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A L

E S

E D L ’IN IT ST T U

F O U R

ANNALES

DE

L’INSTITUT FOURIER

Nicolas CURIEN & Bénédicte HAAS Random trees constructed by aggregation Tome 67, no5 (2017), p. 1963-2001.

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RANDOM TREES CONSTRUCTED BY AGGREGATION

by Nicolas CURIEN & Bénédicte HAAS

Abstract. — We study a general procedure that builds randomR-trees by gluing recursively a new branch on a uniform point of the pre-existing tree. The aim of this paper is to see how the asymptotic behavior of the sequence of lengths of branches influences some geometric properties of the limiting tree, such as com- pactness and Hausdorff dimension. In particular, when the sequence of lengths of branches behaves roughly liken−α for someα(0,1], we show that the limiting tree is a compact random tree of Hausdorff dimensionα−1. This encompasses the famous construction of the Brownian tree of Aldous. Whenα >1, the limiting tree is thinner and its Hausdorff dimension is always 1. In that case, we show thatα−1 corresponds to the dimension of the set of leaves of the tree.

Résumé. — Nous nous intéressons à une procédure générale de construction d’arbres réels aléatoires par collages successifs de nouvelles branches. À chaque étape, la nouvelle branche est collée en un point uniformément sur l’arbre pré- existant. Notre objectif principal est de comprendre comment le comportement asymptotique de la suite des longueurs de branches influence certaines propriétés géométriques de l’arbre, telles que la compacité ou la dimension de Hausdorff.

Nous montrons en particulier que lorsque la suite de longueurs de branches se comporte enn−α, avecα(0,1] fixé, l’arbre limite est compact, de dimension de Hausdorffα−1. A titre d’exemple, ceci englobe une construction bien connue de l’arbre brownien d’Aldous. Lorsqueα >1, l’arbre limite est plus fin et de dimension de Hausdorff 1. Dans ce cas, nous montrons queα−1correspond à la dimension de l’ensemble des feuilles de l’arbre.

1. Introduction

Consider a sequence of closed segments or “branches” of positive lengths a1, a2, . . . and let

Ai=a1+· · ·+ai, i>1

denote the partial sums of their lengths. We construct a sequence of ran- dom trees (Tn)n>1 by starting with the treeT1 made of the single branch

Keywords: random trees, stick-breaking, Gromov–Hausdorff convergence, fractal dimension.

2010Mathematics Subject Classification:60D05, 28A80.

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of lengtha1and then recursively gluing the branch of lengthai on a point uniformly distributed (for the length measure) onTi−1. LetT be the com- pletion of the increasing union of theTn which is thus a random complete continuous tree. The aim of this paper is to discuss some geometric proper- ties of this tree. Our first result shows that even if the seriesPai is diver- gent, provided that the sequencea = (ai)i>1 is sufficiently well-behaved, the treeT is a compact random tree with a fractal behavior.

Theorem 1.1 (Case α 6 1). — Suppose that there exists α ∈ (0,1]

such that

ai6i−α+◦(1) and Ai=i1−α+◦(1) as i→ ∞.

ThenT is almost surely a compactreal tree of Hausdorff dimensionα−1. We actually get more complete results. On the one hand, the tree T is compact and has a Hausdorff dimension at most α−1 as soon as ai 6 i−α+◦(1) for some α ∈ (0,1] (Proposition 3.1). On the other hand, its Hausdorff dimension is at least α−1 as soon as Ai > i1−α+◦(1) for some α∈ (0,1] (Proposition 3.5, this result actually holds under a mild addi- tional assumption that will be discussed in the core of the paper). Let us also mentioned that in a recent paper [2], Amini et al. considered the same aggregation model and obtained a necessary and sufficient condition forT to be bounded in the particular case whenais decreasing, see the discussion in Section 2.4.

Theorem 1.1 encompasses the famous line-breaking construction of the Brownian continuum random tree (CRT) of Aldous. Specifically, if the se- quence a is the random sequence of lengths given by the intervals in a Poisson process onR+ with intensitytdt, then Aldous proved [1] thatT is compact and of Hausdorff dimension 2 (this was the initial definition of the Brownian CRT). Yet, it is a simple exercise to see that such sequences almost surely satisfy the assumptions of our theorem for α = 1/2. More generally, random trees built from a sequence of branches given by the in- tervals of a Poisson process of intensitytβdtonR+ withβ >0 satisfy our assumptions withα=β/(β+1). Typically, in these examples, the sequence ais not monotonic.

When the series Pai is convergent the situation may seem easier. In such cases, it should be intuitive that the limiting tree is compact and of Hausdorff dimension 1. We will see that this is true regardless of the mechanism used to glue the branches together (Proposition 4.1). But we can go further: when the asymptotic behavior of the sequencea is sufficiently regular, the set of leaves ofT exhibits an interesting fractal behavior similar

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to Theorem 1.1. We recall that the leaves of a continuous tree T are the pointsxsuch thatT \{x} stays connected.

Theorem 1.2 (Caseα >1). — Suppose that there exists α >1 such that

ai6i−α+◦(1) and ai+ai+1+· · ·+a2i=i1−α+◦(1) asi→ ∞.

