
u
>
0 inRN,
u
∈
H1
RN
were studied, wheregsatisfies some suitable conditions andh
∈
H−1
RN
\ {
0}
is non-negative, and the existence of at least two positive solutions whenµ
sufficiently small was proved.The main purpose of this paper is to use the shape of the graph off
(
x)
to prove the multiplicity of positive solutions for Eq.(Eλ,µ). First, we consider the following assumptions:(
f3)
there existδ >
0 andC>
0 such thatf
(
x) −
1≥ −
Cexp( − (
1+ δ) |
x| )
for allx∈
RN; (
f4)
there exist some pointsx1,
x2, . . . ,
xkinRNsuch thatf
xi
are strict maximums onRNwith 1
=
f
xi
≡
max
f
(
x) |
x∈
RN
for alli
=
1,
2, . . . ,
k.
Then we have the following results.Theorem 1.1. Suppose that the function f satisfies the conditions
(
f1)
,(
f2)
and(
f3)
. Then for each h∈
L2
RN
\ {
0}
with h≥
0 there exists a positive numberΛ∗such that for anyλ, µ >
0withµλ
N4−pp−−12<
Λ∗, Eq.(Eλ,µ)has at least four positive solutions.Theorem 1.2. Suppose that the function f satisfies the conditions
(
f1)
,(
f2)
,(
f3)
and(
f4)
. Then for each h∈
L2
RN
\ {
0}
with h≥
0there exist positive numbersΛ∗andλ
0such that for anyλ > λ
0andµ >
0withµλ
N4−pp−−12<
Λ∗, Eq.(Eλ,µ)has at least k+
3positive solutions.This paper is organized as follows. In Section2, we prove the existence of four positive solutions. In Section3, we prove the existence of otherkpositive solutions. Based on this result, we can proveTheorem 1.2.
2. Existence of four solutions By the change of variables
η =
√1λ
, v (
x) = η
2/(p−2)u(η
x)
, Eq.(Eλ,µ)is transformed to
−
∆v + v =
fηv
p−1+ µη
2(pp−−21)hη inRN,
v >
0 inRN,
v ∈
H1
RN ,
(2)
where fη
=
f(η
x)
and hη=
h(η
x)
. Associated with Eq. (2), we consider the following minimization problem: forη >
0, µ ≥
0 andu∈
H1
RN
define Iη,µ(
u) =
12
∥
u∥
2H1
−
1 p
RN
fηup+dx
− µη
2(pp−−21)
RN
hηudx
;
Mη,µ=
u
∈
H1
RN
\ {
0} |
Iη,µ′
(
u) ,
u
=
0
; α
η,µ=
inf
Iη,µ
(
u) |
u∈
Mη,µ
where∥
u∥
H1=
RN
|∇
u|
2+
u2
1/2is a standard norm inH1
RN
andu+=
max{
0,
u}
. It is well known that the solutions of Eq.(2)are the critical points of the energy functionalIη,µ(see [16]).Now, we study the break down of the (PS)-condition forIη,µ
.
First, we introduce the following elliptic equation:
−
∆u+
u=
up−1 inRN,
u
>
0 inRN,
u
∈
H1
RN
.
(3)
We define the energy functionalI∞
:
H1
RN
→
Ras follows I∞(
u) =
12
∥
u∥
2H1
−
1 p
RN
up+dx
.
Using the results of Berestycki and Lions [8] and Kwong [9], Eq.(3)has a unique radially symmetric positive solution
w (
x)
such thatα
∞=
I∞(w) =
inf
I∞
(
u) |
for any positive solutionuof Eq.(3)
and for anyδ >
0 andx∈
RN,
w (
x) ≤
Cexp( − (
1− δ) |
x| )
and|∇ w (
x) | ≤
Cexp( − (
1− δ) |
x| )
for someC
>
0. Moreover, the unique solutionw (
x)
of Eq.(3)plays an important role in describing the asymptotic behavior of a (PS)-sequence forIη,µ.
