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Contents lists available atSciVerse ScienceDirect

Nonlinear Analysis

journal homepage:www.elsevier.com/locate/na

Existence of multiple positive solutions for nonhomogeneous elliptic problems in R

N

Tiexiang Li

a

, Tsung-fang Wu

b,

aDepartment of Mathematics, Southeast University, Nanjing 211189, PR China

bDepartment of Applied Mathematics, National University of Kaohsiung, Kaohsiung 811, Taiwan

a r t i c l e i n f o

Article history:

Received 31 October 2011 Accepted 17 May 2012 Communicated by S. Ahmad Keywords:

Nonhomogeneous elliptic problems Palais–Smale

Multiple positive solutions

a b s t r a c t

In this paper, we study the multiplicity of positive solutions for the nonhomogeneous elliptic problem:−∆uu = f(x)up1h(x)inRN. We will show how the shape of the graph off(x)affects the number of positive solutions.

©2012 Elsevier Ltd. All rights reserved.

1. Introduction

In this paper, we study the multiplicity of positive solutions for the following nonhomogeneous elliptic problem:

u

+ λ

u

=

f

(

x

)

up1

+ µ

h

(

x

)

inRN

,

u

>

0 inRN

,

u

H1

RN

, (

Eλ,µ

)

where 2

<

p

<

N2N2

(

N

3

) ,

the parameters

λ, µ >

0

,

f

C

RN

andh

L2

RN

\ {

0

}

withh

0

.

Under the assumption

µ ̸=

0, our equation(Eλ,µ)can be regarded as a perturbation problem of the following semilinear elliptic equation:

u

+ λ

u

=

f

(

x

)

up1 inRN

,

u

>

0 inRN

,

u

H1

RN

.

(1)

It is known that the existence of positive solutions of Eq.(1)is affected by the shape of the graph off

(

x

)

. This has been the focus of a great deal of research by several authors (see [1–7] etc.). Furthermore, iff is a positive constant, then Eq.(1) has a unique radially symmetric positive solution (see [8,9]).

Whenf

1

,

his the exponential decay and

µ

small, Hirano [10] and Zhu [11] showed that Eq.(Eλ,µ)admits at least two positive solutions. Generalizations of the results of [10,11] were made by Cao and Zhou [12], Jeanjean [13] and Adachi and Tanaka [14,15]. In [15] Adachi and Tanaka showed the existence of at least four positive solutions of Eq.(Eλ,µ)under the following assumptions:

Corresponding author. Tel.: +886 7 591 9519; fax: +886 7 591 9344.

E-mail addresses:txli@seu.edu.cn(T. Li),tfwu@nuk.edu.tw(T.-f. Wu).

0362-546X/$ – see front matter©2012 Elsevier Ltd. All rights reserved.

doi:10.1016/j.na.2012.05.012

(2)

(f1) f

(

x

) →

1 as

|

x

| → ∞ ,

(f2) f

(

x

) ∈ (

0

,

1

]

for allx

RNandf

(

x

) ̸≡

1

,

(f3) there exist

δ >

0 andC

>

0 such that

f

(

x

) −

1

≥ −

Cexp

( − (

2

+ δ) |

x

| )

for allx

RN

,

and

µ

sufficiently small. In [12–14], the general equations

u

+ λ

u

=

g

(

x

,

u

) + µ

h

(

x

)

inRN

,

u

>

0 inRN

,

u

H1

RN

were studied, wheregsatisfies some suitable conditions andh

H1

RN

\ {

0

}

is non-negative, and the existence of at least two positive solutions when

µ

sufficiently small was proved.

The main purpose of this paper is to use the shape of the graph off

(

x

)

to prove the multiplicity of positive solutions for Eq.(Eλ,µ). First, we consider the following assumptions:

(

f3

)

there exist

δ >

0 andC

>

0 such that

f

(

x

) −

1

≥ −

Cexp

( − (

1

+ δ) |

x

| )

for allx

RN

; (

f4

)

there exist some pointsx1

,

x2

, . . . ,

xkinRNsuch thatf

xi

are strict maximums onRNwith 1

=

f

xi

max

f

(

x

) |

x

RN

for alli

=

1

,

2

, . . . ,

k

.