Then the set of leaves ofT is almost surely of Hausdorff dimensionα−1. We can decompose the tree T into its set of leaves Leaves(T) and its skeletonT \Leaves(T). Since the skeleton is a countable union of segments, its Hausdorff dimension is 1 and so dimH(T) = 1∨ dimH(Leaves(T)).

Theorem 1.1 and Theorem 1.2 thus imply that when ai = i−α for some α∈(0,∞), the treeT is compact and

dimH(Leaves(T)) =α−1

almost surely. Whenα= 1, the Hausdorff dimension of the leaves ofT is not explicitly given in these theorems, but will be calculated further in the text.

A toy-model for DLA.Apart from the abundant random tree litera- ture and the initial definition of the Brownian CRT by Aldous, a motivation for considering the above line-breaking construction is that it can be seen as a toy model of external diffusion limited aggregation (DLA). Recall that in the standard DLA model, say onZ2, a subsetAn is grown by recursively adding at each time a site on the boundary ofAn according to the har- monic measure from infinity. It still remains a challenging open problem to understand the growth ofAn, see [3, 11]. In our model the particles are now branches of varying size (we do not rescale the aggregate) and harmonic measure seen from infinity is replaced by uniform measure on the structure at timen. Our Theorem 1.1 can thus be interpreted as the fact that in this case the DLA aggregate does not grow arms towards infinity, and identifies its fractal dimension.

The article [7] completes the previous results by studying cases where the treeT is obviously unbounded. Assuming that (ai) is regularly varying with a positive index, it describes the asymptotic behavior of the height ofTn and of the subtrees of Tn spanned by` points picked uniformly and independently in Tn, for all ` ∈ N. In another direction, Sénizergues [12]

extends our results to random metric spaces constructed by aggregation of d-dimensional spheres or more general independent random measured metric spaces, with gluing rules that depend both on the diameters and the measures of the metric spaces. He shows an unexpected and intriguing

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Hausdorff dimension. Last we mention [6] for a recent construction of the so-called stable treesviaan aggregation procedure that generalizes the line- breaking construction of the Brownian CRT, but that does not exactly fall in our setup.

We finish this introduction by giving some elements of the proofs of our main results. In that aim, introduce the quantity

H(a) :=

X

i=1

a2i Ai

.

When the sequencea is bounded, we will see (Theorem 2.5) that condi- tionH(a)<∞ is equivalent to the convergence of the normalized length measureµnonTn towards a limiting random probabilityµonT. For con- noisseurs, the latter is equivalent to the convergence of (Tn, µn) to (T, µ) in the Gromov–Prokhorov sense. In particular, conditionH(a) <∞ensures that the height of a “typical” point ofT (i.e. sampled according to µ) is bounded. However it does not preventT from having very thin tentacles making it unbounded.

Under the hypotheses of Theorem 1.1, this phenomenon cannot happen thanks to an approximate scale invariance of the process. Roughly speaking, we prove that when ai 6 i−α+◦(1), the subtree descending from the ith branch is a random tree built by an aggregation process which is similar to the construction of the original tree except that it is scaled by a factor at mosti−α+◦(1). This gives the first hint that the fractal dimension ofT is at mostα−1. On the other hand, whenAi >i1−α+◦(1) and H(a)<∞, the lower bound on the dimension is obtained using Frostman’s theory by constructing a (random) measure nicely spread onT. This role will be played by the limiting measureµ. To estimate theµ-measure of typical balls of radiusr >0 inT (Lemma 3.7) we will compute the distribution of the distance of two typical points picked independently at random according toµinT, a.k.a. the two-point function (Lemma 3.8).

Under the hypotheses of Theorem 1.2, the upper bound of the dimension of the set of leaves is even true in a deterministic setting (Proposition 4.1), as well as the compactness, and is obtained by exhibiting appropriate cov- erings. The lower bound of the dimension is again obtained via Frostman’s theory. A difficulty in this case is that the random measureµis equal to the normalized length measure onT (recall that the total length ofT is finite in this case). Hence,µis supported by the skeleton of the tree, and not by the leaves. This forces us to introduce another random measure supported by the leaves ofT which captures its fractal behavior. This is done in the last section which is maybe the most technical part of this work.

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Acknowledgments

We thank the organizers and the participants of the IXth workshop

“Probability, Combinatorics and Geometry” at Bellairs institute (2014) where this work started. In particular, we are grateful to Omer Angel and Simon Griffiths for interesting discussions. We also thank Frédéric Paulin for a question raised in 2008 which eventually yields to this work. Last we thank the referee for a relevant question which yields to Proposition 2.6.

In this paper, we only consider bounded sequences (ai)i>1.

2. Tracking a uniform point

The goal of this section is to give a necessary and sufficient condition for the height of a typical point ofTn(i.e. sampled according to the normalized length measure µn) to converge in distribution towards a finite random variable. For bounded sequence (ai)i>1this condition is just

H(a) =

+∞

X

i=1

a2i Ai <∞.