Proposition 2.1. Let
{
un}
be a (PS)-sequence in H1(
RN)
for Iη,µ. Then there exist a subsequence{
un}
, an integer m∈
N∪ {
0} ,
m sequences
x1n
,
x2n
, . . . ,
xmn
⊂
RNand a critical point u0∈
H1(
RN)
of Iη,µsuch that
xin
→ ∞
for 1≤
i≤
m,
xin−
xjn
→ ∞
for 1≤
i,
j≤
m and i̸=
j,
un⇀
u0 weakly in H1(
RN),
un
=
u0+
m
i=1
w( · −
xin) +
o(
1)
strongly in H1(
RN),
Iη,µ(
un) =
Iη,µ(
u0) +
mI∞(w) +
o(
1).
Proof. This is a standard result. See Lions [6,7] and Benci and Cerami [17] for analogous arguments.
2.1. Existence of a local minimum Define
ψ
η,µ(
u) =
Iη,µ′
(
u) ,
u
= ∥
u∥
2H1
−
RN
fηup+dx
− µη
2(pp−−21)
RN
hηudx
.
Clearly, foru∈
Mfη,hη, we have ψ
η,µ′(
u) ,
u
= ∥
u∥
2H1
− (
p−
1)
RN
fηup+dx (4)
= (
2−
p) ∥
u∥
2H1
− (
1−
p) µη
2(pp−−21)
RN
hηudx
.
(5)Let
Λ0
=
p−
2 p−
1
Spp/2 p−
1
p−12∥
h∥
−1L2
.
Then we have the following result.Lemma 2.2. For each
η, µ >
0withµη
2(pp−−21)−N2<
Λ0, we have ψ
η,µ′(
u) ,
u
̸=
0 for all u∈
Mη,µ.
Proof. Our proof is almost the same as that in [18, Lemma 2.3]. Suppose the contrary. Then there exist
η, µ >
0 withµη
2(pp−−21)−N2<
Λ0such that ψ
η,µ′(
u) ,
u
=
0.
Then, foru∈
Mη,µwith
ψ
η,µ′(
u) ,
u
=
0, by(5)and the Hölder and Sobolev inequalities we have∥
u∥
2H1
= µη
2(pp−−21)p−
1 p−
2
RN
hηudx
≤ µη
2(pp−−21)−N2p−
1p
−
2∥
h∥
L2∥
u∥
H1and so
∥
u∥
H1≤ µη
2(pp−−21)−N2p−
1 p−
2∥
h∥
L2.
Similarly, using(4),
(
f2)
and the Sobolev inequality we have 1p
−
1∥
u∥
2H1
=
RN
fηup+dx
≤
S−p p2
∥
u∥
pH1
,
which implies∥
u∥
H1≥
Spp/2 p−
1
p−12for all
µ ≥
0.
Hence, we must haveµη
2(pp−−21)−N2≥
p−
2 p−
1
Spp/2 p−
1
p−12∥
h∥
−1L2
=
Λ0 which is a contradiction. This completes the proof.ByLemma 2.2, we may writeMη,µ
=
M+η,µ∪
M−η,µ, where M+η,µ=
u
∈
Mη,µ
∥
u∥
2H1
− (
p−
1)
RN
fη
|
u+|
pdx>
0
;
M−η,µ
=
u
∈
Mη,µ
∥
u∥
2H1
− (
p−
1)
RN
fη
|
u+|
pdx<
0
and define
α
η,µ+=
infu∈M+ η,µ
Iη,µ
(
u)
andα
η,µ−=
infu∈M− η,µ
Iη,µ
(
u) .
Then we have the following result.Theorem 2.3. We have the following.
(i)
α
η,µ+<
0for allη, µ >
0withµη
2(pp−−21)−N2<
Λ0.
(ii) If
η, µ >
0withµη
2(pp−−21)−N2<
Λ20, thenα
−η,µ>
c0for some c0>
0.
In particular, for each
η, µ >
0withµη
2(pp−−21)−N2<
Λ20, Eq.(2)has a unique positive solution u1η,µ∈
M+η,µsuch that Iη,µ
u1η,µ
= α
η,µ+= α
η,µ.
Proof. Our proof is almost the same as that in [14, Lemma 1.4] and [19, Theorem 3.1].
2.2. Existence of two solutions
First, we establish the decay estimate for solutions of Eq.(2).