Then we have the following results.

Theorem 1.1. Suppose that the function f satisfies the conditions

(

f1

)

,

(

f2

)

and

(

f3

)

. Then for each h

L2

RN

\ {

0

}

with h

0 there exists a positive numberΛsuch that for any

λ, µ >

0with

µλ

N4pp12

<

Λ, Eq.(Eλ,µ)has at least four positive solutions.

Theorem 1.2. Suppose that the function f satisfies the conditions

(

f1

)

,

(

f2

)

,

(

f3

)

and

(

f4

)

. Then for each h

L2

RN

\ {

0

}

with h

0there exist positive numbersΛand

λ

0such that for any

λ > λ

0and

µ >

0with

µλ

N4pp12

<

Λ, Eq.(Eλ,µ)has at least k

+

3positive solutions.

This paper is organized as follows. In Section2, we prove the existence of four positive solutions. In Section3, we prove the existence of otherkpositive solutions. Based on this result, we can proveTheorem 1.2.

2. Existence of four solutions By the change of variables

η =

1

λ

, v (

x

) = η

2/(p2)u

x

)

, Eq.(Eλ,µ)is transformed to

 

 

v + v =

fη

v

p1

+ µη

2(pp21)hη inRN

,

v >

0 inRN

,

v ∈

H1

RN

 ,

(2)

where fη

=

f

x

)

and hη

=

h

x

)

. Associated with Eq. (2), we consider the following minimization problem: for

η >

0

, µ ≥

0 andu

H1

RN

define Iη,µ

(

u

) =

1

2

u

2

H1

1 p

RN

fηup+dx

− µη

2(pp21)

RN

hηudx

;

Mη,µ

= 

u

H1

RN

\ {

0

} | 

Iη,µ

(

u

) ,

u

=

0

; α

η,µ

=

inf

Iη,µ

(

u

) |

u

Mη,µ

where

u

H1

= 

RN

|∇

u

|

2

+

u2

1/2

is a standard norm inH1

RN

andu+

=

max

{

0

,

u

}

. It is well known that the solutions of Eq.(2)are the critical points of the energy functionalIη,µ(see [16]).

Now, we study the break down of the (PS)-condition forIη,µ

.

First, we introduce the following elliptic equation:

u

+

u

=

up1 inRN

,

u

>

0 inRN

,

u

H1

RN

.

(3)

(3)

We define the energy functionalI

:

H1

RN

Ras follows I

(

u

) =

1

2

u

2

H1

1 p

RN

up+dx

.

Using the results of Berestycki and Lions [8] and Kwong [9], Eq.(3)has a unique radially symmetric positive solution

w (

x

)

such that

α

=

I

(w) =

inf

I

(

u

) |

for any positive solutionuof Eq.(3)

and for any

δ >

0 andx

RN

,

w (

x

) ≤

Cexp

( − (

1

− δ) |

x

| )

and

|∇ w (

x

) | ≤

Cexp

( − (

1

− δ) |

x

| )

for someC

>

0. Moreover, the unique solution

w (

x

)

of Eq.(3)plays an important role in describing the asymptotic behavior of a (PS)-sequence forIη,µ

.

Proposition 2.1. Let

{

un

}

be a (PS)-sequence in H1

(

RN

)

for Iη,µ. Then there exist a subsequence

{

un

}

, an integer m

N

∪ {

0

} ,

m sequences

x1n

 , 

x2n

 , . . . , 

xmn

RNand a critical point u0

H1

(

RN

)

of Iη,µsuch that

xin

 → ∞

for 1

i

m

,

xin

xjn

 → ∞

for 1

i

,

j

m and i

̸=

j

,

un

u0 weakly in H1

(

RN

),

un

=

u0

+

m

i=1

w( · −

xin

) +

o

(

1

)

strongly in H1

(

RN

),

Iη,µ

(

un

) =

Iη,µ

(

u0

) +

mI

(w) +

o

(

1

).