We will more precisely show that the above display is a necessary and sufficient condition for the convergence of the random measureµn towards a random probability measureµcarried by the limiting tree T. We begin by introducing a piece of notation.

2.1. Notation

R-trees as subsets of `1(R).We briefly recall here some definitions aboutR-trees and refer to [4, 9] for precisions. AnR-tree is a metric space (T, δ) such that for everyx, y∈ T, there is a unique arc from xtoy and this arc is isometric to a segment inR. If a, b∈ T we denote by [[a, b]] the geodesic line segment betweenaandbinT. The degree (or multiplicity) of a pointx∈ T is the number of connected components of T \{x}. A point of degree 1 is a called a leaf and a point of degree at least 3 is called a branch point.

Leta= (ai)i>1be a sequence of positive reals, andAi=a1+· · ·+ai, for i>1, the associated sequence of partial sums. Froma, we build a sequence

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of random trees (Tn)n>1by grafting randomly closed segments (also called branches) of lengthsai, i>1 inductively as described in the introduction.

To be more precise, we follow the initial approach of Aldous [1] and buildTn as a subset of`1(R). The treeT1is{(x,0,0, . . .) :x∈[0, a1]}and recursively for everyn>1, conditionally onTn, we pick (u(n)1 , . . . , u(n)n ,0,0, . . .)∈ Tn

a uniform point onTn and set Tn+1:=Tn

(u(n)1 , . . . , u(n)n , x,0,0, . . .)∈`1(R) :x∈[0, an+1] . The pointρ= (0,0, . . .) will be seen as the root of the treesTn. With this point of view, the trees Tn are increasing closed subsets of`1(R) and we can define their increasing union

T= [

n>1

Tn.

Note thatT`1(R) will not be closed in general (or equivalently com- plete). We letT denote its closure (or completion), which is therefore a random closed subset of`1(R). For us, T andTn once endowed with their length metricδ, will be viewed as random R-trees (recall that, in general, the completion of anR-tree is anR-tree – see e.g. [8]). In the rest of this article, we will be loose on the fact thatTn,T are subsets of`1(R) and will use it only when necessary for technical proofs.

General notation. Let (Fn)n>1 denote the associated filtration gener- ated by (Tn)n>1, and writebi for the segment or branch of indexi which is seen as a subset ofTn for eachn>i. A moment of thought shows that T \Tis only made of leaves ofT. We should stress that, although our main goal is to study some geometric properties of the sole treeT, we will often need to work with its subtreesTn, n>1. In that aim, we label the leaves of T by order of apparition in the aggregation procedure, so that when observingT, we also know Tn, which is simply the subtree of T spanned by the root and the leaves labeled 1, . . . , n,∀n>1. This property is auto- matic whenTn is constructed as a subset of `1(R) as before since theith branch ranges over theith coordinate of`1(R).

Besides, as already mentioned, we denote by µn the length measure on Tn normalized byA−1n to make it a probability measure. Also, to lighten notation, we writeht(x) =δ(x, ρ) for the height ofx∈ T.

Thanks to the nested structure of the trees (Tn)n>1, fork >1 and for any point x∈ T, we can make sense of [x]k the projection of x ontoTk, that is the (unique) point ofTkthat minimizes the distance tox. IfA⊂ T,

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for alln>iwe denote by

(2.1) Tn(i)(A) =

x∈ Tn: [x]iA ,

the subtree “descending from” A in Tn. Similarly we let T(i)(A) = {x ∈ T : [x]iA}, the subtree “descending from” A in T. Note that these definitions depend in general on the integeri. E.g.,

T(2)(T1)(T(1)(T1) =T.

Stems.A stem of a tree is a maximal open segment that contains no branch point. We will use a genealogical labeling of the stems of the trees (Tn)n>1 by the ternary tree

G=[

i>0

{0,1,2}i,

with the usual genealogical order4. Formally the first branchb1is labeled by ∅. Once we graft a branch on it, it is split into three stems denoted (arbitrary) by 0,1,2. Recursively, when the stem labeledu∈ Gis split into three by grafting a new branch on it, we denoteu0, u1, u2 the three stems created. Here and later we implicitly identify a stem with its label. When Tnis built afterngraftings we denote byGn ⊂ Gthe set of all stems ofTn. Whenu∈ Gi is a stem ofTi we lighten the notation introduced in (2.1) and set

Tn(u) :=Tn(i)(u) and T(u) :=T(i)(u).

It is easy to check that these definition do not depend oniwhenuhappens to belong to severalGi. The last remark is also valid ifuis the closure of a stem. We use the notationL(u) for the length of the stemuand introduce foru∈ Gn

a(u) = (ai(u))i>1

= (0)16i6n−1∪ {L(u)} ∪ ai1{aiis grafted onTi−1(u)}

i>n+1

for the sequence of lengths of branches that are recursively grafted onto the stemuor its descendants, with the convention that the first branch is the stemuappearing at timen. Note thata(u) corresponds to the lengths of branches used to constructT(u). We will sometimes need to consider a notion of height in these subtrees. Letu=u∪ {au} ∪ {bu} be the closure ofuin T, whereau designs the vertex closest to the root. Then we define the height of a vertexx∈ T(u) as the distance δ(au, x) and the height of the treeT(u) as the supremum of the distancesδ(au, x) whenxruns over T(u).