Lemma 2.4. Let u0
∈
H1
RN
be a positive solution of Eq.(Eλ,µ). Then
v
0(
x) = η
2/(p−2)u0(η
x)
is a positive solution of Eq.(2)andv
0(
x) ≥
Cη
2(6p−−p2)exp( − (
1+ ε) η |
x| ) ,
for all|
x| ≥
R0for some C>
0.
(6) Proof. Our proof is almost the same as that in [20,21].Forc
>
0, we define Iη,c0(
u) =
12
∥
u∥
2H1
−
1 p
RN
cfη
|
u+|
pdx;
Mcη,0
=
u∈
H1
RN
\ {
0} |
Iη,c0
′(
u) ,
u
=
0
;
Mη,0=
u
∈
H1
RN
\ {
0} |
Iη,′0
(
u) ,
u
=
0
.
Note thatIη,0
=
Iη,c0forc=
1, and for eachu∈
M−η,µthere is a uniquet1=
t1(
u) >
0 such thatt1u∈
Mη,0. Then we have the following results.Lemma 2.5. Suppose that
η, µ >
0withµη
2(pp−−21)−N2<
Λ20. Then for each u∈
M−η,µ, we have the following.(i) There is a unique tc
(
u) >
0such that tc(
u)
u∈
Mcη,0andmax
t≥0 Iη,c0
(
tu) =
Iη,c0
tc(
u)
u
=
1 2−
1p
c−2 p−2
∥
u∥
pH1
RNfη
|
u+|
pdx
p−22.
(ii)Forσ ∈
0
, µ
−1η
N2−2(pp−−21) ,
Iη,µ(
u) ≥
1
− σ µη
2(pp−−21)−N2
p p−2
Iη,0
t1u
− η
2(pp−−21)−N2 2σ ∥
h∥
2L2
and
Iη,µ
(
u) ≤
1
+ σ µη
2(pp−−21)−N2
p p−2
Iη,0
t1u
+ η
2(pp−−21)−N2 2σ ∥
h∥
2L2
.
Proof. (i) Similar to the proof of Lemma 7.1 in Wu [19].(ii) For eachu
∈
M−η,µ, letc=
1/
1
− σµη
2(pp−−21)−N2
,tc
=
tc(
u) >
0 andt1=
t1(
u) >
0 such thattcu∈
Mcη,0and t1u∈
Mη,0. Forσ ∈ (
0,
1)
, we have
RN
hηtcudx
≤ η
−N2
tcu
H1∥
h∥
L2≤ ση
−N2 2
tcu
2 H1
+ η
−N22
σ ∥
h∥
2L2
.
Then by part (i) and2(pp−−21)−
N2
>
0,
supt≥0
Iη,µ
(
tu) ≥
Iη,µ
tcu
≥
1 2
tcu
2 H1
−
1p
RN
fη
tcu+
dx− µη
2(pp−−21) ση
−N2 2
tcu
2 H1
+ η
−N22
σ ∥
h∥
2L2
=
1 2c
tcu
2 H1
−
1p
RN
fη
tcu+
pdx
− µη
2(pp−−21)−N2 2σ ∥
h∥
2L2
=
1 cIη,c0
tcu
− µη
2(pp−−21)−N2 2σ ∥
h∥
2L2
=
1
− σ µη
2(pp−−21)−N2
p p−2
1 2
−
1p
∥
u∥
pH1
RNfη
|
u+|
pdx
p−22− µη
2(pp−−21)−N2 2σ ∥
h∥
2L2
=
1
− σµη
2(pp−−21)−N2
p p−2
Ifη,0
t1u
− µη
2(pp−−21)−N2 2σ ∥
h∥
2L2
.
Moreover, byTheorem 2.3and [20, Lemma 2.4],sup
t≥0
Iη,µ
(
tu) =
Iη,µ(
u) .
Thus,Iη,µ
(
u) ≥
1
− σ µη
2(pp−−21)−N2
p p−2
Ifη,0
t1u
− µη
2(pp−−21)−N2 2σ ∥
h∥
2L2
.