Proof. This is a standard result. See Lions [6,7] and Benci and Cerami [17] for analogous arguments.

2.1. Existence of a local minimum Define

ψ

η,µ

(

u

) = 

Iη,µ

(

u

) ,

u

= ∥

u

2

H1

RN

fηup+dx

− µη

2(pp21)

RN

hηudx

.

Clearly, foru

Mfη,hη, we have

 ψ

η,µ

(

u

) ,

u

= ∥

u

2

H1

− (

p

1

) 

RN

fηup+dx (4)

= (

2

p

) ∥

u

2

H1

− (

1

p

) µη

2(pp21)

RN

hηudx

.

(5)

Let

Λ0

=

p

2 p

1

Spp/2 p

1

p12

h

1

L2

.

Then we have the following result.

Lemma 2.2. For each

η, µ >

0with

µη

2(pp21)N2

<

Λ0, we have

 ψ

η,µ

(

u

) ,

u

̸=

0 for all u

Mη,µ

.

Proof. Our proof is almost the same as that in [18, Lemma 2.3]. Suppose the contrary. Then there exist

η, µ >

0 with

µη

2(pp21)N2

<

Λ0such that

 ψ

η,µ

(

u

) ,

u

=

0

.

Then, foru

Mη,µwith

ψ

η,µ

(

u

) ,

u

=

0, by(5)and the Hölder and Sobolev inequalities we have

u

2

H1

= µη

2(pp21)p

1 p

2

RN

hηudx

≤ µη

2(pp21)N2p

1

p

2

h

L2

u

H1

(4)

and so

u

H1

≤ µη

2(pp21)N2p

1 p

2

h

L2

.

Similarly, using(4),

(

f2

)

and the Sobolev inequality we have 1

p

1

u

2

H1

=

RN

fηup+dx

S

p p2

u

p

H1

,

which implies

u

H1

Spp/2 p

1

p12

for all

µ ≥

0

.

Hence, we must have

µη

2(pp21)N2

p

2 p

1

Spp/2 p

1

p12

h

1

L2

=

Λ0 which is a contradiction. This completes the proof.

ByLemma 2.2, we may writeMη,µ

=

M+η,µ

Mη,µ, where M+η,µ

=

u

Mη,µ

 ∥

u

2

H1

− (

p

1

)

RN

fη

|

u+

|

pdx

>

0

;

Mη,µ

=

u

Mη,µ

 ∥

u

2

H1

− (

p

1

)

RN

fη

|

u+

|

pdx

<

0

and define

α

η,µ+

=

inf

uM+ η,µ

Iη,µ

(

u

)

and

α

η,µ

=

inf

uM η,µ

Iη,µ

(

u

) .

Then we have the following result.

Theorem 2.3. We have the following.

(i)

α

η,µ+

<

0for all

η, µ >

0with

µη

2(pp21)N2

<

Λ0

.

(ii) If

η, µ >

0with

µη

2(pp21)N2

<

Λ20, then

α

η,µ

>

c0for some c0

>

0

.

In particular, for each

η, µ >

0with

µη

2(pp21)N2

<

Λ20, Eq.(2)has a unique positive solution u1η,µ

M+η,µsuch that Iη,µ

u1η,µ

= α

η,µ+

= α

η,µ

.

Proof. Our proof is almost the same as that in [14, Lemma 1.4] and [19, Theorem 3.1].

2.2. Existence of two solutions

First, we establish the decay estimate for solutions of Eq.(2).

Lemma 2.4. Let u0

H1

RN

be a positive solution of Eq.(Eλ,µ). Then

v

0

(

x

) = η

2/(p2)u0

x

)

is a positive solution of Eq.(2)and

v

0

(

x

) ≥

C

η

2(6pp2)exp

( − (

1

+ ε) η |

x

| ) ,

for all

|

x

| ≥

R0for some C

>

0

.