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Remark 2.1. — Almost surely the set of branch-points ofT is dense in T. Indeed, since the sequence (ai)i>1is bounded,Ai6cifor some constant c <∞and alli. In particular

X

i>1

1 Ai =∞

and the Borel–Cantelli lemma implies that infinitely many branches will be grafted on each stem, almost surely. Ifai→0 we even have that the set of leaves ofT is dense in T a.s..

2.2. Height of a random point

We begin with a simple key observation. Letn>2 and conditionally on Tnpick a pointYn uniformly distributed according to the measureµn. Two cases may happen:

• with probability 1−an/An: the pointYn belongs to the treeTn−1, that is [Yn]n−1 = Yn, and conditionally on this event [Yn]n−1 is uniformly distributed overTn−1,

• with probabilityan/An: the pointYn is located on the last branch bngrafted onTn−1. Conditionally on this event,Ynis uniformly dis- tributed on this branch and its projection [Yn]n−1on the treeTn−1 is independent of its location on the nth branch and is uniformly distributed onTn−1, given Tn−1.

From this observation we deduce that (Tn−1,[Yn]n−1) = (Tn−1, Yn−1) in distribution and more generally, (Tk,[Yn]k) = (Tk, Yk) in distribution for all 16k6n. Note however an important subtlety: given the treeTn, the point [Yn]n−1is notuniformly distributed on its subtreeTn−1since [Yn]n−1 is located on a branch point ofTn with probability an/An.

Reversing the process, it is possible to build a sequence (Tn, Xn)n>1

recursively such that [Xn]k =Xk for all k 6n and such that (Tn, Xn) = (Tn, Yn) in law for every n. To do so, consider an independent sample (Ui, Vi, i>1) of i.i.d. uniform random variables on (0,1). Let firstT1 be a segment of lengtha1, rooted at one end, and letX1 be the point on this segment at distancea1V1 from the root. We then proceed recursively and assume that the pair (Tn, Xn) has been constructed. Then:

• ifUn+1 6an+1/An+1, we branch a segment of length an+1 onXn

to getTn+1 and letXn+1be the point on this segment at distance an+1Vn+1 from the branchpointXn,

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• if Un+1 > an+1/An+1, we branch a segment of length an+1 at a point chosen uniformly (and independently of Xn) at random in Tn, and setXn+1=Xn.

Clearly, [Xn]k = Xk for 1 6 k 6 n and it is easy to see by induction that (Tn, Xn) and (Tn, Yn) have the same distribution for all n>1. It is important to notice that in this coupling, the distance betweenXn and the rootρis non-decreasing, and more precisely that for anyn>m>0,

(2.2) δ(Xn,Tm) =δ(Xn, Xm) =

n

X

i=m+1

aiVi1

Ui6Aiai ,

where we have setX0=T0=ρ. Recalling the definition ofH(a) we see that limn→∞E[ht(Xn)] = H(a)/2. Therefore, when H(a) < ∞, the sequence (ht(Xn)) converges and moreover (Xn) is a Cauchy sequence, by (2.2), almost surely. So, in this case, (Xn) converges a.s. inT, by completeness.

The converse is also true:

Proposition 2.2 (Finiteness of a typical height). — For bounded se- quences(ai)i>1,

(Xn)converges in T a.s. ⇐⇒ H(a)<∞.

Moreover, whenH(a)<∞, ifX := limn→∞Xn, we have

E

eλht(X)

6eλH(a), for allλ∈h

0, supi>1ai

−1i .

Proof. — By (2.2), the convergence of (Xn) is equivalent to the conver- gence of the seriesP

iaiVi1{Ui6ai/Ai} and so the first point follows from the classical three series theorem. To establish the exponential bound, note that for alln>1,

E

heλht(Xn)i

=

n

Y

i=1

Aiai Ai

+ ai AiE

eλaiVi

=

n

Y

i=1

Aiai Ai

+ ai Ai

1 λai

(eλai−1)

.

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Then, sinceλai 61, we can use the bound ex 61 +x+x2 valid for all x∈[0,1], and also log(1 +x)6xforx>0, to get

n

Y

i=1

Aiai

Ai

+ ai

Ai

1 λai

eλai−1

6

n

Y

i=1

Aiai

Ai

+ ai

Ai

(1 +λai)

= exp

n

X

i=1

log

1 +λa2i Ai

!

6exp λ

n

X

i=1

a2i Ai

! .

Lettingn→ ∞we get the desired bound.

Remark 2.3. — By equation (2.2) we get thatP(Xn =Xn0,n>n0) = An0/A and so, with probability one, the sequence (Xn) is eventually constant if and only ifP

iai is convergent.

Remark 2.4. — In the case of unbounded sequences (ai)i>1 (not con- sidered in this paper) the three series theorem shows that (Xn) converges a.s. iff there exists someε >0 such that

X

i>1

ai

Ai1{ai>ε}<∞ and X

i>1

a2i

Ai1{ai6ε}<∞.