Moreover,Ifη,hη
(
tu) ≤
1
+ σ µη
2(pp−−21)−N2
2
∥
tu∥
2H1
−
1 p
RN
fη
|
tu+|
pdx+ µη
2(pp−−21)−N2 2σ ∥
h∥
2L2
and so
Ifη,hη
(
u) ≤
1
+ σ µη
2(pp−−21)−N2
p p−2
Ifη,0
t1u
+ µη
2(pp−−21)−N2 2σ ∥
h∥
2L2
.
This completes the proof.Let
w (
x)
be a unique radially symmetric positive solution of Eq.(3)ande∈
SN−1=
x
∈
RN| |
x| =
1
. We denote
w
l(
x) = w (
x+
le) ,
l∈ (
0, ∞ ) .
Then we have the following results.
Lemma 2.6. Suppose that
η, µ >
0withµη
2(pp−−21)−N2<
Λ20.
Then (i) there exists t0>
0such thatIη,µ
u1η,µ
+
tw
l <
Iη,µ
u1η,µ
for all t
≥
t0and e∈
SN−1;
(ii) there exists l1>
0such that for l>
l1,
sup
t≥0
Iη,µ
u1η,µ
+
tw
l <
Iη,µ
u1η,µ
+ α
∞= α
η,µ+ α
∞,
where u1η,µis the local minimum inTheorem2.3.Proof. (i) Sinceu1η,µis a positive solution of Eq.(2), using the fact that
RN
∇
uη,µ∇ w
ldx= −
RN
w
l∆uη,µdxwe have Iη,µ
u1η,µ
+
tw
l ≤
Iη,µ
u1η,µ
+
t2
2
∥ w
l∥
2H1
+
t
RN
fη
w
l
u1η,µ
p−1dx
−
tp
p
RN
fη
w
lpdx≤
Iη,µ
u1η,µ
+
t2
2
∥ w
l∥
2H1
+
t
RN
fη
w
l
u1η,µ
p−1dx
−
tp
p
BN(0;1)
w
pdx.
Sincep>
2 andw >
0 inRN, we can chooset0>
0 large enough such that (i) holds.(ii) SinceIη,µis continuous inH1
RN
, there existst1
>
0 such that forl>
0,
Iη,µ
u1η,µ
+
tw
l <
Iη,µ
u1η,µ
+ α
∞ for allt<
t1ande∈
SN−1.
Using part (i) we know that forl>
0,
sup
t≥t0
Iη,µ
u1η,µ
+
tw
l <
Iη,µ
u1η,µ
+ α
∞ for alle∈
SN−1.
Thus, we only need to show that there existsl1>
0 such that forl>
l1,
sup
t1≤t≤t0
Iη,µ
u1η,µ
+
tw
l <
Iη,µ
u1η,µ
+ α
∞ for alle∈
SN−1.
By Brown and Zhang [22] and Willem [23], we know thatsup
t>0I∞
(
tw) =
I∞(w) = α
∞.
(7)Forl
>
0 andt1≤
t≤
t0,
Iη,µ
u1η,µ
+
tw
l
≤
Iη,µ
u1η
+
I∞(
tw) +
1 p
RN
1−
fη
tp
w
pldx−
1 p
BN(le;1) fη
t1wl 0
u1η,µ+
s
p−1−
u1η,µ
p−1−
sp−1dsdx≤
Iη,µ
u1η,µ
+
I∞(
tw) + (
I) − (
II) .
Using(7), we havesup
t1≤t≤t0
Iη,µ
u1η,µ
+
tw
l ≤
Iη,µ
u1η,µ
+
I∞(w) + (
I) − (
II) .
We recall the fact that for somec>
0w ( |
x| ) |
x|
N−21exp( |
x| ) →
c as|
x| → ∞ .
(See [1,2,9,24]). In particular, there exists a constantC0
>
0 such thatw (
x) ≤
C0exp( −|
x| )
for allx∈
RN.
Then by the Taylor expansion,
t1wl 0
u1η,µ+
s
p−1−
u1η,µ
p−1−
sp−1ds≥
t1wl0
(
p−
1)
sp−2u1η,µ−
u1η,µ
p−1ds
=
(
t1w
l)
p−2−
u1η,µ
p−2
t1