(6) Proof. Our proof is almost the same as that in [20,21].

Forc

>

0, we define Iη,c0

(

u

) =

1

2

u

2

H1

1 p

RN

cfη

|

u+

|

pdx

;

Mcη,0

=

u

H1

RN

\ {

0

} | 

Iη,c0

(

u

) ,

u

=

0

;

Mη,0

= 

u

H1

RN

\ {

0

} | 

Iη,0

(

u

) ,

u

=

0

.

(5)

Note thatIη,0

=

Iη,c0forc

=

1, and for eachu

Mη,µthere is a uniquet1

=

t1

(

u

) >

0 such thatt1u

Mη,0. Then we have the following results.

Lemma 2.5. Suppose that

η, µ >

0with

µη

2(pp21)N2

<

Λ20. Then for each u

Mη,µ, we have the following.

(i) There is a unique tc

(

u

) >

0such that tc

(

u

)

u

Mcη,0and

max

t0 Iη,c0

(

tu

) =

Iη,c0

tc

(

u

)

u

=

1 2

1

p

c

2 p2

 ∥

u

p

H1

RNfη

|

u+

|

pdx

p22

.

(ii)For

σ ∈

0

, µ

1

η

N22(pp21)

 ,

Iη,µ

(

u

) ≥

1

− σ µη

2(pp21)N2

p p2

Iη,0

t1u

− η

2(pp21)N2 2

σ ∥

h

2

L2

and

Iη,µ

(

u

) ≤

1

+ σ µη

2(pp21)N2

p p2

Iη,0

t1u

+ η

2(pp21)N2 2

σ ∥

h

2

L2

.

Proof. (i) Similar to the proof of Lemma 7.1 in Wu [19].

(ii) For eachu

Mη,µ, letc

=

1

/ 

1

− σµη

2(pp21)N2

,tc

=

tc

(

u

) >

0 andt1

=

t1

(

u

) >

0 such thattcu

Mcη,0and t1u

Mη,0. For

σ ∈ (

0

,

1

)

, we have

RN

hηtcudx

≤ η

N2

tcu

H1

h

L2

≤ ση

N2 2

tcu

2 H1

+ η

N2

2

σ ∥

h

2

L2

.

Then by part (i) and2(pp21)

N

2

>

0

,

sup

t0

Iη,µ

(

tu

) ≥

Iη,µ

tcu

1 2

tcu

2 H1

1

p

RN

fη

tcu+

dx

− µη

2(pp21)

 ση

N2 2

tcu

2 H1

+ η

N2

2

σ ∥

h

2

L2

=

1 2c

tcu

2 H1

1

p

RN

fη

tcu+

p

dx

− µη

2(pp21)N2 2

σ ∥

h

2

L2

=

1 cIη,c0

tcu

− µη

2(pp21)N2 2

σ ∥

h

2

L2

=

1

− σ µη

2(pp21)N2

p p2

1 2

1

p

 

u

p

H1

RNfη

|

u+

|

pdx

p22

− µη

2(pp21)N2 2

σ ∥

h

2

L2

=

1

− σµη

2(pp21)N2

p p2

Ifη,0

t1u

− µη

2(pp21)N2 2

σ ∥

h

2

L2

.

Moreover, byTheorem 2.3and [20, Lemma 2.4],

sup

t0

Iη,µ

(

tu

) =

Iη,µ

(

u

) .

Thus,

Iη,µ

(

u

) ≥

1

− σ µη

2(pp21)N2

p p2

Ifη,0

t1u

− µη

2(pp21)N2 2

σ ∥

h

2

L2

.

Moreover,

Ifη,hη

(

tu

) ≤

1

+ σ µη

2(pp21)N2

2

tu

2

H1

1 p

RN

fη

|

tu+

|

pdx

+ µη

2(pp21)N2 2

σ ∥

h

2

L2

and so

Ifη,hη

(

u

) ≤

1

+ σ µη

2(pp21)N2

p p2

Ifη,0

t1u

+ µη

2(pp21)N2 2

σ ∥

h

2

L2

.