Examples.

(1) If the sum P

i>1ai is finite, or if ai 6 i−ε+◦(1) for some ε > 0, then H(a) is finite (see Lemma A.1 (2)) and so the tree Tn has a typical height which remains bounded asn → ∞. Proposition 3.1 and Proposition 4.1 actually state that in these cases the maximal height of the treeTn remains bounded asn→ ∞.

(2) Ifai ∼(lni)−λ for someλ61 thenH(a) = ∞and so the typical height ofTnblows up. On the other hand, ifai∼(lni)−λ for some λ > 1 then H(a)< ∞ and the typical height of Tn thus remains bounded. In this case, we do not know whether the maximal height ofTn remains stochastically bounded asn→ ∞.

(3) Consider the sequence

ai=i−1/2+1{i∈N3}i>1.

Clearly,Ai ∼2√

i and H(a)<∞. Although the typical height of Tnremains bounded, the treeT is not compact since it contains an infinite number of branches of length greater than 1. (In fact, this tree is even unbounded, see Subsection 2.4.)

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2.3. Convergence of the length measure µn

By Proposition 2.2, when H(a) = ∞ the height of a random point in Tn sampled according to µn tends in probability to ∞. It follows that the sequence of probability measures (µn) cannot converge weakly in this context. However we will see that it does converge as soon asH(a)<∞.

With no loss of generality, we assume in the sequel that the treeT is built jointly with the sequence (Xn), as explained in the previous section.

Theorem 2.5 (Convergence of the length measures). — Suppose that H(a)<∞. Then almost surely, there exists a probability measureµonT such that

µnµ weakly asn→ ∞.

Furthermore, conditionally onµ, the pointX = limn→∞Xn is distributed according toµalmost surely and there is the dichotomy:

• if P

iai=∞ then µ is a.s. supported by the leaves of T,

• if P

iai<∞ then µ is a.s. supported by the skeleton of T and coincides with the normalized length measure ofT.

To get a precise meaning of this theorem, recall that the treesTn, n>1 and T were actually constructed as closed subsets of `1(R). Hence, the random probability measuresµn are just random variables with values in the Polish space of probability measures on`1(R) endowed with the Lévy–

Prokhorov distance (which induces the weak convergence topology). Recall that the Lévy–Prokhorov distance on the probability measures of a metric space (E, d) is given by

dLP(µ, ν) = inf

ε >0 : ν(A)6µ(A(ε)) +ε

µ(A)6ν(A(ε)) +ε for all BorelAE

,

and whereA(ε)={y∈E:d(y, A)6ε}is theε-enlargement ofA.

Proposition 2.6. — Let µn,leaves be the empirical measure on the n leaves ofTn. WhenH(a)<

µn,leavesµ weakly asn→ ∞, a.s.

whereµis the probability measure arising in Theorem 2.5. A similar result holds for the empirical measures on the branch points ofTn, or on the set of leaves and branch points ofTn. For the Brownian CRT, this implies that the measure µ corresponds to the usual uniform measure carried by this tree.

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The proofs of Theorem 2.5 and Proposition 2.6 occupy the rest of this subsection. To prove the first point of the theorem we will show that (µn) is a Cauchy sequence. We point out that this is not a direct consequence of Proposition 2.2. Indeed, as noticed in the previous section, given the treeT, the variableXn isnotdistributed according toµn since it is equal to a branch point of T with a strictly positive probability. We start by introducing a family of martingales which will play an important role.

Mass martingales.Let C ⊂ Ti be measurable for Fi and recall the notation Tn(i)(C) for n > i and T(i)(C) introduced in (2.1). Set then Mn(C) =µn(Tn(i)(C)) to simplify notation. Since the branches are grafted uniformly on the structure at each step, we have conditionally onFn

(Mn+1(C) = (An·Mn(C) +an+1)/An+1 with proba.Mn(C), Mn+1(C) =An·Mn(C)/An+1 with proba. 1−Mn(C).

It readily follows that (Mn(C))n>i is a martingale with respect to (Fn)n>i

and since it takes values in [0,1], it converges almost surely to its limit M(C) ∈[0,1]. This limit M(C) is the natural candidate for the value of µ(T(i)(C)) of the possible limitµof (µn).

Remark 2.7 (Generalized Polya urn). — These martingales are also known as “generalized Polya urns” in the theory of reinforced processes. In general, it is a subtle question to discuss whetherM(C) can have atoms in {0,1}, see [10]. However, in our context, since the sequence (ai)i>1 is bounded, it follows from Pemantle’s work [10] thatM(C)∈(0,1) almost surely when C and Cc have positive length measures. Let us emphasize an important consequence for us. Consider C ⊂ Ti with positive length measure andFi-measurable and letJ be an infinite subset ofN. Then,

X

j∈J,j>i

Mj(C) =∞ a.s.

and the conditional version of the Borel–Cantelli lemma implies that al- most surely an infinite number of branchesbj, jJ belong to the subtree T(i)(C).

Lemma 2.8. — AssumeH(a)<∞. Then almost surely, for anyε >0, there exists (a random)n0 such that

µn Tn(ε)0

>1−ε for alln>1.

Proof. — We use the construction of (Tn, Xn) of Section 2.2. Fix ε >

0 and a (deterministic) integer n0 and consider the stopping time (with

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respect to the filtration (Fn)) defined by θ= infn

n>1 :µn(Tn(ε)0 )<1−εo .

Note that

P(θ <∞, δ(Xθ, Xn0)6ε) =X

n>1

E

P(θ=n, δ(Xn, Xn0)6ε|Fn)

6X

n>1

E 1{θ=n}

(1−ε) = (1ε)P(θ <∞) where we have used that the distribution ofXn givenFn isµn, as well as the definition ofθ, to get the second inequality. This yields

ε·P(θ <∞) 6 P(θ <∞, δ(Xθ, Xn0)> ε) 6 P(δ(X, Xn0)> ε)

6

(2.2)

1 2ε

X

i=n0+1

a2i Ai.

Since the right-hand side can be made arbitrarily small by lettingn0→ ∞, we get that almost surely, for everyε > 0 (rational say), there exists (a random)n0>1 such thatµn Tn(ε)0

>1−εfor alln>1.

Lemma 2.9. — AssumeH(a)<∞. Then almost surely(µn)is a Cauchy sequence for the Lévy–Prokhorov distance.

Proof. — For any 06k6n, let [µn]k be the measureµn projected onto Tk, that is the push forward of µn by x7→[x]k. The following assertions hold almost surely. Fixε > 0, it follows from the last lemma that there exists (a random)n0such that for alln>1

(2.3) dLPn; [µn]n0)6ε .

Indeed, ifYn is sampled according to µn then we have δ(Yn,[Yn]n0) 6 ε with probability at least 1−ε. Since [Yn]n0 is distributed as [µn]n0 this readily implies the (2.3). We then decompose Tn0 into a finite number of Fn0-measurable piecesC1, . . . , CK of diameter less thanε(note thatK is random). For each of these pieces recall the definition of the martingale Mn(Cj) for n > n0. In particular with our notation we have Mn(Cj) = [µn]n0(Cj). Next, note that when

K

X

i=1

|Mn(Ci)−Mm(Ci)|6ε ,

we can couple X ∼ [µn]n0 and X0 ∼ [µm]n0 so that X and X0 be- long to the same set Ci with probability at least 1 −ε. This implies

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that dLP([µn]n0; [µm]n0)6ε. Since the martingales (Mn(Ci)) converge as n→ ∞, the last display is eventually fulfilled forn, mlarge enough. As a result, forn, mlarge enough

dLP([µn]n0; [µm]n0)6ε .

Combining the last display with (2.3) we get that forn, m large enough, dLPn;µm) 6 3ε. Hence (µn) is almost surely Cauchy for the Lévy–

Prokhorov distance on`1(R).

Proof of Theorem 2.5. — The existence of the almost sure limit µ of (µn) is ensured by the previous lemma.

Distribution ofX. — Recall from Section 2.2 thatXnµn, givenµn. In particular, for anyn>m,Xm= [Xn]mis distributed according to [µn]m, given µn. Letting n → ∞ and using the continuity of the projection on Tmfor the Lévy–Prokhorov distance, we obtain thatXm∼[µ]m, given µ.

Now, letm→ ∞. On the one hand, according to the arguments developed in the proof of Lemma 2.9, [µ]mµalmost surely for the Lévy–Prokhorov metric. On the other hand,XmX almost surely. It follows thatXµ almost surely givenµ.

Support of µ. — Since Xµ almost surely given µ, we only need to show that P(X is a leaf of T) = 1 or 0 according to P

iai = ∞ or P

iai<∞. By the construction ofXn andX, we have P(X is a leaf inT) = lim

m→∞ lim

n→∞P(Xn∈ T/ m).

IfP

iai =∞, by Remark 2.3, the sequence (Xn) escapes from any finite treeTmalmost surely and soP(X is a leaf inT) = 1. Conversely ifP

iai<

∞, thenXn=X eventually soP(X is a leaf inT) = 0. In this case, (µn) converges clearly towards the normalized length measure onT. Proof of Proposition 2.6. — For all i and then all Fi-measurable C ⊂ Ti, we let Ln(C) be the number of leaves in Tn(i)(C), n > i. Note that µn,leaves(T(i)(C)) = Ln(C)/n. Omitting easy details, we claim that the almost sure convergence µn,leavesµ will be proved if we check that n−1Ln(C)→µ(T(i)(C)) a.s., for allFi-measurableC⊂ Ti, for alli. So fix such a couple (C, i) and observe that

Nn(C) :=Ln(C)−

n−1

X

k=i

Mk(C), n > i

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defines a centered martingale, such that|Nn+1(C)−Nn(C)|61, a.s for all n > i. Applying Azuma–Hoeffding inequality, we get that for allε >0

P

|Nn(C)|>ηn12

62 exp

η2n1+2ε 2(n−i)

,n > i.