This completes the proof.

(6)

Let

w (

x

)

be a unique radially symmetric positive solution of Eq.(3)ande

SN1

= 

x

RN

| |

x

| =

1

. We denote

w

l

(

x

) = w (

x

+

le

) ,

l

∈ (

0

, ∞ ) .

Then we have the following results.

Lemma 2.6. Suppose that

η, µ >

0with

µη

2(pp21)N2

<

Λ20

.

Then (i) there exists t0

>

0such that

Iη,µ

u1η,µ

+

t

w

l

 <

Iη,µ

u1η,µ

for all t

t0and e

SN1

;

(ii) there exists l1

>

0such that for l

>

l1

,

sup

t0

Iη,µ

u1η,µ

+

t

w

l

 <

Iη,µ

u1η,µ

+ α

= α

η,µ

+ α

,

where u1η,µis the local minimum inTheorem2.3.

Proof. (i) Sinceu1η,µis a positive solution of Eq.(2), using the fact that

RN

uη,µ

∇ w

ldx

= − 

RN

w

luη,µdxwe have Iη,µ

u1η,µ

+

t

w

l

 ≤

Iη,µ

u1η,µ

+

t

2

2

∥ w

l

2

H1

+

t

RN

fη

w

l

u1η,µ

p1

dx

t

p

p

RN

fη

w

lpdx

Iη,µ

u1η,µ

+

t

2

2

∥ w

l

2

H1

+

t

RN

fη

w

l

u1η,µ

p1

dx

t

p

p

BN(0;1)

w

pdx

.

Sincep

>

2 and

w >

0 inRN, we can chooset0

>

0 large enough such that (i) holds.

(ii) SinceIη,µis continuous inH1

RN

, there existst1

>

0 such that forl

>

0

,

Iη,µ

u1η,µ

+

t

w

l

 <

Iη,µ

u1η,µ

+ α

for allt

<

t1ande

SN1

.

Using part (i) we know that forl

>

0

,

sup

tt0

Iη,µ

u1η,µ

+

t

w

l

 <

Iη,µ

u1η,µ

+ α

for alle

SN1

.

Thus, we only need to show that there existsl1

>

0 such that forl

>

l1

,

sup

t1tt0

Iη,µ

u1η,µ

+

t

w

l

 <

Iη,µ

u1η,µ

+ α

for alle

SN1

.

By Brown and Zhang [22] and Willem [23], we know that

sup

t>0I

(

t

w) =

I

(w) = α

.

(7)

Forl

>

0 andt1

t

t0

,

Iη,µ

u1η,µ

+

t

w

l

Iη,µ

u1η

+

I

(

t

w) +

1 p

RN

1

fη

tp

w

pldx

1 p

BN(le;1) fη

t1wl 0

u1η,µ

+

s

p1

− 

u1η,µ

p1

sp1dsdx

Iη,µ

u1η,µ

+

I

(

t

w) + (

I

) − (

II

) .

Using(7), we have

sup

t1tt0

Iη,µ

u1η,µ

+

t

w

l

 ≤

Iη,µ

u1η,µ

+

I

(w) + (

I

) − (

II

) .

We recall the fact that for somec

>

0

w ( |

x

| ) |

x

|

N21exp

( |

x

| ) →

c as

|

x

| → ∞ .

(See [1,2,9,24]). In particular, there exists a constantC0

>

0 such that

w (

x

) ≤

C0exp

( −|

x

| )

for allx

RN

.

Then by the Taylor expansion,

t1wl 0

u1η,µ

+

s

p1

− 

u1η,µ

p1

sp1ds

t1wl

0

(

p

1

)

sp2u1η,µ

− 

u1η,µ

p1

ds

=

 (

t1

w

l

)

p2

− 

u1η,µ

p2

t1

w

lu1η,µ

.

(8)

Références

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