By Borel–Cantelli’s lemma, this obviously implies that Nn(C)

n12

−→a.s.

n→∞0

for allε >0 and in particular thatn−1Nn(C)→0 a.s. On the other hand, whenH(a)<∞, Theorem 2.5 implies thatMn(C)→µ(T(i)(C)) a.s., and so the Cesàro mean n−1Pn−1

k=i Mk(C) → µ(T(i)(C)) a.s. as well. Hence n−1Ln(C)→µ(T(i)(C)) a.s. as expected. The proof holds similarly for the

empirical measure on the branch points.

2.4. Boundedness of the whole tree

By Proposition 2.2, if the tree T is bounded we must haveH(a) <∞.

We refine this a little:

Proposition 2.10. — A necessary condition for the tree T to be bounded is thatai→0 asi→ ∞.

Proof. — To see this, assume that there is a real numberε > 0 and an infinite subsetJ ofNsuch that ai >εfor all iJ (recall that the ai are however supposed to be bounded). For eachiJ, letb+i denote the half part of the branchbi composed by the points at distance at leastε/2 from the vertex ofbiwhich is the closest to the root ofT. Then, by an argument similar to that of Remark 2.7, we know that almost surely, for each b+i , iJ, there is an infinite number of branchesbj, jJ that belong to its descending subtree. Iterating the argument, we see that there is a path in T containing an infinite number of disjoint segments of lengths all greater

than or equal toε/2. HenceT is unbounded.

Using a variation of the above argument we even get Proposition 2.11. — Almost surely,

T is compact ⇐⇒ T is bounded.

Proof. — The implication ⇒ is deterministically true. Notice that the events {T is not compact} and {T is not bounded} are contained in the tailσ-algebra generated by the gluings and so have probability 0 or 1. We

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suppose thus thatT is almost surely non-compact and will prove that it is almost surely non-bounded. We need a little notation. Fixn>m, the set Tn\Tm is a forest (a finite family of trees) whose highest tree is denoted by τ(m, n) (we add its root to make it complete). It is easy to see that conditionally onFm, the treeτ(m, n) is grafted on a uniform point ofTm. By monotonicity the limit

ξ= lim

m→∞ lim

n→∞ht(τ(m, n))∈[0,∞]

exists and is independent ofFm for anym >0. By the zero-one lawξ is thus deterministic. Assume by contradiction thatT is bounded a.s. Then ξ <∞and we must haveξ >0, otherwiseT would be pre-compact hence compact by completeness. Moreover, there exists then an integer k such that

(2.4) P ht(Tk)>ht(T)−ξ/4

>1/2. We denote byCk theFk-measurable part

Ck ={x∈ Tk:δ(ρ, x)>ht(Tk)−ξ/4}.

Then for any m > 1, consider the stopping time θ(m) = inf{n > m : ht(τ(m, n))> ξ/2}which is almost surely finite by definition ofξ. We put θ0 = k and θr the r-fold composition θ◦ · · · ◦θ(k) to simplify notation.

Recalling that for anyi > 0, conditionally on Fθi, the tree τ(θi, θi+1) is grafted on a uniform point ofTθi we get

(2.5) P

\

i=0

nτi, θi+1) is not grafted onTθ(k)i (Ck)o

!

=E

" Y

i=0

1−µθi

Tθ(k)i (Ck)

# .

Remark 2.7 shows thatµn(Tn(k)(Ck)) is a.s. bounded away from 0 uniformly in n and so the last display is equal to 0. This leads to a contradiction with (2.4) since graftingτ(θi, θi+1) ontoTθ(k)i (Ck) gives a tree with height

strictly greater thanht(Tk) +ξ/4.

We will see in the forthcoming Proposition 3.1 and Proposition 4.1 that sufficient conditions for the compactness ofT are either thatai6i−α+◦(1) for some α∈(0,1] or that the series P

iai is convergent. But we do not have a necessary and sufficient condition for boundedness or equivalently compactness of the tree, hence the following question :

Open question 2.12. — Find a necessary and sufficient condition for T to be bounded.

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As mentioned in the Introduction, this problem was solved by Amini et al. [2] for decreasing sequences a: in these cases, with probability one, the treeT is bounded if and only if P

i>1i−1ai<∞. Note that in general this condition cannot be sufficient for boundedness: in the Example (3) of Section 2.2 the sumP

i>1i−1ai is finite, but the corresponding tree is unbounded sinceai does not converge to 0.

3. Infinite length case

The goal of this section is to prove Theorem 1.1. We will first prove (under more general conditions than those of Theorem 1.1) thatT is compact using a covering argument which will also give the upper bound dimH(T)61/α.

The lower bound on the Hausdorff dimension then follows from a careful study of the random measureµ introduced in Theorem 2.5 and, again, is valid under more general conditions than those of Theorem 1.1.

3.1. Compactness and upper bound The main result of this subsection is the following:

Proposition 3.1. — Assume that ai 6 i−α+◦(1) for some α ∈ (0,1].

Then, almost surely, the random treeT is compact and its Hausdorff di- mension is at mostα−1.

We point out that we more generally know that the tree T is compact, with a set of leaves of Hausdorff dimension less thanα−1, as soon asai6 i−α+◦(1) for some α > 0. This follows from the previous result, together with the forthcoming Proposition 4.1. That being said, we focus in the rest of this subsection on the proof of Proposition 3.1 and assume that ai 6i−α+◦(1) forα∈(0,1]. We note with Lemma A.1 (2) that this implies

that

X

i=n

a2i

Ai 6 n−α+◦(1), which will be repeatedly used in the sequel.

3.1.1. Rough scale invariance

We begin with a proposition which is a rough version of scale invariance.

In words it says that the typical height of every subtree grafted onTn is at mostn−α+◦(1). Combined with Proposition 2.2, it is the core of the proof of Proposition 3.1. For a stemu, recall the notationa(u) from Section 2.1.

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Proposition 3.2. — Ifai6i−α+◦(1) for someα∈(0,1], then, almost surely,

sup

u∈Gn

H a(u)

6n−α+◦(1).

Proof. — We first prove that the longest length of a stem of Tn is at mostn−α+◦(1). To see this, suppose by contradiction that a stem of length at least n−α+ε is present inTn for some ε >0. Provided that n is large enough, since ai 6 i−α+◦(1), this stem must be part of a branch bi (of lengthai) grafted at some time i 6n/2. It thus means that we can find a part of lengthn−α+ε/2 of the branch bi whose endpoints are exactly at distancekn−α+ε/2 and (k+ 1)n−α+ε/2 for somek>0 from the extremity of bi closest to root of Ti which has not been hit by the grafting process between timesbn/2c+ 1 andn. For eachk, such an event has probability at most

1−n−α+ε 2An

n/2

6exp

−nε+◦(1) ,

sinceAn 6n1−α+◦(1) because ai6i−α+◦(1) andα∈(0,1]. Summing over all possibilities to choose such a part on some bi for some i6n, we find that asymptotically the probability that there is a stem of length at least n−α+εin Tn is bounded above by

X

i6n/2

2ai

n−α+ε + 1

exp

−nε+◦(1)

= exp

−nε+◦(1) .

We easily conclude by an application of Borel–Cantelli that

(3.1) sup

u∈Gn

L(u)6n−α+◦(1).

To deduce from this the proposition, we need the following lemma.

Lemma 3.3. — Pick a stem uof Tn, then, conditionally onTn,for any λ>0 such thatλL(u)<1andλai<1for alli>n, we have

E h

eλH(a(u))| Fn

i

6exp 2λ

L(u) +

X

i=n+1

a2i Ai

! .

Proof. — Fori>1, letAi(u) =a1(u) +· · ·+ai(u) and forp>1, let Σp=

p

X

i=1

ai(u)2

Ai(u), so that Σ=H(a(u)), with the convention that aAi(u)2

i(u) = 0 ifai(u) = 0. Next, letλ>0 satisfy the assumptions of the statement. Forp>n, since the branchap+1 is grafted

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onTp(u) with probabilityAp(u)/Ap, we have E

eλΣp+1| Fp

=eλΣp ApAp(u)

Ap +Ap(u) Ap eλ

a2 p+1 Ap(u)+ap+1

!

=eλΣp 1 + Ap(u) Ap

eλ

a2 p+1

Ap(u)+ap+1 −1

!

6eλΣp 1 + 2λ a2p+1 Ap(u) +ap+1

×Ap(u) Ap

! .

To go from the second to the third line, we have used that

λ a

2 p+1

Ap(u)+ap+1 6 λap+1 6 1 and that ex−1 6 2x for x ∈ [0,1]. Besides, since for a fixedc >0, the function x7→x/(x+c) is increasing on (0,∞) andAp(u)6Ap we have that (A Ap(u)

p(u)+ap+1)Ap 6 Ap+11 , which finally leads to

E

eλΣp+1 | Fp

6eλΣp 1 + 2λa2p+1 Ap+1

! .

Note that we also haveE[eλΣn] =eλL(u)61 + 2λL(u). So, conditioning in cascades over all integersp>n, we obtain

E[eλH(a(u)) | Fn] =E[eλΣ| Fn]6(1 + 2λL(u))

Y

i=n+1

1 + 2λa2i Ai

6exp 2λ

L(u) +

X

i=n+1

a2i Ai

!

.

Coming back to the proof of Proposition 3.2, fix ε >0 and considernε

such thatan 6n−α+ε and P n

a2i

Ai 6n−α+ε for all n >nε (nε exists by Lemma A.1 (ii) and sinceai6i−α+◦(1)). Then, form>nε, letEm denote the event

sup

u∈Gn

L(u)6n−α+ε for alln>m.

By the first part of the proof, P(Em) converges to 1 as m → ∞. Next, for a fixed m>nε and alln >m, using a standard Markov exponential inequality and Lemma 3.3 withλ=nα−εon the eventEm, we get

P H(a(u))>n−α+2ε| Em

6 e−λn−α+2εE E

eλH(a(u))1Em| Fn P(Em)

6 e−λn−α+2ε+4λn−α+ε

P(Em) 6e−nε+◦(1).

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